Re:RE: Charge moving from decoupling capacitors

2000-05-24 Thread Jim Bacher

Forwarded for George..

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/23/00 12:35 PM

Let's say that you have a cap placed at 1/4 wavelength away from an IC pwr
pin.  When the IC draws current from the Pwr/gnd planes, it causes a voltage
dip/pwr bounce on the parallel planes.  This voltage dip propagates to the
cap at 1/4 wavelength away and draws current out of the cap.  The current
from the cap propagates back to the IC pwr pin at 1/4 wavelength away.  The
total travel for the incident and reflected wave is 1/4 + 1/4 = 1/2
wavelength.  The supply current is 180 degrees out of phase from the IC
switching current.  Some people say that the cap needs to be closer than 1/2
of rising edge.  But you can also calculate the wavelength of the 3rd and
5th harmonic of your pulse to determine your cap placement.  

Regards, 

George Tang
george_t...@dell.com



-Original Message-
From: Roncone Paolo [mailto:paolo.ronc...@compuprint.it]
Sent: Tuesday, May 23, 2000 7:15 AM
To: 'george_t...@dell.com '; 'barry...@altavista.com '
Cc: 'emc-p...@ieee.org '
Subject: RE: Charge moving from decoupling capacitors



George,
can you pls explain your correction ?
I supposed your first statement (At 1/4 wavelength, the charges are 90 
degrees out of phase) was the correct one ! 

Paolo Roncone
Compuprint s.p.a.

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/22/00 9:14 PM

Barry, 

I need to make a correction.  I was rushing to lunch on Thursday, so I
did
not read over what I wrote.  Here is the correction for the 2nd comment
below: 

At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
working against the IC current draw.  1/8 wavelength (90 degrees out of
phase) is what I consider to be acceptable.  

Regards, 

George Tang
george_t...@dell.com



-Original Message-
From: Tang, George 
Sent: Thursday, May 18, 2000 12:31 PM
To: 'Barry Ma'; Tang, George
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


Barry, 

Thanks for the comments.  Here are my comments:  

Ok, you put caps at a certain distance away from the IC because you only
want them to work at 100 MHz.  But that distance turns out to be the 1/4
wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
distance to cause board resonance.  Now what?  Do you tell the caps not
to
work at 400 MHz because it's not their frequency?  


For your 2nd comment:

I used the words loosely define for that reason.  If you are
interested in
high frequency decoupling and instantaneous current, you really want to
have
all your charges moving in phase.  At 1/4 wavelength, the charges are 90
degrees out of phase, so they will not do much for your instantaneous
current.  1/8 wavelength is what I consider to be acceptable.  You can
certainly pick a different number.  

Regards, 

George Tang
george_t...@dell.com



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[SI-LIST] : RE: Charge moving from decoupling capacitors

2000-05-23 Thread George_Tang
Barry, 

The current can flow from the cap, but it will get to the IC at the wrong
time.  

Regards,
George
george_t...@dell.com

-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Tuesday, May 23, 2000 10:22 AM
To: george_t...@exchange.dell.com
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors



George,

I am impressed by your attitude to pursue the correctness, and glad to
discuss with you further on “How does a decoupling capacitor support an IC?”

Here is my two cents worth. The decap supplies necessary charge to the IC
during Tr through a transmission line. As you mentioned before: “The current
is an impulse function, although the voltage waveform is a step function.”
This impulse function, actually a bell-like function on Tr, happens every
time period T when the IC gate switches from low to high. The corresponding
frequency spectrum contains lots of frequencies. There must be some
frequencies making the transmission line a 1/4, 3/4, ... wavelength. It is
hard for me to be convinced that currents of those frequencies cannot flow
from the decap to the IC. ... Pleas correct me if misunderstood. Thanks.

Regards,
Barry Ma
b...@anritsu.com


On Mon, 22 May 2000, george_t...@dell.com wrote:

 
 Barry, 
 
 I need to make a correction.  I was rushing to lunch on Thursday, so I did
 not read over what I wrote.  Here is the correction for the 2nd comment
 below: 
 
 At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
 working against the IC current draw.  1/8 wavelength (90 degrees out of
 phase) is what I consider to be acceptable.  
 
 Regards, 
 
 George Tang
 george_t...@dell.com


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RE: Charge moving from decoupling capacitors

2000-05-23 Thread Barry Ma

George,

I am impressed by your attitude to pursue the correctness, and glad to discuss 
with you further on “How does a decoupling capacitor support an IC?”

Here is my two cents worth. The decap supplies necessary charge to the IC 
during Tr through a transmission line. As you mentioned before: “The current is 
an impulse function, although the voltage waveform is a step function.” This 
impulse function, actually a bell-like function on Tr, happens every time 
period T when the IC gate switches from low to high. The corresponding 
frequency spectrum contains lots of frequencies. There must be some frequencies 
making the transmission line a 1/4, 3/4, ... wavelength. It is hard for me to 
be convinced that currents of those frequencies cannot flow from the decap to 
the IC. ... Pleas correct me if misunderstood. Thanks.

Regards,
Barry Ma
b...@anritsu.com


On Mon, 22 May 2000, george_t...@dell.com wrote:

 
 Barry, 
 
 I need to make a correction.  I was rushing to lunch on Thursday, so I did
 not read over what I wrote.  Here is the correction for the 2nd comment
 below: 
 
 At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
 working against the IC current draw.  1/8 wavelength (90 degrees out of
 phase) is what I consider to be acceptable.  
 
 Regards, 
 
 George Tang
 george_t...@dell.com


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RE: Charge moving from decoupling capacitors

2000-05-23 Thread Roncone Paolo

George,
can you pls explain your correction ?
I supposed your first statement (At 1/4 wavelength, the charges are 90 
degrees out of phase) was the correct one ! 

Paolo Roncone
Compuprint s.p.a.

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/22/00 9:14 PM

Barry, 

I need to make a correction.  I was rushing to lunch on Thursday, so I
did
not read over what I wrote.  Here is the correction for the 2nd comment
below: 

At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
working against the IC current draw.  1/8 wavelength (90 degrees out of
phase) is what I consider to be acceptable.  

Regards, 

George Tang
george_t...@dell.com



-Original Message-
From: Tang, George 
Sent: Thursday, May 18, 2000 12:31 PM
To: 'Barry Ma'; Tang, George
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


Barry, 

Thanks for the comments.  Here are my comments:  

Ok, you put caps at a certain distance away from the IC because you only
want them to work at 100 MHz.  But that distance turns out to be the 1/4
wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
distance to cause board resonance.  Now what?  Do you tell the caps not
to
work at 400 MHz because it's not their frequency?  


For your 2nd comment:

I used the words loosely define for that reason.  If you are
interested in
high frequency decoupling and instantaneous current, you really want to
have
all your charges moving in phase.  At 1/4 wavelength, the charges are 90
degrees out of phase, so they will not do much for your instantaneous
current.  1/8 wavelength is what I consider to be acceptable.  You can
certainly pick a different number.  

Regards, 

George Tang
george_t...@dell.com



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Fwd:RE: Charge moving from decoupling capacitors

2000-05-23 Thread Jim Bacher

for George

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/22/00 9:14 PM

Barry, 

I need to make a correction.  I was rushing to lunch on Thursday, so I did
not read over what I wrote.  Here is the correction for the 2nd comment
below: 

At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
working against the IC current draw.  1/8 wavelength (90 degrees out of
phase) is what I consider to be acceptable.  

Regards, 

George Tang
george_t...@dell.com



-Original Message-
From: Tang, George 
Sent: Thursday, May 18, 2000 12:31 PM
To: 'Barry Ma'; Tang, George
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


Barry, 

Thanks for the comments.  Here are my comments:  

Ok, you put caps at a certain distance away from the IC because you only
want them to work at 100 MHz.  But that distance turns out to be the 1/4
wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
distance to cause board resonance.  Now what?  Do you tell the caps not to
work at 400 MHz because it's not their frequency?  


