Re: Help on saving and retrieving data structures
Dear David,
Thanks for throwing light on the topic by citing the security implications of
executing eval and also suggesting the industry standard 'JSON' for
interoperability.
It is greatly appreciated.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift back to God.
---
From: David Precious dav...@preshweb.co.uk
To: Perl Beginners beginners@perl.org
Sent: Friday, 13 September 2013 6:01 PM
Subject: Re: Help on saving and retrieving data structures
On Fri, 13 Sep 2013 19:10:58 +0800 (SGT)
*Shaji Kalidasan* shajiin...@yahoo.com wrote:
I am saving the data structure to a file and retrieving it back
again, but, when I 'use strict' it is giving the following error
message
Global symbol %game requires explicit package name
Others have pointed out that the problem will be solved by adding a my
%game before you eval the contents of the file.
However, I personally would suggest serialising the data to JSON and
storing that in the file, rather than using Data::Dumper - that way
you've got your data in a more standard format in case you want to work
with it with other tools, and also you're not eval'ing code, so if
someone had decided to edit that file and add, say, system('rm -rf /')
in it, you won't suddenly execute things you didn't expect.
It can be as simple as saying use JSON to load JSON.pm, then using
JSON::to_json(\%game) to generate JSON to write to the file, then
saying e.g. my $game = JSON::from_json($json) (where $json is the JSON
you just read in from the file).
Alternatively, you could even look at DBM::Deep, which would abstract
away the saving/loading for you (although you'd lose the bonus of
having stored the data in a standard widely-supported format).
It is working fine without 'strict'. Please help
[code]
#Code for saving the data structure
use strict;
use warnings;
use Data::Dumper;
my %game = (
worldcup = {
series = WC 2011,
play = [monday, wednesday, friday],
players = [
{name = dhoni, role = captain, country =
india}, {name = tendulkar, role = batsman, country =
india}, {name = yuvraj, role = batsman, country = india}
],
},
ipl = {
series = Edition 5,
play = [saturday, sunday],
players = [
{name = sehwag, role = captain, country =
india}, {name = muralidharan, role = batsman, country =
srilanka}, {name = gayle, role = batsman, country =
westindies} ],
},
);
$Data::Dumper::Purity = 1;
open my $fout, '', 'gameinfo.perldata' or die Cannot open file
($!); print $fout Data::Dumper-Dump([\%game], ['*game']);
close $fout or die Cannot open file ($!);
[/code]
[code]
#Code for reading the data structure. Please note that, I have
disabled 'strict' and 'warnings'
#use strict;
#use warnings;
use Data::Dumper;
open my $fin, '', 'gameinfo.perldata' or die Cannot open file ($!);
undef $/; #read in file all at once
eval $fin;
if($@) {
die Can't recreate game data from gameinfo.perldata $@;
}
close $fin or die Cannot open file ($!);
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
I have also tried using 'do' using strict but in vain
[code]
#use strict;
#use warnings;
use Data::Dumper;
do gameinfo.perldata or die Can't recreate gameinfo: $! $@;
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
[output]
Name : muralidharan
Role : batsman
Country : srilanka
[/output]
My question is, how to use the above program with strict enabled?
Thank you.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift
back to God.
---
--
David Precious (bigpresh) dav...@preshweb.co.uk
http://www.preshweb.co.uk/ www.preshweb.co.uk/twitter
www.preshweb.co.uk/linkedin www.preshweb.co.uk/facebook
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Re: Help on saving and retrieving data structures
Hi Shaji, On Sat, 14 Sep 2013 16:19:26 +0800 (SGT) *Shaji Kalidasan* shajiin...@yahoo.com wrote: Dear David, Thanks for throwing light on the topic by citing the security implications of executing eval and also suggesting the industry standard 'JSON' for interoperability. One should note that JSON is not the only sane option for serialisation and deserialisation in Perl. There are also: * https://metacpan.org/release/Storable - a binary format that is specific for Perl, which works very well. Using it avoids some JSON-specific limitations such as no references to scalars. Make sure you use nstore and friends instead of store. * http://blog.booking.com/the-next-sereal-is-coming.html - there's also this, but I have no experience with it. * There are other formats such as YAML, but YAML should be avoided because it's too complex and quirky (at least for serialisation). Regards, Shlomi Fish -- - Shlomi Fish http://www.shlomifish.org/ Optimising Code for Speed - http://shlom.in/optimise Whitespace in Python is not a problem: just lay out all the whitespace first, then add the code around it. — sizz on Freenode’s #perl Please reply to list if it's a mailing list post - http://shlom.in/reply . -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Help on saving and retrieving data structures
++Storable On 14 September 2013 09:39, Shlomi Fish shlo...@shlomifish.org wrote: Hi Shaji, On Sat, 14 Sep 2013 16:19:26 +0800 (SGT) *Shaji Kalidasan* shajiin...@yahoo.com wrote: Dear David, Thanks for throwing light on the topic by citing the security implications of executing eval and also suggesting the industry standard 'JSON' for interoperability. One should note that JSON is not the only sane option for serialisation and deserialisation in Perl. There are also: * https://metacpan.org/release/Storable - a binary format that is specific for Perl, which works very well. Using it avoids some JSON-specific limitations such as no references to scalars. Make sure you use nstore and friends instead of store. * http://blog.booking.com/the-next-sereal-is-coming.html - there's also this, but I have no experience with it. * There are other formats such as YAML, but YAML should be avoided because it's too complex and quirky (at least for serialisation). Regards, Shlomi Fish -- - Shlomi Fish http://www.shlomifish.org/ Optimising Code for Speed - http://shlom.in/optimise Whitespace in Python is not a problem: just lay out all the whitespace first, then add the code around it. — sizz on Freenode’s #perl Please reply to list if it's a mailing list post - http://shlom.in/reply . -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Help on saving and retrieving data structures
Yes, I agree.
Top answer!
Can also consider YAML if you wanted to do a lot of manual editing of data,
but probably JSON is best.
Dr Jimi C Wills
David Precious wrote in message news:20130913133147.0b88fbeb@columbia...
On Fri, 13 Sep 2013 19:10:58 +0800 (SGT)
*Shaji Kalidasan* shajiin...@yahoo.com wrote:
I am saving the data structure to a file and retrieving it back
again, but, when I 'use strict' it is giving the following error
message
Global symbol %game requires explicit package name
Others have pointed out that the problem will be solved by adding a my
%game before you eval the contents of the file.
However, I personally would suggest serialising the data to JSON and
storing that in the file, rather than using Data::Dumper - that way
you've got your data in a more standard format in case you want to work
with it with other tools, and also you're not eval'ing code, so if
someone had decided to edit that file and add, say, system('rm -rf /')
in it, you won't suddenly execute things you didn't expect.
It can be as simple as saying use JSON to load JSON.pm, then using
JSON::to_json(\%game) to generate JSON to write to the file, then
saying e.g. my $game = JSON::from_json($json) (where $json is the JSON
you just read in from the file).
Alternatively, you could even look at DBM::Deep, which would abstract
away the saving/loading for you (although you'd lose the bonus of
having stored the data in a standard widely-supported format).
It is working fine without 'strict'. Please help
[code]
#Code for saving the data structure
use strict;
use warnings;
use Data::Dumper;
my %game = (
worldcup = {
series = WC 2011,
play = [monday, wednesday, friday],
players = [
{name = dhoni, role = captain, country =
india}, {name = tendulkar, role = batsman, country =
india}, {name = yuvraj, role = batsman, country = india}
],
},
ipl = {
series = Edition 5,
play = [saturday, sunday],
players = [
{name = sehwag, role = captain, country =
india}, {name = muralidharan, role = batsman, country =
srilanka}, {name = gayle, role = batsman, country =
westindies} ],
},
);
$Data::Dumper::Purity = 1;
open my $fout, '', 'gameinfo.perldata' or die Cannot open file
($!); print $fout Data::Dumper-Dump([\%game], ['*game']);
close $fout or die Cannot open file ($!);
[/code]
[code]
#Code for reading the data structure. Please note that, I have
disabled 'strict' and 'warnings'
#use strict;
#use warnings;
use Data::Dumper;
open my $fin, '', 'gameinfo.perldata' or die Cannot open file ($!);
undef $/; #read in file all at once
eval $fin;
if($@) {
die Can't recreate game data from gameinfo.perldata $@;
}
close $fin or die Cannot open file ($!);
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
I have also tried using 'do' using strict but in vain
[code]
#use strict;
#use warnings;
use Data::Dumper;
do gameinfo.perldata or die Can't recreate gameinfo: $! $@;
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
[output]
Name : muralidharan
Role : batsman
Country : srilanka
[/output]
My question is, how to use the above program with strict enabled?
Thank you.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift
back to God.
---
--
David Precious (bigpresh) dav...@preshweb.co.uk
http://www.preshweb.co.uk/ www.preshweb.co.uk/twitter
www.preshweb.co.uk/linkedinwww.preshweb.co.uk/facebook
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Help on saving and retrieving data structures
Dear Perlers,
I am saving the data structure to a file and retrieving it back again, but,
when I 'use strict' it is giving the following error message
Global symbol %game requires explicit package name
It is working fine without 'strict'. Please help
[code]
#Code for saving the data structure
use strict;
use warnings;
use Data::Dumper;
my %game = (
worldcup = {
series = WC 2011,
play = [monday, wednesday, friday],
players = [
{name = dhoni, role = captain, country = india},
{name = tendulkar, role = batsman, country =
india},
{name = yuvraj, role = batsman, country = india}
],
},
ipl = {
series = Edition 5,
play = [saturday, sunday],
players = [
{name = sehwag, role = captain, country = india},
{name = muralidharan, role = batsman, country =
srilanka},
{name = gayle, role = batsman, country =
westindies}
],
},
);
$Data::Dumper::Purity = 1;
open my $fout, '', 'gameinfo.perldata' or die Cannot open file ($!);
print $fout Data::Dumper-Dump([\%game], ['*game']);
close $fout or die Cannot open file ($!);
[/code]
[code]
#Code for reading the data structure. Please note that, I have disabled
'strict' and 'warnings'
#use strict;
#use warnings;
use Data::Dumper;
open my $fin, '', 'gameinfo.perldata' or die Cannot open file ($!);
undef $/; #read in file all at once
eval $fin;
if($@) {
die Can't recreate game data from gameinfo.perldata $@;
}
close $fin or die Cannot open file ($!);
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
I have also tried using 'do' using strict but in vain
[code]
#use strict;
#use warnings;
use Data::Dumper;
do gameinfo.perldata or die Can't recreate gameinfo: $! $@;
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
[output]
Name : muralidharan
Role : batsman
Country : srilanka
[/output]
My question is, how to use the above program with strict enabled?
Thank you.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift back to God.
---
Re: Help on saving and retrieving data structures
On Fri, Sep 13, 2013 at 07:10:58PM +0800, *Shaji Kalidasan* wrote:
Dear Perlers,
I am saving the data structure to a file and retrieving it back again, but,
when I 'use strict' it is giving the following error message
Global symbol %game requires explicit package name
This message means you haven't declared the game hash.
In the first section of code you declare the game hash and populate it.
In the second section of code you haven't decared the game hash at all. You
can declare it using my %game;
Then you actually have to populate it with the data you have read from the file
before you can get any useful output.
You might want to read up on autovivication - particularly with reference to
hashes. ( http://en.wikipedia.org/wiki/Autovivification )
regards
L.
It is working fine without 'strict'. Please help
[code]
#Code for saving the data structure
use strict;
use warnings;
use Data::Dumper;
my %game = (
worldcup = {
series = WC 2011,
play = [monday, wednesday, friday],
players = [
{name = dhoni, role = captain, country = india},
{name = tendulkar, role = batsman, country =
india},
{name = yuvraj, role = batsman, country = india}
],
},
ipl = {
series = Edition 5,
play = [saturday, sunday],
players = [
{name = sehwag, role = captain, country = india},
{name = muralidharan, role = batsman, country =
srilanka},
{name = gayle, role = batsman, country =
westindies}
],
},
);
$Data::Dumper::Purity = 1;
open my $fout, '', 'gameinfo.perldata' or die Cannot open file ($!);
print $fout Data::Dumper-Dump([\%game], ['*game']);
close $fout or die Cannot open file ($!);
[/code]
[code]
#Code for reading the data structure. Please note that, I have disabled
'strict' and 'warnings'
#use strict;
#use warnings;
use Data::Dumper;
open my $fin, '', 'gameinfo.perldata' or die Cannot open file ($!);
undef $/; #read in file all at once
eval $fin;
if($@) {
die Can't recreate game data from gameinfo.perldata $@;
}
close $fin or die Cannot open file ($!);
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
I have also tried using 'do' using strict but in vain
[code]
#use strict;
#use warnings;
use Data::Dumper;
do gameinfo.perldata or die Can't recreate gameinfo: $! $@;
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
[output]
Name : muralidharan
Role : batsman
Country : srilanka
[/output]
My question is, how to use the above program with strict enabled?
Thank you.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift back to
God.
---
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Help on saving and retrieving data structures
Hi Lesley,
Thanks for the explanation and pointing me to further resources (Wikipedia).
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift back to God.
---
From: 'lesleyb' lesl...@herlug.org.uk
To: beginners@perl.org
Sent: Friday, 13 September 2013 5:26 PM
Subject: Re: Help on saving and retrieving data structures
On Fri, Sep 13, 2013 at 07:10:58PM +0800, *Shaji Kalidasan* wrote:
Dear Perlers,
I am saving the data structure to a file and retrieving it back again, but,
when I 'use strict' it is giving the following error message
Global symbol %game requires explicit package name
This message means you haven't declared the game hash.
In the first section of code you declare the game hash and populate it.
In the second section of code you haven't decared the game hash at all. You
can declare it using my %game;
Then you actually have to populate it with the data you have read from the file
before you can get any useful output.
You might want to read up on autovivication - particularly with reference to
hashes. ( http://en.wikipedia.org/wiki/Autovivification )
regards
L.
It is working fine without 'strict'. Please help
[code]
#Code for saving the data structure
use strict;
use warnings;
use Data::Dumper;
my %game = (
worldcup = {
series = WC 2011,
play = [monday, wednesday, friday],
players = [
{name = dhoni, role = captain, country = india},
{name = tendulkar, role = batsman, country =
india},
{name = yuvraj, role = batsman, country = india}
],
},
ipl = {
series = Edition 5,
play = [saturday, sunday],
players = [
{name = sehwag, role = captain, country = india},
{name = muralidharan, role = batsman, country =
srilanka},
{name = gayle, role = batsman, country =
westindies}
],
},
);
$Data::Dumper::Purity = 1;
open my $fout, '', 'gameinfo.perldata' or die Cannot open file ($!);
print $fout Data::Dumper-Dump([\%game], ['*game']);
close $fout or die Cannot open file ($!);
[/code]
[code]
#Code for reading the data structure. Please note that, I have disabled
'strict' and 'warnings'
#use strict;
#use warnings;
use Data::Dumper;
open my $fin, '', 'gameinfo.perldata' or die Cannot open file ($!);
undef $/; #read in file all at once
eval $fin;
if($@) {
die Can't recreate game data from gameinfo.perldata $@;
}
close $fin or die Cannot open file ($!);
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
I have also tried using 'do' using strict but in vain
[code]
#use strict;
#use warnings;
use Data::Dumper;
do gameinfo.perldata or die Can't recreate gameinfo: $! $@;
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
[output]
Name : muralidharan
Role : batsman
Country : srilanka
[/output]
My question is, how to use the above program with strict enabled?
Thank you.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift back to
God.
