Re: [PHP] Global Var Disappearing After Function
APseudoUtopia wrote: > On Mon, Mar 22, 2010 at 5:13 PM, Peter van der Does > wrote: >> On Mon, 22 Mar 2010 16:58:33 -0400 >> APseudoUtopia wrote: >> >>> Hey list, >>> >>> I have a very odd problem which has been driving me crazy for two >>> days. I've been trying to debug my code and gave up. I finally coded a >>> very simple representation of what the code does, and I get the same >>> problem. However, I still don't understand what's causing it. >>> >>> The representational code: >>> http://pastie.org/private/fz3lgvsjopz3dhid8cf9a >>> >>> As you can see, it's very simple. A variable is set, then a function >>> is called which modifies the variable in the global scope. However, >>> the modifications CANNOT BE SEEN after the function is called. >>> >>> The output from the script is here: >>> http://pastie.org/private/29r5mrr1k7rtqmw7eyoja >>> >>> As you can see, the modifications in do_test() cannot be seen after >>> the function is called. >>> >>> What is causing this? And how can I fix it? >>> >>> Thanks! >>> >> From PHP.net: >> >> If a globalized variable is unset() inside of a function, only the >> local variable is destroyed. The variable in the calling environment >> will retain the same value as before unset() was called. [1] >> >> [1] http://php.net/manual/en/function.unset.php >> >> > > Ah ha! I was looking on the php.net/global page for hints, but didn't > see any. I should've looked on the unset page. Thanks! Really no reason to unset() it anyway since you do this: $Session = $UserInfo; -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Global Var Disappearing After Function
On Mon, Mar 22, 2010 at 5:13 PM, Peter van der Does wrote: > On Mon, 22 Mar 2010 16:58:33 -0400 > APseudoUtopia wrote: > >> Hey list, >> >> I have a very odd problem which has been driving me crazy for two >> days. I've been trying to debug my code and gave up. I finally coded a >> very simple representation of what the code does, and I get the same >> problem. However, I still don't understand what's causing it. >> >> The representational code: >> http://pastie.org/private/fz3lgvsjopz3dhid8cf9a >> >> As you can see, it's very simple. A variable is set, then a function >> is called which modifies the variable in the global scope. However, >> the modifications CANNOT BE SEEN after the function is called. >> >> The output from the script is here: >> http://pastie.org/private/29r5mrr1k7rtqmw7eyoja >> >> As you can see, the modifications in do_test() cannot be seen after >> the function is called. >> >> What is causing this? And how can I fix it? >> >> Thanks! >> > > From PHP.net: > > If a globalized variable is unset() inside of a function, only the > local variable is destroyed. The variable in the calling environment > will retain the same value as before unset() was called. [1] > > [1] http://php.net/manual/en/function.unset.php > > Ah ha! I was looking on the php.net/global page for hints, but didn't see any. I should've looked on the unset page. Thanks! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Global Var Disappearing After Function
On Mon, 22 Mar 2010 16:58:33 -0400 APseudoUtopia wrote: > Hey list, > > I have a very odd problem which has been driving me crazy for two > days. I've been trying to debug my code and gave up. I finally coded a > very simple representation of what the code does, and I get the same > problem. However, I still don't understand what's causing it. > > The representational code: > http://pastie.org/private/fz3lgvsjopz3dhid8cf9a > > As you can see, it's very simple. A variable is set, then a function > is called which modifies the variable in the global scope. However, > the modifications CANNOT BE SEEN after the function is called. > > The output from the script is here: > http://pastie.org/private/29r5mrr1k7rtqmw7eyoja > > As you can see, the modifications in do_test() cannot be seen after > the function is called. > > What is causing this? And how can I fix it? > > Thanks! > From PHP.net: If a globalized variable is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called. [1] [1] http://php.net/manual/en/function.unset.php -- Peter van der Does GPG key: E77E8E98 IRC: Ganseki on irc.freenode.net Twitter: @petervanderdoes WordPress Plugin Developer Blog: http://blog.avirtualhome.com Forums: http://forums.avirtualhome.com Twitter: @avhsoftware -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Global Var Disappearing After Function
On Mon, Mar 22, 2010 at 4:58 PM, APseudoUtopia wrote: > Hey list, > > I have a very odd problem which has been driving me crazy for two > days. I've been trying to debug my code and gave up. I finally coded a > very simple representation of what the code does, and I get the same > problem. However, I still don't understand what's causing it. > > The representational code: > http://pastie.org/private/fz3lgvsjopz3dhid8cf9a > > As you can see, it's very simple. A variable is set, then a function > is called which modifies the variable in the global scope. However, > the modifications CANNOT BE SEEN after the function is called. > > The output from the script is here: > http://pastie.org/private/29r5mrr1k7rtqmw7eyoja > > As you can see, the modifications in do_test() cannot be seen after > the function is called. > > What is causing this? And how can I fix it? > > Thanks! > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > I believe line 8 detaches the variable $Session that exists inside the function from the global variable that exists outside the function. Andrew -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] global var.
