from:"Douglas"

Hi. I'm trying to develop a web interface to the ghostscript (gs)
application. I have the ghostscript syntax down perfectly in the console.
Now when I go to try and do it in PHP I get nothing. No errors, nothing just
a blank page with PHP logs turned on and errors turned on.

I'm running Apache with PHP 4.3.3 on OpenBSD 3.3 i386. In my case Apache
(httpd) is chrooted to /var/htdocs/. So I figured I would have to copy
ghostscript and all it's dependencies to /var/htdocs/ at least for it to
work. Still nothing. Here's the code I used below. At this point I do not
know what direction to go to get this to work or if it is even possible.
I've tried exec(), system() and popen() api functions. I get nothing no
results, no errors what so ever. BTW, ghostscript does appear to work fine
in the chrooted directory via the console. At this point the below code is
all I have. The syntax for ghostscript shown below just outputs the data of
the 2 PDF files to the pdfwrite so it will merge them together into a
merged.pdf file. Quite simple actually.

$szPipe = popen(/htdocs/gs -q -dNOPAUSE -dBATCH -sDEVICE=pdfwrite
-sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
/htdocs/Sep08-113523.pdf, r);

I tried resulting to something simple to get this to work. I took the
example from the PHP manual system() page
(http://www.php.net/manual/en/function.system.php). In this example is it
suppose to return Last Line of Output:  and Return value: 127? This
occurs with system() and passthru(). I thought it should return the last
line of a ls would show in the console.

Any ideas or direction on how to do this would be greatly appreciated.

Thanks! 

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RE: [PHP] How to access a program outside of PHP?

 1) please try $szPipe and see if you get any output.
 2) if you are jailed in /var/htdocs/ your pathname /htdocs/qs 
 is incorrect.
 3) I guess you tried running gs from the jail either as 
 yourself or as 
 root.
 please see if nobody or apache (the webserver's user) can run 
 gostscript.
 

1) When I echo out $szPipe I get Resource id #2.
2) Oops, that chrooted in /var/www/. So I thought I should be putting just a
/htdocs/, no?
3)Yes I tried running gs in the console as root works fine and as myself and
that works fine. The user is www that runs httpd. How could I test to see if
www has access? To my understanding such accounts can not be used to log in
with. I have chown the /htdocs/ to be www:.

 Hi. I'm trying to develop a web interface to the ghostscript (gs)
 application. I have the ghostscript syntax down perfectly in 
 the console.
 Now when I go to try and do it in PHP I get nothing. No 
 errors, nothing just
 a blank page with PHP logs turned on and errors turned on.
 
 I'm running Apache with PHP 4.3.3 on OpenBSD 3.3 i386. In my 
 case Apache
 (httpd) is chrooted to /var/htdocs/. So I figured I would 
 have to copy
 ghostscript and all it's dependencies to /var/htdocs/ at 
 least for it to
 work. Still nothing. Here's the code I used below. At this 
 point I do not
 know what direction to go to get this to work or if it is 
 even possible.
 I've tried exec(), system() and popen() api functions. I get 
 nothing no
 results, no errors what so ever. BTW, ghostscript does 
 appear to work fine
 in the chrooted directory via the console. At this point the 
 below code is
 all I have. The syntax for ghostscript shown below just 
 outputs the data of
 the 2 PDF files to the pdfwrite so it will merge them together into a
 merged.pdf file. Quite simple actually.
 
 $szPipe = popen(/htdocs/gs -q -dNOPAUSE -dBATCH -sDEVICE=pdfwrite
 -sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
 /htdocs/Sep08-113523.pdf, r);
 
 I tried resulting to something simple to get this to work. I took the
 example from the PHP manual system() page
 (http://www.php.net/manual/en/function.system.php). In this 
 example is it
 suppose to return Last Line of Output:  and Return value: 
 127? This
 occurs with system() and passthru(). I thought it should 
 return the last
 line of a ls would show in the console.
 
 Any ideas or direction on how to do this would be greatly 
 appreciated.

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RE: [PHP] How to access a program outside of PHP?

  Hi. I'm trying to develop a web interface to the ghostscript (gs)
  application. I have the ghostscript syntax down perfectly 
 in the console.
  Now when I go to try and do it in PHP I get nothing. No 
 errors, nothing
 just
  a blank page with PHP logs turned on and errors turned on.
 
 Does the Apache user have permission to run this program? PHP 
 runs as the
 Apache user when installed as a module.

It should. I've moved the gs and all dependencies into /var/www/htdocs/.
I've ran it from that location and it seems to work fine. Also I've chowned
the /htdocs/ to be www:www. Should have all the rights it needs.
Apache/HTTPD runs as www.

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Re: [PHP] executing shell commands.

2003-09-10 Thread Douglas Douglas

Hi!

I'm not sure this could be your problem, but this is
what I see:

$numlin = '/bin/cat 
/dcsa-ws1/share/webadm1/public_html/system-reports/security/rhosts/eqty/$system
| /bin/wc -l';

I think you should write it like this:

$numlin = /bin/cat 
/dcsa-ws1/share/webadm1/public_html/system-reports/security/rhosts/eqty/$system
| /bin/wc -l;

I had this kind of problem once and my script wasn't
replacing the variable ($system). It was just writing
$system in the string.

Hope this helps.

Regards, Douglas.

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RE: [PHP] How to access a program outside of PHP?

 1) When I echo out $szPipe I get Resource id #2.
 
 Sorry i was thinking of backticks.  btw have you tried it ? 
 (backticks)

Backticks? Is this a PHP API function, I can't find it? That's the thing
here I haven't been able to get things to work and I have no clue what I
should use, exec(), system(), popen(), etc. gs just needs to be run, I do
not require any output back from it other than if I can determine if it's
been ran or not (true/false).
 

 3)Yes I tried running gs in the console as root works fine 
 and as myself and
 that works fine. The user is www that runs httpd. How could 
 I test to see if
 www has access? To my understanding such accounts can not be 
 used to log in
 with. I have chown the /htdocs/ to be www:.
 
 can't login yes. but you can try: sudo -u www /htdocs/gs

Okay, tried that and yes it worked.

Any more ideas? Is there any logs I could look at to find out more, I've
looked around but haven't found anything as of yet.

