Re: [time-nuts] Thermal time constant

2010-03-11 Thread David C. Partridge
Most building insulation foam sold here in UK has an Alu foil cladding on
both sides ...

Dave


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Re: [time-nuts] Thermal time constant

2010-03-11 Thread jimlux

Predrag Dukic wrote:



How well depleted it really is? 


DU has about 1/3 the U235 of  natural U, of which less than 1% is U235. 
 All the isotopes are radioactive, but I don't recall what the relative 
activities are.  I think U238 has a half live of 4E9 years or more, so 
not very many atoms spontaneously disintegrate every second.


 Uranium separation is not perfect. Some

radioactivity is still left.


Not much.. you'd have more trouble if you lived on granite or lived in a 
brick/stone house.


It's an alpha emitter, too, so painting it would provide shielding. 
It's the fact that it's a heavy metal that's more of an issue for toxicity.

Don't know about the neutrons from the spontaneous fission.




I don't think it is healthy to have it beside You for a long time.

Certainly not 8 pounds :))






At 05:35 11.3.2010, you wrote:

Bob Camp wrote:

Hi
The gotcha is that you are interested in the amount of heat per cubic 
foot rather than the amount of heat per pound. You need to take the 
standard heat per weight numbers and convert them to heat per volume 
numbers.
Of the things you can easily get, copper is good. Steel is not as 
good as copper, but better than aluminum.

Bob


Gold is your friend. Mercury has convective losses because it's a 
liquid.  Platinum or Osmium would also be ok.


You might want something that is dense but lower conductivity.. lead? 
Depleted Uranium? (DU is available very cheaply if you can take 80,000 
pound lots)


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Re: [time-nuts] Thermal time constant

2010-03-11 Thread Brooke Clarke

Hi Bob:

How about just wrapping the aluminum block in aluminum foil with the 
shiny side out.  Then wrap the Styrofoam cube with the shiny side in 
before putting it in the aluminum box?


Have Fun,

Brooke Clarke
http://www.PRC68.com


Bob Camp wrote:

Hi

Since styrofoam is being rated as a building insulation, it's reasonable to 
believe that the material on both sides is up around 1. I highly doubt that 
somebody tossing styrofoam in walls is going to add a radiation factor ...

In our application we're talking about a metal block inside a metal enclosure, 
polishing the surfaces could drop the emissivity by10X.  If the budget allows, 
you could gold plate the surfaces in addition to polishing them .

Bob


On Mar 10, 2010, at 8:01 PM, Bruce Griffiths wrote:

   

Oops forgot a factor of 4
Radiative heat transfer for surface with an emissivity of 1 at 300K is about 
612uW/square cm/degree C
which is equivalent to about 25mm of styrofoam.

Which raises the question what's the emissivity of the isothermal surface used 
when measuring the thermal resistance of a slab of styrofoam?

Bruce

Bruce Griffiths wrote:
 

Radiative heat transfer (for a surface with an emissivity of 1) is around 
150uW/square cm /degreeC at 300K.
That's equivalent to about 10cm of styrofoam.

It seems unlikely that the radiative heat transfer component is included in the 
thermal resistance rating for Styrofoam.

The radiative component is independent of insulation thickness where the 
insulation doesnt absorb in the 10-30um infrared region.

Adding carbon black to the foam appears to increase the thermal resistance of 
25mm thick foam by about 10%.

Bruce

Bob Camp wrote:
   

Hi

That raises the interesting question of weather radiant transfer is already included 
in the rated thermal resistance. My guess is that the 8 of foam is enough to 
cover any radiation issues and still get you above 20 C / W.

Since you are probably starting with 1 or 2 slabs, including the aluminum foil 
would be pretty easy. It can't hurt and it might help.

Bob

On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:

 

I have been wondering about achieving the rated thermal resistance from plastic 
foam,
the problem being that radiant transmission may be very strong through the foam.
What happens if you interleave concentric sheets of foam plastic with aluminium 
foil? (taking care to keep the foil
on isothermal surfaces)
Will this stop the radiant transfer and leave only the thermal conduction of 
the plastic foam?
cheers, Neville Michie

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Re: [time-nuts] Thermal time constant

2010-03-11 Thread Bob Camp
Hi

Sounds cheaper than gold plating.

I'd put a couple layers of foil in the 8 of foam as well. Maybe a layer
every 2. 

Bob


-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
Behalf Of Brooke Clarke
Sent: Thursday, March 11, 2010 9:48 AM
To: Discussion of precise time and frequency measurement
Subject: Re: [time-nuts] Thermal time constant

Hi Bob:

How about just wrapping the aluminum block in aluminum foil with the 
shiny side out.  Then wrap the Styrofoam cube with the shiny side in 
before putting it in the aluminum box?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bob Camp wrote:
 Hi

 Since styrofoam is being rated as a building insulation, it's reasonable
to believe that the material on both sides is up around 1. I highly doubt
that somebody tossing styrofoam in walls is going to add a radiation factor
...

 In our application we're talking about a metal block inside a metal
enclosure, polishing the surfaces could drop the emissivity by10X.  If the
budget allows, you could gold plate the surfaces in addition to polishing
them .

 Bob


 On Mar 10, 2010, at 8:01 PM, Bruce Griffiths wrote:


 Oops forgot a factor of 4
 Radiative heat transfer for surface with an emissivity of 1 at 300K is
about 612uW/square cm/degree C
 which is equivalent to about 25mm of styrofoam.

 Which raises the question what's the emissivity of the isothermal surface
used when measuring the thermal resistance of a slab of styrofoam?

 Bruce

 Bruce Griffiths wrote:
  
 Radiative heat transfer (for a surface with an emissivity of 1) is
around 150uW/square cm /degreeC at 300K.
 That's equivalent to about 10cm of styrofoam.

 It seems unlikely that the radiative heat transfer component is included
in the thermal resistance rating for Styrofoam.

 The radiative component is independent of insulation thickness where the
insulation doesnt absorb in the 10-30um infrared region.

 Adding carbon black to the foam appears to increase the thermal
resistance of 25mm thick foam by about 10%.

 Bruce

 Bob Camp wrote:

 Hi

 That raises the interesting question of weather radiant transfer is
already included in the rated thermal resistance. My guess is that the 8 of
foam is enough to cover any radiation issues and still get you above 20 C /
W.

 Since you are probably starting with 1 or 2 slabs, including the
aluminum foil would be pretty easy. It can't hurt and it might help.

 Bob

 On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:

  
 I have been wondering about achieving the rated thermal resistance
from plastic foam,
 the problem being that radiant transmission may be very strong through
the foam.
 What happens if you interleave concentric sheets of foam plastic with
aluminium foil? (taking care to keep the foil
 on isothermal surfaces)
 Will this stop the radiant transfer and leave only the thermal
conduction of the plastic foam?
 cheers, Neville Michie

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Re: [time-nuts] Thermal time constant

2010-03-11 Thread Bob Camp
Hi

Also true here in the US, but not for Styrofoam.

Bob

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
Behalf Of David C. Partridge
Sent: Thursday, March 11, 2010 8:53 AM
To: 'Discussion of precise time and frequency measurement'
Subject: Re: [time-nuts] Thermal time constant

Most building insulation foam sold here in UK has an Alu foil cladding on
both sides ...

