[jQuery] Re: Using selectors successfully...?

2009-02-08 Thread seasoup

In firefox, to see the changed html markup click on the page and do
ctrl-A to select all and then right click and View Selection
Source.  This also work if you just highlight the element you want to
see the source of.

On Feb 7, 10:05 pm, brian bally.z...@gmail.com wrote:
 On Sun, Feb 8, 2009 at 12:37 AM, gberz3 gbe...@gmail.com wrote:

  I'm just glad it only took 2 hours, and not 2 weeks.  I always tend to
  think outside the box.  Unfortunately, I often find myself inside
  another box just beside the original box.  Are there any sorts of
  explicit documentation that warns against gotchas of this nature?
  Thanks for the hand-holding all.  You guys rock!

 I think of it less as hand-holding as ants mutually forming a bridge.

 Wait -- all the ants make it across in the end, right?!


[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread Karl Rudd

That should work fine. Example: http://jsbin.com/odada

Something else must be going wrong.

Karl Rudd

On Sun, Feb 8, 2009 at 2:07 PM, gberz3 gbe...@gmail.com wrote:

 Will someone please explain to me why the following code fails to
 execute?  I have a simple test page set up and jquery doesn't seem
 happy with what I'm trying to do.  I get no errors, and when I log to
 console in firebug it shows that it is indeed finding my two objects,
 however it won't actually perform 'addClass':


$(document).ready(function() {

$(.testclass).each(function(){
$(this).addClass(midget);
});
});




 At first I just figured it was because I wasn't doing an each, but
 then after trying each and having it still fail, I was back to square
 one.  Also, is it not possible to select based on tags (e.g.
 'div.divclass')?

 Any help would be much appreciated.


 Best!



[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread Mauricio (Maujor) Samy Silva


There is nothing wrong with your jQuery code.
Double check the link to jQuery library and the HTML markup.

Try this example tested here:

style type=text/css media=all
.midget {background:red}
/style

script 
src=http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js;/script


script type=text/javascript
$(document).ready(function(){
$(.testclass).each(function(){
$(this).addClass(midget);
});
});
/script
...
body
p class=testclassSome text/p
b class=testclassSome bold text/b
...



-Mensagem Original- 
De: gberz3 gbe...@gmail.com

Para: jQuery (English) jquery-en@googlegroups.com
Enviada em: domingo, 8 de fevereiro de 2009 01:07
Assunto: [jQuery] Using selectors successfully...?




Will someone please explain to me why the following code fails to
execute?  I have a simple test page set up and jquery doesn't seem
happy with what I'm trying to do.  I get no errors, and when I log to
console in firebug it shows that it is indeed finding my two objects,
however it won't actually perform 'addClass':


$(document).ready(function() {

$(.testclass).each(function(){
$(this).addClass(midget);
});
});




At first I just figured it was because I wasn't doing an each, but
then after trying each and having it still fail, I was back to square
one.  Also, is it not possible to select based on tags (e.g.
'div.divclass')?

Any help would be much appreciated.


Best! 




[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread gberz3

Ok, this is odd.  I can perform a .fadeOut() on the acquired divs, but
the .addClass() method specifically isn't working.  Is there anything
in particular that I can check? Specific syntax?  Anything?

Also, thanks for the quick support.

On Feb 7, 10:33 pm, Mauricio \(Maujor\) Samy Silva
css.mau...@gmail.com wrote:
 There is nothing wrong with your jQuery code.
 Double check the link to jQuery library and the HTML markup.

 Try this example tested here:

 style type=text/css media=all
 .midget {background:red}
 /style

  script
 src=http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js;/script

 script type=text/javascript
  $(document).ready(function(){
  $(.testclass).each(function(){
 $(this).addClass(midget);});

  });
 /script
 ...
 body
 p class=testclassSome text/p
 b class=testclassSome bold text/b
 ...

 -Mensagem Original-
 De: gberz3 gbe...@gmail.com
 Para: jQuery (English) jquery-en@googlegroups.com
 Enviada em: domingo, 8 de fevereiro de 2009 01:07
 Assunto: [jQuery] Using selectors successfully...?



