[algogeeks] Re: plz help

2011-09-21 Thread siva viknesh
somebody try to execute in linux and try to find the output...expected
output is 9but when first in ideone without \n in printf it showed
7 .. then with \n it showed 10... again with \n it showed 10 !!! ..
whether its prob with compiler or fork's execution is differing i'm
confused :(

On Sep 22, 1:34 am, Rashmi Jain rashmi.jain...@gmail.com wrote:
 but in this output 10  times hello is printed..how..??







 On Thu, Sep 22, 2011 at 1:52 AM, ravi maggon maggonr...@gmail.com wrote:
  This is the output I am getting

     -

     result: Success     time: 0s    memory: 1720 kB     returned value: 0
      input: no
      output:

     HelloHelloHelloHelloHelloHelloHelloHelloHelloHello

  On Thu, Sep 22, 2011 at 1:40 AM, teja bala pawanjalsa.t...@gmail.comwrote:

  @ ravi but compile it onhttp://ideone.com/nkTVN it showing 45 hello plz
  do look at it...

  On Thu, Sep 22, 2011 at 12:59 AM, Rashmi Jain 
  rashmi.jain...@gmail.comwrote:

  @ravi: thanks..!!

  On Thu, Sep 22, 2011 at 12:54 AM, ravi maggon maggonr...@gmail.comwrote:

  ohh sorry, I thought it was i=9. Yes only 9 times Hello will be
  printed.

  On Thu, Sep 22, 2011 at 12:52 AM, Rashmi Jain rashmi.jain...@gmail.com
   wrote:

  @ravi
  can u plz explain how 10 processes are created..? shouldn't it be 9..??

  On Thu, Sep 22, 2011 at 12:23 AM, ravi maggon 
  maggonr...@gmail.comwrote:

  Output Hello printed 10 times. Since form command spawns the process,
  so for every call their are two process created and since if process 
  gets
  successfully created fork returns some positive no. which is the 
  process id,
  so it will break the loop and finally only the 10 child processes will 
  be
  left which will print Hello 10 times. I hope that I cleared your doubt.

  On Thu, Sep 22, 2011 at 12:03 AM, Anil Arya 
  anilarya...@gmail.comwrote:

 http://ideone.com/nkTVN

  On Wed, Sep 21, 2011 at 11:43 PM, Saravana kumar 
  saravana@gmail.com wrote:

  Hello will be printed 45 times...

  On Wed, Sep 21, 2011 at 7:57 PM, sush57 sushaant...@gmail.comwrote:

  main()
  {
         int tmp;
         for(i=0;i9;i++)
         {
                 tmp=fork();
                 if(tmp0)
                         break;
                 printf(Hello);
         }
  }

  what's the output and how does this work

  can u give few other questions using fork...

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  Thapar University

 www.algorithmguru.com

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 www.algorithmguru.com

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[algogeeks] Re: plz help

2011-09-21 Thread siva viknesh
http://ideone.com/l5ek4   .. in this it had shown 6

http://ideone.com/Lj56O  .. here 10 

On Sep 22, 8:27 am, siva viknesh sivavikne...@gmail.com wrote:
 somebody try to execute in linux and try to find the output...expected
 output is 9but when first in ideone without \n in printf it showed
 7 .. then with \n it showed 10... again with \n it showed 10 !!! ..
 whether its prob with compiler or fork's execution is differing i'm
 confused :(

 On Sep 22, 1:34 am, Rashmi Jain rashmi.jain...@gmail.com wrote:







  but in this output 10  times hello is printed..how..??

  On Thu, Sep 22, 2011 at 1:52 AM, ravi maggon maggonr...@gmail.com wrote:
   This is the output I am getting

      -

      result: Success     time: 0s    memory: 1720 kB     returned value: 0
       input: no
       output:

      HelloHelloHelloHelloHelloHelloHelloHelloHelloHello

   On Thu, Sep 22, 2011 at 1:40 AM, teja bala 
   pawanjalsa.t...@gmail.comwrote:

   @ ravi but compile it onhttp://ideone.com/nkTVN it showing 45 hello plz
   do look at it...

   On Thu, Sep 22, 2011 at 12:59 AM, Rashmi Jain 
   rashmi.jain...@gmail.comwrote:

   @ravi: thanks..!!

