Re: [algogeeks] Amazon interview question
Your solution fails for a number of reasons:
1. If your array is size 1 or 0.
2. The last digit in the array is found by arr[n-1] - [n-2] not
arr[i+1]-arr[i]
3. Recursion here creates unnecessary overheard
How many times are you calling abc? Draw the recursion tree.
On Tue, Apr 9, 2013 at 11:29 AM, rahul sharma rahul23111...@gmail.comwrote:
A = {5, 3, 8, 9, 16}
After one iteration A = {3-5,8-3,9-8,16-9}={-2,5,1,7}
After second iteration A = {5-(-2),1-5,7-1} sum =7+(-4)+6=9
Given an array, return sum after n iterations
my sol/
void abc(int arr[],n)
{
for(i=0;in;i++)
arr[i]=arr[i+1]-arr[i];
abc(arr,n-1);
}
I wana ask that the complexity is o(n) or o(n)2..as loop is executed n
times..say n is 10...so fxn is called 10 timesi.e 10 n..and ignoring n
it comes out to be...n..but if we implemeted with 2 loops then
complexity is n2 ...and both sol are taking same no of iterations...please
tell whether complexity is n or n2 for above codeif it is n2 then how???
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Re: [algogeeks] Amazon interview Question
@Rashmi: I did not get your approach. I do not get emails from the group just in case you have posted a solution :( What do you mean by keeping a count? Also, are you using a hashmap? If yes, whats ur K,V? #Pralay On Tue, Feb 12, 2013 at 10:00 AM, rashmi i rash...@gmail.com wrote: Hey Pralay, Sorry, if I have missed any point.Why would we need to map the frequencies when the second problem can be solved by simply keeping a count and comparing the index values that have been already mapped. On Fri, Feb 8, 2013 at 11:19 AM, sourabh jain wsour...@gmail.com wrote: One solution for the 2nd question can be LinkedHashMap (linked list + hashmap) . Store the integer in linked list in the order of occurrence in stream and make an entry in hashmap on first occurence. Delete the integer entry from linked list on 2nd occurence and replace the reference with some special value so for 3rd time no need to touch the linked list. while printing the result print first k integers from linked list. On Fri, Feb 8, 2013 at 9:46 AM, bharat b bagana.bharatku...@gmail.comwrote: @sourabh : how do u find whether the element in stream gets repeated in heap.-- O(n) time...totally its O(nk) algo .. If we maintain max-heap with BST property on index, then it would be O(nlogk). On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain wsour...@gmail.comwrote: for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- R@$!-! DoN'T LimIt Ur cHaLlEngeS, ChAlLenGe uR LImItS. -- You received this
Re: [algogeeks] Amazon interview Question
Guys, Why can't we simply use a hashset for both the questions. hash the arr[i] and the frequencies in the hash map in the first pass. Then iterate over the array to find the first arr[i] whose freq is 1 in the hash map. For second part, keep a count and find the kth element in the array whose freq in the hashmap is 1. *Pralay MS-Comp Sci* *Univ of California* On Thu, Feb 7, 2013 at 8:16 PM, bharat b bagana.bharatku...@gmail.comwrote: @sourabh : how do u find whether the element in stream gets repeated in heap.-- O(n) time...totally its O(nk) algo .. If we maintain max-heap with BST property on index, then it would be O(nlogk). On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain wsour...@gmail.com wrote: for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
first problem can be solved using a fixed sized array if we know the range of numbers or a hash table with an appropriate hash function and it is O(N) for time and space as some solutions above already mentioned this. for the second problem, I don't think heap is the right data structure which is only good for getting min(max) element in logN time. A possible solution would be to use a combination of linked list and a hash table. For every incoming number num(i) of the stream, check if the number exists in the hash table and: 1. if it does not exist, add an entry in hash table and insert a node in linked list. HashTbl row is key,val pair of num,Node* where Node* points to the corresponding node entry in the linked list. linked list node should contain pointer(index) to the corresponding HashTblRow. It is like hash table entry pointing to corresponding node in the list and list node pointing to hash table entry.O(1) adding to hash table and list. 2. if it does exist, delete the node from hash table and find the list node address, and delete it from the list. O(1) operation To find the k-th unique number: just walk the list, O(k) On Thu, Feb 7, 2013 at 11:16 PM, bharat b bagana.bharatku...@gmail.com wrote: @sourabh : how do u find whether the element in stream gets repeated in heap.-- O(n) time...totally its O(nk) algo .. If we maintain max-heap with BST property on index, then it would be O(nlogk). On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain wsour...@gmail.com wrote: for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
One solution for the 2nd question can be LinkedHashMap (linked list + hashmap) . Store the integer in linked list in the order of occurrence in stream and make an entry in hashmap on first occurence. Delete the integer entry from linked list on 2nd occurence and replace the reference with some special value so for 3rd time no need to touch the linked list. while printing the result print first k integers from linked list. On Fri, Feb 8, 2013 at 9:46 AM, bharat b bagana.bharatku...@gmail.comwrote: @sourabh : how do u find whether the element in stream gets repeated in heap.-- O(n) time...totally its O(nk) algo .. If we maintain max-heap with BST property on index, then it would be O(nlogk). On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain wsour...@gmail.com wrote: for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
Hey Pralay, Sorry, if I have missed any point.Why would we need to map the frequencies when the second problem can be solved by simply keeping a count and comparing the index values that have been already mapped. On Fri, Feb 8, 2013 at 11:19 AM, sourabh jain wsour...@gmail.com wrote: One solution for the 2nd question can be LinkedHashMap (linked list + hashmap) . Store the integer in linked list in the order of occurrence in stream and make an entry in hashmap on first occurence. Delete the integer entry from linked list on 2nd occurence and replace the reference with some special value so for 3rd time no need to touch the linked list. while printing the result print first k integers from linked list. On Fri, Feb 8, 2013 at 9:46 AM, bharat b bagana.bharatku...@gmail.comwrote: @sourabh : how do u find whether the element in stream gets repeated in heap.-- O(n) time...totally its O(nk) algo .. If we maintain max-heap with BST property on index, then it would be O(nlogk). On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain wsour...@gmail.com wrote: for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- R@$!-! DoN'T LimIt Ur cHaLlEngeS, ChAlLenGe uR LImItS. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
was trying to do something clever. Knew it couldnt be that simple. Missed some cases. I still feel with some hacks and handling some special cases this approach would work. But considering it still takes O(n) time I am not thrilled. I am still ok with my algo taking Space for time. But probably not the other way unless there are some special constraints. Hashtable it is. Srikar On Thursday, February 7, 2013 12:35:21 PM UTC+5:30, bharat wrote: @srikar : approach2 is wrong. ex: [1, 5, 7, 66, 7, 1, 77] first window [1,5,7] all are unique.oops On Wed, Feb 6, 2013 at 11:31 PM, Srikar srika...@gmail.com javascript:wrote: *APPROACH 1:* use a hashtable for both the questions ? Insert the integers as they are given in the array into a hashtable. The structure I am thinking is key (the integer) - [index]. Once all elements are inserted. Run through the hashtable and select the one which has len(value) == 1 and is least, since we want the first unique integer. for the second Q, its a more general Q of the first one. In first k=1. space: 2O(n) time: 2O(n) *APPROACH2: * When we say unique, we will have a pattern. Eg: [5, 5, 66, 66, 7, 1, 1, 77]. In this lets have moving window of 3. first consider (5,5,66). we can easily estab. that there is duplicate here. So move the window by 1 element so we get (5,66,66). Same here. move to next (66,66,7). Again dups here. next (66,7,1). No dups here! take the middle element as this has to be the first unique in the set. The left element belongs to the dup so could 1. Hence 7 is the first unique element. space: O(1) time: O(n) For seond Q I still think hashtable is best. As the numbers are streamed, keep inserting. Srikar On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet@gmail.com javascript: wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.an...@gmail.comjavascript: wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet@gmail.com javascript: wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+...@googlegroups.com javascript:. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+...@googlegroups.com javascript:. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+...@googlegroups.com javascript:. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+...@googlegroups.com javascript:. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
I guess the part 1 can be solved in O(n) time and space both. Here is my
approach.
Assume: Array given is arr[] = {2,3,1,2,3,2,4,1,5,6}
1. Given an array, scan thru it, element by element and hash it on a
hashmap with key as the arr[i] as the key and i+1 as the index.
2. There would be two cases
a) arr[i] is already there in the hash map, if so, check if the
hashmap.get(arr[i]) is a negative or not. If it is negative , do nothing.
If its is not negative, negate it.
b) arr[i] is a new element, in such a case, hash key as arr[i] and i+1
as the value.
3. Scan thru the value set, the key corresponding to minimum of positive
values is the answer.
Example.
For {2,3,1,2,3,2,4,1, 5,6}
2 = not seen, hash 2,1 (arr[i], i+1)
3 = not seen, hash 3, 2
1 = not seen, hash 1,3
2 = seen - is the value corresponding to key 2 negative = No. So negate
it- hash entry now becomes 2,-1
3 = similar to above - Hash entry is 3,-2
2 = seen, is the value negative = yes, do nothing
4 = not seen, hash 4,8
1 = seen, is the value corresponding to key 1 -ve? No, negate it, hashentry
= 1,-3
5 = not seen, hash 5,10
6= not seen, hash 6,11
Hasmap ready. Whats the value set (the values only) ? -1,-2,-3,8,10,11
Whats the *least minimum of positive values*? 8
Whats the key corresponding to value 8? Its 4.
*4 is the first unique number!*
Please let me know if you need the code, shall send you ova :)
Cheers,
*Pralay*
*MS,Comp Sci, *
*University of California, Irvine*
On Tue, Feb 5, 2013 at 8:30 PM, navneet singh gaur
navneet.singhg...@gmail.com wrote:
nice algo ankit, so it will be nlogn using O (n) space only. What abt
2nd Q., which have a big online stream.
On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote:
For 1:
i think you can use sorting, sort the array and keep the indices of the
numbers in the sorted list.
Now traverse the sorted list and in the sorted list you need to find the
unique number with the
minimum index which is easy to find.
Eg: Array:5 3 1 2 4 1 4
Indices: 0 1 2 3 4 5 6
After sorting : Array:1 1 2 3 4 4 5
Indices: 2 5 3 1 4 6 1
Now you can see the unique number with lowest index is 3(index=1). So ,
you
have your answer.
