Re: [algogeeks] Re: question at K10
and also
void change()
{
// Code here
int x = 1;
int*p= x;
while(*p != 5) p++;
*p = 10;
}
On Wed, Feb 16, 2011 at 8:02 AM, Balaji S balaji.ceg...@gmail.com wrote:
The solution is..
_AX = 10;
can anyone explain??
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Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee
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Re: [algogeeks] Re: question at K10
a one line solution is needed... -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: question at K10
after termination of semicolon , that will be considered a separate line i
guess
On Tue, Feb 15, 2011 at 10:59 PM, Don dondod...@gmail.com wrote:
void change()
{
printf(10); while(1) {}
}
On Feb 15, 10:17 am, Balaji S balaji.ceg...@gmail.com wrote:
Insert only one line in the function change() so that the output of the
program is 10.
You are not allowed to use exit(). You are not allowed to edit the
function
main() or to
pass the parameter to change()
void change()
{
// Code here}
int main()
{
int i=5;
change();
printf(“%d” ,i);
return 0;
}
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With Regards,
*Jalaj Jaiswal* (+919019947895)
Software developer, Cisco Systems
B.Tech IIIT ALLAHABAD
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Re: [algogeeks] Re: question at K10
Nothing... 10 in base 5 = 5 in base 10.
void change(){
printf(); //...?
}
2011/2/15 Don dondod...@gmail.com
A semicolon is valid in the middle of a line in C or C++.
For instance, no one says that
for(i = 0; i 10; ++i)
is three lines of code.
Don
On Feb 15, 11:31 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote:
after termination of semicolon , that will be considered a separate line
i
guess
On Tue, Feb 15, 2011 at 10:59 PM, Don dondod...@gmail.com wrote:
void change()
{
printf(10); while(1) {}
}
On Feb 15, 10:17 am, Balaji S balaji.ceg...@gmail.com wrote:
Insert only one line in the function change() so that the output of
the
program is 10.
You are not allowed to use exit(). You are not allowed to edit the
function
main() or to
pass the parameter to change()
void change()
{
// Code here}
int main()
{
int i=5;
change();
printf(“%d” ,i);
return 0;
}
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With Regards,
*Jalaj Jaiswal* (+919019947895)
Software developer, Cisco Systems
B.Tech IIIT ALLAHABAD
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Re: [algogeeks] Re: question at K10
void change()
{
#define i i=10,n
}
this will do..
On Tue, Feb 15, 2011 at 11:33 PM, Rel Guzman Apaza rgap...@gmail.comwrote:
Nothing... 10 in base 5 = 5 in base 10.
void change(){
printf(); //...?
}
2011/2/15 Don dondod...@gmail.com
A semicolon is valid in the middle of a line in C or C++.
For instance, no one says that
for(i = 0; i 10; ++i)
is three lines of code.
Don
On Feb 15, 11:31 am, jalaj jaiswal jalaj.jaiswa...@gmail.com wrote:
after termination of semicolon , that will be considered a separate line
i
guess
On Tue, Feb 15, 2011 at 10:59 PM, Don dondod...@gmail.com wrote:
void change()
{
printf(10); while(1) {}
}
On Feb 15, 10:17 am, Balaji S balaji.ceg...@gmail.com wrote:
Insert only one line in the function change() so that the output of
the
program is 10.
You are not allowed to use exit(). You are not allowed to edit the
function
main() or to
pass the parameter to change()
void change()
{
// Code here}
int main()
{
int i=5;
change();
printf(“%d” ,i);
return 0;
}
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Groups
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With Regards,
*Jalaj Jaiswal* (+919019947895)
Software developer, Cisco Systems
B.Tech IIIT ALLAHABAD
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Re: [algogeeks] Re: question at K10
nice solution -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: question at K10
The solution is.. _AX = 10; can anyone explain?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