For your 2nd comment:

I used the words loosely define for that reason.  If you are interested in
high frequency decoupling and instantaneous current, you really want to have
all your charges moving in phase.  At 1/4 wavelength, the charges are 90
degrees out of phase, so they will not do much for your instantaneous
current.  1/8 wavelength is what I consider to be acceptable.  You can
certainly pick a different number.  

Regards, 

George Tang
george_t...@dell.com


-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Thursday, May 18, 2000 10:50 AM
To: george_t...@exchange.dell.com
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


George,

Thanks for your long input. I'd like to make some comments below.
-
On Wed, 17 May 2000, george_t...@dell.com wrote:

 Large parallel plates behave as transmission lines.  A quarter wavelength
 transmission line with a short at the end has infinite impedance, so
 capacitors placed 1/4 wavelength away are bad.  

That's why decaps work on low frequency portion. Let's set 100 MHz and below
for decaps to cover. The wavelength at 100 MHz is 3 meters. A quarter of it
is 75 cm. It's long enough to ordinary PCB size. (The cap is directly
connected to pwr/gnd planes.)


 This means that we can loosely define the largest usable board area
capacitance as 1/8 
 wavelength radius of copper surrounding the IC power pin.  Charges stored
on the planes
 further than 1/8 wavelength away are not very usable due to the time
delay.
 At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
 good enough for your IC?  

George, I beg for differentials. How did you jump from capacitors placed
1/4 wavelength away are bad to the largest usable board area capacitance
as 1/8 wavelength radius?

Can I use the same token to infer from caps placed one wavelength away are
good to the largest usable board area capacitance is within 1/2 wavelength
radius? And so, and so on.

Regards,
Barry Ma
b...@anritsu.com



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[SI-LIST] : RE: Charge moving from decoupling capacitors

2000-05-23 Thread George_Tang
Barry, 

I need to make a correction.  I was rushing to lunch on Thursday, so I did
not read over what I wrote.  Here is the correction for the 2nd comment
below: 

At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
working against the IC current draw.  1/8 wavelength (90 degrees out of
phase) is what I consider to be acceptable.  

Regards, 

George Tang
george_t...@dell.com



-Original Message-
From: Tang, George 
Sent: Thursday, May 18, 2000 12:31 PM
To: 'Barry Ma'; Tang, George
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


Barry, 

Thanks for the comments.  Here are my comments:  

Ok, you put caps at a certain distance away from the IC because you only
want them to work at 100 MHz.  But that distance turns out to be the 1/4
wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
distance to cause board resonance.  Now what?  Do you tell the caps not to
work at 400 MHz because it's not their frequency?  


For your 2nd comment:

I used the words loosely define for that reason.  If you are interested in
high frequency decoupling and instantaneous current, you really want to have
all your charges moving in phase.  At 1/4 wavelength, the charges are 90
degrees out of phase, so they will not do much for your instantaneous
current.  1/8 wavelength is what I consider to be acceptable.  You can
certainly pick a different number.  

Regards, 

George Tang
george_t...@dell.com


-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Thursday, May 18, 2000 10:50 AM
To: george_t...@exchange.dell.com
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


George,

Thanks for your long input. I'd like to make some comments below.
-
On Wed, 17 May 2000, george_t...@dell.com wrote:

 Large parallel plates behave as transmission lines.  A quarter wavelength
 transmission line with a short at the end has infinite impedance, so
 capacitors placed 1/4 wavelength away are bad.  

That’s why decaps work on low frequency portion. Let’s set 100 MHz and below
for decaps to cover. The wavelength at 100 MHz is 3 meters. A quarter of it
is 75 cm. It’s long enough to ordinary PCB size. (The cap is directly
connected to pwr/gnd planes.)


 This means that we can loosely define the largest usable board area
capacitance as 1/8 
 wavelength radius of copper surrounding the IC power pin.  Charges stored
on the planes
 further than 1/8 wavelength away are not very usable due to the time
delay.
 At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
 good enough for your IC?  

George, I beg for differentials. How did you jump from capacitors placed
1/4 wavelength away are bad to the largest usable board area capacitance
as 1/8 wavelength radius?

Can I use the same token to infer from caps placed one wavelength away are
good to the largest usable board area capacitance is within 1/2 wavelength
radius? And so, and so on.

Regards,
Barry Ma
b...@anritsu.com



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Re: Charge moving from decoupling capacitors

2000-05-19 Thread Ralph Cameron

Barry

Thanks for correcting me. Practical solutions have changed from the time I
made many measurements on PCBs with discrete components. I'll be interested
to read the article you mentioned since I wasn't aware a single SMA cap
could do a better job.

Regards,

Ralph Cameron

- Original Message -
From: Barry Ma barry...@altavista.com
To: ral...@igs.net
Cc: emc-p...@ieee.org
Sent: Friday, May 19, 2000 11:33 AM
Subject: Re: Charge moving from decoupling capacitors


 Ralph,

 Please be cautious about what you said below: the reason why most power
buses on PCBs use several values of decoupling is to ensure that a wide
range of frequencies are covered.

 Several V curves shown in the figure of impedance vs. frequency, which we
are all familiar with, would easily convince us the above statement. But
those V curves only show the absolute value of impedance around
self-resonance frequency of various capacitors. If considering related phase
relations, the total impedance of several values of decaps would become not
as simple as we expected - having low impedance over wider frequecy range.
You may refer to an article by Paul, C. R.:

 Effectiveness of multiple decoupling capacitors, IEEE EMC Vol. 34, p.
130, May 1992.

 In my practice of using SMA caps, only the largest value of capacitance
available for given SMA size is selected, if I have a PCB with 10 mil or
less plane spacing.

 Regards,
 Barry Ma
 b...@anritsu.com

 
 On Thu, 18 May 2000, Ralph Cameron wrote:

  As I read in an article related to bypassing for good decoupling ( in
1971)
  one can select from a number of EIA values and by cutting the lead
lengths
  correctly ( e.g. from 1/2- less than 1/4  ) the series reonant
frequency
  will drop by a considerable amount so - yes, the reason why most power
buses
  on PCBs use several values of decoupling is to ensure that a wide range
of
  requencies are covered.  Perhaps, with surface mount caps, that is
easier to
  predict because they are essentially leadless.
 
  I once cured a very severe case of an FM receiver responding to the 7th
  harmonic of a 14Mhz transmitter because an untuned mixer was used.
Placing
  a 100pf cap with 1/4 leads right across the mixer IC completely cured
the
  problem without degrading mixer sensitivity.
 
  Ralph Cameron
  EMC Consultant for Suppression of Consumer Electronics
  (After Sale)


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Re: Charge moving from decoupling capacitors

2000-05-19 Thread Barry Ma

Ralph,

Please be cautious about what you said below: the reason why most power buses 
on PCBs use several values of decoupling is to ensure that a wide range of 
frequencies are covered.

Several V curves shown in the figure of impedance vs. frequency, which we are 
all familiar with, would easily convince us the above statement. But those V 
curves only show the absolute value of impedance around self-resonance 
frequency of various capacitors. If considering related phase relations, the 
total impedance of several values of decaps would become not as simple as we 
expected - having low impedance over wider frequecy range. You may refer to an 
article by Paul, C. R.:

Effectiveness of multiple decoupling capacitors, IEEE EMC Vol. 34, p. 130, 
May 1992.

In my practice of using SMA caps, only the largest value of capacitance 
available for given SMA size is selected, if I have a PCB with 10 mil or less 
plane spacing. 
 
Regards,
Barry Ma
b...@anritsu.com


On Thu, 18 May 2000, Ralph Cameron wrote:

 As I read in an article related to bypassing for good decoupling ( in 1971)
 one can select from a number of EIA values and by cutting the lead lengths
 correctly ( e.g. from 1/2- less than 1/4  ) the series reonant frequency
 will drop by a considerable amount so - yes, the reason why most power buses
 on PCBs use several values of decoupling is to ensure that a wide range of
 requencies are covered.  Perhaps, with surface mount caps, that is easier to
 predict because they are essentially leadless.
 
 I once cured a very severe case of an FM receiver responding to the 7th
 harmonic of a 14Mhz transmitter because an untuned mixer was used.  Placing
 a 100pf cap with 1/4 leads right across the mixer IC completely cured the
 problem without degrading mixer sensitivity.
 
