[sage-support] Re: Sage and skew-schurs
Thanks a bunch Mike!
That's neat. I have been using Sage a lot in my research on Kronecker
products, and the way things go I was expecting something of the sort
s[lambda].skew([b]) vaguely. But the syntax you wrote is way nicer.
I'll be giving a talk on Sage and Symmetric Functions (specifically
focussing on whatever I've used it for) and there should be a lot more
questions coming up!
Thanks again
On Oct 27, 10:54 pm, Mike Hansen mhan...@gmail.com wrote:
On Wed, Oct 27, 2010 at 10:42 PM, vasu tewari.v...@gmail.com wrote:
Hi all
I have tried searching all over the combinatorics sections of the
sagemath wiki, but I could not find if there is an implementation of
the skew schur functions. More specifically, here is what I am looking
for:
given partitions 'lambda' and 'mu', and 's' being the schur basis,
what is s_{lambda\mu}
where lambda\mu is the skew tableau.
sage: lmbda = Partition([3,2,1])
sage: mu = Partition([1])
sage: s = SymmetricFunctions(QQ).s(); s
Symmetric Function Algebra over Rational Field, Schur symmetric
functions as basis
sage: s(lmbda/mu)
s[2, 2, 1] + s[3, 1, 1] + s[3, 2]
sage: s([[3,2,1],[1]])
s[2, 2, 1] + s[3, 1, 1] + s[3, 2]
--Mike
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[sage-support] Re: union of lists and remove an element from a list
Hi Minh,
thank you very much for your detailed answer!!
Marusia
On 27 oct, 22:29, Minh Nguyen nguyenmi...@gmail.com wrote:
Hi Marusia,
On Thu, Oct 28, 2010 at 7:02 AM, m.rebolledo
marusia.reboll...@gmail.com wrote:
Hello,
how to do the union of several lists (more than two)?
Lists are multisets, so I assume you mean to combine several lists
into one, while retaining duplicate elements. You could do so using
the list concatenation operator +:
sage: L1 = [2, 3, 5, 7, 11]
sage: L2 = [a, b, c, 13]
sage: L3 = [1/2, 1/3, 1/4]
sage: L1 + L2 + L3
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
Via the list method extend():
sage: L = []
sage: L.extend(L1)
sage: L.extend(L2)
sage: L.extend(L3)
sage: L
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
Or use the Sage built-in function flatten():
sage: flatten([L1, L2, L3])
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
If you really want to remove duplicate elements in the final combined
list, use Set():
sage: L1 = [1, 2]
sage: L2 = [2, 3, 4]
sage: L3 = [a, b]
sage: Set(L1 + L2 + L3)
{'a', 1, 2, 3, 4, 'b'}
sage: list(Set(L1 + L2 + L3))
['a', 1, 2, 3, 4, 'b']
and how to
remove some elements of the lists?
Use the operator del:
sage: L
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
sage: L[0]
2
sage: del L[0]; L
[3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
sage: L[-1]
1/4
sage: del L[-1]; L
[3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3]
I know that it is probably
elementary but I did not find it in the help... :(
See the Python tutorial [1] for some introductory materials on using
lists. This page [2] and this page [3] provide detailed information on
operations on lists.
[1]http://docs.python.org/tutorial/introduction.html#lists
[2]http://docs.python.org/library/stdtypes.html#sequence-types-str-unico...
[3]http://docs.python.org/library/stdtypes.html#typesseq-mutable
--
Regards
Minh Van Nguyen
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[sage-support] Re: union of lists and remove an element from a list
For the second question the remove is better for me :
list.remove(x) because I don't know the index of x in the list. (I
don't know even if the list contains x)
Thank you again!
On 27 oct, 22:29, Minh Nguyen nguyenmi...@gmail.com wrote:
Hi Marusia,
On Thu, Oct 28, 2010 at 7:02 AM, m.rebolledo
marusia.reboll...@gmail.com wrote:
Hello,
how to do the union of several lists (more than two)?
Lists are multisets, so I assume you mean to combine several lists
into one, while retaining duplicate elements. You could do so using
the list concatenation operator +:
sage: L1 = [2, 3, 5, 7, 11]
sage: L2 = [a, b, c, 13]
sage: L3 = [1/2, 1/3, 1/4]
sage: L1 + L2 + L3
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
Via the list method extend():
sage: L = []
sage: L.extend(L1)
sage: L.extend(L2)
sage: L.extend(L3)
sage: L
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
Or use the Sage built-in function flatten():
sage: flatten([L1, L2, L3])
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
If you really want to remove duplicate elements in the final combined
list, use Set():
sage: L1 = [1, 2]
sage: L2 = [2, 3, 4]
sage: L3 = [a, b]
sage: Set(L1 + L2 + L3)
{'a', 1, 2, 3, 4, 'b'}
sage: list(Set(L1 + L2 + L3))
['a', 1, 2, 3, 4, 'b']
and how to
remove some elements of the lists?
