Re: [Flashcoders] Displaying objects

2006-03-29 Thread John Grden
You might have a look at this:

http://mirror1.cvsdude.com/trac/osflash/red5/browser/java/server/trunk/swf/DEV_Source/classes/org/red5/samples/games/othello/GameBoard.as?rev=604#L98

resolveSiblings() is the method.  Basically, it has some calculations for
finding out if a piece is an end or corner piece by determining
top/bottom/left/right sides based on column and row count.

Might help aid in your resolving some issues in your algorithm

On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
>
> Hehe, all good.  Thanks John.  I'm sitting here trying to write something
> mathematically that works.  Turns out I am the suck at math, so it's
> making
> this complicated.  Hand coding the array would be laborsome and wouldn't
> allow for extensibility.
>
> Grrr...
>
>
> fM.
>
>
>
> On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
> >
> > Sorry, code correction - LOL, on code that's not been tested ...
> >
> > for(var i:Number=0;i > {
> > for(var j:Number=0;j > {
> > this["piece_" + pieceList[i].pieces[j]]._visible = true;
> > }
> > }
> >
> >
> > On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
> > >
> > > well, if you're using my code, then it would essentially build all
> > pieces
> > > the way you show it happening in that link.
> > >
> > > to do it diagonaly the way you specify, there's 2 ways:
> > >
> > > 1.  come up with an algorithm to calculate that type of movement based
> > on
> > > the number of rows/cols you have (ouch)
> > > 2.  create the grid first, hide all pieces.  Create an array by hand
> > with
> > > those values, and loop that array displaying the correct pieces:
> > >
> > > var pieceList:Array ({pieces:[0]}, {pieces: [1,14]},
> > {pieces:[2,15,28]});
> > >
> > > for(var i:Number=0;i > > {
> > > for(var j:Number=0;j > > {
> > > this["piece_" + pieceList[i].pieces[j]._visible = true;
> > > }
> > > }
> > >
> > > Either set visible to true of tell it to gotoAndPlay("transitionIn")
> or
> > > whatever you have in frame lables etc.
> > >
> > > Make sense?
> > >
> > > JG
> > >
> > >
> > > On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> > > >
> > > > Thanks John,
> > > >
> > > > This is great!  When I trace this, it works.  I've applied it to my
> > > > code,
> > > > and I think I have added something wrong.  What happens is that all
> > the
> > > > elements just build in a single area.
> > > >
> > > > Here is what I had in the previous code:
> > > > http://www.apt11.com/test/test.html
> > > >
> > > > Essentially, I need "0" to display, then "1", "14" then "2", "15",
> > "28"
> > > > and
> > > > so on.
> > > >
> > > > Am I not applying your code correctly?  My apologies for the
> bumbling
> > > > and
> > > > thanks for the help.
> > > >
> > > > fM.
> > > >
> > > >
> > > >
> > > > On 3/29/06, John Grden <[EMAIL PROTECTED] > wrote:
> > > > >
> > > > > This will give you what you're looking for:
> > > > >
> > > > > var cols:Number = 3;
> > > > > var rows:Number = 3;
> > > > >
> > > > > for(var i:Number=0;i > > > > {
> > > > > for(var j:Number=0;j > > > > {
> > > > >  var gridLocation:Number = (i+j) + ((rows-1)*i);
> > > > >  trace("grid location = " + gridLocation);
> > > > >  // create your moviecilp
> > > > > }
> > > > > }
> > > > >
> > > > > row by row, create a movieclip per column.
> > > > >
> > > > > hth,
> > > > >
> > > > > John
> > > > >
> > > > > On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> > > > > >
> > > > > > Ok, since my email got through this morning, I'm hoping this one
> > > > gets
> > > > > > through.  Here is the question I've emailed four times
> > now.  Doesn't
> > > > > > show up in the threads.
> > > > > >
> > > > > > Here we go:
> > > > > >
> > > > > >
> > > > > >
> > > > > > Here is what I have so far:
> > > > > >
> > > > > > import mx.transitions.Tween;
> > > > > > import mx.transitions.easing.*;
> > > > > >
> > > > > > m = 0;
> > > > > > numTiles = 112;
> > > > > >
> > > > > > function placeTiles() {
> > > > > > if (m == numTiles){
> > > > > > m = 0;
> > > > > >  clearInterval(buildTiles);
> > > > > > } else {
> > > > > > _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m
> %
> > > > 14
> > > > > > * 50, _y:Math.floor(m / 14) * 50});
> > > > > > myObj = "tile" + m + "_mc";
> > > > > > new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0,
> > 100,
> > > > 35,
> > > > > > false);
> > > > > > _root[myObj].number_text.text = m;
> > > > > > m++;
> > > > > > }
> > > > > > }
> > > > > >
> > > > > > buildTiles = setInterval(placeTiles, 30);
> > > > > >
> > > > > > This works fine.  Builds the rows one after another.  But what I
> > am
> > > > > > trying to do is build one row across and one down.  Make sense?
> > > > > >
> > > > > > In essence, the final display and position of the objects will
> be:
> > > > > >
> > > > > > 123
> > > > > > 456
> > > > > > 789
> > > > > >
> > > > > > The sequence I am after:
> > > > > >
> > > > 

