Re: a servlet-related Java question
Christopher Schultz ch...@christopherschultz.net wrote in message
news:4bcf5f41.6060...@christopherschultz.net...
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
André,
On 4/21/2010 3:46 PM, André Warnier wrote:
Mark Thomas wrote:
On 21/04/2010 20:24, André Warnier wrote:
Mark Thomas wrote:
...
I'd just use JAD and decompile it.
Thanks. But although my intentions are not obnoxious nor illegal nor
anything of the kind, I would not want to even come under suspicion of
reverse-engineering. So is there something that just lists the
standard
calls/methods used in it ?
No. You can see the methods it exposes, but not the methods it uses.
Time to add some debug code to your wrapper to see what is being
called?
Mmmm. :-(
How do I do that, assuming I do not know in advance which methods it
calls ?
Do I need to define all the methods of HttpServletRequest in my wrapper,
just to make them trace their call ?
Or does there exist some more dummy-user-friendly methodology ?
It's pretty inaccessible for novice Java programmers, but you could use
the proxy API which is jsut about the coolest thing available in Java
IMO.
This is how you do the wrapping of the request:
import java.lang.reflect.Proxy;
import java.lang.reflect.InvocationHandler;
public class RequestMethodCallLogger
implements InvocationHandler, Filter
{
public void doFilter(...) {
HttpServletRequest wrappedRequest
= Proxy.newProxyInstance(HttpServletRequest.class.getClassLoader(),
new Class[] { HttpServletRequest.class },
this);
chain.doFilter(wrappedRequest, response);
}
public Object invoke(Object proxy, Method method, Object[] args)
{
// Log to your favorite logger here
return method.invoke(proxy, args);
}
}
Basically, the Proxy class allows you to intercept the calls to
interface methods. The implementation of the invoke method is just a
pass-through to the real method after logging (an exercise left for
the reader).
This can be optimized a bit if you need to use it long-term, but the
above is about as compact as it gets.
If it does a forward or include done the line, this won't work with any
remotely recent version of Tomcat. These versions enforce the spec
requirement that the Request has to be a subclass of HttpServletWrapper
wrapping the original request, or the original request.
I'd still recommend the use of jad, honestly.
- -chris
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.10 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/
iEYEARECAAYFAkvPX0EACgkQ9CaO5/Lv0PCKVQCdG5SMXiySnsFEowVF7/44KM8s
b7kAoIAGSzxOIWmKt4+z6ATkqslTl5uW
=ykwF
-END PGP SIGNATURE-
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
Re: standardize the URL
Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 ... or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 ... how can i get the 2 modes? i hope it is clearer now thanks. -- View this message in context: http://old.nabble.com/standardize-the-URL-tp28287836p28324762.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
On 21/04/2010 18:45, Propes, Barry L wrote: I started having a similar problem yesterday and discovered that somehow my web.xml file had been deleted (not sure how), so I replaced it. Make sure you have that in your manager folder in WEB-INF. Barry probably meant: make sure you have a web.xml in WEB-INF, in webapps/manager - because a web.xml in a manager directory in (any) WEB-INF isn't going to be discovered by Tomcat. p -Original Message- From: Luís de Sousa [mailto:luis.a.de.so...@gmail.com] Sent: Wednesday, April 21, 2010 12:15 PM To: users@tomcat.apache.org Subject: Can't login to Tomcat manager pages Dear all, Tomcat 6.0.20 on Ubuntu 9.10. I can't login to the manager pages (http://localhost:8080/manager/html). I set a new user and a few roles in the /etc/tomcat6/tomcat-users.xml file, restarted Tomcat but can't possibly login. I browsed through a number of threads with similar issues but couldn't solve it so far. Note that I uncommented the users section in the file, it is reproduced below. Thanks for you time, Luís -- ?xml version='1.0' encoding='utf-8'? tomcat-users role rolename=admin/ role rolename=manager/ role rolename=standard/ user username=admin password=admin roles=admin,standard,manager/ /tomcat-users - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org signature.asc Description: OpenPGP digital signature
Re: a servlet-related Java question
On 21/04/2010 19:52, André Warnier wrote: Hi. A while ago, I wrote a servlet filter which has served me well since, to wrap a servlet for which I do not have nor can obtain the source code, and of which I only generally know what it does. Now it seems that with a new version of this servlet, the servlet itself crashes when wrapped by my filter, with a java.lang.StringIndexOutOfBoundsException. Where crash is defined as a condition which produces a stacktrace, or just an error message with the above explanation? p My servlet filter, under certain conditions, creates a HttpRequestWrapper derived object, which it passes to the servlet instead of the original HttpServletRequest object. I have a suspicion that the ultimate reason for the servlet crash, is that it now calls a method which I have not re-defined in my wrapper, which method the previous servlet version did not call (and that it is not very defensive about the result it expects to get, but nothing I can do about that). All this to ask the following : is there some generic java tool which allows to examine a compiled .class file, and determine which methods of HttpServletRequest it calls ? I do not need nor want to decompile the class, just to know what it calls. Thanks. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org signature.asc Description: OpenPGP digital signature
Re: standardize the URL
On 22/04/2010 07:45, banto wrote: Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 Rename the webapp, from instanceVar to ROOT. or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 Change the port in the Connector from 8080 to 80. how can i get the 2 modes? Then add multiple mappings for each instance of the URL. OR Create the servlet and map it to a value also present in the welcome-file list of file names. http://localhost/instanceVar http://localhost/webapp_2 p signature.asc Description: OpenPGP digital signature
Re: standardize the URL
Pid * wrote: On 22/04/2010 07:45, banto wrote: Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 Rename the webapp, from instanceVar to ROOT. or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 Change the port in the Connector from 8080 to 80. how can i get the 2 modes? Then add multiple mappings for each instance of the URL. OR Create the servlet and map it to a value also present in the welcome-file list of file names. http://localhost/instanceVar http://localhost/webapp_2 p thank you g now it works. However i understand the only way to do that is putting the webapps in the ROOT folder,right? -- View this message in context: http://old.nabble.com/standardize-the-URL-tp28287836p28326093.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
Hello everyone, thank you for the answers. I started by looking for the web.xml file, it is together with tomcat-users.xml in the CATALINA_HOME/conf directory (/etc/tomcat6). I don't have a manager directory under /var/lib/tomcat6/webapps so I checked if the tomcat6-admin package is installed: $ dpkg -l '*tomcat*' Desired=Unknown/Install/Remove/Purge/Hold | Status=Not/Inst/Cfg-files/Unpacked/Failed-cfg/Half-inst/trig-aWait/Trig-pend |/ Err?=(none)/Reinst-required (Status,Err: uppercase=bad) ||/ Name Version Description +++-=-=-== ii libtomcat6-java 6.0.20-2ubuntu2.1 Servlet and JSP engine -- core libraries ii tomcat6 6.0.20-2ubuntu2.1 Servlet and JSP engine ii tomcat6-admin 6.0.20-2ubuntu2.1 Servlet and JSP engine -- admin web applications ii tomcat6-common6.0.20-2ubuntu2.1 Servlet and JSP engine -- common files ii tomcat6-docs 6.0.20-2ubuntu2.1 Servlet and JSP engine -- example web applications ii tomcat6-examples 6.0.20-2ubuntu2.1 Servlet and JSP engine -- example web applications ii tomcat6-user 6.0.20-2ubuntu2.1 Servlet and JSP engine -- tools to create user ins It seems to be. I then performed a shutdown and startup. Unlike yesterday, today I'm getting a Connection refused exception when shutting down, but the startup goes ok. The command line log is below, in attach go the Tomcat logs for today. Thank you, Luís - $ cd /usr/share/tomcat6/bin $ sudo ./shutdown.sh Using CATALINA_BASE: /usr/share/tomcat6 Using CATALINA_HOME: /usr/share/tomcat6 Using CATALINA_TMPDIR: /usr/share/tomcat6/temp Using JRE_HOME: /usr 22-Apr-2010 10:51:39 org.apache.catalina.startup.Catalina stopServer SEVERE: Catalina.stop: java.net.ConnectException: Connection refused at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:310) at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:176) at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:163) at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:384) at java.net.Socket.connect(Socket.java:546) at java.net.Socket.connect(Socket.java:495) at java.net.Socket.init(Socket.java:392) at java.net.Socket.init(Socket.java:206) at org.apache.catalina.startup.Catalina.stopServer(Catalina.java:422) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.startup.Bootstrap.stopServer(Bootstrap.java:337) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:415) $ sudo ./startup.sh Using CATALINA_BASE: /usr/share/tomcat6 Using CATALINA_HOME: /usr/share/tomcat6 Using CATALINA_TMPDIR: /usr/share/tomcat6/temp Using JRE_HOME: /usr 22-Apr-2010 10:51:46 org.apache.catalina.core.ApplicationContext log INFO: ContextListener: contextInitialized() 22-Apr-2010 10:51:46 org.apache.catalina.core.ApplicationContext log INFO: SessionListener: contextInitialized() 22-Apr-2010 10:51:51 org.apache.catalina.core.ApplicationContext log INFO: Initializing Spring root WebApplicationContext 22-Apr-2010 10:51:46 org.apache.coyote.http11.Http11Protocol init SEVERE: Error initializing endpoint java.net.BindException: Address already in usenull:8080 at org.apache.tomcat.util.net.JIoEndpoint.init(JIoEndpoint.java:509) at org.apache.coyote.http11.Http11Protocol.init(Http11Protocol.java:176) at org.apache.catalina.connector.Connector.initialize(Connector.java:1058) at org.apache.catalina.core.StandardService.initialize(StandardService.java:677) at org.apache.catalina.core.StandardServer.initialize(StandardServer.java:795) at org.apache.catalina.startup.Catalina.load(Catalina.java:535) at org.apache.catalina.startup.Catalina.load(Catalina.java:555) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.startup.Bootstrap.load(Bootstrap.java:260) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:412) 22-Apr-2010 10:51:46 org.apache.catalina.startup.Catalina load SEVERE: Catalina.start LifecycleException: Protocol handler initialization failed: java.net.BindException: Address already in usenull:8080 at org.apache.catalina.connector.Connector.initialize(Connector.java:1060) at org.apache.catalina.core.StandardService.initialize(StandardService.java:677) at