On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur
navneet.singhg...@gmail.com wrote:
1. Given a array,find a first unique integer.
2. Integers are coming as online stream,have to find a kth unique
integer
till now.
For 1.
Even we cannot use sorting for solving this as if we sort it than our
first number which is non-repetitive changes.
The best I am able to do is nlogn using a space of O( n ).
For 2. No idea
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Re: [algogeeks] Amazon interview Question
Navneet, For 2nd problem, i need a clarification, whether the Kth number is wrt mathematical ordering of numbers or the kth number is wrt to the order in which the number are input ? On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
what would happen of the input is like this : 5, 5, 66, 66, 7, 1, 1, 77,7 i think in this case the moment window reaches to point (66,7,1) it will take 7 as unique number but that too window will not move any futhur , but 7 is not unique . Please comment if i misunderstood ur explanation . On Wed, Feb 6, 2013 at 11:31 PM, Srikar srikar2...@gmail.com wrote: *APPROACH 1:* use a hashtable for both the questions ? Insert the integers as they are given in the array into a hashtable. The structure I am thinking is key (the integer) - [index]. Once all elements are inserted. Run through the hashtable and select the one which has len(value) == 1 and is least, since we want the first unique integer. for the second Q, its a more general Q of the first one. In first k=1. space: 2O(n) time: 2O(n) *APPROACH2: * When we say unique, we will have a pattern. Eg: [5, 5, 66, 66, 7, 1, 1, 77]. In this lets have moving window of 3. first consider (5,5,66). we can easily estab. that there is duplicate here. So move the window by 1 element so we get (5,66,66). Same here. move to next (66,66,7). Again dups here. next (66,7,1). No dups here! take the middle element as this has to be the first unique in the set. The left element belongs to the dup so could 1. Hence 7 is the first unique element. space: O(1) time: O(n) For seond Q I still think hashtable is best. As the numbers are streamed, keep inserting. Srikar On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
Also, for the part two of the question, you can simply go in for the *kth
largest positive index *in the same hashmap (described earlier for part 1).
That solves the part two of the problem :)
Hth,
*Pralay Biswas*
*MS,Comp Sci, *
*University of California, Irvine*
On Tue, Feb 5, 2013 at 8:46 PM, Pralay Biswas pralaybiswas2...@gmail.comwrote:
I guess the part 1 can be solved in O(n) time and space both. Here is my
approach.
Assume: Array given is arr[] = {2,3,1,2,3,2,4,1,5,6}
1. Given an array, scan thru it, element by element and hash it on a
hashmap with key as the arr[i] as the key and i+1 as the index.
2. There would be two cases
a) arr[i] is already there in the hash map, if so, check if the
hashmap.get(arr[i]) is a negative or not. If it is negative , do nothing.
If its is not negative, negate it.
b) arr[i] is a new element, in such a case, hash key as arr[i] and i+1
as the value.
3. Scan thru the value set, the key corresponding to minimum of positive
values is the answer.
Example.
For {2,3,1,2,3,2,4,1, 5,6}
2 = not seen, hash 2,1 (arr[i], i+1)
3 = not seen, hash 3, 2
1 = not seen, hash 1,3
2 = seen - is the value corresponding to key 2 negative = No. So negate
it- hash entry now becomes 2,-1
3 = similar to above - Hash entry is 3,-2
2 = seen, is the value negative = yes, do nothing
4 = not seen, hash 4,8
1 = seen, is the value corresponding to key 1 -ve? No, negate it,
hashentry = 1,-3
5 = not seen, hash 5,10
6= not seen, hash 6,11
Hasmap ready. Whats the value set (the values only) ? -1,-2,-3,8,10,11
Whats the *least minimum of positive values*? 8
Whats the key corresponding to value 8? Its 4.
*4 is the first unique number!*
Please let me know if you need the code, shall send you ova :)
Cheers,
*Pralay*
*MS,Comp Sci, *
*University of California, Irvine*
On Tue, Feb 5, 2013 at 8:30 PM, navneet singh gaur
navneet.singhg...@gmail.com wrote:
nice algo ankit, so it will be nlogn using O (n) space only. What abt
2nd Q., which have a big online stream.
On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote:
For 1:
i think you can use sorting, sort the array and keep the indices of the
numbers in the sorted list.
Now traverse the sorted list and in the sorted list you need to find
the
unique number with the
minimum index which is easy to find.
Eg: Array:5 3 1 2 4 1 4
Indices: 0 1 2 3 4 5 6
After sorting : Array:1 1 2 3 4 4 5
Indices: 2 5 3 1 4 6 1
Now you can see the unique number with lowest index is 3(index=1). So ,
you
have your answer.
On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur
navneet.singhg...@gmail.com wrote:
1. Given a array,find a first unique integer.
2. Integers are coming as online stream,have to find a kth unique
integer
till now.
For 1.
Even we cannot use sorting for solving this as if we sort it than our
first number which is non-repetitive changes.
The best I am able to do is nlogn using a space of O( n ).
For 2. No idea
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Senior Undergraduate
Department of Computer Engineering
Institute of Technology
Banaras Hindu University
Varanasi
Ph: +91 9473629892
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Re: [algogeeks] Amazon interview Question
for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
@sourabh : how do u find whether the element in stream gets repeated in heap.-- O(n) time...totally its O(nk) algo .. If we maintain max-heap with BST property on index, then it would be O(nlogk). On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain wsour...@gmail.com wrote: for 2nd question you can make a heap with their index as a factor to heapify them. whenever a integer in stream gets repeated you just nead to remove it from heap and heapify it. On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Regards, Sourabh Kumar Jain +91-8971547841 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
*APPROACH 1:* use a hashtable for both the questions ? Insert the integers as they are given in the array into a hashtable. The structure I am thinking is key (the integer) - [index]. Once all elements are inserted. Run through the hashtable and select the one which has len(value) == 1 and is least, since we want the first unique integer. for the second Q, its a more general Q of the first one. In first k=1. space: 2O(n) time: 2O(n) *APPROACH2: * When we say unique, we will have a pattern. Eg: [5, 5, 66, 66, 7, 1, 1, 77]. In this lets have moving window of 3. first consider (5,5,66). we can easily estab. that there is duplicate here. So move the window by 1 element so we get (5,66,66). Same here. move to next (66,66,7). Again dups here. next (66,7,1). No dups here! take the middle element as this has to be the first unique in the set. The left element belongs to the dup so could 1. Hence 7 is the first unique element. space: O(1) time: O(n) For seond Q I still think hashtable is best. As the numbers are streamed, keep inserting. Srikar On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
@srikar : approach2 is wrong. ex: [1, 5, 7, 66, 7, 1, 77] first window [1,5,7] all are unique.oops On Wed, Feb 6, 2013 at 11:31 PM, Srikar srikar2...@gmail.com wrote: *APPROACH 1:* use a hashtable for both the questions ? Insert the integers as they are given in the array into a hashtable. The structure I am thinking is key (the integer) - [index]. Once all elements are inserted. Run through the hashtable and select the one which has len(value) == 1 and is least, since we want the first unique integer. for the second Q, its a more general Q of the first one. In first k=1. space: 2O(n) time: 2O(n) *APPROACH2: * When we say unique, we will have a pattern. Eg: [5, 5, 66, 66, 7, 1, 1, 77]. In this lets have moving window of 3. first consider (5,5,66). we can easily estab. that there is duplicate here. So move the window by 1 element so we get (5,66,66). Same here. move to next (66,66,7). Again dups here. next (66,7,1). No dups here! take the middle element as this has to be the first unique in the set. The left element belongs to the dup so could 1. Hence 7 is the first unique element. space: O(1) time: O(n) For seond Q I still think hashtable is best. As the numbers are streamed, keep inserting. Srikar On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur navneet.singhg...@gmail.com wrote: nice algo ankit, so it will be nlogn using O (n) space only. What abt 2nd Q., which have a big online stream. On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit k.anki...@gmail.com wrote: For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- navneet singh gaur -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
in above algo primary index is no of times that value is repeated till now -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
For 1: i think you can use sorting, sort the array and keep the indices of the numbers in the sorted list. Now traverse the sorted list and in the sorted list you need to find the unique number with the minimum index which is easy to find. Eg: Array:5 3 1 2 4 1 4 Indices: 0 1 2 3 4 5 6 After sorting : Array:1 1 2 3 4 4 5 Indices: 2 5 3 1 4 6 1 Now you can see the unique number with lowest index is 3(index=1). So , you have your answer. On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur navneet.singhg...@gmail.com wrote: 1. Given a array,find a first unique integer. 2. Integers are coming as online stream,have to find a kth unique integer till now. For 1. Even we cannot use sorting for solving this as if we sort it than our first number which is non-repetitive changes. The best I am able to do is nlogn using a space of O( n ). For 2. No idea -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out. -- Kumar Ankit Senior Undergraduate Department of Computer Engineering Institute of Technology Banaras Hindu University Varanasi Ph: +91 9473629892 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
I can think of an o(n^2) algo for 2n question Make a heap formed acctoring to two indexes 1.Primary -value 2.Secondary - index Now for each new incoming value first search in head if exist inc its index else make a new node -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
Re: [algogeeks] Amazon interview Question
loop from the end of given number till you get a digit less than the previously scanned digit.Let the index of that number be 'i' . if index = -1,then the given number is the largest one else do the following 1) swap the digit at the index i with the digit just greater than it in the scanned portion 2) sort the remaining scanned digits after index i. Ex:- let the given number be 51432 the digit '1' is the first digit less that its previously scanned digit '4' thus, we swap 2 which is the smallest greater digit the '1' in scanned portion to get 52431 and the we sort the remaining digits after the index to get 52134. --
Re: [algogeeks] Amazon Interview Question
@ashgoel - Could you please explain what exactly are you doing here ?
On Wednesday, 4 July 2012 16:16:38 UTC+5:30, ashgoel wrote:
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.com wrote:
Find the next higher number in set of permutations of a given number
--
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Re: [algogeeks] Amazon Interview Question
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.com wrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google Groups
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To post to this group, send email to algogeeks@googlegroups.com.