Dave


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Re: [time-nuts] Thermal time constant

2010-03-11 Thread Matt Osborn

Jack Smith at Clifton Laboratories built a replacement for the 1502
chart recorders. An early prototype can be seen here:
http://www.cliftonlaboratories.com/mar_2007.htm


On Thu, 11 Mar 2010 04:51:00 +, Mark Sims hol...@hotmail.com
wrote:


Gawd,  tell me about it...   I just got through rebuilding the drive roller in 
half a dozen Tektronix YT-1 and YT-1S chart recorders for the 
1502B/1520C/1503B/1503C TDR's

-- kc0ukk at msosborn dot com

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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Brooke Clarke

Hi Mathew:

There are a bunch of them, but I like the DS3231 because it has a 
software frequency tweak and I2C interface.

http://www.maxim-ic.com/quick_view2.cfm/qv_pk/4627/t/al
http://datasheets.maxim-ic.com/en/ds/DS3231.pdf

Hi Bruce:

Do you have a value for the thermal resistance of Styrofoam?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Matthew Smith wrote:

Quoth Brooke Clarke at 10/03/10 10:22...

...like a Dallas 32khz, or one of the newer Maxim units...


There's a Maxim part to supersede the DS32kHz?  I know that my regular 
vendors [Farnell, Soanar, Futurlec] in Australia don't stock the 
DS32kHz, which makes them mega-expensive to acquire.





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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Brooke Clarke

Hi Bruce:

What does m2K/W mean?  See:
http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

50 mm it's about 1.5 and for 100 mm it's about 3.

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:

Bruce Griffiths wrote:

Brooke Clarke wrote:

Hi:

For some time I've considered surrounding a free running 32678 Hz 
oscillator (like a Dallas 32khz, or one of the newer Maxim units) 
with thermal mass and insulation in order to get the time constant 
into the range of some days.  To get a feel for it a simple 
experiment shows that a half inch diameter brass rod 3.75 long (102 
grams) has a thermal time constant of about 6 min 35 seconds when 
wrapped lightly in a towel.


Is there a way to calculate the amount of aluminum and Styrofoam 
needed to get a time constant of say 100 hours?


This came up in relation to WWVB clocks that free run for most of 
the time.  When you compare WWVB clocks it's not uncommon to see 
tens of seconds difference between them.  
http://www.prc68.com/I/Loop.shtml#TC


Start with the maximum thermal resistance the application can 
withstand (determined by internal dissipation and acceptable 
temperature rise above ambient).


If for example the dissipation is 10mW and acceptable temperature 
rise 10C then thermal resistance will be about 1000C/W.


The thermal capacity required can then be calculated from the time 
constant:


C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from the 
surface area of the aluminium block.


Achieving a thermal resistance of 1000C/W may be a little difficult 
without using radiation shields.


Bruce


Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 
J/gm/C so the mass of Aluminium required would be 430gm if the thermal 
resistance to ambient were 1000K/W. With a thermal resistance of 
100C/W you need 4.3Kg of aluminium 


Bruce


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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Bruce Griffiths

~3.3E-2 W/mK.

If, as I suspect,  its transparent to 10-20um infrared then adding 
intermediate aluminium foil radiation shields may be useful.


Some styrofoam insulating panels include carbon black to inhibit 
infrared transmission:

http://www.glasscellisofab.com/sheets/polystyrene/data_sheets/STYROFOAM%20PANELMATE.pdf
Foam glass is also black for the same reason and its cells are filled 
with sulphur dioxide (at least it smalls like that when you cut it).


Aerogel foam is also good (not sure about its infrared transparency).

Bruce

Brooke Clarke wrote:

Hi Mathew:

There are a bunch of them, but I like the DS3231 because it has a 
software frequency tweak and I2C interface.

http://www.maxim-ic.com/quick_view2.cfm/qv_pk/4627/t/al
http://datasheets.maxim-ic.com/en/ds/DS3231.pdf

Hi Bruce:

Do you have a value for the thermal resistance of Styrofoam?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Matthew Smith wrote:

Quoth Brooke Clarke at 10/03/10 10:22...

...like a Dallas 32khz, or one of the newer Maxim units...


There's a Maxim part to supersede the DS32kHz?  I know that my 
regular vendors [Farnell, Soanar, Futurlec] in Australia don't stock 
the DS32kHz, which makes them mega-expensive to acquire.









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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Bruce Griffiths

Thermal resistance is measured in degrees (C or K or ..) per watt.
Its inversely proportional to area and proportional to thickness.

I think the clueless clown who created that table means that for a 1 
square meter panel of the specified thickness the thermal resistance is 
the tabulated value measured in Kelvin/Watt.


Bruce

Brooke Clarke wrote:

Hi Bruce:

What does m2K/W mean?  See:
http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

50 mm it's about 1.5 and for 100 mm it's about 3.

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:

Bruce Griffiths wrote:

Brooke Clarke wrote:

Hi:

For some time I've considered surrounding a free running 32678 Hz 
oscillator (like a Dallas 32khz, or one of the newer Maxim units) 
with thermal mass and insulation in order to get the time constant 
into the range of some days.  To get a feel for it a simple 
experiment shows that a half inch diameter brass rod 3.75 long 
(102 grams) has a thermal time constant of about 6 min 35 seconds 
when wrapped lightly in a towel.


Is there a way to calculate the amount of aluminum and Styrofoam 
needed to get a time constant of say 100 hours?


This came up in relation to WWVB clocks that free run for most of 
the time.  When you compare WWVB clocks it's not uncommon to see 
tens of seconds difference between them.  
http://www.prc68.com/I/Loop.shtml#TC


Start with the maximum thermal resistance the application can 
withstand (determined by internal dissipation and acceptable 
temperature rise above ambient).


If for example the dissipation is 10mW and acceptable temperature 
rise 10C then thermal resistance will be about 1000C/W.


The thermal capacity required can then be calculated from the time 
constant:


C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from the 
surface area of the aluminium block.


Achieving a thermal resistance of 1000C/W may be a little difficult 
without using radiation shields.


Bruce


Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 
J/gm/C so the mass of Aluminium required would be 430gm if the 
thermal resistance to ambient were 1000K/W. With a thermal resistance 
of 100C/W you need 4.3Kg of aluminium 


Bruce


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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Brooke Clarke

Hi Bruce:

If a square meter of Styrofoam is 1.5 deg C/W then a cubic inch would be 
39.37 * 39.37 * 1.5 or 2,325 deg C/W


The DS3231 dissipates about 1 mw when running.  I'm not sure how to come 
up with an allowable temp increase, but suspect it's based on not 
exceeding the max allowed operating temp.  But for this part the Temp 
vs. freq curve is flattest at room temp so best to minimize the temp rise.

So:  (1 deg C) / (0.001 W) = 1000 deg C/W, the same number you had.

That requires 185 g of Aluminum or about 69 cc volume or 4.25 cubic 
inches.  That's a block about 1.62 on a side.


How does that look?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:

Thermal resistance is measured in degrees (C or K or ..) per watt.
Its inversely proportional to area and proportional to thickness.

I think the clueless clown who created that table means that for a 1 
square meter panel of the specified thickness the thermal resistance 
is the tabulated value measured in Kelvin/Watt.


Bruce

Brooke Clarke wrote:

Hi Bruce:

What does m2K/W mean?  See:
http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

50 mm it's about 1.5 and for 100 mm it's about 3.

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:

Bruce Griffiths wrote:

Brooke Clarke wrote:

Hi:

For some time I've considered surrounding a free running 32678 Hz 
oscillator (like a Dallas 32khz, or one of the newer Maxim units) 
with thermal mass and insulation in order to get the time constant 
into the range of some days.  To get a feel for it a simple 
experiment shows that a half inch diameter brass rod 3.75 long 
(102 grams) has a thermal time constant of about 6 min 35 seconds 
when wrapped lightly in a towel.


Is there a way to calculate the amount of aluminum and Styrofoam 
needed to get a time constant of say 100 hours?


This came up in relation to WWVB clocks that free run for most of 
the time.  When you compare WWVB clocks it's not uncommon to see 
tens of seconds difference between them.  
http://www.prc68.com/I/Loop.shtml#TC


Start with the maximum thermal resistance the application can 
withstand (determined by internal dissipation and acceptable 
temperature rise above ambient).