---
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Help on saving and retrieving data structures
Hi Jimi, Thanks for your explanation and pointing me exactly where I am going wrong. best, Shaji --- Your talent is God's gift to you. What you do with it is your gift back to God. --- From: Dr Jimi-Carlo Bukowski-Wills jbwi...@staffmail.ed.ac.uk To: *Shaji Kalidasan* shajiin...@yahoo.com Sent: Friday, 13 September 2013 5:12 PM Subject: Re: Help on saving and retrieving data structures Hi It’s because the output file has no (my) in it and you haven’t declared the variable scope in the code that reads the data. Try adding my %game; before the line eval $fin; The University of Edinburgh is a charitable body, registered in Scotland, with registration number SC005336.
Re: Help on saving and retrieving data structures
On Fri, 13 Sep 2013 19:10:58 +0800 (SGT)
*Shaji Kalidasan* shajiin...@yahoo.com wrote:
I am saving the data structure to a file and retrieving it back
again, but, when I 'use strict' it is giving the following error
message
Global symbol %game requires explicit package name
Others have pointed out that the problem will be solved by adding a my
%game before you eval the contents of the file.
However, I personally would suggest serialising the data to JSON and
storing that in the file, rather than using Data::Dumper - that way
you've got your data in a more standard format in case you want to work
with it with other tools, and also you're not eval'ing code, so if
someone had decided to edit that file and add, say, system('rm -rf /')
in it, you won't suddenly execute things you didn't expect.
It can be as simple as saying use JSON to load JSON.pm, then using
JSON::to_json(\%game) to generate JSON to write to the file, then
saying e.g. my $game = JSON::from_json($json) (where $json is the JSON
you just read in from the file).
Alternatively, you could even look at DBM::Deep, which would abstract
away the saving/loading for you (although you'd lose the bonus of
having stored the data in a standard widely-supported format).
It is working fine without 'strict'. Please help
[code]
#Code for saving the data structure
use strict;
use warnings;
use Data::Dumper;
my %game = (
worldcup = {
series = WC 2011,
play = [monday, wednesday, friday],
players = [
{name = dhoni, role = captain, country =
india}, {name = tendulkar, role = batsman, country =
india}, {name = yuvraj, role = batsman, country = india}
],
},
ipl = {
series = Edition 5,
play = [saturday, sunday],
players = [
{name = sehwag, role = captain, country =
india}, {name = muralidharan, role = batsman, country =
srilanka}, {name = gayle, role = batsman, country =
westindies} ],
},
);
$Data::Dumper::Purity = 1;
open my $fout, '', 'gameinfo.perldata' or die Cannot open file
($!); print $fout Data::Dumper-Dump([\%game], ['*game']);
close $fout or die Cannot open file ($!);
[/code]
[code]
#Code for reading the data structure. Please note that, I have
disabled 'strict' and 'warnings'
#use strict;
#use warnings;
use Data::Dumper;
open my $fin, '', 'gameinfo.perldata' or die Cannot open file ($!);
undef $/; #read in file all at once
eval $fin;
if($@) {
die Can't recreate game data from gameinfo.perldata $@;
}
close $fin or die Cannot open file ($!);
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
I have also tried using 'do' using strict but in vain
[code]
#use strict;
#use warnings;
use Data::Dumper;
do gameinfo.perldata or die Can't recreate gameinfo: $! $@;
print Name : , $game{ipl}-{players}-[1]-{name}, \n;
print Role : , $game{ipl}-{players}-[1]-{role}, \n;
print Country : , $game{ipl}-{players}-[1]-{country}, \n;
[/code]
[output]
Name : muralidharan
Role : batsman
Country : srilanka
[/output]
My question is, how to use the above program with strict enabled?
Thank you.
best,
Shaji
---
Your talent is God's gift to you. What you do with it is your gift
back to God.
---
--
David Precious (bigpresh) dav...@preshweb.co.uk
http://www.preshweb.co.uk/ www.preshweb.co.uk/twitter
www.preshweb.co.uk/linkedinwww.preshweb.co.uk/facebook
www.preshweb.co.uk/cpanwww.preshweb.co.uk/github
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
Re: Help on saving and retrieving data structures
On Fri, Sep 13, 2013 at 01:31:47PM +0100, David Precious wrote:
On Fri, 13 Sep 2013 19:10:58 +0800 (SGT)
*Shaji Kalidasan* shajiin...@yahoo.com wrote:
I am saving the data structure to a file and retrieving it back
again, but, when I 'use strict' it is giving the following error
message
Global symbol %game requires explicit package name
Others have pointed out that the problem will be solved by adding a my
%game before you eval the contents of the file.
However, I personally would suggest serialising the data to JSON and
storing that in the file, rather than using Data::Dumper - that way
you've got your data in a more standard format in case you want to work
with it with other tools, and also you're not eval'ing code, so if
someone had decided to edit that file and add, say, system('rm -rf /')
in it, you won't suddenly execute things you didn't expect.
It can be as simple as saying use JSON to load JSON.pm, then using
JSON::to_json(\%game) to generate JSON to write to the file, then
saying e.g. my $game = JSON::from_json($json) (where $json is the JSON
you just read in from the file).
Alternatively, you could even look at DBM::Deep, which would abstract
away the saving/loading for you (although you'd lose the bonus of
having stored the data in a standard widely-supported format).
A shame we can't rate answers on beginners but that is an excellent answer and
really informative.
Thanks David.
snip
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Re: Perl Module to parse any other Perl script/module to fetch stats about data-structures
Parag == Parag Kalra paragka...@gmail.com writes: Parag Do we have any Perl module which can parse any other perl script Parag (or module) and fetch information like total number of arrays Parag being used, total number of hashes, total number of scalar Parag variables etc and size information (like total elements, total Parag keys etc) for each data structure in that perl script or may be Parag another perl module It's not possible to completely parse Perl statically [1], although PPI [2] is pretty close and usable for most programs. [1] http://www.perlmonks.org/index.pl?node_id=44722 [2] http://search.cpan.org/~adamk/PPI-1.215/lib/PPI.pm -- Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095 mer...@stonehenge.com URL:http://www.stonehenge.com/merlyn/ Smalltalk/Perl/Unix consulting, Technical writing, Comedy, etc. etc. See http://methodsandmessages.posterous.com/ for Smalltalk discussion -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Perl Module to parse any other Perl script/module to fetch stats about data-structures
On 12-02-08 05:20 PM, Parag Kalra wrote: Do we have any Perl module which can parse any other perl script (or module) and fetch information like total number of arrays being used, total number of hashes, total number of scalar variables etc and size information (like total elements, total keys etc) for each data structure in that perl script or may be another perl module Thanks, Parag I haven't found a module to do exactly what you want, but B::Xref may do for a start: perl -MO=Xref myscript See `perldoc B::Xref` for details. -- Just my 0.0002 million dollars worth, Shawn Programming is as much about organization and communication as it is about coding. -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Perl Module to parse any other Perl script/module to fetch stats about data-structures
Do we have any Perl module which can parse any other perl script (or module) and fetch information like total number of arrays being used, total number of hashes, total number of scalar variables etc and size information (like total elements, total keys etc) for each data structure in that perl script or may be another perl module Thanks, Parag
Re: Perl Module to parse any other Perl script/module to fetch stats about data-structures
On 2012.02.08 17:20, Parag Kalra wrote: Do we have any Perl module which can parse any other perl script (or module) and fetch information like total number of arrays being used, total number of hashes, total number of scalar variables etc and size information (like total elements, total keys etc) for each data structure in that perl script or may be another perl module I've written such to identify subs within my own apps for which I've written numerous interconnected modules, but never had the need to see individual elements. Even my own internal traces didn't follow single elements. I would suspect that this would be something that would have to run against the file itself, even prior to compile. Curious task. Might I ask what the purpose of your desire is? Steve -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Perl Module to parse any other Perl script/module to fetch stats about data-structures
于 2012-2-9 10:15, Steve Bertrand 写道: I would suspect that this would be something that would have to run against the file itself, even prior to compile. Curious task. Might I ask what the purpose of your desire is? I am also not sure what's the special purpuse of the OP. Some modules on CPAN under the namespace of Devel::* may help him. Jeff. -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Perl Module to parse any other Perl script/module to fetch stats about data-structures
By data-structures being used, I mean the data structures that are actually *declared* in the script. And is it possible to find at least the data-structures stats of the current script that is getting executed if no parser is available. For example if I have a big script or module and if I want to find total arrays, hashes and variables declared in that script. Is there any special variable where this info is stored. Thanks, Parag On Wed, Feb 8, 2012 at 6:31 PM, Jeff Peng p...@staff.dnsbed.com wrote: 于 2012-2-9 10:15, Steve Bertrand 写道: I would suspect that this would be something that would have to run against the file itself, even prior to compile. Curious task. Might I ask what the purpose of your desire is? I am also not sure what's the special purpuse of the OP. Some modules on CPAN under the namespace of Devel::* may help him. Jeff. -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Perl Module to parse any other Perl script/module to fetch stats about data-structures
于 2012-2-9 15:21, Parag Kalra 写道: By data-structures being used, I mean the data structures that are actually *declared* in the script. And is it possible to find at least the data-structures stats of the current script that is getting executed if no parser is available. For example if I have a big script or module and if I want to find total arrays, hashes and variables declared in that script. Is there any special variable where this info is stored. I'm not sure, but you may take a look at this module: http://search.cpan.org/~flora/perl-5.14.2/ext/Devel-Peek/Peek.pm http://search.cpan.org/%7Eflora/perl-5.14.2/ext/Devel-Peek/Peek.pm HTH.
Efficient way to compare 2 data structures particularly hash
Hi, I am evaluating different approaches to compare data structures in Perl - i.e whether they are same or not. I am planning to start wit: 1. Data::Compare 2. And then found this - http://stackoverflow.com/questions/1273616/how-do-i-compare-two-hashes-in-perl-without-using-datacompare Any other options or suggestions? I would like to use the most efficient. ~Parag
Re: Efficient way to compare 2 data structures particularly hash
On 30/04/2011 19:22, Parag Kalra wrote: Hi, I am evaluating different approaches to compare data structures in Perl - i.e whether they are same or not. I am planning to start wit: 1. Data::Compare 2. And then found this - http://stackoverflow.com/questions/1273616/how-do-i-compare-two-hashes-in-perl-without-using-datacompare Any other options or suggestions? I would like to use the most efficient. I suggest you take a look at perldoc -q How do I test whether two arrays or hashes are equal? But have you established that Data::Compare is too inefficient? I imagine a lot has gone into making it work as well as possible, and if it is not causing a bottleneck problem then you should go ahead and just use it. Rob -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Efficient way to compare 2 data structures particularly hash
On Sat, Apr 30, 2011 at 11:22:57AM -0700, Parag Kalra wrote: Hi, I am evaluating different approaches to compare data structures in Perl - i.e whether they are same or not. I am planning to start wit: 1. Data::Compare 2. And then found this - http://stackoverflow.com/questions/1273616/how-do-i-compare-two-hashes-in-perl-without-using-datacompare Any other options or suggestions? I would like to use the most efficient. Most efficient in terms of what? Data::Compare seems to do what you want. It is established, tested, maintained, and has no outstanding reported bugs. Since you know about it, is there any reason to look any further? Why evaluate different approaches? I suggest that the most efficient use of your time would be to use Data::Compare, until you have a reason not to. Then you can wonder what to use instead. -- Paul Johnson - p...@pjcj.net http://www.pjcj.net -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Rendering data structures using CGI::Application
I've been stuck for the last three hours trying to render the following
data structure into my browser. I'm using CGI::Application, and
CGI::Application::Plugin::PageBuilder.
No matter what I do or try, I can not loop the structure into a template
variable. I'm literally at wits end, and am considering just figuring
out a way to 'print' it out.
Any strong kick to the teeth as a boost would be most appreciated. This
is my data structure, and below shows that the particular module that
produces this data can be queried to produce more human readable output:
$error-dump_all();
$VAR1 = \[
'quantity is undefined, zero or illegal',
'amount is undefined or illegal',
'payment is undefined or illegal'
];
$VAR2 = \[
{
'sub' = undef,
'filename' = 'tests/purchase.pl',
'line' = 43,
'package' = 'main'
},
{
'sub' = 'ISP::Transac::create_transaction',
'filename' = '../ISP/Transac.pm',
'line' = 32,
'package' = 'ISP::Transac'
},
{
'sub' = 'ISP::Sanity::transaction_data',
'filename' = '../ISP/Sanity.pm',
'line' = 55,
'package' = 'ISP::Sanity'
}
];
# I can print it out nicely on the command line, but not in the browser:
my @messages= $error-get_messages();
my @stack = $error-get_stack();
print join (\n, @messages);
for (@stack) {
while ( my ($key, $value) = each %{$_}) {
print $key = $value\n
if defined $key and
defined $value;
}
}
}
Is there an easy way to render this to the browser, while keeping HTML
out of my code?
Steve
smime.p7s
Description: S/MIME Cryptographic Signature
Re: Rendering data structures using CGI::Application
How do you want the output to look? If you write in a sample output, I
could help with the template to generate that output
Regards
On Mon, 2009-06-29 at 22:56 -0400, Steve Bertrand wrote:
I've been stuck for the last three hours trying to render the following
data structure into my browser. I'm using CGI::Application, and
CGI::Application::Plugin::PageBuilder.
No matter what I do or try, I can not loop the structure into a template
variable. I'm literally at wits end, and am considering just figuring
out a way to 'print' it out.
Any strong kick to the teeth as a boost would be most appreciated. This
is my data structure, and below shows that the particular module that
produces this data can be queried to produce more human readable output:
$error-dump_all();
$VAR1 = \[
'quantity is undefined, zero or illegal',
'amount is undefined or illegal',
'payment is undefined or illegal'
];
$VAR2 = \[
{
'sub' = undef,
'filename' = 'tests/purchase.pl',
'line' = 43,
'package' = 'main'
},
{
'sub' = 'ISP::Transac::create_transaction',
'filename' = '../ISP/Transac.pm',
'line' = 32,
'package' = 'ISP::Transac'
},
{
'sub' = 'ISP::Sanity::transaction_data',
'filename' = '../ISP/Sanity.pm',
'line' = 55,
'package' = 'ISP::Sanity'
}
];
# I can print it out nicely on the command line, but not in the browser:
my @messages= $error-get_messages();
my @stack = $error-get_stack();
print join (\n, @messages);
for (@stack) {
while ( my ($key, $value) = each %{$_}) {
print $key = $value\n
if defined $key and
defined $value;
}
}
}
Is there an easy way to render this to the browser, while keeping HTML
out of my code?
Steve
Re: Rendering data structures using CGI::Application
Gurunandan R. Bhat wrote:
How do you want the output to look? If you write in a sample output, I
could help with the template to generate that output
I would be extremely delighted to even get the following rendered for
now, given the Data::Dumper output below. If I had a decent example,
then I'd be able to learn from it, and go from there:
--- output displayed as I'd see it in the browser---
Error messages:
quantity is undefined, zero or illegal
amount is undefined or illegal
payment is undefined or illegal
Stack trace:
sub = undef;
filename = tests/purchase.pl
line = 43
package = main
sub = ISP::Transac::create_transaction
filename = /usr/local/lib/perl5/site_perl/5.8.9/ISP/Transac.pm
line = 32
package = ISP::Transac
sub = ISP::Sanity::transaction_data
filename = /usr/local/lib/perl5/site_perl/5.8.9/ISP/Sanity.pm
line = 55
package = ISP::Sanity
--- end browser output ---
Here again is the actual data. $VAR1 is an array of the error messages,
and $VAR2 is an array, where each element is a hash which represents a
level in a stack trace.
$VAR1 = \[
'quantity is undefined, zero or illegal',
'amount is undefined or illegal',
'payment is undefined or illegal'
];
$VAR2 = \[
{
'sub' = undef,
'filename' = 'tests/purchase.pl',
'line' = 43,
'package' = 'main'
},
{
'sub' = 'ISP::Transac::create_transaction',
'filename' =
'/usr/local/lib/perl5/site_perl/5.8.9/ISP/Transac.pm',
'line' = 32,
'package' = 'ISP::Transac'
},
{
'sub' = 'ISP::Sanity::transaction_data',
'filename' =
'/usr/local/lib/perl5/site_perl/5.8.9/ISP/Sanity.pm',
'line' = 55,
'package' = 'ISP::Sanity'
}
];
Thank you!