  Will someone please explain to me why the following code fails to
  execute?  I have a simple test page set up and jquery doesn't seem
  happy with what I'm trying to do.  I get no errors, and when I log to
  console in firebug it shows that it is indeed finding my two objects,
  however it won't actually perform 'addClass':

  $(document).ready(function() {

  $(.testclass).each(function(){
  $(this).addClass(midget);
  });
  });

  At first I just figured it was because I wasn't doing an each, but
  then after trying each and having it still fail, I was back to square
  one.  Also, is it not possible to select based on tags (e.g.
  'div.divclass')?

  Any help would be much appreciated.

  Best!


[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread brian

Do you see the class added in firebug's HTML view?

On Sat, Feb 7, 2009 at 10:49 PM, gberz3 gbe...@gmail.com wrote:

 Ok, this is odd.  I can perform a .fadeOut() on the acquired divs, but
 the .addClass() method specifically isn't working.  Is there anything
 in particular that I can check? Specific syntax?  Anything?

 Also, thanks for the quick support.

 On Feb 7, 10:33 pm, Mauricio \(Maujor\) Samy Silva
 css.mau...@gmail.com wrote:
 There is nothing wrong with your jQuery code.
 Double check the link to jQuery library and the HTML markup.

 Try this example tested here:

 style type=text/css media=all
 .midget {background:red}
 /style

  script
 src=http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js;/script

 script type=text/javascript
  $(document).ready(function(){
  $(.testclass).each(function(){
 $(this).addClass(midget);});

  });
 /script
 ...
 body
 p class=testclassSome text/p
 b class=testclassSome bold text/b
 ...

 -Mensagem Original-
 De: gberz3 gbe...@gmail.com
 Para: jQuery (English) jquery-en@googlegroups.com
 Enviada em: domingo, 8 de fevereiro de 2009 01:07
 Assunto: [jQuery] Using selectors successfully...?



  Will someone please explain to me why the following code fails to
  execute?  I have a simple test page set up and jquery doesn't seem
  happy with what I'm trying to do.  I get no errors, and when I log to
  console in firebug it shows that it is indeed finding my two objects,
  however it won't actually perform 'addClass':

  $(document).ready(function() {

  $(.testclass).each(function(){
  $(this).addClass(midget);
  });
  });

  At first I just figured it was because I wasn't doing an each, but
  then after trying each and having it still fail, I was back to square
  one.  Also, is it not possible to select based on tags (e.g.
  'div.divclass')?

  Any help would be much appreciated.

  Best!


[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread gberz3

Alrighty.  First and foremost color me embarrassed, but I wasn't aware
that the actual source wasn't manipulated.  For instance, if I click
on the browsers' VIEW SOURCE, it maintains the original.  However, if
I view the OBJECT via the CONSOLE of either Firebug, or view the HTML
via the CONSOLE in Safari then I see the changes.

Is this something I should have picked up in Javascript 101?  Do
browsers always maintain the original source?  And more important,
where would I have found this bit of information?  What, exactly, is
the most efficient workflow for testing items of this nature?

On Feb 7, 11:32 pm, brian bally.z...@gmail.com wrote:
 Do you see the class added in firebug's HTML view?

 On Sat, Feb 7, 2009 at 10:49 PM, gberz3 gbe...@gmail.com wrote:

  Ok, this is odd.  I can perform a .fadeOut() on the acquired divs, but
  the .addClass() method specifically isn't working.  Is there anything
  in particular that I can check? Specific syntax?  Anything?

  Also, thanks for the quick support.

  On Feb 7, 10:33 pm, Mauricio \(Maujor\) Samy Silva
  css.mau...@gmail.com wrote:
  There is nothing wrong with your jQuery code.
  Double check the link to jQuery library and the HTML markup.

  Try this example tested here:

  style type=text/css media=all
  .midget {background:red}
  /style

   script
  src=http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js;/script

  script type=text/javascript
   $(document).ready(function(){
   $(.testclass).each(function(){
  $(this).addClass(midget);});

   });
  /script
  ...
  body
  p class=testclassSome text/p
  b class=testclassSome bold text/b
  ...