If for example the dissipation is 10mW and acceptable temperature 
rise 10C then thermal resistance will be about 1000C/W.


The thermal capacity required can then be calculated from the time 
constant:


C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from the 
surface area of the aluminium block.


Achieving a thermal resistance of 1000C/W may be a little difficult 
without using radiation shields.


Bruce


Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 
J/gm/C so the mass of Aluminium required would be 430gm if the 
thermal resistance to ambient were 1000K/W. With a thermal 
resistance of 100C/W you need 4.3Kg of aluminium 


Bruce


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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Bob Camp
Hi

If a square meter of foam 2 thick is 1.5 C/W then a 1 square inch piece
(also 2 thick) would be ~40^2 times better.

Your cube has ~2 square inches on a side and six sides. (divide by ~12) 

The outer cube after you put 2 of foam on it has surfaces 5.6 on a side.
That's a surface area of 25 square inches. The 10:1 increase in area needs
to be considered.(divide by X in addition).

2325/12 = 193.75
193.76 / (5) =  38.75 C/W

The block is going to get a *lot* bigger.

Consider using steel instead of aluminum.

Bob 

-Original Message-
From: time-nuts-boun...@febo.com [mailto:time-nuts-boun...@febo.com] On
Behalf Of Brooke Clarke
Sent: Wednesday, March 10, 2010 4:28 PM
To: Discussion of precise time and frequency measurement
Subject: Re: [time-nuts] Thermal Time Constant

Hi Bruce:

If a square meter of Styrofoam is 1.5 deg C/W then a cubic inch would be 
39.37 * 39.37 * 1.5 or 2,325 deg C/W

The DS3231 dissipates about 1 mw when running.  I'm not sure how to come 
up with an allowable temp increase, but suspect it's based on not 
exceeding the max allowed operating temp.  But for this part the Temp 
vs. freq curve is flattest at room temp so best to minimize the temp rise.
So:  (1 deg C) / (0.001 W) = 1000 deg C/W, the same number you had.

That requires 185 g of Aluminum or about 69 cc volume or 4.25 cubic 
inches.  That's a block about 1.62 on a side.

How does that look?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:
 Thermal resistance is measured in degrees (C or K or ..) per watt.
 Its inversely proportional to area and proportional to thickness.

 I think the clueless clown who created that table means that for a 1 
 square meter panel of the specified thickness the thermal resistance 
 is the tabulated value measured in Kelvin/Watt.

 Bruce

 Brooke Clarke wrote:
 Hi Bruce:

 What does m2K/W mean?  See:
 http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

 50 mm it's about 1.5 and for 100 mm it's about 3.

 Have Fun,

 Brooke Clarke
 http://www.PRC68.com


 Bruce Griffiths wrote:
 Bruce Griffiths wrote:
 Brooke Clarke wrote:
 Hi:

 For some time I've considered surrounding a free running 32678 Hz 
 oscillator (like a Dallas 32khz, or one of the newer Maxim units) 
 with thermal mass and insulation in order to get the time constant 
 into the range of some days.  To get a feel for it a simple 
 experiment shows that a half inch diameter brass rod 3.75 long 
 (102 grams) has a thermal time constant of about 6 min 35 seconds 
 when wrapped lightly in a towel.

 Is there a way to calculate the amount of aluminum and Styrofoam 
 needed to get a time constant of say 100 hours?

 This came up in relation to WWVB clocks that free run for most of 
 the time.  When you compare WWVB clocks it's not uncommon to see 
 tens of seconds difference between them.  
 http://www.prc68.com/I/Loop.shtml#TC

 Start with the maximum thermal resistance the application can 
 withstand (determined by internal dissipation and acceptable 
 temperature rise above ambient).

 If for example the dissipation is 10mW and acceptable temperature 
 rise 10C then thermal resistance will be about 1000C/W.

 The thermal capacity required can then be calculated from the time 
 constant:

 C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

 The required thickness of styrofoam can then be calculated from the 
 surface area of the aluminium block.

 Achieving a thermal resistance of 1000C/W may be a little difficult 
 without using radiation shields.

 Bruce


 Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 
 J/gm/C so the mass of Aluminium required would be 430gm if the 
 thermal resistance to ambient were 1000K/W. With a thermal 
 resistance of 100C/W you need 4.3Kg of aluminium 

 Bruce


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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Bruce Griffiths

Surely you meant 1 square inch of styrofoam with the specified thickness??

For a 100 hour (3.6E5 seconds) time constant and 1000 deg C/W thermal 
resistance you need a thermal capacitance of 3.6E5/1E3 = 360 J/C

or 360/0.8371 = 430 gm of Aluminium which has a volume of 430/2.7 = 159 cc.

You still have the thermal radiation coupling problem through the 
infrared transparent insulator.

Gold plating the aluminium will help.

Even if you solve the thermal radiation problem, the thermal conductance 
of any leads bringing power or signals to or from the clock will be an 
major problem even if you use constantan or austenetic stainless steel 
leads.


Bruce

Brooke Clarke wrote:

Hi Bruce:

If a square meter of Styrofoam is 1.5 deg C/W then a cubic  inch would 
be 39.37 * 39.37 * 1.5 or 2,325 deg C/W


The DS3231 dissipates about 1 mw when running.  I'm not sure how to 
come up with an allowable temp increase, but suspect it's based on not 
exceeding the max allowed operating temp.  But for this part the Temp 
vs. freq curve is flattest at room temp so best to minimize the temp 
rise.

So:  (1 deg C) / (0.001 W) = 1000 deg C/W, the same number you had.

That requires 185 g of Aluminum or about 69 cc volume or 4.25 cubic 
inches.  That's a block about 1.62 on a side.


How does that look?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:

Thermal resistance is measured in degrees (C or K or ..) per watt.
Its inversely proportional to area and proportional to thickness.

I think the clueless clown who created that table means that for a 1 
square meter panel of the specified thickness the thermal resistance 
is the tabulated value measured in Kelvin/Watt.


Bruce

Brooke Clarke wrote:

Hi Bruce:

What does m2K/W mean?  See:
http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

50 mm it's about 1.5 and for 100 mm it's about 3.

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:

Bruce Griffiths wrote:

Brooke Clarke wrote:

Hi:

For some time I've considered surrounding a free running 32678 Hz 
oscillator (like a Dallas 32khz, or one of the newer Maxim units) 
with thermal mass and insulation in order to get the time 
constant into the range of some days.  To get a feel for it a 
simple experiment shows that a half inch diameter brass rod 3.75 
long (102 grams) has a thermal time constant of about 6 min 35 
seconds when wrapped lightly in a towel.


Is there a way to calculate the amount of aluminum and Styrofoam 
needed to get a time constant of say 100 hours?


This came up in relation to WWVB clocks that free run for most of 
the time.  When you compare WWVB clocks it's not uncommon to see 
tens of seconds difference between them.  
http://www.prc68.com/I/Loop.shtml#TC


Start with the maximum thermal resistance the application can 
withstand (determined by internal dissipation and acceptable 
temperature rise above ambient).


If for example the dissipation is 10mW and acceptable temperature 
rise 10C then thermal resistance will be about 1000C/W.


The thermal capacity required can then be calculated from the time 
constant:


C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from 
the surface area of the aluminium block.


Achieving a thermal resistance of 1000C/W may be a little 
difficult without using radiation shields.


Bruce


Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 
0.8371 J/gm/C so the mass of Aluminium required would be 430gm if 
the thermal resistance to ambient were 1000K/W. With a thermal 
resistance of 100C/W you need 4.3Kg of aluminium 


Bruce


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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bob Camp
Hi

The gotcha is that you are interested in the amount of heat per cubic foot 
rather than the amount of heat per pound. You need to take the standard heat 
per weight numbers and convert them to heat per volume numbers. 