 Ralph Cameron
 EMC Consultant for Suppression of Consumer Electronics
 (After Sale)


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Re: Re:RE: Charge moving from decoupling capacitors

2000-05-19 Thread Ralph Cameron

As I read in an article related to bypassing for good decoupling ( in 1971)
one can select from a number of EIA values and by cutting the lead lengths
correctly ( e.g. from 1/2- less than 1/4  ) the series reonant frequency
will drop by a considerable amount so - yes, the reason why most power buses
on PCBs use several values of decoupling is to ensure that a wide range of
requencies are covered.  Perhaps, with surface mount caps, that is easier to
predict because they are essentially leadless.

I once cured a very severe case of an FM receiver responding to the 7th
harmonic of a 14Mhz transmitter because an untuned mixer was used.  Placing
a 100pf cap with 1/4 leads right across the mixer IC completely cured the
problem without degrading mixer sensitivity.

Ralph Cameron
EMC Consultant for Suppression of Consumer Electronics
(After Sale)


- Original Message -
From: Jim Bacher jim_bac...@mail.monarch.com
To: george_t...@dell.com
Cc: emc-p...@ieee.org
Sent: Thursday, May 18, 2000 4:24 PM
Subject: Re:RE: Charge moving from decoupling capacitors



 Forwarded for George.

 Reply Separator
 Subject:RE: Charge moving from decoupling capacitors
 Author: george_t...@dell.com
 Date:   5/18/00 2:30 PM

 Barry,

 Thanks for the comments.  Here are my comments:

 Ok, you put caps at a certain distance away from the IC because you only
 want them to work at 100 MHz.  But that distance turns out to be the 1/4
 wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
 distance to cause board resonance.  Now what?  Do you tell the caps not to
 work at 400 MHz because it's not their frequency?


 For your 2nd comment:

 I used the words loosely define for that reason.  If you are interested
in
 high frequency decoupling and instantaneous current, you really want to
have
 all your charges moving in phase.  At 1/4 wavelength, the charges are 90
 degrees out of phase, so they will not do much for your instantaneous
 current.  1/8 wavelength is what I consider to be acceptable.  You can
 certainly pick a different number.

 Regards,

 George Tang
 george_t...@dell.com


 -Original Message-
 From: Barry Ma [mailto:barry...@altavista.com]
 Sent: Thursday, May 18, 2000 10:50 AM
 To: george_t...@exchange.dell.com
 Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
 Subject: RE: Charge moving from decoupling capacitors


 George,

 Thanks for your long input. I'd like to make some comments below.
 -
 On Wed, 17 May 2000, george_t...@dell.com wrote:

  Large parallel plates behave as transmission lines.  A quarter
wavelength
  transmission line with a short at the end has infinite impedance, so
  capacitors placed 1/4 wavelength away are bad.

 That's why decaps work on low frequency portion. Let's set 100 MHz and
below
 for decaps to cover. The wavelength at 100 MHz is 3 meters. A quarter of
it
 is 75 cm. It's long enough to ordinary PCB size. (The cap is directly
 connected to pwr/gnd planes.)


  This means that we can loosely define the largest usable board area
 capacitance as 1/8
  wavelength radius of copper surrounding the IC power pin.  Charges
stored
 on the planes
  further than 1/8 wavelength away are not very usable due to the time
 delay.
  At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board
capacitor
  good enough for your IC?

 George, I beg for differentials. How did you jump from capacitors placed
 1/4 wavelength away are bad to the largest usable board area capacitance
 as 1/8 wavelength radius?

 Can I use the same token to infer from caps placed one wavelength away
are
 good to the largest usable board area capacitance is within 1/2
wavelength
 radius? And so, and so on.

 Regards,
 Barry Ma
 b...@anritsu.com



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RE: Charge moving from decoupling capacitors

2000-05-18 Thread Barry Ma

George,

Sorry, I forgot to repeat what I wrote to you 5/15/00:
It is generally acknowledged that decaps and plane cap are complementary 
(supposing a 10 mil or less spacing between pwr and gnd planes). Decaps cover 
low end of frequency range, while the plane cap takes care of high frequencies.

I wrote similar words to Steve wei...@atdial.net 5/17/00:
If there's a 10 mil or less spacing between pwr and gnd planes, the plane cap 
is available. The plane cap and the decaps are complementary in whole frequency 
range. Plane cap takes care of high end, and decaps cover low portion. Then 
locations of decaps are not critical. And then decaps can be shared by other 
chips, according to the excellent research conducted by EMC lab at UMR.

That's my fault omitting this prerequisite today. In a PCB with 10 mil or less 
plane spacing, the plane capacitance would work better at 400 MHz than any 
decaps.

Please allow me to put some words about plane cap. Why do we - actually the EMC 
lab at UMR, insist on 10 mil or less? Three reasons:
(1) Utilizable plane capacitor.
(2) Low inductance when pwr/gnd serve as a transmission line.
(3) Low mutual inductance between vias.

I apologize for not phrasing properly.

Thank you
Best Regards,
Barry 
---
On Thu, 18 May 2000, george_t...@dell.com wrote:

 Barry, 
 
 Thanks for the comments.  Here are my comments:  
 
 Ok, you put caps at a certain distance away from the IC because you only
 want them to work at 100 MHz.  But that distance turns out to be the 1/4
 wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
 distance to cause board resonance.  Now what?  Do you tell the caps not to
 work at 400 MHz because it's not their frequency?  
 
 
 For your 2nd comment:
 
 I used the words loosely define for that reason.  If you are interested in
 high frequency decoupling and instantaneous current, you really want to have
 all your charges moving in phase.  At 1/4 wavelength, the charges are 90
 degrees out of phase, so they will not do much for your instantaneous
 current.  1/8 wavelength is what I consider to be acceptable.  You can
 certainly pick a different number.  
 
 Regards, 
 
 George Tang
 george_t...@dell.com


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Re:RE: Charge moving from decoupling capacitors

2000-05-18 Thread Jim Bacher

Forwarded for George.  

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/18/00 2:30 PM

Barry, 

Thanks for the comments.  Here are my comments:  

Ok, you put caps at a certain distance away from the IC because you only
want them to work at 100 MHz.  But that distance turns out to be the 1/4
wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
distance to cause board resonance.  Now what?  Do you tell the caps not to
work at 400 MHz because it's not their frequency?  


For your 2nd comment:

I used the words loosely define for that reason.  If you are interested in
high frequency decoupling and instantaneous current, you really want to have
all your charges moving in phase.  At 1/4 wavelength, the charges are 90
degrees out of phase, so they will not do much for your instantaneous
current.  1/8 wavelength is what I consider to be acceptable.  You can
certainly pick a different number.  

Regards, 

George Tang
george_t...@dell.com


-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Thursday, May 18, 2000 10:50 AM
To: george_t...@exchange.dell.com
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


George,

Thanks for your long input. I'd like to make some comments below.
-
On Wed, 17 May 2000, george_t...@dell.com wrote:

 Large parallel plates behave as transmission lines.  A quarter wavelength
 transmission line with a short at the end has infinite impedance, so
 capacitors placed 1/4 wavelength away are bad.  

That's why decaps work on low frequency portion. Let's set 100 MHz and below
for decaps to cover. The wavelength at 100 MHz is 3 meters. A quarter of it
is 75 cm. It's long enough to ordinary PCB size. (The cap is directly
connected to pwr/gnd planes.)


 This means that we can loosely define the largest usable board area
capacitance as 1/8 
 wavelength radius of copper surrounding the IC power pin.  Charges stored
on the planes
 further than 1/8 wavelength away are not very usable due to the time
delay.
 At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
 good enough for your IC?  

George, I beg for differentials. How did you jump from capacitors placed
1/4 wavelength away are bad to the largest usable board area capacitance
as 1/8 wavelength radius?

Can I use the same token to infer from caps placed one wavelength away are
good to the largest usable board area capacitance is within 1/2 wavelength
radius? And so, and so on.

