Re: Marijuana

2001-06-24 Thread David C. Ullrich

On Sat, 23 Jun 2001 23:35:06 GMT, Tetsuo [EMAIL PROTECTED]
wrote:

in article [EMAIL PROTECTED], Tetsuo at
[EMAIL PROTECTED] wrote on 24-06-2001 00:17:

 in article [EMAIL PROTECTED], David C. Ullrich at
 [EMAIL PROTECTED] wrote on 23-06-2001 16:06:
 
[obvious jokes'

[explanation of why the assertions in the obvious jokes are wrong] 

[...]

Sorry for that indeed, ppl actually have this kind of opinion on this
sometimes so I assumed I encountered just another one and got irritated. I
should've realized the poster would not spout such stupidity in a serious
manner though, of course...heh, certainly not in this ng.

No problem, actually I enjoyed reading it. Slightly disappointing
that you finally figured out I was being sarcastic - when I read
your post I was looking forward to stringing you along a bit.

Well, sorry again




David C. Ullrich
*
Sometimes you can have access violations all the 
time and the program still works. (Michael Caracena, 
comp.lang.pascal.delphi.misc 5/1/01)


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Re: Marijuana

2001-06-24 Thread David C. Ullrich

On Sat, 23 Jun 2001 21:12:40 -0700, Chas F Brown
[EMAIL PROTECTED] wrote:



David C. Ullrich wrote:
 
[...]

In the back-of-envelope calculations I did, this is really the key
missing information. If heart attacks are evenly distributed through the
day, while MJ smoking (as far as I know!) clearly isn't for most users,
then the temporal correlation is going to be alot more marked.

 Or they tend to smoke
 before meals (I knew some people like that years ago in college)
 and tend to have heart attacks after meals. Or they tend to
 smoke when they start to feel little chest pains, as someone
 suggested.
 

But you're reading something into what I said, that I didn't say - I'm
not saying that the data imply that smoking _causes_ an increased your
risk of heart attack in the hour after smoking (although this evidence
would support further investigation that that _may_ be the case).

Ok.

[...]

 
 David C. Ullrich
 *
 Sometimes you can have access violations all the
 time and the program still works. (Michael Caracena,
 comp.lang.pascal.delphi.misc 5/1/01)

The scary thing is - he's right.

That's one scary thing - in fact there are places in
Windows95 where the system _regularly_ creates GPF's;
something to do with thunking or something.

But the scary thing about the quote is that the
guy was advocating _hiding_ AV's in programs we
write instead of fixing them. AV's can be hard to
debug - the eaiest way is to make certain they
don't arise in the first place. And given this
guy's attitude, one of the steps involved in
ensuring that your code contains no hard-to-debug
AV's is making sure you never use anything
he wrote. Hence the sig - it's a public-service
thing.

 (Ooops! Netscape just locked up - time
to reboot again...)

Cheers - Chas

---
C Brown Systems Designs
Multimedia Environments for Museums and Theme Parks
---



David C. Ullrich
*
Sometimes you can have access violations all the 
time and the program still works. (Michael Caracena, 
comp.lang.pascal.delphi.misc 5/1/01)


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Help with stats please

2001-06-24 Thread Melady Preece

Hi.  I am teaching educational statistics for the first time, and although I
can go on at length about complex statistical techniques, I find myself at a
loss with this multiple choice question in my test bank.  I understand why
the range of  (b) is smaller than (a) and (c), but I can't figure out how to
prove that it is smaller than (d).

If you can explain it to me, I will be humiliated, but grateful.


1.  Which one of the following classes had
 the smallest range in IQ scores?

 A)  Class A has a mean IQ of 106
   and a standard deviation of ll.
 B)  Class B has an IQ range from 93
   to 119.
 C)  Class C has a mean IQ of 110
   with a variance of 200.
  D)  Class D has a median IQ of 100
   with Q1 = 90 and Q3 = 110.

The test bank says the answer is b.

Melady





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Re: Help with stats please

2001-06-24 Thread dennis roberts

At 12:20 PM 6/24/01 -0700, Melady Preece wrote:
Hi.  I am teaching educational statistics for the first time, and although I
can go on at length about complex statistical techniques, I find myself at a
loss with this multiple choice question in my test bank.  I understand why
the range of  (b) is smaller than (a) and (c), but I can't figure out how to
prove that it is smaller than (d).

If you can explain it to me, I will be humiliated, but grateful.


1.  Which one of the following classes had
  the smallest range in IQ scores?

of course, there is nothing about the shape of the distribution of any 
class ... so, does the item assume sort of normal? in fact, since each of 
these classes is probably on the small side ... it would be hard to assume 
that but, for the sake of the item ... pretend

in addition, it does not say to assume the population of IQ scores has mean 
= 100 and sd about 15 ... so, whether this plays a role or not, i am not 
sure BUT ...


  A)  Class A has a mean IQ of 106
and a standard deviation of ll.

at least about 2 units of 11 = 22 on each side of 106 ... range about 45 or 
so or more

  B)  Class B has an IQ range from 93
to 119.

well, range here is about 26 ... less than in A for sure

  C)  Class C has a mean IQ of 110
with a variance of 200.

variance of 200 means an sd about 14 ... so 2 units of 14 = 28 on each side 
of 110 ...
range must be 50 or more ... similar to A but, more than C

   D)  Class D has a median IQ of 100
with Q1 = 90 and Q3 = 110.

