Re: Circular Particles as Parallel Resonant Tank Circuits
Frank Z wrote. All rotating charges should emit electromagneticenergy and spiral into the nucleus. Why do they not? Is this energy reflected back. What is the mechanism? I believe that free space is not always a constant impediance enviroment. The impediance changes as the intensity of a quantum field exceeds its elastic limit. Its sort of like an insulator breaks down beyond a certain voltage. Here's an abbreviated lesson on how a trapped photon in a lossless-totally -reflecting section of a fiber optic wave guide works, Frank. http://farside.ph.utexas.edu/teaching/jk1/lectures/node95.html Dielectric wave guides "Consider an axisymmetric tube of arbitrary cross section made of some dielectric material and surrounded by a vacuum. This structure can serve as a wave guide provided that the dielectric constant of the material is sufficiently large. Note, however, that the boundary conditions satisfied by the electromagnetic fields are significantly different to those of a conventional wave guide. The transverse fields are governed by two equations; one for the region inside the dielectric, and the other for the vacuum region." "The oscillatory solutions (inside) must be matched to the exponentiating solutions (outside). The boundary conditions are the continuity of normal and and tangential and on the surface of the tube. These boundary conditions are far more complicated than those in a conventional wave guide. For this reason, the normal modes cannot usually be classified as either pure TE or pure TM modes. In general, the normal modes possess both electric and magnetic field components in the transverse plane. However, for the special case of a cylindrical tube o! f dielectric material the normal modes can have either pure TE or pure TM characteristics." Enjoy. Fred
Re: Circular Particles as Parallel Resonant Tank Circuits
Now bend that lossless fiber optic section into a circle "Torus?" with infinite "Q, Frank. Invoke; Heisenberg's Uncertainty Principle. http://zebu.uoregon.edu/~imamura/208/jan27/hup.html "In the Quantum Mechanical world, the idea that we can locate objects exactly breaks down. Let me state this idea more precisely. Suppose a particle has momentum p and position x. In a Quantum Mechanical world, I would not be able to measure p and x precisely. There would be an uncertainty associated with each measurement that I could never get rid of, even in a perfect experiment!!! The size of the uncertainties are not independent; they are related as dp x dx h / (2 x pi) = Planck's constant / (2 x pi) The preceding is a statement of the Heisenberg Uncertainty Principle. A consequence of the Uncertainty Principle is that if an object's position x is defined precisely then the momentum of the object will be only weakly constrained, and vice versa. One cannot simultaneously find both the position and momentum of an object to arbitrary accuracy. " If you can see the photon going around it, I'm certain that the Q is too low. :-) Fred http://farside.ph.utexas.edu/teaching/jk1/lectures/node91.html - Original Message - From: Frederick Sparber To: vortex-l Sent: 3/19/2006 1:55:22 AM Subject: Re: Circular Particles as Parallel Resonant "Tank Circuits" Frank Z wrote. All rotating charges should emit electromagneticenergy and spiral into the nucleus. Why do they not? Is this energy reflected back. What is the mechanism? I believe that free space is not always a constant impediance enviroment. The impediance changes as the intensity of a quantum field exceeds its elastic limit. Its sort of like an insulator breaks down beyond a certain voltage. Here's an abbreviated lesson on how a trapped photon in a lossless-totally -reflecting section of a fiber optic wave guide works, Frank. http://farside.ph.utexas.edu/teaching/jk1/lectures/node95.html Dielectric wave guides "Consider an axisymmetric tube of arbitrary cross section made of some dielectric material and surrounded by a vacuum. This structure can serve as a wave guide provided that the dielectric constant of the material is sufficiently large. Note, however, that the boundary conditions satisfied by the electromagnetic fields are significantly different to those of a conventional wave guide. The transverse fields are governed by two equations; one for the region inside the dielectric, and the other for the vacuum region." "The oscillatory solutions (inside) must be matched to the exponentiating solutions (outside). The boundary conditions are the continuity of normal and and tangential and on the surface of the tube. These boundary conditions are far more complicated than those in a conventional wave guide. For this reason, the normal modes cannot usually be classified as either pure TE or pure TM modes. In general, the normal modes possess both electric and magnetic field components in the transverse plane. However, for the special case of a cylindrical tube o! f! dielectric material the normal modes can have either pure TE or pure TM characteristics." Enjoy. Fred
Re: Efimov state - key to multi-nuclear LENR?