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[PHP] PHP-General List post bounces???

Why do I keep getting this?

 -Original Message-
 From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, September 10, 2003 10:12 AM
 To: [EMAIL PROTECTED]
 Subject: [ERR] RE: [PHP] How to access a program outside of PHP?
 
 
 Transmit Report:
 
  To: [EMAIL PROTECTED], 402 Local User Inbox Full 
 ([EMAIL PROTECTED]) 

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RE: [PHP] How to access a program outside of PHP?

 Backticks is simply the ` sign (usually the character above the tab). 
 Popularly know as `hair on the ear` in my country :-)
 for example if you want to invoke ls from php you just type
 
 $result = `ls`;
 
 hey presto the output from ls is now in your $result variable.

Ohhh okay. Well if you mean to do this, $szPipe = popen(`/htdocs/gs -q
-dNOPAUSE -dBATCH -sDEVICE=pdfwrite
-sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
/htdocs/Sep08-113523.pdf`, r);. This does not seem change anything. If I
do this with the system() example, I get Warning: system(): Cannot execute
a blank command in /htdocs/index.php on line 14.

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Re: [PHP] PHP vs ASP.NET formal opinions request

2003-08-14 Thread Douglas Douglas

Thanks to everybody for your kind responses.

By the way, I go to the Universidad de El Salvador
(Central America).

In a such poor country like this, Free Software and
Open Source could be the answer to the government's
software needs.

Unfortunately, MS has the monopoly in the government's
software, and our leaders see GNU like We don't have
any support for that. Nobody guarantees us the GNU
software's good performance. With MS we can demand
answers to SOMEBODY. They say that they prefer to pay
to get that warranty.

I know that it's going to be hard, but I'm willing to
fight for what I believe in. Wish me luck :D

Thanks again.

Regards, Douglas.

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[PHP] PHP vs ASP.NET formal opinions request

2003-08-14 Thread Douglas Douglas

Hello everybody.

I've been doing some research about the PHP vs ASP.NET
debate, because I need to justify the use of PHP in my
graduation work.

In my University, people in charge of approving the
graduation works advocate Microsoft's technologies.
They don't believe in the free software movement or
the open source movement. Some guys tried to develop a
system using PHP and those people made them change to
ASP.NET. They say because It's the future. According
to them it's where the money is.

Well, I only have one year using PHP, but I'll try to
fight. I've read a lot of opinions that have been very
useful to me.

I collected a lot of those opinions and printed to
show them to the authorities, but they said that I
needed formal basis (books, scientific journals,
etc.) to justify the use of PHP. They said that they'd
only allow BIG COMMERCIAL, IMPARTIAL, RECOGNIZED
WEBSITES opinions and articles.

I pretend to use this comparison found in the
Microsoft MSDN website:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/dnaspp/html/phpvsaspnet.asp

Can you give me some pointers (websites, names, etc)
where I could find this kind of formal comparison
about both technologies?

I've been looking for some book that covers this
issue. I've also been looking for some magazine
article that I could use.

I'd appreciate any kind of help. Thanks.

Regards, Douglas.

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Re: [PHP] PHP vs ASP.NET formal opinions request

2003-08-14 Thread Douglas Douglas

Thank you for the links Mr. Rees.

I specially liked the one about MS giving $500K to the
Peruvian President.

Thanks to everybody's help I have some BIG
COMMERCIAL, IMPARTIAL, RECOGNIZED WEBSITES articles
like IBM, Yahoo and Google.

I'm very thankful to all of you.

Regards, Douglas.

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[PHP] Variable variables question?

2003-06-13 Thread Douglas Douglas

Hello everybody.

I have the following class method:

function HTTPValidator($method)
{
   $this-data = ${'_'.$method};
   $this-rules= array();
   $this-required = array();
}

data, rules and required are arrays. The parameter
$method can have the values: GET or POST.  I'm trying
to store the superglobal array in the data class
property.
To get the superglobal array ($_GET or $_POST), I try
to build these strings '_'.$method. I'm sure this part
works, PHP builds the string _GET or _POST according
to the $method parameter.
I use ${'_'.$method} to get the contents of the
superglobal. But this piece of code doesn't work. It
seems like PHP doesn't build the $_GET or $_POST
string.
Funny thing, I tried the same code on another script
and worked. Here's that script:

?php
echo 'pre';
print_r($_POST);
echo '/prebrbr';
$method = 'POST';
$data = ${'_'.$method};
echo 'pre';
print_r($data);
echo '/prebrbr';
?

(I even tried to send the $method parameter as '_GET'
and '_POST', and didn't work either).

I'm very confused. Thanks for any help.

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RE: [PHP] Variable variables question?

2003-06-13 Thread Douglas Douglas

Thanks for the answer Mike.

Thanks for the explanation, but I think this is a
different case, isn't? I'm not trying to do this
${$_POST}, I'm trying to make this string $_POST.

And I have another question. Why does this code work?

?php
echo 'pre';
print_r($_POST);
echo '/prebrbr';
$method = 'POST';
$data = ${'_'.$method};
echo 'pre';
print_r($data);
echo '/prebrbr';
?

It does what I want it to do. I use it as the action
of the same form I submitted before and it does print
the superglobal array twice. The difference between
this code and the one that doesn't work is that the
latter is a class method.

What do you think? Thanks again.

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[PHP] reading/writing the value of an UL/LI text value

2003-06-09 Thread Bruce Douglas

Hi.

I have a question regarding the DOM model. Does anyone know how to write to
the UL/LI text value using the DOM model. I more or less can write to
select/option attributes of the DOM. but I can't figure out how to write
(or read) the text of a UL-LI attribute

I'd like to be able to do something like:

echo
document.foo.element.LU.LI.text = dfdgd;
;
(of course, using whatever the appropriate doument string would be...)

Any pointers/code samples/web sites would be helpful


Thanks

Bruce
[EMAIL PROTECTED]
(925) 866-2790



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RE: [PHP] creating new mail account on a domain

2003-04-06 Thread Mark Douglas

This is entirely dependant on what mail server you are running, how it's
configured, and what tools you have at your disposal for controlling it
(CLI, web, ...).

If you actually want help with this issue, we're going to need a lot more
detail.

