Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[Hendrik van Rooyen]

 Joe [EMAIL PROTECTED] wrote:

 I am new to lambda and have searched for a few hours this morning, coming up
 empty handed.  Is this possible?

Seeing as it has happened, it must be.

- Hendrik

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[Peter Otten]

Ben Finney wrote:

 mosscliffe [EMAIL PROTECTED] writes:
 
 I have tried the following, for a one dimensional list and it works,
 but I can not get my head around this lambda. How would this be
 written, without the lamda ?

 mylist = ['Fred','bill','PAUL','albert']

 mylist.sort(key=lambda el: el.lower())
 
 Here's a hint:
 
  FoO.lower()
 'foo'
  str.lower(FoO)
 'foo'

But be aware that you lose both the ability to override and duck-typing:

 print r # derived from str
Upper East Side
 print s # unicode
München
 r.lower(), str.lower(r)
('Lower East Side', 'upper east side')
 s.lower(), str.lower(s)
Traceback (most recent call last):
  File stdin, line 1, in module
TypeError: descriptor 'lower' requires a 'str' object but received a
'unicode'

Peter
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Case-Insensitive Sorting of Multi-Dimensional Lists

[Joe]

I have a list of lists that I would like to sort utilizing a certain index
of the nested list.  I am able to successfully use:

 

Import operator

list = [[Apple, 1], [airplane, 2]]

list.sort(key=operator.itemgetter(0))

 

But, unfortunately, this will be case sensitive (Apple will come before
airplane because the A is capital) and I need it to be insensitive.  

 

Can someone provide some input, please?

 

Thanks in advance!

 

Jough

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[Simon Brunning]

On 6/7/07, Joe [EMAIL PROTECTED] wrote:

 I have a list of lists that I would like to sort utilizing a certain index
 of the nested list.  I am able to successfully use:

 Import operator
 list = [[Apple, 1], [airplane, 2]]
 list.sort(key=operator.itemgetter(0))

 But, unfortunately, this will be case sensitive (Apple will come before
 airplane because the A is capital) and I need it to be insensitive.

Try:

list.sort(key=lambda el: el[0].lower())

BUT - it's not a good idea to use list as a name, 'cos list is a
built-in, and you're obscuring it.

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Cheers,
Simon B.
[EMAIL PROTECTED]
http://www.brunningonline.net/simon/blog/
GTalk: simon.brunning | MSN: small_values | Yahoo: smallvalues
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RE: Case-Insensitive Sorting of Multi-Dimensional Lists

[Joe]

 Try:
 
 list.sort(key=lambda el: el[0].lower())

Thanks!  Worked like a charm :)

 BUT - it's not a good idea to use list as a name, 'cos list is a
 built-in, and you're obscuring it.

Oh, don't worry.  That was strictly my portrayal of the problem.

Thanks again!

Jough

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[mosscliffe]

On 8 Jun, 14:18, Simon Brunning [EMAIL PROTECTED] wrote:
 On 6/7/07, Joe [EMAIL PROTECTED] wrote:



  I have a list of lists that I would like to sort utilizing a certain index
  of the nested list.  I am able to successfully use:

  Import operator
  list = [[Apple, 1], [airplane, 2]]
  list.sort(key=operator.itemgetter(0))

  But, unfortunately, this will be case sensitive (Apple will come before
  airplane because the A is capital) and I need it to be insensitive.

 Try:

 list.sort(key=lambda el: el[0].lower())

 BUT - it's not a good idea to use list as a name, 'cos list is a
 built-in, and you're obscuring it.

 --
 Cheers,
 Simon B.
 [EMAIL PROTECTED]://www.brunningonline.net/simon/blog/
 GTalk: simon.brunning | MSN: small_values | Yahoo: smallvalues

I have tried the following, for a one dimensional list and it works,
but I can not get my head around this lambda. How would this be
written, without the lamda ?

mylist = ['Fred','bill','PAUL','albert']

mylist.sort(key=lambda el: el.lower())

Any pointer to an idiot's guide appreciated.

Richard

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[Marc 'BlackJack' Rintsch]

In [EMAIL PROTECTED], mosscliffe
wrote:

 I have tried the following, for a one dimensional list and it works,
 but I can not get my head around this lambda. How would this be
 written, without the lamda ?

Well ``lambda``\s are just anonymous functions so you can write it with a
named function of course.

 mylist = ['Fred','bill','PAUL','albert']
 
 mylist.sort(key=lambda el: el.lower())

So this becomes:

def keyfunc(el):
return el.lower()

mylist.sort(key=keyfunc)

Ciao,
Marc 'BlackJack' Rintsch
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RE: Case-Insensitive Sorting of Multi-Dimensional Lists

[Joe]

 Try:
 
 list.sort(key=lambda el: el[0].lower())

Now, I would like to be able to specify which index to sort by.  I am not
able to pass in external variables like:

List.sort(key=lambda el: el[indexNumber].lower())

I am new to lambda and have searched for a few hours this morning, coming up
empty handed.  Is this possible?

Thanks!

Jough

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[Simon Brunning]

On 6/8/07, Joe [EMAIL PROTECTED] wrote:
 Now, I would like to be able to specify which index to sort by.  I am not
 able to pass in external variables like:

 List.sort(key=lambda el: el[indexNumber].lower())

Why ever not?

-- 
Cheers,
Simon B.
[EMAIL PROTECTED]
http://www.brunningonline.net/simon/blog/
GTalk: simon.brunning | MSN: small_values | Yahoo: smallvalues
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RE: Case-Insensitive Sorting of Multi-Dimensional Lists

[Joe]

  Now, I would like to be able to specify which index to sort by.  I am
 not
  able to pass in external variables like:
 
  List.sort(key=lambda el: el[indexNumber].lower())
 
 Why ever not?

Sorry, I should have written back with my findings.  I had run into the
problem described in this email:
http://mail.python.org/pipermail/python-list/2001-June/090863.html.  See, I
was using bare execs elsewhere in the program.

It had nothing to do with the lambda, which ended up working perfectly once
I fixed the exec.

Thanks!

Jough

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[mosscliffe]

On 8 Jun, 16:39, Marc 'BlackJack' Rintsch [EMAIL PROTECTED] wrote:
 In [EMAIL PROTECTED], mosscliffe
 wrote:

  I have tried the following, for a one dimensional list and it works,
  but I can not get my head around this lambda. How would this be
  written, without the lamda ?

 Well ``lambda``\s are just anonymous functions so you can write it with a
 named function of course.

  mylist = ['Fred','bill','PAUL','albert']

  mylist.sort(key=lambda el: el.lower())

 So this becomes:

 def keyfunc(el):
 return el.lower()

 mylist.sort(key=keyfunc)

 Ciao,
 Marc 'BlackJack' Rintsch

Thanks,

The mist is beginning to clear.

Richard

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Re: Case-Insensitive Sorting of Multi-Dimensional Lists

[Ben Finney]

mosscliffe [EMAIL PROTECTED] writes:

 I have tried the following, for a one dimensional list and it works,
 but I can not get my head around this lambda. How would this be
 written, without the lamda ?

 mylist = ['Fred','bill','PAUL','albert']

 mylist.sort(key=lambda el: el.lower())

Here's a hint:

 FoO.lower()
'foo'
 str.lower(FoO)
'foo'

-- 
 \When I was a baby I kept a diary. Recently I was re-reading |
  `\   it, it said 'Day 1: Still tired from the move. Day 2: Everybody |
_o__)   talks to me like I'm an idiot.'  -- Steven Wright |
Ben Finney
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