Re: [Flashcoders] Displaying objects

2006-03-29 Thread John Grden
> Hand coding the array would be laborsome and wouldn't
allow for extensibility.

hehe yeah... I know ;)

I'd be doing #1 too, but I guess that's probably what we like and hate about
the job we do eh?
___
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Re: [Flashcoders] Displaying objects

2006-03-29 Thread Flash Mel
Hehe, all good.  Thanks John.  I'm sitting here trying to write something
mathematically that works.  Turns out I am the suck at math, so it's making
this complicated.  Hand coding the array would be laborsome and wouldn't
allow for extensibility.

Grrr...


fM.



On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
>
> Sorry, code correction - LOL, on code that's not been tested ...
>
> for(var i:Number=0;i {
> for(var j:Number=0;j {
> this["piece_" + pieceList[i].pieces[j]]._visible = true;
> }
> }
>
>
> On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
> >
> > well, if you're using my code, then it would essentially build all
> pieces
> > the way you show it happening in that link.
> >
> > to do it diagonaly the way you specify, there's 2 ways:
> >
> > 1.  come up with an algorithm to calculate that type of movement based
> on
> > the number of rows/cols you have (ouch)
> > 2.  create the grid first, hide all pieces.  Create an array by hand
> with
> > those values, and loop that array displaying the correct pieces:
> >
> > var pieceList:Array ({pieces:[0]}, {pieces: [1,14]},
> {pieces:[2,15,28]});
> >
> > for(var i:Number=0;i > {
> > for(var j:Number=0;j > {
> > this["piece_" + pieceList[i].pieces[j]._visible = true;
> > }
> > }
> >
> > Either set visible to true of tell it to gotoAndPlay("transitionIn") or
> > whatever you have in frame lables etc.
> >
> > Make sense?
> >
> > JG
> >
> >
> > On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> > >
> > > Thanks John,
> > >
> > > This is great!  When I trace this, it works.  I've applied it to my
> > > code,
> > > and I think I have added something wrong.  What happens is that all
> the
> > > elements just build in a single area.
> > >
> > > Here is what I had in the previous code:
> > > http://www.apt11.com/test/test.html
> > >
> > > Essentially, I need "0" to display, then "1", "14" then "2", "15",
> "28"
> > > and
> > > so on.
> > >
> > > Am I not applying your code correctly?  My apologies for the bumbling
> > > and
> > > thanks for the help.
> > >
> > > fM.
> > >
> > >
> > >
> > > On 3/29/06, John Grden <[EMAIL PROTECTED] > wrote:
> > > >
> > > > This will give you what you're looking for:
> > > >
> > > > var cols:Number = 3;
> > > > var rows:Number = 3;