-Original Message-
From: Lars Tvedt [mailto:[EMAIL PROTECTED]
Sent: Sunday, April 06, 2003 12:48 PM
To: [EMAIL PROTECTED]
Subject: [PHP] creating new mail account on a domain


How do i create a new mail account on a domain?

My domain is waveartists.com
and I wish to create a new mail account without using the server admin
panel.
but rahter using a php script.

Do anyone know how to do this?

any help appreciated.




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RE: [PHP] Quick Sessions ?

2003-04-04 Thread Mark Douglas

Let's ask the dumb questions first:

Is your webserver parsing .html files for PHP?

-Original Message-
From: Anthony [mailto:[EMAIL PROTECTED]
Sent: Friday, April 04, 2003 3:03 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Quick Sessions ?

I have an issue.  For some reason I can't pass session data to pages within
different folders.  What I have is a page in like
mydomain.com/something/somepage.php  This page creates session information
and holds it correctly.  The app collects user data and then eventualy sends
a location header to ../index.html - in this file there is php that check
to see if the session data is there and. no longer there!!!  So what
gives?  Can I not pass session info from pages in folders?  I'm not changing
the domain, so I shouldn't loose the cookie I'm lost   Please help
me out :)

- Anthony

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RE: [PHP] php.ini file not being updated with install

2003-04-04 Thread Mark Douglas

If you are using php as a DSO, you need to restart your webserver to load
the new install.

Mark

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Friday, April 04, 2003 9:25 PM
To: [EMAIL PROTECTED]
Subject: [PHP] php.ini file not being updated with install

Hello Everyone,
I updated php recently in order to add the --with-ldap part.
so my config.nice file now looks like:

'./configure' \
'--with-apache=../apache_1.3.27' \
'--with-mysql=/usr' \
'--with-oci8=/opt/oracle/product/9.2.0' \
'--enable-sigchild' \
'--with-ldap' \
$@

To update php, I ran make clean then the above ./configure line
and then:
make 
make install

Now it looks like my command line php executable has been updated and is
able to connect to ldap.
However if I check out my phpinfo() from the web, it does not show the 
new Build Date.  It still shows all the information from the last time I
complied php and still cannot connect to ldap.

Could anyone please help??
Thanks,
Tracy

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RE: [PHP] Which PHP version is stable with apache 2.0.39

2003-04-03 Thread Mark Douglas

Something you should note before diving into making PHP work with Apache
2.0.39 - Apache 2.0.45 was recently released, to address a DOS vulnerability
in Apache2 on all platforms. You may want to upgrade (or have your system
administrator upgrade) to Apache 2.0.45.

A second note, when I went from 2.0.39 and PHP 4.2.x to Apache 2.0.43 and
4.3.0, my life became a whole lot easier as PHP and Apache seemed to behave
a lot better together. So beyond upgrading Apache for security reasons, I
would recommend using the latest PHP 4.3.x as well.

Mark

-Original Message-
From: Jason Smith [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 03, 2003 8:45 PM
To: Jennifer Goodie; [EMAIL PROTECTED]
Subject: RE: [PHP] Which PHP version is stable with apache 2.0.39


Jennifer,

Thank you,  I have followed that link previously and however find it
somewhat confusing.

~These versions of PHP are compatible to Apache 2.0.40 and later. 

~Note: Apache 2.0 SAPI-support started with PHP 4.2.0. PHP 4.2.3 its
known ~to work in conjunction with Apache 2.0.39. Don't try to use this
version of ~PHP with any other version of Apache. We do not recommend to
use PHP 4.2.3 ~along with Apache 2.0.39.

In one part it is saying that it is known to work and then goes on to
say is not recommended. Does anyone know why it is not recommended.

Thanks 

Jason

All mentioned versions of PHP will work still with Apache 1.3.x. 


-Original Message-
From: Jennifer Goodie [mailto:[EMAIL PROTECTED] 
Sent: Friday, 4 April 2003 11:25 AM
To: Jason Smith; [EMAIL PROTECTED]
Subject: RE: [PHP] Which PHP version is stable with apache 2.0.39

http://www.php.net/manual/en/install.apache2.php



 -Original Message-
 From: Jason Smith [mailto:[EMAIL PROTECTED]
 Sent: Thursday, April 03, 2003 5:22 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Which PHP version is stable with apache 2.0.39
 
 
 Hi,
  
 Need some information as I cant seem to find it in the manual or
online.
  
 We are running apache 2.0.39 on redhat 7.3 and would like to run PHP
on
 the same server.
 I am having trouble finding out if there is a stable version that runs
 with Apache 2.0.39
  
 Any help appreciated
  
 Cheers
 jason
 


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[PHP] Problems with post data

I'm having problems with my post variables. Here's the page I use to submit
data:

FORM ACTION=test2.php METHOD=POST /
INPUT TYPE=text SIZE=50 MAXLENGTH=50 NAME=new_area
/nbsp;nbsp;INPUT TYPE=SUBMIT VALUE=Add New Skill Area /BR /BR /
/FORM

Here's the test2.php page:

?php
print_r($_POST);
?

This is all very simple, and works on one of my webservers. However, on
another webserver with a practically identical configuration, if I post
testing the result that I get is this:

Array ( [new_area] = testingnew_area=testing ) 

I've spent hours scouring my two configurations, changing options here and
there, and have had zero success in making the problem webserver work.

The server is a dual processor RedHat 8 system running apache 2.0.43, and
php 4.3.1. You can see the phpinfo at
http://inexorable.sagelikefool.net/phpinfo.htm (yes htm, not php). Any and
all help is appreciated!

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RE: [PHP] Storing a graphic file in a MySQL database

Here's a good start:

http://www.phpbuilder.com/columns/florian19991014.php3

-Original Message-
From: Phil Schwarzmann [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 29, 2003 7:56 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Storing a graphic file in a MySQL database

Where can I find some information on storing a graphic file such as a JPG or
GIF into a MySQL database.  I'm assuming I have to convert it to a binary
format and store it that way.  Or maybe this isn't possible?

Thanks!

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RE: [PHP] Problems with post data

Yes, the webserver that works is running apache2, however it's 2.0.44
instead of 2.0.43... I'm upgrading the broken one now to see if that fixes
the problem.