   On Thu, Sep 22, 2011 at 12:54 AM, ravi maggon 
   maggonr...@gmail.comwrote:

   ohh sorry, I thought it was i=9. Yes only 9 times Hello will be
   printed.

   On Thu, Sep 22, 2011 at 12:52 AM, Rashmi Jain rashmi.jain...@gmail.com
wrote:

   @ravi
   can u plz explain how 10 processes are created..? shouldn't it be 
   9..??

   On Thu, Sep 22, 2011 at 12:23 AM, ravi maggon 
   maggonr...@gmail.comwrote:

   Output Hello printed 10 times. Since form command spawns the process,
   so for every call their are two process created and since if process 
   gets
   successfully created fork returns some positive no. which is the 
   process id,
   so it will break the loop and finally only the 10 child processes 
   will be
   left which will print Hello 10 times. I hope that I cleared your 
   doubt.

   On Thu, Sep 22, 2011 at 12:03 AM, Anil Arya 
   anilarya...@gmail.comwrote:

  http://ideone.com/nkTVN

   On Wed, Sep 21, 2011 at 11:43 PM, Saravana kumar 
   saravana@gmail.com wrote:

   Hello will be printed 45 times...

   On Wed, Sep 21, 2011 at 7:57 PM, sush57 
   sushaant...@gmail.comwrote:

   main()
   {
          int tmp;
          for(i=0;i9;i++)
          {
                  tmp=fork();
                  if(tmp0)
                          break;
                  printf(Hello);
          }
   }

   what's the output and how does this work

   can u give few other questions using fork...

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   Computer Science *
   *Motilal Nehru National Institute of Technology,Allahabad .
   *

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   Ravi Maggon
   B.E. CSE, Final Year
   Thapar University

  www.algorithmguru.com

   *Failure is the opportunity to begin again more intelligently*

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   B.E. CSE, Final Year
   Thapar University

  www.algorithmguru.com

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[algogeeks] Re: plz help

2011-09-21 Thread siva viknesh
if anybody knows other good online compilers try to post ... codepad
doesn't support fork

On Sep 22, 8:29 am, siva viknesh sivavikne...@gmail.com wrote:
 http://ideone.com/l5ek4  .. in this it had shown 6

 http://ideone.com/Lj56O .. here 10 

 On Sep 22, 8:27 am, siva viknesh sivavikne...@gmail.com wrote:







  somebody try to execute in linux and try to find the output...expected
  output is 9but when first in ideone without \n in printf it showed
  7 .. then with \n it showed 10... again with \n it showed 10 !!! ..
  whether its prob with compiler or fork's execution is differing i'm
  confused :(

  On Sep 22, 1:34 am, Rashmi Jain rashmi.jain...@gmail.com wrote:

   but in this output 10  times hello is printed..how..??

   On Thu, Sep 22, 2011 at 1:52 AM, ravi maggon maggonr...@gmail.com wrote:
This is the output I am getting

   -

   result: Success     time: 0s    memory: 1720 kB     returned value: 0
    input: no
    output:

   HelloHelloHelloHelloHelloHelloHelloHelloHelloHello

On Thu, Sep 22, 2011 at 1:40 AM, teja bala 
pawanjalsa.t...@gmail.comwrote:

@ ravi but compile it onhttp://ideone.com/nkTVN it showing 45 hello plz
do look at it...

On Thu, Sep 22, 2011 at 12:59 AM, Rashmi Jain 
rashmi.jain...@gmail.comwrote:

@ravi: thanks..!!

On Thu, Sep 22, 2011 at 12:54 AM, ravi maggon 
maggonr...@gmail.comwrote:

ohh sorry, I thought it was i=9. Yes only 9 times Hello will be
printed.

On Thu, Sep 22, 2011 at 12:52 AM, Rashmi Jain 
rashmi.jain...@gmail.com
 wrote:

@ravi
can u plz explain how 10 processes are created..? shouldn't it be 
9..??

On Thu, Sep 22, 2011 at 12:23 AM, ravi maggon 
maggonr...@gmail.comwrote:

Output Hello printed 10 times. Since form command spawns the 
process,
so for every call their are two process created and since if 
process gets
successfully created fork returns some positive no. which is the 
process id,
so it will break the loop and finally only the 10 child processes 
will be
left which will print Hello 10 times. I hope that I cleared your 
doubt.