> > > >
> > > > for(var i:Number=0;i > > > {
> > > > for(var j:Number=0;j > > > {
> > > >  var gridLocation:Number = (i+j) + ((rows-1)*i);
> > > >  trace("grid location = " + gridLocation);
> > > >  // create your moviecilp
> > > > }
> > > > }
> > > >
> > > > row by row, create a movieclip per column.
> > > >
> > > > hth,
> > > >
> > > > John
> > > >
> > > > On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> > > > >
> > > > > Ok, since my email got through this morning, I'm hoping this one
> > > gets
> > > > > through.  Here is the question I've emailed four times
> now.  Doesn't
> > > > > show up in the threads.
> > > > >
> > > > > Here we go:
> > > > >
> > > > >
> > > > >
> > > > > Here is what I have so far:
> > > > >
> > > > > import mx.transitions.Tween;
> > > > > import mx.transitions.easing.*;
> > > > >
> > > > > m = 0;
> > > > > numTiles = 112;
> > > > >
> > > > > function placeTiles() {
> > > > > if (m == numTiles){
> > > > > m = 0;
> > > > >  clearInterval(buildTiles);
> > > > > } else {
> > > > > _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m %
> > > 14
> > > > > * 50, _y:Math.floor(m / 14) * 50});
> > > > > myObj = "tile" + m + "_mc";
> > > > > new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0,
> 100,
> > > 35,
> > > > > false);
> > > > > _root[myObj].number_text.text = m;
> > > > > m++;
> > > > > }
> > > > > }
> > > > >
> > > > > buildTiles = setInterval(placeTiles, 30);
> > > > >
> > > > > This works fine.  Builds the rows one after another.  But what I
> am
> > > > > trying to do is build one row across and one down.  Make sense?
> > > > >
> > > > > In essence, the final display and position of the objects will be:
> > > > >
> > > > > 123
> > > > > 456
> > > > > 789
> > > > >
> > > > > The sequence I am after:
> > > > >
> > > > > 1
> > > > >
> > > > > then
> > > > >
> > > > > 12
> > > > > 4
> > > > >
> > > > > then
> > > > >
> > > > > 123
> > > > > 45
> > > > > 7
> > > > >
> > > > > and so on
> > > > >
> > > > > 123
> > > > > 456
> > > > > 78
> > > > >
> > > > > Help?!
> > > > > ___
> > > > > Flashcoders@chattyfig.figleaf.com
> > > > > To change your subscription options or search the archive:
> > > > > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> > > > >
> > > > > Brought to you by Fig Leaf Software
> > > > > Premier Authorized Adobe Consulting and Training
> > > > > http://www.figleaf.com
> > > > > http://training.figleaf.com
> > > > >
> > > >
> > > >
> > > >
> > > > --
> > > > John Grden - Blitz
> > > > ___
> > > > Flashcoders@c

Re: [Flashcoders] Displaying objects

2006-03-29 Thread John Grden
Sorry, code correction - LOL, on code that's not been tested ...