-Original Message-
From: John W. Holmes [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 29, 2003 10:50 AM
To: 'Mark Douglas'; [EMAIL PROTECTED]
Subject: RE: [PHP] Problems with post data

I bet the web server that works is not running Apache 2, is it? Either
way, it's an Apache2 and PHP bug. It's in the bug tracker somewhere...
Use Apache 1.3.27 or whatever the latest is...

---John W. Holmes...

PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/

 -Original Message-
 From: Mark Douglas [mailto:[EMAIL PROTECTED]
 Sent: Saturday, March 29, 2003 7:57 AM
 To: '[EMAIL PROTECTED]'
 Subject: [PHP] Problems with post data

 I'm having problems with my post variables. Here's the page I use to
 submit
 data:

 FORM ACTION=test2.php METHOD=POST /
 INPUT TYPE=text SIZE=50 MAXLENGTH=50 NAME=new_area
 /nbsp;nbsp;INPUT TYPE=SUBMIT VALUE=Add New Skill Area /BR
/BR /
 /FORM

 Here's the test2.php page:

 ?php
 print_r($_POST);
 ?

 This is all very simple, and works on one of my webservers. However,
on
 another webserver with a practically identical configuration, if I
post
 testing the result that I get is this:

 Array ( [new_area] = testingnew_area=testing )

 I've spent hours scouring my two configurations, changing options here
and
 there, and have had zero success in making the problem webserver work.

 The server is a dual processor RedHat 8 system running apache 2.0.43,
and
 php 4.3.1. You can see the phpinfo at
 http://inexorable.sagelikefool.net/phpinfo.htm (yes htm, not php). Any
and
 all help is appreciated!

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RE: [PHP] Problems with post data

Just an FYI, 2.0.44 still isn't working on this server, while it does on
another... I don't know what to do now, so I'm just going to write code to
deal with this bug.

-Original Message-
From: Mark Douglas [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 29, 2003 10:38 PM
To: '[EMAIL PROTECTED]'
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP] Problems with post data

Yes, the webserver that works is running apache2, however it's 2.0.44
instead of 2.0.43... I'm upgrading the broken one now to see if that fixes
the problem.

-Original Message-
From: John W. Holmes [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 29, 2003 10:50 AM
To: 'Mark Douglas'; [EMAIL PROTECTED]
Subject: RE: [PHP] Problems with post data

I bet the web server that works is not running Apache 2, is it? Either
way, it's an Apache2 and PHP bug. It's in the bug tracker somewhere...
Use Apache 1.3.27 or whatever the latest is...

---John W. Holmes...

PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/

 -Original Message-
 From: Mark Douglas [mailto:[EMAIL PROTECTED]
 Sent: Saturday, March 29, 2003 7:57 AM
 To: '[EMAIL PROTECTED]'
 Subject: [PHP] Problems with post data

 I'm having problems with my post variables. Here's the page I use to
 submit
 data:

 FORM ACTION=test2.php METHOD=POST /
 INPUT TYPE=text SIZE=50 MAXLENGTH=50 NAME=new_area
 /nbsp;nbsp;INPUT TYPE=SUBMIT VALUE=Add New Skill Area /BR
/BR /
 /FORM

 Here's the test2.php page:

 ?php
 print_r($_POST);
 ?

 This is all very simple, and works on one of my webservers. However,
on
 another webserver with a practically identical configuration, if I
post
 testing the result that I get is this:

 Array ( [new_area] = testingnew_area=testing )

 I've spent hours scouring my two configurations, changing options here
and
 there, and have had zero success in making the problem webserver work.

 The server is a dual processor RedHat 8 system running apache 2.0.43,
and
 php 4.3.1. You can see the phpinfo at
 http://inexorable.sagelikefool.net/phpinfo.htm (yes htm, not php). Any
and
 all help is appreciated!

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[PHP] How to remove only the last character?

2003-02-08 Thread Douglas Douglas

Good day.

Is there any PHP function that removes only the last
character of a string and returns the new string?

I'm looking in the manual and I can't find anything.

Until now I'm doing this:

$var=substr($var,0,strlen($var)-1)

Is this the most efficient way?

Thanks.

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Re: [PHP] How to remove only the last character?

2003-02-08 Thread Douglas Douglas

I want to thank you Ian, Zydox and Nicos.

After Zydox response I checked the manual again and
read this part in the substr function:

If length is given and is negative, then that many
characters will be omitted from the end of string
(after the start position has been calculated when a
start is negative)

Sorry to bother you guys, and thanks again.

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[PHP] php/sendmail/apache/linux...

2003-01-24 Thread Bruce Douglas

hey...

I'm sure the question has been answered a 1000 times!!! I'm trying to create
a simple app to send email via PHP, using the mail function.

I'm using RedHat(Linux 8.0 , Sendmail), PHP(4.2.2), Apache (2.0.40).

I'm using the following piece of code:

===
//test mail
$to = [EMAIL PROTECTED];
$subject = savannah registration;
$message =  testing mail;
$reply = From: [EMAIL PROTECTED]\r\n
.Reply-To: [EMAIL PROTECTED]\r\n;

echo
 to =  . $to . br;

echo
 subject =  . $subject . br;

echo
 msg =  . $message . br;

echo
 reply =  . $reply . br;

 $q1 = mail($to, $subject, $message, $reply);
echo
 return val  =  . $q1 . br;


===

Pretty simple eh... The problem that I have is that the mail doesn't appear
to get sent. When I look in the /var/spool/clientmqueue directory, I see a
great deal of what look to be error msgs They appear to be telling me
that the mail couldn't be delivered, but I can't tell why

I was able to successfully send a test msg via Sendmail from the command
line by telnet. So I know the Sendmail engine/daemon seems to be
performing... The PHP.ini file appears to be setup correctly, with the
sendmail_path pointing to sendamil.

Any ideas as to what I need to do, or should be checking

Any pointers/assistance would be greatly appreciated.


Thanks

-Bruce
[EMAIL PROTECTED]



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[PHP] RE: php/sendmail/apache/linux...

2003-01-24 Thread Bruce Douglas

Brian

The following information is what I have...

I created the following PHP app I'm running it from the command line.

