[R] Path analysis

2015-05-26 Thread Alberto Canarini
Hi there,

As I'm approaching path analysis I was wondering which packages may suite a 
path analysis for my data. My data are on interaction of soil biotic and 
abiotic factor, like microbial biomass carbon, soil carbon, water content, 
temperature etc.

Thanks in advance,

Best regards.

Alberto

Alberto Canarini
PhD Student l Faculty of Agriculture and Environment
THE UNIVERSITY OF SYDNEY
Shared room l CCWF l Camden Campus l NSW 2570
P 02 935 11892


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Re: [R] Path analysis

2015-05-26 Thread John Fox
Dear Alberto,

There are several R packages available on CRAN for structural equation 
modeling: sem, lavaan, and OpenMx come immediately to mind. If your model is 
recursive with only observed variables, then you could just use lm(). If your 
model is nonrecursive with only observed variables, then you could also use the 
systemfit package.

I hope this helps,
 John


John Fox, Professor
McMaster University
Hamilton, Ontario, Canada
http://socserv.mcmaster.ca/jfox/



On Tue, 26 May 2015 05:43:47 +
 Alberto Canarini alberto.canar...@sydney.edu.au wrote:
 Hi there,
 
 As I'm approaching path analysis I was wondering which packages may suite a 
 path analysis for my data. My data are on interaction of soil biotic and 
 abiotic factor, like microbial biomass carbon, soil carbon, water content, 
 temperature etc.
 
 Thanks in advance,
 
 Best regards.
 
 Alberto
 
 Alberto Canarini
 PhD Student l Faculty of Agriculture and Environment
 THE UNIVERSITY OF SYDNEY
 Shared room l CCWF l Camden Campus l NSW 2570
 P 02 935 11892
 
 
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Re: [R] Path analysis

2015-05-26 Thread Charles Determan
Given that your problem primarily focuses on a biological context you
probably would have better luck with bioconductor (www.bioconductor.org).

Regards,
Charles

On Tue, May 26, 2015 at 12:43 AM, Alberto Canarini 
alberto.canar...@sydney.edu.au wrote:

 Hi there,

 As I'm approaching path analysis I was wondering which packages may suite
 a path analysis for my data. My data are on interaction of soil biotic and
 abiotic factor, like microbial biomass carbon, soil carbon, water content,
 temperature etc.

 Thanks in advance,

 Best regards.

 Alberto

 Alberto Canarini
 PhD Student l Faculty of Agriculture and Environment
 THE UNIVERSITY OF SYDNEY
 Shared room l CCWF l Camden Campus l NSW 2570
 P 02 935 11892


 [[alternative HTML version deleted]]

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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


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Re: [R] Path Analysis

2013-11-05 Thread Sarah Rogers
Dear John,
Thanks for your help. I run the path analysis but the model does not fit
the data. I am in doubt if this reflects the model construction et al. (too
many variables or more needed, more paths or change in direction of paths,
sample size, etc) or it could be that there is an error-variance
I have all observed data (fully recursive model), two exogenous variables
(with no variance or covariance parameters), four exogenous variables, and
for the final sem() model I used data argument instead of a moment matrix
with the covariance symmetric matrix. What would you suggest to be the best
way to investigate this in R?
Here attached the script and results:

library(sem)
model.xdata-specifyEquations()

y1=xy21*x2
y2=xy12*x1 + yy12*y1
y3=yy23*y2
y4=yy24*y2+yy34*y3

model.xdata.sem - sem(model.xdata, data=xdata, fixed.x=c(x1, x2) )
summary(model.xdata.sem,fit.indices=c(CFI,NFI, GFI, RMSEA, AGFI,
NNFI, SRMR))

Model Chisquare =  41.03029   Df =  8 Pr(Chisq) = 2.057595e-06
Goodness-of-fit index =  0.8604332
 Adjusted goodness-of-fit index =  0.6336373
 RMSEA index =  0.2330797   90% CI: (0.1654494, 0.3060134)
Bentler-Bonett NFI =  0.4290901
 Tucker-Lewis NNFI =  -0.08903999
 Bentler CFI =  0.4191787
 SRMR =  0.1472905

 Normalized Residuals
Min.  1st Qu.   Median Mean  3rd Qu. Max.
-3.91600 -0.60120  0.0 -0.09444  0.13940  2.71400

 R-square for Endogenous Variables
y1 y2 y3 y4
0.0009 0.1890 0.0019 0.1558

 Parameter Estimates
  Estimate  Std Errorz value Pr(|z|)
xy210.017817121  0.066762981  0.26687127 7.895683e-01 y1 --- x2
xy12   -0.030928721  0.007447431 -4.15293810 3.282335e-05 y2 --- x1
yy120.311216816  0.475353649  0.65470585 5.126572e-01 y2 --- y1
yy23   -0.077701789  0.203130269 -0.38252196 7.020742e-01 y3 --- y2
yy240.002539283  0.031323241  0.08106706 9.353886e-01 y4 --- y2
yy340.066168523  0.017671263  3.74441396 1.808153e-04 y4 --- y3
V[y1]   1.945406949  0.315586680  6.16441400 7.074463e-10 y1 -- y1
V[y2]  33.438573159  5.424452858  6.16441400 7.074463e-10 y2 -- y2
V[y3] 129.295382082 20.974480627  6.16441400 7.074463e-10 y3 -- y3
V[y4]   3.068539923  0.497782907  6.16441400 7.074463e-10 y4 -- y4




On 2 November 2013 19:48, John Fox j...@mcmaster.ca wrote:

 Dear Sarah,

 It's generally a good idea to include a reproducible example if you want
 to get help with a problem, but in this case it's a safe bet that the
 problem is that the model you specified has no variance or covariance
 parameters for the variables x1 and x2, which, I assume, you mean to be
 exogenous. The easiest way to include these variances and covariance in the
 model is to specify the argument fixed.x=c(x1, x2) in the call to sem().