Steve
smime.p7s
Description: S/MIME Cryptographic Signature
Re: Rendering data structures using CGI::Application
Sure. I think you would like to have the error messages next to the sub
that threw them, but here is what you want: (NOT TESTED!!)
In your module:
my $messages = [
{text = 'quantity is undefined, zero or illegal'},
{text = 'amount is undefined or illegal'},
{text = 'payment is undefined or illegal'},
];
my $stack = [
{
sub = undef,
filename = 'tests/purchase.pl',
line = 43,
package = 'main',
},
{
sub = 'ISP::Transac::create_transaction',
filename =
'/usr/local/lib/perl5/site_perl/5.8.9/ISP/Transac.pm',
line = 32,
package = 'ISP::Transac',
},
{
sub = 'ISP::Sanity::transaction_data',
filename =
'/usr/local/lib/perl5/site_perl/5.8.9/ISP/Sanity.pm',
line = 55,
package = 'ISP::Sanity',
},
];
my $tpl = $app-load_tmpl('templatefile.tpl', die_on_bad_params = 0);
$tpl-param(
MESSAGES = $messages,
STACK = $stack,
);
return $tpl-output;
In your template file
ul
!-- TMPL_LOOP NAME=MESSAGES --
li!-- TMPL_VAR NAME=TEXT --/li
!-- /TMPL_LOOP --
/ul
ul
!-- TMPL_LOOP NAME=STACK --
li
ul
!-- TMPL_VAR NAME=sub --br /
!-- TMPL_VAR NAME=filename --br /
!-- TMPL_VAR NAME=line --br /
!-- TMPL_VAR NAME=package --
/ul
/li
!-- /TMPL_LOOP --
HTH
On Mon, 2009-06-29 at 23:51 -0400, Steve Bertrand wrote:
Gurunandan R. Bhat wrote:
How do you want the output to look? If you write in a sample output, I
could help with the template to generate that output
I would be extremely delighted to even get the following rendered for
now, given the Data::Dumper output below. If I had a decent example,
then I'd be able to learn from it, and go from there:
--- output displayed as I'd see it in the browser---
Error messages:
quantity is undefined, zero or illegal
amount is undefined or illegal
payment is undefined or illegal
Stack trace:
sub = undef;
filename = tests/purchase.pl
line = 43
package = main
sub = ISP::Transac::create_transaction
filename = /usr/local/lib/perl5/site_perl/5.8.9/ISP/Transac.pm
line = 32
package = ISP::Transac
sub = ISP::Sanity::transaction_data
filename = /usr/local/lib/perl5/site_perl/5.8.9/ISP/Sanity.pm
line = 55
package = ISP::Sanity
--- end browser output ---
Here again is the actual data. $VAR1 is an array of the error messages,
and $VAR2 is an array, where each element is a hash which represents a
level in a stack trace.
$VAR1 = \[
'quantity is undefined, zero or illegal',
'amount is undefined or illegal',
'payment is undefined or illegal'
];
$VAR2 = \[
{
'sub' = undef,
'filename' = 'tests/purchase.pl',
'line' = 43,
'package' = 'main'
},
{
'sub' = 'ISP::Transac::create_transaction',
'filename' =
'/usr/local/lib/perl5/site_perl/5.8.9/ISP/Transac.pm',
'line' = 32,
'package' = 'ISP::Transac'
},
{
'sub' = 'ISP::Sanity::transaction_data',
'filename' =
'/usr/local/lib/perl5/site_perl/5.8.9/ISP/Sanity.pm',
'line' = 55,
'package' = 'ISP::Sanity'
}
];
Thank you!
Steve
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Re: Rendering data structures using CGI::Application
Gurunandan R. Bhat wrote: Sure. I think you would like to have the error messages next to the sub that threw them, but here is what you want: (NOT TESTED!!) ..woot!!! Thank you ever so much. Although I inserted the data statically into my _render_error() method, the result is positive! Other than site-specific changes, your code was completely copy and paste. Kudos. Now that I have a baseline to work with, it will be trivial for me to follow this example to insert my data dynamically, and format it as I please. Cheers, Steve ps. I've stuck with my 'passing the $error around' for now. I've been finding that going over older code (a couple of years old) and being able to rewrite it at 20% its original size is a good thing. Even if my error checking is the hard way, it's still 'a' way, and one I'll eventually learn a lesson from ;) smime.p7s Description: S/MIME Cryptographic Signature
RE: references to complex data structures
-Original Message-
From: Rob Dixon [mailto:[EMAIL PROTECTED]
Sent: Monday, January 14, 2008 8:59 PM
To: beginners@perl.org
Cc: Kevin Viel
Subject: Re: references to complex data structures
Kevin Viel wrote:
Consider the following anonymous array of anonymous arrays:
my $a = [ [ 00 , 01 ]
, [ 10 , 11 ]
] ;
I can print the first element of the first anonymous array:
print $$a[ 0 ][ 0 ]\n ;
or, equivalently, I can explicit use bracers to dereference it:
print ${$a}[ 0 ][ 0 ]\n ;
OK
But they're 'braces' :)
Should I not need two pairs of bracers?
The 'missing' pair of braces is because you're using both of
the two different syntaxes for indexing a referenced array.
The first element of the outer array is either
${$a}[0] (which can be written $$a[0] without ambiguity)
or
$a-[0]
These are references to the first inner array, which can also
be indexed in either way. So we have four ways of reaching
the first element of the first inner array:
${${$a}[0]}[0]
${$a}[0]-[0]
${$a-[0]}[0]
$a-[0]-[0]
In addition, Perl allows us to remove the arrow operator
between pairs of closing and opening brackets or braces - ][
or }{, so the second and last options can be written
${$a}[0][0]
$a-[0][0]
and so your code turns out to be the same as the first of
these two. If you use the same syntax for indexing in both
cases then the second pair of braces reappears. It is also
the same as your final example below.
$a is a reference to the anonymous array. The elements of the
anonymous arrays are references to anonymous arrays, correct?
They are references to arrays, yes. They may be named arrays
or anonymous ones.
The following seems to achieve this result:
print ${${$a}[ 0 ]}[ 0 ]\n ;
Is the outmost pair of bracers with the appropriate symbol
($, @, %)
the default? If so, how does perl select the correct symbol?
I'm not sure what you mean here: you have explicit dollar
signs in this code for both dereferences. Perl has no default
way of handling references, but it will complain if you try
to use a reference to one type of data as something different.
I realize that it is seemingly moot, but it may help my
understanding
of more complex structures, like hash of arrays or hash of hases.
Don't get to like them to the extent that you use them when
your data isn't shaped that way. They are a way of expressing
hierarchical data only.
Thanks for another informative post.
My data are hierarchical. I have 22 files, one for each autosome (non-sex
chromosome, sex chromosomes being the X and Y-apologies is this is
unnecessary to state). In each file I have markers and their locations.
The first thing I want to do is to be sure that that a marker is unique to a
chromosome:
if ( exists $marker_hash{ $marker } ) {
print Collision: Chromosome: $Chr Marker: $marker\n ;
}
else{
$marker_hash{ $marker } = $chr ;
}
However, I would also like to do two things: collect the chromosomes on
which a markers exists and create a ordered database table that reports the
chromosome , marker , and location.
The outer most object would be a hash, the keys of which are the markers.
The values of this hash could be a hash with keys being chromosome and the
values being an array of locations.
Coding aside, through which I still must suffer, does a complex data
structure seem appropriate to this problem or should I be considerng another
approach?
Kind regards,
Kevin
Kevin Viel, PhD
Post-doctoral fellow
Department of Genetics
Southwest Foundation for Biomedical Research
San Antonio, TX 78227
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references to complex data structures
Consider the following anonymous array of anonymous arrays:
my $a = [ [ 00 , 01 ]
, [ 10 , 11 ]
] ;
I can print the first element of the first anonymous array:
print $$a[ 0 ][ 0 ]\n ;
or, equivalently, I can explicit use bracers to dereference it:
print ${$a}[ 0 ][ 0 ]\n ;
Should I not need two pairs of bracers? $a is a reference to the anonymous
array. The elements of the anonymous arrays are references to anonymous
arrays, correct?
The following seems to achieve this result:
print ${${$a}[ 0 ]}[ 0 ]\n ;
Is the outmost pair of bracers with the appropriate symbol ($, @, %) the
default? If so, how does perl select the correct symbol?
I realize that it is seemingly moot, but it may help my understanding of
more complex structures, like hash of arrays or hash of hases.
Thanks,
Kevin
Kevin Viel, PhD
Post-doctoral fellow
Department of Genetics
Southwest Foundation for Biomedical Research
San Antonio, TX 78227
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Re: references to complex data structures
Kevin Viel wrote:
Consider the following anonymous array of anonymous arrays:
my $a = [ [ 00 , 01 ]
, [ 10 , 11 ]
] ;
I can print the first element of the first anonymous array:
print $$a[ 0 ][ 0 ]\n ;
or, equivalently, I can explicit use bracers to dereference it:
print ${$a}[ 0 ][ 0 ]\n ;
Should I not need two pairs of bracers? $a is a reference to the anonymous
array. The elements of the anonymous arrays are references to anonymous
arrays, correct?
The following seems to achieve this result:
print ${${$a}[ 0 ]}[ 0 ]\n ;
Well, TIMTOWDI. :) I would have said:
print $a-[0][0]\n;
Have you studied the applicable Perl docs?
perldoc perllol
perldoc perldsc
perldoc perlref
perldoc perlreftut
They explain it better than I ever would be able to...
If you seek help here to better understand references, you'd better do
so via specific questions on one or more of those documents.
--
Gunnar Hjalmarsson
Email: http://www.gunnar.cc/cgi-bin/contact.pl
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Re: references to complex data structures
Kevin Viel wrote:
Consider the following anonymous array of anonymous arrays:
my $a = [ [ 00 , 01 ]
, [ 10 , 11 ]
] ;
I can print the first element of the first anonymous array:
print $$a[ 0 ][ 0 ]\n ;
or, equivalently, I can explicit use bracers to dereference it:
print ${$a}[ 0 ][ 0 ]\n ;
OK
But they're 'braces' :)
Should I not need two pairs of bracers?
The 'missing' pair of braces is because you're using both of the two
different syntaxes for indexing a referenced array. The first element of
the outer array is either
${$a}[0] (which can be written $$a[0] without ambiguity)
or
$a-[0]
These are references to the first inner array, which can also be indexed
in either way. So we have four ways of reaching the first element of the
first inner array:
${${$a}[0]}[0]
${$a}[0]-[0]
${$a-[0]}[0]
$a-[0]-[0]
In addition, Perl allows us to remove the arrow operator between pairs
of closing and opening brackets or braces - ][ or }{, so the second and
last options can be written
${$a}[0][0]
$a-[0][0]
and so your code turns out to be the same as the first of these two. If
you use the same syntax for indexing in both cases then the second pair
of braces reappears. It is also the same as your final example below.
$a is a reference to the anonymous array. The elements of the
anonymous arrays are references to anonymous arrays, correct?
They are references to arrays, yes. They may be named arrays or
anonymous ones.
The following seems to achieve this result:
print ${${$a}[ 0 ]}[ 0 ]\n ;
Is the outmost pair of bracers with the appropriate symbol ($, @, %) the
default? If so, how does perl select the correct symbol?
I'm not sure what you mean here: you have explicit dollar signs in this
code for both dereferences. Perl has no default way of handling
references, but it will complain if you try to use a reference to one
type of data as something different.
I realize that it is seemingly moot, but it may help my understanding of
more complex structures, like hash of arrays or hash of hases.
Don't get to like them to the extent that you use them when your data
isn't shaped that way. They are a way of expressing hierarchical data
only.
HTH,
Rob
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Re: Accessing packed data structures
From: Dharshana Eswaran [EMAIL PROTECTED]
I was going thro the topic Accessing packed data structures in the Perl
Complete Reference Book. I came across this example:
struct utmp {
char ut_user[8]; /* User login name */
char ut_id[4]; /* /etc/inittab id */
char ut_line[12]; /* device name */
short ut_pid; /* process ID */
short ut_type; /* type of entry */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS. */
time_t ut_time; /* time entry was made */
};
For the above structure:
The pack template given was a8a4a12l.
...
You might also want to have a look at Inline::Struct
http://search.cpan.org/~neilw/Inline-Struct-0.06/Struct.pod
Jenda
= [EMAIL PROTECTED] === http://Jenda.Krynicky.cz =
When it comes to wine, women and song, wizards are allowed
to get drunk and croon as much as they like.
-- Terry Pratchett in Sourcery
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Re: Accessing packed data structures
On 3/14/07, Dharshana Eswaran [EMAIL PROTECTED] wrote:
snip
The data which i need to pack and unpack to these elements are in hex
format(0x0B 0x1C 0x34 etc). It is a string of hex bytes.
Can i know about the format in which i need to supply the input? Coz i am
unable to accept the hex string.
Thanks and Regards,
Dharshana
Is 0x0B 0x1C 0x34 the actual form of your data? If so, then you do
not probably want to use pack, in that case split, map, and hex are
your friends:
$input = however_you_get_your_input();
my @bytes = map { hex } split ' ', $input;
die $_ is not a byte unless $_ = 0 and $_ = 255 for @bytes;
If you have a total of six bytes then they are outputing the enum with
two bytes, so you need to determine which order it is in (big endian
or little endian).
my $callId = $bytes[0];
my $type = $bytes[1] 8 | $bytes[2]; #or $bytes[2] 8 | $bytes[1];
my $phonenumber = $bytes[3];
my $lineno = $bytes[4] = 127 ? $bytes[4] : -256 + $bytes[4]; #handle sign
my $alpha = $bytes[5]
If you only have five bytes then they are treating the enum as a one
byte field due to the fact that they know (or hope) it will never be
larger than 255:
my $callId = $bytes[0];
my $type = $bytes[1];
my $phonenumber = $bytes[2];
my $lineno = $bytes[3] = 127 ? $bytes[3] : -256 + $bytes[3]; #handle sign
my $alpha = $bytes[4]
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Re: [SPAM] Re: Accessing packed data structures
On Wed, 14 Mar 2007, Dharshana Eswaran wrote:
On 3/13/07, Tom Phoenix [EMAIL PROTECTED] wrote:
On 3/13/07, Dharshana Eswaran [EMAIL PROTECTED] wrote:
I was going thro the topic Accessing packed data structures in the
Perl
Complete Reference Book. I came across this example:
struct utmp {
char ut_user[8]; /* User login name */
char ut_id[4]; /* /etc/inittab id */
char ut_line[12]; /* device name */
short ut_pid; /* process ID */
short ut_type; /* type of entry */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS. */
time_t ut_time; /* time entry was made */
};
For the above structure:
The pack template given was a8a4a12l.
I am, somehow, not able to understand how to generate the pack template
from
the structure's data types.
The pieces match up this way:
char ut_user[8]; /* User login name: a8 */
char ut_id[4]; /* /etc/inittab id: a4 */
char ut_line[12]; /* device name: a12 */
short ut_pid; /* process ID: s */
short ut_type; /* type of entry: s */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS: s s */
time_t ut_time; /* time entry was made: l */
A char array becomes an a42, with the number being the length of the
array. A short becomes s, and a long becomes l. (You do need to know
something about how C stores data in memory. Note that exit_status and
ut_exit are two variables, even though they are declared on the same
line; that's why there are two s's in the comment.)
Here, how does the pack and unpack play its role? What format should the
input be in? What are the possible formats it can accept here?
Have you seen the documentation for pack and unpack? There is a large
table of format letters. Are you asking for something else?