for(var i:Number=0;i wrote:
>
> well, if you're using my code, then it would essentially build all pieces
> the way you show it happening in that link.
>
> to do it diagonaly the way you specify, there's 2 ways:
>
> 1.  come up with an algorithm to calculate that type of movement based on
> the number of rows/cols you have (ouch)
> 2.  create the grid first, hide all pieces.  Create an array by hand with
> those values, and loop that array displaying the correct pieces:
>
> var pieceList:Array ({pieces:[0]}, {pieces: [1,14]}, {pieces:[2,15,28]});
>
> for(var i:Number=0;i {
> for(var j:Number=0;j {
> this["piece_" + pieceList[i].pieces[j]._visible = true;
> }
> }
>
> Either set visible to true of tell it to gotoAndPlay("transitionIn") or
> whatever you have in frame lables etc.
>
> Make sense?
>
> JG
>
>
> On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> >
> > Thanks John,
> >
> > This is great!  When I trace this, it works.  I've applied it to my
> > code,
> > and I think I have added something wrong.  What happens is that all the
> > elements just build in a single area.
> >
> > Here is what I had in the previous code:
> > http://www.apt11.com/test/test.html
> >
> > Essentially, I need "0" to display, then "1", "14" then "2", "15", "28"
> > and
> > so on.
> >
> > Am I not applying your code correctly?  My apologies for the bumbling
> > and
> > thanks for the help.
> >
> > fM.
> >
> >
> >
> > On 3/29/06, John Grden <[EMAIL PROTECTED] > wrote:
> > >
> > > This will give you what you're looking for:
> > >
> > > var cols:Number = 3;
> > > var rows:Number = 3;
> > >
> > > for(var i:Number=0;i > > {
> > > for(var j:Number=0;j > > {
> > >  var gridLocation:Number = (i+j) + ((rows-1)*i);
> > >  trace("grid location = " + gridLocation);
> > >  // create your moviecilp
> > > }
> > > }
> > >
> > > row by row, create a movieclip per column.
> > >
> > > hth,
> > >
> > > John
> > >
> > > On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> > > >
> > > > Ok, since my email got through this morning, I'm hoping this one
> > gets
> > > > through.  Here is the question I've emailed four times now.  Doesn't
> > > > show up in the threads.
> > > >
> > > > Here we go:
> > > >
> > > >
> > > >
> > > > Here is what I have so far:
> > > >
> > > > import mx.transitions.Tween;
> > > > import mx.transitions.easing.*;
> > > >
> > > > m = 0;
> > > > numTiles = 112;
> > > >
> > > > function placeTiles() {
> > > > if (m == numTiles){
> > > > m = 0;
> > > >  clearInterval(buildTiles);
> > > > } else {
> > > > _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m %
> > 14
> > > > * 50, _y:Math.floor(m / 14) * 50});
> > > > myObj = "tile" + m + "_mc";
> > > > new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0, 100,
> > 35,
> > > > false);
> > > > _root[myObj].number_text.text = m;
> > > > m++;
> > > > }
> > > > }
> > > >
> > > > buildTiles = setInterval(placeTiles, 30);
> > > >
> > > > This works fine.  Builds the rows one after another.  But what I am
> > > > trying to do is build one row across and one down.  Make sense?
> > > >
> > > > In essence, the final display and position of the objects will be:
> > > >
> > > > 123
> > > > 456
> > > > 789
> > > >
> > > > The sequence I am after:
> > > >
> > > > 1
> > > >
> > > > then
> > > >
> > > > 12
> > > > 4
> > > >
> > > > then
> > > >
> > > > 123
> > > > 45
> > > > 7
> > > >
> > > > and so on
> > > >
> > > > 123
> > > > 456
> > > > 78
> > > >
> > > > Help?!
> > > > ___
> > > > Flashcoders@chattyfig.figleaf.com
> > > > To change your subscription options or search the archive:
> > > > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> > > >
> > > > Brought to you by Fig Leaf Software
> > > > Premier Authorized Adobe Consulting and Training
> > > > http://www.figleaf.com
> > > > http://training.figleaf.com
> > > >
> > >
> > >
> > >
> > > --
> > > John Grden - Blitz
> > > ___
> > > Flashcoders@chattyfig.figleaf.com
> > > To change your subscription options or search the archive:
> > > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> > >
> > > Brought to you by Fig Leaf Software
> > > Premier Authorized Adobe Consulting and Training
> > > http://www.figleaf.com
> > > http://training.figleaf.com
> > >
> > ___
> > Flashcoders@chattyfig.figleaf.com
> > To change your subscription options or search the archive:
> > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> >
> > Brought to you by Fig Leaf Software
> > Premier Authorized Adobe Consulting and Training
> > http://www.figleaf.com
> > http://training.figleaf.com
> >
>
>
>
> --
> John Grden - Blitz
>



