Re: [Tutor] Python 2.7 on Ubuntu 11.10 - Do not unintall
On 11/02/2011 02:26 AM, spa...@gmail.com wrote: Shouldn't this be treated as a bug then? As a user I should be allowed to uninstall the software I want to. Or you uninstalled other things by mistake? On Wed, Nov 2, 2011 at 6:18 AM, Joel Montes de Oca joelmonte...@gmail.com mailto:joelmonte...@gmail.com wrote: On Tue 01 Nov 2011 08:56:41 PM EDT, Max gmail wrote: Heh, yeah. It's usually a bad idea to do stuff like that (I know a guy (Windows) who deleted his OS of his system). On Nov 1, 2011, at 7:40 PM, Joel Montes de Oca wrote: I just discovered that it is a bad idea to complete uninstall Python 2.7 on Ubuntu 11.10. If you do, expect a lot of things not to work, mainly your system. haha I just reinstalled Python 2.7 and I hope things are not so bad now when I reboot. -- -Joel M. ___ Tutor maillist - Tutor@python.org mailto:Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor Yea, It wiped out GNOME and UNITY along with a few other applications. It wasn't a big deal tho, I just reinstalled ubuntu-desktop threw apt-get. :) -- -Joel M. ___ Tutor maillist - Tutor@python.org mailto:Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor -- http://spawgi.wordpress.com We can do it and do it better. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor Spawgi, Like a few people have mentioned before, this isn't a bug. Unity and GNOME rely on Python 2.7 to work, which is fine. When I uninstalled Python2.7 GNOME and Unity didn't have a way to run their py files, which results in a broken environment. The package manager was smart enough to list everything that was going to be uninstalled since they rely on Python. So instead of leaving broken systems on my computer, it uninstalled all the packages that would had been broken, including Unity and GNOME. I just want to add one thing that hasn't been mentioned yet. The only bug was the one called Joel M, which failed to read the uninstall list until later when I noticed my environments were being uninstalled. haha! Synaptic, the package manager I was using, listed everything that was going to be uninstalled but I didn't read it. I didn't realize how many system tools used python until later. Live and learn. It wasn't a big deal. All I had to do was reinstall Python2.7 and reboot. Of course, after the reboot, I didn't have an environment to log into. So I pressed Ctr + Alt + F1 to get into tty1 and then ran sudo apt-get install ubuntu-desktop. That took care of the missing environment. Then I restarted with sudo shutdown -r now. I didn't really need to do that since I think restarting X was enough but I restarted anyhow. As far as the comments about Ubuntu 11.10 being buggy. I don't think it's Ubuntu 11.10 that is buggy, I think it's Unity that is a bit buggy. I use Unity and sometimes applications do crash or fail to open when you click on their icons... Like I said, I think it's an issue with Unity but I can't say for sure since I haven't used another environment since I installed Ubuntu 11.10. -- -Joel M. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] login window using Tk
On 11/01/2011 02:18 PM, Alan Gauld wrote: On 01/11/11 18:09, Alexander Etter wrote: Hi, hopefully a more experience hacker can provide clarity, but how secure does this login need to be? I dont much about python in DRAM but your login sounds like it could be easily hacked. That depends entirely on how the user is authenticated. (assuming basic things like blanked password fields in the UI etc) For all we know the authentication could be against a central Single Sign On authentication server someplace. The OP didn't say. Question, once the code is compiled to a binary, can someone inject code to cause the hidden window to show, skipping the login altogether? -- -Joel M. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Python 2.7 on Ubuntu 11.10 - Do not unintall
I just discovered that it is a bad idea to complete uninstall Python 2.7 on Ubuntu 11.10. If you do, expect a lot of things not to work, mainly your system. haha I just reinstalled Python 2.7 and I hope things are not so bad now when I reboot. -- -Joel M. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python 2.7 on Ubuntu 11.10 - Do not unintall
On Tue 01 Nov 2011 08:56:41 PM EDT, Max gmail wrote: Heh, yeah. It's usually a bad idea to do stuff like that (I know a guy (Windows) who deleted his OS of his system). On Nov 1, 2011, at 7:40 PM, Joel Montes de Oca wrote: I just discovered that it is a bad idea to complete uninstall Python 2.7 on Ubuntu 11.10. If you do, expect a lot of things not to work, mainly your system. haha I just reinstalled Python 2.7 and I hope things are not so bad now when I reboot. -- -Joel M. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor Yea, It wiped out GNOME and UNITY along with a few other applications. It wasn't a big deal tho, I just reinstalled ubuntu-desktop threw apt-get. :) -- -Joel M. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Paper Rock Scissors game - User's choice not returned properly
Hello everyone,
I am having a little trouble with a block of code that isn't behaving
the way I would expect. Maybe you can give me a hand and point where it
is going wrong.
