Re: [algogeeks] address calculation

2011-08-06 Thread rajeev bharshetty
@aditi : I Think the output depends on whether it is row major or column
major representation in memory .
 Does he row amjor or column

On Sun, Aug 7, 2011 at 12:19 AM, aditi garg wrote:

> oh @ akshay y ru doing 10x4??? 10 is the no of rows not the columns so it
> shud be 15x3+4...and by multiplying by 4(in 10x4) ur taking it to the 5th
> row ie A[4][4] its only A[3][4]...
> i hope its clear now
>
>
>
> On Sun, Aug 7, 2011 at 12:14 AM, akshay khatri 
> wrote:
>
>>
>>
>> On 6 August 2011 23:56, aditi garg  wrote:
>>
>>> @akshay: what i meant ws suppose the array strted from  in
>>> decimal...so A[3][4] wud be at 0049 and B[3][4] will be at 0196
>>> convert dese 2 values to hex it gives 31 and C4 respectively...now base
>>> address is 1000 and 2000 instead if  so add the base address and u get
>>> the ans 1031 and 20C4...i hope its clear now...
>>>
>>
>> I still don't get how you got the figures of 49 and 196
>>
>> I calculated as follows
>> A[3][4] = 10x4 + 4 = 44 bytes
>> B[3][4] = (10x4 + 4 )x4 = 176
>>
>>>
>>>
>>> On Sat, Aug 6, 2011 at 11:49 PM, akshay khatri <
>>> akshaykhatri...@gmail.com> wrote:
>>>


 On 6 August 2011 23:40, aditi garg  wrote:

> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 
> rows
> + 16 fr the 4th elemnet so 196
>

 How does it start from 46 and 180 ?
 as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192


>
>  On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri <
> akshaykhatri...@gmail.com> wrote:
>
>> how is that 49 bytes and 196 bytes
>> shouldn't it be 44 and 176 bytes respectively
>>
>>
>> On 6 August 2011 23:26, Ram Chauhan  wrote:
>>
>>> 1049 and 1098
>>>
>>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg <
>>> aditi.garg.6...@gmail.com> wrote:
>>>
 CHAR A[10][15] AND INT B[10][15] IS DEFINED
 WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
 IF ADDRESS OF A IS OX1000 AND B IS 0X2000

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Re: [algogeeks] address calculation

2011-08-06 Thread aditi garg
oh @ akshay y ru doing 10x4??? 10 is the no of rows not the columns so it
shud be 15x3+4...and by multiplying by 4(in 10x4) ur taking it to the 5th
row ie A[4][4] its only A[3][4]...
i hope its clear now


On Sun, Aug 7, 2011 at 12:14 AM, akshay khatri wrote:

>
>
> On 6 August 2011 23:56, aditi garg  wrote:
>
>> @akshay: what i meant ws suppose the array strted from  in
>> decimal...so A[3][4] wud be at 0049 and B[3][4] will be at 0196
>> convert dese 2 values to hex it gives 31 and C4 respectively...now base
>> address is 1000 and 2000 instead if  so add the base address and u get
>> the ans 1031 and 20C4...i hope its clear now...
>>
>
> I still don't get how you got the figures of 49 and 196
>
> I calculated as follows
> A[3][4] = 10x4 + 4 = 44 bytes
> B[3][4] = (10x4 + 4 )x4 = 176
>
>>
>>
>> On Sat, Aug 6, 2011 at 11:49 PM, akshay khatri > > wrote:
>>
>>>
>>>
>>> On 6 August 2011 23:40, aditi garg  wrote:
>>>
 A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 
 rows
 + 16 fr the 4th elemnet so 196

>>>
>>> How does it start from 46 and 180 ?
>>> as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192
>>>
>>>

  On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri <
 akshaykhatri...@gmail.com> wrote:

