Re: [algogeeks] Re: Amazon Again

2011-02-01 Thread nishaanth
nice solution..

On Sun, Jan 30, 2011 at 11:51 PM, Wei.QI qiw...@gmail.com wrote:

 here is the code:
 public int findStartPumpIndex(int[][] pumpDistance){
 int leftGas = 0;
  int start = 0;
 //Find the potential start
 for(int i=0; ipumpDistance.length; i++){
  int addGas = pumpDistance[i][0];
 int consumeGas = pumpDistance[i][1];
  int left = leftGas + addGas - consumeGas;
 if(left = 0){
 leftGas = left;
  }else {
 leftGas = 0;
 start = i+1;
  }
 }
  //if we failed find a start at last, not solution
 if(start = pumpDistance.length)
  return -1;
  //otherwise continue to go, until back to start
  for(int i=0; istart; i++){
 int addGas = pumpDistance[i][0];
 int consumeGas = pumpDistance[i][1];
  int left = leftGas + addGas - consumeGas;
 if(left  0){
 leftGas = left;
  }else {
 return -1;
 }
  }
 return start;
 }
 On Sun, Jan 30, 2011 at 9:55 AM, Wei.QI qiw...@gmail.com wrote:

 For any gas pump, when your car arrives, it contains 0 or more gas.
 So, for each gas pump, the worst case is starting from that pump.

 Then, if we starting from pump A1, passed A2 - Ak and failed at Ak+1. for
 A1 to Ak, we can not pass Ak+1 starting from any of them. So we try start
 from Ak+1.

 This could be solved in liner time. finding a possible start pump use O(n)
 and prove it use another O(n).

 -weiq


 On Sat, Jan 29, 2011 at 9:47 PM, nishaanth nishaant...@gmail.com wrote:

 @Wei.Qi Can you clarify when your algorithm terminates and also what
 is  the running time of the algorithm ?


 On Sun, Jan 30, 2011 at 9:46 AM, yq Zhang zhangyunq...@gmail.comwrote:

 can you prove it?

 On Jan 29, 2011 6:38 PM, Wei.QI qiw...@gmail.com wrote:
 
  Starting with any pump A, try to finish the circle, if at pump B that
 can not reach pump B+1, it means all pumps from A to B can not finish the
 circle (it will go broke at pump B), then just start with B+1. After go
 through all the pumps start from some pump, we got an answer. if we go back
 to pump A and later, still can not find an answer, there is no answer.
 
  On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
 richi.sankalp1...@gmail.com wrote:
 
  I'm sure you have misstated the problem statement
 
  just find out the total path length and return the first petrol pump
  which gives you the required milage
  go greedy
 
  On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
   There are N petrol pumps along a circular path. Every petrol pump
   gives some amount of fixed petrol. Need not to be unique and in no
   particular order means it is random. We have a car and we need to
 find
   a petrol pump which can provide so much of petrol that we can take
 a
   full of the circle. Mileage of car is fixed.
   Distance between adjacent petrol pumps are given.
  
   Thanks  Regards
   Shashank
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.
 
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.

 --
 You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




 --
 S.Nishaanth,
 Computer Science and engineering,
 IIT Madras.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.



  --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




-- 
S.Nishaanth,
Computer Science and engineering,
IIT Madras.

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this 

[algogeeks] Re: Amazon Again

2011-01-31 Thread sankalp srivastava
@wei.qui

On a second thought , if the petrol pumps have many petrol pumps
connected to it , we cannot find the answer your way or the method
suggested by me previously .
Thus , the solution becomes one to find out the Eulerian Path
(constraint based of course )

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-30 Thread Nich01as
@Wei.Qi
the algorithm is right, but the running time is ...?


define Pi the amount of petrol each pumps has.
Di is the distance between Ith and i+1th pumps.

then we can double the circle, we can get to sequence
p1, p2, p3, p4...pn, p1, p2, p3..pn
d1, d2, d3, d4...dn, d1, d2, d3..dn

the problem will become to find a subsequence in above sequences with length
N
where sum(P(start, start+i)) = sum(D(start, start+i)) for any 0=iN.

change those two sequences to below one.
p1-d1, p1+p2-d1-d2, p1+p2+p3-d1-d2-d3 . p1+p2+..+p2-d1-d2...-dn
make the sequence as
s1, s2, s3, s4...sn, s1, s2..sn

finally the problem becomes to find a subsquence in Sn start at element j
where S(j+i) = Sj and Sj = 0.
So it can be solved in NlogN
On Sun, Jan 30, 2011 at 1:47 PM, nishaanth nishaant...@gmail.com wrote:

 @Wei.Qi Can you clarify when your algorithm terminates and also what
 is  the running time of the algorithm ?