Regards,
Barry Ma
b...@anritsu.com



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 unsubscribe emc-pstc

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 Richard Nute:   ri...@ieee.org



[SI-LIST] : RE: Charge moving from decoupling capacitors

2000-05-18 Thread George_Tang
Barry, 

Thanks for the comments.  Here are my comments:  

Ok, you put caps at a certain distance away from the IC because you only
want them to work at 100 MHz.  But that distance turns out to be the 1/4
wave distance at 400 MHz, and you placed enough caps at the 1/4 wave
distance to cause board resonance.  Now what?  Do you tell the caps not to
work at 400 MHz because it's not their frequency?  


For your 2nd comment:

I used the words loosely define for that reason.  If you are interested in
high frequency decoupling and instantaneous current, you really want to have
all your charges moving in phase.  At 1/4 wavelength, the charges are 90
degrees out of phase, so they will not do much for your instantaneous
current.  1/8 wavelength is what I consider to be acceptable.  You can
certainly pick a different number.  

Regards, 

George Tang
george_t...@dell.com


-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Thursday, May 18, 2000 10:50 AM
To: george_t...@exchange.dell.com
Cc: si-l...@silab.eng.sun.com; emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors


George,

Thanks for your long input. I'd like to make some comments below.
-
On Wed, 17 May 2000, george_t...@dell.com wrote:

 Large parallel plates behave as transmission lines.  A quarter wavelength
 transmission line with a short at the end has infinite impedance, so
 capacitors placed 1/4 wavelength away are bad.  

That’s why decaps work on low frequency portion. Let’s set 100 MHz and below
for decaps to cover. The wavelength at 100 MHz is 3 meters. A quarter of it
is 75 cm. It’s long enough to ordinary PCB size. (The cap is directly
connected to pwr/gnd planes.)


 This means that we can loosely define the largest usable board area
capacitance as 1/8 
 wavelength radius of copper surrounding the IC power pin.  Charges stored
on the planes
 further than 1/8 wavelength away are not very usable due to the time
delay.
 At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
 good enough for your IC?  

George, I beg for differentials. How did you jump from capacitors placed
1/4 wavelength away are bad to the largest usable board area capacitance
as 1/8 wavelength radius?

Can I use the same token to infer from caps placed one wavelength away are
good to the largest usable board area capacitance is within 1/2 wavelength
radius? And so, and so on.

Regards,
Barry Ma
b...@anritsu.com



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RE: Charge moving from decoupling capacitors

2000-05-18 Thread Barry Ma

George,

Thanks for your long input. I'd like to make some comments below.
-
On Wed, 17 May 2000, george_t...@dell.com wrote:

 Large parallel plates behave as transmission lines.  A quarter wavelength
 transmission line with a short at the end has infinite impedance, so
 capacitors placed 1/4 wavelength away are bad.  

That’s why decaps work on low frequency portion. Let’s set 100 MHz and below 
for decaps to cover. The wavelength at 100 MHz is 3 meters. A quarter of it is 
75 cm. It’s long enough to ordinary PCB size. (The cap is directly connected to 
pwr/gnd planes.)


 This means that we can loosely define the largest usable board area 
 capacitance as 1/8 
 wavelength radius of copper surrounding the IC power pin.  Charges stored on 
 the planes
 further than 1/8 wavelength away are not very usable due to the time delay.
 At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
 good enough for your IC?  

George, I beg for differentials. How did you jump from capacitors placed 1/4 
wavelength away are bad to the largest usable board area capacitance as 1/8 
wavelength radius?

Can I use the same token to infer from caps placed one wavelength away are 
good to the largest usable board area capacitance is within 1/2 wavelength 
radius? And so, and so on.

Regards,
Barry Ma
b...@anritsu.com



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Re:RE: Charge moving from decoupling capacitors

2000-05-18 Thread Jim Bacher

forwarding for George

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/17/00 11:16 PM

Barry, 

This is true on most boards.  But that is because the caps are tied to the
planes through vias and lead traces, which are inductive.  Also, the caps
are further away from the IC power pins than the planes.  This does not mean
that the cap by itself cannot work at 1 GHz.  If you have a 50 mil trace
above a gnd plane terminated to a cap without using vias or other lead
traces and measure VSWR and reflections from the cap, you will see that the
cap works well at 1 GHz and beyond.  You must solder the cap to the gnd
plane and to the 50 mil trace directly.  

Regards, 

George Tang



-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Wednesday, May 17, 2000 9:16 AM
To: si-l...@silab.eng.sun.com; EMC-PSTC
Cc: wei...@atdial.net
Subject: Re: Charge moving from decoupling capacitors



Steve,

Thanks a lot for the very nice hierarchy description below. 

If there's a 10 mil or less spacing between pwr and gnd planes, the plane
cap is available. The plane cap and the decaps are complementary in whole
frequency range. Plane cap takes care of high end, and decaps cover low
portion. Then the location of decaps are not critical. And then decaps can
be shared by other chips, according to the excellent research conducted by
EMC lab at UMR. 

Please allow me to modify a bit your description as follows.   

The capacitance inside the device supports the chip first, but usually not
enough.
Charge from the planes also supports the chip and replenishes the device
capacitance,
Decaps replenish the plane on low frequency portion, while plane cap
responds itself on HF end,
Bulk capacitors replenish decaps and plane cap,
The voltage regulator replenishes the bulk capacitors.

Please correct me. Thanks.

Regards,
Barry
b...@anritsu.com
-
From: sweir wei...@atdial.net, on 5/11/00 9:28 PM:


The capacitance inside the device supports the chip,
Charge from the planes replenishes the device capacitance,
HF capacitors on the board replenish the planes,
Bulk capacitors replenish the HF capacitors,
The voltage regulator replenishes the bulk capacitors.

[edited by bm]


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Fwd:RE: Charge moving from decoupling capacitors

2000-05-18 Thread Jim Bacher

forwarding for George..

Reply Separator
Subject:RE: Charge moving from decoupling capacitors
Author: george_t...@dell.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/17/00 10:50 PM

You ask an open question, so the open answer to that is it depends.  It
depends on how much current the IC is drawing, what frequency and rise time
it has, what type of load the IC output drivers are driving, how much noise
on the power plane the other ICs on the same board can tolerate . . . .  You
are looking for a solution that will work in every case, but you will find
that there are problems or exceptions to every solution.  A capacitor stores
charges and supplies current to ICs when needed.  By that definition, the
charges on the capacitor must move in phase from each other.  For parallel
plates to behave as a good capacitor, their dimensions should be much
smaller than a wavelength so the charges on the plates will move in phase.
Large parallel plates behave as transmission lines.  A quarter wavelength
transmission line with a short at the end has infinite impedance, so
capacitors placed 1/4 wavelength away are bad.  This means that we can
loosely define the largest usable board area capacitance as 1/8 wavelength
radius of copper surrounding the IC power pin.  Charges stored on the planes
further than 1/8 wavelength away are not very usable due to the time delay.
At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
good enough for your IC?  It might be if you have a CMOS IC driving another
CMOS IC less than 2 inches away, so the load on the output of the 1st IC is
mainly the CMOS gate capacitance at the input of the 2nd IC at the end of
the 2 inch transmission line.  During switching, the 2nd IC draws current
from the output of the 1st IC for the 1st 200 or 300 ps to charge up the
input gate capacitance on the 2nd IC.  The current is an impulse function,
although the voltage waveform is a step function.  If these ICs are small
and uses little power, the board capacitance might be enough to supply the
impulse current for the 1st IC.  If the load on the transmission line is a
termination resistor, the current draw will be a step function, and the
board capacitance alone may not be good enough.  But here is an exception.
You have a board that uses only CMOS devices, and the largest IC is a 500
MHz processor that consumes 50W of power at 2.5v, so it switches 20A of
current at 500 MHz.  It is a CMOS device, so its current draws are mostly
impulse functions.  Would the board capacitance be good enough for this 20A
switching current?  Probably not.  Making the pwr plane larger will not
help, but using more layers in parallel will help.  You might have to use 4,
8, or 16 pwr/gnd layer pairs in parallel for this board, the more layers the
better.  But wait!!  Isn't that what a multilayer ceramic capacitor is?  It
has many pwr/gnd layers in parallel . . . .  Hmm, if we could only take
advantage of that . . .  I'm thinking that if you have to use a 50W, 500MHz
processor, and your boss tells you that you cannot have 8 pwr/gnd layers on
your board, you or someone will probably find a way to make the ceramic
capacitor work effectively beyond 1 GHz!!  Another question you might ask is
that do I really want to dump the 20A switching noise directly into the
pwr/gnd planes and create pwr/gnd bounce and board resonance to interfere
with all the ICs on the board, not to mention EMI problems?  