-
#! /usr/bin/php -q
?
#
# a.php - test app for the php mail function
#
$toaddress = [EMAIL PROTECTED];
$subject = test;
$content = Name: www \n
   .E-mail Address: [EMAIL PROTECTED] \n;

$e = mail($toaddress, $subject, $content);

if ($e == False)
{
echo mail = false\n;
}
else
{
 echo mail = true\n;
}
?
-

The response was:
---

mail = false

---


As you can see, the mail app failed.. The information from the
/var/spool/clientmqueue/ dir is:


[root@lserver2 savannah]# more  /var/spool/clientmqueue/dfh0P2qeLE006055

This is a MIME-encapsulated message

--h0P2qeLE006055.1043463166/lserver2.mesa.com

The original message was received at Fri, 24 Jan 2003 18:52:40 -0800
from root@localhost

   - The following addresses had permanent fatal errors -
[EMAIL PROTECTED]
(expanded from: [EMAIL PROTECTED])

   - Transcript of session follows -
550 5.1.2 [EMAIL PROTECTED] Host unknown (Name server: [localhost]:
host not found)

--h0P2qeLE006055.1043463166/lserver2.mesa.com
Content-Type: message/delivery-status

Reporting-MTA: dns; lserver2.mesa.com
Arrival-Date: Fri, 24 Jan 2003 18:52:40 -0800

Final-Recipient: RFC822; [EMAIL PROTECTED]
Action: failed
Status: 5.1.2
Remote-MTA: DNS; [localhost]
Last-Attempt-Date: Fri, 24 Jan 2003 18:52:45 -0800

--h0P2qeLE006055.1043463166/lserver2.mesa.com
Content-Type: message/rfc822

Return-Path: root
Received: (from root@localhost)
  by lserver2.mesa.com (8.12.5/8.12.5/Submit) id h0P2qeLD006055;
  Fri, 24 Jan 2003 18:52:40 -0800
Date: Fri, 24 Jan 2003 18:52:40 -0800
From: root root
Message-Id: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: test

Name: www
E-mail Address: [EMAIL PROTECTED]


--h0P2qeLE006055.1043463166/lserver2.mesa.com--

==

[root@lserver2 savannah]# more  /var/spool/clientmqueue/Qfh0P2qeLE006055
V6
T1043463166
K0
N0
P31120
I3/2/1991420
Fr
$_localhost
$r
$slocalhost
${daemon_flags}c u
SMAILER-DAEMON
C:root
rRFC822; [EMAIL PROTECTED]
RPF:root
H?P?Return-Path: g
H??Received: from localhost (localhost)
  by lserver2.mesa.com (8.12.5/8.12.5/Submit) id h0P2qeLE006055;
  Fri, 24 Jan 2003 18:52:46 -0800
H?D?Date: Fri, 24 Jan 2003 18:52:46 -0800
H?F?From: Mail Delivery Subsystem MAILER-DAEMON
H?x?Full-Name: Mail Delivery Subsystem
H?M?Message-Id: [EMAIL PROTECTED]
H??To: root
H??MIME-Version: 1.0
H??Content-Type: multipart/report; report-type=delivery-status;
  boundary=h0P2qeLE006055.1043463166/lserver2.mesa.com
H??Subject: Returned mail: see transcript for details
H??Auto-Submitted: auto-generated (failure)
.



The above files are pretty much greek to me!! Other than telling me it can't
seem to handle the [EMAIL PROTECTED] address... which is odd... As a
test, I changed the email address.. I get the same response...

Is there something that I'm missing that has to be set for this to work

I have Linux Redhat 8.0, PHP 4.2.2...

I have the sendmail RPM and the PHP RPMs from the Redhat 8.0 installation
disks

Any help/assistance will be appreciated

Thanks...

Bruce
[EMAIL PROTECTED]


-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of Brian Schmidt
Sent: Friday, January 24, 2003 6:04 PM
To: [EMAIL PROTECTED]
Subject: RE: php/sendmail/apache/linux...


On Fri, 24 Jan 2003, Bruce Douglas wrote:

 However, as I stated, I'm fairly sure that the Sendmail app is working
given
 that I was able to send an email from the command line when i did a telnet
 localhost 25

 I'm just not certain as to how to do it through PHP

Bruce,
How about trying something really simple like this. I know it works.
It's part of an HTML form I've used, so you'll need one with a $name,
$email, and $morestuff input section:

  $toaddress = [EMAIL PROTECTED];
  $subject = My Subject;
  $mailcontent = Name: .$name.\n
 .E-mail Address: .$email.\n
 .Additional Information: \n.$morestuff.\n;
  mail($toaddress, $subject, $mailcontent);


 thanks

 bruce
 [EMAIL PROTECTED]


 -Original Message-
 From: [EMAIL PROTECTED]
 [mailto:[EMAIL PROTECTED]]On Behalf Of Lucas Albers
 Sent: Friday, January 24, 2003 4:12 PM
 To: [EMAIL PROTECTED]
 Subject: RE: php/sendmail/apache/linux...


 Test the mailserver with the command

 cat message.txt | mail -f [EMAIL PROTECTED]

 User the Perl sendmail mail wrapper to send the mail.
 http://search.cpan.org/src/MIVKOVIC/Mail-Sendmail-0.78_5/README


  --Luke
  --Computer Science Sysadmin, MSU Bozeman
  --admin(AT)cs.montana.edu 994-3931

  -Original Message

[PHP] a simple getenv question....

2003-01-22 Thread Bruce Douglas

Hi...

A simple question... In the following code:

?

$ip = getenv(REMOTE_ADDR);

echo  ip = .$ip;

echo  ip =  . getenv(REMOTE_ADDR);

echo  ip =  . getenv('REMOTE_ADDR');

echo  ip = . $REMOTE_ADDR;--

?

I can only seem to get the last line to display the correct value. It's as
if I can't seem to get/return any of the SERVER environment variables using
the getenv() function

I'm using Apache 2.0.40, PHP 4.2.2 on Linux RedHat 8.0.

I've checked through the PHP.INI file, but couldn't seem to find why this
might be occuring. Any help/assistance would be appreciated.

thanks

bruce
[EMAIL PROTECTED]



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RE: [PHP] a simple getenv question....

2003-01-22 Thread Bruce Douglas

phpinfo() returns everything as expected.. but not having the code .. i
don't know what internal method it uses to access the information...

but thanks...

