Re: [PSES] IEC 61010-1 Table K.17

2015-08-12 Thread Doug Powell
Rich,

I can see your point.  As a result of rapid polarity reversals, the
acceleration of an ion across the mean free path of a gas will be halted
and even reversed. I will read this paper to gain a better understanding
but at this time I believe this will only affect gas breakdown as a result
of impact ionization.

Thanks for the link,

Doug




On Tue, Aug 11, 2015 at 5:08 PM, Richard Nute ri...@ieee.org wrote:





 Hi Doug:





 A simple (and therefore incomplete) explanation:



 Breakdown in air requires the ions to travel from one pole to the other
 before the polarity reverses.  At high frequencies, the polarity reverses
 before the ions can travel the distance between the poles.



 At high frequencies (compared to mains frequencies) the clearance can be
 less.  See:



 http://lss.fnal.gov/archive/other/ssc/sscl-539.pdf


 http://ewh.ieee.org/r10/taiwan/pses/archive/2012_04_27/IEEE%20PSES%20April/TC108%20hf_FC_v.1.2_IEEE%20PSES%20TAI.pdf







 Best regards,

 Rich





 -- Original Message --
 From: Doug Powell doug...@gmail.com
 To: EMC-PSTC@LISTSERV.IEEE.ORG
 Subject: [PSES] IEC 61010-1 Table K.17
 Date: Fri, 7 Aug 2015 16:47:28 -0600

 All,

 I am evaluating spacings for an RF product that operates at 13.56 MHz and
 can produce maximum voltages of 5,000 Vrms (7,070 Vpk).  If I do an
 interpolation of using Table 6 (Mains 230 V, OV Cat II, indexing on 5,000
 Vrms), I get a minimum clearance requirement of 14.9 mm.  When I do the
 same calculation on Table K.17 (column 3, indexing on 7,070 Vpk), I get
 12.7 mm.

 Now I understand the effects of high frequency voltage stress causing air
 molecules to become more energetic and therefore more likely to break down
 at lower voltages.  So why in this case does IEC 61010-1 Table K.17 result
 in lower clearance values than Table 6?  Somehow, this just seems wrong.

 *Please note that in the case of high frequencies paragraph K.3.1
 indicates I am to skip over section K.3.2 with the D1 + F × (D2 – D1)
 calculations.*

 Thanks a bunch!

 Doug

 Douglas E Powell
 doug...@gmail.com
 http://www.linkedin.com/in/dougp01




-- 

Douglas E Powell

doug...@gmail.com
Skype: doug.powell52
http://www.linkedin.com/in/dougp01

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Re: [PSES] IEC 61010-1 Table K.17

2015-08-11 Thread Brian Gregory
  Doug, The standard must assume the RF circuits are even more energy-limited 
than secondary circuits is my best guess.  If so, it doesn't say that anywhere 
I could find.  It takes voltage, but also energy to create an ionizing path.   
Regards,  Brian Gregory
720-450-4933

-- Original Message --
From: Doug Powell doug...@gmail.com
To: EMC-PSTC@LISTSERV.IEEE.ORG
Subject: [PSES] IEC 61010-1 Table K.17
Date: Fri, 7 Aug 2015 16:47:28 -0600


All,
 
 I am evaluating spacings for an RF product that operates at 13.56 MHz and can 
produce maximum voltages of 5,000 Vrms (7,070 Vpk).  If I do an interpolation 
of using Table 6 (Mains 230 V, OV Cat II, indexing on 5,000 Vrms), I get a 
minimum clearance requirement of 14.9 mm.  When I do the same calculation on 
Table K.17 (column 3, indexing on 7,070 Vpk), I get 12.7 mm.  
 
 Now I understand the effects of high frequency voltage stress causing air 
molecules to become more energetic and therefore more likely to break down at 
lower voltages.  So why in this case does IEC 61010-1 Table K.17 result in 
lower clearance values than Table 6?  Somehow, this just seems wrong.
 
 Please note that in the case of high frequencies paragraph K.3.1 indicates I 
am to skip over section K.3.2 with the D1 + F × (D2 ndash; D1) calculations.
 
 Thanks a bunch!
 
 Doug
 
 Douglas E Powell
 doug...@gmail.com
 http://www.linkedin.com/in/dougp01
-
 
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Re: [PSES] IEC 61010-1 Table K.17

2015-08-11 Thread Richard Nute
 

 

Hi Doug:  

 

 

A simple (and therefore incomplete) explanation:

 

Breakdown in air requires the ions to travel from
one pole to the other before the polarity
reverses.  At high frequencies, the polarity
reverses before the ions can travel the distance
between the poles.  

 

At high frequencies (compared to mains
frequencies) the clearance can be less.  See:

 

http://lss.fnal.gov/archive/other/ssc/sscl-539.pdf

http://ewh.ieee.org/r10/taiwan/pses/archive/2012_0
4_27/IEEE%20PSES%20April/TC108%20hf_FC_v.1.2_IEEE%
20PSES%20TAI.pdf

 

 

 

Best regards,

Rich

 

 

-- Original Message --
From: Doug Powell doug...@gmail.com
mailto:doug...@gmail.com 
To: EMC-PSTC@LISTSERV.IEEE.ORG
mailto:EMC-PSTC@LISTSERV.IEEE.ORG 
Subject: [PSES] IEC 61010-1 Table K.17
Date: Fri, 7 Aug 2015 16:47:28 -0600

All,

I am evaluating spacings for an RF product that
operates at 13.56 MHz and can produce maximum
voltages of 5,000 Vrms (7,070 Vpk).  If I do an
interpolation of using Table 6 (Mains 230 V, OV
Cat II, indexing on 5,000 Vrms), I get a minimum
clearance requirement of 14.9 mm.  When I do the
same calculation on Table K.17 (column 3, indexing
on 7,070 Vpk), I get 12.7 mm.  

Now I understand the effects of high frequency
voltage stress causing air molecules to become
more energetic and therefore more likely to break
down at lower voltages.  So why in this case does
IEC 61010-1 Table K.17 result in lower clearance
values than Table 6?  Somehow, this just seems
wrong.

Please note that in the case of high frequencies
paragraph K.3.1 indicates I am to skip over
section K.3.2 with the D1 + F × (D2 – D1)
calculations.

Thanks a bunch!

Doug

Douglas E Powell
doug...@gmail.com mailto:doug...@gmail.com 
http://www.linkedin.com/in/dougp01


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[PSES] IEC 61010-1 Table K.17

2015-08-07 Thread Doug Powell

All,

I am evaluating spacings for an RF product that operates at 13.56 MHz 
and can produce maximum voltages of 5,000 Vrms (7,070 Vpk).  If I do an 
interpolation of using Table 6 (Mains 230 V, OV Cat II, indexing on 
5,000 Vrms), I get a minimum clearance requirement of 14.9 mm.  When I 
do the same calculation on Table K.17 (column 3, indexing on 7,070 Vpk), 
I get 12.7 mm.


Now I understand the effects of high frequency voltage stress causing 
air molecules to become more energetic and therefore more likely to 
break down at lower voltages.  So why in this case does IEC 61010-1 
Table K.17 result in lower clearance values than Table 6?  Somehow, this 
just seems wrong.


/Please note that in the case of high frequencies paragraph K.3.1 
indicates I am to skip over section K.3.2 with the D1 + F × (D2 – D1) 
calculations./


Thanks a bunch!

Doug

Douglas E Powell
doug...@gmail.com
http://www.linkedin.com/in/dougp01




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list. To post a message to the list, send your e-mail to emc-p...@ieee.org

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