Altering column syntax help/and repare

2006-01-18 Thread John Stile
I think I really misunderstood the directions for alter table, an I'm
not sure how to fix this.  I was trying to allow certain columns to be
null in an existing table.
I used the following syntax:
  ALTER TABLE users ALTER COLUMN title SET DEFAULT NULL;
Now 'describe users;' shows extra columns with no titles.
A.  What did that syntax do?
B.  How do I undo it?
C.  What is the proper syntax?




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Re: Altering column syntax help/and repare

2006-01-18 Thread Martijn Tonies



 I think I really misunderstood the directions for alter table, an I'm
 not sure how to fix this.  I was trying to allow certain columns to be
 null in an existing table.
 I used the following syntax:
   ALTER TABLE users ALTER COLUMN title SET DEFAULT NULL;
 Now 'describe users;' shows extra columns with no titles.

Extra columns with no titles, what does that mean?

 A.  What did that syntax do?
 B.  How do I undo it?
 C.  What is the proper syntax?

SET DEFAULT NULL has nothing to do with the null-ability of a column,
it has to do with the DEFAULT of a column.

Proper syntax:
http://dev.mysql.com/doc/refman/5.0/en/alter-table.html

Check out:
MODIFY [COLUMN] column_definitionMartijn ToniesDatabase Workbench - tool for
InterBase, Firebird, MySQL, Oracle  MS SQL ServerUpscene
Productionshttp://www.upscene.comDatabase development questions? Check the
forum!http://www.databasedevelopmentforum.com


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Re: Advanced SELECT Syntax Help Needed!

2004-11-06 Thread Frederic Wenzel
On Fri, 5 Nov 2004 17:49:29 -0500, Rhino [EMAIL PROTECTED] wrote:
 I'm not sure why you want to use a subquery; if MySQL is anything like DB2,
 a join usually performs better than a subquery and the optimizer converts a
 subquery to a join (under the covers) whenever it can anyway. Therefore,
 how about something like:
 
 select id, name, linkname1, linkname2
 from main m right outer join links1 l1 on m.id = l1.id
 right outer join links l2 on m.id = l2.id;

Yes, indeed joins usually perform better than subselects.
I agree to your suggested query, but I think we ought to use LEFT
joins here rather than RIGHT joins because Monique wants to receive
any main record regardless of the existence of corresponding links.

So the query I would use is:

SELECT m.id, l1.linkname1, l2.linkname2
FROM main m LEFT JOIN links1 l1 ON (m.id = l1.id)
LEFT JOIN links2 l2 ON (m.id = l2.id);

Please let us know if it worked, Monique.

Regards
Fred

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RE: Advanced SELECT Syntax Help Needed!

2004-11-06 Thread Monique
Thank you Frederic!  It worked perfectly!!!  I didn't know you could have
several joins linked together!

Monique.

-Original Message-
From: Frederic Wenzel [mailto:[EMAIL PROTECTED] 
Sent: Saturday, November 06, 2004 3:56 AM
To: Rhino
Cc: Monique; [EMAIL PROTECTED]
Subject: Re: Advanced SELECT Syntax Help Needed!


On Fri, 5 Nov 2004 17:49:29 -0500, Rhino [EMAIL PROTECTED] wrote:
 I'm not sure why you want to use a subquery; if MySQL is anything like
DB2,
 a join usually performs better than a subquery and the optimizer converts
a
 subquery to a join (under the covers) whenever it can anyway. Therefore,
 how about something like:
 
 select id, name, linkname1, linkname2
 from main m right outer join links1 l1 on m.id = l1.id
 right outer join links l2 on m.id = l2.id;

Yes, indeed joins usually perform better than subselects.
I agree to your suggested query, but I think we ought to use LEFT
joins here rather than RIGHT joins because Monique wants to receive
any main record regardless of the existence of corresponding links.

So the query I would use is:

SELECT m.id, l1.linkname1, l2.linkname2
FROM main m LEFT JOIN links1 l1 ON (m.id = l1.id)
LEFT JOIN links2 l2 ON (m.id = l2.id);

Please let us know if it worked, Monique.

Regards
Fred

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Advanced SELECT Syntax Help Needed!

2004-11-05 Thread Monique
Hi!

 

I would love some help with my syntax (or another strategy). I keep bombing.
I've simplified it. Here is the deal: 

Three files: 

Main: id, name 
Links1: id, linkname1 (a record may or may not exist for each record in
Main) 
Links2: id, linkname2 (a record may or may not exist for each record in
Main) 

I need a list of every record in main plus linkname1 and linkname2. I am
trying to use a subquery. 

SELECT name, linkname2, links1.id, links1.linkname1 
FROM 
(SELECT main.id, main.name, links2.linkname2 from main 
LEFT OUTER JOIN links2 using (id)) AS subfile 
LEFT OUTER JOIN links1 using (id) 

I keep getting syntax errors. I would really appreciate any input. Thanks a
bunch -- 

Monique.

 

 



Re: Advanced SELECT Syntax Help Needed!

2004-11-05 Thread Rhino
I'm not sure why you want to use a subquery; if MySQL is anything like DB2,
a join usually performs better than a subquery and the optimizer converts a
subquery to a join (under the covers) whenever it can anyway. Therefore,
how about something like:

select id, name, linkname1, linkname2
from main m right outer join links1 l1 on m.id = l1.id
right outer join links l2 on m.id = l2.id;

I haven't tested it but it ought to work.

Rhino

- Original Message - 
From: Monique [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 05, 2004 4:59 PM
Subject: Advanced SELECT Syntax Help Needed!


Hi!



I would love some help with my syntax (or another strategy). I keep bombing.
I've simplified it. Here is the deal:

Three files:

Main: id, name
Links1: id, linkname1 (a record may or may not exist for each record in
Main)
Links2: id, linkname2 (a record may or may not exist for each record in
Main)

I need a list of every record in main plus linkname1 and linkname2. I am
trying to use a subquery.

SELECT name, linkname2, links1.id, links1.linkname1
FROM
(SELECT main.id, main.name, links2.linkname2 from main
LEFT OUTER JOIN links2 using (id)) AS subfile
LEFT OUTER JOIN links1 using (id)

I keep getting syntax errors. I would really appreciate any input. Thanks a
bunch -- 

Monique.







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newbie ALTER syntax help

2004-09-23 Thread leegold
 alter table keywords change key_id page_id int(10) unsigned NOT NULL PK
 auto_increment;
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'PK auto_increment' at line 1

I'm trying to change the name of a column, but I have to also restate
the type and sttribute on the column while i do that AFAIK. Can someone
show me my syntax error? The statement above is exactlymy try from the
mysql comd. line Thanks.