Of the things you can easily get, copper is good. Steel is not as good as 
copper, but better than aluminum. 

Bob


On Mar 10, 2010, at 5:52 PM, p...@pseng.org.uk wrote:

 Looking at the specific heat of metals:
 http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
 Wouldn't Beryllium be better instead of aluminium?
 I could foresee a few problems though eg machining holes at home, never mind 
 where to get a block from.
 
 Phil
 
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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Joseph M Gwinn
A better metric may be stored heat for a dollar's worth of material. Scrap 
iron is pretty cheap.




From:
Bob Camp li...@rtty.us
To:
Discussion of precise time and frequency measurement time-nuts@febo.com
Date:
03/10/2010 06:03 PM
Subject:
Re: [time-nuts] Thermal time constant
Sent by:
time-nuts-boun...@febo.com



Hi

The gotcha is that you are interested in the amount of heat per cubic foot 
rather than the amount of heat per pound. You need to take the standard 
heat per weight numbers and convert them to heat per volume numbers. 

Of the things you can easily get, copper is good. Steel is not as good as 
copper, but better than aluminum. 

Bob


On Mar 10, 2010, at 5:52 PM, p...@pseng.org.uk wrote:

 Looking at the specific heat of metals:
 http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
 Wouldn't Beryllium be better instead of aluminium?
 I could foresee a few problems though eg machining holes at home, never 
mind where to get a block from.
 
 Phil
 
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 To unsubscribe, go to 
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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths

p...@pseng.org.uk wrote:

Looking at the specific heat of metals:
http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
Wouldn't Beryllium be better instead of aluminium?
I could foresee a few problems though eg machining holes at home, 
never mind where to get a block from.


Phil

Actually in this application minimising the volume of the metal block 
rather than its weight is probably better so one should use specific 
heat*density as a figure of merit.


METALSpecific heat*density (W/J/cubic cm)
Aluminium 2.46

Beryllium3.29

Copper   3.49

Silver  2.41

Iron3.87

Thus copper and iron are better choices than Beryllium they also poses 
fewer machining diffculties


Bruce


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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Neville Michie
Just in case anyone finds a beryllium brick somewhere and tries to  
use it:

Beryllium is very very poisonous.
cheers,
Neville Michie

On 11/03/2010, at 10:08 AM, Bruce Griffiths wrote:


p...@pseng.org.uk wrote:

Looking at the specific heat of metals:
http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
Wouldn't Beryllium be better instead of aluminium?
I could foresee a few problems though eg machining holes at home,  
never mind where to get a block from.


Phil

Actually in this application minimising the volume of the metal  
block rather than its weight is probably better so one should use  
specific heat*density as a figure of merit.


METALSpecific heat*density (W/J/cubic cm)
Aluminium 2.46

Beryllium3.29

Copper   3.49

Silver  2.41

Iron3.87

Thus copper and iron are better choices than Beryllium they also  
poses fewer machining diffculties


Bruce


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time-nuts

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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths
There's at least one known case where someone attempted to grind a 
beryllium mirror substrate using conventional methods without proper 
control of dust resulting in his death.


Bruce

Neville Michie wrote:
Just in case anyone finds a beryllium brick somewhere and tries to use 
it:

Beryllium is very very poisonous.
cheers,
Neville Michie

On 11/03/2010, at 10:08 AM, Bruce Griffiths wrote:


p...@pseng.org.uk wrote:

Looking at the specific heat of metals:
http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
Wouldn't Beryllium be better instead of aluminium?
I could foresee a few problems though eg machining holes at home, 
never mind where to get a block from.


Phil

Actually in this application minimising the volume of the metal block 
rather than its weight is probably better so one should use specific 
heat*density as a figure of merit.


METALSpecific heat*density (W/J/cubic cm)
Aluminium 2.46

Beryllium3.29

Copper   3.49

Silver  2.41

Iron3.87

Thus copper and iron are better choices than Beryllium they also 
poses fewer machining diffculties


Bruce


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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bob Camp
Hi

The same caution applies to the beryllium in beryllium oxide heat spreaders. 
You find them in old RF transistors and some RF tubes.

Bob

On Mar 10, 2010, at 6:45 PM, Bruce Griffiths wrote:

 There's at least one known case where someone attempted to grind a beryllium 
 mirror substrate using conventional methods without proper control of dust 
 resulting in his death.
 
 Bruce
 
 Neville Michie wrote:
 Just in case anyone finds a beryllium brick somewhere and tries to use it:
 Beryllium is very very poisonous.
 cheers,
 Neville Michie
 
 On 11/03/2010, at 10:08 AM, Bruce Griffiths wrote:
 
 p...@pseng.org.uk wrote:
 Looking at the specific heat of metals:
 http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
 Wouldn't Beryllium be better instead of aluminium?
 I could foresee a few problems though eg machining holes at home, never 
 mind where to get a block from.
 
 Phil
 
 Actually in this application minimising the volume of the metal block 
 rather than its weight is probably better so one should use specific 
 heat*density as a figure of merit.
 
 METALSpecific heat*density (W/J/cubic cm)
 Aluminium 2.46
 
 Beryllium3.29
 
 Copper   3.49
 
 Silver  2.41
 
 Iron3.87
 
 Thus copper and iron are better choices than Beryllium they also poses 
 fewer machining diffculties
 
 Bruce
 
 
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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths
Beryllium copper parts are also an issue although the beryllium content 
is only 0.3%-0.5% by weight.


Bruce

Bob Camp wrote:

Hi

The same caution applies to the beryllium in beryllium oxide heat spreaders. 
You find them in old RF transistors and some RF tubes.

Bob

On Mar 10, 2010, at 6:45 PM, Bruce Griffiths wrote:

   

There's at least one known case where someone attempted to grind a beryllium 
mirror substrate using conventional methods without proper control of dust 
resulting in his death.

Bruce

Neville Michie wrote:
 

Just in case anyone finds a beryllium brick somewhere and tries to use it:
Beryllium is very very poisonous.
cheers,
Neville Michie

On 11/03/2010, at 10:08 AM, Bruce Griffiths wrote:

   

p...@pseng.org.uk wrote:
 

Looking at the specific heat of metals:
http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
Wouldn't Beryllium be better instead of aluminium?
I could foresee a few problems though eg machining holes at home, never mind 
where to get a block from.

Phil

   

Actually in this application minimising the volume of the metal block rather 
than its weight is probably better so one should use specific heat*density as a 
figure of merit.

METALSpecific heat*density (W/J/cubic cm)
Aluminium 2.46

Beryllium3.29

Copper   3.49

Silver  2.41

Iron3.87

Thus copper and iron are better choices than Beryllium they also poses fewer 
machining diffculties

Bruce


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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Bob Camp
Hi

So getting back to the original idea.

Taking the other extreme - if you go for ~20 C / W on the insulation:

The mass of the block will be ~50X what it was before. 

1.6 on a side goes to ~5 on a side.

Surface area goes up ~10X. 

200 C/W with 2 foam goes to 20 C/W

Outer surface area goes to ~1.6X the inner surface area

Go to 4 of foam and you are pretty close.

Go to 8 of foam and you have some room left for things like wires and the like.

Resulting block is a bit under 2 feet on a side

Bob

On Mar 10, 2010, at 4:48 PM, Bruce Griffiths wrote:

 Surely you meant 1 square inch of styrofoam with the specified thickness??
 
 For a 100 hour (3.6E5 seconds) time constant and 1000 deg C/W thermal 
 resistance you need a thermal capacitance of 3.6E5/1E3 = 360 J/C
 or 360/0.8371 = 430 gm of Aluminium which has a volume of 430/2.7 = 159 cc.
 
 You still have the thermal radiation coupling problem through the infrared 
 transparent insulator.
 Gold plating the aluminium will help.
 
