complex split (when delimiter appears in one of the fields)
Hi, I have a string that looks like this: my $string = 1, 3, 0. 0. 0. 0, 22, Zak',adfk $! mac., ; Basically, there are seven fields. after the bird, everything up to the last comma is the 5th field. 6th field is blank. Now my problem is splitting it and extracting the 5th field. If I will do a (split/,/,$string)[-2]) then i will only get adfk $! mac. I need to get the entire Zak' , adfk $! mac. -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: complex split (when delimiter appears in one of the fields)
Hi Michael, Michael Alipio wrote: I have a string that looks like this: my $string = 1, 3, 0. 0. 0. 0, 22, Zak',adfk $! mac., ; Basically, there are seven fields. after the bird, everything up to the last comma is the 5th field. 6th field is blank. Now my problem is splitting it and extracting the 5th field. If I will do a (split/,/,$string)[-2]) then i will only get adfk $! mac. I need to get the entire Zak' , adfk $! mac. I doubt this is the best way, but I would use both split and a regular expression. The first split, I would specify there are only five fields so that the 5th, 6th, and 7th fields ends up in the remainder of split (split with three arguments). Then I would use a regular expression on these three fields and pull out the last two. I suppose a human looking at the line would do something similar (remove the fields known not to have commas first and what's left is the 5th). If two fields can have commas...then I'm not sure what to do. :-) Ray -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
AW: complex split (when delimiter appears in one of the fields)
Michael Alipio daem0n...@yahoo.com asked:
I have a string that looks like this:
my $string = 1, 3, 0. 0. 0. 0, 22, Zak',adfk $! mac., ;
Basically, there are seven fields. after the bird, everything up to the
last comma is the 5th field. 6th field is blank.
Now my problem is splitting it and extracting the 5th field.
If I will do a (split/,/,$string)[-2]) then i will only get adfk $!
mac.
I need to get the entire Zak' , adfk $! mac.
Obviously you can't expect split to guess which comma is part of a field and
which is a record separator.
Without more information I'd say that you've chosen the wrong separator to
split on - instead just a comma, it should be a comma and whitespace. That in
turn means that there are only
#!/usr/bin/perl -w
use strict;
my $string = q(1, 3, 0. 0. 0. 0, 22, Zak',adfk $! mac., );
my $i = 0;
foreach ( split /,\s+/, $string ){
print $i: $_\n;
$i++;
}
__END__
HTH,
Thomas
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Re: complex split (when delimiter appears in one of the fields)
Michael Alipio wrote: Hi, Hello, I have a string that looks like this: my $string = 1, 3, 0. 0. 0. 0, 22, Zak',adfk $! mac., ; Basically, there are seven fields. after the bird, everything up to the last comma is the 5th field. 6th field is blank. Now my problem is splitting it and extracting the 5th field. If I will do a (split/,/,$string)[-2]) then i will only get adfk $! mac. I need to get the entire Zak' , adfk $! mac. ( split /(?!'),/, $string )[ -2 ] John -- Those people who think they know everything are a great annoyance to those of us who do.-- Isaac Asimov -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
pass int* to perl
Hello, I need to call perl from c. To pass an integer, I use to make a newSViv. How do I do to pass a int* ? Should I just cast the int* to int ans passed as an SV ? in perl I need to get the value by $$var. Thank. -- --- == Patrick DUPRÉ | | Department of Chemistry| |Phone: (44)-(0)-1904-434384 The University of York | |Fax: (44)-(0)-1904-432516 Heslington | | York YO10 5DD United Kingdom | |email: pd...@york.ac.uk == -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
How to read RegEx match in to a variable?
Team, I am a totally newbee to perl scripting. I have learned enough to understand somebody's simple scripts and written some basic ones. Below is what I am trying to achieve. I am writing a wrapper script to trigger when a syslog message arrives to syslog-ng. It fires up my parser.pl script by passing whole message as an argument. The message looks like this. Jun 2 22:34:30 172.24.100.1 Jun 02 2009 22:34:33 home-pix : %PIX-6-302013: Built inbound TCP connection 3933236 for outside:172.23.1.1/50229 (172.23.1.1/50229) to inside:172.24.100.25/1 (172.24.100.25/1) (smunzani) What I am trying to do is use RegEx to extract information from this. I want to capture IP address to a variable, hostname to another variable and anything after PIX-6-302013: as message variable. I was able to hack through creating the RegEx to match my requirements. However I don't know how to pass RegEx matches strings to value of another variable. Any hints, examples? Thanks, Sam -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: How to read RegEx match in to a variable?
