please see
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Re: Get just one object id at the time in view assignment issue.
I feel I'm getting close to an answer... I hope you guys can help me out... I get this TypeError: Records() takes exactly 3 non-keyword arguments (2 given) def Records (request, UserName, Name): gamer = Artist.objects.get(UserName=UserName) record = Record.objects.get(Name=Name) tags = Tag.objects.get_for_object(record) try: records = artist.record_set.all() except Record.DoesNotExist: records = None ... Thanx in advance! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: In qryset refactor did output of following change?
adding to it.
earlier I could do unassigned_contacts.count()
now I get error "Cannot add count col with multiple cols in 'select'"
On May 16, 8:15 pm, ydjango <[EMAIL PROTECTED]> wrote:
> In qryset refactor branch would the output of following changed?
>
> unassigned_contacts = Contacts.values('id','last_name',
> 'first_name').filter(group__exact=my_group).exclude(pk__in=assignedparts)
>
> where assignedpart=[] and then loaded before the the above statement
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ability to show intermediate results before final response
Hi, How do i make my django app to show intermediate results/ steps before showing the final response. My script inherently takes a lot of time. I was wondering if there is a way to engage the user by showing partial intermediate results before showing the final response. thanks, Ravi. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
In qryset refactor did output of following change?
In qryset refactor branch would the output of following changed?
unassigned_contacts = Contacts.values('id','last_name',
'first_name').filter(group__exact=my_group).exclude(pk__in=assignedparts)
where assignedpart=[] and then loaded before the the above statement
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Re: how to avoid uploading .py source files to shared hosting server
Hahahaha, thats good friday night humor. I look forward to reading your upcoming book. Hopefully it has the same humor. On point 7) what about a navy seal who want to retire and start a software business, how do I design a selection system to avoid those. I do not want future competitor snooping around my code. I would have preferred Himalaya, But it is between india and china. Cannot trust those guys either. They are taking away all our jobs and now code too. No way. thanks Ashish On May 16, 11:11 am, "James Bennett" <[EMAIL PROTECTED]> wrote: > On Fri, May 16, 2008 at 11:52 AM, ydjango <[EMAIL PROTECTED]> wrote: > > I do not want to make it easy for some one who breaks in , either a > > outsider or may be an rougue hosting provider employee or contractor, > > to easily get access to all the information - data and code. > > Again: if this is your worry, you have bigger problems. Allow me to > suggest an alternate method: > > (satire begins here, for the humor-impaired) > > 1. Physically obtain the server upon which the code is stored. Write > random data to the relevant sectors of the hard drive seven times > over, then write zeroes to it seven times over, then write random data > again. > > 2. Physically destroy the hard drive. Sledgehammers are good for this. > > 3. Place the shards of the hard drive into a vat of highly caustic acid. > > 4. Once the shards have dissolved, burn the resulting acidic liquid. > Be sure to capture the smoke. > > 5. Cool the smoke until it turns back to ash. Mix the ash into the > center of a reinforced concrete slab, at least 27 cubic feet in > volume. > > 6. If you have access to sufficient technology, launch the concrete > slab into space, on a course to collide with the Sun or (better) with > any singularity which happens to be nearby. The singularity is best > because -- even though it may not guarantee destruction of the > information -- the subjective time to observe the rocket crossing the > event horizon, from the frame of reference of a person some distance > from it, will be effectively infinite, causing most attackers to give > up. > > 7. If you do not have access to sufficient technology, have the > concrete slab stored in a nuclear-hardened bunker, with no Internet > connection, in a room using biometric identification keyed to > yourself, and with the whole complex guarded 24/7 by US Navy SEALs. > Maintain this watch until the technology available to complete step > (6) becomes available to you. > > Once you've completed this process, your application code will be > safe, for a reasonable value of "safe". > > (satire ends here) > > Or you could just find a host who properly sets up file permissions so > that random people can't access your application code. Unless you own > and personally supervise all of the following you will be susceptible > to rogue employees: the server, the rack in which it's located and the > datacenter in which the rack is found. Many people do not find that > the perceived security gains of doing so outweigh the financial and > maintenance drawbacks. YMMV. > > -- > "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: dúvida
* ı 'm to kid someone, kid, joke. * 17 Mayıs 2008 Cumartesi 05:47 tarihinde HILAL AY <[EMAIL PROTECTED]> yazmış: > siz neden aranızda ispanyolca konuşuyorsunuz bakalım ha? > > 2008/4/30 Andrews Medina <[EMAIL PROTECTED]>: > > >> On Wed, Apr 30, 2008 at 8:01 AM, pauloleandro <[EMAIL PROTECTED]> >> wrote: >> > >> > Bom dia, queria saber se o Django só aceita a linguagem Python, se é >> > um framework desenvolido somente para esta linguagem?? >> > >> >> Sim. O Django foi desenvolvido em Python e só é possível utilizar ele >> com Python. >> >> []'s >> -- >> Andrews Medina >> www.andrewsmedina.com >> >> >> >> > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: dúvida
siz neden aranızda ispanyolca konuşuyorsunuz bakalım ha? 2008/4/30 Andrews Medina <[EMAIL PROTECTED]>: > > On Wed, Apr 30, 2008 at 8:01 AM, pauloleandro <[EMAIL PROTECTED]> > wrote: > > > > Bom dia, queria saber se o Django só aceita a linguagem Python, se é > > um framework desenvolido somente para esta linguagem?? > > > > Sim. O Django foi desenvolvido em Python e só é possível utilizar ele > com Python. > > []'s > -- > Andrews Medina > www.andrewsmedina.com > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
How to use a string in filter()
Hi All,
I am back with another query
I have this (generic) view function
--8><
def object_list(request, object, filter_string = None):
if filter_string:
object_list = object.objects.filter(filter_string)
else:
object_list = object.objects.all()
return render_to_response(object.__name__ + '_list.html',
{object.__name__ + '_list': object_list},
RequestContext(request))
--8><
Now this function works when I don't pass on the filter_string, and I
get the entire object list. But when I pass on a value for filter_string
(say 'entity=2') I get this error :
'unicode' object has no attribute 'get_sql'
How do I pass strings to filter_string and get a filtered object list?
Thanks in advance
Ganesh
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django-tagging: How to generate a TagField input form in a template?
This question is related to the django-tagging application. I've added a TagField to my model, and it is working properly from the admin interface. However, I'd like to create a simple tag input field in my templates so users can add tags for a particular model. I don't want to create a form for the entire model, just the tagging. Has anyone had experience with this? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
James Bennett wrote on 05/16/08 20:11: > On Fri, May 16, 2008 at 11:52 AM, ydjango <[EMAIL PROTECTED]> wrote: >> I do not want to make it easy for some one who breaks in , either a >> outsider or may be an rougue hosting provider employee or contractor, >> to easily get access to all the information - data and code. > > Again: if this is your worry, you have bigger problems. Allow me to > suggest an alternate method: > > (satire begins here, for the humor-impaired) > > 1. Physically obtain the server upon which the code is stored. Write > random data to the relevant sectors of the hard drive seven times > over, then write zeroes to it seven times over, then write random data > again. > > 2. Physically destroy the hard drive. Sledgehammers are good for this. > > 3. Place the shards of the hard drive into a vat of highly caustic acid. > > 4. Once the shards have dissolved, burn the resulting acidic liquid. > Be sure to capture the smoke. > > 5. Cool the smoke until it turns back to ash. Mix the ash into the > center of a reinforced concrete slab, at least 27 cubic feet in > volume. > > 6. If you have access to sufficient technology, launch the concrete > slab into space, on a course to collide with the Sun or (better) with > any singularity which happens to be nearby. The singularity is best > because -- even though it may not guarantee destruction of the > information -- the subjective time to observe the rocket crossing the > event horizon, from the frame of reference of a person some distance > from it, will be effectively infinite, causing most attackers to give > up. > > 7. If you do not have access to sufficient technology, have the > concrete slab stored in a nuclear-hardened bunker, with no Internet > connection, in a room using biometric identification keyed to > yourself, and with the whole complex guarded 24/7 by US Navy SEALs. > Maintain this watch until the technology available to complete step > (6) becomes available to you. > > Once you've completed this process, your application code will be > safe, for a reasonable value of "safe". > > (satire ends here) > > Or you could just find a host who properly sets up file permissions so > that random people can't access your application code. Unless you own > and personally supervise all of the following you will be susceptible > to rogue employees: the server, the rack in which it's located and the > datacenter in which the rack is found. Many people do not find that > the perceived security gains of doing so outweigh the financial and > maintenance drawbacks. YMMV. > > James, your the man :-) I would have suggested: Book a trip to the himalaya (well maybe after china has stopped being a PITA). March all the way to the top (make sure no CIA satellites are watching you). Dig a deep hole, say 100 foot deep, then barry your code in the hole. Then fill it up (again, check that those evil nasty satellites aren't watching), and go back home with the good feeling that your code, that nobody else on this planet could have written in such an elegant, perfect way will never be found and used by anybody. ;-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Reference to the url of the current page in a template
Scott Moonen wrote:
> Ganesh,
>
> First ensure that your TEMPLATE_CONTEXT_PROCESSORS contains:
>
> TEMPLATE_CONTEXT_PROCESSORS = (
> . . .
> 'django.core.context_processors.request',
> . . .
> )
>
> Then you can use the variable {{ request.path }} in your templates,
> assuming that the URLs are all on the same host. If not, you'll need
> to use something like {{ request.META.HTTP_HOST }}://{{ request.path }}.
>
> -- Scott
>
>
> On Fri, May 16, 2008 at 12:58 PM, M.Ganesh <[EMAIL PROTECTED]
> > wrote:
>
>
> Hi,
>
> I don't know how to clearly explain what I want to know. Let me
> try once
> again...
>
> I have a small controlpanel page which I include in all my other
> pages.
> This control panel page has got a link to 'login' page. Users are
> allowed to view the pages without login, but they have to login if
> they
> want to make any changes to the data. So if somebody realises he wants
> to change the data he is currently viewing, he will click the login
> link. Now I want him to be brought back to the page he was viewing
> before logging in. The trouble is because the 'login' link is in a
> template which will get included to a arbitrary page. In other words :
>
> #my controlpane.html
>
> {% if user.is_anonymous %}
>Welcome
> Please login
>login
> {% else %}
>blah blah
> {% endif %}
>
>
> Regards Ganesh
>
Hi Alex and Scott,
That worked like a charm. Thanks a ton.
My next task is to use this path to redirect. I'll get back if need more
help
Regards Ganesh
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Re: Django and Linux distros
JonSidnell wrote on 05/16/08 12:24:
> Hi everyone
>
> I'm suddenly struck by the notion that I would like to be dev'ing
> Django on Linux of some flavour rather than Windows.