 Even if you solve the thermal radiation problem, the thermal conductance of 
 any leads bringing power or signals to or from the clock will be an major 
 problem even if you use constantan or austenetic stainless steel leads.
 
 Bruce
 
 Brooke Clarke wrote:
 Hi Bruce:
 
 If a square meter of Styrofoam is 1.5 deg C/W then a cubic  inch would be 
 39.37 * 39.37 * 1.5 or 2,325 deg C/W
 
 The DS3231 dissipates about 1 mw when running.  I'm not sure how to come up 
 with an allowable temp increase, but suspect it's based on not exceeding the 
 max allowed operating temp.  But for this part the Temp vs. freq curve is 
 flattest at room temp so best to minimize the temp rise.
 So:  (1 deg C) / (0.001 W) = 1000 deg C/W, the same number you had.
 
 That requires 185 g of Aluminum or about 69 cc volume or 4.25 cubic inches.  
 That's a block about 1.62 on a side.
 
 How does that look?
 
 Have Fun,
 
 Brooke Clarke
 http://www.PRC68.com
 
 
 Bruce Griffiths wrote:
 Thermal resistance is measured in degrees (C or K or ..) per watt.
 Its inversely proportional to area and proportional to thickness.
 
 I think the clueless clown who created that table means that for a 1 square 
 meter panel of the specified thickness the thermal resistance is the 
 tabulated value measured in Kelvin/Watt.
 
 Bruce
 
 Brooke Clarke wrote:
 Hi Bruce:
 
 What does m2K/W mean?  See:
 http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm
 
 50 mm it's about 1.5 and for 100 mm it's about 3.
 
 Have Fun,
 
 Brooke Clarke
 http://www.PRC68.com
 
 
 Bruce Griffiths wrote:
 Bruce Griffiths wrote:
 Brooke Clarke wrote:
 Hi:
 
 For some time I've considered surrounding a free running 32678 Hz 
 oscillator (like a Dallas 32khz, or one of the newer Maxim units) with 
 thermal mass and insulation in order to get the time constant into the 
 range of some days.  To get a feel for it a simple experiment shows 
 that a half inch diameter brass rod 3.75 long (102 grams) has a 
 thermal time constant of about 6 min 35 seconds when wrapped lightly in 
 a towel.
 
 Is there a way to calculate the amount of aluminum and Styrofoam needed 
 to get a time constant of say 100 hours?
 
 This came up in relation to WWVB clocks that free run for most of the 
 time.  When you compare WWVB clocks it's not uncommon to see tens of 
 seconds difference between them.  http://www.prc68.com/I/Loop.shtml#TC
 
 Start with the maximum thermal resistance the application can withstand 
 (determined by internal dissipation and acceptable temperature rise 
 above ambient).
 
 If for example the dissipation is 10mW and acceptable temperature rise 
 10C then thermal resistance will be about 1000C/W.
 
 The thermal capacity required can then be calculated from the time 
 constant:
 
 C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.
 
 The required thickness of styrofoam can then be calculated from the 
 surface area of the aluminium block.
 
 Achieving a thermal resistance of 1000C/W may be a little difficult 
 without using radiation shields.
 
 Bruce
 
 
 Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 
 J/gm/C so the mass of Aluminium required would be 430gm if the thermal 
 resistance to ambient were 1000K/W. With a thermal resistance of 100C/W 
 you need 4.3Kg of aluminium 
 
 Bruce
 
 
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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread Brooke Clarke

Hi Bob:

I like the idea of a six inch on a side cube.  An outer aluminum box, 
styrofoam insulation, and a block of (copper, Aluminum, etc.) in the 
center. A DS3231 or similar RTC and a PIC with a DB-9 connector on one face.


Have Fun,

Brooke Clarke
http://www.PRC68.com


Bob Camp wrote:

Hi

So getting back to the original idea.

Taking the other extreme - if you go for ~20 C / W on the insulation:

The mass of the block will be ~50X what it was before.

1.6 on a side goes to ~5 on a side.

Surface area goes up ~10X.

200 C/W with 2 foam goes to 20 C/W

Outer surface area goes to ~1.6X the inner surface area

Go to 4 of foam and you are pretty close.

Go to 8 of foam and you have some room left for things like wires and the like.

Resulting block is a bit under 2 feet on a side

Bob

On Mar 10, 2010, at 4:48 PM, Bruce Griffiths wrote:

   

Surely you meant 1 square inch of styrofoam with the specified thickness??

For a 100 hour (3.6E5 seconds) time constant and 1000 deg C/W thermal 
resistance you need a thermal capacitance of 3.6E5/1E3 = 360 J/C
or 360/0.8371 = 430 gm of Aluminium which has a volume of 430/2.7 = 159 cc.

You still have the thermal radiation coupling problem through the infrared 
transparent insulator.
Gold plating the aluminium will help.

Even if you solve the thermal radiation problem, the thermal conductance of any 
leads bringing power or signals to or from the clock will be an major problem 
even if you use constantan or austenetic stainless steel leads.

Bruce

Brooke Clarke wrote:
 

Hi Bruce:

If a square meter of Styrofoam is 1.5 deg C/W then a cubic  inch would be 39.37 
* 39.37 * 1.5 or 2,325 deg C/W

The DS3231 dissipates about 1 mw when running.  I'm not sure how to come up 
with an allowable temp increase, but suspect it's based on not exceeding the 
max allowed operating temp.  But for this part the Temp vs. freq curve is 
flattest at room temp so best to minimize the temp rise.
So:  (1 deg C) / (0.001 W) = 1000 deg C/W, the same number you had.

That requires 185 g of Aluminum or about 69 cc volume or 4.25 cubic inches.  That's 
a block about 1.62 on a side.

How does that look?

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:
   

Thermal resistance is measured in degrees (C or K or ..) per watt.
Its inversely proportional to area and proportional to thickness.

I think the clueless clown who created that table means that for a 1 square 
meter panel of the specified thickness the thermal resistance is the tabulated 
value measured in Kelvin/Watt.

Bruce

Brooke Clarke wrote:
 

Hi Bruce:

What does m2K/W mean?  See:
http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

50 mm it's about 1.5 and for 100 mm it's about 3.

Have Fun,

Brooke Clarke
http://www.PRC68.com


Bruce Griffiths wrote:
   

Bruce Griffiths wrote:
 

Brooke Clarke wrote:
   

Hi:

For some time I've considered surrounding a free running 32678 Hz oscillator (like a 
Dallas 32khz, or one of the newer Maxim units) with thermal mass and insulation in 
order to get the time constant into the range of some days.  To get a feel for it a 
simple experiment shows that a half inch diameter brass rod 3.75 long (102 
grams) has a thermal time constant of about 6 min 35 seconds when wrapped lightly in 
a towel.

Is there a way to calculate the amount of aluminum and Styrofoam needed to get 
a time constant of say 100 hours?

This came up in relation to WWVB clocks that free run for most of the time.  
When you compare WWVB clocks it's not uncommon to see tens of seconds 
difference between them.  http://www.prc68.com/I/Loop.shtml#TC

 

Start with the maximum thermal resistance the application can withstand 
(determined by internal dissipation and acceptable temperature rise above 
ambient).

If for example the dissipation is 10mW and acceptable temperature rise 10C then 
thermal resistance will be about 1000C/W.

The thermal capacity required can then be calculated from the time constant:

C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from the surface 
area of the aluminium block.

Achieving a thermal resistance of 1000C/W may be a little difficult without 
using radiation shields.