-bruce


-Original Message-
From: Timothy Hitchens (HiTCHO) [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 22, 2003 4:18 PM
To: 'Jim Lucas'; 'Bruce Douglas'; [EMAIL PROTECTED]
Subject: RE: [PHP] a simple getenv question


The simplest way to start looking would be phpinfo() page for starters.


Timothy Hitchens (HiTCHO)
Open Source Consulting
e-mail: [EMAIL PROTECTED]

 -Original Message-
 From: Jim Lucas [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, 23 January 2003 10:15 AM
 To: Bruce Douglas; [EMAIL PROTECTED]
 Subject: Re: [PHP] a simple getenv question


 just copied your code and it worked fine for me.

 system: Apache 1.3.26
 PHP 4.2.2

 I would look into apache 2.0 and the env vars that are
 available from it.


 - Original Message -
 From: Bruce Douglas [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, January 22, 2003 3:57 PM
 Subject: [PHP] a simple getenv question


  Hi...
 
  A simple question... In the following code:
 
  ?
 
  $ip = getenv(REMOTE_ADDR);
 
  echo  ip = .$ip;
 
  echo  ip =  . getenv(REMOTE_ADDR);
 
  echo  ip =  . getenv('REMOTE_ADDR');
 
  echo  ip = . $REMOTE_ADDR; --
 
  ?
 
  I can only seem to get the last line to display the correct value.
  It's as if I can't seem to get/return any of the SERVER environment
  variables
 using
  the getenv() function
 
  I'm using Apache 2.0.40, PHP 4.2.2 on Linux RedHat 8.0.
 
  I've checked through the PHP.INI file, but couldn't seem to
 find why
  this might be occuring. Any help/assistance would be
 appreciated.
 
  thanks
 
  bruce
  [EMAIL PROTECTED]
 
 
 
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RE: [PHP] a simple getenv question....

2003-01-22 Thread Bruce Douglas

Timothy,

Thanks for your input.. but I was trying to get a better understanding as to
why the getenv() function was apparently not returning the SERVER
environment vars.

thanks

-bruce


-Original Message-
From: Timothy Hitchens (HiTCHO) [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 22, 2003 4:39 PM
To: 'Bruce Douglas'; [EMAIL PROTECTED]
Subject: RE: [PHP] a simple getenv question


Do this:

?php

print_r($_SERVER);

?

If what you want is here this just use: $_SERVER['REMOTE_ADDR'] etc

You will need to have a look at the source of the output as the rendered
view will look a little strange.



Timothy Hitchens (HiTCHO)
Open Source Consulting
e-mail: [EMAIL PROTECTED]

 -Original Message-
 From: Bruce Douglas [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, 23 January 2003 10:33 AM
 To: [EMAIL PROTECTED]
 Subject: RE: [PHP] a simple getenv question


 phpinfo() returns everything as expected.. but not having the
 code .. i don't know what internal method it uses to access
 the information...

 but thanks...

 -bruce


 -Original Message-
 From: Timothy Hitchens (HiTCHO) [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, January 22, 2003 4:18 PM
 To: 'Jim Lucas'; 'Bruce Douglas'; [EMAIL PROTECTED]
 Subject: RE: [PHP] a simple getenv question


 The simplest way to start looking would be phpinfo() page for
 starters.


 Timothy Hitchens (HiTCHO)
 Open Source Consulting
 e-mail: [EMAIL PROTECTED]

  -Original Message-
  From: Jim Lucas [mailto:[EMAIL PROTECTED]]
  Sent: Thursday, 23 January 2003 10:15 AM
  To: Bruce Douglas; [EMAIL PROTECTED]
  Subject: Re: [PHP] a simple getenv question
 
 
  just copied your code and it worked fine for me.
 
  system: Apache 1.3.26
  PHP 4.2.2
 
  I would look into apache 2.0 and the env vars that are
 available from
  it.
 
 
  - Original Message -
  From: Bruce Douglas [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Wednesday, January 22, 2003 3:57 PM
  Subject: [PHP] a simple getenv question
 
 
   Hi...
  
   A simple question... In the following code:
  
   ?
  
   $ip = getenv(REMOTE_ADDR);
  
   echo  ip = .$ip;
  
   echo  ip =  . getenv(REMOTE_ADDR);
  
   echo  ip =  . getenv('REMOTE_ADDR');
  
   echo  ip = . $REMOTE_ADDR; --
  
   ?
  
   I can only seem to get the last line to display the
 correct value.
   It's as if I can't seem to get/return any of the SERVER
 environment
   variables
  using
   the getenv() function
  
   I'm using Apache 2.0.40, PHP 4.2.2 on Linux RedHat 8.0.
  
   I've checked through the PHP.INI file, but couldn't seem to
  find why
   this might be occuring. Any help/assistance would be
  appreciated.
  
   thanks
  
   bruce
   [EMAIL PROTECTED]
  
  
  
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   To unsubscribe, visit: http://www.php.net/unsub.php
  
  
 
 
 
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Re: [PHP] nested if in a for statement

2002-12-17 Thread Douglas Douglas

I think your error is this:

$userVars = array($nameFirst, $nameLast, $pass,
$pass2, $auth, $dob_year, $dob_month, $dob_day);

for ($i=0; $i = count($userVars); $i++) {
if (empty($userVars[$i])) {
 echo please enter all required info;
 break;
}
}
You're using eight variables, so $userVars have
indexes like these $userVars[0]=$nameFirst,
$userVars[1]=$nameLast, ... , $userVars[7]=$dob_day
In the for loop you're using $i = count($userVars),
that is $i=8, but you declare $i =0... so the loop is
running nine times 0,1,...,8
The echo that you're seeing is the last run, cause
empty($userVar[8]) is true (there is nothing in that
index) Got it?
Make it $i  count($userVars).
I hope this help you.
Douglas.

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[PHP] Dumb session cookie question?