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Re: newbie ALTER syntax help

2004-09-23 Thread Paul DuBois
At 12:12 -0400 9/23/04, leegold wrote:
 alter table keywords change key_id page_id int(10) unsigned NOT NULL PK
 auto_increment;
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'PK auto_increment' at line 1
I'm trying to change the name of a column, but I have to also restate
the type and sttribute on the column while i do that AFAIK. Can someone
show me my syntax error? The statement above is exactlymy try from the
mysql comd. line Thanks.
The problem is shown by the error message: PK isn't valid.
Do you mean PRIMARY KEY?
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Re: newbie ALTER syntax help

2004-09-23 Thread leegold

On Thu, 23 Sep 2004 15:51:56 -0500, Paul DuBois [EMAIL PROTECTED] said:
 At 12:12 -0400 9/23/04, leegold wrote:
   alter table keywords change key_id page_id int(10) unsigned NOT NULL PK
   auto_increment;
 ERROR 1064 (42000): You have an error in your SQL syntax; check the
 manual that corresponds to your MySQL server version for the right
 syntax to use near 'PK auto_increment' at line 1
 
 I'm trying to change the name of a column, but I have to also restate
 the type and sttribute on the column while i do that AFAIK. Can someone
 show me my syntax error? The statement above is exactlymy try from the
 mysql comd. line Thanks.
 
 The problem is shown by the error message: PK isn't valid.
 Do you mean PRIMARY KEY?

Yes. Fixed it, Thanks.


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query syntax help

2004-01-20 Thread Mike Blezien
Hello all,

I've been looking at this SQL query a dozen times or more, but keep getting a 
syntax error message, Query:

SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS 
name,aw.siteid,ai.email,as.username,as.status
FROM affiliate_info ai,affiliate_signup as,affiliate_website aw
WHERE aw.siteid = 1000
AND ai.affilid = as.affilid AND aw.affilid = ai.affilid

what is wrong with this query syntax ?? the syntax error is suppose to be in 
this area:
`affiliate_website aw WHERE aw.siteid = 1000`

MySQL version 4.0.15 w/InnoDB tables

TIA,

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Re: query syntax help

2004-01-20 Thread Fred van Engen
On Tue, Jan 20, 2004 at 04:10:44PM -0600, Mike Blezien wrote:
 I've been looking at this SQL query a dozen times or more, but keep getting 
 a syntax error message, Query:
 
 SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS 
 name,aw.siteid,ai.email,as.username,as.status
 FROM affiliate_info ai,affiliate_signup as,affiliate_website aw

AS is a reserved word.

 WHERE aw.siteid = 1000
 AND ai.affilid = as.affilid AND aw.affilid = ai.affilid
 
 what is wrong with this query syntax ?? the syntax error is suppose to be 
 in this area:
 `affiliate_website aw WHERE aw.siteid = 1000`
 

A bit before that.


Regards,

Fred.

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fax: +31 36 5462424 The Netherlands

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Re: query syntax help

2004-01-20 Thread Jochem van Dieten
Mike Blezien said:

 I've been looking at this SQL query a dozen times or more, but keep
 getting a  syntax error message, Query:

 SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS
 name,aw.siteid,ai.email,as.username,as.status
 FROM affiliate_info ai,affiliate_signup as,affiliate_website aw
  ^^
 reserved word

 WHERE aw.siteid = 1000
 AND ai.affilid = as.affilid AND aw.affilid = ai.affilid

Jochem





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Re: query syntax help

2004-01-20 Thread Mike Blezien
Thx's Fred...

as soon as I sent the email and re-read it again... I spotted the 'as' alias 
table reference to the table, was actual a reserved word,..causing the error :)

thx's again.

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Quality Web Hosting
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Fred van Engen wrote:
On Tue, Jan 20, 2004 at 04:10:44PM -0600, Mike Blezien wrote:

I've been looking at this SQL query a dozen times or more, but keep getting 
a syntax error message, Query:

SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS 
name,aw.siteid,ai.email,as.username,as.status
FROM affiliate_info ai,affiliate_signup as,affiliate_website aw


AS is a reserved word.


WHERE aw.siteid = 1000
AND ai.affilid = as.affilid AND aw.affilid = ai.affilid
what is wrong with this query syntax ?? the syntax error is suppose to be 
in this area:
`affiliate_website aw WHERE aw.siteid = 1000`



A bit before that.

Regards,

Fred.



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select query syntax help

2003-10-30 Thread Dan Lamb
Hello All,

I have two table the look like this (greatly simplified):

ResourceTable
-
int ResourceID
var ResourceName

ResourceLinkTable
-
int ResourceLinkID
int ResourceID
var Text

I need to find all rows in ResourceTable for which there is NO entry in
ResourceLinkTable.  I know I could do this with sub-selects like this:

Select * from ResourceTable where ResourceID not in (select distinct
ResourceID from ResourceLinkTable) 

How can I do this in MySQL 4.0 without using sub-selects?

Thanks,
Dan Lamb




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RE: select query syntax help [ANSWER]

2003-10-30 Thread Fortuno, Adam
This is a common question. The syntax looks like this:

SELECT a.* 
  FROM tbl_a AS a LEFT JOIN tbl_b AS b 
ON a.id = b.id
 WHERE b.id.id IS NULL;

The idea is you're retrieving a recordset of the two tables where the rows
are joined on the id. For tbl_b, the id field has no value (its null) so you
can identify those rows by asking for nulls in the `tbl_b` `id` column.

In your case, I would try:

SELECT tbl.* 
  FROM ResourceTable AS tbl LEFT JOIN ResourceLinkTable AS lnk 
ON tbl.ResourceID= lnk.ResourceID
 WHERE lnk.ResourceID.id IS NULL
ORDER BY ResourceName ASC;

Regards,
Adam

-Original Message-
From: Dan Lamb [mailto:[EMAIL PROTECTED]
Sent: Thursday, October 30, 2003 9:39 AM
To: [EMAIL PROTECTED]
Subject: select query syntax help


Hello All,

I have two table the look like this (greatly simplified):

ResourceTable
-
int ResourceID
var ResourceName

ResourceLinkTable
-
int ResourceLinkID
int ResourceID
var Text

I need to find all rows in ResourceTable for which there is NO entry in
ResourceLinkTable.  I know I could do this with sub-selects like this:

Select * from ResourceTable where ResourceID not in (select distinct
ResourceID from ResourceLinkTable) 

How can I do this in MySQL 4.0 without using sub-selects?

