[jQuery] jquery array

2009-04-25 Thread Tom Shafer

I need to make a array from a list

ulli class=dataimg src=xtabletrtddata/td/tr/
table/li
li class=dataimg src=x2tabletrtddata2/td/tr/
table/li
li class=dataimg src=x3tabletrtddata3/td/tr/
table/li/ul

I am having a hard time using  jQuery.makeArray() to make an array
from the data and print it out. How can this be done.
Thanks

-Tom


[jQuery] loop through div

2009-03-16 Thread Tom Shafer

how can i loop through each div on a page and have them appear one by
one
i am trying

var arrayList2 = $.makeArray(document.getElementsByClassName
(.type));


$.each(arrayList2,function() {
$(this).show();
});


thanks

-tj


[jQuery] Re: loop through div

2009-03-16 Thread Tom Shafer

thanks guys!

On Mar 16, 7:26 pm, ricardobeat ricardob...@gmail.com wrote:
 jQuery.fn.showLoop = function(i){
   var i = i || 0,
     self = this;
   $( this[i] ).show(600, function(){
        self.showLoop(++i);
   });

 };

 $('.type').showLoop();

 On Mar 16, 7:27 pm, Tom  Shafer tom.sha...@gmail.com wrote:

  how can i loop through each div on a page and have them appear one by
  one
  i am trying

  var arrayList2 = $.makeArray(document.getElementsByClassName
  (.type));

                                                  
  $.each(arrayList2,function() {
                                                          $(this).show();
                                                  });

  thanks

  -tj


[jQuery] Re: loop through div

2009-03-16 Thread Tom Shafer

im getting too much recursion in firebug, any thought?

On Mar 16, 7:26 pm, ricardobeat ricardob...@gmail.com wrote:
 jQuery.fn.showLoop = function(i){
   var i = i || 0,
     self = this;
   $( this[i] ).show(600, function(){
        self.showLoop(++i);
   });

 };

 $('.type').showLoop();

 On Mar 16, 7:27 pm, Tom  Shafer tom.sha...@gmail.com wrote:

  how can i loop through each div on a page and have them appear one by
  one
  i am trying

  var arrayList2 = $.makeArray(document.getElementsByClassName
  (.type));

                                                  
  $.each(arrayList2,function() {
                                                          $(this).show();
                                                  });

  thanks

  -tj


[jQuery] Re: loop through div

2009-03-16 Thread Tom Shafer

doesnt seem to work get a recursion error

thanks!
On Mar 16, 7:26 pm, ricardobeat ricardob...@gmail.com wrote:
 jQuery.fn.showLoop = function(i){
   var i = i || 0,
     self = this;
   $( this[i] ).show(600, function(){
        self.showLoop(++i);
   });

 };

 $('.type').showLoop();

 On Mar 16, 7:27 pm, Tom  Shafer tom.sha...@gmail.com wrote:

  how can i loop through each div on a page and have them appear one by
  one
  i am trying

  var arrayList2 = $.makeArray(document.getElementsByClassName
  (.type));

                                                  
  $.each(arrayList2,function() {
                                                          $(this).show();
                                                  });

  thanks

  -tj


[jQuery] jquery each help

2009-03-15 Thread Tom Shafer

I have articles in a group of divs
div class=art
div id=leftMainimg src=media/img/greenBar.png 
width=11
height=211//div
div id=rightMain
span class=postedDatePOSTED: 15 MARCH 2008 
1400 HOURS/span
div class=articleHeader  SNEAK PREVIEW OF 
iNO CHILD.../i/
div
div class=articleContentpLorem ipsum 
dolor sit am/p/div
div class=articleDownload a 
href=#DOWNLOAD 10% DISCOUNT
PASS/a/div
div class=clearfix/div
/div
div class=art
div id=leftMainimg src=media/img/greenBar.png 
width=11
height=211//div
div id=rightMain
span class=postedDatePOSTED: 15 MARCH 2008 
1400 HOURS/span
div class=articleHeader  SNEAK PREVIEW OF 
iNO CHILD.../i/
div
div class=articleContentpLorem ipsum 
dolor sit amet, conat
nulla facilisis./p/div
div class=articleDownload a 
href=#DOWNLOAD 10% DISCOUNT
PASS/a/div
div class=clearfix/div
/div

I am trying to loop through each class and display them one at a time,
article one will display and each class inside article one will show
(using the show()) function one at a time. This will happen with each
with each article one after another for as many articles as there are.
This could be 2 this could be 10. I know this is not a convenient way
to load a page but this is what i am trying to do. I am also using a
typewriter unction to display letters one at a time.