Use the operator del:
sage: L
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
sage: L[0]
2
sage: del L[0]; L
[3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
sage: L[-1]
1/4
sage: del L[-1]; L
[3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3]
I know that it is probably
elementary but I did not find it in the help... :(
See the Python tutorial [1] for some introductory materials on using
lists. This page [2] and this page [3] provide detailed information on
operations on lists.
[1]http://docs.python.org/tutorial/introduction.html#lists
[2]http://docs.python.org/library/stdtypes.html#sequence-types-str-unico...
[3]http://docs.python.org/library/stdtypes.html#typesseq-mutable
--
Regards
Minh Van Nguyen
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Re: [sage-support] Sage and skew-schurs
On Wed, 27 Oct 2010 at 10:42PM -0700, vasu wrote: ps: I stopped short of posting this question on Sage-combinat as I thought that is a heavily-research oriented forum, and this question wouldn't fit. Mike answered your math question, so let me address this: posting your question in sage-combinat-devel would be perfectly fine. That list is pretty research-oriented, but anyone who wants to calculate Schur functions is very welcome there. Feel free to ask any other combinatorics questions here or in sage-combinat-devel. Dan -- --- Dan Drake - http://mathsci.kaist.ac.kr/~drake --- signature.asc Description: Digital signature
Re: [sage-support] Reading images using Octave into Sage?
For me (using octave 3.2 on ubuntu 10.04, sage 4.5.2a1) it ran on repeating
Exception RuntimeError: RuntimeError('maximum recursion depth exceeded
in cmp',) in Exception RuntimeError: 'maximum recursion depth exceeded
in __subclasscheck__' in type 'exceptions.RuntimeError' ignored
and refused to respond to ctl-c or ctl-d. I had to kill it using a kill -9 PID.
What did your system do?
On Thu, Oct 28, 2010 at 6:39 AM, Alasdair amc...@gmail.com wrote:
I want to do some computations (using Sage) on the pixel values of an
image, and I assumed I'd be able to use Octave to read in the values.
Something like:
c = octave('imread(cameraman.png)')
or even
octave('c = imread(cameraman.png)')
But none of these work. Even if I start up Octave-inside-Sage with
octave.console(), the imread command fails to work. It works fine in
Octave (outside of Sage), though.
It would be nice to be able to use
octave.imread
but that doesn't work (as for example all Maxima functions are so
available).
Any suggestions?
Thanks,
Alasdair
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[sage-support] Re: Reading images using Octave into Sage?
Yep, mine too. But sometimes it just hangs.
On Oct 28, 11:27 pm, David Joyner wdjoy...@gmail.com wrote:
For me (using octave 3.2 on ubuntu 10.04, sage 4.5.2a1) it ran on repeating
Exception RuntimeError: RuntimeError('maximum recursion depth exceeded
in cmp',) in Exception RuntimeError: 'maximum recursion depth exceeded
in __subclasscheck__' in type 'exceptions.RuntimeError' ignored
and refused to respond to ctl-c or ctl-d. I had to kill it using a kill -9
PID.
What did your system do?
On Thu, Oct 28, 2010 at 6:39 AM, Alasdair amc...@gmail.com wrote:
I want to do some computations (using Sage) on the pixel values of an
image, and I assumed I'd be able to use Octave to read in the values.
Something like:
c = octave('imread(cameraman.png)')
or even
octave('c = imread(cameraman.png)')
But none of these work. Even if I start up Octave-inside-Sage with
octave.console(), the imread command fails to work. It works fine in
Octave (outside of Sage), though.
It would be nice to be able to use
octave.imread
but that doesn't work (as for example all Maxima functions are so
available).
Any suggestions?
Thanks,
Alasdair
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[sage-support] Re: union of lists and remove an element from a list
On Oct 27, 10:29 pm, Minh Nguyen nguyenmi...@gmail.com wrote:
Hi Marusia,
On Thu, Oct 28, 2010 at 7:02 AM, m.rebolledo
marusia.reboll...@gmail.com wrote:
Hello,
how to do the union of several lists (more than two)?
Lists are multisets, so I assume you mean to combine several lists
into one, while retaining duplicate elements. You could do so using
the list concatenation operator +:
sage: L1 = [2, 3, 5, 7, 11]
sage: L2 = [a, b, c, 13]
sage: L3 = [1/2, 1/3, 1/4]
sage: L1 + L2 + L3
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
Hi,
just as a sidenote, this might make people write this:
L = sum( a list of list, [] )
which is correct but quite inefficient.