  -Mensagem Original-
  De: gberz3 gbe...@gmail.com
  Para: jQuery (English) jquery-en@googlegroups.com
  Enviada em: domingo, 8 de fevereiro de 2009 01:07
  Assunto: [jQuery] Using selectors successfully...?

   Will someone please explain to me why the following code fails to
   execute?  I have a simple test page set up and jquery doesn't seem
   happy with what I'm trying to do.  I get no errors, and when I log to
   console in firebug it shows that it is indeed finding my two objects,
   however it won't actually perform 'addClass':

   $(document).ready(function() {

   $(.testclass).each(function(){
   $(this).addClass(midget);
   });
   });

   At first I just figured it was because I wasn't doing an each, but
   then after trying each and having it still fail, I was back to square
   one.  Also, is it not possible to select based on tags (e.g.
   'div.divclass')?

   Any help would be much appreciated.

   Best!


[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread brian

I believe that all browsers maintain the *original* source that they
receive. This used to bug the heck out of me until a) the FF
WebDeveloper extension came along with view rendered source and, b)
I realised that it's in everyone's best interest that the browser
inform you of the exact nature of the source that was received from
the server. Now, of course, there's also firebug with which to see the
changes.

Whether browsers should include a view rendered source option by
default is another matter. (hmmm ... maybe I should go dig around in
about:config)

On Sat, Feb 7, 2009 at 11:48 PM, gberz3 gbe...@gmail.com wrote:

 Alrighty.  First and foremost color me embarrassed, but I wasn't aware
 that the actual source wasn't manipulated.  For instance, if I click
 on the browsers' VIEW SOURCE, it maintains the original.  However, if
 I view the OBJECT via the CONSOLE of either Firebug, or view the HTML
 via the CONSOLE in Safari then I see the changes.

 Is this something I should have picked up in Javascript 101?  Do
 browsers always maintain the original source?  And more important,
 where would I have found this bit of information?  What, exactly, is
 the most efficient workflow for testing items of this nature?

 On Feb 7, 11:32 pm, brian bally.z...@gmail.com wrote:
 Do you see the class added in firebug's HTML view?

 On Sat, Feb 7, 2009 at 10:49 PM, gberz3 gbe...@gmail.com wrote:

  Ok, this is odd.  I can perform a .fadeOut() on the acquired divs, but
  the .addClass() method specifically isn't working.  Is there anything
  in particular that I can check? Specific syntax?  Anything?

  Also, thanks for the quick support.

  On Feb 7, 10:33 pm, Mauricio \(Maujor\) Samy Silva
  css.mau...@gmail.com wrote:
  There is nothing wrong with your jQuery code.
  Double check the link to jQuery library and the HTML markup.

  Try this example tested here:

  style type=text/css media=all
  .midget {background:red}
  /style

   script
  src=http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js;/script

  script type=text/javascript
   $(document).ready(function(){
   $(.testclass).each(function(){
  $(this).addClass(midget);});

   });
  /script
  ...
  body
  p class=testclassSome text/p
  b class=testclassSome bold text/b
  ...

  -Mensagem Original-
  De: gberz3 gbe...@gmail.com
  Para: jQuery (English) jquery-en@googlegroups.com
  Enviada em: domingo, 8 de fevereiro de 2009 01:07
  Assunto: [jQuery] Using selectors successfully...?

   Will someone please explain to me why the following code fails to
   execute?  I have a simple test page set up and jquery doesn't seem
   happy with what I'm trying to do.  I get no errors, and when I log to
   console in firebug it shows that it is indeed finding my two objects,
   however it won't actually perform 'addClass':

   $(document).ready(function() {

   $(.testclass).each(function(){
   $(this).addClass(midget);
   });
   });

   At first I just figured it was because I wasn't doing an each, but
   then after trying each and having it still fail, I was back to square
   one.  Also, is it not possible to select based on tags (e.g.
   'div.divclass')?