The function that is not working correctly belongs to a Paper Rock
Scissor game I am making.
This particular function is responsible to:
a) Get the user's choice (Paper, Rock, or Scissors)
b) Return the user's choice within the variable choice to the
function that called it.
The function works correctly as long as the user _does not try to enter
a string other than_ 'P', 'R', or 'S'.
Logic:
Take the user's string and put it in the variable choice.
If choice is not 'P', 'R', or 'S'then pass a message to the user
and call the function again.
If the choice is 'P', 'R', or 'S'then return choice to where it was
called from.
The problem is this.
When the user enters a string other than the valid ones, the if
statements catches it and calls the same function again so the user can
enter a valid string. But the variable choice does not get assigned the
new string entered by the user, instead it is empty.
I would expect if the function runs again, the variable choice would be
updated to the last value given by the user.
The function: ( http://dpaste.com/644857/)
def UserChoice ():# The function that returns the choice from the user
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?:')
if choice.lower() not in ('p', 'r','s'): # Converts the user's
choice to lowercase and confirms the choice is valid
print 'I am sorry, you entered\'' + choice.upper() + '\'
which is an invalid response. Please try again.'
raw_input('Press Enter to try again.')
UserChoice () # If the choice is not valid, run the
function over
else:
return choice
Output with no problems: ( http://dpaste.com/644866/)
http://dpaste.com/644866/
Welcome to the PRS game.
Please select (P) for paper, (R) for Rock, or (S) for Scissors.
What is your selection?: s
You threw down Scissors while the computer threw down Rock
LOOSE
Output with problems: ( http://dpaste.com/644868/)
Welcome to the PRS game.
Please select (P) for paper, (R) for Rock, or (S) for Scissors.
What is your selection?: L
I am sorry, you entered 'L' which is an invalid response. Please try again.
Press Enter to try again.
Please select (P) for paper, (R) for Rock, or (S) for Scissors.
What is your selection?: s
You threw down None while the computer threw down Paper
LOOSE
Here's the full source code in case the problem is outside of the
function: ( http://dpaste.com/644873/)
import random # Import the random library
def main (): # The main function that gets called from main()
print '\nWelcome to the PRS game.\n'
choice = UserChoice () # Gets the choice from the user
cchoice = ComputerChoice () # Gets the choice from the
computer
PrintOutcome (choice, cchoice)# Passes both choices to the
PrintChoice function for display
return 0
def UserChoice ():# The function that returns the choice from the user
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?:')
if choice.lower() not in ('p', 'r','s'): # Converts the user's
choice to lowercase and confirms the choice is valid
print 'I am sorry, you entered\'' + choice.upper() + '\'
which is an invalid response. Please try again.'
raw_input('Press Enter to try again.')