On Thu, Sep 22, 2011 at 12:03 AM, Anil Arya 
anilarya...@gmail.comwrote:

   http://ideone.com/nkTVN

On Wed, Sep 21, 2011 at 11:43 PM, Saravana kumar 
saravana@gmail.com wrote:

Hello will be printed 45 times...

On Wed, Sep 21, 2011 at 7:57 PM, sush57 
sushaant...@gmail.comwrote:

main()
{
       int tmp;
       for(i=0;i9;i++)
       {
               tmp=fork();
               if(tmp0)
                       break;
               printf(Hello);
       }
}

what's the output and how does this work

can u give few other questions using fork...

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Computer Science *
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*

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Thapar University

   www.algorithmguru.com

*Failure is the opportunity to begin again more intelligently*

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[algogeeks] Re: plz help

2011-09-21 Thread siva viknesh
expected op is 9 .. since on each iteration parent process gets
cancelled out (its pid  0 ) and child process alone prints hello ..
no chance of getting 10 or any other output .. correct me if m wrong !

On Sep 22, 8:31 am, siva viknesh sivavikne...@gmail.com wrote:
 if anybody knows other good online compilers try to post ... codepad
 doesn't support fork

 On Sep 22, 8:29 am, siva viknesh sivavikne...@gmail.com wrote:







 http://ideone.com/l5ek4 .. in this it had shown 6

 http://ideone.com/Lj56O .. here 10 

  On Sep 22, 8:27 am, siva viknesh sivavikne...@gmail.com wrote:

   somebody try to execute in linux and try to find the output...expected
   output is 9but when first in ideone without \n in printf it showed
   7 .. then with \n it showed 10... again with \n it showed 10 !!! ..
   whether its prob with compiler or fork's execution is differing i'm
   confused :(

   On Sep 22, 1:34 am, Rashmi Jain rashmi.jain...@gmail.com wrote:

but in this output 10  times hello is printed..how..??

On Thu, Sep 22, 2011 at 1:52 AM, ravi maggon maggonr...@gmail.com 
wrote:
 This is the output I am getting

    -

    result: Success     time: 0s    memory: 1720 kB     returned 
 value: 0
     input: no
     output:

    HelloHelloHelloHelloHelloHelloHelloHelloHelloHello

 On Thu, Sep 22, 2011 at 1:40 AM, teja bala 
 pawanjalsa.t...@gmail.comwrote:

 @ ravi but compile it onhttp://ideone.com/nkTVN it showing 45 hello 
 plz
 do look at it...

 On Thu, Sep 22, 2011 at 12:59 AM, Rashmi Jain 
 rashmi.jain...@gmail.comwrote:

 @ravi: thanks..!!

 On Thu, Sep 22, 2011 at 12:54 AM, ravi maggon 
 maggonr...@gmail.comwrote:

 ohh sorry, I thought it was i=9. Yes only 9 times Hello will be
 printed.

 On Thu, Sep 22, 2011 at 12:52 AM, Rashmi Jain 
 rashmi.jain...@gmail.com
  wrote:

 @ravi
 can u plz explain how 10 processes are created..? shouldn't it be 
 9..??

 On Thu, Sep 22, 2011 at 12:23 AM, ravi maggon 
 maggonr...@gmail.comwrote:

 Output Hello printed 10 times. Since form command spawns the 
 process,
 so for every call their are two process created and since if 
 process gets
 successfully created fork returns some positive no. which is the 
 process id,
 so it will break the loop and finally only the 10 child 
 processes will be
 left which will print Hello 10 times. I hope that I cleared your 
 doubt.

 On Thu, Sep 22, 2011 at 12:03 AM, Anil Arya 
 anilarya...@gmail.comwrote:

http://ideone.com/nkTVN

 On Wed, Sep 21, 2011 at 11:43 PM, Saravana kumar 
 saravana@gmail.com wrote:

 Hello will be printed 45 times...

 On Wed, Sep 21, 2011 at 7:57 PM, sush57 
 sushaant...@gmail.comwrote:

 main()
 {
        int tmp;
        for(i=0;i9;i++)
        {
                tmp=fork();
                if(tmp0)
                        break;
                printf(Hello);
        }
 }

 what's the output and how does this work

 can u give few other questions using fork...

