Re: 3.0: a peek into CakePHP's future
The modeling for me as PHP programmer is much more simpler when i can descripe my models in PHP. You also have to decide first which RDBMS you want to use. I think this is a limitation so it is not so easy to switch to another Datastore in development process because the code first approach is not implemented to generate new DB schema. Also i think is it more the right direction to change models on PHP-side and than apply changes automatted to the DB. I worked with both approaches and i feel better with the Doctrine code first way. greets pete by the way i got mail from 139.com in chinese related to this topic. it seems there is a spam bot in mailing list? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Re: 3.0: a peek into CakePHP's future
Doctrine was mentioned sometimes. I also think it would be a great idea to use this ORM for doing all the crazy DB things. There is no need for a self implementation because doctrine works very well by now. I like the code first approach in doctrine and i'm really missing this in cakephp to write the model and generate the database. Doctrine has also options to generate migration files for differences in database tables and models during the development process. I mean this features should bbe used in future. greets pete -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
Re: Welcome Page not finding CSS/Images
I had this same issue. This fix worked! Thank you. On Wednesday, September 2, 2009 6:20:21 PM UTC-4, ajoberstar wrote: So I finally gave up trying to find the error and re-extracted the files from the tar.bz2 I downloaded from Cakeforge. I saw that that worked before changing anything, but the only thing different between my broken install and this was the database.php config file. So I added that again to see what happened and voila it broke again. Turns out I had the driver set to mysql instead of mysqli and my PHP install only has the mysqli extension installed it crapped out, but wouldn't tell anything was wrong. So magic fix. Thanks to everyone for their suggestions. On Sep 2, 12:44 pm, Vijay Kumbhar k.vidn...@gmail.com wrote: Hello ajoberstar, Please add Document_root before webroot/ in the .htaccess in the application folder, app folder. It will help you, coz i was facing same problem on my server. When i added the DOCUMENT_ROOT path in the .htaccess befor /webroot it worked fine for me. please do check this. On Tue, Sep 1, 2009 at 6:34 AM, ajoberstar ajobers...@gmail.com wrote: I did an install of CakePHP on my local device (Windows XP) with an Apache server. I did the install to the letter as far as I can tell (removed comment in front of mod_rewrite's load module statement), but I'm getting a welcome page with no layout. And it seems like the whole page isn't even showing up. The thing that bugs me the most is that I uploaded the same exact files up to my bluehost account and got the right welcome page. So it's got to be something with my server setup but I can't figure it out. Any help would be much appreciated. This is all that showed up in the page source: h2Release Notes for CakePHP 1.2.4.8284./h2 a href=https://trac.cakephp.org/wiki/changelog/1.2.x.x;Read the changelog /a p span class=notice successYour tmp directory is writable./span/ p p span class=notice successThe emFileEngine/em is being used for caching. To change the config edit APP/config/core.php /span/ p p span class=notice successYour database configuration file is present./span/p -- Thanks Regards, Vijayk. Co-founder (www.weboniselab.com) You Bring the Dreams, We'll Bring the Means -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Sorting by a (second level) associated model using paginate helper
Dear all,
I suspect this is either really easy or very hard. I've been through
endless apparently similar questions on here but haven't been able to
figure out the answer.
I have a Quote model, which I am trying to list in a view. Quote
belongsTo Attendance which belongs to Person. I am trying to sort the
list of quotes by the first_name field in the Person model.
The array being sent to the view is
Array
(
[0] = Array
(
[Quote] = Array
(
[id] = 1
[attendance_id] = 15
[quote_text] = Hello
)
[Attendance] = Array
(
[id] = 15
[person_id] = 2
[trip_id] = 7
[Person] = Array
(
[id] = 2
[first_name] = John
[last_name] = Smith
)
)
)
}
This seems to work fine, and in the view, I can echo out
foreach ($quotes as $quote) {
echo $quote['Attendance']['Person']['first_name'];
}
without any problem.
What I cannot get to work is accessing/using the same variable as a
sort field in paginate
echo $this-Paginator-sort('Name',
'Attendance.Person.first_name');
or
echo $this-Paginator-sort('Location',
'Attendance.Trip.location');
Does not work. It appears to sort by something, but I'm not sure what.
