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Can't say but that seems to be the issue to me
To get the final answer need to explore Stack contents.
On Sun, Jul 24, 2011 at 12:34 PM, shady sinv...@gmail.com wrote:
@sunny it should have printed some garbage after 'charlie' in that case ?
that is what happens with scanf when you overwrite
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left to it are even and right odd.Its an implementation of quick sort as
discussed earlier.Its o(n) no doubt but its not stable.
On Fri, Jul 22, 2011 at 11:51 AM, sunny agrawal
sunny816.i...@gmail.comwrote:
@atul
Your algo is not stable
http://www.ideone.com/DrV5J
BTW what are u trying
the ODD1 and EVEN2
result will be (2,4,1,3)
On Fri, Jul 22, 2011 at 12:36 PM, Puneet Gautam puneet.nsi...@gmail.comwrote:
@sunny: how do u do it by Divide n conquer ...can u provide the algo...?
On 7/22/11, UMESH KUMAR kumar.umesh...@gmail.com wrote:
Anybody try for maintain the stable
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solution below O(n^2)
On Mon, Jul 18, 2011 at 10:01 PM, sunny agrawal
sunny816.i...@gmail.comwrote:
if i am not getting question wrong.
read only 3 rows
find min and max of these 3n numbers
as min and max will be only in one lines output the line without min and
max
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, Jul 11, 2011 at 5:54 PM, Piyush Kapoor
pkjee2...@gmail.comwrote:
Can anybody give a full explanation
http://ideone.com/K1QmV
On Sat, Jul 9, 2011 at 10:49 PM, sunny agrawal
sunny816.i...@gmail.com wrote:
try to find out the binary representation of float value 5.2
On Sat, Jul 9, 2011
study terms like endian ,it is a
pity i had to google it :( :(
On Wed, Jul 13, 2011 at 10:30 PM, Anika Jain anika.jai...@gmail.comwrote:
ya thts ryt, for big endian it will be 64 -90 102 102
On Wed, Jul 13, 2011 at 10:22 PM, sunny agrawal
sunny816.i...@gmail.comwrote:
I think
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Once a reference is initialized to an object, it cannot be changed to refer
to another object.
Ref. Bruce Eckel - ch11
So its Not possible
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PM, shilpa gupta shilpagupta...@gmail.comwrote:
i think there is no need of this part
else if(c== '}' )
{
depth-=1;
}
than there is no need to find out max also
depth will give max itself i think...
On Tue, Jul 12, 2011 at 6:32 PM, sunny agrawal sunny816.i
@shilpa
see some post is hidden
click on hide quoted text to see the complete post
On Tue, Jul 12, 2011 at 6:46 PM, shilpa gupta shilpagupta...@gmail.comwrote:
@sunny well this case is not possible i think in any code a braces that are
opened should be closed...also
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For more
Smallest Number with k bits set will be the number with least significant k
bits set
ie. K=3 000111
K=4 000
and to find nth
we can use thishttp://groups.google.com/group/algogeeks/msg/2b64c4f96fa3598e
TC: O(n)
On Sun, Jul 10, 2011 at 2:13 PM, Sunny T sunny.1...@gmail.com wrote
thanks sunny
On Sun, Jul 10, 2011 at 2:19 PM, sunny agrawal sunny816.i...@gmail.comwrote:
Smallest Number with k bits set will be the number with least significant k
bits set
ie. K=3 000111
K=4 000
and to find nth
we can use thishttp://groups.google.com/group/algogeeks
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Longest AP for that Example is of 7 elements
2,4,6,8,10,12,14
now see your mistake ...
as i have already told you that u r looking for only contiguous AP's and
that won't work
On Sun, Jul 10, 2011 at 7:18 PM, Yogesh Yadav medu...@gmail.com wrote:
@sunny: my algo will give 6
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that LAP[i,j] is
essentially the same as LAP[0, j] by principle of optimality as the result
needs to be calculated with start index 0).
@Sunny: Any bugs in the analysis?
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O(N) algorithm. Descending order printing of pairs.
@Sunny: Your time complexity is O(N^2) as creating that array will take
O(N^2) time.
@Dumanshu: Your algorithm misses cases. Eg. (9,4) will be printed but (9,3)
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A = 0 1 4 5 9 11 20
B = 0 2 3 6 8 13 15
(20, 15) (20, 15) - (20,15)
(20,13) (11,15) - (20,13)
(20,8) (11,15) - (20,8)
(20,6) (11,15) - assume (20,6)
(20,3) (11,15) - (11,15)
(20,3) (9,15)-
On Mon, Jul 11, 2011 at 1:06 AM, sunny agrawal sunny816.i...@gmail.comwrote
value but
did i missed something ??
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, Piyush Sinha ecstasy.piy...@gmail.comwrote:
Nopesits about finding subsequence
On 7/8/11, rajeev bharshetty rajeevr...@gmail.com wrote:
Should the sequence beContinuos ???