Sam Munzani wrote: Team, I am a totally newbee to perl scripting. I have learned enough to understand somebody's simple scripts and written some basic ones. Below is what I am trying to achieve. I am writing a wrapper script to trigger when a syslog message arrives to syslog-ng. It fires up my parser.pl script by passing whole message as an argument. The message looks like this. Jun 2 22:34:30 172.24.100.1 Jun 02 2009 22:34:33 home-pix : %PIX-6-302013: Built inbound TCP connection 3933236 for outside:172.23.1.1/50229 (172.23.1.1/50229) to inside:172.24.100.25/1 (172.24.100.25/1) (smunzani) What I am trying to do is use RegEx to extract information from this. I want to capture IP address to a variable, hostname to another variable and anything after PIX-6-302013: as message variable. I was able to hack through creating the RegEx to match my requirements. However I don't know how to pass RegEx matches strings to value of another variable. A regular expression *is* a string, it operates on strings and it returns strings. For example: ( $string1 ) = $string2 =~ /$string3/; What do you mean by RegEx matches strings? John -- Those people who think they know everything are a great annoyance to those of us who do.-- Isaac Asimov -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
YAPC::NA
hi all, it is a late announcement here but you should all know that YAPC::NA is in pittsburgh at CMU. it runs from june 22-25, 2009. it is the only pure perl conference in NA and it is a blast and a great place to meet other perl hackers. there will be talks for all skill levels and 2 extra days of low cost training available. the conference fee is very low and expenses are low if you stay in the dorms. find out more and register at yapc10.org. uri -- Uri Guttman -- u...@stemsystems.com http://www.sysarch.com -- - Perl Code Review , Architecture, Development, Training, Support -- - Free Perl Training --- http://perlhunter.com/college.html - - Gourmet Hot Cocoa Mix http://bestfriendscocoa.com - -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
YAPC::NA
hi all, it is a late announcement here but you should all know that YAPC::NA is in pittsburgh at CMU. it runs from june 22-25, 2009. it is the only pure perl conference in NA and it is a blast and a great place to meet other perl hackers. there will be talks for all skill levels and 2 extra days of low cost training available. the conference fee is very low and expenses are low if you stay in the dorms. find out more and register at yapc10.org. uri -- Uri Guttman -- u...@stemsystems.com http://www.sysarch.com -- - Perl Code Review , Architecture, Development, Training, Support -- - Free Perl Training --- http://perlhunter.com/college.html - - Gourmet Hot Cocoa Mix http://bestfriendscocoa.com - -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Please, I need help!!!
Hallo @ all,
i am new in this domain(perlscript) and i have a question.i have a
array,i sort it,i get the last element of the array but i want to get
the next element after this one.how can i do this?
for example:
$arr1=(6,3,8,1) ---my last element is 1 and mark that is the last
element
now i sort them $arr1=(1,3,6,8)
my last element is 1 and now i want to go to the next element in the
list,how can i do this?
if i do something like this:$next=$last+1; ---in this case $next will
be 2 and this is not my third element in my list,i want the 3.
BR,
Phil
here is my code:
@arr[1]=(3,7,13,1,19,5,9);
@array=split(/,/,@arr[1]);
$i=0;
while(@array[$i])
{
$i=$i+1;
}
printAnzahl:$i\n;
@sorty=sort(Nummernsort @array);
sub Nummernsort{
if($a$b){
return -1;
}elsif($a==$b){
return 0;
}else{
return 1;
}
}
print sort:@sorty\n;
$last=$array[$i-1];
print last:$last\n;
$next=?
printnextt=$next\n;
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Re: Please, I need help!!!
On 6/11/09 Thu Jun 11, 2009 11:00 AM, Phillip fibbe...@gmx.net
scribbled:
Hallo @ all,
i am new in this domain(perlscript) and i have a question.i have a
array,i sort it,i get the last element of the array but i want to get
the next element after this one.how can i do this?
There is a language called Perlscript that is based on Perl but not the
same. Are you asking about that language or about Perl itself? I will assume
the latter, as this is a Perl list, and as I cannot answer any questions
about Perlscript.
for example:
$arr1=(6,3,8,1) ---my last element is 1 and mark that is the last
element
now i sort them $arr1=(1,3,6,8)
my last element is 1 and now i want to go to the next element in the
list,how can i do this?
if i do something like this:$next=$last+1; ---in this case $next will
be 2 and this is not my third element in my list,i want the 3.