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Re: [algogeeks] Amazon Interview Question
Q5 is sorting problem
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.com wrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
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For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.com wrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
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Re: [algogeeks] Amazon Interview Question
Consider trees:
1 3
2 3 2
1
pre order traversal is same still (1 , 2 ,3) even though ist tree doesn't
satisfy the criteria . So I don't think it can be determined.
On Wed, Jul 4, 2012 at 4:16 PM, Ashish Goel ashg...@gmail.com wrote:
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.com wrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google Groups
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--
Thanks regards
Bhupendra
--
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Re: [algogeeks] Amazon Interview Question
1. For first question trie of given word will be best option.
Space complexity O(total length of words) (worst case)
Time complexity O(T) . T length of input text (Newspaper)
2. consider it to be a 4 digit number ABCD . Find maximum Most
significant digit say it is C , and out of these nos find maximum value of
next digit say A and so on . Suppose Final no. is CADB
Now next highest permutation will be the no. just greater than this and
made of these digits . This is easy.
On Wed, Jul 4, 2012 at 5:17 PM, Bhupendra Dubey bhupendra@gmail.comwrote:
Consider trees:
1 3
2 3 2
1
pre order traversal is same still (1 , 2 ,3) even though ist tree doesn't
satisfy the criteria . So I don't think it can be determined.
On Wed, Jul 4, 2012 at 4:16 PM, Ashish Goel ashg...@gmail.com wrote:
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.comwrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google Groups
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To post to this group, send email to algogeeks@googlegroups.com.
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--
Thanks regards
Bhupendra
--
Thanks regards
Bhupendra
--
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Re: [algogeeks] Amazon Interview Question
For question 5.
Even this doesn't seems right
Consider this scenario
Match b/w Winner
a vs b a
a vs c c
b vs c b
What will be order ?? acb or bca
On Wed, Jul 4, 2012 at 5:38 PM, Bhupendra Dubey bhupendra@gmail.comwrote:
1. For first question trie of given word will be best option.
Space complexity O(total length of words) (worst case)
Time complexity O(T) . T length of input text (Newspaper)
2. consider it to be a 4 digit number ABCD . Find maximum Most
significant digit say it is C , and out of these nos find maximum value of
next digit say A and so on . Suppose Final no. is CADB
Now next highest permutation will be the no. just greater than this and
made of these digits . This is easy.
On Wed, Jul 4, 2012 at 5:17 PM, Bhupendra Dubey
bhupendra@gmail.comwrote:
Consider trees:
1 3
2 3 2
1
pre order traversal is same still (1 , 2 ,3) even though ist tree
doesn't satisfy the criteria . So I don't think it can be determined.
On Wed, Jul 4, 2012 at 4:16 PM, Ashish Goel ashg...@gmail.com wrote:
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.comwrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google
Groups Algorithm Geeks group.
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--
Thanks regards
Bhupendra
--
Thanks regards
Bhupendra
--
Thanks regards
Bhupendra
--
You received this message because you are subscribed to the Google Groups
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Re: [algogeeks] Amazon Interview Question
1
2 3 is not a BST and its pre-order traversal is 1 2 3, pre
order of other is 3 2 1 .
On Wed, Jul 4, 2012 at 5:17 PM, Bhupendra Dubey bhupendra@gmail.comwrote:
Consider trees:
1 3
2 3 2
1
pre order traversal is same still (1 , 2 ,3) even though ist tree doesn't
satisfy the criteria . So I don't think it can be determined.
On Wed, Jul 4, 2012 at 4:16 PM, Ashish Goel ashg...@gmail.com wrote:
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.comwrote:
Find the next higher number in set of permutations of a given number
--
You received this message because you are subscribed to the Google Groups
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To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
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--
Thanks regards
Bhupendra
--
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Re: [algogeeks] Amazon Interview Question
Sorry i typed wrongly
tree is
2
1 3
preorder traversal is 123 and same for other tree as well. Please check !
On Wed, Jul 4, 2012 at 5:24 PM, a g ag20071...@gmail.com wrote:
1
2 3 is not a BST and its pre-order traversal is 1 2 3, pre
order of other is 3 2 1 .
On Wed, Jul 4, 2012 at 5:17 PM, Bhupendra Dubey
bhupendra@gmail.comwrote:
Consider trees:
1 3
2 3 2
1
pre order traversal is same still (1 , 2 ,3) even though ist tree
doesn't satisfy the criteria . So I don't think it can be determined.
On Wed, Jul 4, 2012 at 4:16 PM, Ashish Goel ashg...@gmail.com wrote:
Q4
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
if (visited[i][j]) continue;
visited[i][j] = true;
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 4:13 PM, Ashish Goel ashg...@gmail.com wrote:
1. inverted hasp map
2. not clear
3. VLR, how do you identify end of L and start of R, question incomplete
4. One problem: consider
...
a b...
c d...
...
if ab is a prefix, can aba be another prefix, i would assume so. But if
that is true, i am not sure if this program will come to an end.
vectorString prefix;
prefix[0]=NULL;
prefixCount =1;
for (int i=0;in;i++)
for (int j=0;jn;j++)
for (int k=0; kprefixCount;k++)
{
String s=prefix[k]+a[i][j];
if (isWord(s) { printWord(s); prefix[k]=s; continue;}
else if isPrefix(s) prefix[prefixCount++] = s;
else removePrefix(prefix[k], prefixCount);
prefix[prefixCount++] = String(a[i][j];
}
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Wed, Jul 4, 2012 at 12:22 PM, Decipher ankurseth...@gmail.comwrote:
Find the next higher number in set of permutations of a given number
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Thanks regards
Bhupendra
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Thanks regards
Bhupendra
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Re: [algogeeks] Amazon Interview Question
example pls... On Thu, Jun 14, 2012 at 1:01 PM, Mohit Rathi mohit08...@iiitd.ac.in wrote: Hi, *There are two arrays of length 100 each. Each of these has initially n (n=100) elements. First array contains names and the second array contains numbers such that ith name in array1 corresponds to ith number in array2. Write a program which asks the user to enter a name, finds it in array1,* *a. if it exists, then print the corresponding number in array2, b. else ask the user to input its associated number and add the number and name to array2 and array1 respectively, and update the size of list* I can think of solving it through linear walk to the array. Anyone with more optimized algorithm like BST or HashTable? comments are welcome Thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
arr1 = [abc,xyz,lmn,def] arr2 = [3,6,2,8] if user enters xyz then 6 will be printed else if xyz doesn't exist in arr1 then ask for a number and add them in respective arrays(name in arr1 and number in arr2). Hope it helps On Thu, Jun 14, 2012 at 3:58 PM, utsav sharma utsav.sharm...@gmail.comwrote: example pls... On Thu, Jun 14, 2012 at 1:01 PM, Mohit Rathi mohit08...@iiitd.ac.inwrote: Hi, *There are two arrays of length 100 each. Each of these has initially n (n=100) elements. First array contains names and the second array contains numbers such that ith name in array1 corresponds to ith number in array2. Write a program which asks the user to enter a name, finds it in array1,* *a. if it exists, then print the corresponding number in array2, b. else ask the user to input its associated number and add the number and name to array2 and array1 respectively, and update the size of list* I can think of solving it through linear walk to the array. Anyone with more optimized algorithm like BST or HashTable? comments are welcome Thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Mohit Rathi 4th year, B.Tech (IT) IIIT-Delhi -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
it can be done using map in c++ On Thu, Jun 14, 2012 at 4:23 PM, Mohit Rathi mohit08...@iiitd.ac.in wrote: arr1 = [abc,xyz,lmn,def] arr2 = [3,6,2,8] if user enters xyz then 6 will be printed else if xyz doesn't exist in arr1 then ask for a number and add them in respective arrays(name in arr1 and number in arr2). Hope it helps On Thu, Jun 14, 2012 at 3:58 PM, utsav sharma utsav.sharm...@gmail.comwrote: example pls... On Thu, Jun 14, 2012 at 1:01 PM, Mohit Rathi mohit08...@iiitd.ac.inwrote: Hi, *There are two arrays of length 100 each. Each of these has initially n (n=100) elements. First array contains names and the second array contains numbers such that ith name in array1 corresponds to ith number in array2. Write a program which asks the user to enter a name, finds it in array1, * *a. if it exists, then print the corresponding number in array2, b. else ask the user to input its associated number and add the number and name to array2 and array1 respectively, and update the size of list* I can think of solving it through linear walk to the array. Anyone with more optimized algorithm like BST or HashTable? comments are welcome Thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Mohit Rathi 4th year, B.Tech (IT) IIIT-Delhi -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
Since the size of array is very less I think Hashmap is the best. Use name as the hash key and number as its value. On Thursday, June 14, 2012 6:46:34 PM UTC+5:30, utsav sharma wrote: it can be done using map in c++ On Thu, Jun 14, 2012 at 4:23 PM, Mohit Rathi mohit08...@iiitd.ac.inwrote: arr1 = [abc,xyz,lmn,def] arr2 = [3,6,2,8] if user enters xyz then 6 will be printed else if xyz doesn't exist in arr1 then ask for a number and add them in respective arrays(name in arr1 and number in arr2). Hope it helps On Thu, Jun 14, 2012 at 3:58 PM, utsav sharma utsav.sharm...@gmail.comwrote: example pls... On Thu, Jun 14, 2012 at 1:01 PM, Mohit Rathi mohit08...@iiitd.ac.inwrote: Hi, *There are two arrays of length 100 each. Each of these has initially n (n=100) elements. First array contains names and the second array contains numbers such that ith name in array1 corresponds to ith number in array2. Write a program which asks the user to enter a name, finds it in array1, * *a. if it exists, then print the corresponding number in array2, b. else ask the user to input its associated number and add the number and name to array2 and array1 respectively, and update the size of list* I can think of solving it through linear walk to the array. Anyone with more optimized algorithm like BST or HashTable? comments are welcome Thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Mohit Rathi 4th year, B.Tech (IT) IIIT-Delhi -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/wF1ZUNLZV4UJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
