[PHP] exec from process (deamon) without shell
Hi,
I have a very complex script that is being called by a running deamon that
doesn't have any shell. To simplify it I make this script, that is also
failing:
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly. Exit
code: $exitcode\n;
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
}
}
?
This code give the exit code -1 that is equal to that ls -lrt could not be
executed.
Running this from shell give correct result.
Executing it from a web page (thru apache) gives correct result.
But the shell less deamon is giving the -1 exit code.
Is exec requiring a shell? Any workaround on this? I will play around, maybe
something like system() or passthru() will do it, but I haven't tested that
yet, want to get some feedback first.
Best regards,
Peter Lauri
http://www.dwsasia.com/ www.dwsasia.com - company web site
http://www.lauri.se/ www.lauri.se - personal web site
http://www.carbonfree.org.uk/ www.carbonfree.org.uk - become Carbon Free
Re: [PHP] exec from process (deamon) without shell
# [EMAIL PROTECTED] / 2007-03-01 18:28:35 +0200:
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly. Exit code:
$exitcode\n;
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
}
}
?
This code give the exit code -1 that is equal to that ls -lrt could not be
executed.
Does the daemon run chrooted somewhere?
What does $PATH contain?
What happens if you use /bin/ls?
--
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
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Re: [PHP] exec from process (deamon) without shell
Quoting Roman Neuhauser [EMAIL PROTECTED]:
# [EMAIL PROTECTED] / 2007-03-01 18:28:35 +0200:
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly.
Exit code: $exitcode\n;
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
}
}
?
This code give the exit code -1 that is equal to that ls -lrt could not be
executed.
Does the daemon run chrooted somewhere?
What does $PATH contain?
What happens if you use /bin/ls?
I tried with /bin/ls but still same thing. I just found out that the
exitcode is -1 but the $stdout actually gives correct answer. But that
doesn't make sense. How can I then control what action to take
depending on the exitcode?
apache 10099 1 0 18:47 ?00:00:00 /tmp/log_monitor
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Re: [PHP] exec from process (deamon) without shell
Quoting Roman Neuhauser [EMAIL PROTECTED]:
# [EMAIL PROTECTED] / 2007-03-01 18:28:35 +0200:
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly.
Exit code: $exitcode\n;
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
}
}
?
This code give the exit code -1 that is equal to that ls -lrt could not be
executed.
Does the daemon run chrooted somewhere?
What does $PATH contain?
What happens if you use /bin/ls?
--
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
Becuase this only is having problems when executing from the deamon I added:
exec(php -i, $stdout, $exitcode);
And then put it into a logfile. Is there anything here that makes
$exitcode for all commands executed -1, but they still seams to be
functional as $stdout is as expected:
2007-03-02 00:00:54 Environment
2007-03-02 00:00:54
2007-03-02 00:00:54 Variable = Value
2007-03-02 00:00:54 TERM = xterm
2007-03-02 00:00:54 PATH =
/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/bin
2007-03-02 00:00:54 _ = /usr/bin/php
2007-03-02 00:00:54 PWD = /var/www/util
2007-03-02 00:00:54 LANG = C
2007-03-02 00:00:54 SHLVL = 6
2007-03-02 00:00:54
2007-03-02 00:00:54 PHP Variables
2007-03-02 00:00:54
2007-03-02 00:00:54 Variable = Value
2007-03-02 00:00:54 _SERVER[TERM] = xterm
2007-03-02 00:00:54 _SERVER[PATH] =
/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/bin
2007-03-02 00:00:54 _SERVER[_] = /usr/bin/php
2007-03-02 00:00:54 _SERVER[PWD] = /var/www/util
2007-03-02 00:00:54 _SERVER[LANG] = C
2007-03-02 00:00:54 _SERVER[SHLVL] = 6
2007-03-02 00:00:54 _SERVER[PHP_SELF] =
2007-03-02 00:00:54 _SERVER[SCRIPT_NAME] =
2007-03-02 00:00:54 _SERVER[SCRIPT_FILENAME] =
2007-03-02 00:00:54 _SERVER[PATH_TRANSLATED] =
2007-03-02 00:00:54 _SERVER[DOCUMENT_ROOT] =
2007-03-02 00:00:54 _SERVER[REQUEST_TIME] = 1172786454
2007-03-02 00:00:54 _SERVER[argv] = Array
2007-03-02 00:00:54 (
2007-03-02 00:00:54 )
2007-03-02 00:00:54
2007-03-02 00:00:54 _SERVER[argc] = 0
2007-03-02 00:00:54 _ENV[TERM] = xterm
2007-03-02 00:00:54 _ENV[PATH] =
/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/bin
2007-03-02 00:00:54 _ENV[_] = /usr/bin/php
2007-03-02 00:00:54 _ENV[PWD] = /var/www/util
2007-03-02 00:00:54 _ENV[LANG] = C
2007-03-02 00:00:54 _ENV[SHLVL] = 6
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Re: [PHP] exec from process (deamon) without shell
On Thu, March 1, 2007 10:28 am, Peter Lauri wrote:
I have a very complex script that is being called by a running deamon
that
doesn't have any shell. To simplify it I make this script, that is
also
failing:
PHP also uses a mini non-shell thingie to run exec.
