Re: [algogeeks] probability
Suppose three gunmen are A, B, and C who have a probability of 100%, 50% and 33% respectively. The shooting will start from C, then B and at last A. Now there are several possibilities for C. If C shoots B, then A would shoot C with an accuracy of 100% or in other case if C shoots A, then B would shoot him with an accuracy of 50%. So he has a probability of getting killed. We can see in either of the cases C will die. So what C will do in first round is that it will fire the shot in air. Now the scenario gets interesting. By doing this C has turned the battle among three people into two people A and B. This will increase the chances of survival of C. So now its B's turn of firing. So he can fire at either A or C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows that he will surely die so B won't do that. If B shoots A, then C will shoot B. I think this is the solution. Please point out if there are any loopholes. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@Dave: first of all By shooting in air I meant that C will not fire any one. That was my figure of speech:)) He will simply waste his shot. @Salil: its a duel. everyone will get chance to shoot in each round -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: probability
@snehal: will the shooting take place in increasing order of accuracy of hitting the target and is that at a time only one person can take a shot??? if yes then @Salil: my answer would be the same as above. what C will do is that it will first let A and B kill each other first. After C wastes his shot it will be B's turn. B can kill C, but in that case the turn would go to A and he would surely kill B. If B goes after A, then B may hit it or miss it(as its probability of hitting is 50%) If B misses it then it depends on A whom to kill. A may kill B or C. A will try to kill one who is better shooter i.e. B as C is less likely to hit A. If B hits A then we are done. Round 1 is complete(as required in the question) and C survives the first round. Look the problem is not that who gets killed at last but rather what C should fire in the first round obviously to survive(as I understood the problem). It may happen that eventually C gets killed. But what should C shoot in first round to survive. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] spy in the city
Is there any condition that the people in the city may or may not know each other??? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: C aps ques
for 2nd problem: statement inside the do-while is executed once. Now for the condition checking inside the while loop. The condition i++5 is evaluated which turns out to be true. So the rest of the part ++ch='F' is not evaluated and hence letter A is printed six times. Now when the condition i++5 fails, then the condition ++ch='F' would be evaluated which prints BCDEF. This is a property of the logical OR. If the first condition evaluates to true, then rest of the condition is not evaluated as it would always turn out to be true. However, if the first condition is false then only the second condition is checked to get the final output. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: C aps ques
correct me if I am wrong. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Smallest window of K[] in N[]. Best order solution
@prodigy: how is it coming O(nlogk) can u explain??? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Do This
Take two pointers p and q. Initially p points to head.
while(p!=given pointer)
{
p=p-link;
q=p;
};
Now you hv pointer at 3rd and 4th position. Now insertion is simpleHope
this will work
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Re: [algogeeks] Do This
@shobhan: Ya,I got it!! -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