Am I using the correct syntax?. Is there something I should be doing
in a model or controller to make this work?
Thanks in advance.
Peter
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HABTM Relationships Problem
Hi all,
I'm having some problems with saving HABTM relationships, and I was hoping
you could help me. The two models in question are Registrant and Product.
In my Registrant model, I have a method that builds an array that looks like
this:
Array
(
[Registrant] = Array
(
[id] = 133
)
[Product] = Array
(
[0] = Array
(
[product_id] = 1
[quantity] = 5
[cost] = 25.00
)
[1] = Array
(
[product_id] = 2
[quantity] = 1
[cost] = 8.50
[option_id] = 13
)
[2] = Array
(
[product_id] = 2
[quantity] = 9
[cost] = 76.50
[option_id] = 14
)
[3] = Array
(
[product_id] = 2
[quantity] = 3
[cost] = 25.50
[option_id] = 15
)
)
)
When I try using $this-saveAll($array) it does nothing, and when I
try using $this-Product-saveAll($array), this is the SQL it runs:
44START TRANSACTION0045SELECT `ProductsRegistrant`.`registrant_id`
FROM `products_registrants` AS `ProductsRegistrant` WHERE
`ProductsRegistrant`.`product_id` = ''11046DELETE `ProductsRegistrant`
FROM `products_registrants` AS `ProductsRegistrant` WHERE
`ProductsRegistrant`.`product_id` = '' AND
`ProductsRegistrant`.`registrant_id` = (130)1047INSERT INTO
`products_registrants` (`product_id`,`registrant_id`) VALUES
('','133')1048COMMIT
I've been playing with this for quite a while and I can't figure out
what's wrong. Could someone offer some guidance, please?
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form helper dateTime (cake 1.2)
hi,
is there a way to set the minYear, maxYear for dateTime?
?php echo $form-dateTime('dateTime','DMY',24,null,null); ?
i want to reduce the number of years within the form
thanks
pete
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Re: cakex html inside controller
thanks for all your hints.
as i really like xajax i have already installed Cakex.
the reason why i create this html-code inside the controller is, that
i have a Navigation with Add User which is available on each page.
As soon as i click on it, i render the html code inside div
id=addUser/div
- i want to have only ONE code logic for addUser, thats why i use
innerHTML to add the html code within the addUser-div only if its
necessary.
Should be available for each view:
div id=addUserform.../form/div
- i dont wanna add this div with the form logic inside each view.
- Do you consider using the requestAction and creating a addUser.thml
inside /views/elements?
- Or is it better to create addUser plugin (like the cakex examples)
thanks
pete
On Jun 19, 1:29 am, jitka (poLK) [EMAIL PROTECTED] wrote:
Well, not everything what is possible is automatically right.
My propose is NOT keep any html content in controller - it is work for
view. You're imho looking for
?php echo $cakex-link('Add new item', '/phases/formAdd/',
array('update' = 'add')); ?
BTW: xajax is a great library, but it is aiming to people without php
framework, as it does dispatching, basic sanitize etc. One of reasons
why was CakeX written and published is: take some people from xajax
community to CakePHP world ;)
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cakex html inside controller
hi,
im using cakex (xajax) for my project. i'm just curious if its a good
idea to put html code inside the controller
for example i have a ajax addForm.
Do you think this is a good idea to do it or is it better to have all
html code inside a view.thtml ?
thanks
pete
VIEW
?php echo $cakex-link('Add new item', '/phases/formAdd/'); ?
div id=add/div
CONTROLLER
function formAdd(){
$this-autoRender = false;
$objResponse = $this-Cakex-response;
$objResponse = new xajaxResponse();
$html = '
form method=post name=myform id=myform
table border=1 width=100% class=adminlist
tr
td nowrap align=leftLast Name*/td
td align=leftinput type=text
id=lastname name=lastname
size=25fff/td
/tr
tr
td colspan=2 align=centerbutton
id=submitButton onClick=
\'...\'Continue/button/td
/tr
/table
/form '
$objResponse-assign('add', 'innerHTML',$html);
}
}
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Re: cakex html inside controller
hm..you are right, the thing is i want to have the add-form on the
same page as where i show the data.
is there a way to assign('add') the view.html code?
something like
$objResponse-assign('add', 'innerHTML',$??view.thtml??);
thanks pete
On Jun 18, 8:40 pm, Geoff Ford [EMAIL PROTECTED] wrote:
I wouldn't be doing it
- Breaks MVC putting html in the controller.