--
John Grden - Blitz
___
Flashcoders@chattyfig.fi

Re: [Flashcoders] Displaying objects

2006-03-29 Thread John Grden
well, if you're using my code, then it would essentially build all pieces
the way you show it happening in that link.

to do it diagonaly the way you specify, there's 2 ways:

1.  come up with an algorithm to calculate that type of movement based on
the number of rows/cols you have (ouch)
2.  create the grid first, hide all pieces.  Create an array by hand with
those values, and loop that array displaying the correct pieces:

var pieceList:Array ({pieces:[0]}, {pieces: [1,14]}, {pieces:[2,15,28]});

for(var i:Number=0;i wrote:
>
> Thanks John,
>
> This is great!  When I trace this, it works.  I've applied it to my code,
> and I think I have added something wrong.  What happens is that all the
> elements just build in a single area.
>
> Here is what I had in the previous code:
> http://www.apt11.com/test/test.html
>
> Essentially, I need "0" to display, then "1", "14" then "2", "15", "28"
> and
> so on.
>
> Am I not applying your code correctly?  My apologies for the bumbling and
> thanks for the help.
>
> fM.
>
>
>
> On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
> >
> > This will give you what you're looking for:
> >
> > var cols:Number = 3;
> > var rows:Number = 3;
> >
> > for(var i:Number=0;i > {
> > for(var j:Number=0;j > {
> >  var gridLocation:Number = (i+j) + ((rows-1)*i);
> >  trace("grid location = " + gridLocation);
> >  // create your moviecilp
> > }
> > }
> >
> > row by row, create a movieclip per column.
> >
> > hth,
> >
> > John
> >
> > On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> > >
> > > Ok, since my email got through this morning, I'm hoping this one gets
> > > through.  Here is the question I've emailed four times now.  Doesn't
> > > show up in the threads.
> > >
> > > Here we go:
> > >
> > >
> > >
> > > Here is what I have so far:
> > >
> > > import mx.transitions.Tween;
> > > import mx.transitions.easing.*;
> > >
> > > m = 0;
> > > numTiles = 112;
> > >
> > > function placeTiles() {
> > > if (m == numTiles){
> > > m = 0;
> > >  clearInterval(buildTiles);
> > > } else {
> > > _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m % 14
> > > * 50, _y:Math.floor(m / 14) * 50});
> > > myObj = "tile" + m + "_mc";
> > > new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0, 100,
> 35,
> > > false);
> > > _root[myObj].number_text.text = m;
> > > m++;
> > > }
> > > }
> > >
> > > buildTiles = setInterval(placeTiles, 30);
> > >
> > > This works fine.  Builds the rows one after another.  But what I am
> > > trying to do is build one row across and one down.  Make sense?
> > >
> > > In essence, the final display and position of the objects will be:
> > >
> > > 123
> > > 456
> > > 789
> > >
> > > The sequence I am after:
> > >
> > > 1
> > >
> > > then
> > >
> > > 12
> > > 4
> > >
> > > then
> > >
> > > 123
> > > 45
> > > 7
> > >
> > > and so on
> > >
> > > 123
> > > 456
> > > 78
> > >
> > > Help?!
> > > ___
> > > Flashcoders@chattyfig.figleaf.com
> > > To change your subscription options or search the archive:
> > > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> > >
> > > Brought to you by Fig Leaf Software
> > > Premier Authorized Adobe Consulting and Training
> > > http://www.figleaf.com
> > > http://training.figleaf.com
> > >
> >
> >
> >
> > --
> > John Grden - Blitz
> > ___
> > Flashcoders@chattyfig.figleaf.com
> > To change your subscription options or search the archive:
> > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> >
> > Brought to you by Fig Leaf Software
> > Premier Authorized Adobe Consulting and Training
> > http://www.figleaf.com
> > http://training.figleaf.com
> >
> ___
> Flashcoders@chattyfig.figleaf.com
> To change your subscription options or search the archive:
> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
>
> Brought to you by Fig Leaf Software
> Premier Authorized Adobe Consulting and Training
> http://www.figleaf.com
> http://training.figleaf.com
>