I have this right now
var arrayList = $.makeArray($('.art').get());

$.each(arrayList,function() {
$(this).show();

$('.postedDate').show().jTypeWriter({onComplete:function(){

$('.articleHeader').show().jTypeWriter({onComplete:function(){

$('.articleContent').show().jTypeWriter({onComplete:function()
{
}});
}});
}});
});

it doesnt quite get it right.

Here is the sample page

http://pavlishgroup.com/projects/cpt-test/

thanks in advance



[jQuery] Re: jquery each help

2009-03-15 Thread Tom Shafer

Im getting the effects I want just not in the right order. I think im
going the right way with each, im just not using it the right way. Any
other thoughts?

-TJ

On Mar 15, 4:20 pm, Josh Powell seas...@gmail.com wrote:
 read up on the .animate() jQuery effect, this might be what you are
 looking for.

 http://docs.jquery.com/Effects/animate

 On Mar 15, 11:46 am, Tom  Shafer tom.sha...@gmail.com wrote:

  I have articles in a group of divs
  div class=art
                          div id=leftMainimg 
  src=media/img/greenBar.png width=11
  height=211//div
                          div id=rightMain
                                  span class=postedDatePOSTED: 15 MARCH 
  2008 1400 HOURS/span
                                  div class=articleHeader  SNEAK PREVIEW 
  OF iNO CHILD.../i/
  div
                                  div class=articleContentpLorem ipsum 
  dolor sit am/p/div
                                  div class=articleDownload a 
  href=#DOWNLOAD 10% DISCOUNT
  PASS/a/div
                                  div class=clearfix/div
                          /div
  div class=art
                          div id=leftMainimg 
  src=media/img/greenBar.png width=11
  height=211//div
                          div id=rightMain
                                  span class=postedDatePOSTED: 15 MARCH 
  2008 1400 HOURS/span
                                  div class=articleHeader  SNEAK PREVIEW 
  OF iNO CHILD.../i/
  div
                                  div class=articleContentpLorem ipsum 
  dolor sit amet, conat
  nulla facilisis./p/div
                                  div class=articleDownload a 
  href=#DOWNLOAD 10% DISCOUNT
  PASS/a/div
                          div class=clearfix/div
                          /div

  I am trying to loop through each class and display them one at a time,
  article one will display and each class inside article one will show
  (using the show()) function one at a time. This will happen with each
  with each article one after another for as many articles as there are.
  This could be 2 this could be 10. I know this is not a convenient way
  to load a page but this is what i am trying to do. I am also using a
  typewriter unction to display letters one at a time.

  I have this right now
  var arrayList = $.makeArray($('.art').get());

  $.each(arrayList,function() {
                                          $(this).show();
                                                  
  $('.postedDate').show().jTypeWriter({onComplete:function(){
                                                                  
  $('.articleHeader').show().jTypeWriter({onComplete:function(){
                                                                          
  $('.articleContent').show().jTypeWriter({onComplete:function()
  {
                                                                          }});
                                                                  }});
                                                  }});
                                          });

  it doesnt quite get it right.

  Here is the sample page

 http://pavlishgroup.com/projects/cpt-test/

  thanks in advance


[jQuery] slowly load image 1 line at a time

2009-03-13 Thread Tom Shafer

hi, I am in need of some way to slowly load a image 1 line at a time,
or maybe load a div 1 line at a time

any ideas?

thanks,
-tom


[jQuery] [Exception... Component returned failure code: 0x80070057 (NS_ERROR_ILLEGAL_VALUE)

2009-03-09 Thread Tom Shafer

what does this error mean

[Exception... Component returned failure code: 0x80070057
(NS_ERROR_ILLEGAL_VALUE) [nsIXMLHttpRequest.open] nsresult:
0x80070057 (NS_ERROR_ILLEGAL_VALUE) location: JS frame ::
http://tjshafer.com/projects/boyd/js/jquery-1.3.2.min.js ::
anonymous :: line 19 data: no]