 In addition:

 (1) Your model is fully recursive (guessing that all the x's and y's are
 observed variables), and so it amounts to four OLS regressions. You could
 just use lm() to fit the model.

 (2) It's generally easier in the sem package to use specifyEquations()
 than specifyModel() for model specification.

 (3) If you have the original data set, as you do, it's generally
 preferable to use the data argument to sem() than to pass it the covariance
 matrix for the observed variables.

 I hope that this helps,
  John


 
 John Fox
 McMaster University
 Hamilton, Ontario, Canada
 http://socserv.mcmaster.ca/jfox/

 On Sat, 2 Nov 2013 11:02:31 +0100
  Sarah Rogers rogerssara...@gmail.com wrote:
   Hello,
 
  I have just started to work on a path analysis (see attached image for
 the
  diagram), but I have encountered an error message.
 
 
 
 
  This is the code I have used:
 
  cov_matrix-var(xdata)
 
  library(sem)
  model.xdata-specifyModel()
  x1 - y2, xy12, NA
  x2 - y1, xy21, NA
  y1 - y2, yy12, NA
  y2 - y3, yy23, NA
  y2 - y4, yy24, NA
  y3 - y4, yy34, NA
  y2 - y2, y2error, NA
  y1 - y1, y1error, NA
  y3 - y3, y3error, NA
  y4 - y4, y4error, NA
 
  model.xdata.sem - sem(model.xdata, cov_matrix, nrow(xdata))
 
  and the error message is:
  Error in csem(model = model.description, start, opt.flag = 1, typsize =
  typsize,  :
The matrix is non-invertable.
 
  I fear to have a problem in the data.
  I would be very grateful if you could help me to solve this problem and
  proceed with my analyses.
 
  thank you in advance for your help!
  Sarah
 
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Re: [R] Path Analysis

2013-11-05 Thread John Fox
Dear Sarah,

As you know, our discussion continued off-list, and I'm glad that you were
able to get the software to work.

I'll address your question briefly, but what I have to say probably isn't
what you want to hear:

Most fundamentally, the information you've provided is entirely without
content. That is, variable names like x1 and y1 convey no information about
the substance of the data. It's therefore impossible to know whether the
model that you specified is sensible. I think that you'd do much better to
seek competent statistical help locally than to ask questions on an email
list devoted to statistical software.

That said, you've specified a very restrictive model for the data. You could
add 8 paths to the model and still have a fully recursive model. For
example, your model specifies that x2 can only influence y4 indirectly
through y1. If you've carefully specified the model and believe, for
example, that the missing paths are implausible, that x1 and x2 are really
exogenous, and that all of the disturbances are uncorrelated, then the
correct conclusion is that your model is wrong. You could try adding the
missing paths to the model, but if you're willing to do this that would
suggest that you didn't think carefully enough about the specification in
the first place. In my opinion, structural-equation modeling shouldn't be
regarded as an exploratory method.

Of course, in a very large sample, an overidentified model that's trivially
wrong can be rejected when tested as a hypothesis. I don't know how large
your sample is, but the various fit indices are not encouraging. Your
model isn't just trivially wrong. Moreover, the R^2s for the endogenous
variable are very small -- two are effectively 0.

I can't judge whether your model makes any sense, but it's my impression
that most structural equation models don't. People often think that SEMs are
magic wands that can be waved over observational data to draw causal
inferences, even when the assumptions underlying the model, such as
exogeneity, are implausible, and without attending to aspects of the model,
such as potential nonlinearity, that should be part of careful regression
modeling.

My two cents,
 John

 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
 project.org] On Behalf Of Sarah Rogers
 Sent: Tuesday, November 05, 2013 8:45 AM
 To: r-help@r-project.org
 Cc: John Fox
 Subject: Re: [R] Path Analysis
 
 Dear John,
 Thanks for your help. I run the path analysis but the model does not
 fit
 the data. I am in doubt if this reflects the model construction et al.
 (too
 many variables or more needed, more paths or change in direction of
 paths,
 sample size, etc) or it could be that there is an error-variance
 I have all observed data (fully recursive model), two exogenous
 variables
 (with no variance or covariance parameters), four exogenous variables,
 and
 for the final sem() model I used data argument instead of a moment
 matrix
 with the covariance symmetric matrix. What would you suggest to be the
 best
 way to investigate this in R?
 Here attached the script and results:
 
 library(sem)
 model.xdata-specifyEquations()
 
 y1=xy21*x2
 y2=xy12*x1 + yy12*y1
 y3=yy23*y2
 y4=yy24*y2+yy34*y3
 
 model.xdata.sem - sem(model.xdata, data=xdata, fixed.x=c(x1, x2) )
 summary(model.xdata.sem,fit.indices=c(CFI,NFI, GFI, RMSEA,
 AGFI,
 NNFI, SRMR))
 
 Model Chisquare =  41.03029   Df =  8 Pr(Chisq) = 2.057595e-06
 Goodness-of-fit index =  0.8604332
  Adjusted goodness-of-fit index =  0.6336373
  RMSEA index =  0.2330797   90% CI: (0.1654494, 0.3060134)
 Bentler-Bonett NFI =  0.4290901
  Tucker-Lewis NNFI =  -0.08903999
  Bentler CFI =  0.4191787
  SRMR =  0.1472905
 
  Normalized Residuals
 Min.  1st Qu.   Median Mean  3rd Qu. Max.
 -3.91600 -0.60120  0.0 -0.09444  0.13940  2.71400
 