UserChoice () # If the choice is not valid, run the
function over
else:
return choice
def ComputerChoice ():# The function that returns the choice
from the computer
PRS = ['Rock', 'Paper', 'Scissors'] # A list of choices
cchoice = random.choice(PRS) # Choose a random item from the list
return cchoice # Return the function
def PrintOutcome (UC, CC): # Function responsable to display the
choices and results
PRS = ['Rock', 'Paper', 'Scissors']
# Convert the letters to words
if UC == 'r':
UC = PRS[0]
elif UC == 'p':
UC = PRS[1]
elif UC == 's':
UC = PRS[2]
print '\n\tYou threw down', UC, 'while the computer threw down', CC
+'\n'
# find the outcome of the game
if UC == CC:
print 'We have a tie, both players gain a point!'
elif UC == 'Rock' and CC == 'Scissors':
print 'WIN'
elif UC == 'Paper' and CC == 'Rock':
print 'WIN'
Re: [Tutor] Tutor Digest, Vol 92, Issue 127
On Mon 31 Oct 2011 11:59:47 AM EDT, Asokan Pichai wrote:
From: Joel Montes de Oca joelmonte...@gmail.com
mailto:joelmonte...@gmail.com
To: Tutor Python tutor@python.org mailto:tutor@python.org
Subject: [Tutor] Paper Rock Scissors game - User's choice not returned
properly
Message-ID: 4eaec191.3060...@gmail.com
mailto:4eaec191.3060...@gmail.com
Content-Type: text/plain; charset=iso-8859-1; Format=flowed
Hello everyone,
The function: ( http://dpaste.com/644857/)
def UserChoice ():# The function that returns the choice
from the user
print 'Please select (P) for paper, (R) for Rock, or (S)
for Scissors.'
choice = raw_input('What is your selection?:')
if choice.lower() not in ('p', 'r','s'): # Converts
the user's choice to lowercase and confirms the choice is valid
print 'I am sorry, you entered\'' +
choice.upper() + '\' which is an invalid response. Please try
again.'
raw_input('Press Enter to try again.')
UserChoice () # If the choice is not
valid, run the function over
You should use
return UserChoice()
else:
return choice
Asokan Pichai
SVP - Learning and Development
“Faith consists in believing when it is beyond the power of reason to
believe.
Voltaire http://www.brainyquote.com/quotes/quotes/v/voltaire163832.html
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I am not sure if I understand, why doesn't my way work and what do you
mean I should return UserChoice()?
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Re: [Tutor] Paper Rock Scissors game - User's choice not returned properly
On Mon 31 Oct 2011 12:14:40 PM EDT, Hugo Arts wrote:
On Mon, Oct 31, 2011 at 4:41 PM, Joel Montes de Oca
joelmonte...@gmail.com wrote:
Hello everyone,
I am having a little trouble with a block of code that isn't behaving the
way I would expect. Maybe you can give me a hand and point where it
is going
wrong.
The function that is not working correctly belongs to a Paper Rock
Scissor
game I am making.
This particular function is responsible to:
a) Get the user's choice (Paper, Rock, or Scissors)
b) Return the user's choice within the variable choice to the function
that called it.
The function works correctly as long as the user does not try to enter a
string other than 'P', 'R', or 'S'.
Logic:
Take the user's string and put it in the variable choice.
If choice is not 'P', 'R', or 'S' then pass a message to the user and
call the function again.
If the choice is 'P', 'R', or 'S' then return choice to where it was
called from.
The problem is this.
When the user enters a string other than the valid ones, the if
statements
catches it and calls the same function again so the user can enter a
valid
string. But the variable choice does not get assigned the new string
entered
by the user, instead it is empty.
I would expect if the function runs again, the variable choice would be
updated to the last value given by the user.
The function: ( http://dpaste.com/644857/)
def UserChoice (): # The function that returns the choice from the user
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?: ')
if choice.lower() not in ('p', 'r','s'): # Converts the user's choice to
lowercase and confirms the choice is valid
print 'I am sorry, you entered \'' + choice.upper() + '\' which is an
invalid response. Please try again.'
raw_input('Press Enter to try again.')
UserChoice () # If the choice is not valid, run the function over
else:
return choice
Your problem is that you don't quite understand recursion.
When a function calls itself, it's not actually any different from
when a function A calls another function B. Once function B is done
running and returns, control goes back to function A. It doesn't
matter if function B is actually the same function as A. In fact, even
if A and B are the same function, they don't share any variables and
are totally separate as if they were two different functions that just
happened to do the same thing.