Hashmap can be used for effective retreival.. On Thu, Jun 14, 2012 at 4:23 PM, Mohit Rathi mohit08...@iiitd.ac.in wrote: arr1 = [abc,xyz,lmn,def] arr2 = [3,6,2,8] if user enters xyz then 6 will be printed else if xyz doesn't exist in arr1 then ask for a number and add them in respective arrays(name in arr1 and number in arr2). Hope it helps On Thu, Jun 14, 2012 at 3:58 PM, utsav sharma utsav.sharm...@gmail.comwrote: example pls... On Thu, Jun 14, 2012 at 1:01 PM, Mohit Rathi mohit08...@iiitd.ac.inwrote: Hi, *There are two arrays of length 100 each. Each of these has initially n (n=100) elements. First array contains names and the second array contains numbers such that ith name in array1 corresponds to ith number in array2. Write a program which asks the user to enter a name, finds it in array1, * *a. if it exists, then print the corresponding number in array2, b. else ask the user to input its associated number and add the number and name to array2 and array1 respectively, and update the size of list* I can think of solving it through linear walk to the array. Anyone with more optimized algorithm like BST or HashTable? comments are welcome Thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Utsav Sharma, NIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Mohit Rathi 4th year, B.Tech (IT) IIIT-Delhi -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon interview question
array of bits? if the current integer is present set the bit if else make it zero, searching, insertion and deletion all in O(1) time. On Thu, May 24, 2012 at 4:15 PM, rishabh shukla rockrishabh.mn...@gmail.com wrote: Suggest a data structure for storing million trillion numbers efficiently in very less space. Means space complexity should be as less as possible -- Rishabh Shukla B.Tech Final Year MNNIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon interview question
What is the purpose of these numbers, if the idea is to manage a free pool, then probably 10-ary-tree is the solution. May be Tiger Tree Hash a better answer where it is tree to say level 7 and then for rest three digits it become hash table. This way, the chunks can be kept on different machines too. Best Regards Ashish Goel Think positive and find fuel in failure +919985813081 +919966006652 On Thu, May 24, 2012 at 4:51 PM, Aman Raj amanka...@gmail.com wrote: array of bits? if the current integer is present set the bit if else make it zero, searching, insertion and deletion all in O(1) time. On Thu, May 24, 2012 at 4:15 PM, rishabh shukla rockrishabh.mn...@gmail.com wrote: Suggest a data structure for storing million trillion numbers efficiently in very less space. Means space complexity should be as less as possible -- Rishabh Shukla B.Tech Final Year MNNIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon interview question
refer http://www.cs.bell-labs.com/cm/cs/pearls/sol01.html Best Regards Ashish Goel Think positive and find fuel in failure +919985813081 +919966006652 On Thu, May 24, 2012 at 6:00 PM, Ashish Goel ashg...@gmail.com wrote: What is the purpose of these numbers, if the idea is to manage a free pool, then probably 10-ary-tree is the solution. May be Tiger Tree Hash a better answer where it is tree to say level 7 and then for rest three digits it become hash table. This way, the chunks can be kept on different machines too. Best Regards Ashish Goel Think positive and find fuel in failure +919985813081 +919966006652 On Thu, May 24, 2012 at 4:51 PM, Aman Raj amanka...@gmail.com wrote: array of bits? if the current integer is present set the bit if else make it zero, searching, insertion and deletion all in O(1) time. On Thu, May 24, 2012 at 4:15 PM, rishabh shukla rockrishabh.mn...@gmail.com wrote: Suggest a data structure for storing million trillion numbers efficiently in very less space. Means space complexity should be as less as possible -- Rishabh Shukla B.Tech Final Year MNNIT Allahabad -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
No limit on #nodes and #edges. On Thu, Apr 26, 2012 at 1:06 PM, bharat b bagana.bharatku...@gmail.comwrote: In input, he mentions #nodes and #edges of each nodes has, right? create an array of linked lists.. each index in the array represents the node number and the linked list of that represents edges of that node. Am I right? On Wed, Apr 25, 2012 at 5:40 PM, Radhakrishnan Venkataramani radhakrishnance...@gmail.com wrote: How will you implement a graph data structure ? Give an linked implementation as we do not know how many nodes will be there and how many edges will be there. Make a copy of this graph.. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
@bharat: +1 On Thu, Apr 26, 2012 at 1:06 PM, bharat b bagana.bharatku...@gmail.com wrote: create an array of linked lists.. each index in the array represents the node number and the linked list of that represents edges of that node. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
In input, he mentions #nodes and #edges of each nodes has, right? create an array of linked lists.. each index in the array represents the node number and the linked list of that represents edges of that node. Am I right? On Wed, Apr 25, 2012 at 5:40 PM, Radhakrishnan Venkataramani radhakrishnance...@gmail.com wrote: How will you implement a graph data structure ? Give an linked implementation as we do not know how many nodes will be there and how many edges will be there. Make a copy of this graph.. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
What will be the size of the array? You don't know the number of nodes in the graph. Implementing table doubling would be tedious. If they asked for a specific language implementation then for c++ you can use a vector of linked lists. Otherwise a linked list of pointers to head of linked lists would be a good option, I think. Sukun Tarachandani IDD Electrical Engineering(2nd year) IIT Roorkee On Thu, Apr 26, 2012 at 1:06 PM, bharat b bagana.bharatku...@gmail.comwrote: In input, he mentions #nodes and #edges of each nodes has, right? create an array of linked lists.. each index in the array represents the node number and the linked list of that represents edges of that node. Am I right? On Wed, Apr 25, 2012 at 5:40 PM, Radhakrishnan Venkataramani radhakrishnance...@gmail.com wrote: How will you implement a graph data structure ? Give an linked implementation as we do not know how many nodes will be there and how many edges will be there. Make a copy of this graph.. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
@Neeraj : will u pls explain u'r logic ...
On 1/19/12, NEERAJ KODDHAN neerajdc...@gmail.com wrote:
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek codinggee...@gmail.comwrote:
Place N number from 1 to N, in 2N positions in such a way so that there
are
Exactly “n” number of cells between two placed locations of number “n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
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**Regards
*
* bagana.bharatku...@gmail.com
Bharat B | M.Tech II | Computer Science Engineering | IITM
*
*
*Ph: +91 8056127652*
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Re: [algogeeks] Amazon Interview Question
thats a brute force solution...
can u expalin the complexity..i think its O(n^2)
and also there exist no solution for n 3
On Thu, Jan 19, 2012 at 3:36 PM, bharat b bagana.bharatku...@gmail.comwrote:
@Neeraj : will u pls explain u'r logic ...
On 1/19/12, NEERAJ KODDHAN neerajdc...@gmail.com wrote:
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek codinggee...@gmail.com
wrote:
Place N number from 1 to N, in 2N positions in such a way so that there
are
Exactly “n” number of cells between two placed locations of number “n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
--
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Groups
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Re: [algogeeks] Amazon Interview Question
ignore my last comment.. misunderstood
On Thu, Jan 19, 2012 at 1:04 PM, Prakash D cegprak...@gmail.com wrote:
why can't u simply place it as 1 2 3 4 5 6 7 1 2 3 4 5 6 7?
On Thu, Jan 19, 2012 at 2:05 AM, NEERAJ KODDHAN neerajdc...@gmail.comwrote:
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek codinggee...@gmail.comwrote:
Place N number from 1 to N, in 2N positions in such a way so that there
are
Exactly “n” number of cells between two placed locations of number “n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
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Re: [algogeeks] Amazon Interview Question
why can't u simply place it as 1 2 3 4 5 6 7 1 2 3 4 5 6 7?
On Thu, Jan 19, 2012 at 2:05 AM, NEERAJ KODDHAN neerajdc...@gmail.comwrote:
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek codinggee...@gmail.comwrote:
Place N number from 1 to N, in 2N positions in such a way so that there
are
Exactly “n” number of cells between two placed locations of number “n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
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Re: [algogeeks] Amazon Interview Question
@Neeraj
Thanx for providing the algo
On Thu, Jan 19, 2012 at 7:18 PM, rahul patil
rahul.deshmukhpa...@gmail.comwrote:
Looks like classic example of backtrack !!!
On Thu, Jan 19, 2012 at 1:05 PM, Prakash D cegprak...@gmail.com wrote:
ignore my last comment.. misunderstood
On Thu, Jan 19, 2012 at 1:04 PM, Prakash D cegprak...@gmail.com wrote:
why can't u simply place it as 1 2 3 4 5 6 7 1 2 3 4 5 6 7?
On Thu, Jan 19, 2012 at 2:05 AM, NEERAJ KODDHAN
neerajdc...@gmail.comwrote:
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek
codinggee...@gmail.comwrote:
Place N number from 1 to N, in 2N positions in such a way so that
there are
Exactly “n” number of cells between two placed locations of number
“n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
--
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Re: [algogeeks] Amazon Interview Question
Coding Geek, if you have understood the algo provided by Neeraj, request
you to explain the logic please.
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Thu, Jan 19, 2012 at 8:03 PM, Coding Geek codinggee...@gmail.com wrote:
@Neeraj
Thanx for providing the algo
On Thu, Jan 19, 2012 at 7:18 PM, rahul patil
rahul.deshmukhpa...@gmail.com wrote:
Looks like classic example of backtrack !!!
On Thu, Jan 19, 2012 at 1:05 PM, Prakash D cegprak...@gmail.com wrote:
ignore my last comment.. misunderstood
On Thu, Jan 19, 2012 at 1:04 PM, Prakash D cegprak...@gmail.com wrote:
why can't u simply place it as 1 2 3 4 5 6 7 1 2 3 4 5 6 7?
On Thu, Jan 19, 2012 at 2:05 AM, NEERAJ KODDHAN
neerajdc...@gmail.comwrote:
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek
codinggee...@gmail.comwrote:
Place N number from 1 to N, in 2N positions in such a way so that
there are
Exactly “n” number of cells between two placed locations of number
“n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
--
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Re: [algogeeks] Amazon Interview Question
@ Neeraj: Plz explain ur logic. -- Ravi Shankar MCA 2nd Year Department Of Computer Science University Of Delhi -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
@all : if see the code closely ...logic is simple.
code is just trying many permutation to find an answer.
say input = 6
now assuming that 6 will be placed at position arr[i] and arr[j+i+1] . it
will put that value and move further to find next possible location for
input-1;
at any point of time if condition doesnt satify then we backtrack making
arr[i] and ar[ j+ i +1 ] to 0 . and find another permulation.
add
for (int k : a) {
System.out.print(k + );
}
inside if() condition in the given code and run this prog. you will get an
idea how it working.
On Fri, Jan 20, 2012 at 1:39 AM, RaviShankar Kushwaha
ravishuni...@gmail.com wrote:
@ Neeraj: Plz explain ur logic.