> how is that 49 bytes and 196 bytes
> shouldn't it be 44 and 176 bytes respectively
>
>
> On 6 August 2011 23:26, Ram Chauhan  wrote:
>
>> 1049 and 1098
>>
>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg <
>> aditi.garg.6...@gmail.com> wrote:
>>
>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>>
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 --
 Aditi Garg
 Undergraduate Student
 Electronics & Communication Divison
 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
 New Delhi


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>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
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Re: [algogeeks] address calculation

2011-08-06 Thread akshay khatri
On 6 August 2011 23:56, aditi garg  wrote:

> @akshay: what i meant ws suppose the array strted from  in decimal...so
> A[3][4] wud be at 0049 and B[3][4] will be at 0196
> convert dese 2 values to hex it gives 31 and C4 respectively...now base
> address is 1000 and 2000 instead if  so add the base address and u get
> the ans 1031 and 20C4...i hope its clear now...
>

I still don't get how you got the figures of 49 and 196

I calculated as follows
A[3][4] = 10x4 + 4 = 44 bytes
B[3][4] = (10x4 + 4 )x4 = 176

>
>
> On Sat, Aug 6, 2011 at 11:49 PM, akshay khatri 
> wrote:
>
>>
>>
>> On 6 August 2011 23:40, aditi garg  wrote:
>>
>>> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
>>> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows
>>> + 16 fr the 4th elemnet so 196
>>>
>>
>> How does it start from 46 and 180 ?
>> as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192
>>
>>
>>>
>>>  On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri <
>>> akshaykhatri...@gmail.com> wrote:
>>>
 how is that 49 bytes and 196 bytes
 shouldn't it be 44 and 176 bytes respectively


 On 6 August 2011 23:26, Ram Chauhan  wrote:

> 1049 and 1098
>
> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg  > wrote:
>
>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>
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>>
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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
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>
>
>
> --
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> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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Re: [algogeeks] address calculation

2011-08-06 Thread aditi garg
@akshay: what i meant ws suppose the array strted from  in decimal...so
A[3][4] wud be at 0049 and B[3][4] will be at 0196
convert dese 2 values to hex it gives 31 and C4 respectively...now base
address is 1000 and 2000 instead if  so add the base address and u get
the ans 1031 and 20C4...i hope its clear now...

On Sat, Aug 6, 2011 at 11:49 PM, akshay khatri wrote:

>
>
> On 6 August 2011 23:40, aditi garg  wrote:
>
>> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
>> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows
>> + 16 fr the 4th elemnet so 196
>>
>
> How does it start from 46 and 180 ?
> as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192
>
>
>>
>> On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri > > wrote:
>>
>>> how is that 49 bytes and 196 bytes
>>> shouldn't it be 44 and 176 bytes respectively
>>>
>>>
>>> On 6 August 2011 23:26, Ram Chauhan  wrote:
>>>
 1049 and 1098

 On Sat, Aug 6, 2011 at 11:09 PM, aditi garg 
 wrote:

> CHAR A[10][15] AND INT B[10][15] IS DEFINED
> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>
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>>
>>
>>
>> --
>> Aditi Garg
>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
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Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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Re: [algogeeks] address calculation

2011-08-06 Thread akshay khatri
On 6 August 2011 23:40, aditi garg  wrote:

> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows
> + 16 fr the 4th elemnet so 196
>

How does it start from 46 and 180 ?
as per my knowledge, 0x1000 = 4096 and 0x2000 is 8192


>
> On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri 
> wrote:
>
>> how is that 49 bytes and 196 bytes
>> shouldn't it be 44 and 176 bytes respectively
>>
>>
>> On 6 August 2011 23:26, Ram Chauhan  wrote:
>>
>>> 1049 and 1098
>>>
>>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg 
>>> wrote:
>>>
 CHAR A[10][15] AND INT B[10][15] IS DEFINED
 WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
 IF ADDRESS OF A IS OX1000 AND B IS 0X2000

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>
>
>
> --
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> Undergraduate Student
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> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
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Re: [algogeeks] address calculation