- Original Message - From: Robin van Spaandonk [EMAIL PROTECTED] To: vortex-l@eskimo.com Sent: Saturday, March 18, 2006 8:55 PM Subject: Re: Efimov state - key to multi-nuclear LENR? In reply to RC Macaulay's message of Sat, 18 Mar 2006 07:38:17 -0600: Hi Richard, [snip] Howdy Robin, Simple explanations of physics are never as simple as viewed. The rings, like the favorite magic trick using loops, may actually each be shaped in the figure 8 .. plus in mobus form. Cutting one would provide the optical illusion of separating the remaining two, or even trickier, the mobus strip type rings are not connected but run in a track. When watching a magic show, one must consider what is seen doesn't necessarily mean you are seeing what is. All the smoke and mirrors don't detract from the basic facts. What I said stands. The number 3 is a direct consequence of living in a 3 dimensional universe. Howdy Robin, I agree that the number 3 represents three as I agree many in the Vorts group are the SPOTP. A 3 dimensional universe may be a stretch considering the universe is only an image of the real. Richard
Re: Circular Particles as Parallel Resonant Tank Circuits
If you can see the photon going around it, I'm certain that the Q is too low. :-) Fred Thank you fred. It does not have to be a photon going around in it. It could just be a leptonic energy field with a momentum E/c. It's frequency must be the Compton frequency. If you do an analysis of the Doppler shift of an energy field that moves at velocity c you will find a beat note that has a wavelength equal to the Debroglie wavelength of matter. I've done the analysis, Hal Fox published it in Fusion Facts It can be found on page of the link below with a java animation. http://www.angelfire.com/scifi2/zpt/chapter7.html#Pg9 If you have bothered to read my links you will find that I have calculated the relativistic properties of matter, the deBroglie wavelength, the Compton frequency, and the energy levels of atoms based on the premice that the matter wave propagates at velocity c and has a momentum E/c. What sticks this fast moving matter wave? There is no coax cable or boundry conditions. I went back to elementarymodels ofsimple harmonic motion for an answer. All classical waves are reflected by a change in characteristic impediance. Should the matter wave be any different? Iinjected an elastic limit into a model of manyanswers. For example let us assume that we have an infinite coaxial cable. We increase the voltage to the point were it breaks down.Energy traveling down the coax is refected away at thepoint of the break down. Likewise energy within the break point is trapped there. U! sing this sort of logic I was able to compute the hight of the nuclear potential wall, the mass of a elecron, the radius of the proton, the mass of the W particle, and the probablilty of quantum transition. see chapers 10, 11, and 12.Techniques for controlling the gravitational (antigravity)and nuclear forces (cold fusion) fell out of the analytics. There has got to be something to this. Frank Znidarsic
Re: Efimov state - key to multi-nuclear LENR?
-Original Message- From: RC Macaulay I agree that the number 3 represents three as I agree many in the Vorts group are the SPOTP. A 3 dimensional universe may be a stretch considering the universe is only an image of the real. Really, all that is needed is 2 dimensions. As in hologram, all the information needed to create the third dimension is contained in the two. Terry ___ Try the New Netscape Mail Today! Virtually Spam-Free | More Storage | Import Your Contact List http://mail.netscape.com
Re: Efimov state - key to multi-nuclear LENR?
At 11:10 am 19/03/2006 -0500, you wrote: -Original Message- From: RC Macaulay I agree that the number 3 represents three as I agree many in the Vorts group are the SPOTP. A 3 dimensional universe may be a stretch considering the universe is only an image of the real. Really, all that is needed is 2 dimensions. As in hologram, all the information needed to create the third dimension is contained in the two. Terry Or even one come to that - a string of ones and zeros. One doesn't have to use the three Cartesian coordinates to define space. one could use the locations along a big ball of wool. It may not be so convenient but is would be just as effective. In short, it all depends how you choose to look at things. I wish that there were four of them Then I could believe in more ov 'em. 8-) Frank
Re: Efimov state - key to multi-nuclear LENR?
-Original Message- From: Grimer In short, it all depends how you choose to look at things. Innit da trut! Ackshully, the singularity contained all. Terry ___ Try the New Netscape Mail Today! Virtually Spam-Free | More Storage | Import Your Contact List http://mail.netscape.com
Re: Efimov state - key to multi-nuclear LENR?
In reply to RC Macaulay's message of Sun, 19 Mar 2006 08:25:11 -0600: Hi, [snip] Howdy Robin, I agree that the number 3 represents three as I agree many in the Vorts group are the SPOTP. A 3 dimensional universe may be a stretch considering the universe is only an image of the real. Richard ..but then so is everything in it, thus bound by the same rules. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
Re: Efimov state - key to multi-nuclear LENR?
In reply to [EMAIL PROTECTED]'s message of Sun, 19 Mar 2006 11:10:07 -0500: Hi, [snip] Really, all that is needed is 2 dimensions. As in hologram, all the information needed to create the third dimension is contained in the two. Terry A Hologram does not contain all the information of a 3 D object. You still can't see the back of it, and even if you could, you're still only looking at the surface. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
Re: Efimov state - key to multi-nuclear LENR?
In reply to Grimer's message of Sun, 19 Mar 2006 16:46:28 +: Hi, [snip] Or even one come to that - a string of ones and zeros. One doesn't have to use the three Cartesian coordinates to define space. one could use the locations along a big ball of wool. It may not be so convenient but is would be just as effective. You're ball of wool is still 3 dimensional. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