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 Computer Science *
 *Motilal Nehru National Institute of Technology,Allahabad .
 *

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 Regards
 Ravi Maggon
 B.E. CSE, Final Year
 Thapar University

www.algorithmguru.com

 *Failure is the opportunity to begin again more intelligently*

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Re: [algogeeks] Re: plz help

2011-09-21 Thread ravi maggon
I tried to run code on Mac Os and getting output as 9 times Hello.

On Thu, Sep 22, 2011 at 9:19 AM, siva viknesh sivavikne...@gmail.comwrote:

 expected op is 9 .. since on each iteration parent process gets
 cancelled out (its pid  0 ) and child process alone prints hello ..
 no chance of getting 10 or any other output .. correct me if m wrong !

 On Sep 22, 8:31 am, siva viknesh sivavikne...@gmail.com wrote:
  if anybody knows other good online compilers try to post ... codepad
  doesn't support fork
 
  On Sep 22, 8:29 am, siva viknesh sivavikne...@gmail.com wrote:
 
 
 
 
 
 
 
  http://ideone.com/l5ek4 .. in this it had shown 6
 
  http://ideone.com/Lj56O .. here 10 
 
   On Sep 22, 8:27 am, siva viknesh sivavikne...@gmail.com wrote:
 
somebody try to execute in linux and try to find the
 output...expected
output is 9but when first in ideone without \n in printf it
 showed
7 .. then with \n it showed 10... again with \n it showed 10 !!! ..
whether its prob with compiler or fork's execution is differing i'm
confused :(
 
On Sep 22, 1:34 am, Rashmi Jain rashmi.jain...@gmail.com wrote:
 
 but in this output 10  times hello is printed..how..??
 
 On Thu, Sep 22, 2011 at 1:52 AM, ravi maggon maggonr...@gmail.com
 wrote:
  This is the output I am getting
 
 -
 
 result: Success time: 0smemory: 1720 kB returned
 value: 0
  input: no
  output:
 
 HelloHelloHelloHelloHelloHelloHelloHelloHelloHello
 
  On Thu, Sep 22, 2011 at 1:40 AM, teja bala 
 pawanjalsa.t...@gmail.comwrote:
 
  @ ravi but compile it onhttp://ideone.com/nkTVN it showing 45
 hello plz
  do look at it...
 
  On Thu, Sep 22, 2011 at 12:59 AM, Rashmi Jain 
 rashmi.jain...@gmail.comwrote:
 
  @ravi: thanks..!!
 
  On Thu, Sep 22, 2011 at 12:54 AM, ravi maggon 
 maggonr...@gmail.comwrote:
 
  ohh sorry, I thought it was i=9. Yes only 9 times Hello will
 be
  printed.
 
  On Thu, Sep 22, 2011 at 12:52 AM, Rashmi Jain 
 rashmi.jain...@gmail.com
   wrote:
 
  @ravi
  can u plz explain how 10 processes are created..? shouldn't
 it be 9..??
 
  On Thu, Sep 22, 2011 at 12:23 AM, ravi maggon 
 maggonr...@gmail.comwrote:
 
  Output Hello printed 10 times. Since form command spawns the
 process,
  so for every call their are two process created and since if
 process gets
  successfully created fork returns some positive no. which is
 the process id,
  so it will break the loop and finally only the 10 child
 processes will be
  left which will print Hello 10 times. I hope that I cleared
 your doubt.
 
  On Thu, Sep 22, 2011 at 12:03 AM, Anil Arya 
 anilarya...@gmail.comwrote:
 
 http://ideone.com/nkTVN
 
  On Wed, Sep 21, 2011 at 11:43 PM, Saravana kumar 
  saravana@gmail.com wrote:
 
  Hello will be printed 45 times...
 
  On Wed, Sep 21, 2011 at 7:57 PM, sush57 
 sushaant...@gmail.comwrote:
 
  main()
  {
 int tmp;
 for(i=0;i9;i++)
 {
 tmp=fork();
 if(tmp0)
 break;
 printf(Hello);
 }
  }
 
  what's the output and how does this work
 
  can u give few other questions using fork...
 