--
John Grden - Blitz
___
Flashcoders@chattyfig.figleaf.com
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders

Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com


Re: [Flashcoders] Displaying objects

2006-03-29 Thread Flash Mel
Thanks John,

This is great!  When I trace this, it works.  I've applied it to my code,
and I think I have added something wrong.  What happens is that all the
elements just build in a single area.

Here is what I had in the previous code:
http://www.apt11.com/test/test.html

Essentially, I need "0" to display, then "1", "14" then "2", "15", "28" and
so on.

Am I not applying your code correctly?  My apologies for the bumbling and
thanks for the help.

fM.



On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
>
> This will give you what you're looking for:
>
> var cols:Number = 3;
> var rows:Number = 3;
>
> for(var i:Number=0;i {
> for(var j:Number=0;j {
>  var gridLocation:Number = (i+j) + ((rows-1)*i);
>  trace("grid location = " + gridLocation);
>  // create your moviecilp
> }
> }
>
> row by row, create a movieclip per column.
>
> hth,
>
> John
>
> On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> >
> > Ok, since my email got through this morning, I'm hoping this one gets
> > through.  Here is the question I've emailed four times now.  Doesn't
> > show up in the threads.
> >
> > Here we go:
> >
> >
> >
> > Here is what I have so far:
> >
> > import mx.transitions.Tween;
> > import mx.transitions.easing.*;
> >
> > m = 0;
> > numTiles = 112;
> >
> > function placeTiles() {
> > if (m == numTiles){
> > m = 0;
> >  clearInterval(buildTiles);
> > } else {
> > _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m % 14
> > * 50, _y:Math.floor(m / 14) * 50});
> > myObj = "tile" + m + "_mc";
> > new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0, 100, 35,
> > false);
> > _root[myObj].number_text.text = m;
> > m++;
> > }
> > }
> >
> > buildTiles = setInterval(placeTiles, 30);
> >
> > This works fine.  Builds the rows one after another.  But what I am
> > trying to do is build one row across and one down.  Make sense?
> >
> > In essence, the final display and position of the objects will be:
> >
> > 123
> > 456
> > 789
> >
> > The sequence I am after:
> >
> > 1
> >
> > then
> >
> > 12
> > 4
> >
> > then
> >
> > 123
> > 45
> > 7
> >
> > and so on
> >
> > 123
> > 456
> > 78
> >
> > Help?!
> > ___
> > Flashcoders@chattyfig.figleaf.com
> > To change your subscription options or search the archive:
> > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> >
> > Brought to you by Fig Leaf Software
> > Premier Authorized Adobe Consulting and Training
> > http://www.figleaf.com
> > http://training.figleaf.com
> >
>
>
>
> --
> John Grden - Blitz
> ___
> Flashcoders@chattyfig.figleaf.com
> To change your subscription options or search the archive:
> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
>
> Brought to you by Fig Leaf Software
> Premier Authorized Adobe Consulting and Training
> http://www.figleaf.com
> http://training.figleaf.com
>
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Re: [Flashcoders] Displaying objects

2006-03-29 Thread John Grden
also, i released this in the red5 repository - it's a GridManager class that
you can use to draw a grid (literally or not) and gives you methods like:

1.  calcGridLocation() - based on where you mouse is over the grid, you get
back a zero based grid number.  So if i you have a 3x3 grid, you might get
back 4 if you're in the center piece.
2.  getColRow() - based on the gridLocation number you pass in, you can get
back the column/row numbers that correspond - if you're in 4, you'd get back
2,2 (not zero based)
3.  calcCenterSpot() - gives you the pixels x/y of the center of a
particular piece based on col/row you send in.