Re: standardize the URL
On 22/04/2010 10:10, banto wrote: Pid * wrote: On 22/04/2010 07:45, banto wrote: Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 Rename the webapp, from instanceVar to ROOT. or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 Change the port in the Connector from 8080 to 80. how can i get the 2 modes? Then add multiple mappings for each instance of the URL. OR Create the servlet and map it to a value also present in the welcome-file list of file names. http://localhost/instanceVar http://localhost/webapp_2 p thank you g now it works. However i understand the only way to do that is putting the webapps in the ROOT folder,right? If by webapp, you mean Servlet. ROOT is a webapp in it's own right, it is not the same as the root directory of an HTTPD server. any .war file or directory (effectively an exploded .war file) you put in tomcat/webapps will be treated as an application. p signature.asc Description: OpenPGP digital signature
How to configure ProxyPassReverse for SSL redirect
Hi, our configuration is a Apache 2.2 web server, acting as a reverse proxy for Tomcat 6. This is the configuration: ServerNameit.localhost.de ProxyPass / ajp://127.0.0.1:8009/spike/ ProxyPassReverse/ ajp://127.0.0.1:8009/spike/ ProxyPassReverseCookiePath /spike / As you can see, the webapp is hosted under ContextPath /spike but available through the proxy via /. Everything works fine, until the webapp sends an redirect to HTTPS. This is done via SpringSecurity. The problem is, that the ProxyPassReverse directive doesn't catch the ContextPath and converts it, if it includes the complete address. These are the logs from the web browser: GET http://it.localhost.de/users/65 = 302 = https://it.localhost.de/spike/users/65 1) Why does the ProxyPassReverse doesn't convert the /spike back to / in https://it.localhost.de/spike/users/65? Is it because the Header isn't relative? The protocol is still AJP and so the Proxy should know how to convert it, right? 1a) If so, how could the webapp switch from http to https and vice versa, when not able to send the absolute address with a new protocol? After this, I tried to set additional ProxyPassReverse directives: ProxyPassReverse/https://it.localhost.de/spike/ ProxyPassReverse/http://it.localhost.de/spike/ This time, the /spike/ is converted to /, but the two directives leads to an infintive loop of redirects to http://it.localhost.de/REQUEST-URI. 2) How can I stop this loop? or better 3) How can I configure the ProxyPassReverse correctly? As a workaround I have a RewriteRule added like this one RewriteRule ^/spike/(.*)$ /$1 [R=301,L] but this doesn't feel correct and it leads to 3 GET-Requests and redirects each time the webapps wants it user to switch the protocol. Thank you very much Timo Meinen - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: standardize the URL
Pid * wrote: On 22/04/2010 10:10, banto wrote: Pid * wrote: On 22/04/2010 07:45, banto wrote: Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 Rename the webapp, from instanceVar to ROOT. or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 Change the port in the Connector from 8080 to 80. how can i get the 2 modes? Then add multiple mappings for each instance of the URL. OR Create the servlet and map it to a value also present in the welcome-file list of file names. http://localhost/instanceVar http://localhost/webapp_2 p thank you g now it works. However i understand the only way to do that is putting the webapps in the ROOT folder,right? If by webapp, you mean Servlet. ROOT is a webapp in it's own right, it is not the same as the root directory of an HTTPD server. any .war file or directory (effectively an exploded .war file) you put in tomcat/webapps will be treated as an application. p Just to understand you: i have copied the class files of my webapp and modified the relative web.xml to the folder C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\ROOT i hope you mean the same ROOT? thanks -- View this message in context: http://old.nabble.com/standardize-the-URL-tp28287836p28326999.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: [Tomcat 7-RC1] JNDI Startup Issue
Full stack-trace - javax.naming.NameNotFoundException: Name comp is not bound in this Context at org.apache.naming.NamingContext.lookup(NamingContext.java:774) at org.apache.naming.NamingContext.lookup(NamingContext.java:157) at org.apache.naming.SelectorContext.lookup(SelectorContext.java:156) at javax.naming.InitialContext.lookup(InitialContext.java:392) at au.com.test.web.MyServletContextListener.contextInitialized(MyServletContextListener.java:21) at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4221) at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:4700) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:128) at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:986) at org.apache.catalina.core.StandardHost.startInternal(StandardHost.java:857) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:128) at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:986) at org.apache.catalina.core.StandardEngine.startInternal(StandardEngine.java:452) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:128) at org.apache.catalina.core.StandardService.startInternal(StandardService.java:456) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:128) at org.apache.catalina.core.StandardServer.startInternal(StandardServer.java:662) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:128) at org.apache.catalina.startup.Catalina.startInternal(Catalina.java:564) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:128) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:288) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:413) I have updated the bug with a sample war file + code. https://issues.apache.org/bugzilla/show_bug.cgi?id=49132 Konstantin Kolinko wrote: 2010/4/22 alvins alvins1...@hotmail.com: Any thoughts on this? I would like to see the Tomcat part of the exception that you are observing. That is, at what point in application lifecycle the initialization is performed. If you can attach a sample application to https://issues.apache.org/bugzilla/show_bug.cgi?id=49132 that would be nice. It would be a bit easier if it would be a simple one. Best regards, Konstantin Kolinko - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -- View this message in context: http://old.nabble.com/-Tomcat-7-RC1--JNDI-Startup-Issue-tp28279732p28327054.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: standardize the URL
On 22/04/2010 11:27, banto wrote: Pid * wrote: On 22/04/2010 10:10, banto wrote: Pid * wrote: On 22/04/2010 07:45, banto wrote: Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 Rename the webapp, from instanceVar to ROOT. or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 Change the port in the Connector from 8080 to 80. how can i get the 2 modes? Then add multiple mappings for each instance of the URL. OR Create the servlet and map it to a value also present in the welcome-file list of file names. http://localhost/instanceVar http://localhost/webapp_2 p thank you g now it works. However i understand the only way to do that is putting the webapps in the ROOT folder,right? If by webapp, you mean Servlet. ROOT is a webapp in it's own right, it is not the same as the root directory of an HTTPD server. any .war file or directory (effectively an exploded .war file) you put in tomcat/webapps will be treated as an application. p Just to understand you: i have copied the class files of my webapp and modified the relative web.xml to the folder C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\ROOT i hope you mean the same ROOT? Yes, this is correct. p signature.asc Description: OpenPGP digital signature
Re: standardize the URL
Pid * wrote: On 22/04/2010 11:27, banto wrote: Pid * wrote: On 22/04/2010 10:10, banto wrote: Pid * wrote: On 22/04/2010 07:45, banto wrote: Gregor Schneider wrote: On Tue, Apr 20, 2010 at 12:54 PM, banto banto...@gmail.com wrote: Hi, i know this can be a silly question but i have the following issue: i want to call my web app with a standard URL as http://host:port/myString how does the url look like when you call your webb-app currently? how would you like the url to look like? rgds gregor -- just because you're paranoid, don't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ skype:rc46fi - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org I explain better my problem, my webapp is in the folder: C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\istanceVar and i call it with http://localhost:8080/instanceVar/instance what i would like to do (also for others webapps) is to call it/them as http://localhost:8080/instance http://localhost:8080/webapp_2 http://localhost:8080/webapp_3 Rename the webapp, from instanceVar to ROOT. or better http://localhost/instance http://localhost/webapp_2 http://localhost/webapp_3 Change the port in the Connector from 8080 to 80. how can i get the 2 modes? Then add multiple mappings for each instance of the URL. OR Create the servlet and map it to a value also present in the welcome-file list of file names. http://localhost/instanceVar http://localhost/webapp_2 p thank you g now it works. However i understand the only way to do that is putting the webapps in the ROOT folder,right? If by webapp, you mean Servlet. ROOT is a webapp in it's own right, it is not the same as the root directory of an HTTPD server. any .war file or directory (effectively an exploded .war file) you put in tomcat/webapps will be treated as an application. p Just to understand you: i have copied the class files of my webapp and modified the relative web.xml to the folder C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\ROOT i hope you mean the same ROOT? Yes, this is correct. p thank you!! -- View this message in context: http://old.nabble.com/standardize-the-URL-tp28287836p28327291.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: How to run second instance of Tomcat 6.0.20 on separate port