Compare the following:
timeit('L = sum([[0] for i in range(1)], [])')
and
timeit('L = []\nfor i in range(1): L += [0]')
Regards
Yann
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[sage-support] doubly noncentral F distribution
Is there any code for cdf of double noncentral F distribution? -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
[sage-support] Re: union of lists and remove an element from a list
On 10/28/10 9:25 AM, Yann wrote:
On Oct 27, 10:29 pm, Minh Nguyennguyenmi...@gmail.com wrote:
Hi Marusia,
On Thu, Oct 28, 2010 at 7:02 AM, m.rebolledo
marusia.reboll...@gmail.com wrote:
Hello,
how to do the union of several lists (more than two)?
Lists are multisets, so I assume you mean to combine several lists
into one, while retaining duplicate elements. You could do so using
the list concatenation operator +:
sage: L1 = [2, 3, 5, 7, 11]
sage: L2 = [a, b, c, 13]
sage: L3 = [1/2, 1/3, 1/4]
sage: L1 + L2 + L3
[2, 3, 5, 7, 11, 'a', 'b', 'c', 13, 1/2, 1/3, 1/4]
Hi,
just as a sidenote, this might make people write this:
L = sum( a list of list, [] )
which is correct but quite inefficient.
But you could try using sage's balanced_sum, which is much more
efficient (but still not as efficient as using += like your last
example, at least in this case):
sage: LL=[range(5*n,5*n+3) for n in range(100)]
sage: LL
[[0, 1, 2], [5, 6, 7], [10, 11, 12], [15, 16, 17], [20, 21, 22], [25,
26, 27], [30, 31, 32], [35, 36, 37], [40, 41, 42], [45, 46, 47], [50,
51, 52], [55, 56, 57], [60, 61, 62], [65, 66, 67], [70, 71, 72], [75,
76, 77], [80, 81, 82], [85, 86, 87], [90, 91, 92], [95, 96, 97], [100,
101, 102], [105, 106, 107], [110, 111, 112], [115, 116, 117], [120, 121,
122], [125, 126, 127], [130, 131, 132], [135, 136, 137], [140, 141,
142], [145, 146, 147], [150, 151, 152], [155, 156, 157], [160, 161,
162], [165, 166, 167], [170, 171, 172], [175, 176, 177], [180, 181,
182], [185, 186, 187], [190, 191, 192], [195, 196, 197], [200, 201,
202], [205, 206, 207], [210, 211, 212], [215, 216, 217], [220, 221,
222], [225, 226, 227], [230, 231, 232], [235, 236, 237], [240, 241,
242], [245, 246, 247], [250, 251, 252], [255, 256, 257], [260, 261,
262], [265, 266, 267], [270, 271, 272], [275, 276, 277], [280, 281,
282], [285, 286, 287], [290, 291, 292], [295, 296, 297], [300, 301,
302], [305, 306, 307], [310, 311, 312], [315, 316, 317], [320, 321,
322], [325, 326, 327], [330, 331, 332], [335, 336, 337], [340, 341,
342], [345, 346, 347], [350, 351, 352], [355, 356, 357], [360, 361,
362], [365, 366, 367], [370, 371, 372], [375, 376, 377], [380, 381,
382], [385, 386, 387], [390, 391, 392], [395, 396, 397], [400, 401,
402], [405, 406, 407], [410, 411, 412], [415, 416, 417], [420, 421,
422], [425, 426, 427], [430, 431, 432], [435, 436, 437], [440, 441,
442], [445, 446, 447], [450, 451, 452], [455, 456, 457], [460, 461,
462], [465, 466, 467], [470, 471, 472], [475, 476, 477], [480, 481,
482], [485, 486, 487], [490, 491, 492], [495, 496, 497]]
sage: timeit('flatten(LL)')
625 loops, best of 3: 507 盜 per loop
sage: timeit('sum(LL,[])')
625 loops, best of 3: 104 盜 per loop
sage: timeit('balanced_sum(LL,[])')
625 loops, best of 3: 32.4 盜 per loop
sage: timeit('L=[]\nfor i in LL: L.extend(i)')
625 loops, best of 3: 21.6 盜 per loop
sage: timeit('L=[]\nfor i in LL: L+=i')
625 loops, best of 3: 13.5 盜 per loop
-Jason
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[sage-support] sage console in ubuntu 10.10 and jmol
I installed the sage 4.5.3 binary in my little netbook, and when I type sphere() or show(sphere()= nothing happens. I have the package sun-java6-bin sun-java6-jre and sun-java6-plugin installed. All works in the notebook. Is this intended? I do the same in an ubuntu 10.04 and I do get the jmol window, unlike with 10.10. Thanks. -Adrián. -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
