Re: [Tutor] Python Idioms?
On 04/01/2015 11:04 AM, Alan Gauld wrote: On 01/04/15 05:50, Jim Mooney wrote: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Personally I'd have used slicing in this example: zip(s[::2],s[1::2]) With an emphasis on *in this example*. The idiom you are citing works on any iterable, not all of which support slicing and the slicing version requires two passes over the data. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
[Tutor] Python Idioms?
I'm looking at this and can't see how it works, although I understand zipping and unpacking. The docs say it's a Python idiom. Does idiom mean it works in a special way so I can't figure it out from basic principles? It looks to me like the iterator in the list gets doubled, so the zip should make it [(1,1),(2,2),(3,3),... ], not [(1,2),(3,4),...] What am I missing here? s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] https://docs.python.org/3/library/functions.html#zip -- Jim ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On 01/04/15 05:50, Jim Mooney wrote: I'm looking at this and can't see how it works, although I understand zipping and unpacking. The docs say it's a Python idiom. Does idiom mean it works in a special way so I can't figure it out from basic principles? No idiom means a common pattern of usage in the community. In this case thats true of zip(), its less true of this case which is somewhat obscure. It looks to me like the iterator in the list gets doubled, so the zip should make it [(1,1),(2,2),(3,3),... ], not [(1,2),(3,4),...] What am I missing here? The fact that thew list contains a reference to an iterator so when you multiply by two you get two references to *the same* iterator. So each time the iterator gets accessed it returns the next number in the sequence, not the same number twice. s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Personally I'd have used slicing in this example: zip(s[::2],s[1::2]) Is that any clearer? -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On 04/01/2015 12:50 AM, Jim Mooney wrote: I'm looking at this and can't see how it works, although I understand zipping and unpacking. The docs say it's a Python idiom. Does idiom mean it works in a special way so I can't figure it out from basic principles? It looks to me like the iterator in the list gets doubled, so the zip should make it [(1,1),(2,2),(3,3),... ], not [(1,2),(3,4),...] What am I missing here? s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] https://docs.python.org/3/library/functions.html#zip In that same thread, Peter Otten posted the following, which I think is probably a bit clearer: flat_pairs = ['broadcast', 'd8on', 'broadcast', 'd11on'] it = iter(flat_pairs) pairs = list(zip(it, it)) pairs That does exactly the same thing, but in the first one you can replace the '2' with a variable, to make variable sized tuples. In both cases, the trick is that the same iterator is used twice in the expression, so even though zip is taking one from each, there are no duplications. If you know the original data is a list, or at least that it can do slices, then you can do Alan's suggestion: zip(s[::2],s[1::2]) Or you could try: from itertools import islice pairs = zip(islice(s, 0, , 2), islice(s, 1, , 2)) -- DaveA ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On 01/04/15 11:04, Wolfgang Maier wrote: On 04/01/2015 11:04 AM, Alan Gauld wrote: On 01/04/15 05:50, Jim Mooney wrote: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Personally I'd have used slicing in this example: zip(s[::2],s[1::2]) With an emphasis on *in this example*. The idiom you are citing works on any iterable, not all of which support slicing and the slicing version requires two passes over the data. Agreed, but readability always trumps performance, unless performance is critical. In which case readability usually trumps performance. And especially on a beginners list. -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On 01/04/2015 11:50, Alan Gauld wrote: On 01/04/15 11:04, Wolfgang Maier wrote: On 04/01/2015 11:04 AM, Alan Gauld wrote: On 01/04/15 05:50, Jim Mooney wrote: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Personally I'd have used slicing in this example: zip(s[::2],s[1::2]) With an emphasis on *in this example*. The idiom you are citing works on any iterable, not all of which support slicing and the slicing version requires two passes over the data. Agreed, but readability always trumps performance, unless performance is critical. In which case readability usually trumps performance. And especially on a beginners list. In which case I'll stick with the more-itertools pairwise() function which I pointed out on another thread just yesterday. From http://pythonhosted.org//more-itertools/api.html quote Returns an iterator of paired items, overlapping, from the original take(4, pairwise(count())) [(0, 1), (1, 2), (2, 3), (3, 4)] /quote -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On Tue, Mar 31, 2015 at 09:50:43PM -0700, Jim Mooney wrote: I'm looking at this and can't see how it works, although I understand zipping and unpacking. The docs say it's a Python idiom. Does idiom mean it works in a special way so I can't figure it out from basic principles? It looks to me like the iterator in the list gets doubled, so the zip should make it [(1,1),(2,2),(3,3),... ], not [(1,2),(3,4),...] What am I missing here? The secret is that list multiplication doesn't make *copies*, it replicates multiple references to the same object. s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Let's pull this apart and see how it ticks. It may actually be more obvious what is going on if we use more than two references, and do by hand what * does for us above. py s = [100, 200, 300, 400, 500, 600, 700, 800, 900] py it = iter(s) # One iterator object. py next(it), next(it), next(it) # Call next three times. (100, 200, 300) py args = [it, it, it] # Like [it]*3 py for x in args: ... print(next(x)) # Like next(it). ... 400 500 600 We created *one* iterator. First we called next(it) three times, by hand, which yields the first three items in the list s. Then we stick the iterator in a new list three times, and loop over that, calling next() each time. That is equivalent to next(it) three more times, which gives us the next three items. Finally, we pass them to zip(), as separate arguments: py list(zip(*args)) [(700, 800, 900)] Which gives us the next three items. At that point, we run out of items, and zip completes. Putting it (almost) all together now. Remember that `it` above, the iterator, is now exhausted. It has walked all the way through list s, so we need a new iterator to make it work again: py list(it) # it is exhausted. [] py it = iter(s) # So re-create it. py list(zip(*[it]*3)) [(100, 200, 300), (400, 500, 600), (700, 800, 900)] We can avoid the temporary variable: py list(zip(*[iter(s)]*3)) [(100, 200, 300), (400, 500, 600), (700, 800, 900)] -- Steve ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On Wed, Apr 01, 2015 at 12:06:33PM +0100, Mark Lawrence wrote: In which case I'll stick with the more-itertools pairwise() function which I pointed out on another thread just yesterday. From http://pythonhosted.org//more-itertools/api.html quote Returns an iterator of paired items, overlapping, from the original take(4, pairwise(count())) [(0, 1), (1, 2), (2, 3), (3, 4)] I betcha the implementation of pairwise is something really close to: def pairwise(iterable): it = iter(iterable) return itertools.izip(it, it) for Python 2, and for Python 3: def pairwise(iterable): it = iter(iterable) return zip(it, it) which is all well and good, but what if you want triplets, not pairs? def threewise(iterable): it = iter(iterable) return zip(it, it, it) I don't think it's very practical to include a *wise for every possible number of items... Let's deal some cards! import random cards = [] for value in A 2 3 4 5 6 7 8 9 10 J Q K.split(): for suit in u♠♣♦♥: cards.append(value + suit) random.shuffle(cards) deck = iter(cards) hands = zip(*[deck]*8) for name in Groucho Chico Harpo Zeppo Gummo.split(): print(%s gets dealt %s % (name, ','.join(next(hands I get these