- Mixing presentation with business logic is never good
- Harder to update
- DOes not allow for multiple presentation types
On Jun 19, 12:52 pm, pete [EMAIL PROTECTED] wrote:
hi,
im using cakex (xajax) for my project. i'm just curious if its a good
idea to put html code inside the controller
for example i have a ajax addForm.
Do you think this is a good idea to do it or is it better to have all
html code inside a view.thtml ?
thanks
pete
VIEW
?php echo $cakex-link('Add new item', '/phases/formAdd/'); ?
div id=add/div
CONTROLLER
function formAdd(){
$this-autoRender = false;
$objResponse = $this-Cakex-response;
$objResponse = new xajaxResponse();
$html = '
form method=post name=myform id=myform
table border=1 width=100% class=adminlist
tr
td nowrap align=leftLast Name*/td
td align=leftinput type=text
id=lastname name=lastname
size=25fff/td
/tr
tr
td colspan=2 align=centerbutton
id=submitButton onClick=
\'...\'Continue/button/td
/tr
/table
/form '
$objResponse-assign('add', 'innerHTML',$html);
}
}
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Recursion for my own custom query?
I have a function in my model, to get a list of the months that I have
blog entries in:
function getMonths($limit = null)
{
$sql = SELECT DISTINCT month(Entry.date) number,
monthname(Entry.date) title, year(Entry.date) year FROM entries as
Entry ORDER BY date DESC;
if ($limit): $sql .= LIMIT . $limit; endif;
$result = $this-query($sql);
return $result;
}
What would be the best way to then get the Entries that are in those
months. Could I attach the Entries to those month results?
Basically, I'm trying a pretty typical archive by month, and I'm
trying to get an array like:
[0] = Array
(
[Month] = Array
(
[number] = 5
[title] = May
[year] = 2007
)
[Entry] = Array
(
[0] = Array
(
[title] = Blog Post
[date] = May 06, 2007
)
[1] = Array
(
[title] = Blog Post
[date] = May 06, 2007
)
)
)
Any ideas?
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ajax multiple tables, row delete
hi,
i have a very simple ajax example of deleting a row in a table.
everything works fine.
my problem is, what happens if i have more than 1 table (that means i
have for example
TABLE1 with tbody id=user1, TABLE2 with tbody id=user2. the
problem is the user.thtml, i dont know how many tables i have so i
cant create a user.thtml file for each table.
thanks for helping
pete
VIEW
table
thead
tr
thFirstName/th
/tr
/thead
tbody id=user
?php foreach ($users as $user): ?
tr
td?php echo $user['User']['FirstName']; ?/td
td
form onSubmit=return false;
input type=submit value=delete id=remove?php echo
$user['User']['ID']; ? /
/form
script type=text/javascript
Event.observe(remove?php echo $user['User']['ID']; ?,
'click', function(event){ new Ajax.Updater('user','remove/?php echo
$user
['User']['ID']; ?', {asynchronous:true,
evalScripts:true,
parameters:Form.serialize(Event.element(event).form),
requestHeaders:['X-Update', 'user']}) },
false);
/script
/td
/tr
?php endforeach; ?
/tbody
/table
CONTROLLER
function remove($id)
{
$this-set('users', $this-User-findAll());
$this-render('user', 'ajax');
}
USER.thtml
?php foreach ($users as $user): ?
tr
td?php echo $user['User']['FirstName']; ?/td
td
form onSubmit=return false;
input type=submit value=delete id=remove?php echo
$user['User']['ID']; ? /
/form
script type=text/javascript
Event.observe(remove?php echo $user['User']['ID']; ?,
'click', function(event){ new Ajax.Updater('user','remove/?php echo
$user
['User']['ID']; ?', {asynchronous:true, evalScripts:true,
parameters:Form.serialize(Event.element(event).form),
requestHeaders:['X-Update', 'user']}) }, false);
/script
/td
/tr
?php endforeach; ?