Do you have a C struct that you can't translate to a pack/unpack
template? If so, feel free to post it here. Someone will know how to
deal with it.
Yes, you are right...
I have a structure and it is somethiung like this
typedef struct _TAPI_VOICE_NOTIFY_INCOMING_CALL_MSG_S
TAPI_CALL_ID_T callId;
TAPI_VOICE_INCOMING_CALL_TYPE_E type;
TAPI_PHONE_NUMBER_A phoneNumber;
TAPI_CALL_LINE_ElineNo;
TAPI_PHONEBOOK_NAME_A alpha;
} TAPI_VOICE_NOTIFY_INCOMING_CALL_MSG_S;
Here the typedefs are:
TAPI_CALL_ID_T, TAPI_PHONE_NUMBER_A, TAPI_PHONEBOOK_NAME_A = Unsigned int
8
TAPI_VOICE_INCOMING_CALL_TYPE_E = enum type
TAPI_CALL_LINE_E = signed int 8
Now how do i come up with the pack template? I dont know how a enum should
be represented in the pack template. :-(
/I8(enum)I8i8I8/ = pack template
The above mentioned enum just contains two elements.
The data which i need to pack and unpack to these elements are in hex
format(0x0B 0x1C 0x34 etc). It is a string of hex bytes.
I kindly request anyone to guide me in this.
Thanks and Regards,
Dharshana
What about this one:
http://search.cpan.org/~mhx/Convert-Binary-C-0.67/lib/Convert/Binary/C.pm
I once used it to solve the complex pack/unpack temlate and
machine endianess problem
Vincent Li
http://bl0g.blogdns.com
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Accessing packed data structures
Hi all,
I was going thro the topic Accessing packed data structures in the Perl
Complete Reference Book. I came across this example:
struct utmp {
char ut_user[8]; /* User login name */
char ut_id[4]; /* /etc/inittab id */
char ut_line[12]; /* device name */
short ut_pid; /* process ID */
short ut_type; /* type of entry */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS. */
time_t ut_time; /* time entry was made */
};
For the above structure:
The pack template given was a8a4a12l.
my $packstring = a8a4a12l;
my $reclength = length(pack($packstring));
my @ut_types = qw(EMPTY RUN_LVL BOOT_TIME OLD_TIME
NEW_TIME INIT_PROCESS LOGIN_PROCESS
USER_PROCESS DEAD_PROCESS ACCOUNTING);
open(D,/var/adm/wtmp) or die Couldn't open wtmp, $!;
while(sysread(D,my $rec,$reclength))
{
my ($user,$userid,$line,$pid,$type,$eterm,$eexit,$time)
= unpack($packstring,$rec);
print($user, $userid, $line, $pid, $ut_types[$type], ,
$eterm, $eexit, , scalar localtime($time),\n);
}
close(D) or die Couldn't close wtmp, $!;
I am, somehow, not able to understand how to generate the pack template from
the structure's data types. I understand that we need to refer to the table
in which each character in described (for eg: A - An ASCII string, will be
space padded)
Here, how does the pack and unpack play its role? What format should the
input be in? What are the possible formats it can accept here?
I kindly request anyone to explain me this concept.
Thanks and Regards,
Dharshana
Re: Accessing packed data structures
On 3/13/07, Dharshana Eswaran [EMAIL PROTECTED] wrote:
I was going thro the topic Accessing packed data structures in the Perl
Complete Reference Book. I came across this example:
struct utmp {
char ut_user[8]; /* User login name */
char ut_id[4]; /* /etc/inittab id */
char ut_line[12]; /* device name */
short ut_pid; /* process ID */
short ut_type; /* type of entry */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS. */
time_t ut_time; /* time entry was made */
};
For the above structure:
The pack template given was a8a4a12l.
I am, somehow, not able to understand how to generate the pack template from
the structure's data types.
The pieces match up this way:
char ut_user[8]; /* User login name: a8 */
char ut_id[4]; /* /etc/inittab id: a4 */
char ut_line[12]; /* device name: a12 */
short ut_pid; /* process ID: s */
short ut_type; /* type of entry: s */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS: s s */
time_t ut_time; /* time entry was made: l */
A char array becomes an a42, with the number being the length of the
array. A short becomes s, and a long becomes l. (You do need to know
something about how C stores data in memory. Note that exit_status and
ut_exit are two variables, even though they are declared on the same
line; that's why there are two s's in the comment.)
Here, how does the pack and unpack play its role? What format should the
input be in? What are the possible formats it can accept here?
Have you seen the documentation for pack and unpack? There is a large
table of format letters. Are you asking for something else?
Do you have a C struct that you can't translate to a pack/unpack
template? If so, feel free to post it here. Someone will know how to
deal with it.
Cheers!
--Tom Phoenix
Stonehenge Perl Training
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Re: Accessing packed data structures
Tom Phoenix wrote:
On 3/13/07, Dharshana Eswaran [EMAIL PROTECTED] wrote:
I was going thro the topic Accessing packed data structures in the Perl
Complete Reference Book. I came across this example:
struct utmp {
char ut_user[8]; /* User login name */
char ut_id[4]; /* /etc/inittab id */
char ut_line[12]; /* device name */
short ut_pid; /* process ID */
short ut_type; /* type of entry */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS. */
time_t ut_time; /* time entry was made */
};
For the above structure:
The pack template given was a8a4a12l.
I am, somehow, not able to understand how to generate the pack
template from
the structure's data types.
The pieces match up this way:
char ut_user[8]; /* User login name: a8 */
char ut_id[4]; /* /etc/inittab id: a4 */
char ut_line[12]; /* device name: a12 */
short ut_pid; /* process ID: s */
short ut_type; /* type of entry: s */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS: s s */
time_t ut_time; /* time entry was made: l */
A char array becomes an a42, with the number being the length of the
array. A short becomes s, and a long becomes l. (You do need to know
something about how C stores data in memory. Note that exit_status and
ut_exit are two variables, even though they are declared on the same
line; that's why there are two s's in the comment.)
No, exit_status is an identifier and ut_exit is the variable. In C it is
declared something like:
struct exit_status {
shortone;
shorttwo;
};
And is used something like:
struct exit_status variable_1, variable_2;
See the C Reference Manual at:
http://cm.bell-labs.com/cm/cs/who/dmr/cman.pdf
John
--
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certain sorts of tools at low cost and in short order. -- Larry Wall
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Re: Accessing packed data structures
On 3/13/07, Tom Phoenix [EMAIL PROTECTED] wrote:
On 3/13/07, Dharshana Eswaran [EMAIL PROTECTED] wrote:
I was going thro the topic Accessing packed data structures in the
Perl
Complete Reference Book. I came across this example:
struct utmp {
char ut_user[8]; /* User login name */
char ut_id[4]; /* /etc/inittab id */
char ut_line[12]; /* device name */
short ut_pid; /* process ID */
short ut_type; /* type of entry */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS. */
time_t ut_time; /* time entry was made */
};
For the above structure:
The pack template given was a8a4a12l.
I am, somehow, not able to understand how to generate the pack template
from
the structure's data types.
The pieces match up this way:
char ut_user[8]; /* User login name: a8 */
char ut_id[4]; /* /etc/inittab id: a4 */
char ut_line[12]; /* device name: a12 */
short ut_pid; /* process ID: s */
short ut_type; /* type of entry: s */
struct exit_status ut_exit; /* The exit status of a process */
/* marked as DEAD_PROCESS: s s */
time_t ut_time; /* time entry was made: l */
A char array becomes an a42, with the number being the length of the
array. A short becomes s, and a long becomes l. (You do need to know
something about how C stores data in memory. Note that exit_status and
ut_exit are two variables, even though they are declared on the same
line; that's why there are two s's in the comment.)
Here, how does the pack and unpack play its role? What format should the
input be in? What are the possible formats it can accept here?
Have you seen the documentation for pack and unpack? There is a large
table of format letters. Are you asking for something else?
Do you have a C struct that you can't translate to a pack/unpack
template? If so, feel free to post it here. Someone will know how to
deal with it.
Yes, you are right...
I have a structure and it is somethiung like this
typedef struct _TAPI_VOICE_NOTIFY_INCOMING_CALL_MSG_S
TAPI_CALL_ID_T callId;
TAPI_VOICE_INCOMING_CALL_TYPE_E type;
TAPI_PHONE_NUMBER_A phoneNumber;
TAPI_CALL_LINE_ElineNo;
TAPI_PHONEBOOK_NAME_A alpha;
} TAPI_VOICE_NOTIFY_INCOMING_CALL_MSG_S;
Here the typedefs are:
TAPI_CALL_ID_T, TAPI_PHONE_NUMBER_A, TAPI_PHONEBOOK_NAME_A = Unsigned int
8
TAPI_VOICE_INCOMING_CALL_TYPE_E = enum type
TAPI_CALL_LINE_E = signed int 8
Now how do i come up with the pack template? I dont know how a enum should
be represented in the pack template. :-(
/I8(enum)I8i8I8/ = pack template
The above mentioned enum just contains two elements.
The data which i need to pack and unpack to these elements are in hex
format(0x0B 0x1C 0x34 etc). It is a string of hex bytes.
I kindly request anyone to guide me in this.
Thanks and Regards,
Dharshana
Re: Accessing packed data structures
On 3/14/07, Dharshana Eswaran [EMAIL PROTECTED] wrote: snip Now how do i come up with the pack template? I dont know how a enum should be represented in the pack template. :-( /I8(enum)I8i8I8/ = pack template The above mentioned enum just contains two elements. The data which i need to pack and unpack to these elements are in hex format(0x0B 0x1C 0x34 etc). It is a string of hex bytes. I kindly request anyone to guide me in this. Thanks and Regards, Dharshana In ANSI C enums are of type int. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: Accessing packed data structures
On 3/14/07, Chas Owens [EMAIL PROTECTED] wrote: On 3/14/07, Dharshana Eswaran [EMAIL PROTECTED] wrote: snip Now how do i come up with the pack template? I dont know how a enum should be represented in the pack template. :-( /I8(enum)I8i8I8/ = pack template The above mentioned enum just contains two elements. The data which i need to pack and unpack to these elements are in hex format(0x0B 0x1C 0x34 etc). It is a string of hex bytes. I kindly request anyone to guide me in this. Thanks and Regards, Dharshana In ANSI C enums are of type int. The data which i need to pack and unpack to these elements are in hex format(0x0B 0x1C 0x34 etc). It is a string of hex bytes. Can i know about the format in which i need to supply the input? Coz i am unable to accept the hex string. Thanks and Regards, Dharshana
Can anyone guide me for : Data Structures in Perl
Hi, can anybody help me with a link or a tutorial for understanding the Datastructures in perl. Example, Array of Array, Hash of Array, Hash of Hash, Array of Hash. Along with few scripts to understand their application. thanks in advance, Atul Ashpalia __ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Can anyone guide me for : Data Structures in Perl
You can find everything you need in: perldoc perldsc -- Regards, Edward WIJAYA SINGAPORE can anybody help me with a link or a tutorial for understanding the Datastructures in perl. Example, Array of Array, Hash of Array, Hash of Hash, Array of Hash. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Can anyone guide me for : Data Structures in Perl
Wijaya Edward wrote: can anybody help me with a link or a tutorial for understanding the Datastructures in perl. Example, Array of Array, Hash of Array, Hash of Hash, Array of Hash. You can find everything you need in: perldoc perldsc -- Regards, Edward WIJAYA SINGAPORE There are also: perldoc perllol perldoc perlreftut perldoc perlref And Learning Perl Objects, References, and Modules from O'Reilly. http://danconia.org -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Module to merge arbitrary multi-level data structures?
Randy W. Sims wrote: Does anyone know of a module that can take a reference to two arbitrarily organized data structures, and return a merged structure? Scratch that. Hash::Merge seems to do what I want. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Module to merge arbitrary multi-level data structures?
Does anyone know of a module that can take a reference to two arbitrarily organized data structures, and return a merged structure? Thanks, Randy. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
RE: [PBML] Help with Data Structures
From: William Martell mailto:[EMAIL PROTECTED] wrote:
: Hello All,
:
: I was wondering if someone could tell me how to manipulate
: this data structure. I have attached the datafile. My code
: and code results are printed below.
:
: If you take a look at the results, you will see that there is
: a hash created for each interaction in the loop and the
: results are printed using data::dumper. The problem, is that
: some hash values are blank, because they are printed during
: the following interaction of the loop.
:
: In other words. I am getting this...
[snip]
: and I want to get this...
:
: $VAR1 = {
: 'waste' = '0.00',
: 'promo' = '0.00',
: 'count' = '5.00',
: 'plu' = '002800',
: 'total' = '10.00',
: 'description' = '6 NUGGET',
: 'line' = 'PLU'
: };
:
: Could anyone help explain why this is occuring and how to
: resolve it. Thank you all very much for reading my message.
It occurs because you are resetting the %record on each
pass instead of only as you see a new record begin. Try:
my %record;
# skip first 3 lines
FILE; FILE; FILE;
while ( FILE ) {
if ( /^PLU/ ) {
#reset record
%record = ();
@record{ qw| line plu description | }
= get_plu_and_description($_);
} elsif (/^\t/) {
@record{ qw| count total promo waste | }
= get_count_total_promo_waste($_);
print Dumper(\%record);
}
}
HTH,
Charles K. Clarkson
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Help with Data Structures
Hello All,
I was wondering if someone could tell me how to manipulate this data structure. I
have attached the datafile. My code and code results are printed below.
If you take a look at the results, you will see that there is a hash created for each
interaction in the loop and the results are printed using data::dumper. The problem,
is that some hash values are blank, because they are printed during the following
interaction of the loop.
In other words. I am getting this...
$VAR1 = {
'waste' = '',
'promo' = '',
'count' = '',
'plu' = '002800',
'total' = '',
'description' = '6 NUGGET',
'line' = 'PLU'
};
$VAR1 = {
'waste' = '0.00',
'promo' = '0.00',
'count' = '5.00',
'plu' = '',
'total' = '10.00',
'description' = '',
'line' = ''
};
and I want to get this...
$VAR1 = {
'waste' = '0.00',
'promo' = '0.00',
'count' = '5.00',
'plu' = '002800',
'total' = '10.00',
'description' = '6 NUGGET',
'line' = 'PLU'
};
Could anyone help explain why this is occuring and how to resolve it. Thank you all
very much for reading my message.
PS. Does anyone know where I can get a tutorial or book chapter that talks about how
to use Data::Dumper. I checked the documentation on CPAN and it is difficult for me
to understand. Any ideas??
THANKS!!
CODE
#!/perl
use strict;
use warnings;
use Diagnostics;
use Data::Dumper 'Dumper';
#find the date report you need
#open the report
open(FILE,SAM65 plu report.txt) or die(Can't open report);
my %record;
#print csv( {
#line = 'line',
#plu= 'plu',
#description = 'description',
#count = 'count',
#total = 'total',
#promo = 'promo',
#waste = 'waste'
#} ), \n;
while(FILE){
# create record
my %record = (
line= '',
plu = '',
description = '',
count = '',
total = '',
promo = '',
waste = ''
);
if($.3){
if(/^PLU/){
#print $.starts with plu\n;
@record{ qw| line plu description |} = get_plu_and_description($_);
# delete($record{'count'});
# delete($record{'total'});
# delete($record{'promo'});
# delete($record{'waste'});
}
else{
@record{ qw| count total promo waste | }
= get_count_total_promo_waste($_);
}
#print Data::Dumper-Dump([\%record],[*record]);
print Dumper(\%record);
#print csv( \%record ), \n if is_valid_record( \%record );
}
}
sub get_info{
my $field = shift;
chomp($field);
$field =~ s/\t+/ /g;
my @fields = split(/' '/);
foreach my $each (@fields){
$each =~ s/^\s+//;
$each =~ s/\s+$//;
}
return $fields['line'];
}
sub get_count_total_promo_waste{
my $field = shift;
chomp($field);
$field =~ s/\t+/ /g;#replace all tabs with spaces
my($count, $total, $promo,$waste) = split( ,$field);
return $count, $total, $promo, $waste;
}
sub get_plu_and_description{
my $field = shift;
chomp($field);
my($line, $plu, $description) = split(/\t/,$field);
return $line, $plu, $description;
}
sub is_valid_record {
my $field = shift;
foreach my $value ( values %$field ) {
# return true if one field is valid
return 1 if defined $value $value ne '';
}
# return false if we get here
return;
}
sub csv {
my $field = shift;
# if you need to change field order
# do it here
my @field_order = qw| line plu description count total promo waste |;
# add double quotes ()
foreach my $value ( values %$field ) {
$value = NULL if(!defined($value));
$value =~ s/^\s+//;
$value =~ s/\s+$//;
$value = qq($value);
}
# use a hash slice to order the fields
return join ',', @$field{ @field_order };
}
END CODE
RESULTS
$VAR1 = {
'waste' = '',
'promo' = '',
'count' = '',
'plu' = '002800',
'total' = '',
Help with Data Structures
Hello All,
I hope you all are doing well.