results, but being random of course you will get something different: Groucho gets dealt 8♣,2♠,5♥,7♣,8♦,7♠,6♥,8♥ Chico gets dealt Q♦,K♦,3♥,7♦,K♠,J♠,9♥,10♥ Harpo gets dealt 10♣,4♦,4♥,A♠,A♦,K♥,3♠,J♥ Zeppo gets dealt 5♣,A♥,3♦,Q♣,9♣,9♠,4♣,2♥ Gummo gets dealt J♦,Q♠,4♠,10♦,J♣,6♦,5♦,A♣ -- Steve ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On 01/04/2015 14:16, Steven D'Aprano wrote: On Wed, Apr 01, 2015 at 12:06:33PM +0100, Mark Lawrence wrote: In which case I'll stick with the more-itertools pairwise() function which I pointed out on another thread just yesterday. From http://pythonhosted.org//more-itertools/api.html quote Returns an iterator of paired items, overlapping, from the original take(4, pairwise(count())) [(0, 1), (1, 2), (2, 3), (3, 4)] I betcha the implementation of pairwise is something really close to: def pairwise(iterable): it = iter(iterable) return itertools.izip(it, it) for Python 2, and for Python 3: def pairwise(iterable): it = iter(iterable) return zip(it, it) Not a bad attempt :) It's actually. def pairwise(iterable): Returns an iterator of paired items, overlapping, from the original take(4, pairwise(count())) [(0, 1), (1, 2), (2, 3), (3, 4)] a, b = tee(iterable) next(b, None) return zip(a, b) -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
[Tutor] Python serial interface
Hi all, This is a very general question, but I was wondering if anyone has experience using python to interface with a serial port? If so, can you please forward any useful resources? Thanks! Colin ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
On 01/04/2015 15:43, Colin Ross wrote: Hi all, This is a very general question, but I was wondering if anyone has experience using python to interface with a serial port? If so, can you please forward any useful resources? Thanks! Colin http://pyserial.sourceforge.net/ -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
Pyserial is python 2.x and 3.x compatible. It is very widely used and is stable. http://pyserial.sourceforge.net/ What is your application? Sometimes you can use a higher level module that makes use of pyserial. Francois -- raspberry-python.blogspot.com - www.pyptug.org - www.3DFutureTech.info - @f_dion ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
I am using the following controller: http://www.aerotech.com/product-catalog/drives-and-drive-racks/ensemble-mp.aspx Which does not specifically list python as one of the accepted languages, but I guess this does not mean it is not possible. Colin On Wed, Apr 1, 2015 at 12:58 PM, Colin Ross colin.ross@gmail.com wrote: Thank you Francois, this gives me a lot to think about! I really appreciate your feedback. Colin On Wed, Apr 1, 2015 at 12:50 PM, Francois Dion francois.d...@gmail.com wrote: On Wed, Apr 1, 2015 at 11:01 AM, Colin Ross colin.ross@gmail.com wrote: Hi Francois, Thank you for the fast reply! I am looking to control a brushless servo motor ( http://www.aerotech.com/product-catalog/motors/rotary-motors/bms-series.aspx) that drives a rotary stage. These motors are not controlled by serial, you'll need a brushless controller. In turn the controller might be or not serial, or ip or something else altogether (PWM is typical). They do have an rs-422 connection, but that is for a feedback signal. So you are building a feedback control system. If you google that and python you'll find several useful references, including a design and analysis module (but not control): https://pypi.python.org/pypi/control/0.6.6 http://sourceforge.net/projects/python-control/ Nothing out of the box for your application, obviously. Also, the motor control itself will depend on the microprocessor hardware you are using and the motor controller. Assuming PWM, the raspberry pi has a software PWM module in Python. Same with micropython. Anything else is pretty much DIY. As for the overall concept of control systems, Chapter 9 of Real World Instrumentation ( http://shop.oreilly.com/product/9780596809577.do ) will give you an overview of what is involved (with some python example, but not directly applicable to your system). Francois -- raspberry-python.blogspot.com - www.pyptug.org - www.3DFutureTech.info http://www.3dfuturetech.info/ - @f_dion ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