So, how does this apply to your function? Let's go through a run of
it. We call UserChoice (this is function A) and we input a wrong
letter. So, A calls UserChoice again (this is function B), and this
time we input something valid. So, function B runs the line return
choice.
Control now returns to function A, right at the point where we called
function B. So what do we do here with the choice that was just
returned from function B? Well, looking at the line where it's called,
it's just UserChoice(). So we do nothing. We just throw it away.
Then, we continue on with function A, move out of the if statement,
and fall off the end of the function. And when that happens, Python
returns None from function A to show you that nothing was returned.
If you understood all that, you should be able to fix your problem.
Hugo
Hey Hugo,
I think I understand your explanation. Let me see if I get it.
The code:
def UserChoice (): *# I WILL CALL THIS FUNCTION A*
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?:')
if choice.lower() not in ('p', 'r','s'):
print 'I am sorry, you entered\'' + choice.upper() + '\' which is
an invalid response. Please try again.'
raw_input('Press Enter to try again.')
UserChoice () *# I WILL CALL THIS FUNCTION B*
else:
return choice*# I WILL CALL THE ORIGINAL CALLING FUNCTION, FUNCTION
MAIN*
OK so when the user uses a valid letter, the variable choice gets
returned to FUNCTION MAIN. Everything works fine.
When the user enters an invalid letter, FUNCTION B calls FUNCTION A.
FUNCTION A returns choice to FUNCTION B. FUNCTION B does nothing with
the return, FUNCTION MAIN gets nothing to returned to it, thus choice is
NONE.
FUN MAIN
|
|
|__ FUN A
|
|
|_ FUN B
This is how I understand it. So if I want this to work, I need FUN B to
give something back to FUN A so that FUN A will have something to give
back to FUN MAIN but that doesn't feel right.
Is there a way to say GO TO FUN A instead of calling the function?
I also found this Youtube video on the topic of recursion in python.
http://www.youtube.com/watch?v=72hal4Cp_2I
--
-Joel M.
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Re: [Tutor] Paper Rock Scissors game - User's choice not returned properly
On 10/31/2011 11:41 AM, Joel Montes de Oca wrote:
Hello everyone,
I am having a little trouble with a block of code that isn't behaving
the way I would expect. Maybe you can give me a hand and point where
it is going wrong.
The function that is not working correctly belongs to a Paper Rock
Scissor game I am making.
This particular function is responsible to:
a) Get the user's choice (Paper, Rock, or Scissors)
b) Return the user's choice within the variable choice to the
function that called it.
The function works correctly as long as the user _does not try to
enter a string other than_ 'P', 'R', or 'S'.
Logic:
Take the user's string and put it in the variable choice.
If choice is not 'P', 'R', or 'S'then pass a message to the user
and call the function again.
If the choice is 'P', 'R', or 'S'then return choice to where it
was called from.
The problem is this.
When the user enters a string other than the valid ones, the if
statements catches it and calls the same function again so the user
can enter a valid string. But the variable choice does not get
assigned the new string entered by the user, instead it is empty.
I would expect if the function runs again, the variable choice would
be updated to the last value given by the user.
The function: ( http://dpaste.com/644857/)
def UserChoice ():# The function that returns the choice from the user
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?:')
if choice.lower() not in ('p', 'r','s'): # Converts the user's
choice to lowercase and confirms the choice is valid
print 'I am sorry, you entered\'' + choice.upper() + '\'
which is an invalid response. Please try again.'
raw_input('Press Enter to try again.')
UserChoice () # If the choice is not valid, run the
function over
else:
return choice
Output with no problems: ( http://dpaste.com/644866/)
http://dpaste.com/644866/
Welcome to the PRS game.
Please select (P) for paper, (R) for Rock, or (S) for Scissors.
What is your selection?: s
You threw down Scissors while the computer threw down Rock
LOOSE
Output with problems: ( http://dpaste.com/644868/)
Welcome to the PRS game.