  R-square for Endogenous Variables
 y1 y2 y3 y4
 0.0009 0.1890 0.0019 0.1558
 
  Parameter Estimates
   Estimate  Std Errorz value Pr(|z|)
 xy210.017817121  0.066762981  0.26687127 7.895683e-01 y1 --- x2
 xy12   -0.030928721  0.007447431 -4.15293810 3.282335e-05 y2 --- x1
 yy120.311216816  0.475353649  0.65470585 5.126572e-01 y2 --- y1
 yy23   -0.077701789  0.203130269 -0.38252196 7.020742e-01 y3 --- y2
 yy240.002539283  0.031323241  0.08106706 9.353886e-01 y4 --- y2
 yy340.066168523  0.017671263  3.74441396 1.808153e-04 y4 --- y3
 V[y1]   1.945406949  0.315586680  6.16441400 7.074463e-10 y1 -- y1
 V[y2]  33.438573159  5.424452858  6.16441400 7.074463e-10 y2 -- y2
 V[y3] 129.295382082 20.974480627  6.16441400 7.074463e-10 y3 -- y3
 V[y4]   3.068539923  0.497782907  6.16441400 7.074463e-10 y4 -- y4
 
 
 
 
 On 2 November 2013 19:48, John Fox j...@mcmaster.ca wrote:
 
  Dear Sarah,
 
  It's generally a good idea to include a reproducible example if you
 want
  to get help with a problem, but in this case it's a safe bet that the
  problem is that the model you specified has

[R] Path Analysis

2013-11-02 Thread Sarah Rogers
 Hello,

I have just started to work on a path analysis (see attached image for the
diagram), but I have encountered an error message.




This is the code I have used:

cov_matrix-var(xdata)

library(sem)
model.xdata-specifyModel()
x1 - y2, xy12, NA
x2 - y1, xy21, NA
y1 - y2, yy12, NA
y2 - y3, yy23, NA
y2 - y4, yy24, NA
y3 - y4, yy34, NA
y2 - y2, y2error, NA
y1 - y1, y1error, NA
y3 - y3, y3error, NA
y4 - y4, y4error, NA

model.xdata.sem - sem(model.xdata, cov_matrix, nrow(xdata))

and the error message is:
Error in csem(model = model.description, start, opt.flag = 1, typsize =
typsize,  :
  The matrix is non-invertable.

I fear to have a problem in the data.
I would be very grateful if you could help me to solve this problem and
proceed with my analyses.

thank you in advance for your help!
Sarah

[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Path Analysis

2013-11-02 Thread John Fox
Dear Sarah,

It's generally a good idea to include a reproducible example if you want to get 
help with a problem, but in this case it's a safe bet that the problem is that 
the model you specified has no variance or covariance parameters for the 
variables x1 and x2, which, I assume, you mean to be exogenous. The easiest way 
to include these variances and covariance in the model is to specify the 
argument fixed.x=c(x1, x2) in the call to sem().

In addition:

(1) Your model is fully recursive (guessing that all the x's and y's are 
observed variables), and so it amounts to four OLS regressions. You could just 
use lm() to fit the model.

(2) It's generally easier in the sem package to use specifyEquations() than 
specifyModel() for model specification.

(3) If you have the original data set, as you do, it's generally preferable to 
use the data argument to sem() than to pass it the covariance matrix for the 
observed variables.

I hope that this helps,
 John



John Fox
McMaster University
Hamilton, Ontario, Canada
http://socserv.mcmaster.ca/jfox/

On Sat, 2 Nov 2013 11:02:31 +0100
 Sarah Rogers rogerssara...@gmail.com wrote:
  Hello,
 
 I have just started to work on a path analysis (see attached image for the
 diagram), but I have encountered an error message.
 
 
 
 
 This is the code I have used:
 
 cov_matrix-var(xdata)
 
 library(sem)
 model.xdata-specifyModel()
 x1 - y2, xy12, NA
 x2 - y1, xy21, NA
 y1 - y2, yy12, NA
 y2 - y3, yy23, NA
 y2 - y4, yy24, NA
 y3 - y4, yy34, NA
 y2 - y2, y2error, NA
 y1 - y1, y1error, NA
 y3 - y3, y3error, NA
 y4 - y4, y4error, NA
 
 model.xdata.sem - sem(model.xdata, cov_matrix, nrow(xdata))
 
 and the error message is:
 Error in csem(model = model.description, start, opt.flag = 1, typsize =
 typsize,  :
   The matrix is non-invertable.
 
 I fear to have a problem in the data.
 I would be very grateful if you could help me to solve this problem and
 proceed with my analyses.
 
 thank you in advance for your help!
 Sarah
 
   [[alternative HTML version deleted]]
 
 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
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[R] path analysis

2012-12-25 Thread Ali Mahmoudi
What's the function of 'path analysis ' to do it with R?
Please help me.Thanks.
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Re: [R] path analysis

2012-12-25 Thread Pascal Oettli

First, hello,

Second, http://r.789695.n4.nabble.com/path-analysis-td2528558.html#a2530207

Last, Regards

Le 26/12/2012 04:11, Ali Mahmoudi a écrit :

What's the function of 'path analysis ' to do it with R?
Please help me.Thanks.
[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.



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and provide commented, minimal, self-contained, reproducible code.


[R] path analysis help

2012-08-30 Thread Jinsong Zhao

Hi there,

I searched R-help list with path analysis as keyword, and learn that 
sem package can do it. However, I don't figure out a way to construct 
the model for the path diagram as Fig. 1. in Huang et al. (2002)[1].


I try the following code:

huang.cor - readMoments(diag=FALSE, names=c('x1', 'x2', 'x3', 'y'))
0.76
0.91 0.72
0.94 0.77 0.83

huang.mod - specifyModel()
x1 - y, p1
x2 - y, p2
x3 - y, p3
x1 - x2, p12
x2 - x1, p21
x2 - x3, p23
x3 - x2, p32
x1 - x3, p13
x3 - x1, p31

huang.sem - sem(huang.mod, huang.cor, 100)# 100 is arbitarious.

It give the error message:

Error in sem.default(ram, S = S, N = N, raw = raw, data = data, 
param.names = pars,  :

  The model has negative degrees of freedom = -3

I don't know why.

I hope to get direct effect, indirect effect and total effects for every 
variable. However, I don't figure out how to do with sem package. It 
there any other package that can do it?


Any suggestion or hint will be greatly appreciated.