if you already have a movieclip that has your grid graphic, you just pass
that movieclip reference to initGrid() and all the calculations will be
based on that movieclip.  You still have to pass in the grid's width and
height as this isn't always the size of the movieclip etc ;)

http://mirror1.cvsdude.com/trac/osflash/red5/browser/java/server/trunk/swf/DEV_Source/classes/org/red5/utils/GridManager.as

don't know if it's applicable to your scenario, but it works well for grid
based games.

hth,

On 3/29/06, John Grden <[EMAIL PROTECTED]> wrote:
>
> This will give you what you're looking for:
>
> var cols:Number = 3;
> var rows:Number = 3;
>
> for(var i:Number=0;i {
> for(var j:Number=0;j {
>  var gridLocation:Number = (i+j) + ((rows-1)*i);
>  trace("grid location = " + gridLocation);
>  // create your moviecilp
> }
> }
>
> row by row, create a movieclip per column.
>
> hth,
>
> John
>
>
> On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
> >
> > Ok, since my email got through this morning, I'm hoping this one gets
> > through.  Here is the question I've emailed four times now.  Doesn't
> > show up in the threads.
> >
> > Here we go:
> >
> >
> >
> > Here is what I have so far:
> >
> > import mx.transitions.Tween;
> > import mx.transitions.easing.*;
> >
> > m = 0;
> > numTiles = 112;
> >
> > function placeTiles() {
> > if (m == numTiles){
> > m = 0;
> >  clearInterval(buildTiles);
> > } else {
> > _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m % 14
> > * 50, _y:Math.floor(m / 14) * 50});
> > myObj = "tile" + m + "_mc";
> > new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0, 100, 35,
> > false);
> > _root[myObj].number_text.text = m;
> > m++;
> > }
> > }
> >
> > buildTiles = setInterval(placeTiles, 30);
> >
> > This works fine.  Builds the rows one after another.  But what I am
> > trying to do is build one row across and one down.  Make sense?
> >
> > In essence, the final display and position of the objects will be:
> >
> > 123
> > 456
> > 789
> >
> > The sequence I am after:
> >
> > 1
> >
> > then
> >
> > 12
> > 4
> >
> > then
> >
> > 123
> > 45
> > 7
> >
> > and so on
> >
> > 123
> > 456
> > 78
> >
> > Help?!
> > ___
> > Flashcoders@chattyfig.figleaf.com
> > To change your subscription options or search the archive:
> > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
> >
> > Brought to you by Fig Leaf Software
> > Premier Authorized Adobe Consulting and Training
> > http://www.figleaf.com
> > http://training.figleaf.com
> >
>
>
>
> --
> John Grden - Blitz
>



--
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Re: [Flashcoders] Displaying objects

2006-03-29 Thread John Grden
This will give you what you're looking for:

var cols:Number = 3;
var rows:Number = 3;

for(var i:Number=0;i * 50, _y:Math.floor(m / 14) * 50});
> myObj = "tile" + m + "_mc";
> new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0, 100, 35,
> false);
> _root[myObj].number_text.text = m;
> m++;
> }
> }
>
> buildTiles = setInterval(placeTiles, 30);
>
> This works fine.  Builds the rows one after another.  But what I am
> trying to do is build one row across and one down.  Make sense?
>
> In essence, the final display and position of the objects will be:
>
> 123
> 456
> 789
>
> The sequence I am after:
>
> 1
>
> then
>
> 12
> 4
>
> then
>
> 123
> 45
> 7
>
> and so on
>
> 123
> 456
> 78
>
> Help?!
> ___
> Flashcoders@chattyfig.figleaf.com
> To change your subscription options or search the archive:
> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
>
> Brought to you by Fig Leaf Software
> Premier Authorized Adobe Consulting and Training
> http://www.figleaf.com
> http://training.figleaf.com
>



--
John Grden - Blitz
___
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To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders

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