2002-12-08 Thread Douglas Douglas

Hi all.
I'm sorry about the dumb question, but I've just
expend two hours trying to find the damn cookie and I
couldn't :(
I've read that when you use sessions and configure the
php.ini with session.use_cookies = 1, your sessions
will always send cookies to the client (if the client
accept the cookies)...
Is that right?
I ask because I'm reading my first tutorial about
sessions and it worked fine... but I can't find where
IE6 (Windows XP, Apache 1.3.27) stores those cookies I
used... I want to see the cookie's contents...
So I was wondering if PHP really sends the cookies,
but I also printed the $_SESSION and $_COOKIE arrays
and it displayed the correct information... in
$_COOKIE displayed PHPSESSID == , so I
think there is some cookie somewhere, my question is
where is it?
I'm so confused right now...
Thanks for any help. Sorry again.

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[PHP] callbacks to methods inside a class/object

2002-09-17 Thread Douglas Marsh



Is there a clean way to make use of PHP builtins that use callbacks and 
point those call backs to a method inside the class/object:

A good example would be:

...

class XMLClass {

  var $parser;

  function XMLClass() {
$this-parser = xml_parser_create();
xml_parser_set_option($this-parser, XML_OPTION_CASE_FOLDING, TRUE);
xml_set_element_handler($this-parser, $this-start, $this-end);
xml_set_character_data_handler($this-parser, $this-data);
  }

  function goodbye() { // a manual destructor
xml_parser_free($this-parser);
// other things possibly too
  }


  function start($p2, $name, $attr) {
// do things here
  }

  function data($p2, $data) {
// do some more here
  }

  function end($p2, $name) {
// do even more things here
  }

  [... and so on ...]

...

But since there is no way to set a callback to $this-[function_name] one 
must create a global function that uses a global object and passes things to 
the method inside the class..

Is the a way to address this? or perhaps a better way to deal with callback 
function names?

--Douglas Marsh






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Re: [PHP] 4.04 -- 4.1.2 incompatible

2002-08-20 Thread Douglas Winslow


Petre Agenbag wrote:
 My oh my
 OK, can someone help with this one???
 My original Form conatined the following:
 form action=test.php method=POST enctype=multipart/form-data
 bla, bla
 
 
 And then things broke, so, out of curiosity, I removed the enctype=
 part, and now it works/

Another tip you might find useful if you're writing code that outputs a 
FORM that posts to itself, is to echo $PHP_SELF instead of hard-coding 
the target.  If you happen to move your code elsewhere in the future, 
this will save you the time of having to go back and specify a new POST 
target.

drw



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[PHP] domxml

2002-06-16 Thread Douglas


Hi,

I have a web page with a form. I want the user to be able to use the £ 
symbol in a text field on the form. I then pass the value of the text 
field(the £ symbol) to a DOMXML function which creates a XML string 
which is transformed into XHTML using the XSLT functions.

I have a meta tag defining the encoding of the web page as UTF-8. (So 
the £ symbol is being passed into the DOMXML function in this format? I 
echo it out just before doing this and it displays correctly.)

the DOMXML functions use UTF-8 for input and output. When I echo the XML 
output before passing it to the XSLT functions, I see that it has placed 
a Â symbol immediately before the £ symbol.

Why? What is going on?
Any ideas very much appreciated.

Douglas.


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[PHP] seesion_register() with arrays

2002-05-31 Thread Douglas - IG


Hi All,

I´m trying to register into a session an array which has returned from a 
mysql_fetch_array function. But when I call $array it returns empty or something like 
this.

Do you know how can I do this operation?

Regards!

Here go my scripts:
?
# script1.php4
session_start();
$sql = select * from table1;
$result = mysql_query ($sql);
...
form name=form1 method=post action=test.php4?session_id=?echo session_id();?

while ($array = mysql_fetch_array($result))
{...}
session_register (array);
?

?
# script2.php4
session_start($session_id);
if (session_is_registered(array))
{
  while ($array) {
  echo $array[fieldname];
  }
}
else { echo Errorbr; }
?

RE: [PHP] Session Initially Does Work

2002-05-02 Thread Adam Douglas


 There is a session problem with 4.1
 
 If register_globals is ON, then use session_register().
 
 If it's off, then use $_SESSION[name] = value; and the value will
 automatically be registered.

What kind of session problem? I currently have register_globals set to on. I
am already using session_register().

 
  Hi. I've run into a problem with my PHP session. I'm running PHP
  4.1.0 on OpenBSD v3.0 using .HTACCESS and mod_mysql. I have 
 a PHP file
  that
  is referenced every time content is requested on the web site (this
 file
  also sets/restores the session). This PHP file includes [include()]
 the
  requested content within. When my session is created I register 6
  variables.
  The problem comes into play when you want to access one of the 6
  registered
  variables on the initial page (after the user logs in). For some
 reason
  the
  registered variables are not recognized. I'm accessing the register
  variables using
  $_SESSION[variable_name]. I've also assigned values to these
 variables.
  The
  funny thing about the whole issue is if you reload/refresh 
 the page or
  load
  something else after the initial page everything works 
 fine. I require
  this
  to work initially because if someone comes in directly using a link
  certain
  content will render a error message because the registered 
 variable is
 not
  present for some reason. Oh and yes the cookie to set the session is
 being
  put on the client's machine properly and at the initial page.

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RE: [PHP] Session Initially Doesn't Work

2002-05-02 Thread Adam Douglas


  Alright that's good to hear. In a specific case that I'm having
  this problem
  the main PHP file is including file (content) that refers to
  $_SESSION[nSID_PeopleID] in main. This value is vital in
  rendering the page.
  So it should be there right? Also about removing 
 session_name(), how can I
  do this. It was my understanding that you must call 
 session_name before
  session_start() and session_register(). Is this not correct?
 
 Ahhh, so that's your problem thenthe include isn't 
 getting the session
 id.  I've never used an include with a session setup before 
 but I would see
 the easiest thing to do be have the include first echo the 
 session id number
 and see if it is actually getting passed or not on the first call
 
 echo session_id();

Yuppers. I played around with the echo session_id(); and found it was not
getting into the scope of the included file. So I removed all
session_register() and replaced it with $_SESSION['varname'] = 'value'; and
it solve the problem. Your not suppose (not recommended) to use
session_register() anways, right?

Thanks for the help!