Please select (P) for paper, (R) for Rock, or (S) for Scissors.
What is your selection?: L
I am sorry, you entered 'L' which is an invalid response. Please try again.
Press Enter to try again.
Please select (P) for paper, (R) for Rock, or (S) for Scissors.
What is your selection?: s
You threw down None while the computer threw down Paper
LOOSE
Here's the full source code in case the problem is outside of the
function: ( http://dpaste.com/644873/)
import random # Import the random library
def main (): # The main function that gets called from main()
print '\nWelcome to the PRS game.\n'
choice = UserChoice () # Gets the choice from the user
cchoice = ComputerChoice () # Gets the choice from the
computer
PrintOutcome (choice, cchoice)# Passes both choices to the
PrintChoice function for display
return 0
def UserChoice ():# The function that returns the choice from the user
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?:')
if choice.lower() not in ('p', 'r','s'): # Converts the user's
choice to lowercase and confirms the choice is valid
print 'I am sorry, you entered\'' + choice.upper() + '\'
which is an invalid response. Please try again.'
raw_input('Press Enter to try again.')
UserChoice () # If the choice is not valid, run the
function over
else:
return choice
def ComputerChoice ():# The function that returns the choice
from the computer
PRS = ['Rock', 'Paper', 'Scissors'] # A list of choices
cchoice = random.choice(PRS) # Choose a random item from the list
return cchoice # Return the function
def PrintOutcome (UC, CC): # Function responsable to display the
choices and results
PRS = ['Rock', 'Paper', 'Scissors']
# Convert the letters to words
if UC == 'r':
UC = PRS[0]
elif UC == 'p':
UC = PRS[1]
elif UC == 's':
UC = PRS[2]
print '\n\tYou threw down', UC, 'while the computer threw down', CC
+'\n'
# find the outcome of the game
if UC == CC:
print 'We have a tie, both players gain a point!'
elif UC == 'Rock' and CC == 'Scissors':
print 'WIN'
elif UC == 'Paper
Re: [Tutor] Paper Rock Scissors game - User's choice not returned properly
On 10/31/2011 02:13 PM, Prasad, Ramit wrote:
Just a minor note, this break is redundant. Breaks are used to exit (for/while)
loops but keep control in the function. A return exits the function immediately.
if choice.lower() in ('p', 'r','s'):# Converts the user's choice
to lowercase and confirms the choice is valid
return choice
break
There is also a continue which is similar to a break, but instead of exiting the loop,
it will start the loop code over for the next value (thus continuing the loop).
t = [ 'not this', 'do this', 'not this either', 'most definitely do this' ]
for string in t:
... if string.startswith( 'not' ):
... continue # I want to keep working with the other elements in the
list
... print string
...
do this
most definitely do this
for string in t:
... if string.startswith( 'not' ):
... break # I want to abort the entire loop now
... print string
...
Ramit
Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
712 Main Street | Houston, TX 77002
work phone: 713 - 216 - 5423
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Awesome, thanks for the tip. I removed the break from the code.
Thanks again.
--
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Re: [Tutor] Paper Rock Scissors game - User's choice not returned properly
On 10/31/2011 02:14 PM, Marc Tompkins wrote:
On Mon, Oct 31, 2011 at 10:57 AM, Joel Montes de Oca
joelmonte...@gmail.com wrote:
I came up with this to solve the problem.
def UserChoice ():# The function that returns the choice from the user
while 1:
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?: ')
if choice.lower() in ('p', 'r','s'):# Converts the user's choice
to lowercase and confirms the choice is valid
return choice
break
else:
print 'Try again.'
It puts the choice into a loop and only exits when the user enters a valid
value. It works and it's so much easier to read too!