Regards, 

George Tang



-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Monday, May 15, 2000 1:33 PM
To: george_t...@exchange.dell.com; si-l...@silab.eng.sun.com
Cc: emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors



Thanks a lot for your inputs.

All responses to my second question are only concerned with the inductance
due to long distance between chip and decap. Nobody seems to agree
imposing another constrain to the distance. My question was

Do we really have to limit the distance letting the charge have enough time
to move from the cap to the chip during the rise time interval? I doubt it.

 
But I really read an article implying this extra concern.


George, you wrote:
 This is true if you have only DC current.  For AC, you may have water in
the pipe but 
 no water out of the faucet if the faucet is switching out of phase from
the water in 
 the pipe.

Thank you for reminding me of Frequency Domain analysis. Yes, I should have
described and analyzed a transient problem (charge travel during Tr) in both
TD and FD, and then correlate the results.  Let me have a try this time: 

It is generally acknowledged that decaps and plane cap are complementary
(supposing a 10 mil or less spacing between pwr and gnd planes). Decaps
cover low end of frequency range, while the plane cap takes care of high
frequencies. Thus the interplane cap would play more and more important role
in high-speed PCB design, as the speed

[SI-LIST] : RE: Charge moving from decoupling capacitors

2000-05-18 Thread George_Tang
Barry, 

This is true on most boards.  But that is because the caps are tied to the
planes through vias and lead traces, which are inductive.  Also, the caps
are further away from the IC power pins than the planes.  This does not mean
that the cap by itself cannot work at 1 GHz.  If you have a 50 mil trace
above a gnd plane terminated to a cap without using vias or other lead
traces and measure VSWR and reflections from the cap, you will see that the
cap works well at 1 GHz and beyond.  You must solder the cap to the gnd
plane and to the 50 mil trace directly.  

Regards, 

George Tang



-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Wednesday, May 17, 2000 9:16 AM
To: si-l...@silab.eng.sun.com; EMC-PSTC
Cc: wei...@atdial.net
Subject: Re: Charge moving from decoupling capacitors



Steve,

Thanks a lot for the very nice hierarchy description below. 

If there's a 10 mil or less spacing between pwr and gnd planes, the plane
cap is available. The plane cap and the decaps are complementary in whole
frequency range. Plane cap takes care of high end, and decaps cover low
portion. Then the location of decaps are not critical. And then decaps can
be shared by other chips, according to the excellent research conducted by
EMC lab at UMR. 

Please allow me to modify a bit your description as follows.   

The capacitance inside the device supports the chip first, but usually not
enough.
Charge from the planes also supports the chip and replenishes the device
capacitance,
Decaps replenish the plane on low frequency portion, while plane cap
responds itself on HF end,
Bulk capacitors replenish decaps and plane cap,
The voltage regulator replenishes the bulk capacitors.

Please correct me. Thanks.

Regards,
Barry
b...@anritsu.com
-
From: sweir wei...@atdial.net, on 5/11/00 9:28 PM:


The capacitance inside the device supports the chip,
Charge from the planes replenishes the device capacitance,
HF capacitors on the board replenish the planes,
Bulk capacitors replenish the HF capacitors,
The voltage regulator replenishes the bulk capacitors.

[edited by bm]


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[SI-LIST] : RE: Charge moving from decoupling capacitors

2000-05-18 Thread George_Tang
You ask an open question, so the open answer to that is it depends.  It
depends on how much current the IC is drawing, what frequency and rise time
it has, what type of load the IC output drivers are driving, how much noise
on the power plane the other ICs on the same board can tolerate . . . .  You
are looking for a solution that will work in every case, but you will find
that there are problems or exceptions to every solution.  A capacitor stores
charges and supplies current to ICs when needed.  By that definition, the
charges on the capacitor must move in phase from each other.  For parallel
plates to behave as a good capacitor, their dimensions should be much
smaller than a wavelength so the charges on the plates will move in phase.
Large parallel plates behave as transmission lines.  A quarter wavelength
transmission line with a short at the end has infinite impedance, so
capacitors placed 1/4 wavelength away are bad.  This means that we can
loosely define the largest usable board area capacitance as 1/8 wavelength
radius of copper surrounding the IC power pin.  Charges stored on the planes
further than 1/8 wavelength away are not very usable due to the time delay.
At 500MHz in FR4, 1/8 wavelength is 1.5 inches.  Is such a board capacitor
good enough for your IC?  It might be if you have a CMOS IC driving another
CMOS IC less than 2 inches away, so the load on the output of the 1st IC is
mainly the CMOS gate capacitance at the input of the 2nd IC at the end of
the 2 inch transmission line.  During switching, the 2nd IC draws current
from the output of the 1st IC for the 1st 200 or 300 ps to charge up the
input gate capacitance on the 2nd IC.  The current is an impulse function,
although the voltage waveform is a step function.  If these ICs are small
and uses little power, the board capacitance might be enough to supply the
impulse current for the 1st IC.  If the load on the transmission line is a
termination resistor, the current draw will be a step function, and the
board capacitance alone may not be good enough.  But here is an exception.
You have a board that uses only CMOS devices, and the largest IC is a 500
MHz processor that consumes 50W of power at 2.5v, so it switches 20A of
current at 500 MHz.  It is a CMOS device, so its current draws are mostly
impulse functions.  Would the board capacitance be good enough for this 20A
switching current?  Probably not.  Making the pwr plane larger will not
help, but using more layers in parallel will help.  You might have to use 4,
8, or 16 pwr/gnd layer pairs in parallel for this board, the more layers the
better.  But wait!!  Isn't that what a multilayer ceramic capacitor is?  It
has many pwr/gnd layers in parallel . . . .  Hmm, if we could only take
advantage of that . . .  I'm thinking that if you have to use a 50W, 500MHz
processor, and your boss tells you that you cannot have 8 pwr/gnd layers on
your board, you or someone will probably find a way to make the ceramic
capacitor work effectively beyond 1 GHz!!  Another question you might ask is
that do I really want to dump the 20A switching noise directly into the
pwr/gnd planes and create pwr/gnd bounce and board resonance to interfere
with all the ICs on the board, not to mention EMI problems?  

Regards, 

George Tang



-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Monday, May 15, 2000 1:33 PM
To: george_t...@exchange.dell.com; si-l...@silab.eng.sun.com
Cc: emc-p...@ieee.org
Subject: RE: Charge moving from decoupling capacitors



Thanks a lot for your inputs.

All responses to my second question are only concerned with the inductance
due to “long” distance between chip and decap. Nobody seems to agree
imposing another constrain to the distance. My question was

“Do we really have to limit the distance letting the charge have enough time
to move from the cap to the chip during the rise time interval? I doubt it.”

 
But I really read an article implying this extra concern.


George, you wrote:
 This is true if you have only DC current.  For AC, you may have water in
the pipe but 
 no water out of the faucet if the faucet is switching out of phase from
the water in 
 the pipe.

Thank you for reminding me of Frequency Domain analysis. Yes, I should have
described and analyzed a transient problem (charge travel during Tr) in both
TD and FD, and then correlate the results.  Let me have a try this time: 

It is generally acknowledged that decaps and plane cap are complementary
(supposing a 10 mil or less spacing between pwr and gnd planes). Decaps
cover low end of frequency range, while the plane cap takes care of high
frequencies. Thus the interplane cap would play more and more important role
in high-speed PCB design, as the speed gets faster and faster. On the other
hand, nobody objects closer distances from decaps to the chip, if possible.
. When a chip drains necessary charges from pwr/gnd planes during Tr,
decaps would supply charges to pwr and gnd

Re: Charge moving from decoupling capacitors

2000-05-17 Thread Barry Ma

Hi Yu,

Let’s begin with the excellent description written by Andrew Ingraham:

“The voltage sag propagates outward from the chip, consuming charge stored in 
the intrinsic capacitance of the planes bit by bit (not all of it at once!), 
and eventually reaching external capacitors which help hold up the voltage.”