==
2 or more tables
==
?php for($i=0;$i3;$i++) { ?
table
thead
tr
thFirstName/th
/tr
/thead
tbody id=user
?php foreach ($users as $user): ?
tr
td?php echo $user['User']['FirstName']; ?/td
td
form onSubmit=return false;
input type=submit value=delete id=remove?php echo
$user['User']['ID']; ? /
/form
script type=text/javascript
Event.observe(remove?php echo $user['User']['ID']; ?,
'click', function(event){ new Ajax.Updater('user','remove/?php echo
$user
['User']['ID']; ?', {asynchronous:true,
evalScripts:true,
parameters:Form.serialize(Event.element(event).form),
requestHeaders:['X-Update', 'user']}) },
false);
/script
/td
/tr
?php endforeach; ?
/tbody
/table
? } ?
CONTROLLER
function remove($id)
{
$this-set('users', $this-User-findAll());
$this-render('user???', 'ajax');
}
user.thtml ?
?php foreach ($users as $user): ?
tr
td?php echo $user['User']['FirstName']; ?/td
td
form onSubmit=return false;
input type=submit value=delete id=remove?php echo
$user['User']['ID']; ? /
/form
script type=text/javascript
Event.observe(remove?php echo $user['User']['ID']; ?,
'click', function(event){ new Ajax.Updater('user','remove/?php echo
$user
['User']['ID']; ?', {asynchronous:true, evalScripts:true,
parameters:Form.serialize(Event.element(event).form),
requestHeaders:['X-Update', 'user']}) }, false);
/script
/td
/tr
?php endforeach; ?
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Re: selectTag
thanks for your reply, not as a default value, i just couldnt find out
how it works to set a value as selected
thanks
On May 31, 7:52 pm, metasan [EMAIL PROTECTED] wrote:
hi,
1. i think this error is due to this line :
?php echo $html-selectTag('status_id', $status, null, array(),
null, false, false); ?
try to replace fieldname with Modelname/fieldname.
2. do you want to select delivered as a default value ?
On Jun 1, 10:32 am,pete[EMAIL PROTECTED] wrote:
hi,
im trying to add the selectTag. the select field shows up but i get
the following warning:
Notice: Undefined offset: 1 in C:\Apache\xampp\htdocs\cake\cake\libs
\view\helpers\html.php on line 950
?php echo $html-selectTag('status_id', $status, null, array(),
null, false, false); ?
select name=data[status_id][] id=status_id
option value=3 Declined/option
option value=6 Deleted/option
option value=4 Delivered/option
option value=1 Inquiring/option
option value=5 Invoiced/option
option value=7 Open/option
option value=2 Qualifying/option
/select
1. has anyone an idea why i get the notice?
2. how can i set Delivered as SELECTED ?
thank you
pete
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selectTag
hi,
im trying to add the selectTag. the select field shows up but i get
the following warning:
Notice: Undefined offset: 1 in C:\Apache\xampp\htdocs\cake\cake\libs
\view\helpers\html.php on line 950
?php echo $html-selectTag('status_id', $status, null, array(),
null, false, false); ?
select name=data[status_id][] id=status_id
option value=3 Declined/option
option value=6 Deleted/option
option value=4 Delivered/option
option value=1 Inquiring/option
option value=5 Invoiced/option
option value=7 Open/option
option value=2 Qualifying/option
/select
1. has anyone an idea why i get the notice?
2. how can i set Delivered as SELECTED ?
thank you
pete
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simple relation
hi,
i still play around with creating a simple relation, and i don't get
it to run.
thanks
pete
TABLES:
status
id
description
project
id
status_id
project_title
CONTROLLER
$this-set('projects', $this-Project-findAll());
every project has one status.
how do i create a relation between these 2 tables so i can print the
status.description and not only the status.id
VIEW
project_title: Test
status: Open ??