You could simplify it even further by actually using the while:
def UserChoice ():# The function that returns the choice from the user
choice = ''
attempt = 0
while choice.lower() not in ('p', 'r','s'):
if attempt 0: print 'Please try again.'
print 'Please select (P) for paper, (R) for Rock, or (S) for Scissors.'
choice = raw_input('What is your selection?: ')
attempt +=1
return choice.lower()
It's a matter of personal preference, but I try to avoid while 1 or
while True loops if at all possible. For one thing, it seems
counter-productive to set up a loop that doesn't exit, and then to
have to use 'break' to get out of it!
One last thing: HTML formatting is pretty, but it tends to screw
things up. Someone else is bound to say it if I don't, so: please
use plain text only when submitting code to the list. Thanks!
Things for the tip Mark, I have set up Thunderbird to send text only
when emailing the python.org domain.
--
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Re: [Tutor] Paper Rock Scissors game - User's choice not returned properly
On 10/31/2011 07:10 PM, Steven D'Aprano wrote:
Alan Gauld wrote:
On 31/10/11 20:22, Peter Otten wrote:
Alan Gauld wrote:
if choice.lower() not in ('prs'): # NB use a single string
That's not a good idea. If a user accidentally enters PR (for
example) your
version will mistake that for a valid choice.
Good point, although you could test the first character only...
if choice[0].lower() not in ('prs'): # NB use a single string
Why would you do that? If the user is supposed to enter a single
letter, why would you accept (for example) screw you hippy, I hate
this game! as the valid response s?
I agree, I am not sure that I see the benefit of using a single string.
If anything, it makes it a bit harder to read by someone other than the
person who wrote it.
if choice.lower() in ('p', 'r','s'):
I think the code above is a lot clearer.
--
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[Tutor] Method to create small and simple database
Hello everyone, About me: This is the first time I post to Tutor@Python.org. I am brand spanking new to Python. I can create simple application, gone through a few tutorials and watched the Google Python 2 day class on Youtube. (List of classes: http://goo.gl/Ud5rg) Just yesterday I figured out how to load up a GUI made in Glade and pass singles around and what not. Huge accomplishment for me since documentation is a bit shaky for noobs like me. :) I have some programming knowledge. I learned (self tough) VB when I was in middle school and then did a intro to C++ in college. Of course mentioning that is trivial since I haven't done any programming for about 5 years or so.. But I do know basic concepts. Just need a little push in the right direction.. -- I think I know how to design my application but I would like to put it on here for you guys to review and provide me with feedback/suggestions as to the best way to go about it. -- The application: I want to build a simple application that keeps track of items borrowers check out. So the end user types in the names of /borrowers/ and also types in a list of /items/. Then the end user checks out the /items/ to the /borrowers/. The category that my application would fall under is close to /collection management tools/. Here's a list of a few other applications that do something like what I am aiming for: http://www.makeuseof.com/tag/4-open-source-collection-manager-apps/ In addition to the application keeping track of who has what, I would like to code the date the items are out, which borrowers have not borrowed anything in the last month, and so on. That said, I need to setup some kind of database like file. I don't want to have a database server though. The reason I want to build a new tool is because: A) I want to play around with Python B) My friend needs the application to be simple and geared to his needs without too many extra bells whistles -- My method: I was thinking of using the lxmal module to construct a XML file to read/write all the information. I figured this was the easiest way to do what I need since the information is setup as a tree. (Easy to think about and see) Example: app borrowers userJohn Doe/user checked out Item1:Item2:||2011/4/2/checked out userMary Doe/user checked out Item3||2011/7/22/checked out /borrowers objects itemItem1/item createdOn2011/2/1/createdOn checked_out_times32/checked_out_times itemItem2/item createdOn2011/2/1/createdOn checked_out_times22/checked_out_times itemItem3/item createdOn2011/2/1/createdOn checked_out_times1/checked_out_times /objects /app The application will not be used in an enterprise kind of environment. The application is meant to hold about 80 borrowers and about 100 items and that's about it. Is this a good way to go about my project? Is there a better easier way? I don't want to trade off better with easy. Someone once suggested on Freenode #Python that I should use a sql database. I don't remember the name of it. It was something like lightsql or something like that. That particular database didn't use a server end. I guess it spit out a txt database or something... This might be a good time to mention I know very little about database construction or sql commands. Anyhow, I am looking forward to hearing opinion's and suggestions. Thanks! -- -Joel M ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Method to create small and simple database