Yes, you cannot freely intermix array indices and values.
here is my code:
@arr[1]=(3,7,13,1,19,5,9);
@arr[1] is not the syntax for an array element. It is an array slice with
one element, so might give you equivalent results in some applications, but
you should be using proper syntax. You also don't need and array here, as
you have only one string.
You should be using 'use strict;' and 'use warnings;'
my $text = '3,7,13,1,19,5,9';
@array=split(/,/,@arr[1]);
You can use Perl's qw() operator to form literal arrays:
my @array = qw( 3 7 13 1 19 5 9 );
$i=0;
while(@array[$i])
{
$i=$i+1;
}
Perl has a built-in syntax for the highest index of an array: $#array:
my $i = $#array;
printAnzahl:$i\n;
@sorty=sort(Nummernsort @array);
sub Nummernsort{
if($a$b){
return -1;
}elsif($a==$b){
return 0;
}else{
return 1;
}
}
Perl has a built-in sort function, which defaults to alphabetical order. For
numerical order, you must supply an explicit comparison function, in which
you can use Perl's tri-state comparison operator:
my @sorty = sort { $a = $b } @array;
print sort:@sorty\n;
$last=$array[$i-1];
print last:$last\n;
$next=?
printnextt=$next\n;
You can iterate over the sorted array and find the first element larger than
$last, the last element of the original array. That assumes that 1) you do
not have duplicate elements, and 2) the last element of the original array
is never the largest element in that array. If those assumptions are not
valid, some more logic will be required.
Here is a sample program:
#!/usr/local/bin/perl
use strict;
use warnings;
my @array = qw( 3 7 13 1 19 5 9 );
my $last = $array[$#array];
my @sorted = sort { $a = $b } @array;
my $next;
for ( @sorted ) {
if( $_ $last ) {
$next = $_;
last;
}
}
if( defined $next ) {
print The element after $last is $next\n;
}else{
print $last is the largest element in the array\n;
}
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Re: Please, I need help!!!
From: Jim Gibson jimsgib...@gmail.com On 6/11/09 Thu Jun 11, 2009 11:00 AM, Phillip fibbe...@gmx.net scribbled: Hallo @ all, i am new in this domain(perlscript) and i have a question.i have a array,i sort it,i get the last element of the array but i want to get the next element after this one.how can i do this? There is a language called Perlscript that is based on Perl but not the same. Are you asking about that language or about Perl itself? Are you sure? Any pointers? As far as I know ActiveState has/had something called PerlScript, but it's not a different langauge. It's just a scripting engine for Windows Scripting Host, Internet Explorer and MS IIS/ASP. Just a DLL that allows you to use Perl in those environments. Not a different language. Jenda = je...@krynicky.cz === http://Jenda.Krynicky.cz = When it comes to wine, women and song, wizards are allowed to get drunk and croon as much as they like. -- Terry Pratchett in Sourcery -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Request for code feedback
Hi all, I'm still in the process of updating/replacing some accounting applications, and thought I'd ask for a peer review. I understand that everyone has a life et-al, but if there is a chance that anyone could take a look at this particular piece of code I wrote and provide some in-context feedback as to how I could make it better/more efficient etc, it will help me a great deal going forward. I've already got a few ideas to 'smarten-up' my two modules which are used in the program, but my objective here is feedback on my coding style in general. If anyone has the time to review and report, I would much appreciate it. Code is here: http://ipv6canada.com/extra_billing.txt Steve smime.p7s Description: S/MIME Cryptographic Signature
Re: pass int* to perl
On Fri, Jun 12, 2009 at 10:49 PM, Patrick Dupre pd...@york.ac.uk wrote:
To pass an integer, I use to make a newSViv.
How do I do to pass a int* ?
Perhaps not exactly what you're after ... hope it helps:
##
use warnings;
use Inline C = Config =
BUILD_NOISY = 1;
use Inline C = 'EOC';
void foo(SV * x) {
int i = SvIV(SvRV(x));
printf(%d\n, i);
}
SV * bar() {
int i, *iptr;
SV *obj_ref, *obj;
iptr = i;
i = 1234567;
obj_ref = newSV(0);
obj = newSVrv(obj_ref, NULL);
sv_setiv(obj, *iptr);
SvREADONLY_on(obj); /* optional */
return obj_ref;
}
EOC
$x = 173;
foo(\$x);
$ref = bar();
print $$ref, \n;
##
Outputs:
17
1234567
Cheers,
Rob
Copying a named hash to an anonymous hash
I've created a complex, nested data structure that is, at its
outermost level, a hash: %qa. It collects QA statistics for a school.