Hi, Thanks a lot to all. I achieved the Goal :) But still not able to install the second tomcat instance as Windows Service. Where do i need to make changes? What I did next is Step 1 - Copied the contents of C:\tomcat1 into C:\tomcat2 Step 2 - Changed the Http, shutdown and ajp connecter port in server.xml at C:\tomcat2\conf to 8180, 8105 and 8109 Step 3 - Edited the startup.bat at C:\tomcat2\bin. Deleted all the contents of it and added set CATALINA_BASE=C:\tomcat2 C:\tomcat1\bin\startup.bat Step 4 - Edited the shutdown.bat at C:\tomcat2\bin. Deleted all the contents of it and added set CATALINA_BASE=C:\tomcat2 C:\tomcat1\bin\shutdown.bat Step - 5 Double clicked startup.bat in C:\tomcat2 and in browser used http://localhost:8180/ to access the new port Step - 6 Double clicked startup.bat in C:\tomcat1 and in browser used http://localhost:8080/ to access the default port. regards kapil On Wed, Apr 21, 2010 at 8:08 PM, Kapil Godara kapil.god...@gmail.comwrote: Hi Andre, I did as suggested. Tomcat is running fine as service Tomcat1. I have set CATALINA_HOME=C:\tomcat1 and CATALINA_BASE=C:\tomcat1 (I set the env var from Control Panel - System Properties -Advanced - Environment Variables - System variables) What is the next step for additional instance on different port? thanks and regards kapil On Wed, Apr 21, 2010 at 6:09 PM, André Warnier a...@ice-sa.com wrote: Kapil Godara wrote: Hi I copied the entire folder Tomcat 6.0 at C:\Program Files\Apache Software Foundation (where tomcat is installed) to Tomcat_instance2 . ... Let's start again, from the beginning. This has been discussed many times on this forum, but I believe it is worth repeating it, because it is probably the source of the confusion. In the Tomcat website download page, there are several versions : - one is for Unix/Linux. That is a complete version, with all the files packed together in one .tar.gz file. To install it, you unpack these files under one new directory for Tomcat, and it creates a set of subdirectories conf, bin, etc.. But for Windows, there are *two* versions : - one is a simple version, named installer, which is destined for the quick and simple installation of a single Tomcat under Windows, to run as a Windows Service. This is apparently the one you downloaded and installed. This version does not contain /all/ the same files as the one for Unix/Linux above, only a subset of them. - the other one is a zip version, which does contain all the same files as the Unix/Linux version, and even some additional ones. This version /also/ allows you to install Tomcat as a Windows Service, but this requires a bit more work. It also provides all the files necessary to install a second instance of Tomcat and run it as a second Windows Service. This is the one you should download now. My recommendation is : - remove the first version of Tomcat that you downloaded and installed (the .exe version). - download the zip version - decide on a main and second directories where you will run your two instances of Tomcat. I suggest that you pick directory paths that are simple, without spaces in the name. Like c:\tomcat1 and c:\tomcat2. That will save you time and problems later. - unzip the downloaded Tomcat zip version in the first directory. Note for the future that this is now your CATALINA_HOME directory. - in the directory c:\tomcat1\bin, run the service.bat script, to install this Tomcat instance as the first Windows Service. Give it the name Tomcat1. For this Tomcat, the CATALINA_BASE is also c:\tomcat1. When all the above is done and you have a running first Tomcat instance, then come back here for additional information on how to run an additional instance, using the same CATALINA_HOME, but a separate CATALINA_BASE. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
On 4/21/2010 1:14 PM, Luís de Sousa wrote: Dear all, Tomcat 6.0.20 on Ubuntu 9.10. I can't login to the manager pages (http://localhost:8080/manager/html). I set a new user and a few roles in the /etc/tomcat6/tomcat-users.xml file, restarted Tomcat but can't possibly login. I browsed through a number of threads with similar issues but couldn't solve it so far. Note that I uncommented the users section in the file, it is reproduced below. Thanks for you time, Luís -- ?xml version='1.0' encoding='utf-8'? tomcat-users role rolename=admin/ role rolename=manager/ role rolename=standard/ user username=admin password=admin roles=admin,standard,manager/ /tomcat-users I have a Ubuntu 9.10 system and did exactly what you've posted above. It works like a charm. Have you altered anything else? Change permission inadvertently on tomcat-users.xml? Mine is read/write by root, read-only by tomcat6. --David - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
2010/4/22 Luís de Sousa luis.a.de.so...@gmail.com: I then performed a shutdown and startup. Unlike yesterday, today I'm getting a Connection refused exception when shutting down, Connection refused means Tomcat was not running, or failed to stop. If it is still running, you can use kill utility to stop it. From your logs: java.net.BindException: Address already in usenull:8080 means that Tomcat failed to start, because another instance of Tomcat is still running and using those port numbers. By the way: The attachments to this list are usually stripped by mailing list software, but yours somehow reached me. . Best regards, Konstantin Kolinko - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
On Thu, Apr 22, 2010 at 1:29 PM, David Smith david.sm...@cornell.edu I have a Ubuntu 9.10 system and did exactly what you've posted above. It works like a charm. Have you altered anything else? Change permission inadvertently on tomcat-users.xml? Mine is read/write by root, read-only by tomcat6. Well David you figured it. By some reason the tomcat-users.xml had blank permissions for the 'all' group. I have no idea how it ended up that way, and doubt I'd do such thing out of my own will. Go figure. I think I'll run a test install on another machine to see if this is set by default. Thanks to all for your help, Luís - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
Here's my system's tomcat-user.xml as listed w/ ls -l: -rw-r- 1 root tomcat6 1202 2010-04-22 08:15 /etc/tomcat6/tomcat-users.xml As you can see, user and group permissions are set, but the other permissions are all blank. This is the way it should be since it contains password information. --David On 4/22/2010 9:07 AM, Luís de Sousa wrote: On Thu, Apr 22, 2010 at 1:29 PM, David Smith david.sm...@cornell.edu I have a Ubuntu 9.10 system and did exactly what you've posted above. It works like a charm. Have you altered anything else? Change permission inadvertently on tomcat-users.xml? Mine is read/write by root, read-only by tomcat6. Well David you figured it. By some reason the tomcat-users.xml had blank permissions for the 'all' group. I have no idea how it ended up that way, and doubt I'd do such thing out of my own will. Go figure. I think I'll run a test install on another machine to see if this is set by default. Thanks to all for your help, Luís - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
myeclipse and tomcat
I'm playing a bit with myeclipse and I'm wondering whether anyone on this list here is using it with Tomcat as application server running other apps, rather than using tomcat from within the built into myeclipse Tomcat server. Any experiences with that setup? -- Christoph Kukulies - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
On Thu, Apr 22, 2010 at 2:18 PM, David Smith david.sm...@cornell.edu wrote: Here's my system's tomcat-user.xml as listed w/ ls -l: -rw-r- 1 root tomcat6 1202 2010-04-22 08:15 /etc/tomcat6/tomcat-users.xml As you can see, user and group permissions are set, but the other permissions are all blank. This is the way it should be since it contains password information. --David That way I can't access the manager pages. Only when I added the read permissions to all Tomcat was able to validate the password. What's wrong? Luís - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: myeclipse and tomcat
I'm not sure I understand your question. But first, are you using plain Eclipse, or MyEclipse? (I use the latter) Do you mean: Using MyEclipse configured so that it is using an external Tomcat server, NOT the included myEclipse Tomcat server? I've never used the included myEclipse server, only external servers. --Ken On Apr 22, 2010, at 9:17 AM, Christoph Kukulies wrote: I'm playing a bit with myeclipse and I'm wondering whether anyone on this list here is using it with Tomcat as application server running other apps, rather than using tomcat from within the built into myeclipse Tomcat server. Any experiences with that setup? -- Christoph Kukulies - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
On Thu, Apr 22, 2010 at 2:37 AM, Bill Barker billwbar...@verizon.net wrote:
Christopher Schultz ch...@christopherschultz.net wrote in message
news:4bcf5f41.6060...@christopherschultz.net...
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
André,
On 4/21/2010 3:46 PM, André Warnier wrote:
Mark Thomas wrote:
On 21/04/2010 20:24, André Warnier wrote:
Mark Thomas wrote:
...
I'd just use JAD and decompile it.
Thanks. But although my intentions are not obnoxious nor illegal nor
anything of the kind, I would not want to even come under suspicion of
reverse-engineering. So is there something that just lists the
standard
calls/methods used in it ?
No. You can see the methods it exposes, but not the methods it uses.
Time to add some debug code to your wrapper to see what is being
called?
Mmmm. :-(
How do I do that, assuming I do not know in advance which methods it
calls ?