Thanks,
Dan Lamb




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Re: select query syntax help

2003-10-30 Thread Thomas Spahni
Dan,

SELECT ResourceTable.* FROM ResourceTable
   LEFT JOIN ResourceLinkTable
  ON ResourceTable.ResourceID = ResourceLinkTable.ResourceID
   WHERE ResourceLinkTable.ResourceID IS NULL;

Regards,
Thomas


On Thu, 30 Oct 2003, Dan Lamb wrote:

 Hello All,

 I have two table the look like this (greatly simplified):

 ResourceTable
 -
 int ResourceID
 var ResourceName

 ResourceLinkTable
 -
 int ResourceLinkID
 int ResourceID
 var Text

 I need to find all rows in ResourceTable for which there is NO entry in
 ResourceLinkTable.  I know I could do this with sub-selects like this:

 Select * from ResourceTable where ResourceID not in (select distinct
 ResourceID from ResourceLinkTable)

 How can I do this in MySQL 4.0 without using sub-selects?

 Thanks,
 Dan Lamb







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SHA literal String Syntax Help

2003-09-22 Thread Stout, Jeff
I need help with the proper syntax of my INSERT
Statement.

I have spoken to the support staff of my RADIUS
Vendor they stated that enable to support SHA

The Coolum for password has to have the encrypted
password prefixed with {SHA} not just the hash
I need to include the literal string of {SHA} plus
the hash, see below.

Quote from support
When you select a user password from the table Radius will then retrieve:
{SHA}15346b593c4d0cf05fb6e67a5669d852e6550481


This one encrypts the whole string {SHA}'smith'

mysql INSERT INTO user_profile (userid,password,alias,profile)
- VALUES ('bob',SHA1({SHA}'smith'),'max',default);
Query OK, 1 row affected (0.00 sec)


This one pukes 

mysql INSERT INTO user_profile (userid,password,alias,profile)
- VALUES ('bob',({SHA}SHA1'smith'),'max',default);
ERROR 1064 You have an error in you SQL syntax


This one has a could mismatch

mysql INSERT INTO user_profile (userid,password,alias,profile)
- VALUES ('bob',SHA,HA1'smith'),'max',default);

Please help I'm new to SQL and it's syntax flow.

 
Thanks
Jeff Stout
CSG Systems, Inc.
303-200-3204 


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Idea: Syntax help on command line

2003-03-27 Thread Christian Hammers
Hello

I use the mysql command line tool quite often and always wondered why
there's no feature that lets me quickly see the syntax of a FOREIGN
KEY or GRANT command. Now while browsing the source I found the
new syntax command in 4.0.12 and got the idea of implementing this
syntax help of myself. 

What do you think of a client command:
mysql syntax select;  (or \S or SHOW SYNTAX OF)
SELECT [STRAIGHT_JOIN]
   [SQL_SMALL_RESULT] [SQL_BIG_RESULT] [SQL_BUFFER_RESULT]
   [SQL_CACHE | SQL_NO_CACHE] [SQL_CALC_FOUND_ROWS] [HIGH_PRIORITY]
   [DISTINCT | DISTINCTROW | ALL]
select_expression,...
[INTO {OUTFILE | DUMPFILE} 'file_name' export_options]
[FROM table_references
  [WHERE where_definition]
  [GROUP BY {unsigned_integer | col_name | formula} [ASC | DESC], ...]
  [HAVING where_definition]
  [ORDER BY {unsigned_integer | col_name | formula} [ASC | DESC] ,...]
  [LIMIT [offset,] rows | rows OFFSET offset]
  [PROCEDURE procedure_name(argument_list)]
  [FOR UPDATE | LOCK IN SHARE MODE]]
   
Reference: 6.4.1 http://www.mysql.com/doc/en/SELECT.html

I managed to hacked a working demo in less than 10 minutes which is 
simply a copy of the syntax function and which uses syntax() to pipe the
output of an arbitrary command back to mysql (of course it could be a C
function, too, but why the unnecessary burden and having it as seperate
program makes it useable standalone, too!)

This program could be a perl program which either has syntax definitions
hardcoded or, even better, is able to extract them from the docs.
A preinstalled html documentation could be prerequisite which has
two comments like !-- BEGIN SYNTAX: SELECT -- ... !-- END SYNTAX --
so that the syntax is easily extractable. Something in the kind of
cat /usr/share/doc/mysql/en/$1.html
could be enough for the first start, too.

The final stage would then be that this help command is called whenever
on presses e.g. two times tab after writing a command like a command
completition.

Any suggestions and comments?

bye,

  -christian-


P.S.: Please CC me, I'm not subscribed. Thanks.
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RE: UPDATE syntax help

2003-03-23 Thread Doug Thompson
Very close.

Only one table may be updated per UPDATE statement.

Doug

On Sun, 23 Mar 2003 00:52:59 -, [EMAIL PROTECTED] wrote:

Hi

I may be way off base here but - why do you reference IMPORT_USERS in your
UPDATE statement? You aren't updating any columns in that table.

Regards,

Sal


 -Original Message-
 From: MySQL [mailto:[EMAIL PROTECTED] 
 Sent: 12 March 2003 22:33
 To: MySQL
 Subject: UPDATE syntax help
 
 
 Hi all,  I am having a little UPDATE syntax issue.  According 
 to the manual
 
 UPDATE EBA_USERS, IMPORT_USERS
 SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
 EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
 EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
 EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
 EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
 WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
 
 should work (as I understand it ;-)  but I get the error
 
 ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
 SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID, 
 EBA_USERS.REP_LOCATION_ID =
 IMPO' at line 1
 
 I did note in the comments section at the bottom someone else with
 same/similar problem, but have been unable to find a thread 
 in the mail
 archive.  My apologies if this has been dealt with already, 
 or a workaround
 suggested...
 
 MySQL 3.23.51-nt on a Win2K box
 MyODBC 3.51
 
 Thanks
 
 Jeff Creed
 Throbware
 
 (0417) 797 592
 http://www.throbware.com.au
 



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RE: UPDATE syntax help

2003-03-22 Thread [EMAIL PROTECTED]
Hi

I may be way off base here but - why do you reference IMPORT_USERS in your
UPDATE statement? You aren't updating any columns in that table.

Regards,

Sal


 -Original Message-
 From: MySQL [mailto:[EMAIL PROTECTED] 
 Sent: 12 March 2003 22:33
 To: MySQL
 Subject: UPDATE syntax help
 
 
 Hi all,  I am having a little UPDATE syntax issue.  According 
 to the manual
 
 UPDATE EBA_USERS, IMPORT_USERS
 SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
 EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
 EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
 EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
 EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
 WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
 
 should work (as I understand it ;-)  but I get the error
 
 ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
 SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID, 
 EBA_USERS.REP_LOCATION_ID =
 IMPO' at line 1
 
 I did note in the comments section at the bottom someone else with
 same/similar problem, but have been unable to find a thread 
 in the mail
 archive.  My apologies if this has been dealt with already, 
 or a workaround
 suggested...
 