>
> It's been a wee while since I stuck my toes in the Linux waters, so I
> was wondering if anyone here has any recommendations for a dev machine
> setup? Due to the django host I've signed with, I'm largely stuck with
> MySQL, and don't mind using the manage.py dev server while actually
> developing. Everything else is up for grabs in my mind - distro,
> editor, desktop manager skin, whatever! Although I'm unlikely to man
> up to something like emacs or vi for code editing...
>
> What works for you?
>
> Cheers
> Jon
I've you're a linux noob go with {k,u}buntu. If you're a hardcore *nix
lover go with slackware. If you're a developer go with gentoo linux, as
then, all the fancy libs you need to do your work are just an emerge away :)
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Re: Django and Linux distros
Thanks for the feedback everyone! The deed is done and I've got myself set up with Ubuntu Desktop, MySQL all working with Django, and gedit customised a la http://grigio.org/pimp_my_gedit_was_textmate_linux to act a bit more like Textmate. I'm liking it so far :) Cheers Jon On May 16, 11:24 am, JonSidnell <[EMAIL PROTECTED]> wrote: > Hi everyone > > I'm suddenly struck by the notion that I would like to be dev'ing > Django on Linux of some flavour rather than Windows. > > It's been a wee while since I stuck my toes in the Linux waters, so I > was wondering if anyone here has any recommendations for a dev machine > setup? Due to the django host I've signed with, I'm largely stuck with > MySQL, and don't mind using the manage.py dev server while actually > developing. Everything else is up for grabs in my mind - distro, > editor, desktop manager skin, whatever! Although I'm unlikely to man > up to something like emacs or vi for code editing... > > What works for you? > > Cheers > Jon --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Sorting a dict by value for template rendering
Variations on this come up all the time. Note that arrays can be
sorted.
So, create an array of tuples containing the key and the value.
Then you can sort the array anyway you please.
In the view:
# create the array of tuples
ordered_dict = [(key, val) for key,val in my_original_dict.items()]
# sort by key
ordered_dict.sort(lambda a,b: cmp(a[0], b[0]))
or
# sort by value
ordered_dict.sort(lambda a,b: cmp(a[1], b[1]))
# if values are objects, you can do
ordered_dict.sort(lambda a,b: cmp(a[1].some_attr, b[1].some_attr))
In the template:
{% for item in ordered_dict %}
Key: {{item.0}} Value: {{item.1}}
{% for %}
HTH,
Peter
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Re: displaying/editing multiple records at once
ken wrote: > One thing I've wanted for a long time is a way to enter and view > financial information for stocks I follow. However, this typically > involves working with a table (in the graphical sense) of data, > wherein each piece of data in the table is modeled as a single SQL > record. Frameworks such as Django seem to concentrate on working with > single records at once, and I'm wondering how I would go about putting > up a grid of cells such that the user could enter data into the cells, > submit the page, and have the various multiple records represented by > each cell updated. It's that last bit I wonder about. The HTML and so > forth are not the problem, the problem is simply one of figuring out > how to have Django allow input fields that represent multiple records. > > Feel free to refer me to sections of the django book, I realize I'll > be doing a lot of work on my own and I'm not looking for a full > answer, just a place to get started. > > Thanks, > Ken http://www.djangoproject.com/documentation/newforms/#prefixes-for-forms http://collingrady.wordpress.com/2008/02/18/editing-multiple-objects-in-django-with-newforms/ Regards, Jonathan --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
displaying/editing multiple records at once
One thing I've wanted for a long time is a way to enter and view financial information for stocks I follow. However, this typically involves working with a table (in the graphical sense) of data, wherein each piece of data in the table is modeled as a single SQL record. Frameworks such as Django seem to concentrate on working with single records at once, and I'm wondering how I would go about putting up a grid of cells such that the user could enter data into the cells, submit the page, and have the various multiple records represented by each cell updated. It's that last bit I wonder about. The HTML and so forth are not the problem, the problem is simply one of figuring out how to have Django allow input fields that represent multiple records. Feel free to refer me to sections of the django book, I realize I'll be doing a lot of work on my own and I'm not looking for a full answer, just a place to get started. Thanks, Ken --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Filtering by group
Alright, I think it works now with this: queryset = Quote.objects.select_related(slug) Much simpler than what I was trying... On May 16, 3:55 pm, Alex <[EMAIL PROTECTED]> wrote: > I'm not sure if this is any closer, but maybe it is: > > queryset = Quote.objects.filter(source in > series.tvepisode_set.select_related()), > > There's something wrong with the "source in" part, though... > > On May 16, 3:39 pm, Alex <[EMAIL PROTECTED]> wrote: > > > I'm playing around with a TV quotes database and I'm trying to get all > > quotes from one TV series. My problem is that the quotes are directly > > tied to an episode of a TV series, not the series itself. How can I > > easily get a queryset that represents all quotes from that series? > > > Here's a snippet from my models.py (removing irrelevant info): > > > class Source(models.Model): > > name = models.CharField(max_length=50) > > slug = models.SlugField(max_length=20) > > > class Quote(models.Model): > > quote = models.TextField(max_length=500) > > authors = models.ManyToManyField(Author) > > source = models.ForeignKey(Source) > > > class TVSeries(models.Model): > > name = models.CharField(max_length=50) > > slug = models.SlugField(max_length=20, editable=False) > > > class TVEpisode(Source): > > series = models.ForeignKey(TVSeries) > > episodenum = models.IntegerField() > > > In my view, I'm thinking of something like the following, which > > obviously doesn't work: > > > queryset = > > Quote.objects.filter(source=TVEpisode.objects.filter(TVSeries.objects.filter(authors__slug__iexact=slug))) > > > Is there an easy way to filter by groups like this? > > > Thanks, > > Alex --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Filtering by group
I'm not sure if this is any closer, but maybe it is: queryset = Quote.objects.filter(source in series.tvepisode_set.select_related()), There's something wrong with the "source in" part, though... On May 16, 3:39 pm, Alex <[EMAIL PROTECTED]> wrote: > I'm playing around with a TV quotes database and I'm trying to get all > quotes from one TV series. My problem is that the quotes are directly > tied to an episode of a TV series, not the series itself. How can I > easily get a queryset that represents all quotes from that series? > > Here's a snippet from my models.py (removing irrelevant info): > > class Source(models.Model): > name = models.CharField(max_length=50) > slug = models.SlugField(max_length=20) > > class Quote(models.Model): > quote = models.TextField(max_length=500) > authors = models.ManyToManyField(Author) > source = models.ForeignKey(Source) > > class TVSeries(models.Model): > name = models.CharField(max_length=50) > slug = models.SlugField(max_length=20, editable=False) > > class TVEpisode(Source): > series = models.ForeignKey(TVSeries) > episodenum = models.IntegerField() > > In my view, I'm thinking of something like the following, which > obviously doesn't work: > > queryset = > Quote.objects.filter(source=TVEpisode.objects.filter(TVSeries.objects.filter(authors__slug__iexact=slug))) > > Is there an easy way to filter by groups like this? > > Thanks, > Alex --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem with abstract model class
It looks that this is not the case. The problem seems to be more general. When I add abstract=True to ANY model I receive the same error. Example: class OrderItem(models.Model): num = models.IntegerField(default=1) timestamp = models.DateTimeField(auto_now=True) class Meta: abstract = True On 16 май, 18:25, Julien <[EMAIL PROTECTED]> wrote: > Hi, > > I think it should be %(class)s, not %s(class)s (take out the first > 's') > > Julien > > On May 16, 11:33 pm, Legioneer <[EMAIL PROTECTED]> wrote: > > > Hi All, > > > Got a problem when trying to define an abstract class. Below there is > > an examle: > > > class PaymentData(models.Model): > > owner = models.ForeignKey(Customer, > > related_name="%s(class)s_related" ) > > > class Meta: > > abstract = True > > > When running 'python manage.py validate' receive an error: > > > > > ... > > File "/usr/lib/python2.3/site-packages/django/db/models/base.py", > > line 89, in add_to_class > > value.contribute_to_class(cls, name) > > File "/usr/lib/python2.3/site-packages/django/db/models/options.py", > > line 70, in contribute_to_class > > raise TypeError, "'class Meta' got invalid attribute(s): %s" % > > ','.join(meta_attrs.keys()) > > TypeError: 'class Meta' got invalid attribute(s): abstract > > > What can be the problem? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Sorting a dict by value for template rendering
I have a dict that looks similar to this:
{'com': 'communication', 'tel': 'telephone', 'cel': 'cellphone',
'fax': 'fax machine',}
And I want to sort it by value, and render it in a template. I was
able to do it, but in a very hacked way. Can anyone show me a better
way to do it than my solution.
Here is the template tag (the dict I want to sort is
vocab_dict[vocabulary] on line 13):
http://dpaste.com/hold/50603/
Here is the template (the dict has been converted into a sorted list
of dicts and iterated through on lines 6-11):
http://dpaste.com/hold/50604/
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Filtering by group
I'm playing around with a TV quotes database and I'm trying to get all quotes from one TV series. My problem is that the quotes are directly tied to an episode of a TV series, not the series itself. How can I easily get a queryset that represents all quotes from that series? Here's a snippet from my models.py (removing irrelevant info): class Source(models.Model): name = models.CharField(max_length=50) slug = models.SlugField(max_length=20) class Quote(models.Model): quote = models.TextField(max_length=500) authors = models.ManyToManyField(Author) source = models.ForeignKey(Source) class TVSeries(models.Model): name = models.CharField(max_length=50) slug = models.SlugField(max_length=20, editable=False) class TVEpisode(Source): series = models.ForeignKey(TVSeries) episodenum = models.IntegerField() In my view, I'm thinking of something like the following, which obviously doesn't work: queryset = Quote.objects.filter(source=TVEpisode.objects.filter(TVSeries.objects.filter(authors__slug__iexact=slug))) Is there an easy way to filter by groups like this? Thanks, Alex --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: How to add an object with relations to other objects
For the first question, the db-api doc should provide this and more information, as I am not sure I completely understand, but here goes (assuming the following models): class B(models.Model): attribute = char()... class A(models.Model): attribute = char()... bs = m2m(B) in your view to get all of the B(s) related to a given A a = A.objects.get(pk=1) b = a.bs.all() if you want to get all of the Bs that are related to 'any' A: b = B.objects.filter(a__isnull = False) for question 2, I am not sure what you mean, if you mean can you create a B without relating it to an A? sure, a related A is not required by B. If you do not want to require a B for A just set 'blank=True, null=True' in the M2M field definition in A. Not sure if this helps, your original post was somewhat confusing, if you post relevant snippets from your models you may get more intelligent responses than my intellectual meanderings. -richard On 5/16/08, jabbercat <[EMAIL PROTECTED]> wrote: > > > Hello, > > it's my frist time I'm using this Group. > > My Problems: > I have a class A and a class B with a one(A)-to-many(B) relationship > between them. > > My first question: Is there an efficient way to get in a template all > instances of B, which are related to an instance of A, when i only > knew an instance of A? Something like a special attribute, or > something like that? > > My second question: I want to use form_for_model(), because of my > database-driver design. But how can I add an instance of B so that the > relation to an instance of A is also saved, without specify the > foreign key id of A explicitly? > > I hope you understand what I meen. > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Specifying schema name w/ syncdb
> I'm using PostgreSQL - one question I had was that when I run syncdb, > the tables that are created are under the default 'public' schema. > Is there a way to specify syncdb to create these tables under another > schema name? Er, sorry about that. If I created the schema first, syncdb stuck my tables there. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Image upload not working in newforms admin?