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  Computer Science *
  *Motilal Nehru National Institute of Technology,Allahabad .
  *
 
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[algogeeks] Re: plz help for C output

2011-09-10 Thread abhishek
@ abhinav  u r right

could you plz explain how?

On Sep 10, 12:50 pm, abhinav gupta guptaabhinav...@gmail.com wrote:
 a) 100









 On Sat, Sep 10, 2011 at 12:40 AM, abhishek abhishek.ma...@gmail.com wrote:
  (a)

  #define f(g,g2) g##g2
  int main()
  {
   int var12=100;
   printf(%d,f(var,12));
     getch();
     }

  what will be the output??

  (b)

  main()
  {
  int i=400,j-300;
  printf(%d...%d);
  }

  (c)

  void main()
  {
  char far *farther,* farthest ;
  printf(%d..%d,sizeof(father),sizeof(farthest));
  }

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[algogeeks] Re: plz help for C output

2011-09-10 Thread abhishek
@ parag

u r right

could u explain how??

On Sep 10, 12:51 pm, parag khanna khanna.para...@gmail.com wrote:
 1. 100
 2. 400...300
 3. 4 .. 2

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 B.tech Final Year
 NIT,Kurukshetra

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[algogeeks] Re: plz help

2011-09-07 Thread sush57
finally what's the answer

On Sep 7, 5:36 pm, rahul vatsa vatsa.ra...@gmail.com wrote:
 again sry, its 1 oly :P







 On Wed, Sep 7, 2011 at 8:35 AM, rahul vatsa vatsa.ra...@gmail.com wrote:
  sry, wrongly i ve written 1 in 1st ln of my prev mail. its 25.

  On Wed, Sep 7, 2011 at 8:30 AM, rahul vatsa vatsa.ra...@gmail.com wrote:

  i think it should be 1.
  5/2 paintings r made by 5/2 ppl in 5/2 days  using 5/2 canvas
  = 1 painting is made by 1 person in 1 day using 1 canvas

  i.e. 1 guy cn make a painting in 1 day using a canvas.

  Now, the other case, to make 25 paintings using 25 canvases in 25 days.

  As there r 25 days  total paintings required is 25, so u need just 1 guy
  to do that. u have here 25 canvases, bt he cn make using just 1.

  On Wed, Sep 7, 2011 at 8:15 AM, sush57 sushaant...@gmail.com wrote:

  If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
  how many artists r
  required to make 25 paintings using 25 canvases in 25 days?

  some sayin 25,some sayin 1...can anyone pls explain the answer
  for this puzzle...

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[algogeeks] Re: plz help

2011-09-07 Thread Dave
@Rahul: No, no, no. If you double the people and don't change the
number of days, you double the number of paintings. Similarly, if you
double the number of days and don't change the number of people, you
double the number of paintings. The number of paintings is _jointly
proportional_ to the number of people and the number of days. Thus,
paintings = constant * people * days.

We can use the given data to solve for the constant: 5/2 = c * 5/2 *
5/2, so c = 2/5.

Finally, 25 = 2/5 * people * 25, so people = 5/2.

Dave

On Sep 7, 7:30 am, rahul vatsa vatsa.ra...@gmail.com wrote:
 i think it should be 1.
 5/2 paintings r made by 5/2 ppl in 5/2 days  using 5/2 canvas
 = 1 painting is made by 1 person in 1 day using 1 canvas

 i.e. 1 guy cn make a painting in 1 day using a canvas.

 Now, the other case, to make 25 paintings using 25 canvases in 25 days.

 As there r 25 days  total paintings required is 25, so u need just 1 guy to
 do that. u have here 25 canvases, bt he cn make using just 1.



 On Wed, Sep 7, 2011 at 8:15 AM, sush57 sushaant...@gmail.com wrote:
  If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
  how many artists r
  required to make 25 paintings using 25 canvases in 25 days?

  some sayin 25,some sayin 1...can anyone pls explain the answer
  for this puzzle...

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Re: [algogeeks] Re: plz help

2011-09-07 Thread rahul vatsa
@sushanth, its 1.

@dave, no of days  no of paintings required are 25. And we need to find out
how many ppl r required for this. obviously it will be 1 only.
if there will be more than 1 guy, the work will be finished before 25 days.

