@dave
plz run gene's code for input 0xAD...or send me some link of bitwise
programing which involve simultaneous many opearation... like above...
i am always confused with bitwise programing...
On Sun, Nov 21, 2010 at 11:11 PM, Dave dave_and_da...@juno.com wrote:
@Coolfrog$: Don't forget the
@Coolfrog$: It will be instructive if you do it for yourself. Perhaps
with practice you can work through your confusion. Have you worked out
the bit patterns of those hex constants? They are crucial to
understanding Gene's algorithm. -- Dave
On Nov 22, 6:55 am, coolfrog$
@gene
plz explain .. what is going on... by taking example. i am unable to run
a test case
1. x=0xAD (1010 1101)
2. x1 ===01011010
|
x1 01010110
x =0100
how we will get
answer as ( 0101 1011).??
On Sun, Nov 21, 2010 at 9:59 AM, Gene
@Coolfrog$: Don't forget the bitwise logical products. What is the bit
patterns in those hexadecimal constants? Work out the whole example
and you will see how it works. -- Dave
On Nov 21, 8:21 am, coolfrog$ dixit.coolfrog.div...@gmail.com
wrote:
@gene
plz explain .. what is going on... by
x=((x3)(0x11)|(a3) 0x88 |(a1) 0x44 | (a1) 0x22)
On Sun, Nov 21, 2010 at 11:11 PM, Dave dave_and_da...@juno.com wrote:
@Coolfrog$: Don't forget the bitwise logical products. What is the bit
patterns in those hexadecimal constants? Work out the whole example
and you will see how it works. --
In C,
unsigned char x;
...
x = (x 1) | (x 1);
x = (x 2) | (x 2);
On Nov 20, 10:41 pm, Divesh Dixit dixit.coolfrog.div...@gmail.com
wrote:
assuming all are 8bit no.
input = 0x46 (0100 0110)
output = 0x26 ( 0010 0110 )
input = 0x75 (0111 0101)
output = 0xFC (1110 1010 )
if the input is in unsigned char x, then
x = ((x 1) 0xAA) | ((x 1) 0x55)
x = ((x 2) 0xCC) | ((x 2) 0x33)
On Nov 20, 10:41 pm, Divesh Dixit dixit.coolfrog.div...@gmail.com
wrote:
assuming all are 8bit no.
input = 0x46 (0100 0110)
output = 0x26 ( 0010 0110 )
input = 0x75 (0111
