For specific keys , extract non empty values in a dictionary
*How do I check few specific/selected keys in a dictionary and extract
their values if they are not empty*
*Example : Extract the values for key "one","three","seven" and "nine” if
they are not empty*
*Input :*
*o_num = {'one': 1,*
* 'three': 3,*
* 'bar': None,*
* 'five' : 5,*
* 'rum' : None,*
* 'seven' : None,*
* 'brandy': None,*
* 'nine' : 9,*
* 'gin': None}*
*Output:*
*1 3 9*
Here is my solution , Please review the below code and let me know your
suggestion .
#/usr/bin/python
o_num = {'one': 1,
'three': 3,
'bar': None,
'five' : 5,
'rum' : None,
'seven' : None,
'brandy': None,
'nine' : 9,
'gin': None}
args_list = ["one","three","seven","nine"]
args_dict = dict( (k,v) for k, v in o_num.items() if v and k in args_list )
print args_dict
o/p:
root@X1:/Play_ground/DICT# python hello.py
{'nine': 9, 'three': 3, 'one': 1}
Also, Is unpacking the elements in the o_num dictionary as shown below
fine or are there any other alternatives
arg1, arg2, arg3, arg4, = map(args_dict.get, ('one', 'three', 'seven',
'nine'))
print arg1, arg2, arg3, arg4
I am a Python 2.7 user and on Linux box
Regards,
Ganesh
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Re: For specific keys , extract non empty values in a dictionary
Ganesh Pal wrote:
> *How do I check few specific/selected keys in a dictionary and extract
> their values if they are not empty*
You mean not None.
> o_num = {'one': 1,
> 'three': 3,
> 'bar': None,
> 'five' : 5,
> 'rum' : None,
> 'seven' : None,
> 'brandy': None,
> 'nine' : 9,
> 'gin': None}
> args_list = ["one","three","seven","nine"]
> *Output:*
>
> *1 3 9*
>>> wanted = {"one", "three", "seven", "nine"}
>>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
{'one': 1, 'nine': 9, 'three': 3}
> I am a Python 2.7 user and on Linux box
You have to replace keys() with viewkeys() in Python 2.
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Re: For specific keys , extract non empty values in a dictionary
> >>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
Thanks peter this looks better , except that I will need to use the
logial 'and' operator or else I will get a TypeError
>>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
TypeError: unsupported operand type(s) for &: 'set' and 'list'
Example :
>>>print {k: o_num[k] for k in wanted and o_num.keys() if o_num[k] is not
None}
{'nine': 9, 'five': 5, 'three': 3, 'one': 1}
On Sat, Jun 16, 2018 at 11:12 PM, Peter Otten <__pete...@web.de> wrote:
> Ganesh Pal wrote:
>
> > *How do I check few specific/selected keys in a dictionary and extract
> > their values if they are not empty*
>
> You mean not None.
>
> > o_num = {'one': 1,
> > 'three': 3,
> > 'bar': None,
> > 'five' : 5,
> > 'rum' : None,
> > 'seven' : None,
> > 'brandy': None,
> > 'nine' : 9,
> > 'gin': None}
>
> > args_list = ["one","three","seven","nine"]
>
> > *Output:*
> >
> > *1 3 9*
>
> >>> wanted = {"one", "three", "seven", "nine"}
> >>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
> {'one': 1, 'nine': 9, 'three': 3}
>
> > I am a Python 2.7 user and on Linux box
>
> You have to replace keys() with viewkeys() in Python 2.
>
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>
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Re: For specific keys , extract non empty values in a dictionary
On 2018-06-17 15:47, Ganesh Pal wrote:
>>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
Thanks peter this looks better , except that I will need to use the
logial 'and' operator or else I will get a TypeError
{k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
TypeError: unsupported operand type(s) for &: 'set' and 'list'
Peter said that you need to use viewkeys() instead of keys() in Python 2:
>>> {k: o_num[k] for k in wanted & o_num.viewkeys() if o_num[k] is not
None}
Using 'and' instead won't give the correct result.
Example :
print {k: o_num[k] for k in wanted and o_num.keys() if o_num[k] is not
None}
{'nine': 9, 'five': 5, 'three': 3, 'one': 1}
On Sat, Jun 16, 2018 at 11:12 PM, Peter Otten <__pete...@web.de> wrote:
Ganesh Pal wrote:
> *How do I check few specific/selected keys in a dictionary and extract
> their values if they are not empty*
You mean not None.
> o_num = {'one': 1,
> 'three': 3,
> 'bar': None,
> 'five' : 5,
> 'rum' : None,
> 'seven' : None,
> 'brandy': None,
> 'nine' : 9,
> 'gin': None}
> args_list = ["one","three","seven","nine"]
> *Output:*
>
> *1 3 9*
>>> wanted = {"one", "three", "seven", "nine"}
>>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
{'one': 1, 'nine': 9, 'three': 3}
> I am a Python 2.7 user and on Linux box
You have to replace keys() with viewkeys() in Python 2.
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Re: For specific keys , extract non empty values in a dictionary
Dennis Lee Bieber wrote:
> On Sun, 17 Jun 2018 17:37:25 +0100, MRAB
> declaimed the following:
>
>>On 2018-06-17 15:47, Ganesh Pal wrote:
>>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not
>>> {None}
>>>
>>> Thanks peter this looks better , except that I will need to use the
>>> logial 'and' operator or else I will get a TypeError
>>>
>> {k: o_num[k] for k in wanted & o_num.keys() if o_num[k] is not None}
>>>
>>> TypeError: unsupported operand type(s) for &: 'set' and 'list'
>>>
>>Peter said that you need to use viewkeys() instead of keys() in Python 2:
>>
>> >>> {k: o_num[k] for k in wanted & o_num.viewkeys() if o_num[k] is not
>>None}
>>
>
> What's wrong with the simple
>
o_num = { "one" : 1,
> ... "three" : 3,
> ... "bar" : None,
> ... "five" : 5,
> ... "rum" : None,
> ... "seven" : None,
> ... "brandy" : None,
> ... "nine" : 9,
> ... "gin" : None}
args_list = [ "one", "three", "seven", "nine" ]
{ k : o_num[k] for k in args_list if o_num.get(k, None) is not None }
> {'nine': 9, 'three': 3, 'one': 1}
It's hidden here because of the removal of None values, but in the generic
case when you say
"give me all x in a that are also in b"
instead of
"give me the intersection of a and b"
you are overspecifying the problem.
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