 On Sun, Jan 30, 2011 at 9:46 AM, yq Zhang zhangyunq...@gmail.com wrote:

 can you prove it?

 On Jan 29, 2011 6:38 PM, Wei.QI qiw...@gmail.com wrote:
 
  Starting with any pump A, try to finish the circle, if at pump B that
 can not reach pump B+1, it means all pumps from A to B can not finish the
 circle (it will go broke at pump B), then just start with B+1. After go
 through all the pumps start from some pump, we got an answer. if we go back
 to pump A and later, still can not find an answer, there is no answer.
 
  On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
 richi.sankalp1...@gmail.com wrote:
 
  I'm sure you have misstated the problem statement
 
  just find out the total path length and return the first petrol pump
  which gives you the required milage
  go greedy
 
  On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
   There are N petrol pumps along a circular path. Every petrol pump
   gives some amount of fixed petrol. Need not to be unique and in no
   particular order means it is random. We have a car and we need to
 find
   a petrol pump which can provide so much of petrol that we can take a
   full of the circle. Mileage of car is fixed.
   Distance between adjacent petrol pumps are given.
  
   Thanks  Regards
   Shashank
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.
 
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




 --
 S.Nishaanth,
 Computer Science and engineering,
 IIT Madras.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




-- 
Southeast University
Nicholas.Zhaoyu

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-30 Thread Nich01as
It's not right.

On Sun, Jan 30, 2011 at 4:19 PM, Nich01as nicholas.zha...@gmail.com wrote:

 @Wei.Qi
 the algorithm is right, but the running time is ...?


 define Pi the amount of petrol each pumps has.
 Di is the distance between Ith and i+1th pumps.

 then we can double the circle, we can get to sequence
 p1, p2, p3, p4...pn, p1, p2, p3..pn
 d1, d2, d3, d4...dn, d1, d2, d3..dn

 the problem will become to find a subsequence in above sequences with
 length N
 where sum(P(start, start+i)) = sum(D(start, start+i)) for any 0=iN.

 change those two sequences to below one.
 p1-d1, p1+p2-d1-d2, p1+p2+p3-d1-d2-d3 . p1+p2+..+p2-d1-d2...-dn
 make the sequence as
 s1, s2, s3, s4...sn, s1, s2..sn

 finally the problem becomes to find a subsquence in Sn start at element j
 where S(j+i) = Sj and Sj = 0.
 So it can be solved in NlogN

 On Sun, Jan 30, 2011 at 1:47 PM, nishaanth nishaant...@gmail.com wrote:

 @Wei.Qi Can you clarify when your algorithm terminates and also what
 is  the running time of the algorithm ?


 On Sun, Jan 30, 2011 at 9:46 AM, yq Zhang zhangyunq...@gmail.com wrote:

 can you prove it?

 On Jan 29, 2011 6:38 PM, Wei.QI qiw...@gmail.com wrote:
 
  Starting with any pump A, try to finish the circle, if at pump B that
 can not reach pump B+1, it means all pumps from A to B can not finish the
 circle (it will go broke at pump B), then just start with B+1. After go
 through all the pumps start from some pump, we got an answer. if we go back
 to pump A and later, still can not find an answer, there is no answer.
 
  On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
 richi.sankalp1...@gmail.com wrote:
 
  I'm sure you have misstated the problem statement
 
  just find out the total path length and return the first petrol pump
  which gives you the required milage
  go greedy
 
  On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
   There are N petrol pumps along a circular path. Every petrol pump
   gives some amount of fixed petrol. Need not to be unique and in no
   particular order means it is random. We have a car and we need to
 find
   a petrol pump which can provide so much of petrol that we can take a
   full of the circle. Mileage of car is fixed.
   Distance between adjacent petrol pumps are given.
  