I finally got it to work, but I can't explain why. I followed this tutorial: http://paul.annesley.cc/articles/2007/11/19/django-and-python-imaging-library-pil-on-leopard One minute it wasn't working, the next it was. I've done this installation on a few computers, Win XP and Mac OS X 10.4.10/11 (Intel) without a hitch before. I'm not sure what could have been different on this current Powerbook running 10.4.11. I still can't get PIL to compile on an older Powerbok G4. It always fails with "gcc...exited with status 1" or something along those lines. One thing I noticed about the imageField is that it doesn't overwrite an existing file of the same name - it appends an underscore to the end of the file. I would be nice if it would check to see if the file name is the same and overwrite it, or not re-upload the image if you're just changing other attributes of the model. On May 16, 2:18 pm, mw <[EMAIL PROTECTED]> wrote: > I'm having nothing but tons of trouble right now with the image field > upload. I don't know what the problem is for sure, yet, but yeah I > think that I'm willing to say that the ImageField isn't as easy to get > working as it should be :-/ > > I think my problem may be OS X related and having to do with OS X's > Apache and mod_python being 64 bit while my PIL is something else, but > I need to verify that PIL is, in fact, 32 bit still. > > On May 16, 1:06 pm, Brandon Taylor <[EMAIL PROTECTED]> wrote: > > > Hi everyone, > > > I can't get the newforms admin to upload images. I have PIL and JPEG > > support installed. My selftest on PIL reports that JPEG is supported, > > along with PNG, but when I try to upload, I get: > > > Upload a valid image. The file you uploaded was either not an image or > > a corrupted. > > > I can confirm that it *is* a JPEG, and it was working before I > > switched to newforms-admin :) > > > Thoughts? Anyone experiencing something similar? I'm sure its a > > problem with PIL and no Django, but have no clue as to where to start > > to debug this. > > > TIA, > > Brandon --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
How to add an object with relations to other objects
Hello, it's my frist time I'm using this Group. My Problems: I have a class A and a class B with a one(A)-to-many(B) relationship between them. My first question: Is there an efficient way to get in a template all instances of B, which are related to an instance of A, when i only knew an instance of A? Something like a special attribute, or something like that? My second question: I want to use form_for_model(), because of my database-driver design. But how can I add an instance of B so that the relation to an instance of A is also saved, without specify the foreign key id of A explicitly? I hope you understand what I meen. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: accessing dictionary elements in opening tag of django template for loop
Thanks, John. Your second suggestion (that I find a way to modify the
Document class) put me on the right track. I eventually found this
article:
http://blog.arbingersys.com/2008/04/google-app-engine-better-many-to-many.html
which worked for my problem.
On May 14, 7:17 pm, "John Lenton" <[EMAIL PROTECTED]> wrote:
> On Wed, May 14, 2008 at 6:33 PM,John<[EMAIL PROTECTED]> wrote:
>
> > I'm having trouble accessing dictionary elements within a nested for
> > loop. here are some code snippets:
>
> > [...]
>
> > # so far so good, but then I try to iterate over the documents and
> > their associated tags in a template
> > # here is the template with the html stripped out for readability
> > {% for document in documents %}
> > {{ document.content }}
> > {% for doctag in tag_dict[document.uid] %} {{ doctag.tagid }} {%
> > endfor % }
> > {% endfor %}
>
> > # document.content is fine, but when I try to access tag_dict within
> > the template's for loop, it complains:
> > TemplateSyntaxError: Could not parse the remainder: [document.uid]
>
> right, templates are not python :) you can't do that, and it's on
> purpose: that kind of fiddling around with the model is best done in
> the view, not in the template.
>
> So... instead of doing e.g.
>
> documents = Document.objects.all()
> tag_dict = {}
> for document in documents:
> tag_dict[document.uid] = DocumentTag.objects.filter(docid=document.uid)
>
> and passing those two into the template, you could do something along
> the lines of
>
> documents = [dict(object=document,
> tags=DocumentTag.objects.filter(docid=document.uid))
> for document in Document.objects.all()]
>
> and then in the template, you do
>
> {% for document in documents %}
> {{ document.object.content }}
> {% for doctag in document.tags %} {{ doctag.tagid }} {% endfor %}
> {% endfor %}
>
> this is assuming there is some reason for you not to modify the
> Document class to give it the appropriate methods or attributes to
> access the related DocumentTag directly; if you could do that, life
> would be much easier :)
>
> --JohnLenton ([EMAIL PROTECTED]) -- Random fortune:
> The trouble with a lot of self-made men is that they worship their creator.
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Bind MultiValueField?
Hello,
I'm playing with MultiValueField which I want to be a part of a bound
form.
However, I can't push any value in it.
When I use CharField instead, everything is okay and the value is
displayed in charfield.
However, when I replace charfield with my MultiValueField, nothing is
rendered and when I check what value does the widget get in the render
method, and I see [None, None, None].
Here's how my Field and Widget look like:
class GuidedDateWidget(forms.MultiWidget):
def __init__(self, attrs=None):
widgets = (
forms.TextInput(attrs={'size':'2'}),
forms.TextInput(attrs={'size':'2'}),
forms.TextInput(attrs={'size':'4'})
)
super(GuidedDateWidget, self).__init__(widgets, attrs)
def format_output(self, widgets):
return u"D %sM %sY %s" % tuple(widgets)
def decompress(self, value):
if value:
return [value, 0, 0]
return [None, None, None]
class GuidedDateField(forms.MultiValueField):
widget = GuidedDateWidget
def __init__(self, *args, **kwargs):
fields = (
#forms.IntegerField(min_value=1, max_value=31, required=True),
forms.IntegerField(required=True),
forms.IntegerField(min_value=1, max_value=12, required=True),
forms.IntegerField(min_value=1900, required=True)
)
super(GuidedDateField, self).__init__(fields, *args, **kwargs)
def compress(self, data_list):
print("DEBUG: data list")
print data_list
if data_list:
try:
return datetime.datetime(*map(lambda x:int(x), data_list))
except ValueError:
raise forms.ValidationError(ERROR_INVALID)
return None
What should I do so the widget and field receive correct data to
render?
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Updated to latest trunk root page (/) stopped working
So I ran an svn up on my Django install because I'm running into some issues that QuerysetRefactor should have fixed, and after doing so the root page of my site stopped working. Everything else appears to be working fine, just not /. In my browser it gives me a 502 Proxy Error (which is odd, because I'm not aware that I'm using a proxy...). So I telnetted in to see what it would give me and got this: Shub-Niggurath:~ josho$ telnet bostonchefs.webfactional.com 80 Trying 75.125.175.50... Connected to bostonchefs.webfactional.com. Escape character is '^]'. GET Site not configured Connection closed by foreign host. The appropriate line of my urls.py is here: # Root (r'^/?$', 'myproject.views.index'), Does anyone have any idea what might be causing this? It seems odd that only that URL would stop working while the others are fine. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Caching: Memcached vs locmem
Can someone run down the differences between using Memcached vs locmem? The docs indicate Memcached is "the best" solution, but seems considerably harder to setup. Just curious what the trade-offs are. Thanks. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Image upload not working in newforms admin?
I'm having nothing but tons of trouble right now with the image field upload. I don't know what the problem is for sure, yet, but yeah I think that I'm willing to say that the ImageField isn't as easy to get working as it should be :-/ I think my problem may be OS X related and having to do with OS X's Apache and mod_python being 64 bit while my PIL is something else, but I need to verify that PIL is, in fact, 32 bit still. On May 16, 1:06 pm, Brandon Taylor <[EMAIL PROTECTED]> wrote: > Hi everyone, > > I can't get the newforms admin to upload images. I have PIL and JPEG > support installed. My selftest on PIL reports that JPEG is supported, > along with PNG, but when I try to upload, I get: > > Upload a valid image. The file you uploaded was either not an image or > a corrupted. > > I can confirm that it *is* a JPEG, and it was working before I > switched to newforms-admin :) > > Thoughts? Anyone experiencing something similar? I'm sure its a > problem with PIL and no Django, but have no clue as to where to start > to debug this. > > TIA, > Brandon --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
إلغاء اشتراك
نرجو إلغاء الاشتراك بالرسائل شكراً _ Express yourself instantly with MSN Messenger! Download today it's FREE! http://messenger.msn.click-url.com/go/onm00200471ave/direct/01/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Uploading files to subdirectories
what happens in your example if sally has a holiday.rtf ?
On May 16, 3:00 am, James McGill <[EMAIL PROTECTED]> wrote:
> Hi All,
> I'm new to Django and I'm not sure how best to achieve the following:
>
> Users may upload files - each uploaded file is tied to a user in the
> database using a ForeignKey.
>
> In order to prevent pain to the underlying O/S I don't want to put all
> these files in to a single directory. I could separate the files by
> upload time as mentioned in the Django documentation, but it would be
> nicer to have all the files uploaded by a single user under a single
> subdirectory.
>
> Example:
> Greg uploads "holiday.rtf", it is saved as /media/uploads/greg/
> holiday.rtf
> Sally uploads "family.rtf", it is saved as /media/uploads/sally/
> family.rtf
>
> My current model:
>
> class FileModel(models.Model):
> user = models.ForeignKey(User)
> file = models.FileField(upload_to = 'uploads/'
>
> I am saving the file using FileModel_Instance.save_file_file('path',
> file_contents). Adding extra folders to the path (i.e. path = greg/
> holiday.rtf) doesn't work - I assume this is a security restriction.
>
> I am using the SVN version of Django. Any help would be appreciated.
>
> Regards,
> James
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Re: Add column to generated ManyToMany table and access from admin
Thanks Richard, I'll give it a go.
Cheers
On May 16, 2:44 pm, "Richard Dahl" <[EMAIL PROTECTED]> wrote:
> I do not think that admin currently supports this, but I could be wrong. but
> here are two ways to accomplish it.