Hi Francois, Thank you for the fast reply! I am looking to control a brushless servo motor ( http://www.aerotech.com/product-catalog/motors/rotary-motors/bms-series.aspx) that drives a rotary stage. Colin On Wed, Apr 1, 2015 at 11:53 AM, Francois Dion francois.d...@gmail.com wrote: Pyserial is python 2.x and 3.x compatible. It is very widely used and is stable. http://pyserial.sourceforge.net/ What is your application? Sometimes you can use a higher level module that makes use of pyserial. Francois -- raspberry-python.blogspot.com - www.pyptug.org - www.3DFutureTech.info - @f_dion ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
On Wed, Apr 1, 2015 at 11:01 AM, Colin Ross colin.ross@gmail.com wrote: Hi Francois, Thank you for the fast reply! I am looking to control a brushless servo motor ( http://www.aerotech.com/product-catalog/motors/rotary-motors/bms-series.aspx) that drives a rotary stage. These motors are not controlled by serial, you'll need a brushless controller. In turn the controller might be or not serial, or ip or something else altogether (PWM is typical). They do have an rs-422 connection, but that is for a feedback signal. So you are building a feedback control system. If you google that and python you'll find several useful references, including a design and analysis module (but not control): https://pypi.python.org/pypi/control/0.6.6 http://sourceforge.net/projects/python-control/ Nothing out of the box for your application, obviously. Also, the motor control itself will depend on the microprocessor hardware you are using and the motor controller. Assuming PWM, the raspberry pi has a software PWM module in Python. Same with micropython. Anything else is pretty much DIY. As for the overall concept of control systems, Chapter 9 of Real World Instrumentation ( http://shop.oreilly.com/product/9780596809577.do ) will give you an overview of what is involved (with some python example, but not directly applicable to your system). Francois -- raspberry-python.blogspot.com - www.pyptug.org - www.3DFutureTech.info http://www.3dfuturetech.info/ - @f_dion ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
Thank you Francois, this gives me a lot to think about! I really appreciate your feedback. Colin On Wed, Apr 1, 2015 at 12:50 PM, Francois Dion francois.d...@gmail.com wrote: On Wed, Apr 1, 2015 at 11:01 AM, Colin Ross colin.ross@gmail.com wrote: Hi Francois, Thank you for the fast reply! I am looking to control a brushless servo motor ( http://www.aerotech.com/product-catalog/motors/rotary-motors/bms-series.aspx) that drives a rotary stage. These motors are not controlled by serial, you'll need a brushless controller. In turn the controller might be or not serial, or ip or something else altogether (PWM is typical). They do have an rs-422 connection, but that is for a feedback signal. So you are building a feedback control system. If you google that and python you'll find several useful references, including a design and analysis module (but not control): https://pypi.python.org/pypi/control/0.6.6 http://sourceforge.net/projects/python-control/ Nothing out of the box for your application, obviously. Also, the motor control itself will depend on the microprocessor hardware you are using and the motor controller. Assuming PWM, the raspberry pi has a software PWM module in Python. Same with micropython. Anything else is pretty much DIY. As for the overall concept of control systems, Chapter 9 of Real World Instrumentation ( http://shop.oreilly.com/product/9780596809577.do ) will give you an overview of what is involved (with some python example, but not directly applicable to your system). Francois -- raspberry-python.blogspot.com - www.pyptug.org - www.3DFutureTech.info http://www.3dfuturetech.info/ - @f_dion ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] How do I make pattern to find only '.html' file using Python Regular Expression?
