Re: [Matplotlib-users] MultipleLocator and MaxNLocator
On 14-Feb-2015 02:29, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users Tommy, Perhaps you might find it useful to look at the Python class that Justin Talbot wrote (http://www.justintalbot.com/research/axis-labeling/). I find this very useful in my own work. -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks() #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) ax1.set_xticks(ax1.get_xticks()[1:-1]) ax1.plot(list(range(11))) plt.show() On Sat, Feb 14, 2015 at 2:01 AM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Tommy, (Sorry for the doubleup. I just realized I forgot to hit reply-all.) Do you want to remove the tick at 0 and only have 5,10, etc.? Could you just do something like this instead: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.set_xticks(range(5,11,5)) ax1.plot(range(11)) plt.show() Ryan On Sat, Feb 14, 2015 at 10:47 AM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks() #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) ax1.set_xticks(ax1.get_xticks()[1:-1]) ax1.plot(list(range(11))) plt.show() On Sat, Feb 14, 2015 at 2:01 AM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
On 2015/02/14 7:33 AM, Tommy Carstensen wrote: Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this: ax1.xaxis.set_major_locator(MaxNLocator(prune='lower')) Aha! The problem is that the MaxNLocator is the only one with the prune kwarg. It could be added to the MultipleLocator. For now, though, you can make your own specialized Locator, hardwired to omit the first tick, like this: from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[1:] then just use ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) I haven't tested it--but give it a try. What it is doing is making a subclass of MultipleLocator, and altering only the one little bit of its behavior that you want to modify. Everything else is automatically inherited from the base class, MultipleLocator. Eric But that then overrides this: ax1.xaxis.set_major_locator(MultipleLocator(5)) On Sat, Feb 14, 2015 at 5:27 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, (Sorry for the doubleup. I just realized I forgot to hit reply-all.) Do you want to remove the tick at 0 and only have 5,10, etc.? Could you just do something like this instead: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.set_xticks(range(5,11,5)) ax1.plot(range(11)) plt.show() Ryan On Sat, Feb 14, 2015 at 10:47 AM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks() #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) ax1.set_xticks(ax1.get_xticks()[1:-1]) ax1.plot(list(range(11))) plt.show() On Sat, Feb 14, 2015 at 2:01 AM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Tommy, I'm sorry. I forgot to hit send all *again*. Below is my original message, but the function I wrote is updated because it wasn't exactly correct Ah. I was working on something to help out, so I'm just seeing Eric's very elegant solution, which I have yet to try. However, I feel like you might run into some problems if you always drop the first tick. For example, try this plot: __ import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(2,12,1000) ys = np.sin(xs) n = 5 fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) ax1.xaxis.set_major_locator(MultipleLocator(5)) plt.show() _ In this case, dropping the first tick will result in only one tick on the screen. What is your use-case? Are you annoyed that the axis labels are overlapping at the far left? If that's the case, here's a little function (trimticks) that I whipped up that might help. It drops the far left or far right label if it is exactly at the edge of the axes. Should work for y axes as well. _ def trimticks(ax, n=5): xmin, xmax = ax.get_xlim() if xmin%n == 0: xmin = xmin+n else: xmin = xmin + n - xmin%n if not xmax%n == 0: xmax = xmax + n - xmax%n ticks = np.arange(xmin, xmax, n) ax.set_xticks(ticks) import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(0,20,1) ys = np.sin(xs) fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) trimticks(ax1) plt.show() ___ On Sat, Feb 14, 2015 at 1:45 PM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Erik, that doesn't seem to work either. I tried this: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[2:] fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) #ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1]) ax1.plot(list(range(21))) plt.show() Here is an example of the use of prune='lower', but it does not allow one to set the tick step size: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib I think my best bet is to just set those ticks manually. On Sat, Feb 14, 2015 at 6:19 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 7:33 AM, Tommy Carstensen wrote: Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this: ax1.xaxis.set_major_locator(MaxNLocator(prune='lower')) Aha! The problem is that the MaxNLocator is the only one with the prune kwarg. It could be added to the MultipleLocator. For now, though, you can make your own specialized Locator, hardwired to omit the first tick, like this: from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[1:] then just use ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) I haven't tested it--but give it a try. What it is doing is making a subclass of MultipleLocator, and altering only the one little bit of its behavior that you want to modify. Everything else is automatically inherited from the base class, MultipleLocator. Eric But that then overrides this: ax1.xaxis.set_major_locator(MultipleLocator(5)) On Sat, Feb 14, 2015 at 5:27 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, (Sorry for the doubleup. I just realized I forgot to hit reply-all.) Do you want to remove the tick at 0 and only have 5,10, etc.? Could you just do something like this instead: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.set_xticks(range(5,11,5)) ax1.plot(range(11)) plt.show() Ryan On Sat, Feb 14, 2015 at 10:47 AM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks()
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
On 2015/02/14 5:47 AM, Tommy Carstensen wrote: Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. What is the effect you are trying to achieve? How would you describe the desired tick placement algorithm? Eric import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks() #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) ax1.set_xticks(ax1.get_xticks()[1:-1]) ax1.plot(list(range(11))) plt.show() On Sat, Feb 14, 2015 at 2:01 AM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Erik, that doesn't seem to work either. I tried this: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[2:] fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) #ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1]) ax1.plot(list(range(21))) plt.show() Here is an example of the use of prune='lower', but it does not allow one to set the tick step size: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib I think my best bet is to just set those ticks manually. On Sat, Feb 14, 2015 at 6:19 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 7:33 AM, Tommy Carstensen wrote: Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this: ax1.xaxis.set_major_locator(MaxNLocator(prune='lower')) Aha! The problem is that the MaxNLocator is the only one with the prune kwarg. It could be added to the MultipleLocator. For now, though, you can make your own specialized Locator, hardwired to omit the first tick, like this: from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[1:] then just use ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) I haven't tested it--but give it a try. What it is doing is making a subclass of MultipleLocator, and altering only the one little bit of its behavior that you want to modify. Everything else is automatically inherited from the base class, MultipleLocator. Eric But that then overrides this: ax1.xaxis.set_major_locator(MultipleLocator(5)) On Sat, Feb 14, 2015 at 5:27 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, (Sorry for the doubleup. I just realized I forgot to hit reply-all.) Do you want to remove the tick at 0 and only have 5,10, etc.? Could you just do something like this instead: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.set_xticks(range(5,11,5)) ax1.plot(range(11)) plt.show() Ryan On Sat, Feb 14, 2015 at 10:47 AM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks() #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) ax1.set_xticks(ax1.get_xticks()[1:-1]) ax1.plot(list(range(11))) plt.show() On Sat, Feb 14, 2015 at 2:01 AM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Eric, it works if I do: return MultipleLocator.tick_values(self, vmin, vmax)[2:] But not if I do as first suggested by you: return MultipleLocator.tick_values(self, vmin, vmax)[1:] I don't understand this behaviour. It should be [1:]. I'll just set the ticks manually. Seems to be the easiest thing. It would be awesome, if MPL had the same behaviour as gnuplot, which allows me to simply do: set xtics start, incr On Sat, Feb 14, 2015 at 7:09 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 8:45 AM, Tommy Carstensen wrote: Erik, that doesn't seem to work either. I tried this: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[2:] fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) #ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1]) ax1.plot(list(range(21))) plt.show() Are you sure? I tried it, and it works for me. See attached script and output. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
On 2015/02/14 8:45 AM, Tommy Carstensen wrote:
Erik, that doesn't seem to work either. I tried this:
import matplotlib.pyplot as plt
from matplotlib.ticker import MultipleLocator
class TrimmedMultipleLocator(MultipleLocator):
def tick_values(self, vmin, vmax):
return MultipleLocator.tick_values(self, vmin, vmax)[2:]
fig = plt.figure()
ax1 = fig.add_subplot(111)
ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5))
#xticks[0].label1.set_visible(False)
#xticks[-1].label1.set_visible(False)
#ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1])
ax1.plot(list(range(21)))
plt.show()
Are you sure? I tried it, and it works for me. See attached script and
output.