As such, it has no home directory, no $PATH (or is it $path) and not
much of anything.
Provide the FULL PATH to 'ls' and your test script should work fine.
By extension, you need the FULL PATH to everything file-system-related
in your real application.
You also need to be aware that YOU run as, well, you, and PHP runs as
some user defined in httpd.conf (for Apache module) or
IUSER_machinename for IIS (unless you re-configure) or as, errr,
User in httpd.conf for CGI, and then, ummm, for FCGI, you're going to
have to research that one.
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly.
Exit
code: $exitcode\n;
You may also want to dump out implode(\n, $stdout) just in case it
has useful messages.
You could also consider sending stderr (2) into stdout (1) so that any
error messages are captured.
See thread from last week on this one.
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
If by some chance performance is an issue (probably not) then you may
want to benchmark this end-to-end with 'ab' compared to echo
implode(\n, $stdout)
I'm not making any prediction either way on this, just noting a simple
alternative worth exploring if performance IS an issue.
}
}
?
This code give the exit code -1 that is equal to that ls -lrt could
not be
executed.
Running this from shell give correct result.
This invariably indicates a path/permissions difference between you
logged in as YOU, and PHP running as some other user in a totally
different environment/shell.
Executing it from a web page (thru apache) gives correct result.
But the shell less deamon is giving the -1 exit code.
Is exec requiring a shell? Any workaround on this? I will play around,
maybe
something like system() or passthru() will do it, but I haven't tested
that
yet, want to get some feedback first.
exec doesn't require a shell.
It has some kind of minimal shell already, I think.
But it's definitely not the same full-blown shell you use when you
login as YOU. (well, probably not, unless you're a shell masochist
minimalist. :-)
--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
--
PHP General Mailing List (http://www.php.net/)
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RE: [PHP] exec from process (deamon) without shell
The thing is that the commands are executed as they should. I have tested to
give full path /bin/ls and that gives the same result.
BUT the exit code is -1 still. Not 0 as when running it from command line.
Best regards,
Peter Lauri
www.dwsasia.com - company web site
www.lauri.se - personal web site
www.carbonfree.org.uk - become Carbon Free
-Original Message-
From: Richard Lynch [mailto:[EMAIL PROTECTED]
Sent: Friday, March 02, 2007 12:29 AM
To: Peter Lauri
Cc: 'PHP Mailing'
Subject: Re: [PHP] exec from process (deamon) without shell
On Thu, March 1, 2007 10:28 am, Peter Lauri wrote:
I have a very complex script that is being called by a running deamon
that
doesn't have any shell. To simplify it I make this script, that is
also
failing:
PHP also uses a mini non-shell thingie to run exec.
As such, it has no home directory, no $PATH (or is it $path) and not
much of anything.
Provide the FULL PATH to 'ls' and your test script should work fine.
By extension, you need the FULL PATH to everything file-system-related
in your real application.
