[algogeeks] probability
[image: -]14Answers http://www.careercup.com/question?id=14553727 What is the probability of being the answer correct for this question, when the answer is chosen randomly: a. 0.25 b. 0.60 c. 0.25 d. 0.50 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/nI1VXzZ6HDYJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
0.50 On Fri, Sep 7, 2012 at 6:05 PM, noname narayan.shiv...@gmail.com wrote: [image: -]14Answers http://www.careercup.com/question?id=14553727 What is the probability of being the answer correct for this question, when the answer is chosen randomly: a. 0.25 b. 0.60 c. 0.25 d. 0.50 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/nI1VXzZ6HDYJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
Hi, The answer is= (4C1/2C1)/4C1=1/2 On Fri, Sep 7, 2012 at 6:05 PM, noname narayan.shiv...@gmail.com wrote: [image: -]14Answers http://www.careercup.com/question?id=14553727 What is the probability of being the answer correct for this question, when the answer is chosen randomly: a. 0.25 b. 0.60 c. 0.25 d. 0.50 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/nI1VXzZ6HDYJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Rajat Saxena -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability of winning with two cards
there are 52 cards.. there are 3 players a1,a2,a3 each player is given 2 cards each one of A=2...J=11,Q=12,K=13..a user wins if his sum of cards is greater then the other two players sum. find the probability of a1 being the winner? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability of winning with two cards
isn't the answer will be 1/3, without any calculations :) On Thu, Jan 19, 2012 at 7:10 AM, Sundi sundi...@gmail.com wrote: there are 52 cards.. there are 3 players a1,a2,a3 each player is given 2 cards each one of A=2...J=11,Q=12,K=13..a user wins if his sum of cards is greater then the other two players sum. find the probability of a1 being the winner? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Sunny Aggrawal B.Tech. V year,CSI Indian Institute Of Technology,Roorkee -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability of winning with two cards
ya obviously...it is 1/3.no need of any data is required On 1/18/12, sunny agrawal sunny816.i...@gmail.com wrote: isn't the answer will be 1/3, without any calculations :) On Thu, Jan 19, 2012 at 7:10 AM, Sundi sundi...@gmail.com wrote: there are 52 cards.. there are 3 players a1,a2,a3 each player is given 2 cards each one of A=2...J=11,Q=12,K=13..a user wins if his sum of cards is greater then the other two players sum. find the probability of a1 being the winner? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Sunny Aggrawal B.Tech. V year,CSI Indian Institute Of Technology,Roorkee -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability question
In a railway station, there are two trains going. One in the harbour line and one in the main line, each having a frequency of 10 minutes. The main line service starts at 5 o'clock and the harbour line starts at 5.02A.M. A man goes to the station every day to catch the first train that comes.What is the probability of the man catching the first train? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability question
0.8 is correct. the man will be on the 1st train if he reaches the station after the 2nd leaves and before 1st arrives. and the probability of this happening is 8/10. On Wed, Aug 31, 2011 at 7:07 PM, swetha rahul swetharahu...@gmail.comwrote: In a railway station, there are two trains going. One in the harbour line and one in the main line, each having a frequency of 10 minutes. The main line service starts at 5 o'clock and the harbour line starts at 5.02A.M. A man goes to the station every day to catch the first train that comes.What is the probability of the man catching the first train? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Sri Harsha -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability Q(Mean nd Variance)
Let X and Y be jointly distributed random variables such that the conditional distribution of Y, given X=x, is uniform on the interval (x-1,x+1). Suppose E(X)=1 and Var(X)=5/3. Q.1 The mean of the random variable Y is First question using common data: (A) 1/2(B) 1(C) 3/2 (D) 2 Q.2 The variance of the random variable Y is Second question using common data: (A) 1/2(B) 2/3 (C) 1 (D) 2 Plz anyone provide correct answer with explanation Vijay.. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability
An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
is it 0.55... On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.comwrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
ur answer is correct but i hv a confusion that all four shots fire at a time so there may be probability that all shots hits the craft. but ur assuming that first hit + first not hit * second hit+.. plz clear my confustion On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.comwrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
i hv googled it and the answer is like The enemy aircraft will be brought down even if one of the four shots hits the aircraft. The opposite of this situation is that none of the four shots hit the aircraft. The probability that none of the four shots hit the aircraft is given by (1-0.7)(1-0.6)(1-0.5)(1-0.4) = 0.3*0.4*0.5*0.6 = 0.036 So, the probability that at least one of the four hits the aircraft = 1 – 0.036 = 0.964. On Mon, Aug 29, 2011 at 5:54 PM, vishwa vishwavam...@gmail.com wrote: is it 0.55... On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
It should be 1 - no one hits, i.e. 1 - 0.3*0.6*0.5*0.6 = 1 - 0.0540=0.9460. Correct me if m wrong.. Sanju :) On Mon, Aug 29, 2011 at 5:19 AM, Abhishek Yadav algowithabhis...@gmail.comwrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
i was abt to write it :) but u googled it :D On Mon, Aug 29, 2011 at 5:57 PM, Naman Mahor naman.ma...@gmail.com wrote: i hv googled it and the answer is like The enemy aircraft will be brought down even if one of the four shots hits the aircraft. The opposite of this situation is that none of the four shots hit the aircraft. The probability that none of the four shots hit the aircraft is given by (1-0.7)(1-0.6)(1-0.5)(1-0.4) = 0.3*0.4*0.5*0.6 = 0.036 So, the probability that at least one of the four hits the aircraft = 1 – 0.036 = 0.964. On Mon, Aug 29, 2011 at 5:54 PM, vishwa vishwavam...@gmail.com wrote: is it 0.55... On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- *Dheeraj Sharma* Comp Engg. NIT Kurukshetra +91 8950264227 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
u mean to say .964 and not .946..isnt it? On Mon, Aug 29, 2011 at 5:58 PM, Sanjay Rajpal srn...@gmail.com wrote: It should be 1 - no one hits, i.e. 1 - 0.3*0.6*0.5*0.6 = 1 - 0.0540=0.9460. Correct me if m wrong.. Sanju :) On Mon, Aug 29, 2011 at 5:19 AM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- *Dheeraj Sharma* Comp Engg. NIT Kurukshetra +91 8950264227 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
@naman: whose answer man On Mon, Aug 29, 2011 at 5:56 PM, Naman Mahor naman.ma...@gmail.com wrote: ur answer is correct but i hv a confusion that all four shots fire at a time so there may be probability that all shots hits the craft. but ur assuming that first hit + first not hit * second hit+.. plz clear my confustion On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
abhishek's answer. plz clear my confusion that i hv mentioned above. On Mon, Aug 29, 2011 at 6:04 PM, vishwa vishwavam...@gmail.com wrote: @naman: whose answer man On Mon, Aug 29, 2011 at 5:56 PM, Naman Mahor naman.ma...@gmail.comwrote: ur answer is correct but i hv a confusion that all four shots fire at a time so there may be probability that all shots hits the craft. but ur assuming that first hit + first not hit * second hit+.. plz clear my confustion On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
if first is hit then the probability will be 0.7he missed 1st chance ,, probability with which he missed is 0.3 ... same way he will try 2nd chance.. hit chance is 0.6.. but he missed first already.. so total probabilty of hit is 0.3*0.6... its the same way for all. On Mon, Aug 29, 2011 at 6:06 PM, Naman Mahor naman.ma...@gmail.com wrote: abhishek's answer. plz clear my confusion that i hv mentioned above. On Mon, Aug 29, 2011 at 6:04 PM, vishwa vishwavam...@gmail.com wrote: @naman: whose answer man On Mon, Aug 29, 2011 at 5:56 PM, Naman Mahor naman.ma...@gmail.comwrote: ur answer is correct but i hv a confusion that all four shots fire at a time so there may be probability that all shots hits the craft. but ur assuming that first hit + first not hit * second hit+.. plz clear my confustion On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability
yes .964 easy hai yaar On Mon, Aug 29, 2011 at 5:47 AM, vishwa vishwavam...@gmail.com wrote: if first is hit then the probability will be 0.7he missed 1st chance ,, probability with which he missed is 0.3 ... same way he will try 2nd chance.. hit chance is 0.6.. but he missed first already.. so total probabilty of hit is 0.3*0.6... its the same way for all. On Mon, Aug 29, 2011 at 6:06 PM, Naman Mahor naman.ma...@gmail.comwrote: abhishek's answer. plz clear my confusion that i hv mentioned above. On Mon, Aug 29, 2011 at 6:04 PM, vishwa vishwavam...@gmail.com wrote: @naman: whose answer man On Mon, Aug 29, 2011 at 5:56 PM, Naman Mahor naman.ma...@gmail.comwrote: ur answer is correct but i hv a confusion that all four shots fire at a time so there may be probability that all shots hits the craft. but ur assuming that first hit + first not hit * second hit+.. plz clear my confustion On Mon, Aug 29, 2011 at 5:49 PM, Abhishek Yadav algowithabhis...@gmail.com wrote: i guess it would be 0.7 + 0.3*0.6 + 0.3*0.4*0.5 + 0.3*0.4*0.5*0.4 =.964.correct me if i am wrong.?? On Mon, Aug 29, 2011 at 5:34 PM, Naman Mahor naman.ma...@gmail.comwrote: An anti aircraft gun can fire four shots at a time. If the probabilities of the first, second, third and the last shot hitting the enemy aircraft are 0.7, 0.6, 0.5 and 0.4, what is the probability that four shots aimed at an enemy aircraft will bring the aircraft down? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability ques
Let 'a' be a number between 1 and 100. what is the probability of choosing 'a' such that a+ (100/a) 50 -- Regards Ramya * * *Try to learn something about everything and everything about something* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability ques
@priya give the logic -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability ques
range of 'a' will be [3,47] so in this way 45/98 On Tue, Aug 23, 2011 at 10:36 PM, aayush jain ajain...@gmail.com wrote: @priya give the logic -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- *VpN Vishvkarma vpnvi...@cse.iitb.ac.in @IITB* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability ques
try substituting values for a. for a=1, 2 it's 50 for a=3, 4, 5, 6, 7... it's less than 50 when a approaches 48, 49... it's 50 the max value of a that satisfies the condition is 47. p= total numbers between 3 and 47 (inclusive of 3 and 47) / total numbers between 1 and 100 = 45/98 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability ques
possible value for a can be 1,2,48,49,50 and all (50-100] no. so prob will be 55/100 On Tue, Aug 23, 2011 at 10:41 PM, priya ramesh love.for.programm...@gmail.com wrote: try substituting values for a. for a=1, 2 it's 50 for a=3, 4, 5, 6, 7... it's less than 50 when a approaches 48, 49... it's 50 the max value of a that satisfies the condition is 47. p= total numbers between 3 and 47 (inclusive of 3 and 47) / total numbers between 1 and 100 = 45/98 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability ques
oh sorry i thought it was a+100/a50 because this same question asked by national instrument 2 day ago. in this case passibe cases wil be 44 [3-47} no so it'll be 44/100 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability ques
y its 45/98 and not 45/100 ?? On Wed, Aug 24, 2011 at 9:41 AM, Manoj Bagari manojbag...@gmail.com wrote: oh sorry i thought it was a+100/a50 because this same question asked by national instrument 2 day ago. in this case passibe cases wil be 44 [3-47} no so it'll be 44/100 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- *Dheeraj Sharma* Comp Engg. NIT Kurukshetra +91 8950264227 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability
let's say A keep tossing a fair coin, until he get 2 consecutive heads,
define X to be the number of tosses for this process; B keep tossing another
fair coin, until he get 3 consecutive heads, define Y to be the number of
the tosses for this process.Calculate P{XY}
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[algogeeks] probability! tough one to crack!