-tj


[jQuery] nsIXMLHttpRequest.open error

2009-03-09 Thread Tom Shafer

I get the error

[Exception... Component returned failure code: 0x80070057
(NS_ERROR_ILLEGAL_VALUE) [nsIXMLHttpRequest.open] nsresult:
0x80070057 (NS_ERROR_ILLEGAL_VALUE) location: JS frame ::
http://tjshafer.com/projects/boyd/js/jquery-1.3.2.min.js ::
anonymous :: line 19 data: no]
[Break on this error] (function(){var R=/((?:\((?:\([^()]+\)|[...
(J,typeof K===string?K:K+px)}})})();
Here is the page it is on

http://tjshafer.com/projects/boyd/home.php

click on add new on the left menu, a form will pop open and when you
click next you can see the error in firebug

please let me know what it might be

-thanks,
tj


[jQuery] attr feature

2009-02-09 Thread Tom Shafer

Does the attr feature let me capture my own attribute inside a
element. I am trying and it doesnt seem to be working. I just
wondering if there was a way to do this.

Thanks

-Tom


[jQuery] Re: attr feature

2009-02-09 Thread Tom Shafer

sorry about that

$('#projectid').attr('link')

this is going into ajax post

On Feb 9, 10:59 am, MorningZ morni...@gmail.com wrote:
 Maybe showing an example of what isn't working would help others help
 you

 On Feb 9, 10:28 am, Tom  Shafer tom.sha...@gmail.com wrote:

  Does the attr feature let me capture my own attribute inside a
  element. I am trying and it doesnt seem to be working. I just
  wondering if there was a way to do this.

  Thanks

  -Tom


[jQuery] sortable update problem

2009-02-02 Thread Tom Shafer

I am using sortable and using the update feature to post the order

$(#2).sortable({
//connectWith: [#homePage,#acquire,#build],
items: li,
opacity: 90,
revert: true,
placeholder: sortHelper,
activeclass: sortActive,
hoverclass: sortHelper,
dropOnEmpty:true,
update: function(element, ui) {
 $.post(addLinks.php,{ 
step:'update',order:$(this).sortable
(serialize)});
}
});
it seems that update doesnt work after i upgraded to jquery 1.3.1
i also upgraded jquery ui to
1.5.3 as well as sortable

I can drag and drop and do everything I used to be able to do with
1.2.6. I upgraded to take advantage of the new live function for event
delegation

What could of changed or what I am i missing to make update work

Thanks

Tom


[jQuery] Re: sortable update problem

2009-02-02 Thread Tom Shafer

works perfectly, thank you very much

-Tom

On Feb 2, 12:32 pm, Richard D. Worth rdwo...@gmail.com wrote:
 jQuery UI 1.5.3 is only compatible with jQuery 1.2.6. In order to use jQuery
 UI with jQuery 1.3+, you'll need the latest preview release1.6rc6. It is
 compatible with 1.3 (but not 1.2.6), and the final release is scheduled for
 tonight. See

 http://blog.jquery.com/2009/01/30/jquery-ui-16rc6-help-us-test/

 Also note, there is a dedicated mailing list for jQuery UI help:

 http://groups.google.com/group/jquery-ui

 Thanks.

 - Richard

 On Mon, Feb 2, 2009 at 11:26 AM, Tom Shafer tom.sha...@gmail.com wrote:

  I am using sortable and using the update feature to post the order

  $(#2).sortable({
                 //connectWith: [#homePage,#acquire,#build],
                 items: li,
                 opacity: 90,
                 revert: true,
                 placeholder: sortHelper,
                 activeclass: sortActive,
                 hoverclass: sortHelper,
                 dropOnEmpty:true,
                 update: function(element, ui) {
                          $.post(addLinks.php,{
  step:'update',order:$(this).sortable
  (serialize)});
         }
     });
  it seems that update doesnt work after i upgraded to jquery 1.3.1
  i also upgraded jquery ui to
  1.5.3 as well as sortable

  I can drag and drop and do everything I used to be able to do with
  1.2.6. I upgraded to take advantage of the new live function for event
  delegation