   Thanks  Regards
   Shashank
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.
 
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




 --
 S.Nishaanth,
 Computer Science and engineering,
 IIT Madras.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




 --
 Southeast University
 Nicholas.Zhaoyu




-- 
Southeast University
Nicholas.Zhaoyu

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



[algogeeks] Re: Amazon Again

2011-01-30 Thread sankalp srivastava
[quote]We have a car and we need to find
a petrol pump which can provide so much of petrol that we can take a
full of the circle.[/quote]

So , we just need to find a petrol pump which takes you just a full
circle , not anything ahead , not anything behind .

1)Sort the petrol he can get from maximum stations .If the total
distance is not given , calculate this while sorting .
Binary search over this array for the required distance .

complexity :-O(nlogn+k)
2)Hash it !! keep a hash for all the distance in some boolean
array .now find out the one which can get you the full circle , O(n)
complexity . Not space efficient .

3)Using dynamic programming .

dp[i][j] :-The distance we still need to cover (j) .while , we are on
the started at the ith station .
dp[i][0]:- answer , we need to look at the all the dp pairs for the
answer .
dp[i][j]= min(dp[i+next[i][j-d[i][next[i]]])

Basically a BFS . O(n^2) . worst case .

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-30 Thread Wei.QI
For any gas pump, when your car arrives, it contains 0 or more gas.
So, for each gas pump, the worst case is starting from that pump.

Then, if we starting from pump A1, passed A2 - Ak and failed at Ak+1. for A1
to Ak, we can not pass Ak+1 starting from any of them. So we try start from
Ak+1.

This could be solved in liner time. finding a possible start pump use O(n)
and prove it use another O(n).

-weiq

On Sat, Jan 29, 2011 at 9:47 PM, nishaanth nishaant...@gmail.com wrote:

 @Wei.Qi Can you clarify when your algorithm terminates and also what
 is  the running time of the algorithm ?


 On Sun, Jan 30, 2011 at 9:46 AM, yq Zhang zhangyunq...@gmail.com wrote:

 can you prove it?

 On Jan 29, 2011 6:38 PM, Wei.QI qiw...@gmail.com wrote:
 
  Starting with any pump A, try to finish the circle, if at pump B that
 can not reach pump B+1, it means all pumps from A to B can not finish the
 circle (it will go broke at pump B), then just start with B+1. After go
 through all the pumps start from some pump, we got an answer. if we go back
 to pump A and later, still can not find an answer, there is no answer.
 
  On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
 richi.sankalp1...@gmail.com wrote:
 
  I'm sure you have misstated the problem statement
 
  just find out the total path length and return the first petrol pump
  which gives you the required milage
  go greedy
 
  On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
   There are N petrol pumps along a circular path. Every petrol pump
   gives some amount of fixed petrol. Need not to be unique and in no
   particular order means it is random. We have a car and we need to
 find
   a petrol pump which can provide so much of petrol that we can take a
   full of the circle. Mileage of car is fixed.
   Distance between adjacent petrol pumps are given.
  
   Thanks  Regards
   Shashank
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.
 
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




 --
 S.Nishaanth,
 Computer Science and engineering,
 IIT Madras.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.


-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



[algogeeks] Re: Amazon Again

2011-01-29 Thread sankalp srivastava
I'm sure you have misstated the problem statement

just find out the total path length and return the first petrol pump
which gives you the required milage
go greedy

On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
 There are N petrol pumps along a circular path. Every petrol pump
 gives some amount of fixed petrol. Need not to be unique and in no
 particular order means it is random. We have a car and we need to find
 a petrol pump which can provide so much of petrol that we can take a
 full of the circle. Mileage of car is fixed.
 Distance between adjacent petrol pumps are given.

 Thanks  Regards
 Shashank

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-29 Thread Wei.QI
Starting with any pump A, try to finish the circle, if at pump B that can
not reach pump B+1, it means all pumps from A to B can not finish the circle
(it will go broke at pump B), then just start with B+1. After go through all
the pumps start from some pump, we got an answer. if we go back to pump A
and later, still can not find an answer, there is no answer.