>
> class Item(models.Model):
>name = models.CharField(max_length=30)
>
> class ItemOrder(models.Model):
> item = models.FK(Item)
> order = models.int()
>
> def __unicode__(self): return ('%s - %s'
> %(self.item.__unicode__(), self.order))
>
> class Page(models.Model):
>survey = models.ForeignKey(Survey)
>item = models.M2M(ItemOrder)
>order = models.IntegerField() #Page Order
>file_name = models.CharField(max_length=50)
>
> You can also add a 'unique_together' constraint to your meta class in
> ItemOrder, if helpful.
> hth,
> -richard
>
> On 5/16/08, Peter Bailey <[EMAIL PROTECTED]> wrote:
>
>
>
> > I am pretty new to Django, and am building a web generating app. I am
> > hoping to get a lot of functionality out of the admin. So far that is
> > working great. I do have 2 classes in my models that have a many to
> > many relationship. The code is generated nicely and everything works
> > correctly.
> > The classes represent web pages and generic items that go on pages
> > such as radios, dropdowns, etc.
>
> > However, I would really like to add a column to the join table,
> > "order", so I can use the admin of my Page class to add Items and
> > define their order on that particular page. Is there a way to do this?
> > I have searched around and found lots of discussions, but no solid
> > answers. Sorry if this is a dumb question, but I admit I am a noob.
> > Here is a code snippet:
>
> > # will use this for subclassing into our item subtypes
> > class Item(models.Model):
> >name = models.CharField(max_length=30)
>
> >def __unicode__(self):
> >return self.name
>
> > class Page(models.Model):
> >"""Page information for survey pages - surveys will contain one or
> > more of these"""
> >survey = models.ForeignKey(Survey)
> >items = models.ManyToManyField(Item)
> >order = models.IntegerField() # this is for page ordering - not
> > item ordering
> >file_name = models.CharField(max_length=50)
>
> >def __unicode__(self):
> >return self.file_name
>
> >class Admin:
> >pass
>
> > class RadioBoxType(Item):
> >"""A Radio Button object with its specific attributes"""
> > ...
>
> > So, if I could somehow add an order column to the generated
> > gen_pageitem table and edit it from the admin for the page, I would be
> > set. I'm also not using the new admin branch which I just noticed a
> > couple of days ago. Any advice on if I should switch now or later
> > would be most welcome. I don't mind using newer code, but I am unsure
> > of the timelines for that branch to move into the trunk etc. Don't
> > want to waste time learning code that will be obsolete, but do have
> > some deadlines to meet (of course).
>
> > Advice or pointers greatly appreciated,
>
> > Peter
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Re: Add column to generated ManyToMany table and access from admin
I do not think that admin currently supports this, but I could be wrong. but
here are two ways to accomplish it.
class Item(models.Model):
name = models.CharField(max_length=30)
class ItemOrder(models.Model):
item = models.FK(Item)
order = models.int()
def __unicode__(self): return ('%s - %s'
%(self.item.__unicode__(), self.order))
class Page(models.Model):
survey = models.ForeignKey(Survey)
item = models.M2M(ItemOrder)
order = models.IntegerField() #Page Order
file_name = models.CharField(max_length=50)
You can also add a 'unique_together' constraint to your meta class in
ItemOrder, if helpful.
hth,
-richard
On 5/16/08, Peter Bailey <[EMAIL PROTECTED]> wrote:
>
> I am pretty new to Django, and am building a web generating app. I am
> hoping to get a lot of functionality out of the admin. So far that is
> working great. I do have 2 classes in my models that have a many to
> many relationship. The code is generated nicely and everything works
> correctly.
> The classes represent web pages and generic items that go on pages
> such as radios, dropdowns, etc.
>
> However, I would really like to add a column to the join table,
> "order", so I can use the admin of my Page class to add Items and
> define their order on that particular page. Is there a way to do this?
> I have searched around and found lots of discussions, but no solid
> answers. Sorry if this is a dumb question, but I admit I am a noob.
> Here is a code snippet:
>
> # will use this for subclassing into our item subtypes
> class Item(models.Model):
>name = models.CharField(max_length=30)
>
>def __unicode__(self):
>return self.name
>
> class Page(models.Model):
>"""Page information for survey pages - surveys will contain one or
> more of these"""
>survey = models.ForeignKey(Survey)
>items = models.ManyToManyField(Item)
>order = models.IntegerField() # this is for page ordering - not
> item ordering
>file_name = models.CharField(max_length=50)
>
>def __unicode__(self):
>return self.file_name
>
>class Admin:
>pass
>
> class RadioBoxType(Item):
>"""A Radio Button object with its specific attributes"""
> ...
>
> So, if I could somehow add an order column to the generated
> gen_pageitem table and edit it from the admin for the page, I would be
> set. I'm also not using the new admin branch which I just noticed a
> couple of days ago. Any advice on if I should switch now or later
> would be most welcome. I don't mind using newer code, but I am unsure
> of the timelines for that branch to move into the trunk etc. Don't
> want to waste time learning code that will be obsolete, but do have
> some deadlines to meet (of course).
>
> Advice or pointers greatly appreciated,
>
> Peter
>
>
> >
>
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Specifying schema name w/ syncdb
Hi there ... I'm using PostgreSQL - one question I had was that when I run syncdb, the tables that are created are under the default 'public' schema. Is there a way to specify syncdb to create these tables under another schema name? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: symmetrical associations
On May 14, 2008, at 5:53 PM, Russell Keith-Magee wrote:
> Hi James,
>
> It sounds like you might be looking for ticket #6095 [1]. This lets
> you define an intermediate model to use for m2m relations. This allows
> you to put attributes on the arc, query over the arc attributes, and
> be symmetrical (or not).
As long as the arc model can be defined without modifying the node
model.
For example, in one use case, I'd like the nodes to be able to be
django.contrib.auth Users.
To make it more concrete, here is what I am currently doing in one app
to retrieve friendship relationships between django.contrib.auth Users:
class FriendshipManager(models.Manager):
def friends_for_user(self, user):
friends = []
for friendship in self.filter(user_1=user):
friends.append({"friend": friendship.user_2,
"friendship": friendship})
for friendship in self.filter(user_2=user):
friends.append({"friend": friendship.user_1,
"friendship": friendship})
return friends
class Friendship(models.Model):
user_1 = models.ForeignKey(User, related_name="friends_1")
user_2 = models.ForeignKey(User, related_name="friends_2")
objects = FriendshipManager()
There could, of course, be extra fields on Friendship, but in the
above case there aren't and so it's just a normal symmetrical M2M
relationships except the User model is used unmodified.
James
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Add column to generated ManyToMany table and access from admin
I am pretty new to Django, and am building a web generating app. I am hoping to get a lot of functionality out of the admin. So far that is working great. I do have 2 classes in my models that have a many to many relationship. The code is generated nicely and everything works correctly. The classes represent web pages and generic items that go on pages such as radios, dropdowns, etc. However, I would really like to add a column to the join table, "order", so I can use the admin of my Page class to add Items and define their order on that particular page. Is there a way to do this? I have searched around and found lots of discussions, but no solid answers. Sorry if this is a dumb question, but I admit I am a noob. Here is a code snippet: # will use this for subclassing into our item subtypes class Item(models.Model): name = models.CharField(max_length=30) def __unicode__(self): return self.name class Page(models.Model): """Page information for survey pages - surveys will contain one or more of these""" survey = models.ForeignKey(Survey) items = models.ManyToManyField(Item) order = models.IntegerField() # this is for page ordering - not item ordering file_name = models.CharField(max_length=50) def __unicode__(self): return self.file_name class Admin: pass class RadioBoxType(Item): """A Radio Button object with its specific attributes""" ... So, if I could somehow add an order column to the generated gen_pageitem table and edit it from the admin for the page, I would be set. I'm also not using the new admin branch which I just noticed a couple of days ago. Any advice on if I should switch now or later would be most welcome. I don't mind using newer code, but I am unsure of the timelines for that branch to move into the trunk etc. Don't want to waste time learning code that will be obsolete, but do have some deadlines to meet (of course). Advice or pointers greatly appreciated, Peter --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
On Fri, May 16, 2008 at 11:52 AM, ydjango <[EMAIL PROTECTED]> wrote: > I do not want to make it easy for some one who breaks in , either a > outsider or may be an rougue hosting provider employee or contractor, > to easily get access to all the information - data and code. Again: if this is your worry, you have bigger problems. Allow me to suggest an alternate method: (satire begins here, for the humor-impaired) 1. Physically obtain the server upon which the code is stored. Write random data to the relevant sectors of the hard drive seven times over, then write zeroes to it seven times over, then write random data again. 2. Physically destroy the hard drive. Sledgehammers are good for this. 3. Place the shards of the hard drive into a vat of highly caustic acid. 4. Once the shards have dissolved, burn the resulting acidic liquid. Be sure to capture the smoke. 5. Cool the smoke until it turns back to ash. Mix the ash into the center of a reinforced concrete slab, at least 27 cubic feet in volume. 6. If you have access to sufficient technology, launch the concrete slab into space, on a course to collide with the Sun or (better) with any singularity which happens to be nearby. The singularity is best because -- even though it may not guarantee destruction of the information -- the subjective time to observe the rocket crossing the event horizon, from the frame of reference of a person some distance from it, will be effectively infinite, causing most attackers to give up. 7. If you do not have access to sufficient technology, have the concrete slab stored in a nuclear-hardened bunker, with no Internet connection, in a room using biometric identification keyed to yourself, and with the whole complex guarded 24/7 by US Navy SEALs. Maintain this watch until the technology available to complete step (6) becomes available to you. Once you've completed this process, your application code will be safe, for a reasonable value of "safe". (satire ends here) Or you could just find a host who properly sets up file permissions so that random people can't access your application code. Unless you own and personally supervise all of the following you will be susceptible to rogue employees: the server, the rack in which it's located and the datacenter in which the rack is found. Many people do not find that the perceived security gains of doing so outweigh the financial and maintenance drawbacks. YMMV. -- "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Image upload not working in newforms admin?