I am trying to get this code to work correctly and I have used another Perl Guru's
code [Thanks Charles Clarkson] to get this far, but I am still unsure about a few
things...
I am trying to read a file (attached). and I am trying to make a csv file of it.
Here is my code.
#!/perl -w
use strict;
use warnings;
use Diagnostics;
use Data::Dumper 'Dumper';
#find the date report you need
#open the report
open(FILE,SAM65 financial report.txt) or die(Can't open report);
my %report;
my %rpt_title;
my %record;
print csv( {
name = 'name',
count = 'count',
total = 'total',
ext_total = 'ext_total'
} ), \n;
while(FILE){
if($.3){
print csv( \%record ), \n if is_valid_ad( \%record );
# Set field defaults
%record = (
name = '',
count = '',
total = '',
ext_total = ''
);
# update %record for this line
@record{ qw| name count total ext_total | }
= split(/\t/, $_);
}#end print csv
}#end if.. to skip first three lines.
print csv( \%record ), \n if is_valid_ad( \%record );
sub is_valid_ad {
my $field = shift;
foreach my $value ( values %$field ) {
# return true if one field is valid
return 1 unless $value eq '';
}
# return false if we get here
return;
}
sub csv {
my $field = shift;
# if you need to change field order
# do it here
my @field_order = qw|name count total ext_total|;
# add double quotes ()
foreach my $value ( values %$field ) {
$value = NULL if(!defined($value)); #if there is no match, then make that
field null
$value =~ s/^\s+//;#remove leading whitespace
$value =~ s/\s+$//;#remove trailing whitespace
$value = qq($value);
}
# use a hash slice to order the fields
return join ',', @$field{ @field_order };
}
__END__
What I am curious about is, when I run the code without the line to make value equal
null if there it is undefined, I get a lot of errors...
Use of Uninitialized Values.. Blah Blah.
When I add the line in.. the number of errors is reduced, but I still get them.
Why do I get them. And how do I get rid of them. The source files are ascii files
and I plan on entering each record into a database, then creating a worksheet in excel
out of it.
THanks in Advance for your time.
Will
CRS DEMO/12-12-1997/14:00:29
X1/FINANCIAL/12-12-1997/21:02
COUNT TOTAL
+PLU TTL32.00 52.28
ADJST TTL 32.00 52.28
NONTAX 1 1.00
TAX1 SALES 0 44.99
TAX2 SALES 0 1.09
TAX3 SALES 0 1.29
TAX10 2.25
XMPTl SALES 0 0.25
EATIN TTL 1 5.24
TAKEOUT TTL 1 0.25
% 1 3 -1.57
% 2 2 -1.11
% 3 1 -4.94
NET SALE6 48.49
RETURN 4 -6.98
GROSS SALES 0 63.09
CASH SALES 6 48.49
CASH- IN-D 6 48.49
DRWR TTL0 48.49
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Help with Data Structures
Hello Group,
I am trying to get this code to run. I got it from the book Data Munging with Perl. I
cut and pasted the code, then changed the input from stdin to FILE. I supplied a text
file for the passwords (I am on a Windows 2k box). But I can't get it correct. I think
the line @[EMAIL PROTECTED]) = split(/:/); is incorrect syntactically but I could be
wrong. Could anyone help me understand this problem. Thanks in Advance!
#!/perl -w
use strict;
use warnings;
open(FILE, passwords.txt) or die(cant open file);
#read_passwd;
sub read_passwd {
my %users;
my @fields = qw/name pword uid gid fullname home shell/;
while (FILE) {
chomp;
my %rec;
@[EMAIL PROTECTED]) = split(/:/);
$users{$rec-{name}} = \%rec;
}
return \%users;
}
my $users = read_passwd();
my @names;
foreach (keys %{$users}) {
next unless $users-{$_}{fullname};
my ($forename, $surname) = split(/\s+/, $users-{$_}{fullname}, 2);
push @names, $surname, $forename;
}
print map { $_\n } sort @names;
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RE: Help with Data Structures
From: William Martell mailto:[EMAIL PROTECTED] wrote: : Hello Group, : : : : I am trying to get this code to run. I got it from the book : Data Munging with Perl. I cut and pasted the code, then : changed the input from stdin to FILE. I supplied a text file : for the passwords (I am on a Windows 2k box). But I can't get : it correct. I think the line @[EMAIL PROTECTED]) = split(/:/); is : incorrect syntactically but I could be wrong. Could anyone : help me understand this problem. Thanks in Advance! [snipped code] After removing blank lines and illegal characters I get the following errors. syntax error at bb.pl line 15, near @fields) Global symbol $rec requires explicit package name at bb.pl line 16. Missing right curly or square bracket at bb.pl line 30, at end of line Show us the example from the book. Or give us a link to it on line. (When you cut and paste code please prune excess spacing.) A sample file would be nice to. HTH, Charles K. Clarkson -- Mobile Homes Specialist 254 968-8328 -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
RE: Help with Data Structures
On Fri, 4 Jun 2004 09:52:15 -0500, Charles K. Clarkson wrote:
Show us the example from the book. Or give us a link to it on line.
(When you cut and paste code please prune excess spacing.) A sample
file would be nice to.
Here you go.
Example: listing users
To start with, lets produce a list of all of the real names of all of the users on the
system. As that would be a little too simple well introduce a couple of refinements.
First, included in the list of users in /etc/passwd are a number of special accounts
that arent for real users. These will include root (the superuser), lp (a user ID
which is often used to carry out printer administration tasks) and a number of other
task-oriented users. Assuming that we can detect these uses by the fact that their full
names will be empty, well exclude them from the output. Secondly, in the original
file, the full names are in the format forename surname. Well print them out
as surname, forename, and sort them in surname order. Heres the script:
use strict;
my $users = read_passwd();
my @names;
foreach (keys %{$users}) {
next unless $users-{$_}{fullname};
my ($forename, $surname) = split(/\s+/, $users-{$_}{fullname}, 2);
push @names, $surname, $forename;
}
print map { $_\n } sort @names;Example: reading /etc/passwd
Lets start by writing a routine to read the data into internal data structures. This
routine can then be used by any of the following examples. As always, for flexibility,
well assume that the data is coming in via STDIN.
sub read_passwd {
my %users;
my @fields = qw/name pword uid gid fullname home shell/;
while (STDIN) {
chomp;
my %rec;
@[EMAIL PROTECTED]) = split(/:/);
$users{$rec-{name}} = \%rec;
}
return \%users;
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RE: Help with Data Structures
From: William Martell mailto:[EMAIL PROTECTED] wrote:
: Here you go.
Try this then:
my $users = read_passwd();
my @names;
foreach (keys %{$users}) {
next unless $users-{$_}{fullname};
my ($forename, $surname) = split(/\s+/, $users-{$_}{fullname}, 2);
push @names, $surname, $forename;
}
print map { $_\n } sort @names;
sub read_passwd {
my %users;
my @fields = qw/name pword uid gid fullname home shell/;
while (DATA) {
chomp;
my %rec;
@[EMAIL PROTECTED] = split(/:/);
$users{$rec{name}} = \%rec;
}
return \%users;
}
__END__
0:1:2:3:Porky Pig:5:6
7:8:9:10:Bug's Bunny:12:13
14:15:16:17:Donald Duck:19:20
21:22:23:24:Tweety Bird:26:27
To use a file, open it and replace DATA with that file handle:
sub read_passwd {
my $file = shift;
my %users;
my @fields = qw/name pword uid gid fullname home shell/;
# don't clobber open file handles
local *FH;
open FH, $file or die Cannot open $file: $!;
while ( FH ) {
chomp;
my %rec;
@[EMAIL PROTECTED] = split(/:/);
$users{$rec{name}} = \%rec;
}
return \%users;
}
HTH,
Charles K. Clarkson
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Re: Help with Data Structures
William Martell wrote:
Hello Group,
Hello,
I am trying to get this code to run. I got it from the book
Data Munging with Perl. I cut and pasted the code, then changed
the input from stdin to FILE. I supplied a text file for the
passwords (I am on a Windows 2k box). But I can't get it correct.
I think the line @[EMAIL PROTECTED]) = split(/:/); is incorrect
^ ^
Yes it is incorrect. You have a left brace and a right parenthesis when
it should be left and right braces.
@rec{ @fields } = split /:/;
syntactically but I could be wrong. Could anyone help me
understand this problem. Thanks in Advance!
John
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program
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Your recommendations to tie multi-level data structures
All,
I would like the ability to tie a database and use it as a multi-level data
structure, like
$tied{hash}{subhash}
$tied{hash}{array}[0]
Etc...
Any recommendations for this? I've heard I should check out the MLDBM module.
How have others conquered this issue? Is it possible?
Thanks,
Phil
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RE: Your recommendations to tie multi-level data structures
Phil Schaechter wrote:
All,
I would like the ability to tie a database and use it as a
multi-level data structure, like
$tied{hash}{subhash}
$tied{hash}{array}[0]
Etc...
Any recommendations for this? I've heard I should check out the
MLDBM module. How have others conquered this issue? Is it possible?
Yes, use MLDBM.
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RE: copying complex data structures
use Storable; $arrayref_one = dclone( $arrayref_two ); aha thanks :) it's those details that make a program so much easier to make.. i noticed another poster asking about reference notations- i think that this and Object Oriented programming have given me the most headaches on a conceptual level. while i've gotten a handle on references (i hope) tha OO stuff still gets to me *laugh* again thanks, willy -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
copying complex data structures
the following will not work:
$arrayref_one = $arrayreftwo; #it's just making a new name for the same
#reference.
the following works fine:
foreach my $a (0..$what){
foreach my $b (0..$why){
$arrayref_one-[$a]-[$b] = $arrayref_two-[$a]-[$b];
}
}
it would be nice to have something to copy complex data structures that
isn't going to be a code maintenance headache- the above is dependent
on the data structure being a 2 dimensional array of particular size.
i don't want that restriction.
any help would be apreciated :)
thanks,
willy
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Re: copying complex data structures
On Dec 11, 2003, at 9:37 AM, West, William M wrote:
the following will not work:
$arrayref_one = $arrayreftwo; #it's just making a new name for the same
#reference.
the following works fine:
foreach my $a (0..$what){
foreach my $b (0..$why){
$arrayref_one-[$a]-[$b] = $arrayref_two-[$a]-[$b];
}
}
it would be nice to have something to copy complex data structures that
isn't going to be a code maintenance headache- the above is dependent
on the data structure being a 2 dimensional array of particular size.
i don't want that restriction.
any help would be apreciated :)
From the Perl Cookbook (2nd Edition), recipe 11.12:
use Storable;
$arrayref_one = dclone( $arrayref_two );
James
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RE: copying complex data structures
Try clone method of Storable module from CPAN.
There is also Clone module out there.
HTH,
José.
-Original Message-
From: West, William M [mailto:[EMAIL PROTECTED]
Sent: Thursday, December 11, 2003 4:37 PM
To: [EMAIL PROTECTED]
Subject: copying complex data structures
the following will not work:
$arrayref_one = $arrayreftwo; #it's just making a new name for the same
#reference.
the following works fine:
foreach my $a (0..$what){
foreach my $b (0..$why){
$arrayref_one-[$a]-[$b] = $arrayref_two-[$a]-[$b];
}
}
it would be nice to have something to copy complex data structures that isn't going to
be a code maintenance headache- the above is dependent on the data structure being a
2 dimensional array of particular size. i don't want that restriction.
any help would be apreciated :)
thanks,
willy
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Creating uniqueness in complex data structures
The log files I am parsing have threads (a T followed by several
alphanumeric numbers) associated with each line of text. I want to push
each value of $2 (which is a server name) into an anonymous array.
This works fine in the following code.
if ($_ =~ /(T[0-9A-F]+) MSM SCTS\((.+)\)/)
{
my $thread = $1;
push @{$server{$thread}}, $2
unless grep $_ eq $2, @{$server{$thread}};
}
The problem I just realized is that sometimes a duplicate thread number
exists and it overwrites the information it previously had in it. How do
I create a unique data structure that can prevent this from happening?
--Paul
Re: Creating uniqueness in complex data structures
On Nov 23, 2003, at 6:36 PM, Paul Harwood wrote:
The log files I am parsing have threads (a T followed by several
alphanumeric numbers) associated with each line of text. I want to push
each value of $2 (which is a server name) into an anonymous array.
This works fine in the following code.
if ($_ =~ /(T[0-9A-F]+) MSM SCTS\((.+)\)/)
{
my $thread = $1;
push @{$server{$thread}}, $2
unless grep $_ eq $2, @{$server{$thread}};
}
The problem I just realized is that sometimes a duplicate thread number
exists and it overwrites the information it previously had in it. How
do
I create a unique data structure that can prevent this from happening?
I wouldn't think this could be happening IF the thread number already
contained an array reference.
James
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RE: Creating uniqueness in complex data structures
The problem is that the value in $thread can be duplicated therefore it
will write over anything else contained there. That's the problem I am
having.
-Original Message-
From: James Edward Gray II [mailto:[EMAIL PROTECTED]
Posted At: Monday, November 24, 2003 6:18 AM
Posted To: Perl
Conversation: Creating uniqueness in complex data structures
Subject: Re: Creating uniqueness in complex data structures
On Nov 23, 2003, at 6:36 PM, Paul Harwood wrote:
The log files I am parsing have threads (a T followed by several
alphanumeric numbers) associated with each line of text. I want to
push
each value of $2 (which is a server name) into an anonymous array.
This works fine in the following code.
if ($_ =~ /(T[0-9A-F]+) MSM SCTS\((.+)\)/)
{
my $thread = $1;
push @{$server{$thread}}, $2
unless grep $_ eq $2, @{$server{$thread}};
}
The problem I just realized is that sometimes a duplicate thread
number
exists and it overwrites the information it previously had in it. How
do
I create a unique data structure that can prevent this from happening?
I wouldn't think this could be happening IF the thread number already
contained an array reference.
James
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RE: Creating uniqueness in complex data structures
On Nov 24, Paul Harwood said:
The problem is that the value in $thread can be duplicated therefore it
will write over anything else contained there. That's the problem I am
having.
-Original Message-
if ($_ =~ /(T[0-9A-F]+) MSM SCTS\((.+)\)/)
{
my $thread = $1;
push @{$server{$thread}}, $2
unless grep $_ eq $2, @{$server{$thread}};
}
There's no overwriting going on. You're using push(), which means that
you'll never lose data, you'll only get more and more.
Here's a similarly-functioning block of code:
my @stuff = (
'T123 Here is a message',
'T237 Here's a different one',
'T123 Here's one for the first thread',
'T237 Here's a different one', # -- duplicate, not entered
);
for (@stuff) {
chomp;
my ($thread, $data) = split ' ', $_, 2;
push @{ $server{$thread} }, $data
unless grep $_ eq $data, @{ $server{$thread} };
}
At the end of this, $server{T123} has two messages, and $server{T237} has
only one.