 MySQL 3.23.51-nt on a Win2K box
 MyODBC 3.51
 
 Thanks
 
 Jeff Creed
 Throbware
 
 (0417) 797 592
 http://www.throbware.com.au
 
 
 -
 Before posting, please check:
http://www.mysql.com/manual.php   (the manual)
http://lists.mysql.com/   (the list archive)
 
 To request this thread, e-mail [EMAIL PROTECTED]
 To unsubscribe, e-mail 
 [EMAIL PROTECTED]
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UPDATE syntax help

2003-03-12 Thread MySQL
Hi all,  I am having a little UPDATE syntax issue.  According to the manual

UPDATE EBA_USERS, IMPORT_USERS
SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID

should work (as I understand it ;-)  but I get the error

ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID, EBA_USERS.REP_LOCATION_ID =
IMPO' at line 1

I did note in the comments section at the bottom someone else with
same/similar problem, but have been unable to find a thread in the mail
archive.  My apologies if this has been dealt with already, or a workaround
suggested...

MySQL 3.23.51-nt on a Win2K box
MyODBC 3.51

Thanks

Jeff Creed
Throbware

(0417) 797 592
http://www.throbware.com.au


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Re: UPDATE syntax help

2003-03-12 Thread Paul DuBois
At 8:33 +1000 3/13/03, MySQL wrote:
Hi all,  I am having a little UPDATE syntax issue.  According to the manual
According to the manual, this won't work until MySQL 4.x

UPDATE EBA_USERS, IMPORT_USERS
SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
should work (as I understand it ;-)  but I get the error

ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID, EBA_USERS.REP_LOCATION_ID =
IMPO' at line 1
I did note in the comments section at the bottom someone else with
same/similar problem, but have been unable to find a thread in the mail
archive.  My apologies if this has been dealt with already, or a workaround
suggested...
MySQL 3.23.51-nt on a Win2K box
MyODBC 3.51
Thanks

Jeff Creed
Throbware
(0417) 797 592
http://www.throbware.com.au


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Re: UPDATE syntax help

2003-03-12 Thread JJ
That explains it then D'OH
Is there a workaround?
Thanks :-)

- Original Message -
From: Paul DuBois [EMAIL PROTECTED]
To: MySQL [EMAIL PROTECTED]; MySQL [EMAIL PROTECTED]
Sent: Thursday, March 13, 2003 9:02 AM
Subject: Re: UPDATE syntax help


 At 8:33 +1000 3/13/03, MySQL wrote:
 Hi all,  I am having a little UPDATE syntax issue.  According to the
manual

 According to the manual, this won't work until MySQL 4.x

 
 UPDATE EBA_USERS, IMPORT_USERS
 SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
 EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
 EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
 EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
 EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
 WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
 
 should work (as I understand it ;-)  but I get the error
 
 ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
 SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID, EBA_USERS.REP_LOCATION_ID =
 IMPO' at line 1
 
 I did note in the comments section at the bottom someone else with
 same/similar problem, but have been unable to find a thread in the mail
 archive.  My apologies if this has been dealt with already, or a
workaround
 suggested...
 
 MySQL 3.23.51-nt on a Win2K box
 MyODBC 3.51
 
 Thanks
 
 Jeff Creed
 Throbware
 
 (0417) 797 592
 http://www.throbware.com.au




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Re: UPDATE syntax help

2003-03-12 Thread Paul DuBois
At 9:45 +1000 3/13/03, JJ wrote:
That explains it then D'OH
Is there a workaround?
Thanks :-)
One way is to use a script that issues a join to figure out which
records to update, then constructs the appropriate UPDATE statements.
- Original Message -
From: Paul DuBois [EMAIL PROTECTED]
To: MySQL [EMAIL PROTECTED]; MySQL [EMAIL PROTECTED]
Sent: Thursday, March 13, 2003 9:02 AM
Subject: Re: UPDATE syntax help

 At 8:33 +1000 3/13/03, MySQL wrote:
 Hi all,  I am having a little UPDATE syntax issue.  According to the
manual
 According to the manual, this won't work until MySQL 4.x

 
 UPDATE EBA_USERS, IMPORT_USERS
 SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
 EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
 EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
 EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
 EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
 WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
 
 should work (as I understand it ;-)  but I get the error
 
 ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
 SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID, EBA_USERS.REP_LOCATION_ID =
 IMPO' at line 1
 
 I did note in the comments section at the bottom someone else with
 same/similar problem, but have been unable to find a thread in the mail
 archive.  My apologies if this has been dealt with already, or a
workaround
 suggested...
 
 MySQL 3.23.51-nt on a Win2K box
 MyODBC 3.51
 
 Thanks
 
 Jeff Creed
 Throbware
 
 (0417) 797 592
  http://www.throbware.com.au


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RE: UPDATE syntax help

2003-03-12 Thread Andy Eastham
Paul,

You have to use the results of one select to generate lots of update
statements.  If you execute all these from your program, make sure you use a
different database connection for the updates, if you're keeping a results
set open.

Alternatively, if it's a one off, generate a script file with your code (or
directly from SQL if you're a martyr) and then run it.

I've used both methods successfully,

Andy

 -Original Message-
 From: JJ [mailto:[EMAIL PROTECTED]
 Sent: 12 March 2003 23:45
 To: MySQL
 Cc: Paul DuBois
 Subject: Re: UPDATE syntax help


 That explains it then D'OH
 Is there a workaround?
 Thanks :-)

 - Original Message -
 From: Paul DuBois [EMAIL PROTECTED]
 To: MySQL [EMAIL PROTECTED]; MySQL [EMAIL PROTECTED]
 Sent: Thursday, March 13, 2003 9:02 AM
 Subject: Re: UPDATE syntax help


  At 8:33 +1000 3/13/03, MySQL wrote:
  Hi all,  I am having a little UPDATE syntax issue.  According to the
 manual
 
  According to the manual, this won't work until MySQL 4.x
 
  
  UPDATE EBA_USERS, IMPORT_USERS
  SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
  EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
  EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
  EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
  EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
  WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
  
  should work (as I understand it ;-)  but I get the error
  
  ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
  SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID,
 EBA_USERS.REP_LOCATION_ID =
  IMPO' at line 1
  
  I did note in the comments section at the bottom someone else with
  same/similar problem, but have been unable to find a thread in the mail
  archive.  My apologies if this has been dealt with already, or a
 workaround
  suggested...
  
  MySQL 3.23.51-nt on a Win2K box
  MyODBC 3.51
  
  Thanks
  
  Jeff Creed
  Throbware
  
  (0417) 797 592
  http://www.throbware.com.au
 
 


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Re: UPDATE syntax help

2003-03-12 Thread JJ
Thanks...