You also need to be aware that YOU run as, well, you, and PHP runs as
some user defined in httpd.conf (for Apache module) or
IUSER_machinename for IIS (unless you re-configure) or as, errr,
User in httpd.conf for CGI, and then, ummm, for FCGI, you're going to
have to research that one.
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly.
Exit
code: $exitcode\n;
You may also want to dump out implode(\n, $stdout) just in case it
has useful messages.
You could also consider sending stderr (2) into stdout (1) so that any
error messages are captured.
See thread from last week on this one.
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
If by some chance performance is an issue (probably not) then you may
want to benchmark this end-to-end with 'ab' compared to echo
implode(\n, $stdout)
I'm not making any prediction either way on this, just noting a simple
alternative worth exploring if performance IS an issue.
}
}
?
This code give the exit code -1 that is equal to that ls -lrt could
not be
executed.
Running this from shell give correct result.
This invariably indicates a path/permissions difference between you
logged in as YOU, and PHP running as some other user in a totally
different environment/shell.
Executing it from a web page (thru apache) gives correct result.
But the shell less deamon is giving the -1 exit code.
Is exec requiring a shell? Any workaround on this? I will play around,
maybe
something like system() or passthru() will do it, but I haven't tested
that
yet, want to get some feedback first.
exec doesn't require a shell.
It has some kind of minimal shell already, I think.
But it's definitely not the same full-blown shell you use when you
login as YOU. (well, probably not, unless you're a shell masochist
minimalist. :-)
--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec from process (deamon) without shell
On Thu, March 1, 2007 12:56 pm, [EMAIL PROTECTED] wrote: I tried with /bin/ls but still same thing. I just found out that the exitcode is -1 but the $stdout actually gives correct answer. But that doesn't make sense. How can I then control what action to take depending on the exitcode? I *think* this could be the result of trying to ls a bunch of files, some of which you don't have permission to 'ls', so you are getting a partial list of stuff, but also an error code for trying to ls stuff you shouldn't have been doing that too, if you see what I mean... I am hoping that your real script is a bit more complicated, as you currently have a shell script that runs PHP only to run a shell script that just does 'ls', which, really, you could probably just splat into your shell script without PHP being involved... -- Some people have a gift link here. Know what I want? I want you to buy a CD from some starving artist. http://cdbaby.com/browse/from/lynch Yeah, I get a buck. So? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec from process (deamon) without shell
Add a nice clean line to the end of your PHP scripts:
exit 0; //exit cleanly
If your PHP scripts' last function call returns, say, -1, and then PHP
just passes that back on out, it's probably going to look like an
error code to the outermost shell, if you see what I mean...
I'm not promising this is how it actually works; this is just a theory.
Thu, March 1, 2007 5:12 pm, [EMAIL PROTECTED] wrote:
Quoting Roman Neuhauser [EMAIL PROTECTED]:
# [EMAIL PROTECTED] / 2007-03-01 18:28:35 +0200:
#/thepathtophp
?php
exec(ls -lrt, $stdout, $exitcode);
if($exitcode!=0) {
echo Command ls -lrt could not be executed correctly.
Exit code: $exitcode\n;
} else {
echo Result:\n;
foreach($stdout AS $line) {
echo $line.\n;
}
}
?
This code give the exit code -1 that is equal to that ls -lrt
could not be
executed.
Does the daemon run chrooted somewhere?
What does $PATH contain?
What happens if you use /bin/ls?
--
How many Vietnam vets does it take to screw in a light bulb?
You don't know, man. You don't KNOW.