On Sat Oct 29 14:14:24 2011, Joel Montes de Oca wrote: On Sat Oct 29 13:29:59 2011, Peter Otten wrote: Joel Montes de Oca wrote: Hello everyone, About me: This is the first time I post to Tutor@Python.org. I am brand spanking new to Python. I can create simple application, gone through a few tutorials and watched the Google Python 2 day class on Youtube. (List of classes: http://goo.gl/Ud5rg) Just yesterday I figured out how to load up a GUI made in Glade and pass singles around and what not. Huge accomplishment for me since documentation is a bit shaky for noobs like me. :) I have some programming knowledge. I learned (self tough) VB when I was in middle school and then did a intro to C++ in college. Of course mentioning that is trivial since I haven't done any programming for about 5 years or so.. But I do know basic concepts. Just need a little push in the right direction.. -- I think I know how to design my application but I would like to put it on here for you guys to review and provide me with feedback/suggestions as to the best way to go about it. -- The application: I want to build a simple application that keeps track of items borrowers check out. So the end user types in the names of /borrowers/ and also types in a list of /items/. Then the end user checks out the /items/ to the /borrowers/. The category that my application would fall under is close to /collection management tools/. Here's a list of a few other applications that do something like what I am aiming for: http://www.makeuseof.com/tag/4-open-source-collection-manager-apps/ In addition to the application keeping track of who has what, I would like to code the date the items are out, which borrowers have not borrowed anything in the last month, and so on. That said, I need to setup some kind of database like file. I don't want to have a database server though. The reason I want to build a new tool is because: A) I want to play around with Python B) My friend needs the application to be simple and geared to his needs without too many extra bells whistles -- My method: I was thinking of using the lxmal module to construct a XML file to read/write all the information. I figured this was the easiest way to do what I need since the information is setup as a tree. (Easy to think about and see) Example: app borrowers userJohn Doe/user checked out Item1:Item2:||2011/4/2/checked out userMary Doe/user checked out Item3||2011/7/22/checked out /borrowers objects itemItem1/item createdOn2011/2/1/createdOn checked_out_times32/checked_out_times itemItem2/item createdOn2011/2/1/createdOn checked_out_times22/checked_out_times itemItem3/item createdOn2011/2/1/createdOn checked_out_times1/checked_out_times /objects /app The application will not be used in an enterprise kind of environment. The application is meant to hold about 80 borrowers and about 100 items and that's about it. Is this a good way to go about my project? Is there a better easier way? I don't want to trade off better with easy. Someone once suggested on Freenode #Python that I should use a sql database. I don't remember the name of it. It was something like lightsql or something like that. That particular database didn't use a server end. I guess it spit out a txt database or something... This might be a good time to mention I know very little about database construction or sql commands. Anyhow, I am looking forward to hearing opinion's and suggestions. Well, using sqlite http://docs.python.org/library/sqlite3.html may be both better and easier than lxml, but for the tiny amount of data you are planning to handle you can also make do with a few of Python's lists and dicts, and use pickle http://docs.python.org/library/pickle.html to save the data when you're done. It won't get easier than that. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor Awesome Peter, Yea, sqlite3 was what the good folks on irc.freenode.net #Python told me to use but the pickle module seems like the simpliest way to get the job done. I'll look into both of them. I'm going to have to rethink how I am going to build the program using sqlite or pickle(). Thanks again -Joel M. After looking at the Python module documentation for sqlite3 (http://docs.python.org/library/sqlite3.html#module-sqlite3), it seems to me it's the best way to make the small database that I am looking for. Now I need to look for a basic tutorial on constructing a simple database (tables, rows, keys) and how to connect all that stuff together. If anyone happens to know of a good intro tutorial or documentation to database concepts, please forward it to me. Thanks! ___ Tutor maillist - Tutor