Currently I am doing exactly that.  One data set open creating another.  I
was trying to speed the process up, although I am only dealing with 20,000
records so shouldn't complain.  Thanks all for the suggestions...  I look
forward to 4.x

JJ

- Original Message -
From: Andy Eastham [EMAIL PROTECTED]
To: [EMAIL PROTECTED] Mysql. Com [EMAIL PROTECTED]
Sent: Thursday, March 13, 2003 10:14 AM
Subject: RE: UPDATE syntax help


 Paul,

 You have to use the results of one select to generate lots of update
 statements.  If you execute all these from your program, make sure you use
a
 different database connection for the updates, if you're keeping a results
 set open.

 Alternatively, if it's a one off, generate a script file with your code
(or
 directly from SQL if you're a martyr) and then run it.

 I've used both methods successfully,

 Andy

  -Original Message-
  From: JJ [mailto:[EMAIL PROTECTED]
  Sent: 12 March 2003 23:45
  To: MySQL
  Cc: Paul DuBois
  Subject: Re: UPDATE syntax help
 
 
  That explains it then D'OH
  Is there a workaround?
  Thanks :-)
 
  - Original Message -
  From: Paul DuBois [EMAIL PROTECTED]
  To: MySQL [EMAIL PROTECTED]; MySQL [EMAIL PROTECTED]
  Sent: Thursday, March 13, 2003 9:02 AM
  Subject: Re: UPDATE syntax help
 
 
   At 8:33 +1000 3/13/03, MySQL wrote:
   Hi all,  I am having a little UPDATE syntax issue.  According to the
  manual
  
   According to the manual, this won't work until MySQL 4.x
  
   
   UPDATE EBA_USERS, IMPORT_USERS
   SET EBA_USERS.HUB_ID = IMPORT_USERS.HUB_ID,
   EBA_USERS.REP_LOCATION_ID = IMPORT_USERS.REP_LOCATION_ID,
   EBA_USERS.REP_FIRST_NAME = IMPORT_USERS.REP_FIRST_NAME,
   EBA_USERS.REP_LAST_NAME = IMPORT_USERS.REP_LAST_NAME,
   EBA_USERS.REP_DISABLED = IMPORT_USERS.REP_DISABLED
   WHERE EBA_USERS.REP_ID = IMPORT_USERS.REP_ID
   
   should work (as I understand it ;-)  but I get the error
   
   ERROR 1064: You have an error in your SQL syntax near ' IMPORT_USERS
   SET EBA_USERS.HUB_ID = IIMPORT_USERS.HUB_ID,
  EBA_USERS.REP_LOCATION_ID =
   IMPO' at line 1
   
   I did note in the comments section at the bottom someone else with
   same/similar problem, but have been unable to find a thread in the
mail
   archive.  My apologies if this has been dealt with already, or a
  workaround
   suggested...
   
   MySQL 3.23.51-nt on a Win2K box
   MyODBC 3.51
   
   Thanks
   
   Jeff Creed
   Throbware
   
   (0417) 797 592
   http://www.throbware.com.au
  
  
 
 
  -
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 http://www.mysql.com/manual.php   (the manual)
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  To unsubscribe, e-mail
  [EMAIL PROTECTED]
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Query syntax help?

2003-02-22 Thread Scott Brown
OK, I am having a bit of trouble designing a MySQL query that returns what 
I want. Here is the query as I have it thus far:

SELECT DISTINCT regformfields.name AS thename,
	  regformfields.label AS thelabel,
	  regfields.name AS fieldsname
   FROM regformfields
   INNER JOIN regfields ON (regformfields.name = regfields.Name) WHERE 
regformfields.label != ''
   ORDER BY regfields.saveorder;

In this particular query, there can be multiple occurrences of thename(can 
be filtered by DISTINCT), therefore multiple occurrences of thelabel (which 
can't be filtered by DISTINCT, as it is always different for the same 
thename), but fieldsname is always unique.

I don't care which thename or which thelabel is returned, but I only want 
one (these two tables, together with some others, construct a schema for 
yet others...), i.e thename = 'email' may be returned twice in this result 
set, but I only want it to appear once. DISTINCT, as it is used here, does 
not return what I want, as thelabel will rarely, if ever, be distinct.

The ideal query would force the DISTINCT to be related ONLY to thename, and 
return whatever thelabel it happens to grab, based on however it is 
indexing, which would be the first saveorder it stumbles upon.

Any help would be appreciated!

TIA,
--Scott Brown


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Re: Query syntax help?

2003-02-22 Thread Tore Bostrup
Try:

SELECT FF.name AS thename,
   MAX(FF.label) AS thelabel,
   F.name AS fieldsname
FROM regformfields as FF
INNER JOIN regfields as F
ON (FF.name = F.Name)
WHERE FF.label != ''
GROUP BY FF.name, F.name

I don't think you can include the ORDER BY F.saveorder (another column) in
this case, unless you include it (F.saveorder) in the SELECT and GROUP BY
list.

HTH,
Tore.


- Original Message -
From: Scott Brown [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, February 22, 2003 1:57 PM
Subject: Query syntax help?


 OK, I am having a bit of trouble designing a MySQL query that returns what
 I want. Here is the query as I have it thus far:

 SELECT DISTINCT regformfields.name AS thename,
regformfields.label AS thelabel,
regfields.name AS fieldsname
 FROM regformfields
 INNER JOIN regfields ON (regformfields.name = regfields.Name) WHERE
 regformfields.label != ''
 ORDER BY regfields.saveorder;

 In this particular query, there can be multiple occurrences of thename(can
 be filtered by DISTINCT), therefore multiple occurrences of thelabel
(which
 can't be filtered by DISTINCT, as it is always different for the same
 thename), but fieldsname is always unique.

 I don't care which thename or which thelabel is returned, but I only want
 one (these two tables, together with some others, construct a schema for
 yet others...), i.e thename = 'email' may be returned twice in this result
 set, but I only want it to appear once. DISTINCT, as it is used here, does
 not return what I want, as thelabel will rarely, if ever, be distinct.

 The ideal query would force the DISTINCT to be related ONLY to thename,
and
 return whatever thelabel it happens to grab, based on however it is
 indexing, which would be the first saveorder it stumbles upon.

 Any help would be appreciated!