  What could of changed or what I am i missing to make update work

  Thanks

  Tom


[jQuery] Re: sortable update problem

2009-02-02 Thread Tom Shafer



On Feb 2, 12:32 pm, Richard D. Worth rdwo...@gmail.com wrote:
 jQuery UI 1.5.3 is only compatible with jQuery 1.2.6. In order to use jQuery
 UI with jQuery 1.3+, you'll need the latest preview release1.6rc6. It is
 compatible with 1.3 (but not 1.2.6), and the final release is scheduled for
 tonight. See

 http://blog.jquery.com/2009/01/30/jquery-ui-16rc6-help-us-test/

 Also note, there is a dedicated mailing list for jQuery UI help:

 http://groups.google.com/group/jquery-ui

 Thanks.


thanks

i appreciate it
 - Richard

 On Mon, Feb 2, 2009 at 11:26 AM, Tom Shafer tom.sha...@gmail.com wrote:

  I am using sortable and using the update feature to post the order

  $(#2).sortable({
                 //connectWith: [#homePage,#acquire,#build],
                 items: li,
                 opacity: 90,
                 revert: true,
                 placeholder: sortHelper,
                 activeclass: sortActive,
                 hoverclass: sortHelper,
                 dropOnEmpty:true,
                 update: function(element, ui) {
                          $.post(addLinks.php,{
  step:'update',order:$(this).sortable
  (serialize)});
         }
     });
  it seems that update doesnt work after i upgraded to jquery 1.3.1
  i also upgraded jquery ui to
  1.5.3 as well as sortable

  I can drag and drop and do everything I used to be able to do with
  1.2.6. I upgraded to take advantage of the new live function for event
  delegation

  What could of changed or what I am i missing to make update work

  Thanks

  Tom


[jQuery] live and plugins

2009-02-01 Thread Tom Shafer

How would I make live work with plugins? With the livequery plugin i
used

$('.text-edit').livequery('click', function() {
akedit(save_url, options);

});

akedit is a not a jquery function. How would I make a plugin work with
this

Thanks,

-Tom


[jQuery] Re: live and plugins

2009-02-01 Thread Tom Shafer

no your right, i have no idea what i was thinking. I got it working

Thanks though

On Feb 1, 9:31 pm, Mike Alsup mal...@gmail.com wrote:
  How would I make live work with plugins? With the livequery plugin i
  used

  $('.text-edit').livequery('click', function() {
                  akedit(save_url, options);

          });

  akedit is a not a jquery function. How would I make a plugin work with
  this

 It should work the same way (unless I misunderstood your question):

 $('.text-edit').live('click', function() {
     akedit(save_url, options);

 });


[jQuery] jquery fadeto

2009-01-24 Thread Tom Shafer

I have the following li. I am trying to make it so when you hover over
the first a and all of the child ul with the class of sub fadeTo will
come to full opacity. When you mouseout it changes opacity again.

Here is what I have come up with.

li class=parent first id=parent1a href=aboutAbout Us/a
ul class=sub id=sub1
li id=lisub1a href=valuesOur Values/a/li
li id=lisub2a href=teamOur Team/a/li
/ul
/li

$(#parent1).find(a:first + ul).mouseover(function() {
 $(#firstImage).fadeTo(slow,.99);
   });
$(#parent1).find(a:first + ul).mouseout(function() {
 $(#firstImage).fadeTo(slow,0.33);
   });

I have it working with a:first. I just need it to work on both the a,
and the ul, I have achieved something like this with all the a's but
it fades in and out more than once when using this method.

Any suggestions?


[jQuery] move and resize window according to parent window position

2008-10-18 Thread Tom Shafer

Does anybody have a way to move a popup window so that it is always
centered over the parent window. I am having trouble figuring this
out.

Thanks,

Tom


[jQuery] apples webclip feature in jquery

2008-09-17 Thread Tom Shafer

I am wanting to write something like apples webclip feature in safari
for jquery, I am trying to figure out where the best place to start
is. Does anyone have any ideas?

Thanks,

-TJ


[jQuery] Re: apples webclip feature in jquery

2008-09-17 Thread Tom Shafer

In safari 3 there is a webclip feature to make a widget for dashboard

http://www.apple.com/pro/tips/webclip.html

I am trying to make this in javascript and would like yo use jquery

On Sep 17, 10:54 am, Andy Matthews [EMAIL PROTECTED] wrote:
 Could you elaborate? What is this webclip of which you speak?

 -Original Message-
 From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On

 Behalf Of Tom Shafer
 Sent: Wednesday, September 17, 2008 11:41 AM
 To: jQuery (English)
 Subject: [jQuery] apples webclip feature in jquery

 I am wanting to write something like apples webclip feature in safari for
 jquery, I am trying to figure out where the best place to start is. Does
 anyone have any ideas?