Regards,
Jinsong


[1] Huang, B., Thornhill, N., Shah, S. and Shook, D. (2002). Path 
analysis for process troubleshooting. Proceedings of Advanced Control of 
Industrial Processes, Kumamoto, Japan, 10–12 June, 149–154.

url: http://eprints.ucl.ac.uk/494/1/HuangEtAl_AdConIP_2002.pdf

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Re: [R] path analysis help

2012-08-30 Thread John Fox
Dear Jinsong,

This model is grossly underidentified because there are no exogenous
variables in it. Your inability to estimate the model isn't a software
issue.

Best,
 John

---
John Fox
Senator McMaster Professor of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada



 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 On Behalf Of Jinsong Zhao
 Sent: Thursday, August 30, 2012 10:47 AM
 To: r-help@r-project.org
 Subject: [R] path analysis help
 
 Hi there,
 
 I searched R-help list with path analysis as keyword, and learn that
 sem package can do it. However, I don't figure out a way to construct
 the model for the path diagram as Fig. 1. in Huang et al. (2002)[1].
 
 I try the following code:
 
 huang.cor - readMoments(diag=FALSE, names=c('x1', 'x2', 'x3', 'y'))
 0.76
 0.91 0.72
 0.94 0.77 0.83
 
 huang.mod - specifyModel()
 x1 - y, p1
 x2 - y, p2
 x3 - y, p3
 x1 - x2, p12
 x2 - x1, p21
 x2 - x3, p23
 x3 - x2, p32
 x1 - x3, p13
 x3 - x1, p31
 
 huang.sem - sem(huang.mod, huang.cor, 100)# 100 is arbitarious.
 
 It give the error message:
 
 Error in sem.default(ram, S = S, N = N, raw = raw, data = data,
 param.names = pars,  :
The model has negative degrees of freedom = -3
 
 I don't know why.
 
 I hope to get direct effect, indirect effect and total effects for every
 variable. However, I don't figure out how to do with sem package. It
 there any other package that can do it?
 
 Any suggestion or hint will be greatly appreciated.
 
 Regards,
 Jinsong
 
 
 [1] Huang, B., Thornhill, N., Shah, S. and Shook, D. (2002). Path
 analysis for process troubleshooting. Proceedings of Advanced Control of
 Industrial Processes, Kumamoto, Japan, 10-12 June, 149-154.
 url: http://eprints.ucl.ac.uk/494/1/HuangEtAl_AdConIP_2002.pdf
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] path analysis and diagram (structural model)

2012-05-26 Thread Kristi Glover

Hi R- USER,
I have been struggling to compute path analysis in R. I installed package sem 
and I tried to run the analysis but could not get a diagram. 

I have very big data set, here I just copied a sample of my data and I wanted 
to see how I can do the path analysis and get the patch diagram (with r2 in 
each path). 

I have two tables;  1: num. of species - which is the depended variable and 2. 
env is the independent(predictors)  variable. 

I was trying to do multiple regression (num. of species vs env) and trying to 
see the path diagram (structural model). But I could not do it.

would you help me on how I can perform the analysis and show in diagram of the 
model?

dput(env)
structure(list(preci = c(45.145, 38.501, 32.631, 38.392, 44.807, 
45.774, 46.917, 44.384), wind = c(90L, 113L, 127L, 63L, 54L, 
43L, 31L, 38L), radiation = c(11.805, 18.31, 19.381, 13.154, 
9.752, 7.075, 5.558, 7.616), temp = c(12L, 15L, 21L, 20L, 14L, 
18L, 21L, 18L)), .Names = c(preci, wind, radiation, temp
), class = data.frame, row.names = c(NA, -8L))

dput(num.of.species)
structure(list(S = c(4L, 7L, 9L, 10L, 10L, 8L, 8L, 1L)), .Names = S, class = 
data.frame, row.names = c(NA, 
-8L))

Sincerely,

Kristi

  
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[R] Path analysis with logistic regression

2010-10-27 Thread Mohamed Lajnef
Dear all,

I would like to make a path analysis after retrieving relevant variables 
(continuous or binary) after logistic regression.

So I try to model the dependent variable (0/1)  based on the significant 
predictors using path analysis

Could you tell me if there is a suitable package in R to do this?

Any help would be appreciated

Regards

-- 

Mohamed Lajnef,IE INSERM U955 eq 15#
Pôle de Psychiatrie#
Hôpital CHENEVIER  #
40, rue Mesly  #
94010 CRETEIL Cedex FRANCE #
mohamed.laj...@inserm.fr   #
tel : 01 49 81 31 31 (poste 18467) #
Sec : 01 49 81 32 90   #
fax : 01 49 81 30 99   #




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Re: [R] path analysis

2010-09-07 Thread JLucke
There are three paths to path analysis in R:  the SEM package; the LAVAAN 
package; and the OpenMx approach.  The first two are R programs.  The last 
accesses the program OpenMx. 




Guy rotem rottem...@gmail.com 
Sent by: r-help-boun...@r-project.org
09/06/2010 10:37 AM

To
r-help@r-project.org
cc

Subject
[R] path analysis






Hi.

which package i need to install to be able to run Path analysis using r?

many thanks, Guy

-- 
Guy Rotem
Department of Life Sciences
The Spatial Ecology Lab
Ben Gurion University of the Negev
P.O.B. 653   Beer-Sheva 84105
ISRAEL

+972-52-3354485 (mobile)
+972-8-6461350 (lab)

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Re: [R] path analysis

2010-09-07 Thread Mark Difford

Guy,

For a partial least squares approach look at packages plspm and pathmox.
Also look at sem.additions.

Regards, Mark.
-- 
View this message in context: 
http://r.789695.n4.nabble.com/path-analysis-tp2528558p2530207.html
Sent from the R help mailing list archive at Nabble.com.

