Re: [Vo]: Deuterium analysis
In reply to Michel Jullian's message of Wed, 21 Mar 2007 17:09:34 +0100: Hi, [snip] >Sorry to be so obtuse Robin, do you mean (Hy - Hy)+ with one electron orbiting >around? > I think you get it. It's two protons tightly bound by a single shrunken electron, which is thus a Hydrino molecular ion, acting as a nucleus, with an additional electron in a normal Bohr "ground state" orbit. As near as I can tell it should be chemically virtually indistinguishable from normal D, and hence should form part of natural heavy water. (Not heavy water created in fission reactors, which is formed by addition of a real neutron to protium). Because Hydrinos are formed among other places, on the Sun, they should be carried to the Earth in the Solar wind, some in the form of Hydrino molecular ions, and when they interact with Oxygen in the Earth's atmosphere, they can form Faux heavy water, which eventually falls as rain. Faux D can be distinguished from normal D by bombarding it with ionizing radiation with a per particle energy of at least 3000 eV. This is enough to break the Hydrino molecular ion apart, freeing up the proton which is then easily detected with SIMS. Since SIMS itself usually uses primary ions with an energy well in excess of 3000 eV, these should be capable of serving both purposes concurrently, hence my interest in SIMS results from heavy water experiments. The 3000 eV is actually a bit of a cheat. This is the energy required to break up a Hydrino molecular ion containing a Hydrino shrunken to level 24, which is IMO the most interesting, because it's the lowest level still capable of forming Hydrinohydride according to Mills. However Faux D could exist at any level of shrinkage, from 2 to at least 120. Hydrinohydride formation is important because it can be an intermediary in the rapid formation of Hydrino molecules, which in turn are important for clean fusion see - http://users.bigpond.net.au/rvanspaa/Molecular%20Hydrino%20Fusion.htm [snip] BTW I think SIMS usually uses about 2 eV, which would be enough to separate a Hydrino molecular ion with shrinkage level 49. If my variant of Mills theory is correct, then this would imply a radius of the Hydrino of only 22 fm, allowing for very rapid fusion. (A level 24 shrinkage implies a radius of 92 fm). Note that muon catalyzed fusion happens at a distance of Bohr radius / 207 = 256 fm, and at that distance it is already blindingly fast, with up to 150 reactions being catalyzed during the lifetime of the muon (on average 2.2 micro seconds), and this takes into account the migration time of the muon from one atom to the next, as well as the actual time for fusion to occur. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
Sorry to be so obtuse Robin, do you mean (Hy - Hy)+ with one electron orbiting around? Michel - Original Message - From: "Robin van Spaandonk" <[EMAIL PROTECTED]> To: Sent: Wednesday, March 21, 2007 6:34 AM Subject: Re: [Vo]: Deuterium analysis In reply to Michel Jullian's message of Fri, 16 Mar 2007 08:20:37 +0100: Hi Michel, [snip] >Faux D being a H-Hydrino molecule (mass ~2 nucleons) looking like a D atom >(mass ~2 nucleons) ?? > >Michel [snip] I coined the term Faux D to describe a one electron atom with a nucleus comprising a Hydrino molecular *ion*. I expect it to be virtually indistinguishable from real D in as much as a Hydrino molecular ion looks very like a real D nucleus. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
In reply to Michel Jullian's message of Fri, 16 Mar 2007 08:20:37 +0100: Hi Michel, [snip] >Faux D being a H-Hydrino molecule (mass ~2 nucleons) looking like a D atom >(mass ~2 nucleons) ?? > >Michel [snip] I coined the term Faux D to describe a one electron atom with a nucleus comprising a Hydrino molecular *ion*. I expect it to be virtually indistinguishable from real D in as much as a Hydrino molecular ion looks very like a real D nucleus. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