On Tuesday 01 April 2003 11:59, Sebastian wrote:
> Hmm, interesting.. i dunno why it doesn't work for me, here is a bit of the
> code, $var isn't getting the output of $id, any ideas?
Are you sure that $id contains what you think it contains?
Also could you explain the reason why your code is laid out the way it is?
Line 1
> $var = &$id;
Line 2
> if( ! $forg = resizer_main("image","image_$var", blah, blah");
Line 3
> $org = getimagesize( "$root/$forg" );
Line 4
> $result = @mysql_query("INSERT INTO images blah blah.");
Line 5
> $id = mysql_insert_id();
In Line 2, $var will contain whatever $id contained in Line 1. IOW if the
value of $id was not defined before Line 1, then $var will be similarly
"undefined". Is that your intention?
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Re: [PHP] global var.
Hmm, interesting.. i dunno why it doesn't work for me, here is a bit of the
code, $var isn't getting the output of $id, any ideas?
$var = &$id;
if( ! $forg = resizer_main("image","image_$var", blah, blah");
$org = getimagesize( "$root/$forg" );
$result = @mysql_query("INSERT INTO images blah blah.");
$id = mysql_insert_id();
cheers,
Sebastian
- Original Message -
From: "Marcus Rasmussen" <[EMAIL PROTECTED]>
Putting an & sign in front of the $id in the first line should do the trick:
$variable = &$id;
A short example:
$bar = 0;
$foo = &$bar;
$bar = 2;
print $foo; //prints 2
__
Marcus Rasmussen
[EMAIL PROTECTED]
www.marcusr.dk
-
On 31-03-2003 at 19:56 Sebastian wrote:
-
hello all,
$variable = $id;
// some other stuff
@mysql_query here
$id = mysql_insert_id();
to the question: How do I get $id from insert_id() to pass to $variable
above? Hard to explain the situation i am in, but the query has to be below
$variable, is it possible to 'globalize' $id so it passes to the top
$variable?
first time i ever ran into this problem.
Thanks in advanced.
cheers,
- Sebastian
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Re: [PHP] global var.
Putting an & sign in front of the $id in the first line should do the trick: $variable = &$id; A short example: $bar = 0; $foo = &$bar; $bar = 2; print $foo; //prints 2 __ Marcus Rasmussen [EMAIL PROTECTED] www.marcusr.dk - On 31-03-2003 at 19:56 Sebastian wrote: - hello all, $variable = $id; // some other stuff @mysql_query here $id = mysql_insert_id(); to the question: How do I get $id from insert_id() to pass to $variable above? Hard to explain the situation i am in, but the query has to be below $variable, is it possible to 'globalize' $id so it passes to the top $variable? first time i ever ran into this problem. Thanks in advanced. cheers, - Sebastian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] global var.
Hi Sebastian,
> $variable = $id;
> // some other stuff
> @mysql_query here
> $id = mysql_insert_id();
>
> How do I get $id from insert_id() to pass to $variable
> above? Hard to explain the situation i am in, but the
> query has to be below $variable
::blink::
Perhaps something like:
$loc = $PHP_SELF. "?variable=". $id;
header("Location:". $loc);
You'd have to put something in to stop an infinte loop though.
Cheers
Jon
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