Explain how you think your code has a problem.
--
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RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
stu what does y/// stand for? tenderpuss why, yansliterate of course.
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RE: Creating uniqueness in complex data structures
OK, maybe I am confusing myself. :)
-Original Message-
From: Jeff 'japhy' Pinyan [mailto:[EMAIL PROTECTED]
Sent: Monday, November 24, 2003 9:27 AM
To: Paul Harwood
Cc: James Edward Gray II; Beginner Perl
Subject: RE: Creating uniqueness in complex data structures
On Nov 24, Paul Harwood said:
The problem is that the value in $thread can be duplicated therefore it
will write over anything else contained there. That's the problem I am
having.
-Original Message-
if ($_ =~ /(T[0-9A-F]+) MSM SCTS\((.+)\)/)
{
my $thread = $1;
push @{$server{$thread}}, $2
unless grep $_ eq $2, @{$server{$thread}};
}
There's no overwriting going on. You're using push(), which means that
you'll never lose data, you'll only get more and more.
Here's a similarly-functioning block of code:
my @stuff = (
'T123 Here is a message',
'T237 Here's a different one',
'T123 Here's one for the first thread',
'T237 Here's a different one', # -- duplicate, not entered
);
for (@stuff) {
chomp;
my ($thread, $data) = split ' ', $_, 2;
push @{ $server{$thread} }, $data
unless grep $_ eq $data, @{ $server{$thread} };
}
At the end of this, $server{T123} has two messages, and $server{T237}
has
only one.
Explain how you think your code has a problem.
--
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http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/
http://www.cpan.org/
stu what does y/// stand for? tenderpuss why, yansliterate of
course.
[ I'm looking for programming work. If you like my work, let me know.
]
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RE: Data Structures in Perl
HI,
I must be missing something, after following Gupta's advice the particular
object printed fine using this code:
$obj-order_number ($order_num);
print obj: . $obj-order_number($order_num) . \n;
push @order, $obj;
for each of the 15 orders which I have shown below. Now, at the end of my
program I run a for loop:
for (my $w=0;$w=$#order;$w++) {
print Order Number: . $order[$w]-order_number() . \n;
}
to print out all of the 15 differnet order numbers and all I get is the last
order number printed 15 times. What am I missing besides sleep. TIA.
Trevor
C:\maverickperl miva_struc_class.pl
# of Rows in Order: 25 rows in the 1 order
Order Number is 3225
w is 1
obj:3225
# of Rows in Order: 27 rows in the 2 order
Order Number is 3218
w is 2
obj:3218
# of Rows in Order: 25 rows in the 3 order
Order Number is 3223
w is 3
obj:3223
# of Rows in Order: 26 rows in the 4 order
Order Number is 5010
w is 4
obj:5010
# of Rows in Order: 29 rows in the 5 order
Order Number is 5006
w is 5
obj:5006
# of Rows in Order: 26 rows in the 6 order
Order Number is 5010
w is 6
obj:5010
# of Rows in Order: 26 rows in the 7 order
Order Number is 5003
w is 7
obj:5003
# of Rows in Order: 27 rows in the 8 order
Order Number is 4971
w is 8
obj:4971
# of Rows in Order: 26 rows in the 9 order
Order Number is 4931
w is 9
obj:4931
# of Rows in Order: 27 rows in the 10 order
Order Number is 4925
w is 10
obj:4925
# of Rows in Order: 25 rows in the 11 order
Order Number is 4893
w is 11
obj:4893
# of Rows in Order: 26 rows in the 12 order
Order Number is 4864
w is 12
obj:4864
# of Rows in Order: 25 rows in the 13 order
Order Number is 4870
w is 13
obj:4870
# of Rows in Order: 29 rows in the 14 order
Order Number is 4873
w is 14
obj:4873
# of Rows in Order: 25 rows in the 15 order
Order Number is 3280
w is 15
obj:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
Order Number:3280
C:\maverick
-Original Message-
From: Gupta, Sharad [mailto:[EMAIL PROTECTED]
Sent: Sunday, July 06, 2003 4:55 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: RE: Data Structures in Perl
From ur example i assume that:
my @order is an array collecting all of the objects with each order.
So, instead of
my @order = new miva_order;
we mean to say:
my @orders;
my $obj = new miva_order;
$obj-order_number(get_order_num_via_regex());
push @orders,$obj;
for (my $w=0;$w=$#orders;$w++) {
print $order[$w]-order_number();
}
Note that in the for loop above i am starting $w with 0 and not 1. If u
start with 1 and ur @order have only 1 element, it won't print anything
because the index start with '0'
-Sharad
-Original Message-
From: Trevor Morrison [mailto:[EMAIL PROTECTED]
Sent: Sunday, July 06, 2003 10:37 AM
To: [EMAIL PROTECTED]
Subject: Data Structures in Perl
Hi,
I am new to using data structures in Perl, but have played with them in C (a
long time ago). I have downloaded the Class::Struct::Fields module on my
W2K system and all works well. I am finding the documentation a little
terse though.
I am trying to read into my Perl program orders that was placed through an
on-line shopping cart that are sent to an Outlook mailbox. I export the
email to a file that I read into my Perl program. Since each order is
basically the same as far as content is concerned there are some variation.
I would like to use a data structure to store each orders information in.
Now, I have read through the Programming Perl manual (Chapter 9) on Data
structures several times and searched the web for the information that I
need, but cannot find it.
If I claim my data structure like so:
use Class::Struct::FIELDS;
struct (miva_order = {
order_number='$' ,
date='$' ,
bill_name ='$' ,
ship_name ='$' ,
ship_email_address ='$' ,
ship_phone_number ='$' ,
ship_business_name ='$' ,
ship_to_street ='$' ,
ship_to_city='$' ,
ship_to_state ='$' ,
ship_to_zip ='$' ,
bill_to_street ='$' ,
bill_to_city='$' ,
bill_to_state ='$' ,
bill_to_zip ='$' ,
quantity='$' ,
code='$' ,
shipping_method ='$' ,
shipping_amount
how to create/use data structures in perl ?
Hi,
How to create data structures in perl ?
I have following data structure in C...and i have to
create similar data structure in perl and use...
how to create data strutures in perl and how to use ?
typedef struct { charPrefix[8];
charPrint;
charName[80];
charModTime[32];
int Len;
} fileinfo_;
Thanks
-Madhu
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Re: how to create/use data structures in perl ?
Madhu Reddy wrote:
Hi,
How to create data structures in perl ?
I have following data structure in C...and i have to
create similar data structure in perl and use...
how to create data strutures in perl and how to use ?
perldoc -f pack
perldoc -f unpack
typedef struct { charPrefix[8];
charPrint;
charName[80];
charModTime[32];
int Len;
} fileinfo_;
Eg.
#!/usr/bin/perl
use strict;
use warnings;
my $format = 'Z8 c Z80 Z32 i';
my $fileinfo_instance = pack ($format, 'project_', 1, 'SomeName',
'ModTime', 40);
my ($prefix, $print, $name, $modtime, $length) = unpack ($format,
$fileinfo_instance);
print Prefix = $prefix\n;
print Print = $print\n;
print Name= $name\n;
print Modtime = $modtime\n;
print Length = $length\n;
Thanks
-Madhu
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Data Structures in Perl
Hi,
I am new to using data structures in Perl, but have played with them in C (a
long time ago). I have downloaded the Class::Struct::Fields module on my
W2K system and all works well. I am finding the documentation a little
terse though.
I am trying to read into my Perl program orders that was placed through an
on-line shopping cart that are sent to an Outlook mailbox. I export the
email to a file that I read into my Perl program. Since each order is
basically the same as far as content is concerned there are some variation.
I would like to use a data structure to store each orders information in.
Now, I have read through the Programming Perl manual (Chapter 9) on Data
structures several times and searched the web for the information that I
need, but cannot find it.
If I claim my data structure like so:
use Class::Struct::FIELDS;
struct (miva_order = {
order_number='$' ,
date='$' ,
bill_name ='$' ,
ship_name ='$' ,
ship_email_address ='$' ,
ship_phone_number ='$' ,
ship_business_name ='$' ,
ship_to_street ='$' ,
ship_to_city='$' ,
ship_to_state ='$' ,
ship_to_zip ='$' ,
bill_to_street ='$' ,
bill_to_city='$' ,
bill_to_state ='$' ,
bill_to_zip ='$' ,
quantity='$' ,
code='$' ,
shipping_method ='$' ,
shipping_amount ='$' ,
sales_tax ='$' ,
notes ='$'
}
);
my @order = new miva_order;
I want to fill the fields saying $order-order_number($order_numb) where the
$orders numb is pulled from the email using regular expressions.
Now, what I want to be able to do is say :
for (my $w=1; $w=$number_of_orders; w++) {
print $order[$w]-order_number ;
}
and have all the order numbers that are associated with the each of the
orders print out; and it does not work this way. This is where my problem
is, I am coding wrong and I cannot see it. Any help is appreciated.
Trevor
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RE: Data Structures in Perl
From ur example i assume that:
my @order is an array collecting all of the objects with each order.
So, instead of
my @order = new miva_order;
we mean to say:
my @orders;
my $obj = new miva_order;
$obj-order_number(get_order_num_via_regex());
push @orders,$obj;
for (my $w=0;$w=$#orders;$w++) {
print $order[$w]-order_number();
}
Note that in the for loop above i am starting $w with 0 and not 1. If u start with 1
and ur @order have only 1 element, it won't print anything because the index start
with '0'
-Sharad
-Original Message-
From: Trevor Morrison [mailto:[EMAIL PROTECTED]
Sent: Sunday, July 06, 2003 10:37 AM
To: [EMAIL PROTECTED]
Subject: Data Structures in Perl
Hi,
I am new to using data structures in Perl, but have played with them in C (a
long time ago). I have downloaded the Class::Struct::Fields module on my
W2K system and all works well. I am finding the documentation a little
terse though.
I am trying to read into my Perl program orders that was placed through an
on-line shopping cart that are sent to an Outlook mailbox. I export the
email to a file that I read into my Perl program. Since each order is
basically the same as far as content is concerned there are some variation.
I would like to use a data structure to store each orders information in.
Now, I have read through the Programming Perl manual (Chapter 9) on Data
structures several times and searched the web for the information that I
need, but cannot find it.
If I claim my data structure like so:
use Class::Struct::FIELDS;
struct (miva_order = {
order_number='$' ,
date='$' ,
bill_name ='$' ,
ship_name ='$' ,
ship_email_address ='$' ,
ship_phone_number ='$' ,
ship_business_name ='$' ,
ship_to_street ='$' ,
ship_to_city='$' ,
ship_to_state ='$' ,
ship_to_zip ='$' ,
bill_to_street ='$' ,
bill_to_city='$' ,
bill_to_state ='$' ,
bill_to_zip ='$' ,
quantity='$' ,
code='$' ,
shipping_method ='$' ,
shipping_amount ='$' ,
sales_tax ='$' ,
notes ='$'
}
);
my @order = new miva_order;
I want to fill the fields saying $order-order_number($order_numb) where the
$orders numb is pulled from the email using regular expressions.
Now, what I want to be able to do is say :
for (my $w=1; $w=$number_of_orders; w++) {
print $order[$w]-order_number ;
}
and have all the order numbers that are associated with the each of the
orders print out; and it does not work this way. This is where my problem
is, I am coding wrong and I cannot see it. Any help is appreciated.
Trevor
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Re: Data Structures in Perl
Gupta, Sharad [EMAIL PROTECTED] writes:
From ur example i assume that:
my @order is an array collecting all of the objects with each order.
So, instead of
my @order = new miva_order;
we mean to say:
my @orders;
my $obj = new miva_order;
$obj-order_number(get_order_num_via_regex());
push @orders,$obj;
for (my $w=0;$w=$#orders;$w++) {
print $order[$w]-order_number();
^ 'order', or 'orders'?
}
The Perlish way to do the above is:
foreach my $order (@orders) {
print $order-order_number();
}
This iterates over each element in the array @orders, and places them
in turn in a variable called '$order'. Do it this way, and you don't
have to worry about the index of the array at all.
-RN
--
Robin Norwood
Red Hat, Inc.
The Sage does nothing, yet nothing remains undone.
-Lao Tzu, Te Tao Ching
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RE: data structures one more try
Rob, Good call! You can print out the data in @bags and @bag_quantity using Data::Dumper.. print Dumper [EMAIL PROTECTED]; http://www.coraconnection.com/paul_s/pages/catalog.html Check this out, 'order' second and third bag in the first row. and hit the CGI and see the results, bizarre! Thanks for your help, Regards Dave ( kora musician / audiophile / web master @ cora connection / DFW, TX, USA) and web designer for Afropop Worldwide http://www.afropop.org/community/contributors.php?ID=8 == Cora Connection: Your West African Music Source Resources, Recordings, Instruments More! http://www.coraconnection.com/ == == Cora Connection: Your West African Music Source Resources, Recordings, Instruments More! http://www.coraconnection.com/ == -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: data structures one more try
Rob and all the rest reading this, Here's what fixed the problem. The check boxes are only sent to CGI.pm if checked, while all the input fields are sent regardless. So @bag_quantity was filled with '0's ... get rid of 'o's @bag_quantity = grep(/[^0]/, @bag_quantity); ...this now seems to work Thanks, Dave ( kora musician / audiophile / web master @ cora connection / DFW, TX, USA) and web designer for Afropop Worldwide http://www.afropop.org/community/contributors.php?ID=8 == Cora Connection: Your West African Music Source Resources, Recordings, Instruments More! http://www.coraconnection.com/ == -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
data structures
I am trying to build a data structure, and am tripping up here.
any suggestions?
Thx!
Dave
!/usr/bin/perl -w
snip...
@bags = param('handbag'); get all of the bags styles
@bag_quantity = param('quantity'); get all of the bags quantity
foreach my $bag (@bags){
($bag_name,$imgName) = split (/,/,$bag);
push %bags_ordered,$bag_name;
push %bags_ordered{$bag_name}{image_name} = $imgName;
}
foreach my $q (@bag_quantity){
push %bags_ordered{$bag_name}{$bag_quantity} =$q;
}
Data structure:
%bags_ordered = (
bag-style1 = { price = 10,
image_name = 'FIO-142b-small',
quantity= 5
},
bag-style2 = { price = 12,
image_name = 'GUC-208-small',
quantity= 5,
},
);
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RE: data structures
any suggestions?
I'll try.
@bags = param('handbag'); get all of the bags styles
Missing comment...
@bags = param('handbag'); # get all of the bags styles
push %bags_ordered,$bag_name;
You can't push onto a hash, only an array. So either %bags_ordered need to
be an array, or you mean something else.
Maybe this is what you mean...
use strict; # a big bonus for debugging
use Data::Dumper; # for testing
my %bags_ordered;
my @bags = param('handbag'); # get all of the bags styles
my @bag_quantity = param('quantity'); # get all of the bags quantity
for (my $i = 0; $i @bags; $i++) {
# split the bag item
my ($bag_name, $imgName) = split (/,/, $bags[$i]);
# create an empty hash if this is a new bag
$bags_ordered{$bag_name} = {} unless exists $bags_ordered{$bag_name};
# set the image name
$bags_ordered{$bag_name}-{image_name} = $imgName;
# set the quantity. should it be additive with +=?
$bags_ordered{$bag_name}-{quantity} = $bag_quantity[$i];
}
# print the structure for testing using Data::Dumper
print Dumper \%bags_ordered;
Rob
-Original Message-
From: David Gilden [mailto:[EMAIL PROTECTED]
Sent: Tuesday, March 04, 2003 4:57 PM
To: [EMAIL PROTECTED]
Subject: data structures
I am trying to build a data structure, and am tripping up here.
any suggestions?