 Thanks,

 -TJ


[jQuery] post data response problem

2008-09-11 Thread Tom Shafer

I am getting a data response from post in the form of

variable1 | variable2

I am having trouble splitting this and applying the results to where
its needed.

$.post($(this).attr(href)),{},
function(data)
{
 update = data.split('|');
$(update[0]).replaceWith(update[1]);

};
return false;

Thanks



[jQuery] $.post callback problem

2008-09-11 Thread Tom Shafer

i am trying to use data i am getting back from $.post but I am not
able to get the function with the data in it to work



$(a.rater).click(function(event)
{
$.post($(this).attr(href)),
function(data)
{
   update = data.split('|');
  $('#'update[0]).replaceWith(update[1]);
};
return false;
}
);

i also tried

$(a.rater).click(function(event)
{
$.post($(this).attr(href)),
function(data)
{
  alert(+data);
};
return false;
}
);

any suggestions?




[jQuery] jquery.livequery with with variables

2008-07-15 Thread Tom Shafer

i got livequery to bind but i need to be able to pass a variable to it

lets say i have a function like deleteitem(id)
how can i make livequery use this function with the variable
i tried this

$(li).livequery(click, deleteitem);

but i get a syntax error
deleteitem(

how would i do something like this

thanks


[jQuery] Re: remove dynamically placed dom element

2008-07-14 Thread Tom Shafer

im not exactly sure what i would be listening for, i get the error in
firebug that deleteitem doesn't exist. I understand the concept of how
to use on other elements but im not sure how this would be used on my
submit function

On Jul 13, 11:17 pm, Kevin Pepperman [EMAIL PROTECTED] wrote:
 For dynamicly loaded elements you will need to use a plugin.

 I suggest the 'listen' plugin.

 Refer to the FAQ for more information.

 http://docs.jquery.com/Frequently_Asked_Questions#Why_do_my_events_st...https://mail.google.com/mail/#inbox/11b1f57192f17027



 On Sun, Jul 13, 2008 at 9:46 PM, Tom Shafer [EMAIL PROTECTED] wrote:

  I am using this code to add a new item to a list

  $(#addLinks).submit(function()
  {

         $.post(addLinks.php,{ step:'addLink',title:$
  ('#title').val(),url:$('#url').val(),pageID:$('#pageID').val()} ,
         function(data)
         {
                         $('#'+$('#pageID').val()).
                         append(li id='link_'+data+a
  href='javascript://'
  id='delete' onclick='deleteitem(+data+); return false;'img
  src='img/delete.gif' //ah1+$('#title').val()+/h1p+$
  ('#url').val()+/p/li);
                         $('#link_'+data).effect(pulsate, { times: 3 },
  1000);

         });
        return false;
  });

  as you can see i am adding a href='javascript://' id='delete'
  onclick='deleteitem(+data+); return false;'img src='img/
  delete.gif' //a
  to delete the newest dom element.

  this works on page refresh but I would like it to work right after
  someone added the dom element

  here is what i am using to delete data from the database and the
  element that goes along with the delete item

  function deleteitem(id) {
         $(function() {
                 $.post(addLinks.php,{ step:'deleteLink',linkId:+id});
                         $('#link_'+id).remove();

      });
  }

  $('#link_'+id).remove();  removes the item after a page refresh. How
  can it the element be removed without a page refresh after being added

  thanks

  -tom

 --
 Fred Allen  - Television is a medium because anything well done is rare.


[jQuery] using live query howto

2008-07-14 Thread Tom Shafer

i am trying to use live query to bind a click to a href on a form
submit

$(#addLinks).submit(function()
{
$('#addLinks')
 .livequery('onclick', function(event) {
deleteitem();
});
$.post(addLinks.php,{ step:'addLink',title:$
('#title').val(),url:$('#url').val(),pageID:$('#pageID').val()} ,
function(data)
{
$('#'+$('#pageID').val()).
append(li id='link_'+data+a href='javascript://'
id='delete' onclick='deleteitem(+data+); return false;'img
src='img/delete.gif' //ah1+$('#title').val()+/h1p+$
('#url').val()+/p/li);
$('#link_'+data).effect(pulsate, { times: 3 }, 1000);