Eric
test_loc.pdf
Description: Adobe PDF document
import matplotlib.pyplot as plt
from matplotlib.ticker import MultipleLocator
class TrimmedMultipleLocator(MultipleLocator):
def tick_values(self, vmin, vmax):
return MultipleLocator.tick_values(self, vmin, vmax)[2:]
fig, ax1 = plt.subplots()
ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5))
ax1.plot(list(range(21)))
fig.savefig('test_loc.pdf')
--
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Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Ryan, my use case is indeed that I want to avoid overlapping ticks and I want to avoid them by not displaying them. Here is a guy with the same problem: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib Here is the problem at the top left of my plot: www.tommycarstensen.com/matplotlib.png I'll just set the ticks manually. Sadly seems like the easiest thing to do. On Sat, Feb 14, 2015 at 7:01 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, I'm sorry. I forgot to hit send all *again*. Below is my original message, but the function I wrote is updated because it wasn't exactly correct Ah. I was working on something to help out, so I'm just seeing Eric's very elegant solution, which I have yet to try. However, I feel like you might run into some problems if you always drop the first tick. For example, try this plot: __ import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(2,12,1000) ys = np.sin(xs) n = 5 fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) ax1.xaxis.set_major_locator(MultipleLocator(5)) plt.show() _ In this case, dropping the first tick will result in only one tick on the screen. What is your use-case? Are you annoyed that the axis labels are overlapping at the far left? If that's the case, here's a little function (trimticks) that I whipped up that might help. It drops the far left or far right label if it is exactly at the edge of the axes. Should work for y axes as well. _ def trimticks(ax, n=5): xmin, xmax = ax.get_xlim() if xmin%n == 0: xmin = xmin+n else: xmin = xmin + n - xmin%n if not xmax%n == 0: xmax = xmax + n - xmax%n ticks = np.arange(xmin, xmax, n) ax.set_xticks(ticks) import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(0,20,1) ys = np.sin(xs) fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) trimticks(ax1) plt.show() ___ On Sat, Feb 14, 2015 at 1:45 PM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Erik, that doesn't seem to work either. I tried this: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[2:] fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) #ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1]) ax1.plot(list(range(21))) plt.show() Here is an example of the use of prune='lower', but it does not allow one to set the tick step size: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib I think my best bet is to just set those ticks manually. On Sat, Feb 14, 2015 at 6:19 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 7:33 AM, Tommy Carstensen wrote: Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this: ax1.xaxis.set_major_locator(MaxNLocator(prune='lower')) Aha! The problem is that the MaxNLocator is the only one with the prune kwarg. It could be added to the MultipleLocator. For now, though, you can make your own specialized Locator, hardwired to omit the first tick, like this: from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[1:] then just use ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) I haven't tested it--but give it a try. What it is doing is making a subclass of MultipleLocator, and altering only the one little bit of its behavior that you want to modify. Everything else is automatically inherited from the base class, MultipleLocator. Eric But that then overrides this: ax1.xaxis.set_major_locator(MultipleLocator(5)) On Sat, Feb 14, 2015 at 5:27 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, (Sorry for the doubleup. I just realized I forgot to hit reply-all.) Do you want to remove the tick at 0 and only have 5,10, etc.? Could you just do something like this instead: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.set_xticks(range(5,11,5)) ax1.plot(range(11)) plt.show()
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this: ax1.xaxis.set_major_locator(MaxNLocator(prune='lower')) But that then overrides this: ax1.xaxis.set_major_locator(MultipleLocator(5)) On Sat, Feb 14, 2015 at 5:27 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, (Sorry for the doubleup. I just realized I forgot to hit reply-all.) Do you want to remove the tick at 0 and only have 5,10, etc.? Could you just do something like this instead: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.set_xticks(range(5,11,5)) ax1.plot(range(11)) plt.show() Ryan On Sat, Feb 14, 2015 at 10:47 AM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Thanks for you answer Eric. I had to get some sleep before trying out things. I currently have the code below, but it does not remove the zero value tick. It removes the tick at 5 and 10 however. import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(MultipleLocator(5)) xticks = ax1.xaxis.get_major_ticks() #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) ax1.set_xticks(ax1.get_xticks()[1:-1]) ax1.plot(list(range(11))) plt.show() On Sat, Feb 14, 2015 at 2:01 AM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