A 1 inch diameter coin is thrown on a table covered with a grid of lines two inches apart. What is the probability the coin lands in a square without touching any of the lines of the grid? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability! tough one to crack!
area of coin = pie * 1^2 = n(e) area of square= 2^2 * 4(as there are four such squares)= n(S) probablility = n(E)/n(S) = pie/16 . the ans ;) On Fri, Aug 19, 2011 at 10:20 PM, priya ramesh love.for.programm...@gmail.com wrote: A 1 inch diameter coin is thrown on a table covered with a grid of lines two inches apart. What is the probability the coin lands in a square without touching any of the lines of the grid? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- best wishes!! Vaibhav MCA -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability tough one!
what is the probability of having b'days of 2 persons on the same day in a gathering of 50 persons? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability tough one!
no of days in a year shud be 365 or 366 ?? On Wed, Aug 17, 2011 at 5:49 PM, priya ramesh love.for.programm...@gmail.com wrote: what is the probability of having b'days of 2 persons on the same day in a gathering of 50 persons? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability tough one!
nothing is specified. I guess it's 365 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability
Two person each make a single throw with a pair of dice. The probability that the sum of numbers if the dice of their throws are unequal is A. 575/648 B. 273/432 c. 264/816. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/7kJ9mvxKd_oJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability question.. help
is it 101/200?? On Wed, Aug 10, 2011 at 3:41 AM, Prakash D cegprak...@gmail.com wrote: is there anything like there should be atleast one man and one women should dance together? On Wed, Aug 10, 2011 at 2:26 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Wed, Aug 10, 2011 at 1:45 AM, Brijesh Upadhyay brijeshupadhyay...@gmail.com wrote: No thers is not.. someone has asked me this., dont know anything else about the question :| Seems like you got half of the question there. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/mqMvDgb6TqUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability question.. help
is it 100 men 100 women? On Wed, Aug 10, 2011 at 3:25 PM, programming love love.for.programm...@gmail.com wrote: is it 101/200?? On Wed, Aug 10, 2011 at 3:41 AM, Prakash D cegprak...@gmail.com wrote: is there anything like there should be atleast one man and one women should dance together? On Wed, Aug 10, 2011 at 2:26 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Wed, Aug 10, 2011 at 1:45 AM, Brijesh Upadhyay brijeshupadhyay...@gmail.com wrote: No thers is not.. someone has asked me this., dont know anything else about the question :| Seems like you got half of the question there. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/mqMvDgb6TqUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability!-need help
Please send a link where i can find hard permutations and combinations and probability questions. Please help. If you guys have good e books or materials for apti questions, please mail me. Thanks in advance. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability question.. help
100 men women dance with each other. What is the Probability that a man cannot dance with more than two women? -- Regards, Brijesh Upadhyay CSE Thapar University -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability question.. help
is there any constraint for anyone to dance? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability question.. help
No thers is not.. someone has asked me this., dont know anything else about the question :| -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/mqMvDgb6TqUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability question.. help
On Wed, Aug 10, 2011 at 1:45 AM, Brijesh Upadhyay brijeshupadhyay...@gmail.com wrote: No thers is not.. someone has asked me this., dont know anything else about the question :| Seems like you got half of the question there. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/mqMvDgb6TqUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability question.. help
is there anything like there should be atleast one man and one women should dance together? On Wed, Aug 10, 2011 at 2:26 AM, Shuaib Khan aries.shu...@gmail.com wrote: On Wed, Aug 10, 2011 at 1:45 AM, Brijesh Upadhyay brijeshupadhyay...@gmail.com wrote: No thers is not.. someone has asked me this., dont know anything else about the question :| Seems like you got half of the question there. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/mqMvDgb6TqUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability
Hello guys! Please suggest good books to learn probability, Permutations combinations. Any tips and tricks or methods regarding the ways in which the problems can be solved will help. Plz reply and help me with this. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability Puzzle
A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability Puzzle
17/80 On Sun, Aug 7, 2011 at 10:34 AM, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Probability Puzzle
Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/76ZXC3K0UDAJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
x is even number probability 0.9x + x = 1 x = 1/1.9 P(2) = P(4) = P(6) = (1 / 1.9) / 3 P(4|5|6) = (P(4) + P(6)) / 0.75 = 2 / 1.9 / 3 / 0.75 = 0.4678362573099415 -weiq On Thu, Jan 13, 2011 at 11:29 PM, snehal jain learner@gmail.com wrote: An unbalanced dice (with 6 faces, numbered from 1 to 6) is thrown. The probability that the face value is odd is 90% of the probability that the face value is even. The probability of getting any even numbered face is the same. If the probability that the face is even given that it is greater than 3 is 0.75, which one of the following options is closest to the probability that the face value exceeds 3? (A) 0.453 (B) 0.468 (C) 0.485 (D) 0.492 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability
An unbalanced dice (with 6 faces, numbered from 1 to 6) is thrown. The probability that the face value is odd is 90% of the probability that the face value is even. The probability of getting any even numbered face is the same. If the probability that the face is even given that it is greater than 3 is 0.75, which one of the following options is closest to the probability that the face value exceeds 3? (A) 0.453 (B) 0.468 (C) 0.485 (D) 0.492 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
Suppose three gunmen are A, B, and C who have a probability of 100%, 50% and 33% respectively. The shooting will start from C, then B and at last A. Now there are several possibilities for C. If C shoots B, then A would shoot C with an accuracy of 100% or in other case if C shoots A, then B would shoot him with an accuracy of 50%. So he has a probability of getting killed. We can see in either of the cases C will die. So what C will do in first round is that it will fire the shot in air. Now the scenario gets interesting. By doing this C has turned the battle among three people into two people A and B. This will increase the chances of survival of C. So now its B's turn of firing. So he can fire at either A or C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows that he will surely die so B won't do that. If B shoots A, then C will shoot B. I think this is the solution. Please point out if there are any loopholes. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] probability
hahaha... lol... shoot in air ... lamo :-)) On Sat, Jan 1, 2011 at 6:28 PM, RAHUL KUJUR kujurismonu2...@gmail.comwrote: Suppose three gunmen are A, B, and C who have a probability of 100%, 50% and 33% respectively. The shooting will start from C, then B and at last A. Now there are several possibilities for C. If C shoots B, then A would shoot C with an accuracy of 100% or in other case if C shoots A, then B would shoot him with an accuracy of 50%. So he has a probability of getting killed. We can see in either of the cases C will die. So what C will do in first round is that it will fire the shot in air. Now the scenario gets interesting. By doing this C has turned the battle among three people into two people A and B. This will increase the chances of survival of C. So now its B's turn of firing. So he can fire at either A or C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows that he will surely die so B won't do that. If B shoots A, then C will shoot B. I think this is the solution. Please point out if there are any loopholes. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Thanks Regards Salil Joshi. CSE MTech II, IITB A-414, Hostel 12 +91.9819.442.865 This is a confidential E-Mail. If it has reached you by mistake or if you are not the intended receiver, please send it back to me. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] probability
You are in duel with two other gunmen. First guy shoot with 100% accuracy, second person shoot with 50% accuracy and you shoot with 33% accuracy. Everyone will get a chance to shoot in every round and shooting will start from the guy with worst accuracy. What will you shoot in first round? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Probability of a phrase in a text document?
Hi, If I have a large corpus of text documents and I need to find the probability of occurence of a phrase like I am in the given set of text documents, how do I go about finding the value? I can very well search how many time does the phrase I am occurs in the whole set of text documents including all the sentences, but what do i divide the count by? Thanks With Regards, Abhishek S --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~--~~~~--~~--~--~---
