Re: Displaying octal numbers in bash
While on the octal front, anyone know how to get the date command, when used with format specifiers, NOT to prefix a number with a zero? I use it in a Makefile to put a time stamp in a C program, but the leading 0 forces the compiler to think it is octal. So, this month '09' is not accepted. Offending are month, hour and minute. day and year have a format without leading 0. e.g.; date +%m gives '09'. On Wed, 24 Sep 2003 21:00:08 -0400 Joel Hammer [EMAIL PROTECTED] wrote: I understand that bash will do arithmetic in octal if you prefix the constant with 0. So: a=05 b=017 c=$((a*b)) echo $c yields 75 This is the correct answer, but it is in decimals, not octals. Is there a way to make echo display octal? Thanks, Joel -- ++···+ · Roger Oberholtzer · E-mail: [EMAIL PROTECTED]· · OPQ Systems AB · WWW: http://www.opq.se/ · · Erik Dahlbergsgatan 41-43 ·Phone: Int + 46 8 314223 · · 115 34 Stockholm · Mobile: Int + 46 733 621657 · · Sweden · Fax: Int + 46 8 302602 · ++···+ ___ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc - http://www.linux-sxs.org/mailman/listinfo/linux-users
Re: Displaying octal numbers in bash
On Thu, 25 Sep 2003 08:40:02 +0200 Roger Oberholtzer [EMAIL PROTECTED] wrote: While on the octal front, anyone know how to get the date command, when used with format specifiers, NOT to prefix a number with a zero? I use it in a Makefile to put a time stamp in a C program, but the leading 0 forces the compiler to think it is octal. So, this month '09' is not accepted. Offending are month, hour and minute. day and year have a format without leading 0. e.g.; date +%m gives '09'. from the man page: By default, date pads numeric fields with zeroes. GNU date recognizes the following modifiers between `%' and a numeric directive. `-' (hyphen) do not pad the field `_' (underscore) pad the field with spaces Ciao, David A. Bandel -- Focus on the dream, not the competition. Nemesis Racing Team motto GPG key autoresponder: mailto:[EMAIL PROTECTED] pgp0.pgp Description: PGP signature ___ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc - http://www.linux-sxs.org/mailman/listinfo/linux-users
Re: Displaying octal numbers in bash
This seems more work that it should be. I did solve my problem with bc, but, there must be an easy way to get bash to display octal. Joel On Wed, Sep 24, 2003 at 06:35:18PM -0700, Tom Wekell wrote: Joel Hammer wrote: I understand that bash will do arithmetic in octal if you prefix the constant with 0. So: a=05 b=017 c=$((a*b)) echo $c yields 75 This is the correct answer, but it is in decimals, not octals. Is there a way to make echo display octal? Thanks, Joel More arithmetic? echo $((8#$c*1)) gives 61 ___ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc - http://www.linux-sxs.org/mailman/listinfo/linux-users
Displaying octal numbers in bash
I understand that bash will do arithmetic in octal if you prefix the constant with 0. So: a=05 b=017 c=$((a*b)) echo $c yields 75 This is the correct answer, but it is in decimals, not octals. Is there a way to make echo display octal? Thanks, Joel ___ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc - http://www.linux-sxs.org/mailman/listinfo/linux-users
Re: Displaying octal numbers in bash
Joel Hammer wrote: I understand that bash will do arithmetic in octal if you prefix the constant with 0. So: a=05 b=017 c=$((a*b)) echo $c yields 75 This is the correct answer, but it is in decimals, not octals. Is there a way to make echo display octal? Thanks, Joel More arithmetic? echo $((8#$c*1)) gives 61 Tom Wekell ___ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc - http://www.linux-sxs.org/mailman/listinfo/linux-users