Hi everyone, I can't get the newforms admin to upload images. I have PIL and JPEG support installed. My selftest on PIL reports that JPEG is supported, along with PNG, but when I try to upload, I get: Upload a valid image. The file you uploaded was either not an image or a corrupted. I can confirm that it *is* a JPEG, and it was working before I switched to newforms-admin :) Thoughts? Anyone experiencing something similar? I'm sure its a problem with PIL and no Django, but have no clue as to where to start to debug this. TIA, Brandon --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: MySQL Boolean vs. PostgresQL Boolean
Thanks Karen. Actually, the behavior here is worst case, from my perspective, in that Ture/False values will update an instance, but will not be saved and no exception is thrown. When I try to update the model with a True/False value, it simply fails to update without giving any indication of an error. So, on my Slicehost installation (MySQL based): m = Model.object.get(id=id) print m.BooleanField // Prints 0, if the value is False m.BooleanField = True m.save() print m.BooleanField // Prints True m = Model.object.get(id=id) print m.BooleanField // Still prints 0. The instance was updated, but did not save. No error. m.BooleanField = 1 m.save() print m.BooleanField // Prints 1 m = Model.object.get(id=id) print m.BooleanField // Now prints 1. Saved correctly. I have to alter my code so 0 and 1 are submitted to get updates to save correctly. I am not pulling anything through SQL, only directly through the Django models. This sounds like a bug to me, but I want to be sure there's not some MySQL boolean setting that I might be missing in my settings.py, or even in my MySQL setup files. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
On May 16, 12:52 pm, ydjango <[EMAIL PROTECTED]> wrote: > I do not want to make it easy for some one who breaks in , either a > outsider or may be an rougue hosting provider employee or contractor, > to easily get access to all the information - data and code. > Your best bet is to ensure that doesn't happen--secure passwords and limiting server access to your IP address is a good start. But if someone gets into your server they will be able to access your code. It doesn't matter if it's .py or .pyc--if it can be executed it can be deconstructed by a motivated attacker. This isn't the fault of Python, it's the same in other languages. You can obfuscate your code, but it's still security through obscurity. > Also, I read somewhere that google does not use python for its core > busines applications. It uses it as glue langauage and for internal > operations automation mostly. Just a random thought. This isn't because of security, it's because of speed. There are plenty of public facing services using Python, including Groups and Code. Google does a ton in Java (like Gmail) and that's really easy to decompile. Google protects access to its code and as such a .py file is just as secure as anything else. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Reference to the url of the current page in a template
Ganesh,
First ensure that your TEMPLATE_CONTEXT_PROCESSORS contains:
TEMPLATE_CONTEXT_PROCESSORS = (
. . .
'django.core.context_processors.request',
. . .
)
Then you can use the variable {{ request.path }} in your templates, assuming
that the URLs are all on the same host. If not, you'll need to use
something like {{ request.META.HTTP_HOST }}://{{ request.path }}.
-- Scott
On Fri, May 16, 2008 at 12:58 PM, M.Ganesh <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I don't know how to clearly explain what I want to know. Let me try once
> again...
>
> I have a small controlpanel page which I include in all my other pages.
> This control panel page has got a link to 'login' page. Users are
> allowed to view the pages without login, but they have to login if they
> want to make any changes to the data. So if somebody realises he wants
> to change the data he is currently viewing, he will click the login
> link. Now I want him to be brought back to the page he was viewing
> before logging in. The trouble is because the 'login' link is in a
> template which will get included to a arbitrary page. In other words :
>
> #my controlpane.html
>
> {% if user.is_anonymous %}
>Welcome
> Please login
>login
> {% else %}
>blah blah
> {% endif %}
>
>
> Regards Ganesh
>
>
> >
>
--
http://scott.andstuff.org/ | http://truthadorned.org/
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Re: Reference to the url of the current page in a template
If you have `django.core.context_processors.request` context processor
enabled and you use RequestContext so the `{{request.path}}` will
return current path. Or you can simple pass `request.path` variable to
the template context manually.
On May 16, 8:58 pm, "M.Ganesh" <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I don't know how to clearly explain what I want to know. Let me try once
> again...
>
> I have a small controlpanel page which I include in all my other pages.
> This control panel page has got a link to 'login' page. Users are
> allowed to view the pages without login, but they have to login if they
> want to make any changes to the data. So if somebody realises he wants
> to change the data he is currently viewing, he will click the login
> link. Now I want him to be brought back to the page he was viewing
> before logging in. The trouble is because the 'login' link is in a
> template which will get included to a arbitrary page. In other words :
>
> #my controlpane.html
>
> {% if user.is_anonymous %}
> Welcome
>Please login
> login
> {% else %}
> blah blah
> {% endif %}
>
> Regards Ganesh
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Reference to the url of the current page in a template
Hi,
I don't know how to clearly explain what I want to know. Let me try once
again...
I have a small controlpanel page which I include in all my other pages.
This control panel page has got a link to 'login' page. Users are
allowed to view the pages without login, but they have to login if they
want to make any changes to the data. So if somebody realises he wants
to change the data he is currently viewing, he will click the login
link. Now I want him to be brought back to the page he was viewing
before logging in. The trouble is because the 'login' link is in a
template which will get included to a arbitrary page. In other words :
#my controlpane.html
{% if user.is_anonymous %}
Welcome
Please login
login
{% else %}
blah blah
{% endif %}
Regards Ganesh
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Re: Keeping track of which user did what
This can be done with the threadlocals middleware: http://code.djangoproject.com/wiki/CookBookThreadlocalsAndUser On 5/16/08, Chris Farley <[EMAIL PROTECTED]> wrote: > > > Django has that nice "auto_add=True" property you can set on a model's > field. I have two fields in my models called "created_at" and > "updated_at" that keeps track of each model instance's creation/ > modification date. It's incredibly easy. > > I also want to keep track of which user created/updated each instance. > Right now, I'm doing this from my views -- I just get the user from > the request object and manually populate my "created_by" and > "updated_by" fields. This definitely violates the DRY principle... I > would love to move this code into my model code (by maybe overriding > the save method), but I don't think I have access to the request > object in my models. > > Any suggestions? Thanks! > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
I do not want to make it easy for some one who breaks in , either a outsider or may be an rougue hosting provider employee or contractor, to easily get access to all the information - data and code. I would have thought by this time easy solutions for this issue would have been found. I know I am a bit paranoid when it comes to security, probably becuase of my background in financial industry. I also do understand at some point you need to trust some one and that a hosting provider will not do such a thing as stealing your code. and likelyhood of such a break-in happening is very rare. ( I have no ssn or credit card info, so why would anyone bother to break in.) Also, I read somewhere that google does not use python for its core busines applications. It uses it as glue langauage and for internal operations automation mostly. Just a random thought. thanks Ashish On May 16, 8:42 am, jonknee <[EMAIL PROTECTED]> wrote: > On May 16, 6:02 am, ydjango <[EMAIL PROTECTED]> wrote: > > > I have propriety commercial code and some formula/ algo > > implementations which I do not want to expose. > > Hence I do not want to upload .py source files > > Expose to whom? Your files (even on shared hosting) are still just > your files. If you believe your host is going to snoop in your account > and steal your algorithm and sell it to your competitors, you > definitely need a new host. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Get just one object id at the time in view assignment issue.
Hello guys!
I have another little (i'm sure it is) problem (i have like 3 days
trying to resolve it by myself but i just gave up lol), i'm using
django-tagging so I can tag some records, the problem here is that i
don't know how to take one object, take its id and then keep the
cycle. this is what i got so far:
def Records (request, UserName):
artists = Artist.objects.get(UserName=UserName)
try:
records = artist.record_set.all()
except Record.DoesNotExist:
records = None
record_id = # Missing code here i guess
record_tags = Record.objects.get(id=record_id)
RecordTags = Tag.objects.get_for_object(record_tags)
I mean, if i put a Int en record_id i can get the tags but just for
that one and i dont want that:
{% if tags %}
Tags: | {% for tags in tags %}{{ tags.name }} | {% endfor %}
{% else %}
no tags {{ id }}
{% endif %}
I hope you can help me out!
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Problem with : Updating multiple objects at once
Hello, I want to do something like this: UPDATE news SET sequence = sequence-1 WHERE sequence > 5 With the database-api I tried the following: News.objects.filter(sequence__gt = msequence).update(sequence = sequence-1) But thats not possible, beacause the assignment parameter sequence-1 must be a variable and not a reference to a column-value. Is there any possibility to solve this problem without iterating over all results with News.objects.filter(sequence__gt = msequence) and setting the new sequence manually in each iteration? Thanks, Toni --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
On May 16, 6:02 am, ydjango <[EMAIL PROTECTED]> wrote: > I have propriety commercial code and some formula/ algo > implementations which I do not want to expose. > Hence I do not want to upload .py source files Expose to whom? Your files (even on shared hosting) are still just your files. If you believe your host is going to snoop in your account and steal your algorithm and sell it to your competitors, you definitely need a new host. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Getting 'instance' in ModelForms
On May 16, 6:27 am, Greg Taylor <[EMAIL PROTECTED]> wrote: > class Form_SKU(ModelForm): > """ > The form for updating SKUs. > """ > selected = self.instance.colors ``self`` isn't in scope here, try the code below (and it wouldn't hurt to read-up on Python OOP). class Form_SKU(ModelForm): def __init__(self, *args, **kwargs): super(Form_SKU, self).__init__(*args, **kwargs) if self.instance: selected = self.instance.colors --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: custom SQL problem
I'm stupid, thanks.
>>> cursor.fetchone()
(1L,)
>>> cursor.fetchall()
((3L,),)
On May 16, 12:01 pm, "Karen Tracey" <[EMAIL PROTECTED]> wrote:
> On Fri, May 16, 2008 at 10:45 AM, enri57ar <[EMAIL PROTECTED]> wrote:
>
> > I can't execute custom SQL. 'Cursor' object has no attribute
> > 'fechone', and 'fechall'
> > I have a model named 'Labels' with db_name = 'labels'.
>
> You're missing a 't' in fetchone() and fetchall().
>
> Karen
>
>
>
> > mysql> SELECT id FROM labels;
> > ++
> > | id |
> > ++
> > | 1 |
> > | 3 |
> > ++
> > 2 rows in set (0.00 sec)
>
> >
>
> > >>> django.get_version()
> > u'0.97-pre-SVN-7523'
>
> > >>> Labels.objects.count()
> > 2L
> > >>> from django.db import connection
> > >>> cursor = connection.cursor()
> > >>> cursor.execute("SELECT id FROM labels;")
> > 2L
>
> > >>> row = cursor.fechone()
> > Traceback (most recent call last):
> > File "", line 1, in
> > File "C:\Python25\lib\site-packages\django\db\backends\util.py",
> > line 42, in _
> > _getattr__
> > return getattr(self.cursor, attr)
> > AttributeError: 'Cursor' object has no attribute 'fechone'
>
> > >>> row = cursor.fechall()
> > Traceback (most recent call last):
> > File "", line 1, in
> > File "C:\Python25\lib\site-packages\django\db\backends\util.py",
> > line 42, in _
> > _getattr__
> > return getattr(self.cursor, attr)
> > AttributeError: 'Cursor' object has no attribute 'fechall'
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Re: Getting 'instance' in ModelForms
To elaborate, I can't do a self.instance, as it errors saying "self is not defined". For example: color_field = forms.ModelMultipleChoiceField(queryset=self.instance.colors) I need to find the difference of two lists on a model to form the queryset in my application. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: custom SQL problem
> I can't execute custom SQL. 'Cursor' object has no attribute
> 'fechone', and 'fechall'
Try "fetchone" and "fetchall" (with the letter "t")
However, for your use-case, you may prefer to simply use the
.values() method of a recordset:
Labels.objects.values("id")
as described at
http://www.djangoproject.com/documentation/db-api/#values-fields
-tim
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Re: custom SQL problem
On Fri, May 16, 2008 at 10:45 AM, enri57ar <[EMAIL PROTECTED]> wrote:
>
> I can't execute custom SQL. 'Cursor' object has no attribute
> 'fechone', and 'fechall'
> I have a model named 'Labels' with db_name = 'labels'.