When a chip gate opens, the V (and Q) sag on the metal plane propagates outward 
from the chip at circle front, consuming charges inside the circle. If the 
outgoing circle front meets a decap, charge would be moving from the decap to 
the chip. ... What if the circle does not reach any decap before the end of Tr? 
The gate has closed, no current loop can be formed. That is the scenario I was 
interested in. Now an electrical potential imbalance happens in a metallic 
plane. Charge on the plane would flow toward the circle for regaining 
eqi-potential. ...

Regards,
Barry Ma
ANRITSU company
Morgan Hill, CA 95037

-
From: Yu Wang wangy...@yahoo.com, on 5/17/00 7:45 AM:

Hi, Barry,

I think we all do agree the 1st point you said.
 
But on the 2nd point, I have another opinion. Say, you are right,When an 
electrical potential imbalance happens in a metallic plane, a current would 
flow on the plane for regaining the equi-potential. But we regard the metallic 
plane as a reference plane,
then, theoretically, there is no an electrical potential imbalance happens in a 
metallic plane. In fact, we can never get a ideal reference plane(even the 
earth is not IDEAL). Based on this, I would say yes on your question Does it 
need EM field support from the dielectric?. Still but, the need of the support 
is usually slight if the electical size of the metallic plane is big enough. 
because we know the metallic plane is a equi-potential plane.

regards,
Yu Wang, Ph.D
U.T. MD Anderson Cancer Center
1100 Holcombe Blvd., Box 217
Houston, TX, 77030
Tel:713-745-1671


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Re: Charge moving from decoupling capacitors

2000-05-17 Thread Barry Ma

Steve,

Thanks a lot for the very nice hierarchy description below. 

If there's a 10 mil or less spacing between pwr and gnd planes, the plane cap 
is available. The plane cap and the decaps are complementary in whole frequency 
range. Plane cap takes care of high end, and decaps cover low portion. Then the 
location of decaps are not critical. And then decaps can be shared by other 
chips, according to the excellent research conducted by EMC lab at UMR. 

Please allow me to modify a bit your description as follows.   

The capacitance inside the device supports the chip first, but usually not 
enough.
Charge from the planes also supports the chip and replenishes the device 
capacitance,
Decaps replenish the plane on low frequency portion, while plane cap responds 
itself on HF end,
Bulk capacitors replenish decaps and plane cap,
The voltage regulator replenishes the bulk capacitors.

Please correct me. Thanks.

Regards,
Barry
b...@anritsu.com
-
From: sweir wei...@atdial.net, on 5/11/00 9:28 PM:


The capacitance inside the device supports the chip,
Charge from the planes replenishes the device capacitance,
HF capacitors on the board replenish the planes,
Bulk capacitors replenish the HF capacitors,
The voltage regulator replenishes the bulk capacitors.

[edited by bm]


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RE: Charge moving from decoupling capacitors

2000-05-17 Thread Maxwell, Chris

Barry,

You're hitting upon one of the basic fundamentals of how radiated emissions
occur.  

The situation that Andrew is describing occurs if we design our boards
properly, with a low inductance return path for each current and with proper
impedance matching; then our traces will act more like waveguides and
transmissions lines where the charge flows in the conductors and the
corresponding field stays mostly contained in the dielectric.

The other situation that you're describing is the situation where there is
no loop for return current.  In this situation, the trace is acting more
like an antenna which is more or less a conductor with a time varying
potential at one end which causes charge to accelerate back and forth within
the conductor.   Since there is no readily available return path, the
current is more of a common mode current which will find it's own return
path by radiating a field (displacement current?) to another conductor.
The problem frequencies will be determined by the frequency at which the
charge accelerates (changes speed or direction) and by the distance that the
charge accelerates (length of antenna).   This is the main mechanism for the
radiated emissions that we get paid to minimize.

As for the velocity.  The equations for a stripline may be used (too complex
for me to write using an email editor).  One good reference is pages 407-411
of Fields and Waves in Communication Electronics by Ramo, Whinnery and Van
Duzer, published by Wiley.  In short, you can only use the velocity of
propogation from the dielectric if you have a perfect stripline (strip
conductor sandwiched in dielectric between two very wide conductive planes).
Correction factors need to be applied in other situations.

Thanks for bringing up such a challenging topic.  It helps keep the juices
flowing.

Chris Maxwell, Design Engineer
GN Nettest Optical Division
109 N. Genesee St.  
Utica, NY 13502
PH:  315-797-4449
FAX:  315-797-8024
EMAIL:  chr...@gnlp.com


 -Original Message-
 From: Barry Ma [SMTP:barry...@altavista.com]
 Sent: Tuesday, May 16, 2000 4:29 PM
 To:   EMC-PSTC; si-l...@silab.eng.sun.com
 Subject:  Re: Charge moving from decoupling capacitors
 
 
 Hi Andrew,
 
 You said: It is just like an ordinary transmission line such as
 stripline.  
 
 Please allow me to say something different. 
 
 (1) When a signal propagates along a transmission line, we could observe a
 current loop from source to load through the transmission line. The signal
 velocity is the same as the speed of light in the dielectric. You are
 right.
 (2) When an electrical potential imbalance happens in a metallic plane, a
 current would flow on the plane for regaining the equi-potential. This
 current looks different from the signal current. There's no current loop
 here. Does it need EM field support from the dielectric? If not, should it
 have a different velocity? That is my point. I have no answer, and
 appreciate any input. Thanks.
 
 Bets Regards,
 Barry Ma
 b...@anritsu.com
 
 
 Barry Ma wrote:
  As the speed of digital signals gets faster and faster, people begin
 being
  concerned with the distance for electric charge to move on power and
  ground planes of multilayer PCB during the signal rise time from a
  decoupling capacitor (cap) to a chip it serves. I would like to raise two
  questions.
 
  (1) The charge is moving in a metalic plane, not inside the dielectric
  between pwr and gnd planes. Please let me know why you have to use the
  propagation velocity in the dielectric, instead of that in the metal.
 --
 Ingraham, Andrew wrote:
  
  The charge may be moving in the metal, but the energy (which makes the
  charge keep moving) is primarily in the electro-magnetic field between
 the
  planes, in the dielectric.  The charge won't move unless there is an E-M
  field to push it.
 
  It is just like an ordinary transmission line such as stripline.  The
  propagation velocity of a trace is that of the dielectric, even though
 the
  charge moves only in the metal trace and planes.
 
 (Edited by BM)
 
 
 
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Re: Charge moving from decoupling capacitors

2000-05-16 Thread Barry Ma

Hi Andrew,

You said: It is just like an ordinary transmission line such as stripline.  

Please allow me to say something different. 

(1) When a signal propagates along a transmission line, we could observe a 
current loop from source to load through the transmission line. The signal 
velocity is the same as the speed of light in the dielectric. You are right.
(2) When an electrical potential imbalance happens in a metallic plane, a 
current would flow on the plane for regaining the equi-potential. This current 
looks different from the signal current. There's no current loop here. Does it 
need EM field support from the dielectric? If not, should it have a different 
velocity? That is my point. I have no answer, and appreciate any input. Thanks.

Bets Regards,
Barry Ma
b...@anritsu.com


Barry Ma wrote:
 As the speed of digital signals gets faster and faster, people begin being
 concerned with the distance for electric charge to move on power and
 ground planes of multilayer PCB during the signal rise time from a
 decoupling capacitor (cap) to a chip it serves. I would like to raise two
 questions.