On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
richi.sankalp1...@gmail.com wrote:

 I'm sure you have misstated the problem statement

 just find out the total path length and return the first petrol pump
 which gives you the required milage
 go greedy

 On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
  There are N petrol pumps along a circular path. Every petrol pump
  gives some amount of fixed petrol. Need not to be unique and in no
  particular order means it is random. We have a car and we need to find
  a petrol pump which can provide so much of petrol that we can take a
  full of the circle. Mileage of car is fixed.
  Distance between adjacent petrol pumps are given.
 
  Thanks  Regards
  Shashank

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.



-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-29 Thread yq Zhang
can you prove it?
On Jan 29, 2011 6:38 PM, Wei.QI qiw...@gmail.com wrote:

 Starting with any pump A, try to finish the circle, if at pump B that can
not reach pump B+1, it means all pumps from A to B can not finish the circle
(it will go broke at pump B), then just start with B+1. After go through all
the pumps start from some pump, we got an answer. if we go back to pump A
and later, still can not find an answer, there is no answer.

 On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
richi.sankalp1...@gmail.com wrote:

 I'm sure you have misstated the problem statement

 just find out the total path length and return the first petrol pump
 which gives you the required milage
 go greedy

 On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
  There are N petrol pumps along a circular path. Every petrol pump
  gives some amount of fixed petrol. Need not to be unique and in no
  particular order means it is random. We have a car and we need to find
  a petrol pump which can provide so much of petrol that we can take a
  full of the circle. Mileage of car is fixed.
  Distance between adjacent petrol pumps are given.
 
  Thanks  Regards
  Shashank

 --
 You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
.
 For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.


 --
 You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
.
 For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-29 Thread nishaanth
@Wei.Qi Can you clarify when your algorithm terminates and also what is
the running time of the algorithm ?

On Sun, Jan 30, 2011 at 9:46 AM, yq Zhang zhangyunq...@gmail.com wrote:

 can you prove it?

 On Jan 29, 2011 6:38 PM, Wei.QI qiw...@gmail.com wrote:
 
  Starting with any pump A, try to finish the circle, if at pump B that can
 not reach pump B+1, it means all pumps from A to B can not finish the circle
 (it will go broke at pump B), then just start with B+1. After go through all
 the pumps start from some pump, we got an answer. if we go back to pump A
 and later, still can not find an answer, there is no answer.
 
  On Sat, Jan 29, 2011 at 4:38 AM, sankalp srivastava 
 richi.sankalp1...@gmail.com wrote:
 
  I'm sure you have misstated the problem statement
 
  just find out the total path length and return the first petrol pump
  which gives you the required milage
  go greedy
 
  On Jan 28, 5:09 pm, bittu shashank7andr...@gmail.com wrote:
   There are N petrol pumps along a circular path. Every petrol pump
   gives some amount of fixed petrol. Need not to be unique and in no
   particular order means it is random. We have a car and we need to find
   a petrol pump which can provide so much of petrol that we can take a
   full of the circle. Mileage of car is fixed.
   Distance between adjacent petrol pumps are given.
  
   Thanks  Regards
   Shashank
 
  --
  You received this message because you are subscribed to the Google
 Groups Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.
 
 
  --
  You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
  To post to this group, send email to algogeeks@googlegroups.com.
  To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
  For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.

 --
 You received this message because you are subscribed to the Google Groups
 Algorithm Geeks group.
 To post to this group, send email to algogeeks@googlegroups.com.
 To unsubscribe from this group, send email to
 algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com
 .
 For more options, visit this group at
 http://groups.google.com/group/algogeeks?hl=en.




-- 
S.Nishaanth,
Computer Science and engineering,
IIT Madras.

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



[algogeeks] Re: Amazon Again

2011-01-19 Thread bittu
@radha krishnanan do u  means this

http://en.wikipedia.org/wiki/Matrix_exponential

anyways got it.

Regards
Shashank

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



[algogeeks] Re: Amazon Again

2011-01-19 Thread Dave
If the matrix is diagonalizable, then it can be raised to any power in
O(n^3) independent of k. Find the eigenvalue/eigenvector decomposition
of the matrix, raise the eigenvalues to power k, and then multiply on
the right and left by the matrix of eigenvectors and its inverse,
respectively.