On 2015/02/14 9:15 AM, Tommy Carstensen wrote: Eric, it works if I do: return MultipleLocator.tick_values(self, vmin, vmax)[2:] But not if I do as first suggested by you: return MultipleLocator.tick_values(self, vmin, vmax)[1:] Are you using my test script but getting a different result? If not, what is the difference in your test script? I don't understand this behaviour. It should be [1:]. I'll just set the ticks manually. Seems to be the easiest thing. It would be awesome, if MPL had the same behaviour as gnuplot, which allows me to simply do: set xtics start, incr def xtics(ax, start, incr): stop = ax.dataLim.x1 + 0.01 * incr ax.xaxis.set_ticks(np.arange(start, stop, incr)) Now invoke that function *after* all your plot calls, so that the dataLim bounding box includes all the data in your plot. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Ryan, I stopped using gnuplot, because it requires the data to be formatted in very specific ways :) I remember having functions just to format the input data correctly for heat plots and the wrapper scripts I wrote were quite convoluted. Matplotlib has its advantages for sure. Otherwise I would not have switched. I'm just frustrated with being back at the start line. Thanks for your help and bearing with my impatience. On Sat, Feb 14, 2015 at 7:42 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Yep. I see your problem. My function and Eric's object should help here. A sore-spot with many folks coming over to Matplotlib from X is the fact that MPL does not calculate the size of text until the plot is generated. That means it doesn't always get text positioning, etc. exactly correct. That takes a little getting used to, and for me, it is minor. Admit it, Gnuplot as it's quirks as well :) I always hated that it wouldn't cut off some markers at the edge of the screen. For example, with Gnuplot 4.6rev5 the following plot x with points ps 7 Leads to a bunch of markers running over the axes limits. (Maybe there is a way to fix this now. Many years ago that was not the case.) Ryan On Sat, Feb 14, 2015 at 2:18 PM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Ryan, my use case is indeed that I want to avoid overlapping ticks and I want to avoid them by not displaying them. Here is a guy with the same problem: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib Here is the problem at the top left of my plot: www.tommycarstensen.com/matplotlib.png I'll just set the ticks manually. Sadly seems like the easiest thing to do. On Sat, Feb 14, 2015 at 7:01 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, I'm sorry. I forgot to hit send all *again*. Below is my original message, but the function I wrote is updated because it wasn't exactly correct Ah. I was working on something to help out, so I'm just seeing Eric's very elegant solution, which I have yet to try. However, I feel like you might run into some problems if you always drop the first tick. For example, try this plot: __ import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(2,12,1000) ys = np.sin(xs) n = 5 fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) ax1.xaxis.set_major_locator(MultipleLocator(5)) plt.show() _ In this case, dropping the first tick will result in only one tick on the screen. What is your use-case? Are you annoyed that the axis labels are overlapping at the far left? If that's the case, here's a little function (trimticks) that I whipped up that might help. It drops the far left or far right label if it is exactly at the edge of the axes. Should work for y axes as well. _ def trimticks(ax, n=5): xmin, xmax = ax.get_xlim() if xmin%n == 0: xmin = xmin+n else: xmin = xmin + n - xmin%n if not xmax%n == 0: xmax = xmax + n - xmax%n ticks = np.arange(xmin, xmax, n) ax.set_xticks(ticks) import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(0,20,1) ys = np.sin(xs) fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) trimticks(ax1) plt.show() ___ On Sat, Feb 14, 2015 at 1:45 PM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Erik, that doesn't seem to work either. I tried this: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[2:] fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) #ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1]) ax1.plot(list(range(21))) plt.show() Here is an example of the use of prune='lower', but it does not allow one to set the tick step size: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib I think my best bet is to just set those ticks manually. On Sat, Feb 14, 2015 at 6:19 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 7:33 AM, Tommy Carstensen wrote: Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this:
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Yep. I see your problem. My function and Eric's object should help here. A sore-spot with many folks coming over to Matplotlib from X is the fact that MPL does not calculate the size of text until the plot is generated. That means it doesn't always get text positioning, etc. exactly correct. That takes a little getting used to, and for me, it is minor. Admit it, Gnuplot as it's quirks as well :) I always hated that it wouldn't cut off some markers at the edge of the screen. For example, with Gnuplot 4.6rev5 the following plot x with points ps 7 Leads to a bunch of markers running over the axes limits. (Maybe there is a way to fix this now. Many years ago that was not the case.) Ryan On Sat, Feb 14, 2015 at 2:18 PM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Ryan, my use case is indeed that I want to avoid overlapping ticks and I want to avoid them by not displaying them. Here is a guy with the same problem: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib Here is the problem at the top left of my plot: www.tommycarstensen.com/matplotlib.png I'll just set the ticks manually. Sadly seems like the easiest thing to do. On Sat, Feb 14, 2015 at 7:01 PM, Ryan Nelson rnelsonc...@gmail.com wrote: Tommy, I'm sorry. I forgot to hit send all *again*. Below is my original message, but the function I wrote is updated because it wasn't exactly correct Ah. I was working on something to help out, so I'm just seeing Eric's very elegant solution, which I have yet to try. However, I feel like you might run into some problems if you always drop the first tick. For example, try this plot: __ import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(2,12,1000) ys = np.sin(xs) n = 5 fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) ax1.xaxis.set_major_locator(MultipleLocator(5)) plt.show() _ In this case, dropping the first tick will result in only one tick on the screen. What is your use-case? Are you annoyed that the axis labels are overlapping at the far left? If that's the case, here's a little function (trimticks) that I whipped up that might help. It drops the far left or far right label if it is exactly at the edge of the axes. Should work for y axes as well. _ def trimticks(ax, n=5): xmin, xmax = ax.get_xlim() if xmin%n == 0: xmin = xmin+n else: xmin = xmin + n - xmin%n if not xmax%n == 0: xmax = xmax + n - xmax%n ticks = np.arange(xmin, xmax, n) ax.set_xticks(ticks) import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator import numpy as np xs = np.linspace(0,20,1) ys = np.sin(xs) fig = plt.figure() ax1 = fig.add_subplot(111) ax1.plot(xs, ys) trimticks(ax1) plt.show() ___ On Sat, Feb 14, 2015 at 1:45 PM, Tommy Carstensen tommy.carsten...@gmail.com wrote: Erik, that doesn't seem to work either. I tried this: import matplotlib.pyplot as plt from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[2:] fig = plt.figure() ax1 = fig.add_subplot(111) ax1.xaxis.set_major_locator(TrimmedMultipleLocator(5)) #xticks[0].label1.set_visible(False) #xticks[-1].label1.set_visible(False) #ax1.set_xticks(ax1.xaxis.get_major_ticks()[1:-1]) ax1.plot(list(range(21))) plt.show() Here is an example of the use of prune='lower', but it does not allow one to set the tick step size: http://stackoverflow.com/questions/9422587/overlapping-y-axis-tick-label-and-x-axis-tick-label-in-matplotlib I think my best bet is to just set those ticks manually. On Sat, Feb 14, 2015 at 6:19 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 7:33 AM, Tommy Carstensen wrote: Thanks again Ryan. That's exactly what I want to achieve; i.e. remove the tick at 0 and only keep 5 and 10. Your solution works, but it's a bit of hack to use magic constants. I could however get those values from the xlim. Eric, I would describe the desired tick placement algorithm as removing the first tick on the axis. It can be achieved like this: ax1.xaxis.set_major_locator(MaxNLocator(prune='lower')) Aha! The problem is that the MaxNLocator is the only one with the prune kwarg. It could be added to the MultipleLocator. For now, though, you can make your own specialized Locator, hardwired to omit the first tick, like this: from matplotlib.ticker import MultipleLocator class TrimmedMultipleLocator(MultipleLocator): def tick_values(self, vmin, vmax): return MultipleLocator.tick_values(self, vmin, vmax)[1:] then just
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
Thanks Eric. I decided to get peace of mind and just set the tick labels manually. I can't afford to spend several hours on all of my plots. I appreciate your help a lot. On Sat, Feb 14, 2015 at 7:37 PM, Eric Firing efir...@hawaii.edu wrote: On 2015/02/14 9:15 AM, Tommy Carstensen wrote: Eric, it works if I do: return MultipleLocator.tick_values(self, vmin, vmax)[2:] But not if I do as first suggested by you: return MultipleLocator.tick_values(self, vmin, vmax)[1:] Are you using my test script but getting a different result? If not, what is the difference in your test script? I don't understand this behaviour. It should be [1:]. I'll just set the ticks manually. Seems to be the easiest thing. It would be awesome, if MPL had the same behaviour as gnuplot, which allows me to simply do: set xtics start, incr def xtics(ax, start, incr): stop = ax.dataLim.x1 + 0.01 * incr ax.xaxis.set_ticks(np.arange(start, stop, incr)) Now invoke that function *after* all your plot calls, so that the dataLim bounding box includes all the data in your plot. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] MultipleLocator and MaxNLocator
Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MultipleLocator and MaxNLocator
On 2015/02/13 3:29 PM, Tommy Carstensen wrote: Is it possible to combine MultipleLocator and MaxNLocator? One seems to erase the effect of the other. They are for different situations. MultipleLocator is for when you know what you want your tick interval to be; MaxNLocator is for when you don't know that, but you do know roughly how many ticks you want, and what sort of numerical intervals are acceptable. Eric -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