25th PR = 90 and 75PR = 110 ... IF we assumed the class was ND ... then the 
mean would be about 100 too ... and since -1 for SD below the mean and +1 
SD above the mean would give your roughly the 16th PR and 84th PR ... Q1 
and Q3 are NOT that far out ... so, the SD must be at least 10 or more ... 
thus, 2 units of at least 10 = 20 on either side of 100 = range of at least 
about 40 ... probably less than A or C ... but, more than B ...

B is probably the best of the lot BUT, i am NOT sure what the real purpose 
of this item is ...


The test bank says the answer is b.

Melady





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_
dennis roberts, educational psychology, penn state university
208 cedar, AC 8148632401, mailto:[EMAIL PROTECTED]
http://roberts.ed.psu.edu/users/droberts/drober~1.htm



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Re: cigs figs

2001-06-24 Thread Rich Ulrich

  - re: some outstandingly confused thinking.  Or writing.

On Sat, 23 Jun 2001 15:25:31 GMT, mackeral@remove~this~first~yahoo.com
(J. Williams) wrote:

[ snip;  Slate reference, etcetera ]
   ... My mother was 91 years
 old when she died  a year ago and chain smoked since her college days.
 She defended the tobacco companies for years saying, it didn't hurt
 me.  She outlived most of her doctors.   Upon quoting statistics and
 research on the subject, her view was that I, like other do gooders
 and non-smokers, wanted to deny smokers their rights.  

What statistics would her view quote?  to show that someone
wants to deny smokers 'their rights'?
[ Hey, I didn't write the sentence ]

I just love it, how a 'natural right'  works out to be *exactly*
what the speaker wants to do.  And not a whit more.
(Thomas and Scalia are probably going to give us tons 
of that bad philosophy, over the next decades.)

What rights are denied to smokers?  You know, you can't 
build your outhouse right on the riverbank, either.

Obviously,
 there is a health connection.  How strong that connection is, is what
 makes this a unique statistical conundrum.

How strong is that connection?  Well, quite strong.

I once considered that it might not be so bad to die 9 years
early, owing to smoking, if that cut off years of bad health 
and suffering.  Then I realized, the smoking grants you 
most of the bad health of old age, EARLY.  (You do miss 
the Alzheimer's.)  One day, I might give up smoking my pipe.

What is the statistical conundrum?  I can almost 
imagine an ethical conundrum.  (How strongly can
we legislate, to encourage cyclists to wear helmets?)
I sure don't spot a statistical conundrum.

Is this word intended?  If so, how so?

-- 
Rich Ulrich, [EMAIL PROTECTED]
http://www.pitt.edu/~wpilib/index.html


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Re: Help with stats please

2001-06-24 Thread Donald Burrill

On Sun, 24 Jun 2001, Melady Preece wrote in part:

 I am teaching educational statistics for the first time, and although I 
 can go on at length about complex statistical techniques, I find myself 
 at a loss with this multiple choice question in my test bank.  I 
 understand why the range of (b) is smaller than (a) and (c), but I 
 can't figure out how to prove that it is smaller than (d).
 
 1.  Which of the following classes had the smallest range in IQ scores? 
 
  A)  Class A has a mean IQ of 106 and a standard deviation of ll.
  B)  Class B has an IQ range from 93 to 119.
  C)  Class C has a mean IQ of 110 with a variance of 200.
  D)  Class D has a median IQ of 100 with Q1 = 90 and Q3 = 110.
 
 The test bank says the answer is b.

Right.  Since you're happy that  range(B)  range(A)  and 
range(B)  range(C),  I'll focus on  (B) vs. (D).
In (B), the entire _range_ is from 93 to 119:  26 (or 27, 
depending on how you choose to define range) points.
In (D), the central half of the distribution is from 90 to 110: 
the interquartile range (IQR) is 20 points, symmetric about the median;  
the full range must therefore be greater than 20.  Now, _if_ the 
distribution is normal (which may be what we were to assume from the 
allegation that these are IQ scores;  although as Dennis has pointed out, 
ille non sequitur -- unless these are rather large classes AND NOT 
SELECTED BY I.Q. (or by any variable strongly related to I.Q.)), then 10 
points from Q1 to median (or from median to Q3) represents 0.67 standard 
deviation, which implies a standard deviation of about 15, which is 
larger than the standard deviation in (A) and slightly larger than that 
in (C).
However, we need not invoke the normal distribution.  We observe 
that the distribution in (D) is at least approximately symmetric (insofar 
as the quartiles are equidistant from the median).  If we may assume also 
that the distribution is unimodal (which I should think reasonable), it 
then follows (from the tailing off of distributions as one approaches 
the extremes) that the distance from minimum to Q1 (and the distance from 
Q3 to maximum) is greater than the distance from Q1 to median (or median 
to Q3).  This implies that the range of the distribution exceeds twice 
the interquartile range:  that is,  range(D)  2*20 = 40.  Since the 
range in (B) is only 26, clearly the range of (B) is less than the range 
of (D).

If any part of this argument remains unclear, I'd be happy to attack it 
again.  A rough sketch should make things pretty obvious, but it's a bit 
of a nuisance to draw pictures in ASCII characters!
--DFB.
 
 Donald F. Burrill [EMAIL PROTECTED]
 184 Nashua Road, Bedford, NH 03110  603-471-7128


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