Do I need to define all the methods of HttpServletRequest in my wrapper,
just to make them trace their call ?
Or does there exist some more dummy-user-friendly methodology ?
It's pretty inaccessible for novice Java programmers, but you could use
the proxy API which is jsut about the coolest thing available in Java
IMO.
This is how you do the wrapping of the request:
import java.lang.reflect.Proxy;
import java.lang.reflect.InvocationHandler;
public class RequestMethodCallLogger
implements InvocationHandler, Filter
{
public void doFilter(...) {
HttpServletRequest wrappedRequest
= Proxy.newProxyInstance(HttpServletRequest.class.getClassLoader(),
new Class[] { HttpServletRequest.class },
this);
chain.doFilter(wrappedRequest, response);
}
public Object invoke(Object proxy, Method method, Object[] args)
{
// Log to your favorite logger here
return method.invoke(proxy, args);
}
}
Basically, the Proxy class allows you to intercept the calls to
interface methods. The implementation of the invoke method is just a
pass-through to the real method after logging (an exercise left for
the reader).
This can be optimized a bit if you need to use it long-term, but the
above is about as compact as it gets.
If it does a forward or include done the line, this won't work with any
remotely recent version of Tomcat. These versions enforce the spec
requirement that the Request has to be a subclass of HttpServletWrapper
wrapping the original request, or the original request.
Good point - which really kills the proxy approach as a
general-purpose solution in this context...
I'd still recommend the use of jad, honestly.
- -chris
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.10 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/
iEYEARECAAYFAkvPX0EACgkQ9CaO5/Lv0PCKVQCdG5SMXiySnsFEowVF7/44KM8s
b7kAoIAGSzxOIWmKt4+z6ATkqslTl5uW
=ykwF
-END PGP SIGNATURE-
--
Kris Schneider
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
Luís de Sousa wrote: On Thu, Apr 22, 2010 at 2:18 PM, David Smith david.sm...@cornell.edu wrote: Here's my system's tomcat-user.xml as listed w/ ls -l: -rw-r- 1 root tomcat6 1202 2010-04-22 08:15 /etc/tomcat6/tomcat-users.xml As you can see, user and group permissions are set, but the other permissions are all blank. This is the way it should be since it contains password information. --David That way I can't access the manager pages. Only when I added the read permissions to all Tomcat was able to validate the password. What's wrong? Probably that your Tomcat is not running under a user-id which has read access to that file. What do you see when running ps -ef | grep tomcat ? - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't login to Tomcat manager pages
On Thu, Apr 22, 2010 at 2:49 PM, André Warnier a...@ice-sa.com wrote: What do you see when running ps -ef | grep tomcat ? Hi André, I see loadsa stuff I don't understand :) Luís $ ps -ef | grep tomcat root 2129 1 0 08:07 ?00:00:00 /usr/bin/jsvc -user tomcat6 -cp /usr/share/java/commons-daemon.jar:/usr/share/tomcat6/bin/bootstrap.jar -outfile SYSLOG -errfile SYSLOG -pidfile /var/run/tomcat6.pid -Djava.awt.headless=true -Xmx128M -Djava.endorsed.dirs=/usr/share/tomcat6/endorsed -Dcatalina.base=/var/lib/tomcat6 -Dcatalina.home=/usr/share/tomcat6 -Djava.io.tmpdir=/tmp/tomcat6-temp -Djava.security.manager -Djava.security.policy=/var/lib/tomcat6/work/catalina.policy -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager -Djava.util.logging.config.file=/var/lib/tomcat6/conf/logging.properties org.apache.catalina.startup.Bootstrap root 2131 2129 0 08:07 ?00:00:00 /usr/bin/jsvc -user tomcat6 -cp /usr/share/java/commons-daemon.jar:/usr/share/tomcat6/bin/bootstrap.jar -outfile SYSLOG -errfile SYSLOG -pidfile /var/run/tomcat6.pid -Djava.awt.headless=true -Xmx128M -Djava.endorsed.dirs=/usr/share/tomcat6/endorsed -Dcatalina.base=/var/lib/tomcat6 -Dcatalina.home=/usr/share/tomcat6 -Djava.io.tmpdir=/tmp/tomcat6-temp -Djava.security.manager -Djava.security.policy=/var/lib/tomcat6/work/catalina.policy -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager -Djava.util.logging.config.file=/var/lib/tomcat6/conf/logging.properties org.apache.catalina.startup.Bootstrap tomcat6 2132 2129 0 08:07 ?00:00:12 /usr/bin/jsvc -user tomcat6 -cp /usr/share/java/commons-daemon.jar:/usr/share/tomcat6/bin/bootstrap.jar -outfile SYSLOG -errfile SYSLOG -pidfile /var/run/tomcat6.pid -Djava.awt.headless=true -Xmx128M -Djava.endorsed.dirs=/usr/share/tomcat6/endorsed -Dcatalina.base=/var/lib/tomcat6 -Dcatalina.home=/usr/share/tomcat6 -Djava.io.tmpdir=/tmp/tomcat6-temp -Djava.security.manager -Djava.security.policy=/var/lib/tomcat6/work/catalina.policy -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager -Djava.util.logging.config.file=/var/lib/tomcat6/conf/logging.properties org.apache.catalina.startup.Bootstrap root 8600 1 0 14:01 pts/100:00:13 /usr/bin/java -Djava.util.logging.config.file=/usr/share/tomcat6/conf/logging.properties -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager -Djava.endorsed.dirs=/usr/share/tomcat6/endorsed -classpath :/usr/share/tomcat6/bin/bootstrap.jar -Dcatalina.base=/usr/share/tomcat6 -Dcatalina.home=/usr/share/tomcat6 -Djava.io.tmpdir=/usr/share/tomcat6/temp org.apache.catalina.startup.Bootstrap start lads 9328 3055 0 14:52 pts/100:00:00 grep tomcat - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
RE: Can't login to Tomcat manager pages
Sorry, yes, Pid, that's what I meant. Sorry for confusion there. -Original Message- From: Pid [mailto:p...@pidster.com] Sent: Thursday, April 22, 2010 2:57 AM To: Tomcat Users List Subject: Re: Can't login to Tomcat manager pages On 21/04/2010 18:45, Propes, Barry L wrote: I started having a similar problem yesterday and discovered that somehow my web.xml file had been deleted (not sure how), so I replaced it. Make sure you have that in your manager folder in WEB-INF. Barry probably meant: make sure you have a web.xml in WEB-INF, in webapps/manager - because a web.xml in a manager directory in (any) WEB-INF isn't going to be discovered by Tomcat. p -Original Message- From: Luís de Sousa [mailto:luis.a.de.so...@gmail.com] Sent: Wednesday, April 21, 2010 12:15 PM To: users@tomcat.apache.org Subject: Can't login to Tomcat manager pages Dear all, Tomcat 6.0.20 on Ubuntu 9.10. I can't login to the manager pages (http://localhost:8080/manager/html). I set a new user and a few roles in the /etc/tomcat6/tomcat-users.xml file, restarted Tomcat but can't possibly login. I browsed through a number of threads with similar issues but couldn't solve it so far. Note that I uncommented the users section in the file, it is reproduced below. Thanks for you time, Luís -- ?xml version='1.0' encoding='utf-8'? tomcat-users role rolename=admin/ role rolename=manager/ role rolename=standard/ user username=admin password=admin roles=admin,standard,manager/ /tomcat-users - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: How to configure ProxyPassReverse for SSL redirect
On Thu, Apr 22, 2010 at 3:25 AM, Timo Meinen timomei...@googlemail.com wrote: our configuration is a Apache 2.2 web server, acting as a reverse proxy for Tomcat 6. This is the configuration: ServerName it.localhost.de ProxyPass / ajp://127.0.0.1:8009/spike/ ProxyPassReverse / ajp://127.0.0.1:8009/spike/ ProxyPassReverseCookiePath /spike / That's *one* configuration -- do you have this for both the standard port 80 and SSL port 443? In a default 2.2.x install there are separate extra/httpd-vhosts.conf and extra/httpd-ssl.conf files. -- Hassan Schroeder hassan.schroe...@gmail.com twitter: @hassan - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: How to configure ProxyPassReverse for SSL redirect
Hi Hassan, yes, there are two VirtualHost entries. One for port 80 and one for port 443 with SSL engine enabled. Both have the same proxy configuration. Timo 2010/4/22 Hassan Schroeder hassan.schroe...@gmail.com: On Thu, Apr 22, 2010 at 3:25 AM, Timo Meinen timomei...@googlemail.com wrote: our configuration is a Apache 2.2 web server, acting as a reverse proxy for Tomcat 6. This is the configuration: ServerName it.localhost.de ProxyPass / ajp://127.0.0.1:8009/spike/ ProxyPassReverse / ajp://127.0.0.1:8009/spike/ ProxyPassReverseCookiePath /spike / That's *one* configuration -- do you have this for both the standard port 80 and SSL port 443? In a default 2.2.x install there are separate extra/httpd-vhosts.conf and extra/httpd-ssl.conf files. -- Hassan Schroeder hassan.schroe...@gmail.com twitter: @hassan - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -- Glück Auf Timo - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Where is this class?