On Wed, Sep 7, 2011 at 9:11 AM, Dave dave_and_da...@juno.com wrote:

 @Rahul: No, no, no. If you double the people and don't change the
 number of days, you double the number of paintings. Similarly, if you
 double the number of days and don't change the number of people, you
 double the number of paintings. The number of paintings is _jointly
 proportional_ to the number of people and the number of days. Thus,
 paintings = constant * people * days.

 We can use the given data to solve for the constant: 5/2 = c * 5/2 *
 5/2, so c = 2/5.

 Finally, 25 = 2/5 * people * 25, so people = 5/2.

 Dave

 On Sep 7, 7:30 am, rahul vatsa vatsa.ra...@gmail.com wrote:
  i think it should be 1.
  5/2 paintings r made by 5/2 ppl in 5/2 days  using 5/2 canvas
  = 1 painting is made by 1 person in 1 day using 1 canvas
 
  i.e. 1 guy cn make a painting in 1 day using a canvas.
 
  Now, the other case, to make 25 paintings using 25 canvases in 25 days.
 
  As there r 25 days  total paintings required is 25, so u need just 1 guy
 to
  do that. u have here 25 canvases, bt he cn make using just 1.
 
 
 
  On Wed, Sep 7, 2011 at 8:15 AM, sush57 sushaant...@gmail.com wrote:
   If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
   how many artists r
   required to make 25 paintings using 25 canvases in 25 days?
 
   some sayin 25,some sayin 1...can anyone pls explain the answer
   for this puzzle...
 
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[algogeeks] Re: plz help

2011-09-07 Thread Don
@Rahul: You are OBVIOUSLY wrong. Obviously.

On Sep 7, 8:16 am, rahul vatsa vatsa.ra...@gmail.com wrote:

 @dave, no of days  no of paintings required are 25. And we need to find out
 how many ppl r required for this. obviously it will be 1 only.
 if there will be more than 1 guy, the work will be finished before 25 days.



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[algogeeks] Re: plz help

2011-09-07 Thread Don
Figure out the man days per painting:
5/2 artists working for 5/2 days is 25/4 man days.
They produce 5/2 paintings, so that is 5/2 man days per painting.
Thus to make 25 paintings will require 25*5/2 man days.
To complete that work in 25 days will require 5/2 painters.
Don

On Sep 7, 7:15 am, sush57 sushaant...@gmail.com wrote:
 If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
 how many artists r
 required to make 25 paintings using 25 canvases in 25 days?

 some sayin 25,some sayin 1...can anyone pls explain the answer
 for this puzzle...

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Re: [algogeeks] Re: plz help

2011-09-07 Thread rahul vatsa
 don u r rt  :-)

On Wed, Sep 7, 2011 at 10:00 AM, Don dondod...@gmail.com wrote:

 Figure out the man days per painting:5/2 artists working for 5/2 days is
 25/4 man days.
 They produce 5/2 paintings, so that is 5/2 man days per painting.
 Thus to make 25 paintings will require 25*5/2 man days.
 To complete that work in 25 days will require 5/2 painters.
 Don

 On Sep 7, 7:15 am, sush57 sushaant...@gmail.com wrote:
  If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
  how many artists r



  required to make 25 paintings using 25 canvases in 25 days?
 
  some sayin 25,some sayin 1...can anyone pls explain the answer
  for this puzzle...

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[algogeeks] Re: plz help

2011-09-07 Thread Dave
@Rahul: Wasn't I correct, too?

Dave

On Sep 7, 9:07 am, rahul vatsa vatsa.ra...@gmail.com wrote:
  don u r rt  :-)



 On Wed, Sep 7, 2011 at 10:00 AM, Don dondod...@gmail.com wrote:
  Figure out the man days per painting:5/2 artists working for 5/2 days is
  25/4 man days.
  They produce 5/2 paintings, so that is 5/2 man days per painting.
  Thus to make 25 paintings will require 25*5/2 man days.
  To complete that work in 25 days will require 5/2 painters.
  Don

  On Sep 7, 7:15 am, sush57 sushaant...@gmail.com wrote:
   If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
   how many artists r

   required to make 25 paintings using 25 canvases in 25 days?

   some sayin 25,some sayin 1...can anyone pls explain the answer
   for this puzzle...