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hasOne Problem
hi,
i have problems using hasOne
basically i want to achieve: a project hasOne status
TABLES
projects
id
title
status_id
statuses
id
title
class Project extends AppModel
{
var $name='Project';
var $hasOne = array('Status' =
array('className' = 'Status',
'conditions' = '',
'order' = '',
'foreignKey' = 'status_id'));
}
CONTROLLER
$this-('projects', $this-Project-findAll());
VIEW
when i print out the array
...[Status]=Array([id]=[title]))
}
the array is empty and i dont get the status title
anyone has a hint how that could work correctly?
thanks
pete
Status is empty.
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Re: hasOne Problem
hm.. i want to print out all projects and instead of the project.status_id, i want to show the status.title how could i do that? thanks pete On May 23, 5:29 pm, John David Anderson (_psychic_) [EMAIL PROTECTED] wrote: On May 23, 2007, at 3:21 PM, pete wrote: hi, i have problems using hasOne basically i want to achieve: a project hasOne status TABLES projects id title status_id statuses id title The way you have things keyed here, its actually Status hasOne Project (and Project belongsTo Status). -- John --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
ajax inline edit
hi,
i already tested the Ajax cakephp ToDo example and it works great. now
try to do the same thing in my own project
the problem is, it works fine for one resource, i created a view
called resource_1 and the ajax works,
how do i do that i have more than one div? i cant create for each
resource_X div a view...
thanks for helping
Pete
VIEW (view.thtml)
div id=resource_? echo $i; ??php echo $resource; ?/div
? print $ajax-editor('resource_'.$i,'/projects/update/'.$i); ?
UPDATE (view update.thtml)
? echo new text; ?
CONTROLLER; //
function update()
{
$this-render('resource_1', 'ajax');
}
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ajax div update
hi,
can anyone tell me why updating 2 divs with ajax-link works, but not
with ajax-editor.
basically i want to enter a value for resource_8 and then calculate a
new value for resource_9
thanks
pete
View
?=$ajax-div(resource_8); ??=$ajax-divEnd(resource_8); ?
?=$ajax-div(resource_9); ??=$ajax-divEnd(resource_9); ?
?
//WORKING
php echo $ajax-link('Link', '/myproject/update/8', array('update' =
array('resource_8', 'resource_9'))); ?
?php
//NOT WORKING
echo $ajax-editor('resource_8', '/myproject/update/8', array('update'
= array('resource_8', 'resource_9'))); ?
CONTROLLER
function update()
{
$this-set('value8', $_POST['value']);
$this-set('value9', $_POST['value']+1);
$this-layout = ajax;
}
UPDATE VIEW
?php echo $ajax-div('resource_8'); ?
?php echo $value8; ?
?php echo $ajax-divEnd('resource_8'); ?
?php echo $ajax-div('resource_9); ?
?php echo $value9; ?
?php echo $ajax-divEnd('resource_9'); ?
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ajax adding table row
hi,
i downloaded and tested the ajax example from http://demo.grahambird.co.uk/tasks
everything works fine. now im trying to do the same with a table.
after clicking on 'Add task' a new row should be added to the table.
could anyone help me out? it works fine with divs but not with a table
thanks
pete
CONTROLLER
var $helpers = array('Html','Javascript','Ajax','Form');
function add()
{
$this-Project-saveProject();
$this-set('data', $this-Project-findAll());
$this-render('todo', 'ajax');
}
VIEW
div id=add_task
form onSubmit=return false;
?php
print $html-input('Task/title', array('id' = 'add_input'));
print $ajax-submit('Add task', array('url' = 'add',
'update'='tasks_todo'));
?
/form
/div
table border=1 width=100%
?
foreach ($data as $row)
{
$item = $row['Project'];
?
tr
td? echo $item['ProjectTitle']; ?/td
/tr
?
}
?
/table
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phpThumb caching
I was able to get phpThumb working from the Bakery script here: http://bakery.cakephp.org/articles/view/82, but caching doesn't work. Permissions are 777 for the /cache/thumbs folder. I can't seem to get a decent error message from this line: $phpThumb-RenderToFile($phpThumb-cache_filename); Does anyone else have any insight into either why it's not working, or how to debug it? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