   Any help would be much appreciated.

   Best!


[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread gberz3

I'm just glad it only took 2 hours, and not 2 weeks.  I always tend to
think outside the box.  Unfortunately, I often find myself inside
another box just beside the original box.  Are there any sorts of
explicit documentation that warns against gotchas of this nature?
Thanks for the hand-holding all.  You guys rock!



On Feb 8, 12:28 am, brian bally.z...@gmail.com wrote:
 I believe that all browsers maintain the *original* source that they
 receive. This used to bug the heck out of me until a) the FF
 WebDeveloper extension came along with view rendered source and, b)
 I realised that it's in everyone's best interest that the browser
 inform you of the exact nature of the source that was received from
 the server. Now, of course, there's also firebug with which to see the
 changes.

 Whether browsers should include a view rendered source option by
 default is another matter. (hmmm ... maybe I should go dig around in
 about:config)

 On Sat, Feb 7, 2009 at 11:48 PM, gberz3 gbe...@gmail.com wrote:

  Alrighty.  First and foremost color me embarrassed, but I wasn't aware
  that the actual source wasn't manipulated.  For instance, if I click
  on the browsers' VIEW SOURCE, it maintains the original.  However, if
  I view the OBJECT via the CONSOLE of either Firebug, or view the HTML
  via the CONSOLE in Safari then I see the changes.

  Is this something I should have picked up in Javascript 101?  Do
  browsers always maintain the original source?  And more important,
  where would I have found this bit of information?  What, exactly, is
  the most efficient workflow for testing items of this nature?

  On Feb 7, 11:32 pm, brian bally.z...@gmail.com wrote:
  Do you see the class added in firebug's HTML view?

  On Sat, Feb 7, 2009 at 10:49 PM, gberz3 gbe...@gmail.com wrote:

   Ok, this is odd.  I can perform a .fadeOut() on the acquired divs, but
   the .addClass() method specifically isn't working.  Is there anything
   in particular that I can check? Specific syntax?  Anything?

   Also, thanks for the quick support.

   On Feb 7, 10:33 pm, Mauricio \(Maujor\) Samy Silva
   css.mau...@gmail.com wrote:
   There is nothing wrong with your jQuery code.
   Double check the link to jQuery library and the HTML markup.

   Try this example tested here:

   style type=text/css media=all
   .midget {background:red}
   /style

    script
   src=http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js;/script

   script type=text/javascript
    $(document).ready(function(){
    $(.testclass).each(function(){
   $(this).addClass(midget);});

    });
   /script
   ...
   body
   p class=testclassSome text/p
   b class=testclassSome bold text/b
   ...

   -Mensagem Original-
   De: gberz3 gbe...@gmail.com
   Para: jQuery (English) jquery-en@googlegroups.com
   Enviada em: domingo, 8 de fevereiro de 2009 01:07
   Assunto: [jQuery] Using selectors successfully...?

Will someone please explain to me why the following code fails to
execute?  I have a simple test page set up and jquery doesn't seem
happy with what I'm trying to do.  I get no errors, and when I log to
console in firebug it shows that it is indeed finding my two objects,
however it won't actually perform 'addClass':

$(document).ready(function() {

$(.testclass).each(function(){
$(this).addClass(midget);
});
});

At first I just figured it was because I wasn't doing an each, but
then after trying each and having it still fail, I was back to square
one.  Also, is it not possible to select based on tags (e.g.
'div.divclass')?

Any help would be much appreciated.

Best!


[jQuery] Re: Using selectors successfully...?

2009-02-07 Thread brian

On Sun, Feb 8, 2009 at 12:37 AM, gberz3 gbe...@gmail.com wrote:

 I'm just glad it only took 2 hours, and not 2 weeks.  I always tend to
 think outside the box.  Unfortunately, I often find myself inside
 another box just beside the original box.  Are there any sorts of
 explicit documentation that warns against gotchas of this nature?
 Thanks for the hand-holding all.  You guys rock!

I think of it less as hand-holding as ants mutually forming a bridge.

Wait -- all the ants make it across in the end, right?!