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Re: [algogeeks] Re: plz help

2011-09-07 Thread rahul vatsa
ya dave u r also correct :-)

On Wed, Sep 7, 2011 at 10:21 AM, Dave dave_and_da...@juno.com wrote:

 @Rahul: Wasn't I correct, too?

 Dave

 On Sep 7, 9:07 am, rahul vatsa vatsa.ra...@gmail.com wrote:
   don u r rt  :-)
 
 
 
  On Wed, Sep 7, 2011 at 10:00 AM, Don dondod...@gmail.com wrote:
   Figure out the man days per painting:5/2 artists working for 5/2 days
 is
   25/4 man days.
   They produce 5/2 paintings, so that is 5/2 man days per painting.
   Thus to make 25 paintings will require 25*5/2 man days.
   To complete that work in 25 days will require 5/2 painters.
   Don
 
   On Sep 7, 7:15 am, sush57 sushaant...@gmail.com wrote:
If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
how many artists r
 
required to make 25 paintings using 25 canvases in 25 days?
 
some sayin 25,some sayin 1...can anyone pls explain the
 answer
for this puzzle...
 
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[algogeeks] Re: plz help

2011-09-07 Thread SVIX
i think u can ignore number of canvases here...

artists and days are inversely proportional while artists and
paintings are directly proportional.

artistspaintingsdays
-   ---  -
5/25/2 5/2
so,
1   5/2 25/4
1/45/2 25

so, for (5/2) * 10 paintings (25 paintings), u'll need 10 times more
artists

artistspaintingsdays
-   ---  -
 (1/4)*10(5/2)*1025

which is 5/2 artists...

On Sep 7, 5:15 am, sush57 sushaant...@gmail.com wrote:
 If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then
 how many artists r
 required to make 25 paintings using 25 canvases in 25 days?

 some sayin 25,some sayin 1...can anyone pls explain the answer
 for this puzzle...

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Re: [algogeeks] Re: PLz help urgent

2011-08-26 Thread mani walia
i also want to know buddy.. if u knw thn help me buddy

On Thu, Aug 25, 2011 at 11:01 PM, vivek vivek.thapar2...@gmail.com wrote:

 hello  buddy...hows u...american express
 also cuming to our campus,..have u got any info abt its
 technical written and apti written test that questions mainly comes from
 whch technical subject and whch portions of aptitude...
 pls  help me buddy

 its very urgent..

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[algogeeks] Re: PLz help urgent

2011-08-25 Thread vivek
hello  buddy...hows u...american express 
also cuming to our campus,..have u got any info abt its 
technical written and apti written test that questions mainly comes from 
whch technical subject and whch portions of aptitude...
pls  help me buddy

its very urgent..

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[algogeeks] Re: plz help with this

2011-08-02 Thread Gayathri Anandan
Ya correct, I didnt see that. Now I got it. I added the condition
s==e-1. Thanks a lot.

On Aug 2, 3:12 pm, durgaprasad k durga...@gmail.com wrote:
 I think the code is running infinity times as there is no checking condition
 when to stop the calculation of max value. so before going to the max
 function there should be a checking till when you need to run the loop.

 Regards,
 Durga

 On Tue, Aug 2, 2011 at 2:30 PM, Gayathri Anandan 







 gayathriananda...@gmail.com wrote:
  I didnt get any output for this pgm. I think its keep on running and
  got struck in the 6th line. Plz help with this.

  1 #includestdio.h
  2 #includeconio.h
  3 int max(int a[10],int s,int e)
  4 {
  5 int res,res1,res2,mid=(s+e-1)/2;
  6 res1=max(a,s,mid+1);
  7 res2=max(a,mid+1,e);
  8 res=res1res2?res1:res2;
  9 return res;
  10 }
  void main()
  {
  int a[]={2,4,1,2,3,8,7,6,9},maxval;
  maxval=max(a,0,9);
  printf(%d,maxval);
  getch();
  }

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[algogeeks] Re: Plz help with multidimensional array

2010-07-08 Thread Devendra Pratap Singh
u can access arr[0],arr[1],arr[2] in following way ...


#include stdio.h

int main()
{
char name[3][10] = {jan,feb,march};
char (*p)[10] = name;

int i;

for(i=0;i=3;i++){
printf(%s\n,p);
p = p+1;
}

return 0;
}

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