--
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MCA 2nd Year
Department Of Computer Science
University Of Delhi
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Re: [algogeeks] Amazon Interview Question
@all Please check the Backtracking examples at http://www.geeksforgeeks.org/archives/tag/backtracking. You will understand the logic. In this examples first we fix a no. onto some position. After we check for other no. if any of the no. do not fit according to property we move back and reset all the changes made. Then we move our first fixed no. to some advance position and again check for the same. We repeat until we find a Sol. Thanx, -- To Iterate is Human, To Recurse is Divine -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
int[] a = new int[2*n];
put(a, n);
static void put(int[] a,int i){
if(i0){
for(int j=0;ja.length-i-1;j++){
if(a[j]==0 a[j+i+1]==0){
a[j]=i;
a[j+i+1]=i;
put(a, i-1);
a[j]=0;
a[j+i+1]=0;
}
}
}else if(i==0){
for (int k : a) {
System.out.print(k + );
}
System.out.println();
}
}
On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek codinggee...@gmail.comwrote:
Place N number from 1 to N, in 2N positions in such a way so that there
are
Exactly “n” number of cells between two placed locations of number “n”.
Write a program to display numbers placed in this way.
Example:-
(1) One of the possible placement for 7 numbers in 14 positions is :
5 7 2 3 6 2 5 3 4 7 1 6 1 4
--
To Iterate is Human, To Recurse is Divine
--
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Re: [algogeeks] Amazon Interview Question
@utkarsh: in yr code it shud be two-- after the swap function and not
before for case 2
On Thu, Nov 10, 2011 at 1:25 PM, UTKARSH SRIVASTAV
usrivastav...@gmail.comwrote:
sorry it was incomplete
On Fri, Nov 11, 2011 at 2:53 AM, UTKARSH SRIVASTAV
usrivastav...@gmail.com wrote:
one = zero = 0;
two = n-1; //n is length of string
while(two=one)
{
switch(a[one])
{
case '0' : swap(a[zero],z[one]);
one++;zero++;break;
case '1' : one++;
break;
case '2' : two--;
swap(a[one],a[two]);
}
}
On Mon, Oct 24, 2011 at 9:50 PM, praveen raj praveen0...@gmail.comwrote:
This can be done in O(n)..
first shift all the 2's to the right side in O(n)...
then again shift 1to the right shift b efore 2's. in O(n)...
With regards,
Praveen Raj
DCE-IT 3rd yr
735993
praveen0...@gmail.com
On Mon, Sep 26, 2011 at 6:23 PM, Naren s sweetna...@gmail.com wrote:
dutch national flag problem..search in wiki...classical.
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should produce 00122
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College Of Engineering Guindy,
Anna University,
Chennai-25.
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Re: [algogeeks] Amazon Interview Question
also I dont think that for case 0 we do not need to have one ++. I guess it
fails for this example
2200101
On Mon, Jan 2, 2012 at 5:36 PM, Arun Vishwanathan aaron.nar...@gmail.comwrote:
@utkarsh: in yr code it shud be two-- after the swap function and not
before for case 2
On Thu, Nov 10, 2011 at 1:25 PM, UTKARSH SRIVASTAV
usrivastav...@gmail.com wrote:
sorry it was incomplete
On Fri, Nov 11, 2011 at 2:53 AM, UTKARSH SRIVASTAV
usrivastav...@gmail.com wrote:
one = zero = 0;
two = n-1; //n is length of string
while(two=one)
{
switch(a[one])
{
case '0' : swap(a[zero],z[one]);
one++;zero++;break;
case '1' : one++;
break;
case '2' : two--;
swap(a[one],a[two]);
}
}
On Mon, Oct 24, 2011 at 9:50 PM, praveen raj praveen0...@gmail.comwrote:
This can be done in O(n)..
first shift all the 2's to the right side in O(n)...
then again shift 1to the right shift b efore 2's. in O(n)...
With regards,
Praveen Raj
DCE-IT 3rd yr
735993
praveen0...@gmail.com
On Mon, Sep 26, 2011 at 6:23 PM, Naren s sweetna...@gmail.com wrote:
dutch national flag problem..search in wiki...classical.
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.comwrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should produce 00122
--
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*Narayanan S,*
B.E., C.S.E., (final year),
College Of Engineering Guindy,
Anna University,
Chennai-25.
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*UTKARSH SRIVASTAV
CSE-3
B-Tech 3rd Year
@MNNIT ALLAHABAD*
--
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CSE-3
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Re: [algogeeks] Amazon Interview Question
I think smallest will be having just one character . it can be a or b or c. On Sat, Nov 12, 2011 at 3:07 PM, Snoopy Me thesnoop...@gmail.com wrote: Given a string consisting of a,b and c's, we can perform the following operation: Take any two adjacent distinct characters and replace it with the third character. For example, if 'a' and 'c' are adjacent, they can replaced with 'b'. What is the smallest string which can result by applying this operation repeatedly? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
sorry it was incomplete
On Fri, Nov 11, 2011 at 2:53 AM, UTKARSH SRIVASTAV
usrivastav...@gmail.comwrote:
one = zero = 0;
two = n-1; //n is length of string
while(two=one)
{
switch(a[one])
{
case '0' : swap(a[zero],z[one]);
one++;zero++;break;
case '1' : one++;
break;
case '2' : two--;
swap(a[one],a[two]);
}
}
On Mon, Oct 24, 2011 at 9:50 PM, praveen raj praveen0...@gmail.comwrote:
This can be done in O(n)..
first shift all the 2's to the right side in O(n)...
then again shift 1to the right shift b efore 2's. in O(n)...
With regards,
Praveen Raj
DCE-IT 3rd yr
735993
praveen0...@gmail.com
On Mon, Sep 26, 2011 at 6:23 PM, Naren s sweetna...@gmail.com wrote:
dutch national flag problem..search in wiki...classical.
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should produce 00122
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--
*Narayanan S,*
B.E., C.S.E., (final year),
College Of Engineering Guindy,
Anna University,
Chennai-25.
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@MNNIT ALLAHABAD*
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@MNNIT ALLAHABAD*
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Re: [algogeeks] Amazon Interview Question
one = zero = 0;
two = n-1; //n is length of string
while(two=one)
{
switch(a[one])
On Mon, Oct 24, 2011 at 9:50 PM, praveen raj praveen0...@gmail.com wrote:
This can be done in O(n)..
first shift all the 2's to the right side in O(n)...
then again shift 1to the right shift b efore 2's. in O(n)...
With regards,
Praveen Raj
DCE-IT 3rd yr
735993
praveen0...@gmail.com
On Mon, Sep 26, 2011 at 6:23 PM, Naren s sweetna...@gmail.com wrote:
dutch national flag problem..search in wiki...classical.
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should produce 00122
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*Narayanan S,*
B.E., C.S.E., (final year),
College Of Engineering Guindy,
Anna University,
Chennai-25.
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@MNNIT ALLAHABAD*
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Re: [algogeeks] Amazon Interview Question
count the number of 0s 1s 2s.then store os first den 1s followed by 2s On Sat, Sep 24, 2011 at 9:55 AM, Anup Ghatage ghat...@gmail.com wrote: Is this like the segregating all the 1's to the right and the 0's to the left or am i missing something? On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote: You are given a string (consisting of 0's, 1's or 2's) where 0 represents a blue ball, 1 a red ball, and 2 a black ball. Using only swap operations (counting sort not allowed) rearrange the string such that all blue balls are together on one side, followed by all red balls, and then all black balls. You can iterate through the string only once. Eg 102112011 should produce 00122? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Anup Ghatage -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
dutch national flag problem..search in wiki...classical. On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote: You are given a string (consisting of 0's, 1's or 2's) where 0 represents a blue ball, 1 a red ball, and 2 a black ball. Using only swap operations (counting sort not allowed) rearrange the string such that all blue balls are together on one side, followed by all red balls, and then all black balls. You can iterate through the string only once. Eg 102112011 should produce 00122 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- *Narayanan S,* B.E., C.S.E., (final year), College Of Engineering Guindy, Anna University, Chennai-25. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 01112
0 1 2
starting_index 0 1 4
ending_index 0 3 4
next character '2'
0 1 2
starting_index 0 1 4
ending_index 0 3 5
(ending_index0ending_index1ending_index2) so no swap
so string will become 011122
next character '0'
0 1 2
starting_index 0 1 4
ending_index 6 3 5
(ending_index0ending_index1ending_index2) so we swap the current 0 with
staring index of 2 first and then with starting index of 1
so string will become 0011122
0 1 2
starting_index 0 2 5
ending_index 1 4 6
and so on i hope its much explained...
On Sat, Sep 24, 2011 at 10:30 AM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
char str[100],t;
scanf(%s,str);
char ch='0';
int i=0,j=0;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
ch='1';
j=i;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
printf(%s\n,str);
On Sat, Sep 24, 2011 at 9:55 AM, Anup Ghatage ghat...@gmail.com wrote:
Is this like the segregating all the 1's to the right and the 0's to the
left
or am i missing something?
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should produce 00122?
--
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Re: [algogeeks] Amazon Interview Question
i think this travels only once ... correct me if am wrong
#includestdio.h
#includestring.h
#define SWAP(a,b,c) (c)=(a),(a)=(b),(b)=(c)
int main()
{
int t,x;
scanf(%d,t);
while(t--)
{
char str[100];
scanf(%s,str);
int i=0,j=0,k=strlen(str)-1;
while(str[i]=='0')
i++;
while(str[k]=='2')
k--;
j=i;
while(j=k)
{
if(str[j]=='2')
{
SWAP(str[j],str[k],x);
k--;
}
if(str[j]=='0')
{
SWAP(str[i],str[j],x);
i++;
}
if(str[j]!='2')
j++;
}
printf(%s\n,str);
}
return 0;
}
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 01112
0 1 2
starting_index 0 1 4
ending_index 0 3 4
next character '2'
0 1 2
starting_index 0 1 4
ending_index 0 3 5
(ending_index0ending_index1ending_index2) so no swap
so string will become 011122
next character '0'
0 1 2
starting_index 0 1 4
ending_index 6 3 5
(ending_index0ending_index1ending_index2) so we swap the current 0 with
staring index of 2 first and then with starting index of 1
so string will become 0011122
0 1 2
starting_index 0 2 5
ending_index 1 4 6
and so on i hope its much explained...