On Fri, Jul 8, 2011 at 1:18 AM, sunny agrawal
sunny816.i...@gmail.comwrote:
@rajiv
if Count = 2 means 3
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@rajiv
if Count = 2 means 3 elements isn't it a,a+d,a+2d
else according to you
for case 10 12 14 24 26 28
diff 2 2 10 2 2
diff 2 has count 4 so will you say ap of 4 elements with diff 2
On Fri, Jul 8, 2011 at 1:06 AM, rajeev bharshetty rajeevr...@gmail.comwrote:
@sunny Keep count
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http://ideone.com/xv73J
On Fri, Jul 8, 2011 at 2:16 AM, Piyush Sinha ecstasy.piy...@gmail.comwrote:
@Sunny...can u post a definite algo for it??
On 7/8/11, Ravi Shukla shuklaravi...@gmail.com wrote:
@sunny , yep it looks DP. more of MCM.
solve for substrings of length 1,2,3
...@gmail.comwrote:
Can u explain ur algo too??
On 7/8/11, Piyush Sinha ecstasy.piy...@gmail.com wrote:
@Sunny...nice solution but ur solution works if there can 1 to 3
groups of digits..but in the question its mentioned the group should
contain exactly 2 or 3 digits...
but anyways nice
i = m-1
j = m-1
k = 2m-1
*compare (i,j) and put the maximum at k
if (i is max) decrement i;
if (j is max) decrement j
decrement k
*
and take care of boundary cases as well
On Fri, Jul 8, 2011 at 10:55 AM, ankit sambyal ankitsamb...@gmail.comwrote:
@Sunny : Plz can u expain ur approach
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Oops ...
my method will also not work as probabilities will not be equal !!!
On Wed, Jul 6, 2011 at 11:29 PM, sunny agrawal sunny816.i...@gmail.comwrote:
For RNG in range [a,b] first thing is that all numbers should be generated
with equal probability.
in your case you are considering mid
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Regards,
Sandeep Jain
On Sun, Jul 3, 2011 at 1:09 PM, sunny agrawal sunny816.i...@gmail.comwrote:
@sandeep
SET A - {0,3,4,7}
SET B - {1,2,5,6}
xor of all elements is zero
sum of both the sets is same
no of elements in both are same
overall result : all Algorithm posted above
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yes i have written that only
difference between indexes of first set bit and last set bit
On Sat, Jul 2, 2011 at 2:08 PM, cegprakash cegprak...@gmail.com wrote:
whats mean by first set bit and last set bit? do you simply mean the
index of first and last bit?
On Jul 2, 1:25 pm, sunny agrawal
l = 81 0 0 0
k = 6 0 1 1 0
xor 1 1 1 0
difference = 2
l = 161 0 0 0 0
k = 4 0 0 1 0 0
xor
On Sat, Jul 2, 2011 at 2:09 PM, sunny agrawal sunny816.i...@gmail.comwrote:
yes i have written that only
difference between indexes of first set bit
why ?
On Sat, Jul 2, 2011 at 2:20 PM, cegprakash cegprak...@gmail.com wrote:
@ sunny: so your's doesn't work right?
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You
try out with examples!!
u will surely get in 2-3 examples
N(N-1) is a very famous expression, used in counting set bits. see what
this expression return
On Sat, Jul 2, 2011 at 2:51 PM, cegprakash cegprak...@gmail.com wrote:
btw what N = N-(N(N-1)) does actually
On Jul 2, 2:11 pm, sunny
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the difference between all maxIdx and minIdx if maxIdx
is not -1
On Fri, Jul 1, 2011 at 5:34 PM, abc abc may.i.answ...@gmail.com wrote:
@sunny very nice solution .
can you write the code for hashing part
On Fri, Jul 1, 2011 at 5:07 PM, Anantha Krishnan
ananthakrishnan@gmail.com wrote
yes but for largest interval we need only one index :) greater of i or j
On Fri, Jul 1, 2011 at 6:01 PM, Dumanshu duman...@gmail.com wrote:
@sunny: if a[i]==0 then 0,i is the solution
suppose a[i]==a[j] ==0 now 0,i and 0,j is the solution. is i,j also
the solution??
On Jul 1, 4:08 pm, sunny
or in other words equal no of 0's and 1's
On Sat, Jul 2, 2011 at 12:42 AM, Anika Jain anika.jai...@gmail.com wrote:
@sunny: in a[2,4] has 2 1s and one 0 then how is it a solution? i mean i
didnt get wen a[i]==a[j] then a[i,j] is a solution case..
On Fri, Jul 1, 2011 at 4:13 PM, sunny agrawal
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the error is in quotes, just rewrite them
On Wed, Jun 29, 2011 at 5:24 PM, Anika Jain anika.jai...@gmail.com wrote:
hey, printf(%d ya %u in both same error cming..
On Wed, Jun 29, 2011 at 5:10 PM, sunny agrawal sunny816.i...@gmail.comwrote:
Because u copied the code i think :P
try
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