Hi, Im running Tomcat 6.0.26. In my app, I'm getting a java.lang.ClassNotFoundException: javax.validation.ValidatorFactory exception. Does anyone know where to find the ValidatorFactory class? More generally, is there a web site taht will tell me what JAR a particular class belongs to? Thanks, - Dave -- View this message in context: http://old.nabble.com/Where-is-this-class--tp28332023p28332023.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
RE: Where is this class?
http://jcp.org/en/jsr/detail?id=303 -Original Message- From: laredotornado [mailto:laredotorn...@gmail.com] Sent: Thursday, April 22, 2010 12:22 PM To: users@tomcat.apache.org Subject: Where is this class? Hi, Im running Tomcat 6.0.26. In my app, I'm getting a java.lang.ClassNotFoundException: javax.validation.ValidatorFactory exception. Does anyone know where to find the ValidatorFactory class? More generally, is there a web site taht will tell me what JAR a particular class belongs to? Thanks, - Dave -- View this message in context: http://old.nabble.com/Where-is-this-class--tp28332023p28332023.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
RE: Where is this class?
Is this just the documentation ? I'm not able to find the JAR file to download from this page. Thanks, - Dave Joseph Morgan-2 wrote: http://jcp.org/en/jsr/detail?id=303 -Original Message- From: laredotornado [mailto:laredotorn...@gmail.com] Sent: Thursday, April 22, 2010 12:22 PM To: users@tomcat.apache.org Subject: Where is this class? Hi, Im running Tomcat 6.0.26. In my app, I'm getting a java.lang.ClassNotFoundException: javax.validation.ValidatorFactory exception. Does anyone know where to find the ValidatorFactory class? More generally, is there a web site taht will tell me what JAR a particular class belongs to? Thanks, - Dave -- View this message in context: http://old.nabble.com/Where-is-this-class--tp28332023p28332023.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -- View this message in context: http://old.nabble.com/Where-is-this-class--tp28332023p28332333.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Session Timeout - Filter Not Called
I guess what I really need to be able to do is determine when a user creates a new session. This could either be done by the user opening the browser and browse to our application where the user logs in and the new session is created. Or the user's session times out and the user is presented with our login page and the user will login and a new session is created. --- rfha...@yahoo.com wrote: From: Bob Hall rfha...@yahoo.com To: Tomcat Users List users@tomcat.apache.org Subject: Re: Session Timeout - Filter Not Called Date: Mon, 12 Apr 2010 23:58:45 -0700 (PDT) Paul, --- On Mon, 4/12/10 at 7:21 AM, Paul Carroll pcarr...@nfmail.net wrote: That works in that my filter is called when the session times out and the user is redirected to the login page. However, the Referer header makes no indication that the user is logging in. What does the referrer header contain? If the request URI is not null, then I can redirect them to the requested URI if it has been determined that it is a safe area that does not need any session variables established. Is there a way to determine if the user's session has timed out and the user is logging in once again? Check for the session variables that would have been set? - Bob - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
RE: Where is this class?
Sorry. Go to this page: http://jcp.org/aboutJava/communityprocess/final/jsr303/index.html And then click on the Reference Implementation link to download it from there. Unzip the file and in the lib directory you'll find a validation-api-1.0.0.GA.jar which will have the class in it -Original Message- From: laredotornado [mailto:laredotorn...@gmail.com] Sent: Thursday, April 22, 2010 12:45 PM To: users@tomcat.apache.org Subject: RE: Where is this class? Is this just the documentation ? I'm not able to find the JAR file to download from this page. Thanks, - Dave Joseph Morgan-2 wrote: http://jcp.org/en/jsr/detail?id=303 -Original Message- From: laredotornado [mailto:laredotorn...@gmail.com] Sent: Thursday, April 22, 2010 12:22 PM To: users@tomcat.apache.org Subject: Where is this class? Hi, Im running Tomcat 6.0.26. In my app, I'm getting a java.lang.ClassNotFoundException: javax.validation.ValidatorFactory exception. Does anyone know where to find the ValidatorFactory class? More generally, is there a web site taht will tell me what JAR a particular class belongs to? Thanks, - Dave -- View this message in context: http://old.nabble.com/Where-is-this-class--tp28332023p28332023.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -- View this message in context: http://old.nabble.com/Where-is-this-class--tp28332023p28332333.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Client cert authentication
Thanks Mark,
I use mod_proxy (ProxyPass and ProxyReverse) to connect Apache (2.2.3) to
Tomcat(5.5)/Jboss (4.2). Can mod_proxy pass client cert to Tomcat?
I use the following code to get the client cert, but certs object is null:
public void verificaCertCliente(HttpServletRequest req) throws
ServletException
{
String[] mensagem = null;
X509Certificate[] certs = (X509Certificate[])
req.getAttribute(javax.servlet.request.X509Certificate);
if (certs != null) {
for (int i = 0; i certs.length; i++) {
mensagem[i] = (Client Certificate [ + i + ] = +
certs[i].toString());
log.info(mensagem[i]);
}
} else {
if (https.equals(req.getScheme())) {
log.info(This was an HTTPS request, + but no client certificate is
available);
} else {
log.info(This was not an HTTPS request, + so no client certificate
is available);
}
}
}
Thanks in advance for your attention.
markt-2 wrote:
On 19/04/2010 13:05, acastanheira2001 wrote:
Hi,
I have an apache server in front of Tomcat/Jboss, the former receives the
client cert and does revocation list and trust validation.
I need to pass the client cert to Tomcat only to check the
SubjectAltNames.
As far as trust accreditation is done by apache, does Tomcat need to have
a
keystore and https set?
No.
Mark
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
--
View this message in context:
http://old.nabble.com/Client-cert-authentication-tp28287654p28333274.html
Sent from the Tomcat - User mailing list archive at Nabble.com.
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Client cert authentication
On 22/04/2010 20:00, acastanheira2001 wrote: Thanks Mark, I use mod_proxy (ProxyPass and ProxyReverse) to connect Apache (2.2.3) to Tomcat(5.5)/Jboss (4.2). Can mod_proxy pass client cert to Tomcat? With 5.5.x, not with out some custom code. With 6.0.x, yes. You'd need to port this to Tomcat 5: http://svn.apache.org/viewvc/tomcat/tc6.0.x/trunk/java/org/apache/catalina/valves/SSLValve.java?view=annotate Mark - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Running tomcat/6.0.26 with security manager generates ORACLE jdbc error
hi Users, when I run TOMCAT using -security option on Java 1.6 jdk, I get following error. I added policy definitions for all properities, oraclejars and JNDIpermission for the context. org.apache.jasper.JasperException: java.lang.ArrayIndexOutOfBoundsException: -1 org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:491) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:419) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) java.lang.reflect.Method.invoke(Method.java:597) org.apache.catalina.security.SecurityUtil$1.run(SecurityUtil.java:269) java.security.AccessController.doPrivileged(Native Method) javax.security.auth.Subject.doAsPrivileged(Subject.java:517) org.apache.catalina.security.SecurityUtil.execute(SecurityUtil.java:301) org.apache.catalina.security.SecurityUtil.doAsPrivilege(SecurityUtil.java:162) root cause java.lang.ArrayIndexOutOfBoundsException: -1 oracle.jdbc.driver.T4CTTIoauthenticate.setSessionFields(T4CTTIoauthenticate.java:942) oracle.jdbc.driver.T4CTTIoauthenticate.init(T4CTTIoauthenticate.java:221) oracle.jdbc.driver.T4CConnection.logon(T4CConnection.java:358) oracle.jdbc.driver.PhysicalConnection.init(PhysicalConnection.java:508) oracle.jdbc.driver.T4CConnection.init(T4CConnection.java:203) oracle.jdbc.driver.T4CDriverExtension.getConnection(T4CDriverExtension.java:33) oracle.jdbc.driver.OracleDriver.connect(OracleDriver.java:510) oracle.jdbc.pool.OracleDataSource.getPhysicalConnection(OracleDataSource.java:275) oracle.jdbc.pool.OracleDataSource.getConnection(OracleDataSource.java:206) xxx.yyy.CPC.data.DAOUtil.getConnection(Unknown Source) xxx.yyy.CPC.logging.LogDAO.createLog(Unknown Source) xxx.yyy.CPC.logging.DBLogger.db(Unknown Source) org.apache.jsp.CPC.Default_jsp._jspService(Default_jsp.java:90) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:377) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) java.lang.reflect.Method.invoke(Method.java:597) org.apache.catalina.security.SecurityUtil$1.run(SecurityUtil.java:269) java.security.AccessController.doPrivileged(Native Method) javax.security.auth.Subject.doAsPrivileged(Subject.java:517) org.apache.catalina.security.SecurityUtil.execute(SecurityUtil.java:301) org.apache.catalina.security.SecurityUtil.doAsPrivilege(SecurityUtil.java:162) when I run the similar program outside tomcat with -security it runs fine. any thoughts -suresh -- View this message in context: http://old.nabble.com/Running-tomcat-6.0.26-with-security-manager-generates-ORACLE-jdbc-error-tp28333480p28333480.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Where is this class? - Check out http://findjar.com
Dave, Yes, there is, http://findjar.com On Thu, 22 Apr 2010 11:22:05 -0600, laredotornado laredotorn...@gmail.com wrote: Hi, Im running Tomcat 6.0.26. In my app, I'm getting a java.lang.ClassNotFoundException: javax.validation.ValidatorFactory exception. Does anyone know where to find the ValidatorFactory class? More generally, is there a web site taht will tell me what JAR a particular class belongs to? Thanks, - Dave -- Using Opera's revolutionary e-mail client: http://www.opera.com/mail/ - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Bill, On 4/22/2010 2:37 AM, Bill Barker wrote: It's pretty inaccessible for novice Java programmers, but you could use the proxy API which is [just] about the coolest thing available in Java IMO. If it does a forward or include done the line, this won't work with any remotely recent version of Tomcat. These versions enforce the spec requirement that the Request has to be a subclass of HttpServletWrapper wrapping the original request, or the original request. How does Tomcat enforce that? HttpServletRequestWrapper doesn't expose the underlying request. I must admit that I didn't try it. I should. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQpjMACgkQ9CaO5/Lv0PDioACfXvCsWsL6dPHDsegCEqCx0ISZ oF8Anj+PpzWrSWN9I6BWru0urmdLaWLg =qt08 -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
On Thu, Apr 22, 2010 at 3:40 PM, Christopher Schultz ch...@christopherschultz.net wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Bill, On 4/22/2010 2:37 AM, Bill Barker wrote: It's pretty inaccessible for novice Java programmers, but you could use the proxy API which is [just] about the coolest thing available in Java IMO. If it does a forward or include done the line, this won't work with any remotely recent version of Tomcat. These versions enforce the spec requirement that the Request has to be a subclass of HttpServletWrapper wrapping the original request, or the original request. How does Tomcat enforce that? HttpServletRequestWrapper doesn't expose the underlying request. ...but ServletRequestWrapper does I must admit that I didn't try it. I should. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQpjMACgkQ9CaO5/Lv0PDioACfXvCsWsL6dPHDsegCEqCx0ISZ oF8Anj+PpzWrSWN9I6BWru0urmdLaWLg =qt08 -END PGP SIGNATURE- -- Kris Schneider - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Bill,
On 4/22/2010 2:37 AM, Bill Barker wrote:
If [the request/filter] does a forward or include done the line, this
won't work with any remotely recent version of Tomcat. These
versions enforce the spec requirement that the Request has to be a
subclass of HttpServletWrapper wrapping the original request, or the
original request.