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[R] path analysis

2010-09-06 Thread Guy rotem
Hi.

which package i need to install to be able to run Path analysis using r?

many thanks, Guy

-- 
Guy Rotem
Department of Life Sciences
The Spatial Ecology Lab
Ben Gurion University of the Negev
P.O.B. 653   Beer-Sheva 84105
ISRAEL

+972-52-3354485 (mobile)
+972-8-6461350 (lab)

[[alternative HTML version deleted]]

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Re: [R] path analysis

2010-09-06 Thread Sarah Goslee
There are lots of options for path analysis in R.

If you go to http://www.rseek.org and type path analysis into the search box,
you will get lots of information on functions/packages, and more general
info as well.

Beyond that, we'd need more specifics about your task.

Sarah

On Mon, Sep 6, 2010 at 10:37 AM, Guy rotem rottem...@gmail.com wrote:
 Hi.

 which package i need to install to be able to run Path analysis using r?

 many thanks, Guy



-- 
Sarah Goslee
http://www.functionaldiversity.org

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[R] Path Analysis

2010-05-24 Thread R Help
Hello list,

I'm trying to make sure that I'm performing a path analysis correctly
using the sem package.  the figure at
http://flame.cs.dal.ca/~sstewart/regressDiag.png has a detailing of
the model.

The challenge I'm having is that reuse is an indicator (0/1) variable.

Here's the code I'm using:

corr = 
hetcor(dat[,c('intent','exposure','benefit','norms','childBarrier','parentBarrier','knowBenefit','recuse')],use=pairwise.complete.obs)$correlations
modMat = matrix(c(
  'exposure - intent', 'gam11',NA,
  'benefit - intent', 'gam12',NA,
  'norms - intent', 'gam13',NA,
  'childBarrier - intent', 'gam14',NA,
  'parentBarrier - intent', 'gam15',NA,
  'knowBenefit - intent', 'gam16',NA,
  'intent-intent','psi11',NA,
  'intent-recuse','gam21',NA,
  'recuse-recuse','psi22',NA),
  ncol=3,byrow=T)
model4 = 
sem(modMat,corr,N=1520,fixed.x=c('exposure','benefit','norms','childBarrier','parentBarrier','knowBenefit'))

Is this correctly modeling my diagram?  I'm not sure if a) I'm dealing
with the categorical variable correctly, or b) whether fixed.x is
accurately modeling the correlations for me.

Any help would be appreciated.  I'm also looking into creating a plot
function within R (similar to the path.diagram function, but using R
plots).  If I get something useful I'll try and post it back

__
R-help@r-project.org mailing list
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Path Analysis

2010-05-24 Thread John Fox
Dear sstewart,

The model appears to reflect the path diagram, assuming that you intend to
allow the exogenous variables to be correlated and want the errors to be
uncorrelated. 

This is one way to model the binary variable reuse. An alternative would be
to fit the equation for intent by least-squares regression (assuming that
the relationships are linear, etc.), and the equation of reuse by, e.g.,
logistic regression (again assuming that the model is correctly specified).
If you're right that the effects of the exogenous variables are entirely
mediated by intent, then if you put these variables in the equation for
reuse, their coefficients should be small.

I hope this helps,
 John 


John Fox
Senator William McMaster 
  Professor of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web: socserv.mcmaster.ca/jfox


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
 Behalf Of R Help
 Sent: May-24-10 11:18 AM
 To: r-help
 Subject: [R] Path Analysis
 
 Hello list,
 
 I'm trying to make sure that I'm performing a path analysis correctly
 using the sem package.  the figure at
 http://flame.cs.dal.ca/~sstewart/regressDiag.png has a detailing of
 the model.
 
 The challenge I'm having is that reuse is an indicator (0/1) variable.
 
 Here's the code I'm using:
 
 corr =

hetcor(dat[,c('intent','exposure','benefit','norms','childBarrier','parentBa
r
 rier','knowBenefit','recuse')],use=pairwise.complete.obs)$correlations
 modMat = matrix(c(
   'exposure - intent', 'gam11',NA,
   'benefit - intent', 'gam12',NA,
   'norms - intent', 'gam13',NA,
   'childBarrier - intent', 'gam14',NA,
   'parentBarrier - intent', 'gam15',NA,
   'knowBenefit - intent', 'gam16',NA,
   'intent-intent','psi11',NA,
   'intent-recuse','gam21',NA,
   'recuse-recuse','psi22',NA),
   ncol=3,byrow=T)
 model4 =

sem(modMat,corr,N=1520,fixed.x=c('exposure','benefit','norms','childBarrier'
,
 'parentBarrier','knowBenefit'))
 
 Is this correctly modeling my diagram?  I'm not sure if a) I'm dealing
 with the categorical variable correctly, or b) whether fixed.x is
 accurately modeling the correlations for me.
 
 Any help would be appreciated.  I'm also looking into creating a plot
 function within R (similar to the path.diagram function, but using R
 plots).  If I get something useful I'll try and post it back
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Path Analysis

2010-05-24 Thread R Help
That's an interesting idea, I got the same impression from your SEM
appendix to Companion to applied regression in the paragraph just
before Section 3.

So I could get the same results if I built the following two models:

mod1 = 
lm(intent~exposure+benefit+norms+childBarrier+parentBarrier+knowBenefit,data=dat)
mod2 = 
glm(recuse~intent+norms+exposure+childBarrier+parentBarrier,data=dat,family=binomial(link=logit))

And in the second model only the intent should have a significant coefficient?

When I run those models I get a number of significant findings in the
mod2.  Does that mean that I have mis-specified my model?  If so (and
I think I have), can I postulate that there is a link between each
significant coefficient?