>
You're missing a 't' in fetchone() and fetchall().
Karen
>
>
> mysql> SELECT id FROM labels;
> ++
> | id |
> ++
> | 1 |
> | 3 |
> ++
> 2 rows in set (0.00 sec)
>
>
>
> >>> django.get_version()
> u'0.97-pre-SVN-7523'
> >>>
> >>> Labels.objects.count()
> 2L
> >>> from django.db import connection
> >>> cursor = connection.cursor()
> >>> cursor.execute("SELECT id FROM labels;")
> 2L
> >>>
> >>>
> >>> row = cursor.fechone()
> Traceback (most recent call last):
> File "", line 1, in
> File "C:\Python25\lib\site-packages\django\db\backends\util.py",
> line 42, in _
> _getattr__
>return getattr(self.cursor, attr)
> AttributeError: 'Cursor' object has no attribute 'fechone'
> >>>
> >>>
> >>> row = cursor.fechall()
> Traceback (most recent call last):
> File "", line 1, in
> File "C:\Python25\lib\site-packages\django\db\backends\util.py",
> line 42, in _
> _getattr__
>return getattr(self.cursor, attr)
> AttributeError: 'Cursor' object has no attribute 'fechall'
> >
>
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custom SQL problem
I can't execute custom SQL. 'Cursor' object has no attribute
'fechone', and 'fechall'
I have a model named 'Labels' with db_name = 'labels'.
mysql> SELECT id FROM labels;
++
| id |
++
| 1 |
| 3 |
++
2 rows in set (0.00 sec)
>>> django.get_version()
u'0.97-pre-SVN-7523'
>>>
>>> Labels.objects.count()
2L
>>> from django.db import connection
>>> cursor = connection.cursor()
>>> cursor.execute("SELECT id FROM labels;")
2L
>>>
>>>
>>> row = cursor.fechone()
Traceback (most recent call last):
File "", line 1, in
File "C:\Python25\lib\site-packages\django\db\backends\util.py",
line 42, in _
_getattr__
return getattr(self.cursor, attr)
AttributeError: 'Cursor' object has no attribute 'fechone'
>>>
>>>
>>> row = cursor.fechall()
Traceback (most recent call last):
File "", line 1, in
File "C:\Python25\lib\site-packages\django\db\backends\util.py",
line 42, in _
_getattr__
return getattr(self.cursor, attr)
AttributeError: 'Cursor' object has no attribute 'fechall'
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Re: partially edit an object
koenb wrote: sted a snippet on > djangosnippets with my DisplayModelForm [1]. > Basically, it allows you to reuse your form definitions, but turn them > into a "display_only" mode. You can do all fields or just a few. > .. I've passed this to my colleague who will no doubt digest in due time; thanks. -- Robin Becker --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
I would see at least two things to keep your files secure on a shared hosting service: make sure permissions are set correctly (e.g. don't give any right to "others" to your home directory), and use a complex password for your account (using numbers, a mix or lowercased and uppercased characters, et no word from the dictionary). Following that kind of basic precautions I'd put all my trust in hosts like webfaction. On May 17, 12:16 am, "James Bennett" <[EMAIL PROTECTED]> wrote: > On Fri, May 16, 2008 at 9:15 AM, ydjango <[EMAIL PROTECTED]> wrote: > > Yes, that was another thing on my mind, how to encrypt password in > > settings.py > > You don't. I think either you misunderstand how shared hosting works, > or you have an extremely bad host. > > -- > "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Problem with abstract model class
Hi, I think it should be %(class)s, not %s(class)s(take out the first 's') Julien On May 16, 11:33 pm, Legioneer <[EMAIL PROTECTED]> wrote: > Hi All, > > Got a problem when trying to define an abstract class. Below there is > an examle: > > class PaymentData(models.Model): > owner = models.ForeignKey(Customer, > related_name="%s(class)s_related" ) > > class Meta: > abstract = True > > When running 'python manage.py validate' receive an error: > > > ... > File "/usr/lib/python2.3/site-packages/django/db/models/base.py", > line 89, in add_to_class > value.contribute_to_class(cls, name) > File "/usr/lib/python2.3/site-packages/django/db/models/options.py", > line 70, in contribute_to_class > raise TypeError, "'class Meta' got invalid attribute(s): %s" % > ','.join(meta_attrs.keys()) > TypeError: 'class Meta' got invalid attribute(s): abstract > > What can be the problem? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
On Fri, May 16, 2008 at 9:15 AM, ydjango <[EMAIL PROTECTED]> wrote: > Yes, that was another thing on my mind, how to encrypt password in > settings.py You don't. I think either you misunderstand how shared hosting works, or you have an extremely bad host. -- "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
Yes, that was another thing on my mind, how to encrypt password in settings.py On May 16, 3:20 am, "James Bennett" <[EMAIL PROTECTED]> wrote: > On Fri, May 16, 2008 at 5:02 AM, ydjango <[EMAIL PROTECTED]> wrote: > > I have propriety commercial code and some formula/ algo > > implementations which I do not want to expose. > > Hence I do not want to upload .py source files > > If your host's setup would allow other users to view this code, you > have much larger and much more dangerous security problems to worry > about (since, for example, that would mean they could also see > sensitive passwords in configuration files). > > -- > "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
> What works for you? Ubuntu + Eric4 as ide + Mysql. Javier. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Problem with abstract model class
Hi All, Got a problem when trying to define an abstract class. Below there is an examle: class PaymentData(models.Model): owner = models.ForeignKey(Customer, related_name="%s(class)s_related" ) class Meta: abstract = True When running 'python manage.py validate' receive an error: ... File "/usr/lib/python2.3/site-packages/django/db/models/base.py", line 89, in add_to_class value.contribute_to_class(cls, name) File "/usr/lib/python2.3/site-packages/django/db/models/options.py", line 70, in contribute_to_class raise TypeError, "'class Meta' got invalid attribute(s): %s" % ','.join(meta_attrs.keys()) TypeError: 'class Meta' got invalid attribute(s): abstract What can be the problem? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: partially edit an object
Robin, I don't know if this is a 'right' way, but I posted a snippet on djangosnippets with my DisplayModelForm [1]. Basically, it allows you to reuse your form definitions, but turn them into a "display_only" mode. You can do all fields or just a few. I use it to display objects to users, with an edit button, which shows the same object, but this time in the normal ModelForm way. The advantage is that the layout is more or less the same for the user, and for me that I can reuse my form definitions and my templates for both. I have put this inside a bunch of custom crud views, because I needed this same pattern for a lot of objects. Obviously, using the newforms machinery to just display an object is not exactly efficient, but for me that is not an issue. Hope this helps, Koen [1]: http://www.djangosnippets.org/snippets/758/ On 15 mei, 15:37, Robin Becker <[EMAIL PROTECTED]> wrote: > I have a colleague who wishes to restrict the editability of fields > dynamically. > I can see how this arises by considering a Person object. The supervisor role > might be allowed to edit more than the individual concerned. > > We looked in vain for an 'easy' way to do this using old forms, newforms, > generic views etc etc, but eventually started writing our own views to do > this. > > Sure I could probably start trying to grok the inner horrors of update_object > and minulators etc etc, but that seems really overkill for such a simple > requirement. > > I expected to be able to pass in a list of fields that were to be left alone > or > something as easy. Is there no easy way to do these simple extensions; if not > what's the 'right' way to do this in the various contexts? > -- > Robin Becker --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
I'm using Ubuntu, vim, sqlite3, svn and Django development server. Matic Žgur On Fri, May 16, 2008 at 2:59 PM, Almir Karic <[EMAIL PROTECTED]> wrote: > > On Fri, May 16, 2008 at 12:24 PM, JonSidnell <[EMAIL PROTECTED]> wrote: >> What works for you? > > debian & vim, tho i'm considering switching to openbsd as my primary OS. > > > -- > For far too long, power has been concentrated in the hands of "root" > and his "wheel" oligarchy. We have instituted a dictatorship of the > users. All system administration functions will be handled by the > People's Committee for Democratically Organizing the System (PC-DOS). > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
Ubuntu for desktop. FreeBSD and OpenBSD for production server. Regards, Valts. On Fri, May 16, 2008 at 3:59 PM, Almir Karic <[EMAIL PROTECTED]> wrote: > > On Fri, May 16, 2008 at 12:24 PM, JonSidnell <[EMAIL PROTECTED]> wrote: > > What works for you? > > debian & vim, tho i'm considering switching to openbsd as my primary OS. > > > -- > For far too long, power has been concentrated in the hands of "root" > and his "wheel" oligarchy. We have instituted a dictatorship of the > users. All system administration functions will be handled by the > People's Committee for Democratically Organizing the System (PC-DOS). > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
On Fri, May 16, 2008 at 12:24 PM, JonSidnell <[EMAIL PROTECTED]> wrote: > What works for you? debian & vim, tho i'm considering switching to openbsd as my primary OS. -- For far too long, power has been concentrated in the hands of "root" and his "wheel" oligarchy. We have instituted a dictatorship of the users. All system administration functions will be handled by the People's Committee for Democratically Organizing the System (PC-DOS). --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: This field is required. NO!