The following filter works as expected on Tomcat 6.0.26 (some changes
were required to make it actually work... my off-the-cuff implementation
was lacking a few details).
I can confirm that this filter operates properly across a forward()
call: I have a struts action handles by the Struts servlet that forwards
to a Velocity template handled by the Velocity servlet. All calls are
logged to stdout. (Wow, lots of calls to Request.getAttribute!)
import java.io.IOException;
import java.lang.reflect.InvocationHandler;
import java.lang.reflect.Method;
import java.lang.reflect.Proxy;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class RequestMethodCallLogger
implements Filter
{
public void doFilter(ServletRequest request,
ServletResponse response,
FilterChain chain)
throws ServletException, IOException
{
if(request instanceof HttpServletRequest)
request = (ServletRequest)Proxy
.newProxyInstance(HttpServletRequest.class.getClassLoader(),
new Class[] {
HttpServletRequest.class },
new Wrapper(request));
chain.doFilter(request, response);
}
public void init(FilterConfig config) { }
public void destroy() { }
static class Wrapper
implements InvocationHandler
{
private Object _target;
Wrapper(Object target)
{
_target = target;
}
public Object invoke(Object proxy, Method method, Object[] args)
throws Throwable
{
System.out.print(Intercepted: );
System.out.println(method);
return method.invoke(_target, args);
}
}
}
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.10 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/
iEYEARECAAYFAkvQsjUACgkQ9CaO5/Lv0PA65ACgiR4tiSji6MElZr9/Z0ibXdtX
WJQAnRoB/GZbrSwdfPjcf50IpHFmW4L9
=Stkm
-END PGP SIGNATURE-
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Running tomcat/6.0.26 with security manager generates ORACLE jdbc error
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Suresh, On 4/22/2010 3:19 PM, suresht wrote: when I run TOMCAT using -security option on Java 1.6 jdk, I get following error. I added policy definitions for all properities, oraclejars and JNDIpermission for the context. Care to share those policy definitions? java.lang.ArrayIndexOutOfBoundsException: -1 oracle.jdbc.driver.T4CTTIoauthenticate.setSessionFields(T4CTTIoauthenticate.java:942) Are you running the latest version of Oracle's JDBC driver? when I run the similar program outside tomcat with -security it runs fine. any thoughts Tomcat + your webapp + Oracle JDBC Driver + SecurityManager = Exception Some other app + Oracle JDBC Driver = no exception There are very few common terms in those two equations. Are you sure they have any relation to one another? For instance, are you running your similar program with the same policy file? Are you running through the same code that your webapp does? You never said whether your webapp works properly without the SecurityManager installed. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQtFcACgkQ9CaO5/Lv0PDm2QCbBZChSL7huRcZS18GvFBFCTza 1BUAn1WGlfBSYbboiHeZNbC/GqxcNzDP =zOZB -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Session Timeout - Filter Not Called
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Paul, On 4/22/2010 2:44 PM, Paul Carroll wrote: I guess what I really need to be able to do is determine when a user creates a new session. This could either be done by the user opening the browser and browse to our application where the user logs in and the new session is created. Or the user's session times out and the user is presented with our login page and the user will login and a new session is created. I think Bob's suggestion that you use a session marker variable will take care of this for you, no? --- rfha...@yahoo.com wrote: From: Bob Hall rfha...@yahoo.com To: Tomcat Users List users@tomcat.apache.org Subject: Re: Session Timeout - Filter Not Called Date: Mon, 12 Apr 2010 23:58:45 -0700 (PDT) Paul, --- On Mon, 4/12/10 at 7:21 AM, Paul Carroll pcarr...@nfmail.net wrote: That works in that my filter is called when the session times out and the user is redirected to the login page. However, the Referer header makes no indication that the user is logging in. What does the referrer header contain? If the request URI is not null, then I can redirect them to the requested URI if it has been determined that it is a safe area that does not need any session variables established. Is there a way to determine if the user's session has timed out and the user is logging in once again? Check for the session variables that would have been set? - Bob - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQtVYACgkQ9CaO5/Lv0PB3lQCfZVO1HEaBGdeIQpsKb3ebkLp5 eUIAn1DndzYGedUzYnapHgKi5DOasGpz =NbBJ -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
On Thu, Apr 22, 2010 at 4:31 PM, Christopher Schultz
ch...@christopherschultz.net wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Bill,
On 4/22/2010 2:37 AM, Bill Barker wrote:
If [the request/filter] does a forward or include done the line, this
won't work with any remotely recent version of Tomcat. These
versions enforce the spec requirement that the Request has to be a
subclass of HttpServletWrapper wrapping the original request, or the
original request.
The following filter works as expected on Tomcat 6.0.26 (some changes
were required to make it actually work... my off-the-cuff implementation
was lacking a few details).
I can confirm that this filter operates properly across a forward()
call: I have a struts action handles by the Struts servlet that forwards
to a Velocity template handled by the Velocity servlet. All calls are
logged to stdout. (Wow, lots of calls to Request.getAttribute!)
For reference, here's the snippet from the Servlet 2.5 Spec:
SRV.8.2 Using a Request Dispatcher
To use a request dispatcher, a servlet calls either the include method
or forward method of the RequestDispatcher interface. The parameters
to these methods can be either the request and response arguments that
were passed in via the service method of the javax.servlet interface,
or instances of subclasses of the request and response wrapper classes
that were introduced for version 2.3 of the specification. In the
latter case, the wrapper instances must wrap the request or response
objects that the container passed into the service method.