Thanks so much for your input,
Sam Stewart


 summary(mod2)

Call:
glm(formula = recuse ~ intent + norms + exposure + childBarrier +
parentBarrier, family = binomial(link = logit), data = dat)

Deviance Residuals:
Min   1Q   Median   3Q  Max
-2.2784  -0.9018   0.5899   0.7686   1.9314

Coefficients:
  Estimate Std. Error z value Pr(|z|)
(Intercept)   -2.512690.50359  -4.990 6.05e-07 ***
intent 0.595740.08345   7.139 9.39e-13 ***
norms  0.238220.02991   7.964 1.67e-15 ***
exposure   0.125220.08613   1.454 0.145981
childBarrier  -0.312960.08693  -3.600 0.000318 ***
parentBarrier -0.234000.08676  -2.697 0.006995 **
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

(Dispersion parameter for binomial family taken to be 1)

Null deviance: 1803.0  on 1479  degrees of freedom
Residual deviance: 1567.8  on 1474  degrees of freedom
  (40 observations deleted due to missingness)
AIC: 1579.8

Number of Fisher Scoring iterations: 4

On Mon, May 24, 2010 at 1:17 PM, John Fox j...@mcmaster.ca wrote:
 Dear sstewart,

 The model appears to reflect the path diagram, assuming that you intend to
 allow the exogenous variables to be correlated and want the errors to be
 uncorrelated.

 This is one way to model the binary variable reuse. An alternative would be
 to fit the equation for intent by least-squares regression (assuming that
 the relationships are linear, etc.), and the equation of reuse by, e.g.,
 logistic regression (again assuming that the model is correctly specified).
 If you're right that the effects of the exogenous variables are entirely
 mediated by intent, then if you put these variables in the equation for
 reuse, their coefficients should be small.

 I hope this helps,
  John

 
 John Fox
 Senator William McMaster
  Professor of Social Statistics
 Department of Sociology
 McMaster University
 Hamilton, Ontario, Canada
 web: socserv.mcmaster.ca/jfox


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 On
 Behalf Of R Help
 Sent: May-24-10 11:18 AM
 To: r-help
 Subject: [R] Path Analysis

 Hello list,

 I'm trying to make sure that I'm performing a path analysis correctly
 using the sem package.  the figure at
 http://flame.cs.dal.ca/~sstewart/regressDiag.png has a detailing of
 the model.

 The challenge I'm having is that reuse is an indicator (0/1) variable.

 Here's the code I'm using:

 corr =

 hetcor(dat[,c('intent','exposure','benefit','norms','childBarrier','parentBa
 r
 rier','knowBenefit','recuse')],use=pairwise.complete.obs)$correlations
 modMat = matrix(c(
   'exposure - intent', 'gam11',NA,
   'benefit - intent', 'gam12',NA,
   'norms - intent', 'gam13',NA,
   'childBarrier - intent', 'gam14',NA,
   'parentBarrier - intent', 'gam15',NA,
   'knowBenefit - intent', 'gam16',NA,
   'intent-intent','psi11',NA,
   'intent-recuse','gam21',NA,
   'recuse-recuse','psi22',NA),
   ncol=3,byrow=T)
 model4 =

 sem(modMat,corr,N=1520,fixed.x=c('exposure','benefit','norms','childBarrier'
 ,
 'parentBarrier','knowBenefit'))

 Is this correctly modeling my diagram?  I'm not sure if a) I'm dealing
 with the categorical variable correctly, or b) whether fixed.x is
 accurately modeling the correlations for me.

 Any help would be appreciated.  I'm also looking into creating a plot
 function within R (similar to the path.diagram function, but using R
 plots).  If I get something useful I'll try and post it back

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Path Analysis

2010-05-24 Thread John Fox
Dear Sam,

 -Original Message-
 From: R Help [mailto:rhelp.st...@gmail.com]
 Sent: May-24-10 1:04 PM
 To: John Fox
 Cc: r-help
 Subject: Re: [R] Path Analysis
 
 That's an interesting idea, I got the same impression from your SEM
 appendix to Companion to applied regression in the paragraph just
 before Section 3.
 
 So I could get the same results if I built the following two models:

Not really the same results, but the models are similar.

 
 mod1 =

lm(intent~exposure+benefit+norms+childBarrier+parentBarrier+knowBenefit,data
=
 dat)
 mod2 =

glm(recuse~intent+norms+exposure+childBarrier+parentBarrier,data=dat,family=
b
 inomial(link=logit))
 
 And in the second model only the intent should have a significant
 coefficient?

Yes, if you're right that the effects of the other variables are entirely
mediated by intent.

 
 When I run those models I get a number of significant findings in the
 mod2.  Does that mean that I have mis-specified my model?  If so (and
 I think I have), can I postulate that there is a link between each
 significant coefficient?

With the usual caveats about significance and interpreting regressions
causally, large coefficients for the other variables suggests that their
effects are not wholly mediated by intent.

Best,
 John

 
 Thanks so much for your input,
 Sam Stewart
 
 
  summary(mod2)
 
 Call:
 glm(formula = recuse ~ intent + norms + exposure + childBarrier +
 parentBarrier, family = binomial(link = logit), data = dat)
 
 Deviance Residuals:
 Min   1Q   Median   3Q  Max
 -2.2784  -0.9018   0.5899   0.7686   1.9314
 
 Coefficients:
   Estimate Std. Error z value Pr(|z|)
 (Intercept)   -2.512690.50359  -4.990 6.05e-07 ***
 intent 0.595740.08345   7.139 9.39e-13 ***
 norms  0.238220.02991   7.964 1.67e-15 ***
 exposure   0.125220.08613   1.454 0.145981
 childBarrier  -0.312960.08693  -3.600 0.000318 ***
 parentBarrier -0.234000.08676  -2.697 0.006995 **
 ---
 Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
 
 (Dispersion parameter for binomial family taken to be 1)
 
 Null deviance: 1803.0  on 1479  degrees of freedom
 Residual deviance: 1567.8  on 1474  degrees of freedom
   (40 observations deleted due to missingness)
 AIC: 1579.8
 
 Number of Fisher Scoring iterations: 4
 
 On Mon, May 24, 2010 at 1:17 PM, John Fox j...@mcmaster.ca wrote:
  Dear sstewart,
 
  The model appears to reflect the path diagram, assuming that you intend
to
  allow the exogenous variables to be correlated and want the errors to be
  uncorrelated.
 