Bruce


   

Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 J/gm/C so 
the mass of Aluminium required would be 430gm if the thermal resistance to 
ambient were 1000K/W. With a thermal resistance of 100C/W you need 4.3Kg of 
aluminium 

Bruce


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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Neville Michie


I have been wondering about achieving the rated thermal resistance  
from plastic foam,
the problem being that radiant transmission may be very strong  
through the foam.
What happens if you interleave concentric sheets of foam plastic with  
aluminium foil? (taking care to keep the foil

on isothermal surfaces)
Will this stop the radiant transfer and leave only the thermal  
conduction of the plastic foam?

cheers, Neville Michie

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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bob Camp
Hi

That raises the interesting question of weather radiant transfer is already 
included in the rated thermal resistance. My guess is that the 8 of foam is 
enough to cover any radiation issues and still get you above 20 C / W. 

Since you are probably starting with 1 or 2 slabs, including the aluminum foil 
would be pretty easy. It can't hurt and it might help.

Bob

On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:

 
 I have been wondering about achieving the rated thermal resistance from 
 plastic foam,
 the problem being that radiant transmission may be very strong through the 
 foam.
 What happens if you interleave concentric sheets of foam plastic with 
 aluminium foil? (taking care to keep the foil
 on isothermal surfaces)
 Will this stop the radiant transfer and leave only the thermal conduction of 
 the plastic foam?
 cheers, Neville Michie
 
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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths
Radiative heat transfer (for a surface with an emissivity of 1) is 
around 150uW/square cm /degreeC at 300K.

That's equivalent to about 10cm of styrofoam.

It seems unlikely that the radiative heat transfer component is included 
in the thermal resistance rating for Styrofoam.


The radiative component is independent of insulation thickness where the 
insulation doesnt absorb in the 10-30um infrared region.


Adding carbon black to the foam appears to increase the thermal 
resistance of 25mm thick foam by about 10%.


Bruce

Bob Camp wrote:

Hi

That raises the interesting question of weather radiant transfer is already included 
in the rated thermal resistance. My guess is that the 8 of foam is enough to 
cover any radiation issues and still get you above 20 C / W.

Since you are probably starting with 1 or 2 slabs, including the aluminum foil 
would be pretty easy. It can't hurt and it might help.

Bob

On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:

   

I have been wondering about achieving the rated thermal resistance from plastic 
foam,
the problem being that radiant transmission may be very strong through the foam.
What happens if you interleave concentric sheets of foam plastic with aluminium 
foil? (taking care to keep the foil
on isothermal surfaces)
Will this stop the radiant transfer and leave only the thermal conduction of 
the plastic foam?
cheers, Neville Michie

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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths

Oops forgot a factor of 4
Radiative heat transfer for surface with an emissivity of 1 at 300K is 
about 612uW/square cm/degree C

which is equivalent to about 25mm of styrofoam.

Which raises the question what's the emissivity of the isothermal 
surface used when measuring the thermal resistance of a slab of styrofoam?


Bruce

Bruce Griffiths wrote:
Radiative heat transfer (for a surface with an emissivity of 1) is 
around 150uW/square cm /degreeC at 300K.

That's equivalent to about 10cm of styrofoam.

It seems unlikely that the radiative heat transfer component is 
included in the thermal resistance rating for Styrofoam.


The radiative component is independent of insulation thickness where 
the insulation doesnt absorb in the 10-30um infrared region.


Adding carbon black to the foam appears to increase the thermal 
resistance of 25mm thick foam by about 10%.


Bruce

Bob Camp wrote:

Hi

That raises the interesting question of weather radiant transfer is 
already included in the rated thermal resistance. My guess is that 
the 8 of foam is enough to cover any radiation issues and still get 
you above 20 C / W.


Since you are probably starting with 1 or 2 slabs, including the 
aluminum foil would be pretty easy. It can't hurt and it might help.


Bob

On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:

I have been wondering about achieving the rated thermal resistance 
from plastic foam,
the problem being that radiant transmission may be very strong 
through the foam.
What happens if you interleave concentric sheets of foam plastic 
with aluminium foil? (taking care to keep the foil

on isothermal surfaces)
Will this stop the radiant transfer and leave only the thermal 
conduction of the plastic foam?

cheers, Neville Michie

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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bob Camp
Hi

Since styrofoam is being rated as a building insulation, it's reasonable to 
believe that the material on both sides is up around 1. I highly doubt that 
somebody tossing styrofoam in walls is going to add a radiation factor ...

In our application we're talking about a metal block inside a metal enclosure, 
polishing the surfaces could drop the emissivity by 10X.  If the budget 
allows, you could gold plate the surfaces in addition to polishing them .

Bob


On Mar 10, 2010, at 8:01 PM, Bruce Griffiths wrote:

 Oops forgot a factor of 4
 Radiative heat transfer for surface with an emissivity of 1 at 300K is about 
 612uW/square cm/degree C
 which is equivalent to about 25mm of styrofoam.
 
 Which raises the question what's the emissivity of the isothermal surface 
 used when measuring the thermal resistance of a slab of styrofoam?
 
 Bruce
 
 Bruce Griffiths wrote:
 Radiative heat transfer (for a surface with an emissivity of 1) is around 
 150uW/square cm /degreeC at 300K.
 That's equivalent to about 10cm of styrofoam.
 
 It seems unlikely that the radiative heat transfer component is included in 
 the thermal resistance rating for Styrofoam.
 
 The radiative component is independent of insulation thickness where the 
 insulation doesnt absorb in the 10-30um infrared region.
 
 Adding carbon black to the foam appears to increase the thermal resistance 
 of 25mm thick foam by about 10%.
 
 Bruce
 
 Bob Camp wrote:
 Hi
 
 That raises the interesting question of weather radiant transfer is already 
 included in the rated thermal resistance. My guess is that the 8 of foam 
 is enough to cover any radiation issues and still get you above 20 C / W.
 
 Since you are probably starting with 1 or 2 slabs, including the aluminum 
 foil would be pretty easy. It can't hurt and it might help.
 
 Bob
 
 On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:
 
 I have been wondering about achieving the rated thermal resistance from 
 plastic foam,
 the problem being that radiant transmission may be very strong through the 
 foam.
 What happens if you interleave concentric sheets of foam plastic with 
 aluminium foil? (taking care to keep the foil
 on isothermal surfaces)
 Will this stop the radiant transfer and leave only the thermal conduction 
 of the plastic foam?
 cheers, Neville Michie
 
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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths
There's a small problem with my calculation and the published figures 
for the thermal resistance of styrofoam.
If the measurements include radiative transfers the thermal resistance 
per unit area of a styrofoam slab should reach a limiting value (when 
the radiative transfer component dominates) as the thickness is increased.

Possibilities

1) My calculation is incorrect.

2) Infrared absorption in thick styrofoam slabs is significant.

3) The tabulated figures for the thermal resistance of styrofoam are 
merely scaled up from the values measured with thin sheets.
This gives misleading values for thick sheets if the tabulated values 
include radiative transfer.


Bruce

Bob Camp wrote:

Hi

Since styrofoam is being rated as a building insulation, it's reasonable to 
believe that the material on both sides is up around 1. I highly doubt that 
somebody tossing styrofoam in walls is going to add a radiation factor ...

In our application we're talking about a metal block inside a metal enclosure, 
polishing the surfaces could drop the emissivity by10X.  If the budget allows, 
you could gold plate the surfaces in addition to polishing them .

Bob


On Mar 10, 2010, at 8:01 PM, Bruce Griffiths wrote:

   

Oops forgot a factor of 4
Radiative heat transfer for surface with an emissivity of 1 at 300K is about 
612uW/square cm/degree C
which is equivalent to about 25mm of styrofoam.

Which raises the question what's the emissivity of the isothermal surface used 
when measuring the thermal resistance of a slab of styrofoam?

Bruce

Bruce Griffiths wrote:
 

Radiative heat transfer (for a surface with an emissivity of 1) is around 
150uW/square cm /degreeC at 300K.
That's equivalent to about 10cm of styrofoam.