On Sat, Sep 24, 2011 at 10:30 AM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
char str[100],t;
scanf(%s,str);
char ch='0';
int i=0,j=0;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
ch='1';
j=i;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
printf(%s\n,str);
Re: [algogeeks] Amazon Interview Question
dutch national flag problem :)
On Sat, Sep 24, 2011 at 3:45 PM, Dheeraj Sharma dheerajsharma1...@gmail.com
wrote:
i think this travels only once ... correct me if am wrong
#includestdio.h
#includestring.h
#define SWAP(a,b,c) (c)=(a),(a)=(b),(b)=(c)
int main()
{
int t,x;
scanf(%d,t);
while(t--)
{
char str[100];
scanf(%s,str);
int i=0,j=0,k=strlen(str)-1;
while(str[i]=='0')
i++;
while(str[k]=='2')
k--;
j=i;
while(j=k)
{
if(str[j]=='2')
{
SWAP(str[j],str[k],x);
k--;
}
if(str[j]=='0')
{
SWAP(str[i],str[j],x);
i++;
}
if(str[j]!='2')
j++;
}
printf(%s\n,str);
}
return 0;
}
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 01112
0 1 2
starting_index 0 1 4
ending_index 0 3 4
next character '2'
0 1 2
starting_index 0 1 4
ending_index 0 3 5
(ending_index0ending_index1ending_index2) so no swap
so string will become 011122
next character '0'
0 1 2
starting_index 0 1 4
ending_index 6 3 5
(ending_index0ending_index1ending_index2) so we swap the current 0 with
staring index of 2 first and then with starting index of 1
so string will become 0011122
0 1 2
starting_index 0 2 5
ending_index 1 4 6
and so on i hope its much explained...
On Sat, Sep 24, 2011 at 10:30 AM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
char str[100],t;
scanf(%s,str);
char ch='0';
int i=0,j=0;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
ch='1';
j=i;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
Re: [algogeeks] Amazon Interview Question
I think this will do the same: -
#include stdafx.h
#include stdlib.h
void swap(int *a, int start, int end)
{
int temp;
temp = *(a + start);
*(a + start) = *(a + end);
*(a + end) = temp;
}
int _tmain(int argc, _TCHAR* argv[])
{
int minIndex=0, maxIndex=8;
int i=1;
int a[9] ={1,0,2,1,0,2,0,0,1};
while(imaxIndex)
{
if(a[maxIndex] == 2)
maxIndex--;
if(a[minIndex] == 0)
minIndex++;
if(a[i] a[maxIndex])
{
swap(a, i, maxIndex);
continue;
}
else if (a[i] a[minIndex])
{
swap(a, i, minIndex);
continue;
}
i++;
}
for (i =0 ; i 9; i++)
printf([%d], a[i]);
system(PAUSE);
return 0;
}
Please comment.
Cheers,
Ankit Sinha
On Sat, Sep 24, 2011 at 4:10 PM, malay chakrabarti m1234...@gmail.com wrote:
dutch national flag problem :)
On Sat, Sep 24, 2011 at 3:45 PM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
i think this travels only once ... correct me if am wrong
#includestdio.h
#includestring.h
#define SWAP(a,b,c) (c)=(a),(a)=(b),(b)=(c)
int main()
{
int t,x;
scanf(%d,t);
while(t--)
{
char str[100];
scanf(%s,str);
int i=0,j=0,k=strlen(str)-1;
while(str[i]=='0')
i++;
while(str[k]=='2')
k--;
j=i;
while(j=k)
{
if(str[j]=='2')
{
SWAP(str[j],str[k],x);
k--;
}
if(str[j]=='0')
{
SWAP(str[i],str[j],x);
i++;
}
if(str[j]!='2')
j++;
}
printf(%s\n,str);
}
return 0;
}
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2) so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 01112
0 1 2
starting_index 0 1 4
ending_index 0 3 4
next character '2'
0 1 2
starting_index 0 1 4
ending_index 0 3 5
(ending_index0ending_index1ending_index2) so no swap
so string will become 011122
next character '0'
0 1 2
starting_index 0 1 4
ending_index 6 3 5
(ending_index0ending_index1ending_index2) so we swap the current 0 with
Re: [algogeeks] Amazon Interview Question
void sort012(int a[],int n){
int i = 0, s = 0, last = n-1;
while(i=last){
if(a[i] == 0 i!=s)
{
swap(a[i], a[s]);
s++;
}
else if(a[i] == 2 i!=last)
{
swap(a[i], a[last]);
last--;
}
else
i++;
}
}
On Sat, Sep 24, 2011 at 5:13 PM, Ankit Sinha akki12...@gmail.com wrote:
I think this will do the same: -
#include stdafx.h
#include stdlib.h
void swap(int *a, int start, int end)
{
int temp;
temp = *(a + start);
*(a + start) = *(a + end);
*(a + end) = temp;
}
int _tmain(int argc, _TCHAR* argv[])
{
int minIndex=0, maxIndex=8;
int i=1;
int a[9] ={1,0,2,1,0,2,0,0,1};
while(imaxIndex)
{
if(a[maxIndex] == 2)
maxIndex--;
if(a[minIndex] == 0)
minIndex++;
if(a[i] a[maxIndex])
{
swap(a, i, maxIndex);
continue;
}
else if (a[i] a[minIndex])
{
swap(a, i, minIndex);
continue;
}
i++;
}
for (i =0 ; i 9; i++)
printf([%d], a[i]);
system(PAUSE);
return 0;
}
Please comment.
Cheers,
Ankit Sinha
On Sat, Sep 24, 2011 at 4:10 PM, malay chakrabarti m1234...@gmail.com
wrote:
dutch national flag problem :)
On Sat, Sep 24, 2011 at 3:45 PM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
i think this travels only once ... correct me if am wrong
#includestdio.h
#includestring.h
#define SWAP(a,b,c) (c)=(a),(a)=(b),(b)=(c)
int main()
{
int t,x;
scanf(%d,t);
while(t--)
{
char str[100];
scanf(%s,str);
int i=0,j=0,k=strlen(str)-1;
while(str[i]=='0')
i++;
while(str[k]=='2')
k--;
j=i;
while(j=k)
{
if(str[j]=='2')
{
SWAP(str[j],str[k],x);
k--;
}
if(str[j]=='0')
{
SWAP(str[i],str[j],x);
i++;
}
if(str[j]!='2')
j++;
}
printf(%s\n,str);
}
return 0;
}
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com
wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 01112
0 1 2
starting_index 0 1 4
ending_index 0 3 4
next character '2'
Re: [algogeeks] Amazon Interview Question
Classic problem http://en.wikipedia.org/wiki/Dutch_national_flag_problem
On Sat, Sep 24, 2011 at 5:15 PM, Ankur Garg ankurga...@gmail.com wrote:
void sort012(int a[],int n){
int i = 0, s = 0, last = n-1;
while(i=last){
if(a[i] == 0 i!=s)
{
swap(a[i], a[s]);
s++;
}
else if(a[i] == 2 i!=last)
{
swap(a[i], a[last]);
last--;
}
else
i++;
}
}
On Sat, Sep 24, 2011 at 5:13 PM, Ankit Sinha akki12...@gmail.com wrote:
I think this will do the same: -
#include stdafx.h
#include stdlib.h
void swap(int *a, int start, int end)
{
int temp;
temp = *(a + start);
*(a + start) = *(a + end);
*(a + end) = temp;
}
int _tmain(int argc, _TCHAR* argv[])
{
int minIndex=0, maxIndex=8;
int i=1;
int a[9] ={1,0,2,1,0,2,0,0,1};
while(imaxIndex)
{
if(a[maxIndex] == 2)
maxIndex--;
if(a[minIndex] == 0)
minIndex++;
if(a[i] a[maxIndex])
{
swap(a, i, maxIndex);
continue;
}
else if (a[i] a[minIndex])
{
swap(a, i, minIndex);
continue;
}
i++;
}
for (i =0 ; i 9; i++)
printf([%d], a[i]);
system(PAUSE);
return 0;
}
Please comment.
Cheers,
Ankit Sinha
On Sat, Sep 24, 2011 at 4:10 PM, malay chakrabarti m1234...@gmail.com
wrote:
dutch national flag problem :)
On Sat, Sep 24, 2011 at 3:45 PM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
i think this travels only once ... correct me if am wrong
#includestdio.h
#includestring.h
#define SWAP(a,b,c) (c)=(a),(a)=(b),(b)=(c)
int main()
{
int t,x;
scanf(%d,t);
while(t--)
{
char str[100];
scanf(%s,str);
int i=0,j=0,k=strlen(str)-1;
while(str[i]=='0')
i++;
while(str[k]=='2')
k--;
j=i;
while(j=k)
{
if(str[j]=='2')
{
SWAP(str[j],str[k],x);
k--;
}
if(str[j]=='0')
{
SWAP(str[i],str[j],x);
i++;
}
if(str[j]!='2')
j++;
}
printf(%s\n,str);
}
return 0;
}
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com
wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 01112
Re: [algogeeks] Amazon Interview Question
Keep two pointers - p1 and p2
p1 points at the index just after last 0 such that there are all zero's
before it.
p2 points at the entry just before last 2, and there are all 2's after it.
*example*- 0010201201222
p1 = 2; p2 = 9;
*Pseudo code - *
p1 = 0;
p2 = n-1;
i = 0;
while(in)
if(A[i]) ==0) swap(p1,i); p1++;
else if (A[i]==1) i++;
else if(A[i]==2) swap (p2,i); p2--;
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1 2
starting_index 0 1 3
ending_index 0 4 3
(ending_index1ending_index2) so we swap the current 1 with starting index
of 2
so string will become 01112
0 1 2
starting_index 0 1 4
ending_index 0 3 4
next character '2'
0 1 2
starting_index 0 1 4
ending_index 0 3 5
(ending_index0ending_index1ending_index2) so no swap
so string will become 011122
next character '0'
0 1 2
starting_index 0 1 4
ending_index 6 3 5
(ending_index0ending_index1ending_index2) so we swap the current 0 with
staring index of 2 first and then with starting index of 1
so string will become 0011122
0 1 2
starting_index 0 2 5
ending_index 1 4 6
and so on i hope its much explained...