 (1) The charge is moving in a metalic plane, not inside the dielectric
 between pwr and gnd planes. Please let me know why you have to use the
 propagation velocity in the dielectric, instead of that in the metal.
--
Ingraham, Andrew wrote:
 
 The charge may be moving in the metal, but the energy (which makes the
 charge keep moving) is primarily in the electro-magnetic field between the
 planes, in the dielectric.  The charge won't move unless there is an E-M
 field to push it.

 It is just like an ordinary transmission line such as stripline.  The
 propagation velocity of a trace is that of the dielectric, even though the
 charge moves only in the metal trace and planes.

(Edited by BM)



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RE: Charge moving from decoupling capacitors

2000-05-15 Thread Barry Ma

Thanks a lot for your inputs.

All responses to my second question are only concerned with the inductance due 
to “long” distance between chip and decap. Nobody seems to agree imposing 
another constrain to the distance. My question was

“Do we really have to limit the distance letting the charge have enough time to 
move from the cap to the chip during the rise time interval? I doubt it.” 
 
But I really read an article implying this extra concern.


George, you wrote:
 This is true if you have only DC current.  For AC, you may have water in the 
 pipe but 
 no water out of the faucet if the faucet is switching out of phase from the 
 water in 
 the pipe.

Thank you for reminding me of Frequency Domain analysis. Yes, I should have 
described and analyzed a transient problem (charge travel during Tr) in both TD 
and FD, and then correlate the results.  Let me have a try this time: 

It is generally acknowledged that decaps and plane cap are complementary 
(supposing a 10 mil or less spacing between pwr and gnd planes). Decaps cover 
low end of frequency range, while the plane cap takes care of high frequencies. 
Thus the interplane cap would play more and more important role in high-speed 
PCB design, as the speed gets faster and faster. On the other hand, nobody 
objects closer distances from decaps to the chip, if possible. . When a 
chip drains necessary charges from pwr/gnd planes during Tr, decaps would 
supply charges to pwr and gnd planes on lower frequencies, while interplane cap 
can respond itself on higher frequencies.

Best Regards,
Barry Ma
b...@anritsu.com



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Re:RE: [SI-LIST] : Charge moving from decoupling capacitors

2000-05-12 Thread Jim Bacher

forwarding for Francis

Reply Separator
Subject:RE: [SI-LIST] : Charge moving from decoupling capacitors
Author: Kai; Francis francis@intel.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/12/00 9:02 AM

Dear Electrical Engineers,

 Based on Mr. Ma's questions, I would like to know if you guys are
really interested in the electron movements in metal.
The transport of electrons in a solid is dominated by Boltzmann's Equation.
How do you solve this equation for an electron to 
move from the decoupling capacitor to a chip (package and...) it serves in a
metal plane? This might be something that the 
tools vendors are interested in for the next generation high-speed tools. 

Kind Regards,

Francis Kai
Intel Corporation

-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Thursday, May 11, 2000 3:50 PM
To: EMC-PSTC; si-l...@silab.eng.sun.com
Subject: [SI-LIST] : Charge moving from decoupling capacitors


Hi,

As the speed of digital signals gets faster and faster, people begin being
concerned with the distance for electric charge to move on power and ground
planes of multilayer PCB during the signal rise time from a decoupling
capacitor (cap) to a chip it serves. I would like to raise two questions.

(1) The charge is moving in a metalic plane, not inside the dielectric
between pwr and gnd planes. Please let me know why you have to use the
propagation velocity in the dielectric, instead of that in the metal.

(2) The second question is regarding distance between the cap and the chip.
Do we really have to limit the distance letting the charge have enough time
to move from the cap to the chip during the rise time interval? I doubt it. 

Take the running water system for example. When we open, then close the
water faucet within one second, does the water we've got in basin come from
water tower (or water station, or reservoir)? No, it is the water that
resides in the pipe. As a matter of fact, we have a very large pipe -
pwr/gnd planes. Well, of cause you know, I did not mean we don't need water
tower - the cap. ..

Regards,
Barry Ma
b...@anritsu.com
Morgan Hill, CA 95037
Tel. 408-778-2000


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Re: Re[2]: [SI-LIST] : Charge moving from decoupling capacitors

2000-05-12 Thread Ralph Cameron

Equally important is that respect has to be paid to impedance matching ;
other wise, energy is reflected from the load and this will degrade the
risetime as well as cause some energy to be radiated. The dielectric
material must be low loss so that you ensure the signal is conducted with
minimum attenuation.and keeping the path length to the chip to a minimum
keeps the undesired switching products very low.

Ralph Cameron
EMC Consultant for Suppression of Consumer Electronics
(after Sale).

- Original Message -
From: Jim Bacher jim_bac...@mail.monarch.com
To: Larry Miller ldmil...@nortelnetworks.com; EMC-PSTC
emc-p...@ieee.org
Sent: Friday, May 12, 2000 11:24 AM
Subject: Re[2]: [SI-LIST] : Charge moving from decoupling capacitors



 Forwarded for Larry.

 Reply Separator
 Subject:Re: [SI-LIST] : Charge moving from decoupling capacitors
 Author: Larry Miller ldmil...@nortelnetworks.com
 Date:   5/12/00 7:37 AM

 Hi, Barry,

 Responses below:
 At 03:49 PM 5/11/00 -0700, Barry Ma wrote:
 Hi,
 
 As the speed of digital signals gets faster and faster, people begin
being
 concerned with the distance for electric charge to move on power and
ground
 planes of multilayer PCB during the signal rise time from a decoupling
 capacitor (cap) to a chip it serves. I would like to raise two questions.
 
 (1) The charge is moving in a metalic plane, not inside the dielectric
 between pwr and gnd planes. Please let me know why you have to use the
 propagation velocity in the dielectric, instead of that in the metal.

 Due to skin effect at anything above a few tens of kHz, the current flows
 mainly on the surface of the trace, so it has to interact with the
 dielectric in accordance with Maxwell's equations for electromagnetic
waves.

 (2) The second question is regarding distance between the cap and the
 chip. Do we really have to limit the distance letting the charge have
 enough time to move from the cap to the chip during the rise time
interval?
 I doubt it.
 
 No, you have to let the wave propagate (see below).

 Take the running water system for example. When we open, then close the
 water faucet within one second, does the water we've got in basin come
from
 water tower (or water station, or reservoir)? No, it is the water that
 resides in the pipe. As a matter of fact, we have a very large pipe -
 pwr/gnd planes. Well, of cause you know, I did not mean we don't need
water
 tower - the cap. ..

 The running water analogy breaks down here (at AC). Another analogy would
 be that the current is comprised of many successive collisions between
 billiard balls, not the motion of one single ball. Yet another analogy
 would be to look at the current as a game of Chinese checkers, where an
 individual electron can only move into a hole in the board vacated by
 another electron (if you overcome this you get superconduction!). As I
 recollect, the actual speed of an identifiable electron, assuming you
could
 actually identify it, is on the order of a few meters/sec, though the
 electromagnetic wave caused by the transfer of energy between electrons
 travels at the speed of light in the medium.

 Larry Miller



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RE: [SI-LIST] : Charge moving from decoupling capacitors

2000-05-12 Thread Ingraham, Andrew
 As the speed of digital signals gets faster and faster, people begin being
 concerned with the distance for electric charge to move on power and
 ground planes of multilayer PCB during the signal rise time from a
 decoupling capacitor (cap) to a chip it serves. I would like to raise two
 questions.
 
 (1) The charge is moving in a metalic plane, not inside the dielectric
 between pwr and gnd planes. Please let me know why you have to use the
 propagation velocity in the dielectric, instead of that in the metal.
 
The charge may be moving in the metal, but the energy (which makes the
charge keep moving) is primarily in the electro-magnetic field between the
planes, in the dielectric.  The charge won't move unless there is an E-M
field to push it.

It is just like an ordinary transmission line such as stripline.  The
propagation velocity of a trace is that of the dielectric, even though the
charge moves only in the metal trace and planes.


 (2) The second question is regarding distance between the cap and the
 chip. Do we really have to limit the distance letting the charge have
 enough time to move from the cap to the chip during the rise time
 interval? I doubt it. 
 
That depends whether you need the capacitor to help during the rise time
interval itself.