It seems unlikely that the radiative heat transfer component is included in the 
thermal resistance rating for Styrofoam.

The radiative component is independent of insulation thickness where the 
insulation doesnt absorb in the 10-30um infrared region.

Adding carbon black to the foam appears to increase the thermal resistance of 
25mm thick foam by about 10%.

Bruce

Bob Camp wrote:
   

Hi

That raises the interesting question of weather radiant transfer is already included 
in the rated thermal resistance. My guess is that the 8 of foam is enough to 
cover any radiation issues and still get you above 20 C / W.

Since you are probably starting with 1 or 2 slabs, including the aluminum foil 
would be pretty easy. It can't hurt and it might help.

Bob

On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:

 

I have been wondering about achieving the rated thermal resistance from plastic 
foam,
the problem being that radiant transmission may be very strong through the foam.
What happens if you interleave concentric sheets of foam plastic with aluminium 
foil? (taking care to keep the foil
on isothermal surfaces)
Will this stop the radiant transfer and leave only the thermal conduction of 
the plastic foam?
cheers, Neville Michie

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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bob Camp
Hi

Low density (1 or 2 lb / cu ft) urethane foam is going to be a better insulator 
than styrofoam. I believe it's reasonably opaque at IR.

Bob

On Mar 10, 2010, at 8:23 PM, Bruce Griffiths wrote:

 There's a small problem with my calculation and the published figures for the 
 thermal resistance of styrofoam.
 If the measurements include radiative transfers the thermal resistance per 
 unit area of a styrofoam slab should reach a limiting value (when the 
 radiative transfer component dominates) as the thickness is increased.
 Possibilities
 
 1) My calculation is incorrect.
 
 2) Infrared absorption in thick styrofoam slabs is significant.
 
 3) The tabulated figures for the thermal resistance of styrofoam are merely 
 scaled up from the values measured with thin sheets.
 This gives misleading values for thick sheets if the tabulated values include 
 radiative transfer.
 
 Bruce
 
 Bob Camp wrote:
 Hi
 
 Since styrofoam is being rated as a building insulation, it's reasonable to 
 believe that the material on both sides is up around 1. I highly doubt that 
 somebody tossing styrofoam in walls is going to add a radiation factor ...
 
 In our application we're talking about a metal block inside a metal 
 enclosure, polishing the surfaces could drop the emissivity by10X.  If the 
 budget allows, you could gold plate the surfaces in addition to polishing 
 them .
 
 Bob
 
 
 On Mar 10, 2010, at 8:01 PM, Bruce Griffiths wrote:
 
   
 Oops forgot a factor of 4
 Radiative heat transfer for surface with an emissivity of 1 at 300K is 
 about 612uW/square cm/degree C
 which is equivalent to about 25mm of styrofoam.
 
 Which raises the question what's the emissivity of the isothermal surface 
 used when measuring the thermal resistance of a slab of styrofoam?
 
 Bruce
 
 Bruce Griffiths wrote:
 
 Radiative heat transfer (for a surface with an emissivity of 1) is around 
 150uW/square cm /degreeC at 300K.
 That's equivalent to about 10cm of styrofoam.
 
 It seems unlikely that the radiative heat transfer component is included 
 in the thermal resistance rating for Styrofoam.
 
 The radiative component is independent of insulation thickness where the 
 insulation doesnt absorb in the 10-30um infrared region.
 
 Adding carbon black to the foam appears to increase the thermal resistance 
 of 25mm thick foam by about 10%.
 
 Bruce
 
 Bob Camp wrote:
   
 Hi
 
 That raises the interesting question of weather radiant transfer is 
 already included in the rated thermal resistance. My guess is that the 8 
 of foam is enough to cover any radiation issues and still get you above 
 20 C / W.
 
 Since you are probably starting with 1 or 2 slabs, including the 
 aluminum foil would be pretty easy. It can't hurt and it might help.
 
 Bob
 
 On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:
 
 
 I have been wondering about achieving the rated thermal resistance from 
 plastic foam,
 the problem being that radiant transmission may be very strong through 
 the foam.
 What happens if you interleave concentric sheets of foam plastic with 
 aluminium foil? (taking care to keep the foil
 on isothermal surfaces)
 Will this stop the radiant transfer and leave only the thermal 
 conduction of the plastic foam?
 cheers, Neville Michie
 
 ___
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 To unsubscribe, go to 
 https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
 and follow the instructions there.
 
   
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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Bruce Griffiths

Depends on the duration of the experiment.
Urethanes arent well known for stability.

The low thermal resistance of close cell urethanes is largely due to 
their better retention of the blowing agent which has lower thermal 
conductivity than air.
Closed cell foam glass (however the sulphur dioxide released when a cell 
is broken may be an issue) is much more stable than plastic foams the 
thermal resistance of which slowly deteriorates due to gas diffusion 
(air diffuse in and blowing agent diffuses out).
The gradual permeation of the plastic foam by water vapour can also have 
a significant effect.


Foam glass is sometimes used to insulate very large cryogen tanks.

Bruce

Bob Camp wrote:

Hi

Low density (1 or 2 lb / cu ft) urethane foam is going to be a better insulator 
than styrofoam. I believe it's reasonably opaque at IR.

Bob

On Mar 10, 2010, at 8:23 PM, Bruce Griffiths wrote:

   

There's a small problem with my calculation and the published figures for the 
thermal resistance of styrofoam.
If the measurements include radiative transfers the thermal resistance per unit 
area of a styrofoam slab should reach a limiting value (when the radiative 
transfer component dominates) as the thickness is increased.
Possibilities

1) My calculation is incorrect.

2) Infrared absorption in thick styrofoam slabs is significant.

3) The tabulated figures for the thermal resistance of styrofoam are merely 
scaled up from the values measured with thin sheets.
This gives misleading values for thick sheets if the tabulated values include 
radiative transfer.

Bruce

Bob Camp wrote:
 

Hi

Since styrofoam is being rated as a building insulation, it's reasonable to 
believe that the material on both sides is up around 1. I highly doubt that 
somebody tossing styrofoam in walls is going to add a radiation factor ...

In our application we're talking about a metal block inside a metal enclosure, 
polishing the surfaces could drop the emissivity by10X.  If the budget allows, 
you could gold plate the surfaces in addition to polishing them .

Bob


On Mar 10, 2010, at 8:01 PM, Bruce Griffiths wrote:


   

Oops forgot a factor of 4
Radiative heat transfer for surface with an emissivity of 1 at 300K is about 
612uW/square cm/degree C
which is equivalent to about 25mm of styrofoam.

Which raises the question what's the emissivity of the isothermal surface used 
when measuring the thermal resistance of a slab of styrofoam?

Bruce

Bruce Griffiths wrote:

 

Radiative heat transfer (for a surface with an emissivity of 1) is around 
150uW/square cm /degreeC at 300K.
That's equivalent to about 10cm of styrofoam.

It seems unlikely that the radiative heat transfer component is included in the 
thermal resistance rating for Styrofoam.

The radiative component is independent of insulation thickness where the 
insulation doesnt absorb in the 10-30um infrared region.

Adding carbon black to the foam appears to increase the thermal resistance of 
25mm thick foam by about 10%.

Bruce

Bob Camp wrote:

   

Hi

That raises the interesting question of weather radiant transfer is already included 
in the rated thermal resistance. My guess is that the 8 of foam is enough to 
cover any radiation issues and still get you above 20 C / W.

Since you are probably starting with 1 or 2 slabs, including the aluminum foil 
would be pretty easy. It can't hurt and it might help.