Faux D being a H-Hydrino molecule (mass ~2 nucleons) looking like a D atom (mass ~2 nucleons) ?? Michel - Original Message - From: "Robin van Spaandonk" <[EMAIL PROTECTED]> To: Sent: Thursday, March 15, 2007 11:03 PM Subject: Re: [Vo]: Deuterium analysis In reply to Michel Jullian's message of Thu, 15 Mar 2007 22:24:40 +0100: Hi, [snip] >Er, D2 is not a deuteride is it? That's why I thought you meant HD (hydrogen >deuteride). > >Anyway so you mean molecular deuterium D2 goes into e.g. the palladium (thus >forming a palladium deuteride PdD), and H comes out? Yes, and no. I mean D2 goes in forming e.g. PdD, but SIMS analysis turns up some H as well. Then I would need to know the % of the Hydrogen that turned up as H (as opposed to D), and also the purity of the original D2. I'm both looking for evidence of Faux D, and trying to determine what percentage it is of real D. A related question is how is the purity of heavy water determined? >By which mechanism? The primary ions used in SIMS have enough energy to convert most Faux D into H + Hydrino, so an increase in the H content would indicate how much Faux D was present. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
In reply to Michel Jullian's message of Thu, 15 Mar 2007 22:24:40 +0100: Hi, [snip] >Er, D2 is not a deuteride is it? That's why I thought you meant HD (hydrogen >deuteride). > >Anyway so you mean molecular deuterium D2 goes into e.g. the palladium (thus >forming a palladium deuteride PdD), and H comes out? Yes, and no. I mean D2 goes in forming e.g. PdD, but SIMS analysis turns up some H as well. Then I would need to know the % of the Hydrogen that turned up as H (as opposed to D), and also the purity of the original D2. I'm both looking for evidence of Faux D, and trying to determine what percentage it is of real D. A related question is how is the purity of heavy water determined? >By which mechanism? The primary ions used in SIMS have enough energy to convert most Faux D into H + Hydrino, so an increase in the H content would indicate how much Faux D was present. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
Er, D2 is not a deuteride is it? That's why I thought you meant HD (hydrogen deuteride). Anyway so you mean molecular deuterium D2 goes into e.g. the palladium (thus forming a palladium deuteride PdD), and H comes out? By which mechanism? Michel - Original Message - From: "Robin van Spaandonk" <[EMAIL PROTECTED]> To: Sent: Thursday, March 15, 2007 9:58 PM Subject: Re: [Vo]: Deuterium analysis In reply to Michel Jullian's message of Thu, 15 Mar 2007 09:22:54 +0100: Hi Michel, >Hi Robin, I know of no such analysis but I am intrigued by your question > >> SIMS analysis run on either pure deuterium > >In which form ? Can one run a SIMS analysis on a gas? > >> where *only* the deuteride went in, but some H (1H) came out? > >You mean HD goes into the metal and H comes out? No, I mean D2 goes in and H is detected by SIMS. [snip] Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
In reply to Michel Jullian's message of Thu, 15 Mar 2007 09:22:54 +0100: Hi Michel, >Hi Robin, I know of no such analysis but I am intrigued by your question > >> SIMS analysis run on either pure deuterium > >In which form ? Can one run a SIMS analysis on a gas? > >> where *only* the deuteride went in, but some H (1H) came out? > >You mean HD goes into the metal and H comes out? No, I mean D2 goes in and H is detected by SIMS. [snip] Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
Hi Robin, I know of no such analysis but I am intrigued by your question > SIMS analysis run on either pure deuterium In which form ? Can one run a SIMS analysis on a gas? > where *only* the deuteride went in, but some H (1H) came out? You mean HD goes into the metal and H comes out? Michel - Original Message - From: "Robin van Spaandonk" <[EMAIL PROTECTED]> To: Sent: Thursday, March 15, 2007 8:10 AM Subject: Re: [Vo]: Deuterium analysis In reply to Robin van Spaandonk's message of Thu, 15 Mar 2007 18:07:07 +1100: Hi, [snip] >Hi, > >Does anyone know of a SIMS analysis run on either pure deuterium or a metal >deuteride, where *only* the deuteride went in, but some Hydrogen came out? [snip] I meant "but some protium came out". Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
Re: [Vo]: Deuterium analysis
In reply to Robin van Spaandonk's message of Thu, 15 Mar 2007 18:07:07 +1100: Hi, [snip] >Hi, > >Does anyone know of a SIMS analysis run on either pure deuterium or a metal >deuteride, where *only* the deuteride went in, but some Hydrogen came out? [snip] I meant "but some protium came out". Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition (capitalism) provides the motivation, Cooperation (communism) provides the means.