On Sat, Sep 24, 2011 at 10:30 AM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
char str[100],t;
scanf(%s,str);
char ch='0';
int i=0,j=0;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
ch='1';
j=i;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
printf(%s\n,str);
On Sat, Sep 24, 2011 at 9:55 AM, Anup Ghatage ghat...@gmail.com wrote:
Is this like the segregating all the 1's to the right and the 0's to the
left
or am i missing something?
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should
Re: [algogeeks] Amazon Interview Question
@guarav true
@others no point in sending the code describe your logic... anyway link
provided by guarav is suffice to solve the problem
On Sat, Sep 24, 2011 at 5:26 PM, Gaurav Aggarwal gaurav91.2...@gmail.comwrote:
Classic problem http://en.wikipedia.org/wiki/Dutch_national_flag_problem
On Sat, Sep 24, 2011 at 5:15 PM, Ankur Garg ankurga...@gmail.com wrote:
void sort012(int a[],int n){
int i = 0, s = 0, last = n-1;
while(i=last){
if(a[i] == 0 i!=s)
{
swap(a[i], a[s]);
s++;
}
else if(a[i] == 2 i!=last)
{
swap(a[i], a[last]);
last--;
}
else
i++;
}
}
On Sat, Sep 24, 2011 at 5:13 PM, Ankit Sinha akki12...@gmail.com wrote:
I think this will do the same: -
#include stdafx.h
#include stdlib.h
void swap(int *a, int start, int end)
{
int temp;
temp = *(a + start);
*(a + start) = *(a + end);
*(a + end) = temp;
}
int _tmain(int argc, _TCHAR* argv[])
{
int minIndex=0, maxIndex=8;
int i=1;
int a[9] ={1,0,2,1,0,2,0,0,1};
while(imaxIndex)
{
if(a[maxIndex] == 2)
maxIndex--;
if(a[minIndex] == 0)
minIndex++;
if(a[i] a[maxIndex])
{
swap(a, i, maxIndex);
continue;
}
else if (a[i] a[minIndex])
{
swap(a, i, minIndex);
continue;
}
i++;
}
for (i =0 ; i 9; i++)
printf([%d], a[i]);
system(PAUSE);
return 0;
}
Please comment.
Cheers,
Ankit Sinha
On Sat, Sep 24, 2011 at 4:10 PM, malay chakrabarti m1234...@gmail.com
wrote:
dutch national flag problem :)
On Sat, Sep 24, 2011 at 3:45 PM, Dheeraj Sharma
dheerajsharma1...@gmail.com wrote:
i think this travels only once ... correct me if am wrong
#includestdio.h
#includestring.h
#define SWAP(a,b,c) (c)=(a),(a)=(b),(b)=(c)
int main()
{
int t,x;
scanf(%d,t);
while(t--)
{
char str[100];
scanf(%s,str);
int i=0,j=0,k=strlen(str)-1;
while(str[i]=='0')
i++;
while(str[k]=='2')
k--;
j=i;
while(j=k)
{
if(str[j]=='2')
{
SWAP(str[j],str[k],x);
k--;
}
if(str[j]=='0')
{
SWAP(str[i],str[j],x);
i++;
}
if(str[j]!='2')
j++;
}
printf(%s\n,str);
}
return 0;
}
On Sat, Sep 24, 2011 at 11:39 AM, Yogesh Yadav medu...@gmail.com
wrote:
we cant traverse the string twice...
if there is an error in my logic then plz tell
my logic is:
we have to take starting and ending indexes for '0','1','2' like
below
0 1 2
starting_index
ending_index
now suppose our string 102112011
so we start from the left and traverse the whole string
first character ='1'
0 1 2
starting_index 0
ending_index 0
next character = '0'
0 1 2
starting_index 1 0
ending_index 1 0
( ending_index0 ending_index1 ) so we swap the numbers according to
Starting_index not according to Ending_index
So it will become
0 1 2
starting_index 0 1
ending_index 0 1
and string will become 01
next character '2'
0 1 2
starting_index 0 1 2
ending_index 0 1 2
(ending_index0ending_index1ending_index2)so ending indexes in
increasing order...so no need to swap
so string is now 012
next character '1'
0 1 2
starting_index 0 1 2
ending_index 0 3 2
(ending_index1ending_index2) so we swap the current 1 with starting
index of 2
so string will become 0112
0 1 2
starting_index 0 1 3
ending_index 0 2 3
next character '1'
0 1
Re: [algogeeks] Amazon Interview Question
Is this like the segregating all the 1's to the right and the 0's to the left or am i missing something? On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote: You are given a string (consisting of 0's, 1's or 2's) where 0 represents a blue ball, 1 a red ball, and 2 a black ball. Using only swap operations (counting sort not allowed) rearrange the string such that all blue balls are together on one side, followed by all red balls, and then all black balls. You can iterate through the string only once. Eg 102112011 should produce 00122? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Anup Ghatage -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
char str[100],t;
scanf(%s,str);
char ch='0';
int i=0,j=0;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
ch='1';
j=i;
while(jstrlen(str))
{
if(str[j]==ch)
{
SWAP(str[i],str[j],t);
i++;
}
j++;
}
printf(%s\n,str);
On Sat, Sep 24, 2011 at 9:55 AM, Anup Ghatage ghat...@gmail.com wrote:
Is this like the segregating all the 1's to the right and the 0's to the
left
or am i missing something?
On Sat, Sep 24, 2011 at 9:39 AM, VIHARRI viharri@gmail.com wrote:
You are given a string (consisting of 0's, 1's or 2's) where 0
represents a blue ball, 1 a
red ball, and 2 a black ball. Using only swap operations (counting
sort not allowed)
rearrange the string such that all blue balls are together on one
side, followed by all red
balls, and then all black balls. You can iterate through the string
only once.
Eg 102112011 should produce 00122?
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
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http://groups.google.com/group/algogeeks?hl=en.
--
Anup Ghatage
--
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--
*Dheeraj Sharma*
Comp Engg.
NIT Kurukshetra
--
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Re: [algogeeks] Amazon Interview Question
@Ravi +1 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/E0NIFwY150EJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview question
I would like to have pseudo for this . On Mon, Feb 7, 2011 at 11:12 AM, jalaj jaiswal jalaj.jaiswa...@gmail.comwrote: A very common interview question let the array be from 0 to 2n-1 now, every element of array has its initial position and final position.. start from beginning if the elemnt you r processing is the first half of array then f=i+i; else f=2*i-(2n-1); replace the elemnt at final position with the initial element .. now next elemnt to process will be oroginal elemnt at final position if the final position is empty or the same position then process next element to the initial position. do until you process the last element. inplace with O(n). On Mon, Feb 7, 2011 at 8:32 AM, may.I.answer may.i.answ...@gmail.comwrote: If [a1,a2,a3...,an,b1,b2...bn] is given input change this to [a1,b1,a2,b2.an,bn] -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Final Year Undergraduate, IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview question
algo in more detail :-o if the array is numbered from 0..(2n-1) i= initial position of int/char f= final position of int/char if (i (2n-1)/2) #for integer f = i+i else #for char f = i - ((2n-1)-i) so iterate through the array in the following way choose first element determine it final position put the element in the final position the next element to be processed is the original element in the final position if initial position=final position or the final position was empty,then choose the next element(element next to the initial position) as current element stop when last element has been processed. eg 1234abcd current = 1 i = 0 f = 0+0 = 0 i=f so current= next element= 2 i=1 f=1+1=2 put 2 in 2nd position 1-24abcd current element = original element in 2nd position = 3 for 3 i = 2 f=2+2=4 so put 3 in 4th position 1-243bcd current =a i=4 f=(i - ((2n-1)-i) = (4-(7-4)) = 1 1a243bcd now final position was empty so next element = intital position +1 = intitial position of a +1 = 4 +1 = 5 current = b processing in a similar way 1a2b3-cd current = 4 1a2b3-4d current = c 1a2b3c4d current = d 1a2b3c4d processed last element so stop can't explain more better :-o On Mon, Feb 7, 2011 at 10:59 PM, Manmeet Singh mans.aus...@gmail.comwrote: thr is some error in algo On Mon, Feb 7, 2011 at 10:48 PM, abc abc may.i.answ...@gmail.com wrote: I would like to have pseudo for this . On Mon, Feb 7, 2011 at 11:12 AM, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: A very common interview question let the array be from 0 to 2n-1 now, every element of array has its initial position and final position.. start from beginning if the elemnt you r processing is the first half of array then f=i+i; else f=2*i-(2n-1); replace the elemnt at final position with the initial element .. now next elemnt to process will be oroginal elemnt at final position if the final position is empty or the same position then process next element to the initial position. do until you process the last element. inplace with O(n). On Mon, Feb 7, 2011 at 8:32 AM, may.I.answer may.i.answ...@gmail.comwrote: If [a1,a2,a3...,an,b1,b2...bn] is given input change this to [a1,b1,a2,b2.an,bn] -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Final Year Undergraduate, IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems Final Year Undergraduate, IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview question
@above, if initial position=final position or the final position was empty,then choose the next element(element next to the initial position) as current element How do you guarantee when you move to the next element, the next element is not already processed? Otherwise, you will double process on element. On Mon, Feb 7, 2011 at 9:36 AM, jalaj jaiswal jalaj.jaiswa...@gmail.comwrote: algo in more detail :-o if the array is numbered from 0..(2n-1) i= initial position of int/char f= final position of int/char if (i (2n-1)/2) #for integer f = i+i else #for char f = i - ((2n-1)-i) so iterate through the array in the following way choose first element determine it final position put the element in the final position the next element to be processed is the original element in the final position if initial position=final position or the final position was empty,then choose the next element(element next to the initial position) as current element stop when last element has been processed. eg 1234abcd current = 1 i = 0 f = 0+0 = 0 i=f so current= next element= 2 i=1 f=1+1=2 put 2 in 2nd position 1-24abcd current element = original element in 2nd position = 3 for 3 i = 2 f=2+2=4 so put 3 in 4th position 1-243bcd current =a i=4 f=(i - ((2n-1)-i) = (4-(7-4)) = 1 1a243bcd now final position was empty so next element = intital position +1 = intitial position of a +1 = 4 +1 = 5 current = b processing in a similar way 1a2b3-cd current = 4 1a2b3-4d current = c 1a2b3c4d current = d 1a2b3c4d processed last element so stop can't explain more better :-o On Mon, Feb 7, 2011 at 10:59 PM, Manmeet Singh mans.aus...@gmail.comwrote: thr is some error in algo On Mon, Feb 7, 2011 at 10:48 PM, abc abc may.i.answ...@gmail.com wrote: I would like to have pseudo for this . On Mon, Feb 7, 2011 at 11:12 AM, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote: A very common interview question let the array be from 0 to 2n-1 now, every element of array has its initial position and final position.. start from beginning if the elemnt you r processing is the first half of array then f=i+i; else f=2*i-(2n-1); replace the elemnt at final position with the initial element .. now next elemnt to process will be oroginal elemnt at final position if the final position is empty or the same position then process next element to the initial position. do until you process the last element. inplace with O(n). On Mon, Feb 7, 2011 at 8:32 AM, may.I.answer may.i.answ...@gmail.comwrote: If [a1,a2,a3...,an,b1,b2...bn] is given input change this to [a1,b1,a2,b2.an,bn] -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Final Year Undergraduate, IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Software developer, Cisco Systems Final Year Undergraduate, IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview question
I tried implementing the problem.