});
   return false;
});

im not sure where i should put it, any help would be appreciated

thanks

-tj


[jQuery] remove dynamically placed dom element

2008-07-13 Thread Tom Shafer

I am using this code to add a new item to a list

$(#addLinks).submit(function()
{

$.post(addLinks.php,{ step:'addLink',title:$
('#title').val(),url:$('#url').val(),pageID:$('#pageID').val()} ,
function(data)
{
$('#'+$('#pageID').val()).
append(li id='link_'+data+a href='javascript://'
id='delete' onclick='deleteitem(+data+); return false;'img
src='img/delete.gif' //ah1+$('#title').val()+/h1p+$
('#url').val()+/p/li);
$('#link_'+data).effect(pulsate, { times: 3 }, 1000);

});
   return false;
});

as you can see i am adding a href='javascript://' id='delete'
onclick='deleteitem(+data+); return false;'img src='img/
delete.gif' //a
to delete the newest dom element.

this works on page refresh but I would like it to work right after
someone added the dom element

here is what i am using to delete data from the database and the
element that goes along with the delete item

function deleteitem(id) {
$(function() {
$.post(addLinks.php,{ step:'deleteLink',linkId:+id});
$('#link_'+id).remove();

 });
}

$('#link_'+id).remove();  removes the item after a page refresh. How
can it the element be removed without a page refresh after being added

thanks

-tom


[jQuery] jquery form multiple php variables

2008-07-12 Thread Tom Shafer

Hi, I am trying to use the jquery form plugin and i have 3 form fields
i need to go to php and come back and be inserted into a list. I am
having trouble getting more than 1 php variable to return.

here is the code example i am using

  $('#addLinks').ajaxForm({
// dataType identifies the expected content type of the server
response
dataType:  'json',

// success identifies the function to invoke when the server
response
// has been received
success:   processJson
});
function processJson(data) {
// 'data' is the json object returned from the server
alert(data.message);
}

and the php

?php  echo '{ message: ' . $_POST['message']. ' }';  ?

How can i return more than 1 variable and specify what returns where?

I am very confused on this

thanks


[jQuery] jquery form multiple php variables

2008-07-12 Thread Tom Shafer

Hi, I am trying to use the jquery form plugin and i have 3 form fields
i need to go to php and come back and be inserted into a list. I am
having trouble getting more than 1 php variable to return.

here is the code example i am using

  $('#addLinks').ajaxForm({
// dataType identifies the expected content type of the server
response
dataType:  'json',

// success identifies the function to invoke when the server
response
// has been received
success:   processJson
});
function processJson(data) {
// 'data' is the json object returned from the server
alert(data.message);
}

and the php

?php  echo '{ message: ' . $_POST['message']. ' }';  ?

How can i return more than 1 variable and specify what returns where?

I am very confused on this

thanks


[jQuery] jquery ajax post not working

2008-07-11 Thread Tom Shafer

I am trying to use ajax post to simply send a form field to php and
return it to a div
Here is what I have
$(document).ready(function(){
$(#addLinks).submit(function() {
$.ajax({
url: 'addLinks.php',
type: 'POST',
data: {url: $(#url).val(),title: $
(#title).val() },
error: function(){
alert('Error adding link');
},
success: function(data){
  $(#contentcol4).append(data);
 }
})
});
});
the php file contains  ? echo $_POST['url'];?

i keep getting a error of
This XML file does not appear to have any style information associated
with it. The document tree is shown below.

im not sure what to do, I am new to this

Thanks



[jQuery] thickbox moves underlying div in ie

2007-06-08 Thread Tom Shafer

When a state is pressed on my example. Thickbox opens but the
underlying div moves to the left, but only in ie.

Is there anyway to fix this?

http://thebattalion.tv/firehouses.php

Thanks

-TJ



[jQuery] Re: disable tooltip plugin upon thickbox call and enable when thickbox is closed

2007-05-26 Thread Tom Shafer

Well it seems to be a safari only issue. I wonder why that is.
Thanks anyway

-TJ

On May 26, 10:56 pm, Su [EMAIL PROTECTED] wrote:
 Be more specific? I don't see this in my copies of IE6 or Fx2.

 On 5/26/07, Tom Shafer [EMAIL PROTECTED] wrote:



  I have a page where you select a state and the tooltip plugin displays
  the states name. When you click on it thickbox appears with a list of
  states. Now when you hover around thickbox the tooltps show up. How
  can i prevent this from happening. I tried setting the z-index of the
  elements.