 TIA,
 --Scott Brown



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Re: SQL Syntax Help

2003-02-01 Thread Bob Hall
On Fri, Jan 31, 2003 at 02:07:11PM -, Kevin Smith wrote:
 Hi All,
 
 Can anyone help me get this query working in MySQL, this was created using
 Access, but it doesn't port well for MySQL syntax:
 
 SELECT b.id, p.part_code, p.product_type, p.description, po1.options,
 b.price, b.quantity, b.price*b.quantity AS total
 FROM (products AS p LEFT JOIN product_options AS po ON p.prod_id =
 po.prod_id) RIGHT JOIN (product_options AS po1 RIGHT JOIN (basket_header AS
 bh INNER JOIN basket AS b ON bh.basket_id = b.basket_id) ON po1.po_id =
 b.op_id) ON p.prod_id = b.prod_id
 GROUP BY b.id, p.part_code, p.product_type, p.description, po1.options,
 b.price, b.quantity, b.price*b.quantity, bh.basket_id, p.options
 HAVING (((bh.basket_id)=4));

Try
FROM (((basket_header AS bh INNER JOIN basket AS b 
ON bh.basket_id = b.basket_id)
LEFT JOIN product_options AS po1 
ON po1.po_id = b.op_id) 
LEFT JOIN products AS p 
ON p.prod_id = b.prod_id)
LEFT JOIN product_options AS po 
ON p.prod_id = po.prod_id

MySQL tends to be more finicky than Jet about how you group things.
I haven't tried this, but I think it will avoid confusing the MySQL 
optimizer.

Bob Hall

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SQL Syntax Help

2003-01-31 Thread Kevin Smith
Hi All,

Can anyone help me get this query working in MySQL, this was created using
Access, but it doesn't port well for MySQL syntax:

SELECT b.id, p.part_code, p.product_type, p.description, po1.options,
b.price, b.quantity, b.price*b.quantity AS total
FROM (products AS p LEFT JOIN product_options AS po ON p.prod_id =
po.prod_id) RIGHT JOIN (product_options AS po1 RIGHT JOIN (basket_header AS
bh INNER JOIN basket AS b ON bh.basket_id = b.basket_id) ON po1.po_id =
b.op_id) ON p.prod_id = b.prod_id
GROUP BY b.id, p.part_code, p.product_type, p.description, po1.options,
b.price, b.quantity, b.price*b.quantity, bh.basket_id, p.options
HAVING (((bh.basket_id)=4));

Here is the error message MySQL reports:

You have an error in your SQL syntax near '(product_options AS po1 RIGHT
JOIN (basket_header AS bh INNER JOIN basket AS b O' at line 1

Any ideas to the correct syntax?

Thanks,

Kevin


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Re: Thanks and SQL Syntax help

2003-01-13 Thread Diana Soares
I don't know if i understood you very well, but here's a try..

mysql select * from Classes;
++-+
| ID | Name|
++-+
|  1 | XO-312  |
|  2 | PA-211a |
|  3 | XUL-001 |
++-+
3 rows in set (0.00 sec)

mysql select * from Workshops order by ClassID,Date;
++-++
| ID | ClassID | Date   |
++-++
|  1 |   1 | 2002-05-15 |
|  8 |   1 | 2002-09-22 |
|  7 |   1 | 2002-10-29 |
|  2 |   1 | 2003-02-20 |
|  3 |   2 | 2002-05-15 |
|  9 |   2 | 2003-01-01 |
|  4 |   2 | 2003-02-17 |
|  5 |   3 | 2002-05-15 |
| 10 |   3 | 2002-12-16 |
|  6 |   3 | 2003-01-01 |
++-++
10 rows in set (0.00 sec)

mysql select ClassID, MIN(Date) min, MAX(Date) max, Classes.Name
- FROM Workshops LEFT JOIN Classes ON (ClassID=Classes.ID)
- GROUP BY ClassID HAVING now() BETWEEN min and max;
+-+++-+
| ClassID | min| max| Name|
+-+++-+
|   1 | 2002-05-15 | 2003-02-20 | XO-312  |
|   2 | 2002-05-15 | 2003-02-17 | PA-211a |
+-+++-+
2 rows in set (0.00 sec)

Hope this helps...

On Sat, 2003-01-11 at 16:25, Steve Lefevre wrote:
 First of, thanks to all who replied to my questions earlier!
 
 Now I have another problem. I have a table of Classes and Workshops. Each
 Class has a number of workshops. Each workshop has a date.
 
 I have a query that gives me the date range of a class - the min and max
 dates of its workshops.
 
 select ClassID, MIN(Date), MAX(Date), Classes.Name FROM Workshops LEFT JOIN
 Classes ON ClassID=Classes.ID GROUP BY ClassID;
 
 gives me:
 
 +-+++-+
 | ClassID | MIN(Date)  | MAX(Date)  | Name|
 +-+++-+
 |  56 | 2002-05-15 | 2002-12-29 | XO-312  |
 | 408 | 2002-05-15 | 2002-05-17 | PA-211a |
 | 600 | 2002-05-15 | 2002-05-16 | XUL-001 |
 +-+++-+
 3 rows in set (0.00 sec)
 
 Now I want to get *active* classes - WHERE Now() Between MIN(Date) and
 Max(Date) -- but I can't figure out where to put the friggin clause. I get
 errors all over the place. Can I use the between function with a group by
 function?
 
 select ClassID, MIN(Date), MAX(Date), Classes.Name
  FROM Workshops
  LEFT JOIN Classes ON ClassID=Classes.ID
  WHERE Now() BETWEEN MIN(Date) and MAX(Date)
  GROUP BY ClassID;
 
 What am I doing wrong?
 
 
 
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-- 
Diana Soares


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Thanks and SQL Syntax help

2003-01-11 Thread Steve Lefevre
First of, thanks to all who replied to my questions earlier!

Now I have another problem. I have a table of Classes and Workshops. Each
Class has a number of workshops. Each workshop has a date.

I have a query that gives me the date range of a class - the min and max
dates of its workshops.

select ClassID, MIN(Date), MAX(Date), Classes.Name FROM Workshops LEFT JOIN
Classes ON ClassID=Classes.ID GROUP BY ClassID;

gives me:

+-+++-+
| ClassID | MIN(Date)  | MAX(Date)  | Name|
+-+++-+
|  56 | 2002-05-15 | 2002-12-29 | XO-312  |
| 408 | 2002-05-15 | 2002-05-17 | PA-211a |
| 600 | 2002-05-15 | 2002-05-16 | XUL-001 |
+-+++-+
3 rows in set (0.00 sec)

Now I want to get *active* classes - WHERE Now() Between MIN(Date) and
Max(Date) -- but I can't figure out where to put the friggin clause. I get
errors all over the place. Can I use the between function with a group by
function?

select ClassID, MIN(Date), MAX(Date), Classes.Name
 FROM Workshops
 LEFT JOIN Classes ON ClassID=Classes.ID
 WHERE Now() BETWEEN MIN(Date) and MAX(Date)
 GROUP BY ClassID;

What am I doing wrong?