Abdullah Al Imran abdalim...@live.com writes: How to do it using Python Regular Expression? Don't assume which tool you must use; instead, ask how best the problem can be solved. In the case of parsing HTML, regular expressions are a poor fit URL:http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags/1732454#1732454 because they're not doing the job of parsing. Use a parser which better understands HTML, like Beautiful Soup URL:https://pypi.python.org/pypi/BeautifulSoup. -- \ “An expert is a man who has made all the mistakes which can be | `\ made in a very narrow field.” —Niels Bohr | _o__) | Ben Finney ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
Mark Lawrence schreef: On 01/04/2015 11:50, Alan Gauld wrote: On 01/04/15 11:04, Wolfgang Maier wrote: On 04/01/2015 11:04 AM, Alan Gauld wrote: On 01/04/15 05:50, Jim Mooney wrote: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Personally I'd have used slicing in this example: zip(s[::2],s[1::2]) With an emphasis on *in this example*. The idiom you are citing works on any iterable, not all of which support slicing and the slicing version requires two passes over the data. Agreed, but readability always trumps performance, unless performance is critical. In which case readability usually trumps performance. And especially on a beginners list. In which case I'll stick with the more-itertools pairwise() function Which does not the same thing. Original: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Pairwise: take(4, pairwise(count())) [(0, 1), (1, 2), (2, 3), (3, 4)] Greetings, Roel -- The saddest aspect of life right now is that science gathers knowledge faster than society gathers wisdom. -- Isaac Asimov Roel Schroeven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On Wed, Apr 01, 2015 at 09:59:30PM +0100, Mark Lawrence wrote: [snip mass quoting] Yo are of course completely correct, I was conflating two different threads :) Hey guys, how about trimming some of the excessive quoting in your posts? Especially if you're going to complain about the annoyance of top-posting, bottom-posting without trimming is actually *worse* and more distruptive to ease of reading. After I've flipped through two pages of quotes without any new comments at all, I'm sorely tempted to just hit Delete on the rest unread. -- Steve ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Idioms?
On 01/04/2015 18:20, Roel Schroeven wrote: Mark Lawrence schreef: On 01/04/2015 11:50, Alan Gauld wrote: On 01/04/15 11:04, Wolfgang Maier wrote: On 04/01/2015 11:04 AM, Alan Gauld wrote: On 01/04/15 05:50, Jim Mooney wrote: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Personally I'd have used slicing in this example: zip(s[::2],s[1::2]) With an emphasis on *in this example*. The idiom you are citing works on any iterable, not all of which support slicing and the slicing version requires two passes over the data. Agreed, but readability always trumps performance, unless performance is critical. In which case readability usually trumps performance. And especially on a beginners list. In which case I'll stick with the more-itertools pairwise() function Which does not the same thing. Original: s = [1,2,3,4,5,6,7,8] list(zip(*[iter(s)]*2)) [(1, 2), (3, 4), (5, 6), (7, 8)] Pairwise: take(4, pairwise(count())) [(0, 1), (1, 2), (2, 3), (3, 4)] Greetings, Roel Yo are of course completely correct, I was conflating two different threads :) -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python serial interface
On 01/04/2015 17:14, Colin Ross wrote: I am using the following controller: http://www.aerotech.com/product-catalog/drives-and-drive-racks/ensemble-mp.aspx Which does not specifically list python as one of the accepted languages, but I guess this does not mean it is not possible. Colin Can you please stop top posting, it's extremely irritating trying to follow fairly long threads like this, thanks. -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
[Tutor] How do I make pattern to find only '.html' file using Python Regular Expression?
I have some HTML content where there are many links as the following pattern: a href=http://example.com/2013/01/problem1.html;Problem No-1/abr / I want to filter all the links into a list as: ['http://example.com/2013/01/problem1.html', 'http://example.com/2013/02/problem2.html'] How to do it using Python Regular Expression? If I want to filter all the links into a dictionary as: ['http://example.com/2013/01/problem1.html':'Problem No-1', 'http://example.com/2013/02/problem2.html ':'Problem No-2',] How do I do it? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] How do I make pattern to find only '.html' file using Python Regular Expression?
On 01/04/15 20:22, Abdullah Al Imran wrote: I have some HTML content where there are many links as the following pattern: a href=http://example.com/2013/01/problem1.html;Problem No-1/abr / I want to filter all the links into a list as: ['http://example.com/2013/01/problem1.html', 'http://example.com/2013/02/problem2.html'] How to do it using Python Regular Expression? You can try, but regular expressions are not a reliable way to parse HTML. You are much better to use a dedicated HTML parser such as the one found in htmllib in the standard library or a third party tool like BeautifulSoup. These recognise the different tag types and separate the content and data for you. You can then just ask for the parser to find a... tags and then fetch the data from each tag. HTH -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