  Here is the problem page.

 http://www.thebattalion.tv/dev/firehouses.php

  -Tom

  Shafer



[jQuery] Re: jqgrid and php

2007-05-25 Thread Tom Shafer

Thanks. I wasnt sure what those params woudl be. Thanks

-TJ

On May 25, 5:09 am, Tony [EMAIL PROTECTED] wrote:
 Hi Tom,

 You must calculate this values by hand.
 I personaly use a exelent adodb library which returns this values from
 the resulting query.

 In your case:
 To the server are passed 4 parameters, that you must have attention.
 page - the requested page
 rows - the number of rows, that the server must return
 sidx - the culumn that must be sorted
 sord - the sort order

 Having this you must first calculate haw many rows are returned from
 the query - i.e use a count(*) function - let this is variable
 $mycount
 The total number of pages is  (fill total tag with this value) :
 $mycount/rows - (round this value).
 If the query return data you must fill the tag page with the requested
 page parameter.

 As for the LIMIT in MySql - this can be calculated easy
 You reqest by example page 5, then
 you request must end with  5*rows
 The  begining records are  rows*(5-1) + 1 records or 4*rows + 1

 By the way I have add some additinal features - subgrid. Have fixed
 some bugs.
 This will be available next week

 Regards
 Tony



[jQuery] load thick box within ajax load

2007-05-23 Thread Tom Shafer

I am using the jquery load function

function loadContent(id) {
$(#bioscontent).load(grabbios.php?id=+id+);
}

and I am wondering how I can make thickbox work inside of it. When i
try It just pushes the loading ar to the bottom of the page.

Here is the page I am using it on.
http://www.thebattalion.tv/dev/bios.php

I am trying to make it popup to play a flash movie.

Thanks

-TJ



[jQuery] simple div with scrollbar plugin

2007-05-17 Thread Tom Shafer

I am in need of a simple div with scrollbar plugisn. I am not quite
sure how to write one. Is there one out there?

Thanks



[jQuery] Re: jcarousel safari

2007-05-17 Thread Tom Shafer

That doesnt seem to work. Is there any other way.

-TJ

On May 15, 11:14 pm, Klaus Hartl [EMAIL PROTECTED] wrote:
 Karl Rudd wrote:

  I haven't looked at the page but I'll wager it's one of Safari's lazy
  update type problems. Sometimes you change the styling of an object
  and it doesn't update till it gets an actual change in the DOM.

  You can try putting the following somewhere after the carousel is built:

  if ( $.browser.safari )
  $('span/').appendTo( section ).remove();// force redraw

  Karl Rudd

 Ah, Karl, thats interesting! I have the same problem and had no clue
 what to do to fix it. Will try it out when I'm getting to the office!
 That would be just in time... :-)

 -- Klaus



[jQuery] jcarousel safari

2007-05-15 Thread Tom Shafer

In safari I have to redraw the page in order for it to work. Like
resize it or something. It has to be redrawn so I can use the arrows.
Anybody else have this prob?

-TJ



[jQuery] ajax and links

2007-04-22 Thread Tom Shafer

is it possible to have the url and the data come from the link href
using the ajax funtions in jquery?



[jQuery] Re: jquery page jump

2007-04-14 Thread Tom Shafer

Yea that does work. Here is what I have on the onsubmit

 onclick=\$('#comment.$row2['feedbackID'].').slideToggle('slow');$
('#scrollLink.$row2['feedbackID'].').ScrollTo(1500); return false;\
please note that this came from php

On Apr 14, 6:26 pm, Allan Mullan [EMAIL PROTECTED] wrote:
 You need to do an onclick=return(false); to prevent this...

 Allan

 Tom Shafer wrote:
  how do I prevent the page from jumping back to the top when calling
  scrollto from the interface plugin

 http://dev.unfetteredpress.com/story/Chavez_to_shut_down_opposition_TV#

  click on add comment



[jQuery] custom selecters

2007-04-14 Thread Tom Shafer

Hi, i need to be able to find all elements with a div id of something
like divname plus some randmom number, each div id will be like this,
so something like divname324 or divname453

so how can I select all divs with a name divname plus some random
numbers

$(#divname + random number).ajaxForm({
target: '#commentFormOutput',
success:   processcommentForm
});

Thanks

-TJ



[jQuery] jquery form plugin

2007-04-12 Thread Tom Shafer

I am trying to return html after the form has been processed. I get it
to work with plain text such as echo '{ message:  Thanks  }'; but
html doesnt seem to want to work.