  This is one way to model the binary variable reuse. An alternative would
be
  to fit the equation for intent by least-squares regression (assuming
that
  the relationships are linear, etc.), and the equation of reuse by, e.g.,
  logistic regression (again assuming that the model is correctly
specified).
  If you're right that the effects of the exogenous variables are entirely
  mediated by intent, then if you put these variables in the equation for
  reuse, their coefficients should be small.
 
  I hope this helps,
   John
 
  
  John Fox
  Senator William McMaster
   Professor of Social Statistics
  Department of Sociology
  McMaster University
  Hamilton, Ontario, Canada
  web: socserv.mcmaster.ca/jfox
 
 
  -Original Message-
  From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]
  On
  Behalf Of R Help
  Sent: May-24-10 11:18 AM
  To: r-help
  Subject: [R] Path Analysis
 
  Hello list,
 
  I'm trying to make sure that I'm performing a path analysis correctly
  using the sem package.  the figure at
  http://flame.cs.dal.ca/~sstewart/regressDiag.png has a detailing of
  the model.
 
  The challenge I'm having is that reuse is an indicator (0/1) variable.
 
  Here's the code I'm using:
 
  corr =
 
 

hetcor(dat[,c('intent','exposure','benefit','norms','childBarrier','parentBa
  r
 
rier','knowBenefit','recuse')],use=pairwise.complete.obs)$correlations
  modMat = matrix(c(
    'exposure - intent', 'gam11',NA,
    'benefit - intent', 'gam12',NA,
    'norms - intent', 'gam13',NA,
    'childBarrier - intent', 'gam14',NA,
    'parentBarrier - intent', 'gam15',NA,
    'knowBenefit - intent', 'gam16',NA,
    'intent-intent','psi11',NA,
    'intent-recuse','gam21',NA,
    'recuse-recuse','psi22',NA),
    ncol=3,byrow=T)
  model4 =
 
 

sem(modMat,corr,N=1520,fixed.x=c('exposure','benefit','norms','childBarrier'
  ,
  'parentBarrier','knowBenefit'))
 
  Is this correctly modeling my diagram?  I'm not sure if a) I'm dealing
  with the categorical variable correctly, or b) whether fixed.x is
  accurately modeling the correlations for me.
 
  Any help would be appreciated.  I'm also looking into creating a plot
  function within R (similar to the path.diagram function, but using R
  plots).  If I get something useful I'll try and post it back
 
  __
  R

[R] path analysis in R (standardized solution)

2009-03-08 Thread Martin Batholdy

hi,

this is my first time I use the sem package in R.


I made a simple path analysis.

Now I was wondering how to get the standardized solution.
How can I get the standardized estimates of the path coefficients?

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] path analysis (misspecification?)

2009-03-08 Thread Martin Batholdy
hi,


I have following data and code;





cov -  
c 
(1.670028 
,-1.197685 
,-2.931445,-1.197685,1.765646,3.883839,-2.931445,3.883839,12.050816)


cov.matrix - matrix(cov, 3, 3, dimnames=list(c(y1,x1,x2),  
c(y1,x1,x2)))


path.model - specify.model()
   x1 - y1,x1-y1
   x2 - x1,   x2-x1
   x2 - x2,   x2-x2
   x1 - x1,   x1-x1
   y1 - y1,   y1-y1
  x2 - y1, x2-y1

  summary(sem(path.model, cov.matrix, N = 422))







and I get following results;



  Model Chisquare =  12.524   Df =  1 Pr(Chisq) = 0.00040179
  Chisquare (null model) =  812.69   Df =  3
  Goodness-of-fit index =  0.98083
  Adjusted goodness-of-fit index =  0.885
  RMSEA index =  0.16545   90% CI: (0.09231, 0.25264)
  Bentler-Bonnett NFI =  0.98459
  Tucker-Lewis NNFI =  0.9573
  Bentler CFI =  0.98577
  SRMR =  0.027022
  BIC =  6.4789

  Parameter Estimates
   Estimate Std Error z value Pr(|z|)
x1-y1 -0.67833 0.033967  -19.970 0y1 --- x1
x2-x1  3.88384 0.293743   13.222 0x1 -- x2
x2-x2 12.05082 0.831569   14.492 0x2 -- x2
x1-x1  1.76565 0.121839   14.492 0x1 -- x1
y1-y1  0.85761 0.059124   14.505 0y1 -- y1

  Iterations =  0







Now I wonder why the chi-square  value is so bad and what Pr(Chisq)  
tells me.

Can anyone help me on this?


When I allow the path x2 - y1 I get of course a good fit, but the  
path coefficient of x2 - y1 is pretty low (-0.084653), so I thought I  
can restrict that one to zero.



[[alternative HTML version deleted]]

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Re: [R] path analysis in R (standardized solution)

2009-03-08 Thread William Revelle

At 4:16 AM +0100 3/9/09, Martin Batholdy wrote:

hi,

this is my first time I use the sem package in R.


I made a simple path analysis.

Now I was wondering how to get the standardized solution.
How can I get the standardized estimates of the path coefficients?