Bob

On Mar 10, 2010, at 7:29 PM, Neville Michie wrote:


 

I have been wondering about achieving the rated thermal resistance from plastic 
foam,
the problem being that radiant transmission may be very strong through the foam.
What happens if you interleave concentric sheets of foam plastic with aluminium 
foil? (taking care to keep the foil
on isothermal surfaces)
Will this stop the radiant transfer and leave only the thermal conduction of 
the plastic foam?
cheers, Neville Michie

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and 

Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread jimlux

Brooke Clarke wrote:

Hi Bruce:

What does m2K/W mean?  See:
http://building.dow.com/europe/uk/proddata/styrofoam/thermal.htm

50 mm it's about 1.5 and for 100 mm it's about 3.



thermal resistance (you can tell because it's degrees/watt, as opposed 
to watts/degree which would be conductivity)


square meter Kelvin/Watt.

and doubling for a doubling in thickness makes perfect sense.




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Re: [time-nuts] Thermal Time Constant

2010-03-10 Thread jimlux

Brooke Clarke wrote:

Hi Bruce:

If a square meter of Styrofoam is 1.5 deg C/W then a cubic inch would be 
39.37 * 39.37 * 1.5 or 2,325 deg C/W


The DS3231 dissipates about 1 mw when running.  I'm not sure how to come 
up with an allowable temp increase, but suspect it's based on not 
exceeding the max allowed operating temp.  But for this part the Temp 
vs. freq curve is flattest at room temp so best to minimize the temp rise.

So:  (1 deg C) / (0.001 W) = 1000 deg C/W, the same number you had.

That requires 185 g of Aluminum or about 69 cc volume or 4.25 cubic 
inches.  That's a block about 1.62 on a side.


How does that look?




you can also use U.S. R-values..  BTU/hr/ft^2/deg F.

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Re: [time-nuts] Thermal time constant

2010-03-10 Thread jimlux

Bob Camp wrote:

Hi

The gotcha is that you are interested in the amount of heat per cubic foot rather than the amount of heat per pound. You need to take the standard heat per weight numbers and convert them to heat per volume numbers. 

Of the things you can easily get, copper is good. Steel is not as good as copper, but better than aluminum. 


Bob




Gold is your friend. Mercury has convective losses because it's a 
liquid.  Platinum or Osmium would also be ok.


You might want something that is dense but lower conductivity.. lead? 
Depleted Uranium? (DU is available very cheaply if you can take 80,000 
pound lots)


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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Don Latham

water is pretty good, too and cheap. Coupling to it is easy as well.
Don

- Original Message - 
From: jimlux jim...@earthlink.net
To: Discussion of precise time and frequency measurement 
time-nuts@febo.com

Sent: Wednesday, March 10, 2010 9:35 PM
Subject: Re: [time-nuts] Thermal time constant



Bob Camp wrote:

Hi

The gotcha is that you are interested in the amount of heat per cubic 
foot rather than the amount of heat per pound. You need to take the 
standard heat per weight numbers and convert them to heat per volume 
numbers. Of the things you can easily get, copper is good. Steel is not 
as good as copper, but better than aluminum. Bob




Gold is your friend. Mercury has convective losses because it's a liquid. 
Platinum or Osmium would also be ok.


You might want something that is dense but lower conductivity.. lead? 
Depleted Uranium? (DU is available very cheaply if you can take 80,000 
pound lots)


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Re: [time-nuts] Thermal time constant

2010-03-10 Thread Predrag Dukic



How well depleted it really is?  Uranium separation is not perfect. 
Some radioactivity is still left.


I don't think it is healthy to have it beside You for a long time.

Certainly not 8 pounds :))






At 05:35 11.3.2010, you wrote:

Bob Camp wrote:

Hi
The gotcha is that you are interested in the amount of heat per 
cubic foot rather than the amount of heat per pound. You need to 
take the standard heat per weight numbers and convert them to heat 
per volume numbers.
Of the things you can easily get, copper is good. Steel is not as 
good as copper, but better than aluminum.

Bob


Gold is your friend. Mercury has convective losses because it's a 
liquid.  Platinum or Osmium would also be ok.


You might want something that is dense but lower conductivity.. 
lead? Depleted Uranium? (DU is available very cheaply if you can 
take 80,000 pound lots)


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The message was checked by ESET NOD32 Antivirus.

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Re: [time-nuts] Thermal Time Constant

2010-03-09 Thread Matthew Smith

Quoth Brooke Clarke at 10/03/10 10:22...

...like a Dallas 32khz, or one of the newer Maxim units...


There's a Maxim part to supersede the DS32kHz?  I know that my regular 
vendors [Farnell, Soanar, Futurlec] in Australia don't stock the 
DS32kHz, which makes them mega-expensive to acquire.


--
Matthew Smith
Smiffytech - Technology Consulting  Web Application Development
Business:  http://www.smiffytech.com/
Blog/personal: http://www.smiffysplace.com/
LinkedIn:  http://www.linkedin.com/in/smiffy
Skype: msmiffy
Twitter:   @smiffy

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Re: [time-nuts] Thermal Time Constant

2010-03-09 Thread Bruce Griffiths

Brooke Clarke wrote:

Hi:

For some time I've considered surrounding a free running 32678 Hz 
oscillator (like a Dallas 32khz, or one of the newer Maxim units) with 
thermal mass and insulation in order to get the time constant into the 
range of some days.  To get a feel for it a simple experiment shows 
that a half inch diameter brass rod 3.75 long (102 grams) has a 
thermal time constant of about 6 min 35 seconds when wrapped lightly 
in a towel.


Is there a way to calculate the amount of aluminum and Styrofoam 
needed to get a time constant of say 100 hours?


This came up in relation to WWVB clocks that free run for most of the 
time.  When you compare WWVB clocks it's not uncommon to see tens of 
seconds difference between them.  http://www.prc68.com/I/Loop.shtml#TC


Start with the maximum thermal resistance the application can withstand 
(determined by internal dissipation and acceptable temperature rise 
above ambient).


If for example the dissipation is 10mW and acceptable temperature rise 
10C then thermal resistance will be about 1000C/W.


The thermal capacity required can then be calculated from the time constant:

C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from the 
surface area of the aluminium block.


Achieving a thermal resistance of 1000C/W may be a little difficult 
without using radiation shields.


Bruce


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Re: [time-nuts] Thermal Time Constant

2010-03-09 Thread Bruce Griffiths

Bruce Griffiths wrote:

Brooke Clarke wrote:

Hi:

For some time I've considered surrounding a free running 32678 Hz 
oscillator (like a Dallas 32khz, or one of the newer Maxim units) 
with thermal mass and insulation in order to get the time constant 
into the range of some days.  To get a feel for it a simple 
experiment shows that a half inch diameter brass rod 3.75 long (102 
grams) has a thermal time constant of about 6 min 35 seconds when 
wrapped lightly in a towel.


Is there a way to calculate the amount of aluminum and Styrofoam 
needed to get a time constant of say 100 hours?


This came up in relation to WWVB clocks that free run for most of the 
time.  When you compare WWVB clocks it's not uncommon to see tens of 
seconds difference between them.  http://www.prc68.com/I/Loop.shtml#TC


Start with the maximum thermal resistance the application can 
withstand (determined by internal dissipation and acceptable 
temperature rise above ambient).


If for example the dissipation is 10mW and acceptable temperature rise 
10C then thermal resistance will be about 1000C/W.


The thermal capacity required can then be calculated from the time 
constant:


C= 3.6E5/1E3 = 360 J/C requires about 7.2 kg of aluminium.

The required thickness of styrofoam can then be calculated from the 
surface area of the aluminium block.


Achieving a thermal resistance of 1000C/W may be a little difficult 
without using radiation shields.


Bruce


Oops, the specific heat of Alum9inium is about 0.2Cal/gm/C or 0.8371 
J/gm/C so the mass of Aluminium required would be 430gm if the thermal 
resistance to ambient were 1000K/W. With a thermal resistance of 100C/W 
you need 4.3Kg of aluminium 


Bruce


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