Cause you weren't THERE. http://bash.org/?255991
Becuase this only is having problems when executing from the deamon I
added:
exec(php -i, $stdout, $exitcode);
And then put it into a logfile. Is there anything here that makes
$exitcode for all commands executed -1, but they still seams to be
functional as $stdout is as expected:
2007-03-02 00:00:54 Environment
2007-03-02 00:00:54
2007-03-02 00:00:54 Variable = Value
2007-03-02 00:00:54 TERM = xterm
2007-03-02 00:00:54 PATH =
/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/bin
2007-03-02 00:00:54 _ = /usr/bin/php
2007-03-02 00:00:54 PWD = /var/www/util
2007-03-02 00:00:54 LANG = C
2007-03-02 00:00:54 SHLVL = 6
2007-03-02 00:00:54
2007-03-02 00:00:54 PHP Variables
2007-03-02 00:00:54
2007-03-02 00:00:54 Variable = Value
2007-03-02 00:00:54 _SERVER[TERM] = xterm
2007-03-02 00:00:54 _SERVER[PATH] =
/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/bin
2007-03-02 00:00:54 _SERVER[_] = /usr/bin/php
2007-03-02 00:00:54 _SERVER[PWD] = /var/www/util
2007-03-02 00:00:54 _SERVER[LANG] = C
2007-03-02 00:00:54 _SERVER[SHLVL] = 6
2007-03-02 00:00:54 _SERVER[PHP_SELF] =
2007-03-02 00:00:54 _SERVER[SCRIPT_NAME] =
2007-03-02 00:00:54 _SERVER[SCRIPT_FILENAME] =
2007-03-02 00:00:54 _SERVER[PATH_TRANSLATED] =
2007-03-02 00:00:54 _SERVER[DOCUMENT_ROOT] =
2007-03-02 00:00:54 _SERVER[REQUEST_TIME] = 1172786454
2007-03-02 00:00:54 _SERVER[argv] = Array
2007-03-02 00:00:54 (
2007-03-02 00:00:54 )
2007-03-02 00:00:54
2007-03-02 00:00:54 _SERVER[argc] = 0
2007-03-02 00:00:54 _ENV[TERM] = xterm
2007-03-02 00:00:54 _ENV[PATH] =
/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/bin
2007-03-02 00:00:54 _ENV[_] = /usr/bin/php
2007-03-02 00:00:54 _ENV[PWD] = /var/www/util
2007-03-02 00:00:54 _ENV[LANG] = C
2007-03-02 00:00:54 _ENV[SHLVL] = 6
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--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
--
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RE: [PHP] exec from process (deamon) without shell
-Original Message- From: Richard Lynch [mailto:[EMAIL PROTECTED] Sent: Friday, March 02, 2007 12:35 AM To: [EMAIL PROTECTED] Cc: Roman Neuhauser; 'PHP Mailing' Subject: Re: [PHP] exec from process (deamon) without shell On Thu, March 1, 2007 12:56 pm, [EMAIL PROTECTED] wrote: I tried with /bin/ls but still same thing. I just found out that the exitcode is -1 but the $stdout actually gives correct answer. But that doesn't make sense. How can I then control what action to take depending on the exitcode? I *think* this could be the result of trying to ls a bunch of files, some of which you don't have permission to 'ls', so you are getting a partial list of stuff, but also an error code for trying to ls stuff you shouldn't have been doing that too, if you see what I mean... I am hoping that your real script is a bit more complicated, as you currently have a shell script that runs PHP only to run a shell script that just does 'ls', which, really, you could probably just splat into your shell script without PHP being involved... [Peter Lauri - DWS Asia] It is a much more complicated logic, so therefore I am not using a shell script. I will examine how perl acts on executing the same commands and if that is catching 0 as error code I might move to run perl instead. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] exec from process (deamon) without shell
-Original Message- From: Richard Lynch [mailto:[EMAIL PROTECTED] Sent: Friday, March 02, 2007 12:37 AM To: [EMAIL PROTECTED] Cc: Roman Neuhauser; 'PHP Mailing' Subject: Re: [PHP] exec from process (deamon) without shell Add a nice clean line to the end of your PHP scripts: exit 0; //exit cleanly If your PHP scripts' last function call returns, say, -1, and then PHP just passes that back on out, it's probably going to look like an error code to the outermost shell, if you see what I mean... I'm not promising this is how it actually works; this is just a theory. [Peter Lauri - DWS Asia] I will take a look at that tomorrow; right now it is 1am and time for bed :) I will keep you updated on that one to inform you if your theory was working :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
