Re: [algogeeks] Re: intel puzzle
http://math.ucsd.edu/~wgarner/personal/puzzles/cube_puzzle_sol.htm On Tue, Mar 1, 2011 at 8:46 AM, Vinay Pandey babbupan...@gmail.com wrote: each pair of opposite faces can make 4 such triangles, so I think the answer is 12 On Mon, Feb 28, 2011 at 5:47 AM, sourabh jakhar sourabhjak...@gmail.comwrote: the answer would be more than 8 an it is 32 i think. but i m sure it will be more than 8 On Wed, Feb 23, 2011 at 7:54 AM, Terence technic@gmail.com wrote: 8C3 - 12 * 4C3 = 8 Any 3 vertices out of a rectangle only form a right triangles. Then only 8 regular triangle left. (Cut out each of the 8 vertices) On 2011-2-23 3:10, jalaj jaiswal wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- SOURABH JAKHAR,(CSE)(3 year) ROOM NO 167 , TILAK,HOSTEL 'MNNIT ALLAHABAD The Law of Win says, Let's not do it your way or my way; let's do it the best way. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Thank You Rajeev Kumar -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: intel puzzle
each pair of opposite faces can make 4 such triangles, so I think the answer is 12 On Mon, Feb 28, 2011 at 5:47 AM, sourabh jakhar sourabhjak...@gmail.comwrote: the answer would be more than 8 an it is 32 i think. but i m sure it will be more than 8 On Wed, Feb 23, 2011 at 7:54 AM, Terence technic@gmail.com wrote: 8C3 - 12 * 4C3 = 8 Any 3 vertices out of a rectangle only form a right triangles. Then only 8 regular triangle left. (Cut out each of the 8 vertices) On 2011-2-23 3:10, jalaj jaiswal wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- SOURABH JAKHAR,(CSE)(3 year) ROOM NO 167 , TILAK,HOSTEL 'MNNIT ALLAHABAD The Law of Win says, Let's not do it your way or my way; let's do it the best way. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: intel puzzle
the answer would be more than 8 an it is 32 i think. but i m sure it will be more than 8 On Wed, Feb 23, 2011 at 7:54 AM, Terence technic@gmail.com wrote: 8C3 - 12 * 4C3 = 8 Any 3 vertices out of a rectangle only form a right triangles. Then only 8 regular triangle left. (Cut out each of the 8 vertices) On 2011-2-23 3:10, jalaj jaiswal wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- SOURABH JAKHAR,(CSE)(3 year) ROOM NO 167 , TILAK,HOSTEL 'MNNIT ALLAHABAD The Law of Win says, Let's not do it your way or my way; let's do it the best way. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: intel puzzle
@priyaranjan No,Your triangle will be right angle triangle. In fact any triangle chosen will be right angle triangle. Proof: suppose there are 2 planes kept at parallel with each other.(top bottom) join corresponding vertices of up to down and form cube. Now 3 points chosen can be on same plane .(means 2 must be adjacent) so right angle triangle is only possible or at least 2 points are on same plane and 3rd point is other plane(pigeon hole as only 2 holes are there for 3 pegions) Now as 3 rd point always lies on perpendicular point so triagle formed will always be right angled. On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid priyaranjan@gmail.comwrote: The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
@Priyaranjan: Suppose that the cube has side 1 and is placed in standard position at the origin. Then the triangle with vertices (0,0,0), (1,0,1), and (1,1,0) is equilateral with side sqrt(2), and therefore is not a right triangle. Dave On Feb 24, 8:49 am, Vikas Kumar dev.vika...@gmail.com wrote: @priyaranjan No,Your triangle will be right angle triangle. In fact any triangle chosen will be right angle triangle. Proof: suppose there are 2 planes kept at parallel with each other.(top bottom) join corresponding vertices of up to down and form cube. Now 3 points chosen can be on same plane .(means 2 must be adjacent) so right angle triangle is only possible or at least 2 points are on same plane and 3rd point is other plane(pigeon hole as only 2 holes are there for 3 pegions) Now as 3 rd point always lies on perpendicular point so triagle formed will always be right angled. On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid priyaranjan@gmail.comwrote: The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