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Re: syntax help , sql,query

2002-10-08 Thread Roger Baklund

* Dragos Madalin Popa
 I am trying to run this update statement, but I got an error syntax...near
 offsetCould You please point out what is wrong?

 Update TIMEZONE_INFO set ABBREVIATION = 'GMT' || to_char(OFFSET) where
 ABBREVIATION is null;

Use the CONCAT function:

URL: http://www.mysql.com/doc/en/String_functions.html 

--
Roger


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re: syntax help , sql,query

2002-10-08 Thread Victoria Reznichenko

Dragos,
Monday, October 07, 2002, 7:30:47 PM, you wrote:

DMP I am trying to run this update statement, but I got an error syntax...near
DMP offsetCould You please point out what is wrong?

DMP Update TIMEZONE_INFO set ABBREVIATION = 'GMT' || to_char(OFFSET) where
DMP ABBREVIATION is null;

There is no function TO_CHAR() in MySQL.


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Re: sql syntax help

2002-10-07 Thread Brent Baisley

You almost got it. Your syntax will be something like this:
UPDATE Table SET address=REPLACE(address,'#','Number') WHERE column 
like%#%

When I am trying to figure out the syntax for something, I always add a 
LIMIT 1 at the end so that only one record gets changed.

On Saturday, October 5, 2002, at 12:45 AM, Scott Johnson wrote:

 I have a db with slightly over 614,000 records of names and addresses.  
 In
 the address column, there are quite a few records like

 123 any rd # 2
 319 w. 1st st # B
 4321 test blvd # 42
 etc

 I want to replace all the number signs with the actual word 'number'.

 Is there a SQL command I can use for this or do I need the help of a
 scripting language (php or vb)?

 I was trying to construct something like update into table.column 
 select
 where column like '%#%' replace with '%number%'

 but of course that is not going to work.  I am a SQL newb btw.

 Any help appreciated.

 Thanks

 Scott

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re: sql syntax help

2002-10-07 Thread Victoria Reznichenko

Scott,
Saturday, October 05, 2002, 7:45:16 AM, you wrote:

SJ I have a db with slightly over 614,000 records of names and addresses.  In
SJ the address column, there are quite a few records like

SJ 123 any rd # 2
SJ 319 w. 1st st # B
SJ 4321 test blvd # 42
SJ etc

SJ I want to replace all the number signs with the actual word 'number'.

SJ Is there a SQL command I can use for this or do I need the help of a
SJ scripting language (php or vb)?

SJ I was trying to construct something like update into table.column select
SJ where column like '%#%' replace with '%number%'

SJ but of course that is not going to work.  I am a SQL newb btw.

Take a look at string function REPLACE():
 http://www.mysql.com/doc/en/String_functions.html


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syntax help , sql,query

2002-10-07 Thread Dragos Madalin Popa

sql,query

Hi,

I am trying to run this update statement, but I got an error syntax...near
offsetCould You please point out what is wrong?

Update TIMEZONE_INFO set ABBREVIATION = 'GMT' || to_char(OFFSET) where
ABBREVIATION is null;

Thank You,

Best Regards,
Madalin.



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sql syntax help

2002-10-04 Thread Scott Johnson

I have a db with slightly over 614,000 records of names and addresses.  In
the address column, there are quite a few records like

123 any rd # 2
319 w. 1st st # B
4321 test blvd # 42
etc

I want to replace all the number signs with the actual word 'number'.

Is there a SQL command I can use for this or do I need the help of a
scripting language (php or vb)?

I was trying to construct something like update into table.column select
where column like '%#%' replace with '%number%'

but of course that is not going to work.  I am a SQL newb btw.

Any help appreciated.

Thanks

Scott



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Re: Conditional join SQL syntax help?

2002-07-23 Thread Benjamin Pflugmann

Hi.

On Mon 2002-07-08 at 22:54:09 -0700, [EMAIL PROTECTED] wrote:
 I'm trying to get the name of a booth or tradeshow depending on the
 customer_link_type (which is an ENUM) combined with the
 customer_link_table_id which tells me the index/id of the correct table
 to look in. I've tried this SQL command, but it doesn't work right. I
 get multiple permutations still.
 
 Is this even possible to do with mySQL? Or do I have to make two queries
 (one for 'booth' and one for 'tradeshow' and store them in a PHP array
 or something)

In MySQL 4.x you can use UNION to accomplish what you want, in earlier
versions you have to do two queries and do some application-side work
or if you want the ORDER BY done by the database, you have to use a
TEMPORARY TABLE.

I think the problem could be avoided if the database design would be
normalized further. Considering your select, it could be that a
intermediate table, containing reference to type, name and id
(and maybe others) would help and the both and tradeshow tables would
only contain the information unique to them.

Greetings,

Benjamin.

 SELECT customer_id, customer_name, customer_link_type,
 customer_link_table_id, tradeshow_name, booth_name
 FROM Customer_Table, TradeShow_Table, Booth_Table
 WHERE ((customer_link_table_id = tradeshow_id AND customer_link_type =
 'tradeshow') OR (customer_link_table_id = booth_id AND
 customer_link_type = 'booth'))
 AND customer_mail_list = 1
 ORDER BY customer_date DESC, customer_link_type 
 
 Here are the three relevant tables and fields (some removed for space
 saving):
 
 CREATE TABLE Customer_Table (
   customer_id INT(10) UNSIGNED DEFAULT '0' NOT NULL PRIMARY KEY
 auto_increment,
   customer_link_table_id INT(10) UNSIGNED DEFAULT '0' NOT NULL,
   customer_link_type enum(booth, tradeshow) NOT NULL,
   customer_name varchar(30),
   customer_mail_list tinyint(1) UNSIGNED DEFAULT '0',
 );
 
 CREATE TABLE TradeShow_Table (
   tradeshow_id int(10) unsigned NOT NULL auto_increment,
   tradeshow_name varchar(100) NOT NULL default ''
 )
 
 CREATE TABLE Booth_Table (
booth_id int(10) UNSIGNED DEFAULT '0' NOT NULL PRIMARY KEY
 auto_increment,
booth_name varchar(30) NOT NULL
 );

-- 
[EMAIL PROTECTED]

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Conditional join SQL syntax help?

2002-07-08 Thread Daevid Vincent

I'm trying to get the name of a booth or tradeshow depending on the
customer_link_type (which is an ENUM) combined with the
customer_link_table_id which tells me the index/id of the correct table
to look in. I've tried this SQL command, but it doesn't work right. I
get multiple permutations still.