Now I want to be able to process multiple schools in one run, so I've
created another hash, %sch_qa, whose key is School Name and whose
value is a ref to *a copy of* %qa.
Assuming $sch_name is the name of the school, I wrote this:
if ( ! exists $sch_qa{$sch_name} ) {
%{$sch_qa{$sch_name}} = %qa;
}
That seemed to execute okay. At the end, however, when I dumped
%sch_qa it looked pretty strange. Actually, the first entry looks
somewhat normal. It's the last three that are weird: they all seem to
recursively refer to this entire hash.
Am I duplicating the original %qa hash correctly?
Thanks for any help!
Chap
$VAR1 = {
'173' = {
'M_Admins' = {
'SchoolID' = {
'notnull' = []
},
'first_name' = {
'notnull' = []
},
'last_name' = {
'notnull' = [],
'alpha' = []
}
},
'M_Discipline' = {
'Student_Number' = {
'notnull' = []
},
'Consequence' = {
'histo'
= [
{
'011
' = 4,
'002
' = 83,
'' =
60,
'081
' = 1,
'XRD
' = 235,
'XTO
' = 60,
'022
' = 12,
'004
' = 16,
}
]
},
'Last_Name' = {
'notnull'
= []
},
'SchoolID' = {
'constant'
= [
10114
]
},
'First_Name' = {
'notnull'
= []
},
'Category' = {
'histo' = [
{
'' =
13802
}
]
}
},
'M_Historical_Grades' = {
'Storecode' = {
'histo' = [
{
'S1
' = 7090,
'YR
' = 12548,
'S2
' = 3783,
'2007
-2' = 7,
'SS
' = 126
}
Re: Please, I need help!!!
Phillip wrote:
Hallo @ all,
Hello,
i am new in this domain(perlscript) and i have a question.i have a
array,i sort it,i get the last element of the array but i want to get
the next element after this one.how can i do this?
for example:
$arr1=(6,3,8,1) ---my last element is 1 and mark that is the last
element
now i sort them $arr1=(1,3,6,8)
my last element is 1 and now i want to go to the next element in the
list,how can i do this?
if i do something like this:$next=$last+1; ---in this case $next will
be 2 and this is not my third element in my list,i want the 3.
BR,
Phil
here is my code:
@arr[1]=(3,7,13,1,19,5,9);
@array=split(/,/,@arr[1]);
That should be:
my @array = ( 3, 7, 13, 1, 19, 5, 9 );
$i=0;
while(@array[$i])
{
$i=$i+1;
}
printAnzahl:$i\n;
print Anzahl:, scalar @array, \n;
@sorty=sort(Nummernsort @array);
sub Nummernsort{
if($a$b){
return -1;
}elsif($a==$b){
return 0;
}else{
return 1;
}
}
my @sorty = sort Nummernsort @array;
sub Nummernsort { $a = $b }
print sort:@sorty\n;
$last=$array[$i-1];
my $last = $array[ -1 ];
print last:$last\n;
$next=?
Do you want the next-to-last?
my $next = $array[ -2 ];
printnextt=$next\n;
John
--
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annoyance to those of us who do.-- Isaac Asimov
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RE: Request for code feedback
Steve Bertrand wrote: If anyone has the time to review and report, I would much appreciate it. http://ipv6canada.com/extra_billing.txt 1. I don't see a header comment block. 2. I don't see comment section boundaries. 3. I don't see author information. 4. I don't see a copyright notice. 5. I don't see any POD. 6. I don't see command line options/ processing. 7. I don't see a usage message. 8. I prefer 4 column indentation. 9. I prefer limiting my code to 72 columns. 10. I don't see a version control system tag; I use CVS and put $Id$ near the top of all my files. Version control is a key differentiator between hacked code and professional systems software product. If your company is using this script to bill people, your company and customers expect the latter. 11. Use h2xs to create a module and move your code into it. (Another key differentiator.) 12. Do you have automated regression tests? (Another key differentiator.) 13. You're using a lot of 'my' variables to fetch fields from data structures. I do this and/or suffer through with the full syntax, but have always wanted a cleaner solution. Perhaps a full set of accessors? AUTOLOAD? Alias? Here's a fairly current example of my coding style which demonstrates all of the above points: http://www.holgerdanske.com/node/460 HTH, David -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