If you had a single 1.0 Farad cap and attached it with 20 foot long jumper
cables to your chip, it would do nothing to help the chip during the rise
time interval.  The jumper cable is a transmission line.  If the voltage
sags at your chip, it takes many nanoseconds for the sag to reach the
capacitor.  Until the sag reaches it, charge doesn't even start moving out
of it, i.e., the cap might as well not be there.

Now flatten the jumper cable into two planes.  The planes are a fat
transmission line (really!).  The voltage sag propagates outward from the
chip, consuming charge stored in the intrinsic capacitance of the planes bit
by bit (not all of it at once!), and eventually reaching external capacitors
which help hold up the voltage.


 Take the running water system for example. When we open, then close the
 water faucet within one second, does the water we've got in basin come
 from water tower (or water station, or reservoir)? No, it is the water
 that resides in the pipe. As a matter of fact, we have a very large pipe -
 pwr/gnd planes. Well, of cause you know, I did not mean we don't need
 water tower - the cap. ..
 
Pwr/gnd planes are similar to a long pipe.  At first they help hold up the
pressure, but without a tank, the pressure would disappear.

Even with a tank, the pressure does drop a little when you open the faucet.
Open a very large faucet, and the pressure immediately drops a lot ...
especially if you are the house at the end of the water main.  Open a very
large faucet right at the tank or pumping station, and the drop in pressure
is much less.  (This analogy is not very good, however, because water pipes
also have resistance.)

Regards,
Andy


 To unsubscribe from si-list or si-list-digest: send e-mail to
majord...@silab.eng.sun.com. In the BODY of message put: UNSUBSCRIBE
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RE: [SI-LIST] : Charge moving from decoupling capacitors

2000-05-12 Thread Kai, Francis
Dear Electrical Engineers,

 Based on Mr. Ma's questions, I would like to know if you guys are
really interested in the electron movements in metal.
The transport of electrons in a solid is dominated by Boltzmann's Equation.
How do you solve this equation for an electron to 
move from the decoupling capacitor to a chip (package and...) it serves in a
metal plane? This might be something that the 
tools vendors are interested in for the next generation high-speed tools. 

Kind Regards,

Francis Kai
Intel Corporation

-Original Message-
From: Barry Ma [mailto:barry...@altavista.com]
Sent: Thursday, May 11, 2000 3:50 PM
To: EMC-PSTC; si-l...@silab.eng.sun.com
Subject: [SI-LIST] : Charge moving from decoupling capacitors


Hi,

As the speed of digital signals gets faster and faster, people begin being
concerned with the distance for electric charge to move on power and ground
planes of multilayer PCB during the signal rise time from a decoupling
capacitor (cap) to a chip it serves. I would like to raise two questions.

(1) The charge is moving in a metalic plane, not inside the dielectric
between pwr and gnd planes. Please let me know why you have to use the
propagation velocity in the dielectric, instead of that in the metal.

(2) The second question is regarding distance between the cap and the chip.
Do we really have to limit the distance letting the charge have enough time
to move from the cap to the chip during the rise time interval? I doubt it. 

Take the running water system for example. When we open, then close the
water faucet within one second, does the water we've got in basin come from
water tower (or water station, or reservoir)? No, it is the water that
resides in the pipe. As a matter of fact, we have a very large pipe -
pwr/gnd planes. Well, of cause you know, I did not mean we don't need water
tower - the cap. ..

Regards,
Barry Ma
b...@anritsu.com
Morgan Hill, CA 95037
Tel. 408-778-2000


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Re[2]: [SI-LIST] : Charge moving from decoupling capacitors

2000-05-12 Thread Jim Bacher

Forwarded for Larry.

Reply Separator
Subject:Re: [SI-LIST] : Charge moving from decoupling capacitors
Author: Larry Miller ldmil...@nortelnetworks.com
List-Post: emc-pstc@listserv.ieee.org
Date:   5/12/00 7:37 AM

Hi, Barry,

Responses below:
At 03:49 PM 5/11/00 -0700, Barry Ma wrote:
Hi,

As the speed of digital signals gets faster and faster, people begin being
concerned with the distance for electric charge to move on power and ground
planes of multilayer PCB during the signal rise time from a decoupling
capacitor (cap) to a chip it serves. I would like to raise two questions.

(1) The charge is moving in a metalic plane, not inside the dielectric
between pwr and gnd planes. Please let me know why you have to use the
propagation velocity in the dielectric, instead of that in the metal.

Due to skin effect at anything above a few tens of kHz, the current flows
mainly on the surface of the trace, so it has to interact with the
dielectric in accordance with Maxwell's equations for electromagnetic waves.

(2) The second question is regarding distance between the cap and the
chip. Do we really have to limit the distance letting the charge have
enough time to move from the cap to the chip during the rise time interval?
I doubt it. 

No, you have to let the wave propagate (see below).

Take the running water system for example. When we open, then close the
water faucet within one second, does the water we've got in basin come from
water tower (or water station, or reservoir)? No, it is the water that
resides in the pipe. As a matter of fact, we have a very large pipe -
pwr/gnd planes. Well, of cause you know, I did not mean we don't need water
tower - the cap. ..

The running water analogy breaks down here (at AC). Another analogy would
be that the current is comprised of many successive collisions between
billiard balls, not the motion of one single ball. Yet another analogy
would be to look at the current as a game of Chinese checkers, where an
individual electron can only move into a hole in the board vacated by
another electron (if you overcome this you get superconduction!). As I
recollect, the actual speed of an identifiable electron, assuming you could
actually identify it, is on the order of a few meters/sec, though the
electromagnetic wave caused by the transfer of energy between electrons
travels at the speed of light in the medium.

Larry Miller



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Re: Charge moving from decoupling capacitors

2000-05-12 Thread Doug McKean

Barry Ma wrote:
 
 Hi,
 
 As the speed of digital signals gets faster and faster, people begin being 
 concerned 
 with the distance for electric charge to move on power and ground planes of 
 multilayer 
 PCB during the signal rise time from a decoupling capacitor (cap) to a chip 
 it serves. 
 I would like to raise two questions.
 
 (1) The charge is moving in a metalic plane, not inside the dielectric 
 between pwr and 
 gnd planes. Please let me know why you have to use the propagation velocity 
 in the 
 dielectric, instead of that in the metal.

Simple.  The power/ground plane construction is 
a 2-dimensional transmission line.  Just as you 
determine the velocity of propagation in a 
1-dimensional transmission line, the dielectric 
is part of the equation for the capacitive 
component.  And so it follows with the planar 
construction. 

 (2) The second question is regarding distance between the cap and the chip. 
 Do we 
 really have to limit the distance letting the charge have enough time to move 
 from 
 the cap to the chip during the rise time interval? I doubt it. 

Depends.  Distance can mean inductance. 

Since, v(t) = L di/dt and with L in nano-henries (10^-9) 
and suppose dt in pico-seconds (10^-12), we're already 
up in the 10^3 range ... - Doug McKean

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Charge moving from decoupling capacitors

2000-05-12 Thread Barry Ma

Hi,

As the speed of digital signals gets faster and faster, people begin being 
concerned with the distance for electric charge to move on power and ground 
planes of multilayer PCB during the signal rise time from a decoupling 
capacitor (cap) to a chip it serves. I would like to raise two questions.

(1) The charge is moving in a metalic plane, not inside the dielectric between 
pwr and gnd planes. Please let me know why you have to use the propagation 
velocity in the dielectric, instead of that in the metal.

(2) The second question is regarding distance between the cap and the chip. Do 
we really have to limit the distance letting the charge have enough time to 
move from the cap to the chip during the rise time interval? I doubt it. 

Take the running water system for example. When we open, then close the water 
faucet within one second, does the water we've got in basin come from water 
tower (or water station, or reservoir)? No, it is the water that resides in the 
pipe. As a matter of fact, we have a very large pipe - pwr/gnd planes. Well, of 
cause you know, I did not mean we don't need water tower - the cap. ..

Regards,
Barry Ma
b...@anritsu.com
Morgan Hill, CA 95037
Tel. 408-778-2000


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