2011-08-06 Thread aditi garg
A[3][4] wud be in the 4th row...so strtung address of 4th row wud be 46..and
thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows + 16 fr
the 4th elemnet so 196

On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri wrote:

> how is that 49 bytes and 196 bytes
> shouldn't it be 44 and 176 bytes respectively
>
>
> On 6 August 2011 23:26, Ram Chauhan  wrote:
>
>> 1049 and 1098
>>
>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>>
>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>>
>>> --
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Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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Re: [algogeeks] address calculation

2011-08-06 Thread akshay khatri
how is that 49 bytes and 196 bytes
shouldn't it be 44 and 176 bytes respectively

On 6 August 2011 23:26, Ram Chauhan  wrote:

> 1049 and 1098
>
> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>
>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>
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Re: [algogeeks] address calculation

2011-08-06 Thread Ram Chauhan
1049 and 1098

On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:

> CHAR A[10][15] AND INT B[10][15] IS DEFINED
> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>
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Re: [algogeeks] address calculation

2011-08-06 Thread aditi garg
@ankit ur ans is fine bt u missed a point that dey are calculating in hex so
convert ur ans to hex and it will be the same as the one i posted...
@siddharth...A[3][4] will be 49 bytes ahead of the base address...and 49 in
hex is 31 so ans will be 1031
and int (assuming 4 bytes) the value B[3][4] will be 196 bytes ahead of base
address whch in hex is C 4 hence the ans 20C4...
I hope its clear

On Sat, Aug 6, 2011 at 11:18 PM, siddharth srivastava
wrote:

>
>
> On 6 August 2011 23:15, aditi garg  wrote:
>
>> No the ans is 1031 and 20C4...
>> i got it btw...thanx :)
>>
>
> explain ?
>
>>
>>
>> On Sat, Aug 6, 2011 at 11:13 PM, Aditya Virmani > > wrote:
>>
>>> 1033,2066?
>>>
>>>
>>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg 
>>> wrote:
>>>
 CHAR A[10][15] AND INT B[10][15] IS DEFINED
 WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
 IF ADDRESS OF A IS OX1000 AND B IS 0X2000

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>>
>>
>>
>> --
>> Aditi Garg
>> Undergraduate Student
>> Electronics & Communication Divison
>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>> Sector 3, Dwarka
>> New Delhi
>>
>>
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Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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Re: [algogeeks] address calculation

2011-08-06 Thread ankit sambyal
@aditi: explain ur answer.. How u got it ?

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Re: [algogeeks] address calculation

2011-08-06 Thread siddharth srivastava
On 6 August 2011 23:15, aditi garg  wrote:

> No the ans is 1031 and 20C4...
> i got it btw...thanx :)
>

explain ?

>
>
> On Sat, Aug 6, 2011 at 11:13 PM, Aditya Virmani 
> wrote:
>
>> 1033,2066?
>>
>>
>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>>
>>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>>
>>> --
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>>>
>>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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Siddharth Srivastava

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Re: [algogeeks] address calculation

2011-08-06 Thread ankit sambyal
A[3][4]= 1049
B[3][4]= 2196

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Re: [algogeeks] address calculation

2011-08-06 Thread aditi garg
No the ans is 1031 and 20C4...
i got it btw...thanx :)

On Sat, Aug 6, 2011 at 11:13 PM, Aditya Virmani wrote:

> 1033,2066?
>
>
> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>
>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>>
>> --
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>>
>>
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-- 
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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Re: [algogeeks] address calculation

2011-08-06 Thread Aditya Virmani
1033,2066?

On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:

> CHAR A[10][15] AND INT B[10][15] IS DEFINED
> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>
> --
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>

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[algogeeks] address calculation

2011-08-06 Thread aditi garg
CHAR A[10][15] AND INT B[10][15] IS DEFINED
WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
IF ADDRESS OF A IS OX1000 AND B IS 0X2000

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