But...the proxy is created prior to entering a servlet's service
method, so it may well appear to be the original request for the
purposes of creating and validating a dispatcher and its parameters...
import java.io.IOException;
import java.lang.reflect.InvocationHandler;
import java.lang.reflect.Method;
import java.lang.reflect.Proxy;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class RequestMethodCallLogger
implements Filter
{
public void doFilter(ServletRequest request,
ServletResponse response,
FilterChain chain)
throws ServletException, IOException
{
if(request instanceof HttpServletRequest)
request = (ServletRequest)Proxy
.newProxyInstance(HttpServletRequest.class.getClassLoader(),
new Class[] {
HttpServletRequest.class },
new Wrapper(request));
chain.doFilter(request, response);
}
public void init(FilterConfig config) { }
public void destroy() { }
static class Wrapper
implements InvocationHandler
{
private Object _target;
Wrapper(Object target)
{
_target = target;
}
public Object invoke(Object proxy, Method method, Object[] args)
throws Throwable
{
System.out.print(Intercepted: );
System.out.println(method);
return method.invoke(_target, args);
}
}
}
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.10 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/
iEYEARECAAYFAkvQsjUACgkQ9CaO5/Lv0PA65ACgiR4tiSji6MElZr9/Z0ibXdtX
WJQAnRoB/GZbrSwdfPjcf50IpHFmW4L9
=Stkm
-END PGP SIGNATURE-
--
Kris Schneider
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Could not get dir listing
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Christoph, On 4/21/2010 8:59 AM, Christoph Kukulies wrote: Strange. Don't know whether this has happened since I upgraded to Tomcat 6.0.26, anyway, my application doesn't start anymore. :( 21.04.2010 14:49:36 org.apache.naming.resources.FileDirContext list WARNUNG: Could not get dir listing for C:\Programme\Apache_Group\Tomcat_6.0\webapps\ROOT\WEB-INF\lib 21.04.2010 14:49:36 org.apache.naming.resources.FileDirContext list WARNUNG: Could not get dir listing for C:\Programme\Apache_Group\Tomcat_6.0\webapps\ROOT\WEB-INF The directories are there. I compared the entry with a backup I have and I couldn't see any differences. Sounds like a permissions issue. Check all the permissions for the directories in that path to make sure the Tomcat user has access to them. Remember that if you're running Tomcat as a service, it runs with virtually no access privileges. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQtjgACgkQ9CaO5/Lv0PCbnACfYlfSTp327QATuozOlWR0dCzQ JWQAoIAMHdt93nJHFoldWNfDk5/b/k2s =q4Ie -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Running tomcat/6.0.26 with security manager generates ORACLE jdbc error
hi Christopher i have attached a copy of the policy file. yes that is true but the command line application includes the security manager with equivalent policy, Tomcat + your webapp + Oracle JDBC Driver + SecurityManager = Exception Some other app + Oracle JDBC Driver = no exception I am running oracle jdbc thin driver ConnectionPool http://old.nabble.com/file/p28334465/catalina.policy.2 catalina.policy.2 11.1.0.7.0-Produ The web application works fine without the security manager. Christopher Schultz-2 wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Suresh, On 4/22/2010 3:19 PM, suresht wrote: when I run TOMCAT using -security option on Java 1.6 jdk, I get following error. I added policy definitions for all properities, oraclejars and JNDIpermission for the context. Care to share those policy definitions? java.lang.ArrayIndexOutOfBoundsException: -1 oracle.jdbc.driver.T4CTTIoauthenticate.setSessionFields(T4CTTIoauthenticate.java:942) Are you running the latest version of Oracle's JDBC driver? when I run the similar program outside tomcat with -security it runs fine. any thoughts Tomcat + your webapp + Oracle JDBC Driver + SecurityManager = Exception Some other app + Oracle JDBC Driver = no exception There are very few common terms in those two equations. Are you sure they have any relation to one another? For instance, are you running your similar program with the same policy file? Are you running through the same code that your webapp does? You never said whether your webapp works properly without the SecurityManager installed. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQtFcACgkQ9CaO5/Lv0PDm2QCbBZChSL7huRcZS18GvFBFCTza 1BUAn1WGlfBSYbboiHeZNbC/GqxcNzDP =zOZB -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -- View this message in context: http://old.nabble.com/Running-tomcat-6.0.26-with-security-manager-generates-ORACLE-jdbc-error-tp28333480p28334465.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: separating content from the application
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Milko, On 4/21/2010 4:54 AM, M.H.G. Emmerig wrote: webapps\Root\applicationfiles webapps\Root\content\publications webapps\Root\content\images Make sure that's ROOT, not Root, unless your webapp really is called Root. the application comes as a war file and the content is placed via another process. the folder structure is placed on a windows share. Yikes. I've seen clusters using NFS to share a deployment like this... it doesn't work well. Our current problem: Whenever there is a problem with the share, the application crashes, because tomcat can't find the application files anymore. Yup. When the share comes back online, tomcat does not recover from the failure and a restart is the only option. Yup. Now I have the following questions: I think separating the application from the content and placing the application local to tomcat (basically on the same machine) will solve the recovery issue. Yes, but the content will seem to disappear and reappear. I'm not an expert with Tomcat's DefaultServlet, but it does some caching of data and might actually cache a 404/500 so any interruption of data access might result in the content disappearing for longer than the share's disappearance. I know placing everything local to the tomcat will be the best way and gives the best performance, but at the moment that is not an option. That's too bad. The questions - Will placing the app local to the tomcat solve the recovery issue? Tomcat will not have to recover, so, presumably, yes. - Is there an easy way to separate the app and the content, ie. some sort of pathsetting ? That depends on how you use your content. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQtzwACgkQ9CaO5/Lv0PAaDACeKQHuefJiiZcmbBBv7u1fH40T qhkAoLf4cYu3hpnVT14/CN6ZgJruxFX9 =LKQW -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
2010/4/23 Kris Schneider kschnei...@gmail.com: On Thu, Apr 22, 2010 at 4:31 PM, Christopher Schultz ch...@christopherschultz.net wrote: -BEGIN PGP SIGNED MESSAGE- On 4/22/2010 2:37 AM, Bill Barker wrote: If [the request/filter] does a forward or include done the line, this won't work with any remotely recent version of Tomcat. These versions enforce the spec requirement that the Request has to be a subclass of HttpServletWrapper wrapping the original request, or the original request. SRV.8.2 is enforced when STRICT_SERVLET_COMPLIANCE property is set to true. http://tomcat.apache.org/tomcat-6.0-doc/config/systemprops.html#Specification Best regards, Konstantin Kolinko - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Kris, On 4/22/2010 4:48 PM, Kris Schneider wrote: On Thu, Apr 22, 2010 at 4:31 PM, Christopher Schultz ch...@christopherschultz.net wrote: The following filter works as expected on Tomcat 6.0.26 (some changes were required to make it actually work... my off-the-cuff implementation was lacking a few details). For reference, here's the snippet from the Servlet 2.5 Spec: SRV.8.2 Using a Request Dispatcher To use a request dispatcher, a servlet calls either the include method or forward method of the RequestDispatcher interface. The parameters to these methods can be either the request and response arguments that were passed in via the service method of the javax.servlet interface, or instances of subclasses of the request and response wrapper classes that were introduced for version 2.3 of the specification. In the latter case, the wrapper instances must wrap the request or response objects that the container passed into the service method. But...the proxy is created prior to entering a servlet's service method Yes, but there's nothing stopping me from placing the filter so that it only wraps FORWARD requests and violating the specification. I'll try that: I'm sure it'll still work. so it may well appear to be the original request for the purposes of creating and validating a dispatcher and its parameters... It probably doesn't matter: there's no real value in enforcing this particular requirement of the specification, so I'd be surprised if anyone has bothered to do so. Yup: adding dispatcherFORWARD/dispatcher to my filter still intercepts the calls without complaint. With a Servlet 2.3 DOCTYPE to boot. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQuwwACgkQ9CaO5/Lv0PAH+ACdHvyK0sJoaDQ1qIbnWA5eD9c8 sccAoL4TyPUWAcvzXTE06vha3QFYUK4s =EehI -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Konstantin, On 4/22/2010 4:53 PM, Konstantin Kolinko wrote: 2010/4/23 Kris Schneider kschnei...@gmail.com: On Thu, Apr 22, 2010 at 4:31 PM, Christopher Schultz ch...@christopherschultz.net wrote: -BEGIN PGP SIGNED MESSAGE- On 4/22/2010 2:37 AM, Bill Barker wrote: If [the request/filter] does a forward or include done the line, this won't work with any remotely recent version of Tomcat. These versions enforce the spec requirement that the Request has to be a subclass of HttpServletWrapper wrapping the original request, or the original request. SRV.8.2 is enforced when STRICT_SERVLET_COMPLIANCE property is set to true. http://tomcat.apache.org/tomcat-6.0-doc/config/systemprops.html#Specification $ export CATALINA_OPTS=-Dorg.apache.catalina.STRICT_SERVLET_COMPLIANCE=true $ ant tomcat-start Buildfile: build.xml check-local-properties: build-local-properties: init: check-tomcat-config: prepare-local-tomcat: tomcat-start: [echo] === [echo] Starting Tomcat [echo] === [echo] JAVA_HOME is /usr [echo] JAVA_OPTS is -Xmx64M [echo] CATALINA_HOME is /usr/local/apache-tomcat-6.0.26 [echo] CATALINA_BASE is /xxx [echo] CATALINA_OPTS is - -Dorg.apache.catalina.STRICT_SERVLET_COMPLIANCE=true - -Djava.library.path=/usr/local/apache-tomcat-6.0.26/server/lib [echo] security-option is BUILD SUCCESSFUL Total time: 0 seconds $ Still runs. :p I double-checked that the system property org.apache.catalina.STRICT_SERVLET_COMPLIANCE = true in the running VM. It is. I'd love to see the code that enforces this: it shouldn't be that hard to do, as Tomcat gets to specify the implementation of the original request and can unwrap any wrapped request to determine if it's legit. Kris and Bill are right: this shouldn't work, but it does. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQvIEACgkQ9CaO5/Lv0PCmBQCfYmmspo4D8/Dvh0G7/QrF5dI7 eQYAoKLfh7XbI6wphEMyxuikqDORthlk =l+5A -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Running tomcat/6.0.26 with security manager generates ORACLE jdbc error