@dave i never said it will be a right angled triangle ,it will be a equilateral triangle and thus an acute angled triangle. On Feb 24, 8:38 pm, Dave dave_and_da...@juno.com wrote: @Priyaranjan: Suppose that the cube has side 1 and is placed in standard position at the origin. Then the triangle with vertices (0,0,0), (1,0,1), and (1,1,0) is equilateral with side sqrt(2), and therefore is not a right triangle. Dave On Feb 24, 8:49 am, Vikas Kumar dev.vika...@gmail.com wrote: @priyaranjan No,Your triangle will be right angle triangle. In fact any triangle chosen will be right angle triangle. Proof: suppose there are 2 planes kept at parallel with each other.(top bottom) join corresponding vertices of up to down and form cube. Now 3 points chosen can be on same plane .(means 2 must be adjacent) so right angle triangle is only possible or at least 2 points are on same plane and 3rd point is other plane(pigeon hole as only 2 holes are there for 3 pegions) Now as 3 rd point always lies on perpendicular point so triagle formed will always be right angled. On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid priyaranjan@gmail.comwrote: The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.-Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
@vikash kumar please read my answer then give your comment..it will be a equilateral triangle and not a right angled triangle i.e an acute angled triangle. On Feb 24, 7:49 pm, Vikas Kumar dev.vika...@gmail.com wrote: @priyaranjan No,Your triangle will be right angle triangle. In fact any triangle chosen will be right angle triangle. Proof: suppose there are 2 planes kept at parallel with each other.(top bottom) join corresponding vertices of up to down and form cube. Now 3 points chosen can be on same plane .(means 2 must be adjacent) so right angle triangle is only possible or at least 2 points are on same plane and 3rd point is other plane(pigeon hole as only 2 holes are there for 3 pegions) Now as 3 rd point always lies on perpendicular point so triagle formed will always be right angled. On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid priyaranjan@gmail.comwrote: The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
@Priyaranjan. Right. I should have directed my comment to Vikas. Sorry. Dave On Feb 24, 9:35 pm, awesomeandroid priyaranjan@gmail.com wrote: @dave i never said it will be a right angled triangle ,it will be a equilateral triangle and thus an acute angled triangle. On Feb 24, 8:38 pm, Dave dave_and_da...@juno.com wrote: @Priyaranjan: Suppose that the cube has side 1 and is placed in standard position at the origin. Then the triangle with vertices (0,0,0), (1,0,1), and (1,1,0) is equilateral with side sqrt(2), and therefore is not a right triangle. Dave On Feb 24, 8:49 am, Vikas Kumar dev.vika...@gmail.com wrote: @priyaranjan No,Your triangle will be right angle triangle. In fact any triangle chosen will be right angle triangle. Proof: suppose there are 2 planes kept at parallel with each other.(top bottom) join corresponding vertices of up to down and form cube. Now 3 points chosen can be on same plane .(means 2 must be adjacent) so right angle triangle is only possible or at least 2 points are on same plane and 3rd point is other plane(pigeon hole as only 2 holes are there for 3 pegions) Now as 3 rd point always lies on perpendicular point so triagle formed will always be right angled. On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid priyaranjan@gmail.comwrote: The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.-Hidequoted text - - Show quoted text -- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
@Vikas: Suppose that the cube has side 1 and is placed in standard position at the origin. Then the triangle with vertices (0,0,0), (1,0,1), and (1,1,0) is equilateral with side sqrt(2), and therefore is not a right triangle. Dave On Feb 24, 8:49 am, Vikas Kumar dev.vika...@gmail.com wrote: @priyaranjan No,Your triangle will be right angle triangle. In fact any triangle chosen will be right angle triangle. Proof: suppose there are 2 planes kept at parallel with each other.(top bottom) join corresponding vertices of up to down and form cube. Now 3 points chosen can be on same plane .(means 2 must be adjacent) so right angle triangle is only possible or at least 2 points are on same plane and 3rd point is other plane(pigeon hole as only 2 holes are there for 3 pegions) Now as 3 rd point always lies on perpendicular point so triagle formed will always be right angled. On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid priyaranjan@gmail.comwrote: The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways. Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: intel puzzle
Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: intel puzzle
answer is 8 ,,, duno how On Wed, Feb 23, 2011 at 12:31 AM, Sundi sundi...@gmail.com wrote: Is it not 8C3 = 56 On Feb 22, 9:55 pm, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: Think of the 8 vertices of a given cube. You are allowed to join three vertices to form a triangle. How many such unique acute triangles can you make ?? -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