Thx!
Dave
!/usr/bin/perl -w
snip...
@bags = param('handbag'); get all of the bags styles
@bag_quantity = param('quantity'); get all of the bags quantity
foreach my $bag (@bags){
($bag_name,$imgName) = split (/,/,$bag);
push %bags_ordered,$bag_name;
push %bags_ordered{$bag_name}{image_name} = $imgName;
}
foreach my $q (@bag_quantity){
push %bags_ordered{$bag_name}{$bag_quantity} =$q;
}
Data structure:
%bags_ordered = (
bag-style1 = { price = 10,
image_name = 'FIO-142b-small',
quantity= 5
},
bag-style2 = { price = 12,
image_name = 'GUC-208-small',
quantity= 5,
},
);
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RE: data structures / CGI.pm
Good afternon,
I am not seeing consistent results from my script below.
It seems that sometimes it works and other times I get '0's in
the quantity field.
As I don't write PERL often enough this is probably poorly written code!
Thanks for any help.
Dave
HTML at:
http://www.coraconnection.com/paul_s/pages/catalog.htm
#!/usr/bin/perl -w
use CGI qw/:standard/;
use CGI::Carp qw(fatalsToBrowser);
use strict;
my (@bags,@bag_quantity);
my ($bag_name,$imgName);
my (%bags_ordered,%prices);
my $n=0;
my $bags_ordered;
use Data::Dumper;
# Build data structure
@bags = param('handbag'); # get all of the bags styles
@bag_quantity = param('quantity'); # get all of the bags quantity
foreach my $bag (@bags){
($bag_name,$imgName) = split (/,/,$bag);
$bags_ordered{$bag_name} = {} unless exists $bags_ordered{$bag_name}; # thanks rob!
$bags_ordered{$bag_name}-{image_name} =$imgName;
$bags_ordered{$bag_name}-{quantity} = $bag_quantity[$n];
$n++;
}
## I don't think '-' really needed
# will the order be correct, don think so!
Prices amounts with out '$' #
%prices = (
'bag-style-dots' = 12,
'bag-style-dogs' =5,
'bag-style-cats' =44,
'bag-style-leather' =15,
'bag-style-fur' =23,
'bag-style-stripes' =12,
'bag-style1' =14,
'bag-style2' =6,
'bag-style3' =51,
);
#
#%bags_ordered = (
#bag-style1 = { price = 10,
# image_name = 'FIO-142b-small',
#quantity= 5
# },
#
#bag-style2 = { price = 12,
# image_name = 'GUC-208-small',
# quantity= 5,
# },
#
#);
print header;
# print HTML
print START_HTML;
!DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.01 Transitional//EN
http://www.w3.org/TR/1999/REC-html401-19991224/loose.dtd;
html lang=en
head
titleCatalog/title
style type=text/css media=all
!--
[EMAIL PROTECTED] ../paul_s/css/list.css;
--
/style
style type=text/css media=screen
!--
#catalog td {text-align:center; }
--
/style
link rel=stylesheet href=/paul_s/css/main.css type=text/css
/head
body bgcolor=white text=black
img src=../paul_s/images/banner.jpg alt= tmp banner width=720 height=76
border=1
h1 align=centerComplete your order/h1
pmore text on how complete your order../p
START_HTML
[EMAIL PROTECTED] = param();
#foreach my $name (@test){
#my $val = param($name);
# print qq|p\$name $name \$val $val/p\n|;
# }
print Dumper \%bags_ordered;
print hr noshade\n;
print qq|table border=1 width=600\ntr\n|;
print qq|th colspan=2Description/ththQuantity/ththPrice/th\n|;
print /tr\n;
foreach my $bag (keys %bags_ordered){
print tr\n;
print qq|tdimg src=../paul_s/images/| . $bags_ordered{$bag}{image_name} .
qq|.jpg alt=$imgName width=120 height=179 alt= bag /td\n|;
print td$bag/td;
print td$bags_ordered{$bag}{quantity}/tdtd\$$prices{$bag}/td\n;
print /tr\n;
}
print trtdnbsp;/tdtdsubtotal/td\n;
print trtdnbsp;/tdtd fill in /td\n;
print /table\n;
#print ORDER_HTML;
#ORDER_HTML
# print end html tags
print end_html;
# print start_form( -method = 'post' , -action =finnish-not done.pl);
exit;
==
Cora Connection: Your West African Music Source
Resources, Recordings, Instruments More!
http://www.coraconnection.com/
==
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Re: STILL NEEW SOME HELP: Using data structures to find similarities and differences
Aimal Pashtoonmal wrote: Hello, I have three files, for two different cites. The first file contains names of men with their faves, in columns. The second file is the same but for their partner. The third file is a list of similar partners (partner selection based on data fed into a perl script): FILE_1 and FILE_2 column headings: NAMEtabAGEtabFAVE MOVIEtabFAVE ACTOR(IN THAT MOVIE)tabCHOICE OF NICK NAME(FOR THAT ACTOR)tabGUESS LENGTH OF ACTING CAREER(STARTtabEND)tabFAVE HOL DESTN. FILE_1 data: DAVEtab36tabBATMANtabJ.NICKELSONtabWALL FILLER FACEtab38tab2003tabIBIZA FILE_2 data: JOtab28tabGIJANEtabD.MOOREtabTRACEYtab89tab2003tabIBIZA FILE_3 data: DAVEtabJO EG. OF TYPE OF DATA I INTEND TO EXTRACT: for each set of partners i am trying count the number of times the holiday desnn. is the same and different; for each person in file 1, how many times does the seclected partner choose the same actor, and then find the averaage length of career. The problem I have is since I am not well versed with perl, which data structure do I use, I am not finding this easy. CAN ANYONE HELP PLEASE? All I need is to be pointed in the right direction. ALL WILL BE APPRECIATED. Cheers, aim. Hi Aimal, Can you post any of what you have tried to do to sort out the issues here. Choosing appropriate data structures actually comes in a later part of the process, after you have decided what you want to do with the information in general terms. If you wish to program, you must take responsibility for examining the data, and planning a strategy for how to use it. No one else can do that for you. I can give you a couple hints: The first line of the two data files contains meta-information. You will want to handle this separately, and use the information contained there to set up the structure to hold the actual data. This might suggest a hash as the overall structure, using the column names as keys. Anyway, try to make at least some start on this on your own, and you will find more help here. Joseph -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: STILL NEEW SOME HELP: Using data structures to find similarities and differences
Hello, I have three files, for two different cites. The first file contains names of men with their faves, in columns. The second file is the same but for their partner. The third file is a list of similar partners (partner selection based on data fed into a perl script): FILE_1 and FILE_2 column headings: NAMEtabAGEtabFAVE MOVIEtabFAVE ACTOR(IN THAT MOVIE)tabCHOICE OF NICK NAME(FOR THAT ACTOR)tabGUESS LENGTH OF ACTING CAREER(STARTtabEND)tabFAVE HOL DESTN. FILE_1 data: DAVEtab36tabBATMANtabJ.NICKELSONtabWALL FILLER FACEtab38tab2003tabIBIZA FILE_2 data: JOtab28tabGIJANEtabD.MOOREtabTRACEYtab89tab2003tabIBIZA FILE_3 data: DAVEtabJO EG. OF TYPE OF DATA I INTEND TO EXTRACT: for each set of partners i am trying count the number of times the holiday desnn. is the same and different; for each person in file 1, how many times does the seclected partner choose the same actor, and then find the averaage length of career. The problem I have is since I am not well versed with perl, which data structure do I use, I am not finding this easy. CAN ANYONE HELP PLEASE? All I need is to be pointed in the right direction. ALL WILL BE APPRECIATED. Cheers, aim. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Storing complex Data structures ?
You can also store your complexe data structures in a xml file by using XML::Simple module. http://search.cpan.org/author/GRANTM/XML-Simple-1.08/Simple.pm José. -Original Message- From: Rowan Reid [mailto:[EMAIL PROTECTED]] Sent: Tuesday, September 10, 2002 8:39 PM To: 'Perl beginners' Subject: RE: Storing complex Data structures ? No. You access the data through %COMPANY_DB. That's the whole point of tie(). The object $db is used only if you need to call additional methods of MLDBM on it. You really don't even need to save $db, because you can always get it via: tied(%COMPANY_DB) This is what I did previously, but whenever I closed the data file And tried to re-open it the data could nto be retrieved. I was under The impression that DB-File was able to store referenced data. perldoc -f tie perldoc -f tied perldoc perltie -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] DISCLAIMER This e-mail and any attachment thereto may contain information which is confidential and/or protected by intellectual property rights and are intended for the sole use of the recipient(s) named above. Any use of the information contained herein (including, but not limited to, total or partial reproduction, communication or distribution in any form) by other persons than the designated recipient(s) is prohibited. If you have received this e-mail in error, please notify the sender either by telephone or by e-mail and delete the material from any computer. Thank you for your cooperation. For further information about Proximus mobile phone services please see our website at http://www.proximus.be or refer to any Proximus agent. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Storing complex Data structures ?
What is the correct way to access and store complex data structures to a file. I.e. hashes with several references. The method I have been using is as follows tie (%COMPANY_DB,'MLDBM','studio3.db',O_RDWR|O_CREAT,0777,$DB_BTREE) || die $!; Also DB_File. I'm realizing from previous help that I have to access this as an Object as in $db = tie (%COMPANY_DB,'MLDBM','studio3.db',O_RDWR|O_CREAT,0777,$DB_BTREE) || die $!; Where in my %COMPANY_DB %COMPANY_DB -@employee -n - %info name='name' address =@address And so forth what would be the correct way to access contents of the data structure using the object $db ? Thanks in advance. Rowan Reid Job Captain, Systems Administrator STUDIO 3 ARCHITECTS 909 982 1717 -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Storing complex Data structures ?
On Tue, Sep 10, 2002 at 11:17:33AM -0700, Rowan Reid wrote: What is the correct way to access and store complex data structures to a file. I.e. hashes with several references. This is Perl. There is no correct way. But you could take a look at Data::Dumper and Storable for other solutions. You might also like to investigate YAML. -- Paul Johnson - [EMAIL PROTECTED] http://www.pjcj.net -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Storing complex Data structures ?
-Original Message- From: Rowan Reid [mailto:[EMAIL PROTECTED]] Sent: Tuesday, September 10, 2002 2:18 PM To: 'Perl beginners' Subject: Storing complex Data structures ? What is the correct way to access and store complex data structures to a file. I.e. hashes with several references. The method I have been using is as follows tie (%COMPANY_DB,'MLDBM','studio3.db',O_RDWR|O_CREAT,0777,$DB_BTREE) || die $!; Also DB_File. I'm realizing from previous help that I have to access this as an Object as in $db = tie (%COMPANY_DB,'MLDBM','studio3.db',O_RDWR|O_CREAT,0777,$DB_BTRE E) || die $!; Where in my %COMPANY_DB %COMPANY_DB -@employee -n - %info name='name' address =@address And so forth what would be the correct way to access contents of the data structure using the object $db ? No. You access the data through %COMPANY_DB. That's the whole point of tie(). The object $db is used only if you need to call additional methods of MLDBM on it. You really don't even need to save $db, because you can always get it via: tied(%COMPANY_DB) perldoc -f tie perldoc -f tied perldoc perltie -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Storing complex Data structures ?
