Re: [Puppet Users] regsubst and regex
Ok, I totally forget that replacement part is not a search :D
On Mon, Apr 16, 2012 at 5:00 PM, Thomas Bellman wrote:
> On 2012-04-16 15:57, Antidot SAS top-posted:
>
> > Thx for the reply it helps.
> >
> > But how come the \2 returns something that I never asked?
>
> It doesn't. But since there are no occurrances of '^(.*)->(.*)',
> then there are none that get replaced. Similarly, if you do:
>
>regsubst('foobar', 'x', 'y')
>
> you will get 'foobar', since there *is* no 'x' in 'foobar' that
> can be replaced by a 'y'.
>
>
>/Bellman
>
> --
> You received this message because you are subscribed to the Google Groups
> "Puppet Users" group.
> To post to this group, send email to puppet-users@googlegroups.com.
> To unsubscribe from this group, send email to
> puppet-users+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/puppet-users?hl=en.
>
>
--
You received this message because you are subscribed to the Google Groups
"Puppet Users" group.
To post to this group, send email to puppet-users@googlegroups.com.
To unsubscribe from this group, send email to
puppet-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/puppet-users?hl=en.
Re: [Puppet Users] regsubst and regex
On 2012-04-16 15:57, Antidot SAS top-posted:
> Thx for the reply it helps.
>
> But how come the \2 returns something that I never asked?
It doesn't. But since there are no occurrances of '^(.*)->(.*)',
then there are none that get replaced. Similarly, if you do:
regsubst('foobar', 'x', 'y')
you will get 'foobar', since there *is* no 'x' in 'foobar' that
can be replaced by a 'y'.
/Bellman
--
You received this message because you are subscribed to the Google Groups
"Puppet Users" group.
To post to this group, send email to puppet-users@googlegroups.com.
To unsubscribe from this group, send email to
puppet-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/puppet-users?hl=en.
Re: [Puppet Users] regsubst and regex
Thx for the reply it helps.
But how come the \2 returns something that I never asked?
On Mon, Apr 16, 2012 at 3:47 PM, Thomas Bellman wrote:
> On 2012-04-16 15:26, Antidot SAS wrote:
>
> > A quick question for you, here is the code:
> > $tt=regsubst("test","^(.*)->(.*)",'\2')
> >
> > Doesn't return: undef or nil, it does return: "test"
>
> As expected and intended.
>
> > Niether does $tt=regsubst("test","^(.?)->(.*)",'\2')
> > or $tt=regsubst("test","^(.+?)->(.*)",'\2').
> >
> > Is there a way to return undef if the string doesn't include
> '->something' ?
>
> Perhaps something like this:
>
>$x = 'test'
>$temp = regsubst($x, '^(.*)->(.*)', '\2')
>if $temp == $x {
># No substitution done, must mean there is no "->" in $x
>$tt = undef
>} else {
>$tt = $temp
>}
>
> Or perhaps this:
>
>$tt = regsubst($x, '^(.*)->(.*)|.*', '\2')
>
> It will however give you the empty string (""), not undef, if there is
> no "->" in the string.
>
>
>/Bellman
>
> --
> You received this message because you are subscribed to the Google Groups
> "Puppet Users" group.
> To post to this group, send email to puppet-users@googlegroups.com.
> To unsubscribe from this group, send email to
> puppet-users+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/puppet-users?hl=en.
>
>
--
You received this message because you are subscribed to the Google Groups
"Puppet Users" group.
To post to this group, send email to puppet-users@googlegroups.com.
To unsubscribe from this group, send email to
puppet-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/puppet-users?hl=en.
Re: [Puppet Users] regsubst and regex
On 2012-04-16 15:26, Antidot SAS wrote:
> A quick question for you, here is the code:
> $tt=regsubst("test","^(.*)->(.*)",'\2')
>
> Doesn't return: undef or nil, it does return: "test"
As expected and intended.
> Niether does $tt=regsubst("test","^(.?)->(.*)",'\2')
> or $tt=regsubst("test","^(.+?)->(.*)",'\2').
>
> Is there a way to return undef if the string doesn't include '->something' ?
Perhaps something like this:
$x = 'test'
$temp = regsubst($x, '^(.*)->(.*)', '\2')
if $temp == $x {
# No substitution done, must mean there is no "->" in $x
$tt = undef
} else {
$tt = $temp
}
Or perhaps this:
$tt = regsubst($x, '^(.*)->(.*)|.*', '\2')
It will however give you the empty string (""), not undef, if there is
no "->" in the string.
/Bellman
--
You received this message because you are subscribed to the Google Groups
"Puppet Users" group.
To post to this group, send email to puppet-users@googlegroups.com.
To unsubscribe from this group, send email to
puppet-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/puppet-users?hl=en.
[Puppet Users] regsubst and regex
Hi everyone,
A quick question for you, here is the code:
$tt=regsubst("test","^(.*)->(.*)",'\2')
Doesn't return: undef or nil, it does return: "test"
Niether does $tt=regsubst("test","^(.?)->(.*)",'\2')
or $tt=regsubst("test","^(.+?)->(.*)",'\2').
Is there a way to return undef if the string doesn't include '->something' ?
Regards,
JM
--
You received this message because you are subscribed to the Google Groups
"Puppet Users" group.
To post to this group, send email to puppet-users@googlegroups.com.
To unsubscribe from this group, send email to
puppet-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/puppet-users?hl=en.