On 16-May-08, at 5:48 PM, Andre Meyer wrote: > still need to figure out why ;-) by default, django treats all fields as not null and not blank. Usually, the 'null' part is enforced at the database level and the 'blank' part at django level. So for fields like CharFields, saying null is allowed is not the same as saying blank is allowed. -- regards kg http://lawgon.livejournal.com http://nrcfosshelpline.in/code/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Getting 'instance' in ModelForms
Is there a way to get the value of the 'instance' keyword argument from within a Form sub-classed by ModelForm? For example: class CS_SKU(models.Model): colors = models.ManyToManyField(Color, blank=True, null=True) color_field = forms.ModelMultipleChoiceField(queryset=colors) class Form_SKU(ModelForm): """ The form for updating SKUs. """ selected = self.instance.colors def some_test_view(): Form_SKU(instance=) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
Jon, On Fri, 16 May 2008, JonSidnell wrote: > I'm suddenly struck by the notion that I would like to be dev'ing > Django on Linux of some flavour rather than Windows. Congratulations!!! > It's been a wee while since I stuck my toes in the Linux waters, so I > was wondering if anyone here has any recommendations for a dev machine > setup? My personal distro preference is Debian. > Due to the django host I've signed with, I'm largely stuck with MySQL, > and don't mind using the manage.py dev server while actually developing. I have both PostgreSQL and MySQL on my Debian box. > Everything else is up for grabs in my mind - distro, editor, desktop > manager skin, whatever! Although I'm unlikely to man up to something > like emacs or vi for code editing... If you don't like vi and/or emacs you probably don't want to ask me about desktop managers or editors. I use vim for editing and Ion for desktop management. I have also used emacs off and on in the past. Kevin http://www.RawFedDogs.net http://www.WacoAgilityGroup.org Bruceville, TX Si hoc legere scis nimium eruditionis habes. Longum iter est per praecepta, breve et efficax per exempla!!! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: This field is required. NO!
oh dear, this seems to be a well-known thing.
thanks so much for this, it works!
still need to figure out why ;-)
thanks to you all
André
On Fri, May 16, 2008 at 1:10 PM, Ben Ford <[EMAIL PROTECTED]> wrote:
>
> Andre,
>
> You also need blank=True here:
> pn = models.CharField('Publication number', max_length=20, null=True)
>
>
> That will fix you :-)
> Ben
>
>
> Andre Meyer wrote:
> > hi all
> >
> > now, this is driving me crazy. this problem persists even after
> > switching from 0.96.1 to the newforms-admin branch.
> >
> > after declaring a model class with an attribute that may be null (pn)
> > the admin site still tells me to fill in that field, because "This
> > field is required.", but it isn't.
> >
> > i have registered the model class to the admin site without any custom
> > options.
> >
> > recreated the database file (sqlite) after switching to the na branch.
> >
> > checked in SQLite Manager that the pn field may indeed be null.
> >
> > new Dossier instances can be created and saved in the shell without
> > the pn attribute, but when viewing the instance on the admin page and
> > pressing Save, the error appears.
> >
> > what is the matter?
> >
> > thanks for your suggestions
> > cheers
> > André
> >
> >
> > code:
> >
> > /model.py
> > /
> > class Dossier(models.Model):
> > an = models.CharField('Dossier number', max_length=10,
> > primary_key=True)
> > pn = models.CharField('Publication number', max_length=20, null=True)
> >
> > def __unicode__(self):
> > return self.an
> >
> > admin.site.register(Dossier)
> >
> >
> > >
>
>
> >
>
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Keeping track of which user did what
Django has that nice "auto_add=True" property you can set on a model's field. I have two fields in my models called "created_at" and "updated_at" that keeps track of each model instance's creation/ modification date. It's incredibly easy. I also want to keep track of which user created/updated each instance. Right now, I'm doing this from my views -- I just get the user from the request object and manually populate my "created_by" and "updated_by" fields. This definitely violates the DRY principle... I would love to move this code into my model code (by maybe overriding the save method), but I don't think I have access to the request object in my models. Any suggestions? Thanks! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: This field is required. NO!
Andre,
You also need blank=True here:
pn = models.CharField('Publication number', max_length=20, null=True)
That will fix you :-)
Ben
Andre Meyer wrote:
> hi all
>
> now, this is driving me crazy. this problem persists even after
> switching from 0.96.1 to the newforms-admin branch.
>
> after declaring a model class with an attribute that may be null (pn)
> the admin site still tells me to fill in that field, because "This
> field is required.", but it isn't.
>
> i have registered the model class to the admin site without any custom
> options.
>
> recreated the database file (sqlite) after switching to the na branch.
>
> checked in SQLite Manager that the pn field may indeed be null.
>
> new Dossier instances can be created and saved in the shell without
> the pn attribute, but when viewing the instance on the admin page and
> pressing Save, the error appears.
>
> what is the matter?
>
> thanks for your suggestions
> cheers
> André
>
>
> code:
>
> /model.py
> /
> class Dossier(models.Model):
> an = models.CharField('Dossier number', max_length=10,
> primary_key=True)
> pn = models.CharField('Publication number', max_length=20, null=True)
>
> def __unicode__(self):
> return self.an
>
> admin.site.register(Dossier)
>
>
> >
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Re: This field is required. NO!
Andre Meyer pisze: > now, this is driving me crazy. this problem persists even after > switching from 0.96.1 to the newforms-admin branch. > > after declaring a model class with an attribute that may be null (pn) > the admin site still tells me to fill in that field, because "This field > is required.", but it isn't. > > i have registered the model class to the admin site without any custom > options. > > recreated the database file (sqlite) after switching to the na branch. > > checked in SQLite Manager that the pn field may indeed be null. > > new Dossier instances can be created and saved in the shell without the > pn attribute, but when viewing the instance on the admin page and > pressing Save, the error appears. > > what is the matter? http://www.b-list.org/weblog/2006/jun/28/django-tips-difference-between-blank-and-null/ -- Jarek Zgoda Skype: jzgoda | GTalk: [EMAIL PROTECTED] | voice: +48228430101 "We read Knuth so you don't have to." (Tim Peters) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: This field is required. NO!
On 16-May-08, at 5:36 PM, Andre Meyer wrote: > after declaring a model class with an attribute that may be null > (pn) the admin site still tells me to fill in that field, because > "This field is required.", but it isn't. have you set blank=True? -- regards kg http://lawgon.livejournal.com http://nrcfosshelpline.in/code/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: This field is required. NO!
Andre, in addition to saying null=True, try adding blank=True.
-- Scott
On Fri, May 16, 2008 at 8:06 AM, Andre Meyer <[EMAIL PROTECTED]>
wrote:
> hi all
>
> now, this is driving me crazy. this problem persists even after switching
> from 0.96.1 to the newforms-admin branch.
>
> after declaring a model class with an attribute that may be null (pn) the
> admin site still tells me to fill in that field, because "This field is
> required.", but it isn't.
>
> i have registered the model class to the admin site without any custom
> options.
>
> recreated the database file (sqlite) after switching to the na branch.
>
> checked in SQLite Manager that the pn field may indeed be null.
>
> new Dossier instances can be created and saved in the shell without the pn
> attribute, but when viewing the instance on the admin page and pressing
> Save, the error appears.
>
> what is the matter?
>
> thanks for your suggestions
> cheers
> André
>
>
> code:
>
> *model.py
> *
> class Dossier(models.Model):
> an = models.CharField('Dossier number', max_length=10,
> primary_key=True)
> pn = models.CharField('Publication number', max_length=20, null=True)
>
> def __unicode__(self):
> return self.an
>
> admin.site.register(Dossier)
>
>
> >
>
--
http://scott.andstuff.org/ | http://truthadorned.org/
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Re: This field is required. NO!
On Fri, May 16, 2008 at 2:06 PM, Andre Meyer <[EMAIL PROTECTED]> wrote:
> pn = models.CharField('Publication number', max_length=20, null=True)
missing a 'blank=True'
--
For far too long, power has been concentrated in the hands of "root"
and his "wheel" oligarchy. We have instituted a dictatorship of the
users. All system administration functions will be handled by the
People's Committee for Democratically Organizing the System (PC-DOS).
--~--~-~--~~~---~--~~
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This field is required. NO!
hi all
now, this is driving me crazy. this problem persists even after switching
from 0.96.1 to the newforms-admin branch.
after declaring a model class with an attribute that may be null (pn) the
admin site still tells me to fill in that field, because "This field is
required.", but it isn't.
i have registered the model class to the admin site without any custom
options.
recreated the database file (sqlite) after switching to the na branch.
checked in SQLite Manager that the pn field may indeed be null.
new Dossier instances can be created and saved in the shell without the pn
attribute, but when viewing the instance on the admin page and pressing
Save, the error appears.
what is the matter?
thanks for your suggestions
cheers
André
code:
*model.py
*
class Dossier(models.Model):
an = models.CharField('Dossier number', max_length=10, primary_key=True)
pn = models.CharField('Publication number', max_length=20, null=True)
def __unicode__(self):
return self.an
admin.site.register(Dossier)
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Re: Uploading files to subdirectories
Hello James,
You can do that following this:
http://code.djangoproject.com/wiki/CustomUploadAndFilters
It uses signals to customize the upload path.
James McGill escribió:
> Hi All,
> I'm new to Django and I'm not sure how best to achieve the following:
>
> Users may upload files - each uploaded file is tied to a user in the
> database using a ForeignKey.
>
> In order to prevent pain to the underlying O/S I don't want to put all
> these files in to a single directory. I could separate the files by
> upload time as mentioned in the Django documentation, but it would be
> nicer to have all the files uploaded by a single user under a single
> subdirectory.
>
> Example:
> Greg uploads "holiday.rtf", it is saved as /media/uploads/greg/
> holiday.rtf
> Sally uploads "family.rtf", it is saved as /media/uploads/sally/
> family.rtf
>
> My current model:
>
> class FileModel(models.Model):
> user = models.ForeignKey(User)
> file = models.FileField(upload_to = 'uploads/'
>
> I am saving the file using FileModel_Instance.save_file_file('path',
> file_contents). Adding extra folders to the path (i.e. path = greg/
> holiday.rtf) doesn't work - I assume this is a security restriction.
>
> I am using the SVN version of Django. Any help would be appreciated.
>
> Regards,
> James
>
>
> >
>
--
Un saludote..