Dave

On Jan 12, 6:58 am, bittu shashank7andr...@gmail.com wrote:
 How will you raise a n x n matrix to the power k efficiently. What's
 the time complexity and space complexity of you algorithm? How will
 you optimize this?

 Thanks Regards
 Shashank Don't b Evil U Can Earn While U Learn

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



[algogeeks] Re: Amazon Again

2011-01-12 Thread Jammy
I think you meant n^3*log(K).
Multiplication on two matrices would take O(n) per entry. And total
#entries is n*n, thus multiplying 2 matrices takes O(n^3)
To get a^(K), use simple divide-and-conquer technique. Since once one
gets a^(K/2), to get a^(K) only needs to square it.
Now we get T(K) = T(K/2)+O(multiply)---T(K) = logK*O(multiply) =
n^3*logK.

On Jan 12, 8:04 am, radha krishnan radhakrishnance...@gmail.com
wrote:
 Using Matrix Exponentiation technique
 Complexity is n^3*(lg n) for matrix n x n
 we need two n x n matrix to raise the matrix to power K ..
 Correct me if am wronf

 On Wed, Jan 12, 2011 at 6:28 PM, bittu shashank7andr...@gmail.com wrote:
  How will you raise a n x n matrix to the power k efficiently. What's
  the time complexity and space complexity of you algorithm? How will
  you optimize this?

  Thanks Regards
  Shashank Don't b Evil U Can Earn While U Learn

  --
  You received this message because you are subscribed to the Google Groups 
  Algorithm Geeks group.
  To post to this group, send email to algoge...@googlegroups.com.
  To unsubscribe from this group, send email to 
  algogeeks+unsubscr...@googlegroups.com.
  For more options, visit this group 
  athttp://groups.google.com/group/algogeeks?hl=en.

-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algoge...@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.



Re: [algogeeks] Re: Amazon Again

2011-01-12 Thread radha krishnan
@jammy: Sorry for wrong answer
thats O(n^3 *lg(K))


On Thu, Jan 13, 2011 at 12:28 AM, Jammy xujiayiy...@gmail.com wrote:
 I think you meant n^3*log(K).
 Multiplication on two matrices would take O(n) per entry. And total
 #entries is n*n, thus multiplying 2 matrices takes O(n^3)
 To get a^(K), use simple divide-and-conquer technique. Since once one
 gets a^(K/2), to get a^(K) only needs to square it.
 Now we get T(K) = T(K/2)+O(multiply)---T(K) = logK*O(multiply) =
 n^3*logK.

 On Jan 12, 8:04 am, radha krishnan radhakrishnance...@gmail.com
 wrote:
 Using Matrix Exponentiation technique
 Complexity is n^3*(lg n) for matrix n x n
 we need two n x n matrix to raise the matrix to power K ..
 Correct me if am wronf

 On Wed, Jan 12, 2011 at 6:28 PM, bittu shashank7andr...@gmail.com wrote:
  How will you raise a n x n matrix to the power k efficiently. What's
  the time complexity and space complexity of you algorithm? How will
  you optimize this?

  Thanks Regards
  Shashank Don't b Evil U Can Earn While U Learn

  --
  You received this message because you are subscribed to the Google Groups 
  Algorithm Geeks group.
  To post to this group, send email to algoge...@googlegroups.com.
  To unsubscribe from this group, send email to 
  algogeeks+unsubscr...@googlegroups.com.
  For more options, visit this group 
  athttp://groups.google.com/group/algogeeks?hl=en.

 --
 You received this message because you are subscribed to the Google Groups 
 Algorithm Geeks group.
 To post to this group, send email to algoge...@googlegroups.com.
 To unsubscribe from this group, send email to 
 algogeeks+unsubscr...@googlegroups.com.
 For more options, visit this group at 
 http://groups.google.com/group/algogeeks?hl=en.



-- 
You received this message because you are subscribed to the Google Groups 
Algorithm Geeks group.
To post to this group, send email to algoge...@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.