Is this even possible to do with mySQL? Or do I have to make two queries
(one for 'booth' and one for 'tradeshow' and store them in a PHP array
or something)

SELECT customer_id, customer_name, customer_link_type,
customer_link_table_id, tradeshow_name, booth_name
FROM Customer_Table, TradeShow_Table, Booth_Table
WHERE ((customer_link_table_id = tradeshow_id AND customer_link_type =
'tradeshow') OR (customer_link_table_id = booth_id AND
customer_link_type = 'booth'))
AND customer_mail_list = 1
ORDER BY customer_date DESC, customer_link_type 

Here are the three relevant tables and fields (some removed for space
saving):

CREATE TABLE Customer_Table (
  customer_id INT(10) UNSIGNED DEFAULT '0' NOT NULL PRIMARY KEY
auto_increment,
  customer_link_table_id INT(10) UNSIGNED DEFAULT '0' NOT NULL,
  customer_link_type enum(booth, tradeshow) NOT NULL,
  customer_name varchar(30),
  customer_mail_list tinyint(1) UNSIGNED DEFAULT '0',
);

CREATE TABLE TradeShow_Table (
  tradeshow_id int(10) unsigned NOT NULL auto_increment,
  tradeshow_name varchar(100) NOT NULL default ''
)

CREATE TABLE Booth_Table (
   booth_id int(10) UNSIGNED DEFAULT '0' NOT NULL PRIMARY KEY
auto_increment,
   booth_name varchar(30) NOT NULL
);



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Query syntax help

2002-03-21 Thread rory oconnor

I'm trying to figure out a query that will tell me the total number of
people in our house email file that physically opted out in the last
week.  I'm a bit of a mysql newbie as you can tell...

This is the general concept, though it doesn't seem to work:

select count(id) from contact   # my data table 
where optin='no'# shows they are an opt-out
AND bad_email IS NULL   # is ticked if it was a bounceback opt-out
AND email IS NOT NULL   # show only for records that have emails
AND date = 2002-03-17; # show data only since last sunday

I appear to be getting hung up on the date part.  I'm not sure if I can
use that kind of operator on a date with that format.  Any help is
appreciated!

Thanks,

Rory


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RE: Query syntax help

2002-03-21 Thread Rick Emery

AND date = 2002-03-17;

-Original Message-
From: rory oconnor [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 21, 2002 10:49 AM
To: mysql list (choose midget)
Subject: Query syntax help


I'm trying to figure out a query that will tell me the total number of
people in our house email file that physically opted out in the last
week.  I'm a bit of a mysql newbie as you can tell...

This is the general concept, though it doesn't seem to work:

select count(id) from contact   # my data table 
where optin='no'# shows they are an opt-out
AND bad_email IS NULL   # is ticked if it was a bounceback opt-out
AND email IS NOT NULL   # show only for records that have emails
AND date = 2002-03-17; # show data only since last sunday

I appear to be getting hung up on the date part.  I'm not sure if I can
use that kind of operator on a date with that format.  Any help is
appreciated!

Thanks,

Rory


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RE: Query syntax help

2002-03-21 Thread Roger Baklund

 I'm trying to figure out a query that will tell me the total number of
 people in our house email file that physically opted out in the last
 week.  I'm a bit of a mysql newbie as you can tell...
 
 This is the general concept, though it doesn't seem to work:
 
 select count(id) from contact   # my data table 
 where optin='no'  # shows they are an opt-out
 AND bad_email IS NULL # is ticked if it was a bounceback opt-out
 AND email IS NOT NULL # show only for records that have emails
 AND date = 2002-03-17;   # show data only since last sunday
 
 I appear to be getting hung up on the date part.  I'm not sure if I can
 use that kind of operator on a date with that format.  Any help is
 appreciated!

You need to put the date constant in quotes:

 ... AND date = '2002-03-17';

-- 
Roger

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RE: Query syntax help

2002-03-21 Thread Daren Cotter

What you had looks fine except the date...change what you had to:

AND date = '2002-03-17';   # date needs quotes around it

Should work.



-Original Message-
From: rory oconnor [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 21, 2002 8:49 AM
To: mysql list (choose midget)
Subject: Query syntax help


I'm trying to figure out a query that will tell me the total number of
people in our house email file that physically opted out in the last
week.  I'm a bit of a mysql newbie as you can tell...

This is the general concept, though it doesn't seem to work:

select count(id) from contact   # my data table
where optin='no'# shows they are an opt-out
AND bad_email IS NULL   # is ticked if it was a bounceback opt-out
AND email IS NOT NULL   # show only for records that have emails
AND date = 2002-03-17; # show data only since last sunday

I appear to be getting hung up on the date part.  I'm not sure if I can
use that kind of operator on a date with that format.  Any help is
appreciated!

Thanks,

Rory


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Syntax Help

2001-09-16 Thread mickalo

I've been trying to figure out where I might be going wrong with this SQL
syntax:

select format(sum(p.badcheck)+ (count(p.badcheck)*-15)) as Badcheck
from payout p,payhistory ph 
where ph.paydate between '2001-09-20' and '2001-09-30' 
and (p.payid = ph.payid and p.badcheck != '0.00')

MySQL said: You have an error in your SQL syntax near ') as Badcheck from
payout p,payhistory ph where ph.paydate between '2001-09-2' at line 1

If I remove the format() from the query, it works prefectly! I'm
trying to format the result.

Any help, appreciated! ;)

mysql database.

Mike(mickalo)Blezien
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Thunder Rain Internet Publishing
Providing Internet Solutions that work!
http://www.thunder-rain.com
Tel: 1(225)686-2002
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=


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Syntax Help - CANCEL

2001-09-16 Thread mickalo


Cancel this, I spotted the problem, forgot the format(..,2);

This query works as expected:

select format(sum(p.badcheck)+ (count(p.badcheck)*-15),2) as Badcheck
from payout p,payhistory ph 
where ph.paydate between '2001-09-20' and '2001-09-30' 
and (p.payid = ph.payid and p.badcheck != '0.00')

I've been trying to figure out where I might be going wrong with this SQL syntax:

select format(sum(p.badcheck)+ (count(p.badcheck)*-15)) as Badcheck
from payout p,payhistory ph 
where ph.paydate between '2001-09-20' and '2001-09-30' 
and (p.payid = ph.payid and p.badcheck != '0.00')

MySQL said: You have an error in your SQL syntax near ') as Badcheck from
payout p,payhistory ph where ph.paydate between '2001-09-2' at line 1

If I remove the format() from the query, it works prefectly! I'm trying to 
format the result.

Any help, appreciated! ;)

mysql database.

Mike(mickalo)Blezien
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Thunder Rain Internet Publishing
Providing Internet Solutions that work!
http://www.thunder-rain.com
Tel: 1(225)686-2002
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=


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