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[PHP] Session Initially Does Work


Hi. I've run into a problem with my PHP session. I'm running PHP
4.1.0 on OpenBSD v3.0 using .HTACCESS and mod_mysql. I have a PHP file that
is referenced every time content is requested on the web site (this file
also sets/restores the session). This PHP file includes [include()] the
requested content within. When my session is created I register 6 variables.
The problem comes into play when you want to access one of the 6 registered
variables on the initial page (after the user logs in). For some reason the
registered variables are not recognized. I'm accessing the register
variables using 
$_SESSION[variable_name]. I've also assigned values to these variables. The
funny thing about the whole issue is if you reload/refresh the page or load
something else after the initial page everything works fine. I require this
to work initially because if someone comes in directly using a link certain
content will render a error message because the registered variable is not
present for some reason. Oh and yes the cookie to set the session is being
put on the client's machine properly and at the initial page.

Am I doing something wrong? Any suggestions would be greatly appreciated!

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RE: [PHP] Session Initially Does Work


I already have this setup. The session works just not on the initial page
after login.

 Add ? session_start(); ?
 
 At the top of each page, before anything else is done.

 -Original Message-
 From: Adam Douglas [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, May 01, 2002 3:15 PM
 To: PHP-General (mailing list) (E-mail)
 Subject: [PHP] Session Initially Does Work
 
 
   Hi. I've run into a problem with my PHP session. I'm running PHP
 4.1.0 on OpenBSD v3.0 using .HTACCESS and mod_mysql. I have a 
 PHP file that
 is referenced every time content is requested on the web site 
 (this file
 also sets/restores the session). This PHP file includes 
 [include()] the
 requested content within. When my session is created I 
 register 6 variables.
 The problem comes into play when you want to access one of 
 the 6 registered
 variables on the initial page (after the user logs in). For 
 some reason the
 registered variables are not recognized. I'm accessing the register
 variables using
 $_SESSION[variable_name]. I've also assigned values to these 
 variables. The
 funny thing about the whole issue is if you reload/refresh 
 the page or load
 something else after the initial page everything works fine. 
 I require this
 to work initially because if someone comes in directly using 
 a link certain
 content will render a error message because the registered 
 variable is not
 present for some reason. Oh and yes the cookie to set the 
 session is being
 put on the client's machine properly and at the initial page.
 
 Am I doing something wrong? Any suggestions would be greatly 
 appreciated!

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To unsubscribe, visit: http://www.php.net/unsub.php

RE: [PHP] Session Initially Does Work


  something else after the initial page everything works fine. I
  require this
  to work initially because if someone comes in directly using a
  link certain
  content will render a error message because the registered 
 variable is not
  present for some reason. Oh and yes the cookie to set the 
 session is being
  put on the client's machine properly and at the initial page.

 When do you set the session cookie?  Keep in mind cookies 
 don't not function
 in the same call they are created so say you create the 
 cookie on page
 A, until the user refreshes page A or goes to page B the cookie won't
 actually be in effect.

Well the cookie is set at the start of the PHP file that gets referenced
each time. I'm not setting any manual cookies just using the default session
cookie set by PHP. Below is all the code I use for the session. Formatting
is kind of goofed up in e-mail but it's there. So even though the cookie is
placed in the client's browser it's not used/session is not used or
recognized until you refresh/reload or go to another page??

-- Code Snippet --

session_name(sid);
$nSession = session_start();

if(isset($REMOTE_USER))
{
if(!$nSID_PeopleID)
{
$szQuery = SELECT WebAccounts.People_ID,
WebAccounts.Security_Level, People.Status_Type_ID, Company.Company_Status_ID
FROM WebAccounts, People, Company 
WHERE WebAccounts.People_ID=People.People_ID AND
People.Company_ID=Company.Company_ID AND User_Name='$REMOTE_USER';
$szDBConn =
mysql_connect(server_address,user_name,password) or die(could not
connect to server for security authentication.);
mysql_select_db(venmar, $szDBConn) or die(could
not connect to venmar for security //   authentication.);
$saResults = mysql_query($szQuery, $szDBConn) or die
(could not query venmar for security authentication.);
$obResults = mysql_fetch_row($saResults);
$nSID_PeopleID = $obResults[0]; $nSID_SecurityLevel
= $obResults[1];$nSID_PeopleStatus = $obResults[2];
$nSID_CompanyStatus = $obResults[3];

$szQuery1 = SELECT PeopleMailing.Country_ID FROM
PeopleMailing, WebAccounts WHERE
WebAccounts.People_ID=PeopleMailing.People_ID AND
WebAccounts.User_Name='$REMOTE_USER';
$dbConnection = mysql_connect(server_address,
user_name, password) or die(could not connect to server for security
authentication.);
mysql_select_db(venmar, $szDBConn) or die(could
not connect to venmar for security authentication.);
$saResults1 = mysql_query($szQuery1, $szDBConn) or
die (could not query venmar for security authentication.);
$obResults1 = mysql_fetch_row($saResults1);
$nSID_Country = $obResults1[0];

if(!$obResults1[0])
{
$szQuery1 = SELECT Company.Country_ID FROM
Company, WebAccounts, People WHERE WebAccounts.People_ID=People.People_ID
AND People.Company_ID=Company.Company_ID AND
WebAccounts.User_Name='$REMOTE_USER';
$saResults1 = mysql_query($szQuery1,
$szDBConn) or die (could not query venmar for security authentication
(24).);
$obResults1 = mysql_fetch_row($saResults1);
$nSID_Country = $obResults1[0];
}
mysql_close();

if($obResults[2] == 1  $obResults[3] == 1)
{
if($nSession == 1)
{
session_register(nSession);
session_register(nSID_PeopleID);

session_register(nSID_SecurityLevel);

session_register(nSID_PeopleStatus);

session_register(nSID_CompanyStatus);
session_register(nSID_Country);

$szQuery = SELECT First_Login,
Last_Login, Creation_Date FROM WebAccounts WHERE User_Name='$REMOTE_USER';
$dbConnection =
mysql_connect(server_address, user_name, password) or die(could not
connect to server for security authentication.);
mysql_select_db(venmar,
$dbConnection) or die(could not connect to venmar for security
authentication.);
$saResults = mysql_query($szQuery,
$dbConnection) or die (could not query venmar for security
authentication.);
$obResults =
mysql_fetch_row($saResults);

if($obResults[0] == 00)
{

RE: [PHP] Session Initially Does Work