No. You access the data through %COMPANY_DB. That's the whole point of tie(). The object $db is used only if you need to call additional methods of MLDBM on it. You really don't even need to save $db, because you can always get it via: tied(%COMPANY_DB) This is what I did previously, but whenever I closed the data file And tried to re-open it the data could nto be retrieved. I was under The impression that DB-File was able to store referenced data. perldoc -f tie perldoc -f tied perldoc perltie -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: undef of nested data structures
-Original Message- From: Nikola Janceski [mailto:[EMAIL PROTECTED]] Sent: Thursday, August 15, 2002 12:44 PM To: Beginners (E-mail) Subject: undef of nested data structures I am wondering how undef works. perldoc -f undef I know that undef will undefine a variable if used like undef($scalar); Yes. I also know that it doesn't actually free up the memory but tells Perl that it's now available to be recycled for other data. Well, you probably should't worry about memory allocation details. Perl takes care of all those details behind the scenes. but what about nested data (ie. hashes of hashes, arrays of arrays, etc.). if $ref is a reference to a nested structure (let's say a hash of hashes). will - undef $ref; - undefine the enitre nested data structure if no other variables contain references to any part of it? (assuming no cyclical references) undef($ref) undefines the scalar $ref. Now, if whatever $ref was pointing to had no other references to it, then yes, that data would be freed. But this is a side effect of the undef(), not something special about undef() itself. The same thing would happen if you assigned foo to $ref, so that $ref no longer contained a reference to some data. Data is freed when the last reference to it is removed. You can think of undef like this: undef($scalar); is the same as: $scalar = undef; undef(@array); is the same as: @array = (); undef(%hash); is the same as: %hash = (); -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: undef of nested data structures
From: Nikola Janceski [EMAIL PROTECTED] I am wondering how undef works. I know that undef will undefine a variable if used like undef($scalar); I also know that it doesn't actually free up the memory but tells Perl that it's now available to be recycled for other data. but what about nested data (ie. hashes of hashes, arrays of arrays, etc.). if $ref is a reference to a nested structure (let's say a hash of hashes). will - undef $ref; - undefine the enitre nested data structure if no other variables contain references to any part of it? (assuming no cyclical references) Perl as usual does what you need. If there are no cyclic references the whole structure will be garbage collected (freed) and the memory will be reused. To create even cyclic references that may be garbage collected use the weakref() function from Scalar::Util. I'm not feeling like explaining garbage collection (I know how it works, but would screw the explanation.) so please try to find something on reference counting garbage collection. Jenda === [EMAIL PROTECTED] == http://Jenda.Krynicky.cz == There is a reason for living. There must be. I've seen it somewhere. It's just that in the mess on my table ... and in my brain I can't find it. --- me -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: undef of nested data structures
As a side note, you can play around with Devel::Peek to see how many things are referencing a variable. # perl -MDevel::Peek -e '$foo=foo;$bar=\$foo;$zog=\$foo;Dump($foo);$bar=bar;Dump($foo);print $foo;'; SV = PV(0x80f2424) at 0x810b3cc REFCNT = 3 FLAGS = (POK,pPOK) PV = 0x80f10a0 foo\0 CUR = 3 LEN = 4 SV = PV(0x80f2424) at 0x810b3cc REFCNT = 2 FLAGS = (POK,pPOK) PV = 0x80f10a0 foo\0 CUR = 3 LEN = 4 foo There, you can see $foo has a REFCNT (ref count) of 3 ($foo, $bar and $zog), then a REFCNT of 2 after the value of $bar is re-assigned. Of course, the value in $foo is still 'foo'; # perl -MDevel::Peek -e '$foo=foo;$bar=\$foo;$zog=\$foo;Dump($foo);$$bar=bar;Dump($foo);print $foo;'; SV = PV(0x80f2424) at 0x810b3cc REFCNT = 3 FLAGS = (POK,pPOK) PV = 0x80f10a0 foo\0 CUR = 3 LEN = 4 SV = PV(0x80f2424) at 0x810b3cc REFCNT = 3 FLAGS = (POK,pPOK) PV = 0x80f10a0 bar\0 CUR = 3 LEN = 4 bar Here, the REFCNT, as expected, stays the same. And the value in $foo is changed. If you are within code and want to make sure you don't undef things which have refs to it, you can use: # perl -MDevel::Peek=SvREFCNT -e \ '$foo=foo;$bar=\$foo;$zog=\$foo;print SvREFCNT($foo);'; 3 Which will tell you how many refs there are. Of course, if it is 1, then nothing else should be referencing $foo aside $foo. This doesn't answer the question in any way, but thought some may be interested in this side-note. Cheers, Kevin On Thu, Aug 15, 2002 at 01:52:23PM -0400, Bob Showalter ([EMAIL PROTECTED]) said something similar to: -Original Message- From: Nikola Janceski [mailto:[EMAIL PROTECTED]] Sent: Thursday, August 15, 2002 12:44 PM To: Beginners (E-mail) Subject: undef of nested data structures I am wondering how undef works. perldoc -f undef I know that undef will undefine a variable if used like undef($scalar); Yes. I also know that it doesn't actually free up the memory but tells Perl that it's now available to be recycled for other data. Well, you probably should't worry about memory allocation details. Perl takes care of all those details behind the scenes. but what about nested data (ie. hashes of hashes, arrays of arrays, etc.). if $ref is a reference to a nested structure (let's say a hash of hashes). will - undef $ref; - undefine the enitre nested data structure if no other variables contain references to any part of it? (assuming no cyclical references) undef($ref) undefines the scalar $ref. Now, if whatever $ref was pointing to had no other references to it, then yes, that data would be freed. But this is a side effect of the undef(), not something special about undef() itself. The same thing would happen if you assigned foo to $ref, so that $ref no longer contained a reference to some data. Data is freed when the last reference to it is removed. You can think of undef like this: undef($scalar); is the same as: $scalar = undef; undef(@array); is the same as: @array = (); undef(%hash); is the same as: %hash = (); -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- [Writing CGI Applications with Perl - http://perlcgi-book.com] Children are naive -- they trust everyone. School is bad enough, but, if you put a child anywhere in the vicinity of a church, you're asking for trouble. -- Frank Zappa -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
newbie: data structures
How would I store (and access) a table of information...assuming there is a unique key 'email'...ie - These are the column names: email firstName lastName phone address1 [EMAIL PROTECTED] Joe Blow 415-555- 123 Mayberry [EMAIL PROTECTED] John Doe 619-555-5551 456 Happy Ln. etc...etc... (also some of the fields will be null from time to time). __ Do You Yahoo!? Yahoo! Health - Feel better, live better http://health.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: newbie: data structures
This is a very broad question, so giving a specific answer is difficult to say the least, but since no one else has responded I will provide at least this much You are going to want to be looking at using a hash of hashes essentially you create a hash where each key is the email address (which you will be looking up on) and the value associated with that key is itself a hash. Here is one place to start: http://www.wdvl.com/Authoring/Languages/Perl/PerlfortheWeb/hash_of_hashes.html Or there are examples of these types of structures in the Camel, Advanced Perl Programming, and possibly the other perl related O'Reilly books. Good luck. http://danconia.org Anthony E. wrote: How would I store (and access) a table of information...assuming there is a unique key 'email'...ie - These are the column names: email firstName lastName phone address1 [EMAIL PROTECTED] Joe Blow 415-555- 123 Mayberry [EMAIL PROTECTED] John Doe 619-555-5551 456 Happy Ln. etc...etc... (also some of the fields will be null from time to time). __ Do You Yahoo!? Yahoo! Health - Feel better, live better http://health.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: newbie: data structures
ur mail title says data structure but ur problem doe not seem to be of the nature. please be a little more clear. store and retreive, there are as many options as u want. what do u exactly r lookign for??? regards vicki On Wed, 24 Jul 2002 Anthony E. wrote : How would I store (and access) a table of information...assuming there is a unique key 'email'...ie - These are the column names: email firstName lastName phone address1 [EMAIL PROTECTED] Joe Blow 415-555- 123 Mayberry [EMAIL PROTECTED] John Doe 619-555-5551 456 Happy Ln. etc...etc... (also some of the fields will be null from time to time). __ Do You Yahoo!? Yahoo! Health - Feel better, live better http://health.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:32 AM To: [EMAIL PROTECTED] Subject: combining data structures into one array I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); $stats and $totals are reference to arrays of arrays. $loads is just a ref to an array. what i want to do is is combine each record of each array into one. here is how the structures look: $stats - @array - [user, cpu, mem] $totals - @array - [tot_cpu, tot_mem] $loads - [load1, load2] so i would like to itereate through the records of each of these arrays and end up with @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] [ ..another record...] [ ..another record...] ...etc I have tried a few things, but no luck. Thanks Jim -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
Oops..your Requirements was different.. To achieve, @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] you need to do push (@$stats, @$totals, $loads); I am assuming User, cpu, mem, tot_cpu, tot_mem are again reference to an array Cheers Shihir -Original Message- From: Shishir K. Singh Sent: Tuesday, June 18, 2002 10:55 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:32 AM To: [EMAIL PROTECTED] Subject: combining data structures into one array I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); $stats and $totals are reference to arrays of arrays. $loads is just a ref to an array. what i want to do is is combine each record of each array into one. here is how the structures look: $stats - @array - [user, cpu, mem] $totals - @array - [tot_cpu, tot_mem] $loads - [load1, load2] so i would like to itereate through the records of each of these arrays and end up with @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] [ ..another record...] [ ..another record...] ...etc I have tried a few things, but no luck. Thanks Jim -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
this won't work, will just push one array onto another. thanks -Original Message- From: Shishir K. Singh [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:55 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
-Original Message-
From: Kipp, James [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 18, 2002 10:32 AM
To: [EMAIL PROTECTED]
Subject: combining data structures into one array
I have a subroutine that returns 3 array refs. so i have:
my ($stats, $totals, $loads) = gets_stats();
$stats and $totals are reference to arrays of arrays. $loads
is just a ref
to an array. what i want to do is is combine each record of
each array
into one. here is how the structures look:
$stats - @array - [user, cpu, mem]
$totals - @array - [tot_cpu, tot_mem]
$loads - [load1, load2]
so i would like to itereate through the records of each of
these arrays and
end up with
@stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2]
[ ..another record...]
[ ..another record...] ...etc
I have tried a few things, but no luck
Is there a correspondence between stats and totals, such that the
nth entry in stats matches the nth entry in totals? If so,
you would want to say something like:
push @{$stats-[$_]}, @{$totals-[$_]}, @$loads
for 0 .. $#$stats;
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RE: combining data structures into one array
I am assuming User, cpu, mem, tot_cpu, tot_mem are again reference to an array woops let me clarify. $stats is a ref to an array of anon arrays. so '$stats-[0]' contains a record lie [someuser, 5.5, 10.2] same goes for $totals $loads just refs a single anon array: $loads = [load1, load2] thanks Cheers Shihir -Original Message- From: Shishir K. Singh Sent: Tuesday, June 18, 2002 10:55 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:32 AM To: [EMAIL PROTECTED] Subject: combining data structures into one array I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); $stats and $totals are reference to arrays of arrays. $loads is just a ref to an array. what i want to do is is combine each record of each array into one. here is how the structures look: $stats - @array - [user, cpu, mem] $totals - @array - [tot_cpu, tot_mem] $loads - [load1, load2] so i would like to itereate through the records of each of these arrays and end up with @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] [ ..another record...] [ ..another record...] ...etc I have tried a few things, but no luck. Thanks Jim -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
Do you mean to say push (@$stats, @$totals, $loads); didn't work ?? -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 11:23 AM To: Shishir K. Singh; Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array I am assuming User, cpu, mem, tot_cpu, tot_mem are again reference to an array woops let me clarify. $stats is a ref to an array of anon arrays. so '$stats-[0]' contains a record lie [someuser, 5.5, 10.2] same goes for $totals $loads just refs a single anon array: $loads = [load1, load2] thanks Cheers Shihir -Original Message- From: Shishir K. Singh Sent: Tuesday, June 18, 2002 10:55 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:32 AM To: [EMAIL PROTECTED] Subject: combining data structures into one array I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); $stats and $totals are reference to arrays of arrays. $loads is just a ref to an array. what i want to do is is combine each record of each array into one. here is how the structures look: $stats - @array - [user, cpu, mem] $totals - @array - [tot_cpu, tot_mem] $loads - [load1, load2] so i would like to itereate through the records of each of these arrays and end up with @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] [ ..another record...] [ ..another record...] ...etc I have tried a few things, but no luck. Thanks Jim -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
push (@$stats, @$totals, $loads); didn't work ?? haven't tried yet. get back to you in a bit thanks again -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
Is there a correspondence between stats and totals, such that the
nth entry in stats matches the nth entry in totals? If so,
you would want to say something like:
push @{$stats-[$_]}, @{$totals-[$_]}, @$loads
for 0 .. $#$stats;
no, there is not. i just want to combine the records pointed to by each
array into one record (in a new array of records). going to try Shihir's
suggestion in a few minutes.
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RE: combining data structures into one array
-Original Message-
From: Kipp, James [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 18, 2002 11:46 AM
To: [EMAIL PROTECTED]
Subject: RE: combining data structures into one array
Is there a correspondence between stats and totals, such that the
nth entry in stats matches the nth entry in totals? If so,
you would want to say something like:
push @{$stats-[$_]}, @{$totals-[$_]}, @$loads
for 0 .. $#$stats;
no, there is not. i just want to combine the records pointed
to by each
array into one record (in a new array of records).
Well then, I can't figure out how you plan to combine the data.
How about an example with some real data?
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RE: combining data structures into one array
Shishir and Bob, still can't get it to work. also decided we can leave out $loads, so basically i want to combine $stats and $totals. as bob suggested, here is sample data: ($stats, $totals, $loads) = gets_stats(); when the get_stats() func is called $stats will contain something like this: $stats = [ [ oracle, 6.8, 11.2 ], [ ksh, 1.8, 1.2 ], etc ]; and $totals will have something like: $totals = [ [ 15.8, 17.2 ], [ 3.7, 3.9 ], etc ]; so i want to end up with something like: @stats = ( [oracle, 6.8, 11.2,15.8, 17.2 ], [ksh, 1.8, 1.2, 3.7, 3.9 ], etc... ); thanks. -Original Message- From: Shishir K. Singh [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 11:04 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array Oops..your Requirements was different.. To achieve, @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] you need to do push (@$stats, @$totals, $loads); I am assuming User, cpu, mem, tot_cpu, tot_mem are again reference to an array Cheers Shihir -Original Message- From: Shishir K. Singh Sent: Tuesday, June 18, 2002 10:55 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:32 AM To: [EMAIL PROTECTED] Subject: combining data structures into one array I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); $stats and $totals are reference to arrays of arrays. $loads is just a ref to an array. what i want to do is is combine each record of each array into one. here is how the structures look: $stats - @array - [user, cpu, mem] $totals - @array - [tot_cpu, tot_mem] $loads - [load1, load2] so i would like to itereate through the records of each of these arrays and end up with @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] [ ..another record...] [ ..another record...] ...etc I have tried a few things, but no luck. Thanks Jim -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: combining data structures into one array
Hello Jim,
how about something along these lines:
for(0..$#{$stats}) { push @stats, $stats-[$_],$totals-[$_]; }
Shawn
- Original Message -
From: Kipp, James [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, June 18, 2002 11:40 AM
Subject: RE: combining data structures into one array
Shishir and Bob,
still can't get it to work. also decided we can leave out $loads, so
basically i want to combine $stats and $totals. as bob suggested, here is
sample data:
($stats, $totals, $loads) = gets_stats();
when the get_stats() func is called $stats will contain something like this:
$stats = [
[ oracle, 6.8, 11.2 ],
[ ksh, 1.8, 1.2 ],
etc
];
and $totals will have something like:
$totals = [
[ 15.8, 17.2 ],
[ 3.7, 3.9 ],
etc
];
so i want to end up with something like:
@stats = (
[oracle, 6.8, 11.2,15.8, 17.2 ],
[ksh, 1.8, 1.2, 3.7, 3.9 ],
etc...
);
thanks.
-Original Message-
From: Shishir K. Singh [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 18, 2002 11:04 AM
To: Kipp, James; [EMAIL PROTECTED]
Subject: RE: combining data structures into one array
Oops..your Requirements was different..
To achieve, @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2]
you need to do
push (@$stats, @$totals, $loads);
I am assuming User, cpu, mem, tot_cpu, tot_mem are again
reference to an array
Cheers
Shihir
-Original Message-
From: Shishir K. Singh
Sent: Tuesday, June 18, 2002 10:55 AM
To: Kipp, James; [EMAIL PROTECTED]
Subject: RE: combining data structures into one array
push (@myVar, @$_) for @$stats;
push (@myVar, @$_) for @$totals;
push (@myVar, $_) for @$loads;
-Original Message-
From: Kipp, James [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 18, 2002 10:32 AM
To: [EMAIL PROTECTED]
Subject: combining data structures into one array
I have a subroutine that returns 3 array refs. so i have:
my ($stats, $totals, $loads) = gets_stats();
$stats and $totals are reference to arrays of arrays. $loads
is just a ref
to an array. what i want to do is is combine each record of
each array
into one. here is how the structures look:
$stats - @array - [user, cpu, mem]
$totals - @array - [tot_cpu, tot_mem]
$loads - [load1, load2]
so i would like to itereate through the records of each of
these arrays and
end up with
@stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2]
[ ..another record...]
[ ..another record...] ...etc
I have tried a few things, but no luck.
Thanks
Jim
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Re: combining data structures into one array
On Tuesday, June 18, 2002, at 07:32 , Kipp, James wrote: I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); would it be possible to expose this gets_stats() function - and/or re-think how it deals with generating data... ciao drieux --- -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
Oh Simple...What threw me off is that I though you wanted to use the rest of the arrays in the same format as $stats which is a reference to an anonymous array of anonymous arrays. $stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2]; Now I see that you want something like this @stats = (user, cpu, mem, tot_cpu, tot_mem, load1, load2); You can do this # my @myVars = (); push (@myVars, @$stats, @$totals, $loads); ## -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 12:40 PM To: [EMAIL PROTECTED] Subject: RE: combining data structures into one array Shishir and Bob, still can't get it to work. also decided we can leave out $loads, so basically i want to combine $stats and $totals. as bob suggested, here is sample data: ($stats, $totals, $loads) = gets_stats(); when the get_stats() func is called $stats will contain something like this: $stats = [ [ oracle, 6.8, 11.2 ], [ ksh, 1.8, 1.2 ], etc ]; and $totals will have something like: $totals = [ [ 15.8, 17.2 ], [ 3.7, 3.9 ], etc ]; so i want to end up with something like: @stats = ( [oracle, 6.8, 11.2,15.8, 17.2 ], [ksh, 1.8, 1.2, 3.7, 3.9 ], etc... ); thanks. -Original Message- From: Shishir K. Singh [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 11:04 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array Oops..your Requirements was different.. To achieve, @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] you need to do push (@$stats, @$totals, $loads); I am assuming User, cpu, mem, tot_cpu, tot_mem are again reference to an array Cheers Shihir -Original Message- From: Shishir K. Singh Sent: Tuesday, June 18, 2002 10:55 AM To: Kipp, James; [EMAIL PROTECTED] Subject: RE: combining data structures into one array push (@myVar, @$_) for @$stats; push (@myVar, @$_) for @$totals; push (@myVar, $_) for @$loads; -Original Message- From: Kipp, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 18, 2002 10:32 AM To: [EMAIL PROTECTED] Subject: combining data structures into one array I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); $stats and $totals are reference to arrays of arrays. $loads is just a ref to an array. what i want to do is is combine each record of each array into one. here is how the structures look: $stats - @array - [user, cpu, mem] $totals - @array - [tot_cpu, tot_mem] $loads - [load1, load2] so i would like to itereate through the records of each of these arrays and end up with @stats = [ user, cpu, mem, tot_cpu, tot_mem, load1, load2] [ ..another record...] [ ..another record...] ...etc I have tried a few things, but no luck. Thanks Jim -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: combining data structures into one array
I have a subroutine that returns 3 array refs. so i have: my ($stats, $totals, $loads) = gets_stats(); would it be possible to expose this gets_stats() function - and/or re-think how it deals with generating data... of course, that is what i am doing now :-). -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