Working code is:
#include stdio.h
void print_arr(int* arr, int len)
{
int i;
printf(\n Array is \n);
for (i = 0; i len; i++)
{
printf(%d , arr[i]);
}
printf(\n);
}
int get_right_index(int i, int len)
{
if (i len/2) {
return 2*i;
}
return 2*(i-len/2)+1;
}
int get_right_candidate(int i, int len)
{
if (i%2) {
return (i-1)/2 + len/2;
}
return i/2;
}
void make_pattern(int* arr, int len)
{
if (len%2) {
return;
}
if (len == 2)
{
return;
}
int total_no_assign = 0;
int index = 1;
while (total_no_assign (len -2)) {
int cur = index;
int val = arr[cur];
int target_index = get_right_index(cur, len);
if (val 0) {
printf(\n Already shuffled);
index++;
continue;
}
while(cur != target_index) {
int ci = get_right_candidate(cur, len);
arr[cur] = 0 - arr[ci];
printf(\n Index shuffled cur = %d, ci = %d\n, cur, ci);
cur = ci;
total_no_assign++;
print_arr(arr, len);
}
arr[cur] = 0 - val;
total_no_assign++;
print_arr(arr, len);
}
int i;
for (i = 0; i len; i++) {
if (arr[i] 0) {
arr[i] = 0 - arr[i];
}
}
}
int main()
{
int count;
int* arr;
printf(\nEnter no of elements (array elemnts should be striclty greater
than 0) );
scanf(%d, count);
if (count%2) {
return -1;
}
arr = (int*) malloc(sizeof(int)*count);
if (!arr) {
return;
}
int i;
for ( i = 1; i = count; i++)
{
printf(\nEnter element %d , i);
scanf(%d, arr[i-1]);
}
print_arr(arr, count);
make_pattern(arr, count);
print_arr(arr, count);
return 0;
}
Please correct me if the code is wrong.
I tested with few inputs.
On Mon, Feb 7, 2011 at 11:43 PM, yq Zhang zhangyunq...@gmail.com wrote:
@above, if initial position=final position or the final position was
empty,then choose the next element(element next to the initial position) as
current element
How do you guarantee when you move to the next element, the next element is
not already processed? Otherwise, you will double process on element.
On Mon, Feb 7, 2011 at 9:36 AM, jalaj jaiswal
jalaj.jaiswa...@gmail.comwrote:
algo in more detail :-o
if the array is numbered from 0..(2n-1)
i= initial position of int/char
f= final position of int/char
if (i (2n-1)/2) #for integer
f = i+i
else #for char
f = i - ((2n-1)-i)
so iterate through the array in the following way
choose first element
determine it final position
put the element in the final position
the next element to be processed is the original element in the final
position
if initial position=final position or the final position was empty,then
choose the next element(element next to the initial position) as current
element
stop when last element has been processed.
eg
1234abcd
current = 1
i = 0
f = 0+0 = 0
i=f
so current= next element= 2
i=1
f=1+1=2
put 2 in 2nd position
1-24abcd
current element = original element in 2nd position = 3
for 3
i = 2
f=2+2=4
so put 3 in 4th position
1-243bcd
current =a
i=4
f=(i - ((2n-1)-i) = (4-(7-4)) = 1
1a243bcd
now final position was empty
so next element = intital position +1
= intitial position of a +1 =
4 +1 = 5
current = b
processing in a similar way
1a2b3-cd
current = 4
1a2b3-4d
current = c
1a2b3c4d
current = d
1a2b3c4d
processed last element so stop
can't explain more better :-o
On Mon, Feb 7, 2011 at 10:59 PM, Manmeet Singh mans.aus...@gmail.comwrote:
thr is some error in algo
On Mon, Feb 7, 2011 at 10:48 PM, abc abc may.i.answ...@gmail.comwrote:
I would like to have pseudo for this .
On Mon, Feb 7, 2011 at 11:12 AM, jalaj jaiswal
jalaj.jaiswa...@gmail.com wrote:
A very common interview question
let the array be from 0 to 2n-1
now,
every element of array has its initial position and final position..
start from beginning
if the elemnt you r processing is the first half of array then f=i+i;
else f=2*i-(2n-1);
replace the elemnt at final position with the initial element .. now
next elemnt to process will be oroginal elemnt at final position
if the final position is empty or the same position then process next
element to the initial position.
do until you process the last element.
inplace with O(n).
On Mon, Feb 7, 2011 at 8:32 AM, may.I.answer
may.i.answ...@gmail.comwrote:
If [a1,a2,a3...,an,b1,b2...bn] is given input change this to
[a1,b1,a2,b2.an,bn]
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For
Re: [algogeeks] Amazon Interview question
A very common interview question let the array be from 0 to 2n-1 now, every element of array has its initial position and final position.. start from beginning if the elemnt you r processing is the first half of array then f=i+i; else f=2*i-(2n-1); replace the elemnt at final position with the initial element .. now next elemnt to process will be oroginal elemnt at final position if the final position is empty or the same position then process next element to the initial position. do until you process the last element. inplace with O(n). On Mon, Feb 7, 2011 at 8:32 AM, may.I.answer may.i.answ...@gmail.comwrote: If [a1,a2,a3...,an,b1,b2...bn] is given input change this to [a1,b1,a2,b2.an,bn] -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards, *Jalaj Jaiswal* (+919019947895) Final Year Undergraduate, IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question about Linked Lists
@Saurabh You used an extra pointer compared to shiva's code ,you can avoid that. :) On Mon, Dec 20, 2010 at 8:24 PM, Saurabh Koar saurabhkoar...@gmail.comwrote: @Rishi:I think Shiva's code is also fine.U can access the list easily by using down pointer in his code. Because he is assigning temp-down=temp2 and then he is making temp-fwd=NULL. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Thanks Regards Nikhil Agarwal Senior Undergraduate Computer Science Engineering, National Institute Of Technology, Durgapur,India http://tech-nikk.blogspot.com http://beta.freshersworld.com/communities/nitd -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question about Linked Lists
@Nikhil: ya..rt -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question about Linked Lists
See inline ..
On Sat, Dec 18, 2010 at 12:09 PM, siva viknesh sivavikne...@gmail.comwrote:
Given a linked list structure where every node represents a linked list
and contains two pointers of its type:
(i) pointer to next node in the main list.
(ii) pointer to a linked list where this node is head.
Write a C function to flatten the list into a single linked list.
Eg.
If the given linked list is
1 -- 5 -- 7 -- 10
| | |
2 6 8
| |
3 9
|
4
then convert it to
1 - 2 - 3 - 4 - 5 - 6 - 9 - 7 - 8 -10
My solution - not tested :
struct node
{
int data;
struct node *fwd; //pointer to next node in the main list.
struct node *down; //pointer to a linked list where this node is head.
}*head,*temp,*temp2;
temp=head;
while(temp-fwd!=NULL)
{
temp2=temp-fwd;
while(temp-down!=NULL)
{
temp=temp-down;
}
temp-down=temp2;
// how will the code access the flattened linked list by down or by fwd ? In
this case there in no particular pointer by which the code can access the
linked list. Try to write a function to print the flattened linked list.
temp-fwd=NULL;
temp=temp2;
}
plz notify me if anything...other solutions and optimizations are welcome
--
Regards,
$iva
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Re: [algogeeks] Amazon Interview Question about Linked Lists
temp=head;
temp1=temp-fwd;
while(temp-fwd!=NULL)
{
temp2=temp;
while(temp2-down!=NULL)
temp2=temp2-link;
temp2-down=temp1;
temp-fwd=NULL;
temp=temp1;
temp1=temp1-fwd;
}
U can print the linked list using down pointer.Hope this will
work.Correct me if I m wrong.
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Re: [algogeeks] Amazon Interview Question about Linked Lists
@Rishi:I think Shiva's code is also fine.U can access the list easily
by using down pointer in his code.
Because he is assigning temp-down=temp2 and then he is making temp-fwd=NULL.
On 12/20/10, Saurabh Koar saurabhkoar...@gmail.com wrote:
temp=head;
temp1=temp-fwd;
while(temp-fwd!=NULL)
{
temp2=temp;
while(temp2-down!=NULL)
temp2=temp2-link;
temp2-down=temp1;
temp-fwd=NULL;
temp=temp1;
temp1=temp1-fwd;
}
U can print the linked list using down pointer.Hope this will
work.Correct me if I m wrong.
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Re: [algogeeks] Amazon Interview Question about Linked Lists
@Rishi:I think Shiva's code is also fine.U can access the list easily by using down pointer in his code. Because he is assigning temp-down=temp2 and then he is making temp-fwd=NULL. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview Question
What if we have an array :- index - 1 2 3 4 5 value - 1 2 3 4 5 How will ANY logn solution determine all ALL elements are equal to it's index value ? Maybe I misunderstand. Thank you, Ashim On Sat, Dec 4, 2010 at 5:38 PM, ankit sablok ankit4...@gmail.com wrote: u can then move to other advance data structures On Sat, Dec 4, 2010 at 4:58 PM, mo...@ismu mohan...@gmail.com wrote: in worst case it takes o(n)time if all the elemets match with their indexes -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