?std.coef





__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.



--
William Revelle http://personality-project.org/revelle.html
Professor   http://personality-project.org/personality.html
Department of Psychology http://www.wcas.northwestern.edu/psych/
Northwestern University http://www.northwestern.edu/
Attend  ISSID/ARP:2009   http://issid.org/issid.2009/

__
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Re: [R] path analysis (misspecification?)

2009-03-08 Thread William Revelle

Martin,


hi,

I have following data and code;

cov - 
c

(1.670028
,-1.197685
,-2.931445,-1.197685,1.765646,3.883839,-2.931445,3.883839,12.050816)

cov.matrix - matrix(cov, 3, 3, dimnames=list(c(y1,x1,x2),
c(y1,x1,x2)))

path.model - specify.model()
   x1 - y1, x1-y1
   x2 - x1, x2-x1
   x2 - x2, x2-x2
   x1 - x1, x1-x1
   y1 - y1, y1-y1
  x2 - y1,  x2-y1

  summary(sem(path.model, cov.matrix, N = 422))


and I get following results;



  Model Chisquare =  12.524   Df =  1 Pr(Chisq) = 0.00040179
  Chisquare (null model) =  812.69   Df =  3
  Goodness-of-fit index =  0.98083
  Adjusted goodness-of-fit index =  0.885
  RMSEA index =  0.16545   90% CI: (0.09231, 0.25264)
  Bentler-Bonnett NFI =  0.98459
  Tucker-Lewis NNFI =  0.9573
  Bentler CFI =  0.98577
  SRMR =  0.027022
  BIC =  6.4789

  Parameter Estimates
   Estimate Std Error z value Pr(|z|)
x1-y1 -0.67833 0.033967  -19.970 0y1 --- x1
x2-x1  3.88384 0.293743   13.222 0x1 -- x2
x2-x2 12.05082 0.831569   14.492 0x2 -- x2
x1-x1  1.76565 0.121839   14.492 0x1 -- x1
y1-y1  0.85761 0.059124   14.505 0y1 -- y1

  Iterations =  0


Now I wonder why the chi-square  value is so bad and what Pr(Chisq) 
tells me.


Can anyone help me on this?


When I allow the path x2 - y1 I get of course a good fit, but the 
path coefficient of x2 - y1 is pretty low (-0.084653), so I thought I

can restrict that one to zero.




If you examine the residuals
 mod1 - sem(p.model,cov.matrix,N=422)
residuals(mod1)

You will see that you are completing ignoring the y1-x2 covariance.

When you examine your covariance matrix as a correlation matrix,
r.mat - cov2cor(cov.matrix)
 you will note that the  x2-y1 relationship is very large (the 
correlation is -.65)


Your original model was fully saturated and what you are reporting is 
actually what I label as p.model which is your full model without the 
last row.


If you compare the fully saturated model with your  mod1, you will 
find that the reason for the  large chi square is due to not 
specifying the x2-y1 path.


You might want to read some more on sem techniques.  A good 
introduction is a text by John Loehlin.


Bill

--
William Revelle http://personality-project.org/revelle.html
Professor   http://personality-project.org/personality.html
Department of Psychology http://www.wcas.northwestern.edu/psych/
Northwestern University http://www.northwestern.edu/
Attend  ISSID/ARP:2009   http://issid.org/issid.2009/

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Re: [R] path analysis (misspecification?)

2009-03-08 Thread Martin Batholdy

thank you very much!
I definitely need more theoretical background ...


but for now;
what does that mean for this dataset?

x1 should be the intermediate variable of x2 and y1
(x2 - x1 - y1)

Can I test that with this kind of analysis?



or do I see know that this kind of intermediate variable model does  
not fit the data well
and I need to set all paths to get a good model that represents the  
data good enough?




Am 09.03.2009 um 06:15 schrieb William Revelle:


Martin,


hi,

I have following data and code;

cov - c
(1.670028
,-1.197685
,-2.931445,-1.197685,1.765646,3.883839,-2.931445,3.883839,12.050816)

cov.matrix - matrix(cov, 3, 3, dimnames=list(c(y1,x1,x2),
c(y1,x1,x2)))

path.model - specify.model()
  x1 - y1,  x1-y1
  x2 - x1,  x2-x1
  x2 - x2,  x2-x2
  x1 - x1,  x1-x1
  y1 - y1,  y1-y1
 x2 - y1,   x2-y1

 summary(sem(path.model, cov.matrix, N = 422))


and I get following results;



 Model Chisquare =  12.524   Df =  1 Pr(Chisq) = 0.00040179
 Chisquare (null model) =  812.69   Df =  3
 Goodness-of-fit index =  0.98083
 Adjusted goodness-of-fit index =  0.885
 RMSEA index =  0.16545   90% CI: (0.09231, 0.25264)
 Bentler-Bonnett NFI =  0.98459
 Tucker-Lewis NNFI =  0.9573
 Bentler CFI =  0.98577
 SRMR =  0.027022
 BIC =  6.4789

 Parameter Estimates
  Estimate Std Error z value Pr(|z|)
x1-y1 -0.67833 0.033967  -19.970 0y1 --- x1
x2-x1  3.88384 0.293743   13.222 0x1 -- x2
x2-x2 12.05082 0.831569   14.492 0x2 -- x2
x1-x1  1.76565 0.121839   14.492 0x1 -- x1
y1-y1  0.85761 0.059124   14.505 0y1 -- y1

 Iterations =  0


Now I wonder why the chi-square  value is so bad and what  
Pr(Chisq) tells me.


Can anyone help me on this?


When I allow the path x2 - y1 I get of course a good fit, but the  
path coefficient of x2 - y1 is pretty low (-0.084653), so I  
thought I

can restrict that one to zero.




If you examine the residuals
mod1 - sem(p.model,cov.matrix,N=422)
residuals(mod1)

You will see that you are completing ignoring the y1-x2 covariance.

When you examine your covariance matrix as a correlation matrix,
r.mat - cov2cor(cov.matrix)
you will note that the  x2-y1 relationship is very large (the  
correlation is -.65)


Your original model was fully saturated and what you are reporting  
is actually what I label as p.model which is your full model without  
the last row.


If you compare the fully saturated model with your  mod1, you will  
find that the reason for the  large chi square is due to not  
specifying the x2-y1 path.


You might want to read some more on sem techniques.  A good  
introduction is a text by John Loehlin.


Bill

--
William Revelle http://personality-project.org/revelle.html
Professor   http://personality-project.org/personality.html
Department of Psychology http://www.wcas.northwestern.edu/psych/
Northwestern University http://www.northwestern.edu/
Attend  ISSID/ARP:2009   http://issid.org/issid.2009/


__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.