Any thoughts?



[jQuery] Re: jquery form plugin

2007-04-12 Thread Tom Shafer

Yea I am using json.

http://dev.unfetteredpress.com/story/Chavez_to_shut_down_opposition_TV

click your turn and you can reply, the data is inserted into the
database it just wont come back with the html message i wouls like

Thanks,
-TJ

On Apr 12, 7:22 pm, Mike Alsup [EMAIL PROTECTED] wrote:
 Do you have the dataType set to 'json' by any chance?  Can you post a
 sample page that shows the problem?

 Mike

 On 4/12/07, Tom  Shafer [EMAIL PROTECTED] wrote:



  I am trying to return html after the form has been processed. I get it
  to work with plain text such as echo '{ message:  Thanks  }'; but
  html doesnt seem to want to work.

  Any thoughts?



[jQuery] Re: jquery form plugin

2007-04-12 Thread Tom Shafer

oh, ok cool i did not know that. Thank you.

-TJ

On Apr 12, 7:46 pm, Mike Alsup [EMAIL PROTECTED] wrote:
 Tom,

 The target and dataType options can not be used together.  If you must
 use json then you need to process the response yourself.  Otherwise
 you can just remove the dataType option and return html from the
 server and the target will be updated for you.

 Mike

 On 4/12/07, Tom  Shafer [EMAIL PROTECTED] wrote:



  Yea I am using json.

 http://dev.unfetteredpress.com/story/Chavez_to_shut_down_opposition_TV

  click your turn and you can reply, the data is inserted into the
  database it just wont come back with the html message i wouls like

  Thanks,
  -TJ

  On Apr 12, 7:22 pm, Mike Alsup [EMAIL PROTECTED] wrote:
   Do you have the dataType set to 'json' by any chance?  Can you post a
   sample page that shows the problem?

   Mike

   On 4/12/07, Tom  Shafer [EMAIL PROTECTED] wrote:

I am trying to return html after the form has been processed. I get it
to work with plain text such as echo '{ message:  Thanks  }'; but
html doesnt seem to want to work.

Any thoughts?



[jQuery] Traversing the dom selecting ever other dom

2007-04-06 Thread Tom Shafer

I was wondering how I can traverse through the dom and start at a div
and then select every other div until i want it to stop so that I may
add a class to it.

Any Ideas?

Thanks

Tom



[jQuery] Re: blockui timeout

2007-04-03 Thread Tom Shafer

thanks mike, im getting the hang of this. $this is your friend im
learning

On Apr 3, 6:32 am, Mike Alsup [EMAIL PROTECTED] wrote:
 Tom,

 Just add the timeout after you've called block().

 $('a.respond').bind('click', function() {
 var $el = $(this);
 $el.prev('div').block('h1Please a href=\login\Login/a to
 submit your opinion./a/h1',{ border: '3px solid #a00'});
 setTimeout(function(){ $el.unblock(); }, 5000);
 return false;

 });

 Mike

 PS: Thanks Erik!

 On 4/3/07, Tom  Shafer [EMAIL PROTECTED] wrote:



  Thanks guys, I got rid of the function and using this.
  $('a.respond').bind('click', function() {
   $(this).prev('div').block('h1Please a href=\login\Login/
  a to submit your opinion./a/h1',{ border: '3px solid #a00'});
  return false;
  });

  so wouldnt I need to chain the settimeout onto this and set it to call
  the function $.unblockUI?

  On Apr 2, 11:33 pm, Erik Beeson [EMAIL PROTECTED] wrote:
   Your setTimeout syntax looks a little off. Maybe:

   setTimeout(function() { $el.unblock(); }, 5000);

   --Erik

   On 4/2/07, Mike Alsup [EMAIL PROTECTED] wrote:

Tom,

If you're still using a function to block, it's something like this:

function blockElement(id) {
var $el =$('#'+id);
$el.block();
setTimeout(function() { $el.unblock(); 5000 });
}

On 4/2/07, Tom  Shafer [EMAIL PROTECTED] wrote:

 How could I use settimeout on block so that blockui will goway after a
 certain amount of time?