--==@ Sergio @==--
Barraquito.net - http://www.barraquito.net
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Re: Printing out HTML that doesn't get converted to
Alex gmail.com> writes: > > > I'm working on my first Django project and I can't seem to get > information printed out as I would like it. I'm trying to print out > quotes to a page with the newlines turned into HTML tags (similar > to PHP's nl2br function). So far I've been able to do this using the > __str__ function for the Quote model, but it escapes the tags into > html entities that I see the tags in my browser instead of the line > breaks. I'm using the development version of Django. > Hi Alex AFAIK the Django dev version automatically escapes output unless you mark it safe. Check the docs for more info. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Custom model field for sequence-functionality
Hello, what I need is a modelField that provides sequence-functionality for a model. This field should have the following features: - auto_increment when a new instance of the Model is created - a method move_up() // Increments the sequence of the object - a method move_down() // Decreases the sequence of the object - a method sync_order() // Syncronizes all sequences; This sould be called when a certain model-instance was deleted. The method finds the "hole" and decreses all other items greater than the one that was deleted. My plan was to extend PositiveIntegerField and adding the desired functionality. But I could not figure out how to add auto_increment, without falling back to raw sql. ...and how to add the 3 methods I mentioned above Here a short example how a Model containing the SequenceField should be used: n = News.objects.get(pk = id) n.moveUp() || n.moveDown() I am relativley new to Django, and need some help of how to implement this custom model field. Thanks, Toni --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
JonSidnell pisze: > It's been a wee while since I stuck my toes in the Linux waters, so I > was wondering if anyone here has any recommendations for a dev machine > setup? Due to the django host I've signed with, I'm largely stuck with > MySQL, and don't mind using the manage.py dev server while actually > developing. Everything else is up for grabs in my mind - distro, > editor, desktop manager skin, whatever! Although I'm unlikely to man > up to something like emacs or vi for code editing... > > What works for you? If you ever plan to use PostgreSQL instead of MySQL, stay away from OpenSuse 10.3, I did not found a way to have working psycopg1 in this distro. I'd recommend Ubuntu, but YMMV. -- Jarek Zgoda Skype: jzgoda | GTalk: [EMAIL PROTECTED] | voice: +48228430101 "We read Knuth so you don't have to." (Tim Peters) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
hi Jon ubuntu certainly works like a charm and you may want to use eclipse with pydev, just like on windows. i use it on both platforms (even on the same machine using a shared partition). cheers André On Fri, May 16, 2008 at 12:24 PM, JonSidnell <[EMAIL PROTECTED]> wrote: > > Hi everyone > > I'm suddenly struck by the notion that I would like to be dev'ing > Django on Linux of some flavour rather than Windows. > > It's been a wee while since I stuck my toes in the Linux waters, so I > was wondering if anyone here has any recommendations for a dev machine > setup? Due to the django host I've signed with, I'm largely stuck with > MySQL, and don't mind using the manage.py dev server while actually > developing. Everything else is up for grabs in my mind - distro, > editor, desktop manager skin, whatever! Although I'm unlikely to man > up to something like emacs or vi for code editing... > > What works for you? > > Cheers > Jon > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
On 16-May-08, at 3:54 PM, JonSidnell wrote: > What works for you? try mandriva spring 2008 - perfect for people migrating from the windows world -- regards kg http://lawgon.livejournal.com http://nrcfosshelpline.in/code/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django and Linux distros
JonSidnell gmail.com> writes: > > > Hi everyone > > I'm suddenly struck by the notion that I would like to be dev'ing > Django on Linux of some flavour rather than Windows. > > It's been a wee while since I stuck my toes in the Linux waters, so I > was wondering if anyone here has any recommendations for a dev machine > setup? Due to the django host I've signed with, I'm largely stuck with > MySQL, and don't mind using the manage.py dev server while actually > developing. Everything else is up for grabs in my mind - distro, > editor, desktop manager skin, whatever! Although I'm unlikely to man > up to something like emacs or vi for code editing... > > What works for you? > Hello mate I've been using Ubuntu 8.04 desktop on my macbook. It's really superb. I prefer gnome because in Ubuntu it is so much more polished. I can also get apache, mysql, etc running, along with any revision control system I desire - which at the moment means Bazaar. For actually editing I use Gedit, with the extra plugins installed, and all snippets etc enabled. If I don't feel like Gedit I use Komodo IDE. I think we both need to do some soul-searching to pluck up enough courage to take on the mighty beasts of Vi and Emacs!! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Django and Linux distros
Hi everyone I'm suddenly struck by the notion that I would like to be dev'ing Django on Linux of some flavour rather than Windows. It's been a wee while since I stuck my toes in the Linux waters, so I was wondering if anyone here has any recommendations for a dev machine setup? Due to the django host I've signed with, I'm largely stuck with MySQL, and don't mind using the manage.py dev server while actually developing. Everything else is up for grabs in my mind - distro, editor, desktop manager skin, whatever! Although I'm unlikely to man up to something like emacs or vi for code editing... What works for you? Cheers Jon --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
On Fri, May 16, 2008 at 5:02 AM, ydjango <[EMAIL PROTECTED]> wrote: > I have propriety commercial code and some formula/ algo > implementations which I do not want to expose. > Hence I do not want to upload .py source files If your host's setup would allow other users to view this code, you have much larger and much more dangerous security problems to worry about (since, for example, that would mean they could also see sensitive passwords in configuration files). -- "Bureaucrat Conrad, you are technically correct -- the best kind of correct." --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
ydjango gmail.com> writes: > I have propriety commercial code and some formula/ algo > implementations which I do not want to expose. > Hence I do not want to upload .py source files > > Is rewriting that business logic in a compiled langauge only way out? > how do I call it from python, Using web services? > No no, I have come across a number of ways of obfuscating Python code, just have a search. Using the .pyc files provides weaker obfuscation which may or may not be enough. Can you not simply do something using rsync: rsync -vrlptzH --delete --progress /home/user/*.pyc \ [EMAIL PROTECTED]:/home/user/www Can't remember what exactly to get rsync to only copy pyc files but check the man pages. Otherwise you could look at scp. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: how to avoid uploading .py source files to shared hosting server
I have propriety commercial code and some formula/ algo implementations which I do not want to expose. Hence I do not want to upload .py source files Is rewriting that business logic in a compiled langauge only way out? how do I call it from python, Using web services? Ashish On May 15, 2:51 pm, jonknee <[EMAIL PROTECTED]> wrote: > > I want to upload only .pyc and no source files. Whats the best way to > > make sure my .pyc works there. > > Your best bet is to probably upload the .py files, run the app and > then delete the .py files. That way you're sure that the .pyc files > are compatible. But unless you really need to get rid of the .py > files, you should leave them be. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
hot pictures of indian actress, models and fashion shows
hot pictures of indian actress, models and fashion shows http://cutehyderabadbabes.blogspot.com/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Printing out HTML that doesn't get converted to
Alex wrote:
> I'm working on my first Django project and I can't seem to get
> information printed out as I would like it. I'm trying to print out
> quotes to a page with the newlines turned into HTML tags (similar
> to PHP's nl2br function). So far I've been able to do this using the
> __str__ function for the Quote model, but it escapes the tags into
> html entities that I see the tags in my browser instead of the line
> breaks. I'm using the development version of Django.
>
> Here's what my __str__ function looks like:
>
> return self.quote.replace('\n', '')
>
> And I'm just printing them out with a generic view that looks like
> this:
>
> {% for quote in object_list %}
> {{ quote }}
You need to run your HTML through the safe filter.
Django auto escapes HTML.
so the above would be {{ quote|safe}}
see
http://www.djangoproject.com/documentation/templates/#automatic-html-escaping
adi
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Mysql vs. sqlite filtering of datetimefields with None values
I have recently come across a slight difference in the way that datetimefields are handled by mysql and sqlite. Locally, on my desktop I use sqlite for debugging, while the production server runs mysql. Running django-trunk. One of my models includes a datetimefield: last_fetched = models.DateTimeField(null=True, blank=True) In some of my instances the field is still None, while others have a datetime set. When trying to filter on the instances where the datetime is earlier/lower than a given date or the datetime is still None I initially tried something along the lines of: queryset_something.exclude(last_fetched__gt=given_date) On sqlite this returned both the datetimes that where lower and the once not yet set. On mysql, however, it did not return the empty datetimes. I then tried to use Q-objects, like this: queryset_something.filter(Q(last_fetched__lt=given_date) | Q(last_fetched__isnull = True)) This worked, but I keep wondering if this is the best sollution and if this actually is an unwanted inconsistency of Django. Comments? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Uploading files to subdirectories
Hi All,
I'm new to Django and I'm not sure how best to achieve the following:
Users may upload files - each uploaded file is tied to a user in the
database using a ForeignKey.
In order to prevent pain to the underlying O/S I don't want to put all
these files in to a single directory. I could separate the files by
upload time as mentioned in the Django documentation, but it would be
nicer to have all the files uploaded by a single user under a single
subdirectory.
Example:
Greg uploads "holiday.rtf", it is saved as /media/uploads/greg/
holiday.rtf
Sally uploads "family.rtf", it is saved as /media/uploads/sally/
family.rtf
My current model:
class FileModel(models.Model):
user = models.ForeignKey(User)
file = models.FileField(upload_to = 'uploads/'
I am saving the file using FileModel_Instance.save_file_file('path',
file_contents). Adding extra folders to the path (i.e. path = greg/
holiday.rtf) doesn't work - I assume this is a security restriction.
I am using the SVN version of Django. Any help would be appreciated.
Regards,
James
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Re: MySQL Boolean vs. PostgresQL Boolean
On Thu, May 15, 2008 at 7:04 PM, Szaijan <[EMAIL PROTECTED]> wrote: > > I see it in my views. When I return the set and saved values for a > model, I get True or False from my app on the MacBook (Postgres) and 1 > or 0 from the exact same code on my Slicehost site (MySQL.) > > So, if I add something like: > > m = Model.objects.get(id=id) > print m.boolean_field_name > > I get True/False on my MacBook and 1/0 on my Slicehost site. I have > also confirmed this in python manage.py shell. > > >>> from visionary.harp.models import Combatant_Template > >>> ct = Combatant_Template.objects.all() > >>> ct[0] > > >>> ct[0].party <--- A BooleanField > 0 <-- result on Slicehost site using MySQL > > >>> ct[0].party <--- A BooleanField > True <-- result on MacBook Pro using PostgreSQL > > Perhaps there's a setting I need that is missing? > Hmm, that's interesting, and I never noticed it. I guess I haven't interrogated values directly like that. That does seem odd, I'd expect a boolean field to be returning a boolean value. But in Python 1 == True evaluates to True and 0 == False evaluates to True, so your code doesn't really need to care one way or the other what is returned, does it? I also see on further looking around that there is a ticket open on this: http://code.djangoproject.com/ticket/7190 Also note you don't have to supply 0/1 when querying. You can filter values, e.g. on True/False and that works properly. Karen --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Boolean Values: PostgreSQL vs. MySQL
On Thu, May 15, 2008 at 1:59 PM, Szaijan <[EMAIL PROTECTED]> wrote: > Hi, I developed my first Django app on my Macbook Pro using PostgreSQL > and > have recently moved it to a production site which uses MySQL. > PostgreSQL stores boolean values as True and False, just like Python > and JS, while MySQL uses 1 and 0. > > Is there some automated way to get the models to understand this and > present/save boolean values to and from views, or do I need to > override the save and get methods so that they translate 0 to False, 1 > to True, and vice versa? This seems to be a barrier to portability if > I have to hard code DB awareness into my models. > You don't need to do anything, the right thing will just happen. Your Python/Django code deals with boolean fields and doesn't need to know anything about the details of how MySQL stores them. (Unless you use raw sql, in which case you might have to care.) Karen --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