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Suresh, On 4/22/2010 4:51 PM, suresht wrote: i have attached a copy of the policy file. It was stripped by the list. yes that is true but the command line application includes the security manager with equivalent policy Ok. The web application works fine without the security manager. Since the error occurs in the JDBC driver, I would imagine that the problem is there: the driver is not properly checking array bounds when accessing a String. Now, more than likely it's some String that is no longer available due to the presence of the SecurityManager, but we'll never know what the real problem is until we can get a report of what String the driver can't read properly. Do you have the source code of the JDBC driver? Can you decompile it to find out what is blowing up? - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQvccACgkQ9CaO5/Lv0PDqXQCfT5BcPuXT2qaKp4ZCChMsBrKy Ex4AnikHuVhogRnOM8HW0y3cx9TjqRWu =4vR2 -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Session Timeout - Filter Not Called
Yes. I put the session marker in my filter and I perform a simple check each time through the filter to determine if the marker exists and to check if it equals the current session id. Thanks. --- ch...@christopherschultz.net wrote: From: Christopher Schultz ch...@christopherschultz.net To: Tomcat Users List users@tomcat.apache.org Subject: Re: Session Timeout - Filter Not Called Date: Thu, 22 Apr 2010 16:45:10 -0400 -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Paul, On 4/22/2010 2:44 PM, Paul Carroll wrote: I guess what I really need to be able to do is determine when a user creates a new session. This could either be done by the user opening the browser and browse to our application where the user logs in and the new session is created. Or the user's session times out and the user is presented with our login page and the user will login and a new session is created. I think Bob's suggestion that you use a session marker variable will take care of this for you, no? --- rfha...@yahoo.com wrote: From: Bob Hall rfha...@yahoo.com To: Tomcat Users List users@tomcat.apache.org Subject: Re: Session Timeout - Filter Not Called Date: Mon, 12 Apr 2010 23:58:45 -0700 (PDT) Paul, --- On Mon, 4/12/10 at 7:21 AM, Paul Carroll pcarr...@nfmail.net wrote: That works in that my filter is called when the session times out and the user is redirected to the login page. However, the Referer header makes no indication that the user is logging in. What does the referrer header contain? If the request URI is not null, then I can redirect them to the requested URI if it has been determined that it is a safe area that does not need any session variables established. Is there a way to determine if the user's session has timed out and the user is logging in once again? Check for the session variables that would have been set? - Bob - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQtVYACgkQ9CaO5/Lv0PB3lQCfZVO1HEaBGdeIQpsKb3ebkLp5 eUIAn1DndzYGedUzYnapHgKi5DOasGpz =NbBJ -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: a servlet-related Java question
2010/4/23 Christopher Schultz ch...@christopherschultz.net: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Konstantin, On 4/22/2010 4:53 PM, Konstantin Kolinko wrote: 2010/4/23 Kris Schneider kschnei...@gmail.com: On Thu, Apr 22, 2010 at 4:31 PM, Christopher Schultz ch...@christopherschultz.net wrote: -BEGIN PGP SIGNED MESSAGE- On 4/22/2010 2:37 AM, Bill Barker wrote: If [the request/filter] does a forward or include done the line, this won't work with any remotely recent version of Tomcat. These versions enforce the spec requirement that the Request has to be a subclass of HttpServletWrapper wrapping the original request, or the original request. SRV.8.2 is enforced when STRICT_SERVLET_COMPLIANCE property is set to true. http://tomcat.apache.org/tomcat-6.0-doc/config/systemprops.html#Specification $ export CATALINA_OPTS=-Dorg.apache.catalina.STRICT_SERVLET_COMPLIANCE=true I'd love to see the code that enforces this: Search for applicationDispatcher.specViolation.request and applicationDispatcher.specViolation.response or for SRV.8.2 in the code. Best regards, Konstantin Kolinko - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: virtual host configuration
Try here http://myunster.com/blog/10.html http://myunster.com/blog/10.htmlBest Regards, Leon Kolchinsky On Thu, Apr 22, 2010 at 12:00, daulat khan daulat@gmail.com wrote: Hi, I am planning to setup virtual hosting in apache-tomcat integrated setup. Please share useful links or docs which will help me in accomplishing this. also using, httpd v2.2.14 tomcat v6.0.20 tomcat connector v1.2.28 Thanks, Daulatkhan - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Running tomcat/6.0.26 with security manager generates ORACLE jdbc error
hi Christopher, I see a char array being set to a number. charstring1[charstring1-1] = 0; Christopher Schultz-2 wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Suresh, On 4/22/2010 4:51 PM, suresht wrote: i have attached a copy of the policy file. It was stripped by the list. yes that is true but the command line application includes the security manager with equivalent policy Ok. The web application works fine without the security manager. Since the error occurs in the JDBC driver, I would imagine that the problem is there: the driver is not properly checking array bounds when accessing a String. Now, more than likely it's some String that is no longer available due to the presence of the SecurityManager, but we'll never know what the real problem is until we can get a report of what String the driver can't read properly. Do you have the source code of the JDBC driver? Can you decompile it to find out what is blowing up? - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkvQvccACgkQ9CaO5/Lv0PDqXQCfT5BcPuXT2qaKp4ZCChMsBrKy Ex4AnikHuVhogRnOM8HW0y3cx9TjqRWu =4vR2 -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org -- View this message in context: http://old.nabble.com/Running-tomcat-6.0.26-with-security-manager-generates-ORACLE-jdbc-error-tp28333480p28336163.html Sent from the Tomcat - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Q: how to obtain notification when a WebApp is unloaded/reloaded?
Following up on an earlier conversation about how to obtain notification when a WebApp is unloaded/reloaded [1], I was told that registering a ServletContextListener is the only possibility (that is, there is no runtime API.) However, registering a ServletContextListener doesn't work and leads to me being unable to start the web application. To recap: I have an application with context reloadable=true. I continuously recompile this application during development. The application starts a worker thread I need to shut down when a newly compiled version of the application is loaded (that is, when new versions of the .class files show up in the WEB-INF/classes directory. Right now, I'm getting messages that the listener class is missing (it isn't - it's just a new .class file after recompilation.) Apr 22, 2010 10:31:25 PM org.apache.catalina.loader.WebappClassLoader modified SEVERE: Resource '/WEB-INF/classes/org/libx/editionbuilder/GCHelper$ShutdownListener.class' is missing Apr 22, 2010 10:31:25 PM org.apache.catalina.core.StandardContext reload INFO: Reloading this Context has started Apr 22, 2010 10:31:25 PM org.apache.catalina.core.StandardContext start SEVERE: Error listenerStart Apr 22, 2010 10:31:25 PM org.apache.catalina.core.StandardContext start SEVERE: Context [/gbed] startup failed due to previous errors My web.xml contains: listener listener-classorg.libx.editionbuilder.GCHelper$ShutdownListener/listener-class /listener So - what is the correct way to register a listener that is executed when an application is reloaded due to a recompilation? Does Tomcat get confused when the listener class itself is part of the to-be-reloaded web application? Thanks. - Godmar [1] See http://mail-archives.apache.org/mod_mbox/tomcat-users/201004.mbox/%3cu2s719dced31004132122oc656c456ya25e1a4ba4d4a...@mail.gmail.com%3e and the messages in that thread. -- Forwarded message -- From: Godmar Back god...@gmail.com Date: Wed, Apr 14, 2010 at 10:20 AM Subject: Re: Q: how to obtain notification when a WebApp is unloaded/reloaded? To: Tomcat Users List users@tomcat.apache.org On Wed, Apr 14, 2010 at 10:12 AM, Pid p...@pidster.com wrote: For instance, if you look at http://java.sun.com/products/servlet/2.3/javadoc/javax/servlet/ServletContextListener.html it says: To recieve (sic) notification events, the implementation class must be configured in the deployment descriptor for the web application. Web applications are largely configured by the web.xml file in app/WEB-INF. Servlets, listeners etc are all configured in it. Thank you for your confirmation. I thought I was going nuts, after having waded through various *Facade classes, hoping to find an API method I could call at runtime. I have added a ServletContextListener, but it is very much a solution I strongly dislike. The reason is that my application is layered on top of another application (ZK), and I don't really want to touch web.xml. 'web.xml' describes how ZK is configured to run inside Tomcat or another J2EE server. My applications runs on top of ZK, and having to go and made changes to the underlying deployment descriptor violates basic principles of layering. It also creates a maintenance problem (unless an application can have multiple .xml files that are combined to form a deployment descriptor). Whenever ZK is updated, a new version of web.xml will be installed, and I would then have to merge my listener declaration into the new file. Just out of curiosity, what is the rationale for the (apparently deliberate) lack of an runtime API? - Godmar
