Re: [algogeeks] Re: char *arr and char arr[]

2011-06-27 Thread sagar pareek
@oppilas char *ptr=hello in this case the string becomes constant but not the ptr, you can do this. char *ptr=hello; char arr[]=hi; ptr[0]=B; //not work ptr=arr; //work arr[0]=H; //work ptr[0]=N; //work Only string Hello becomes constant, it cant be changed. Read - const char *ptr , char const

[algogeeks] Re: char *arr and char arr[]

2011-06-25 Thread Adarsh
char array[] = hello; char *pointer = hello; array is an array, enough to store sequence of characters and '\0' array will always refer to same storage. Here, pointer is initialized to point to a string constant, pointer may be modified, but you cannot chage string contents -- You received this

Re: [algogeeks] Re: char *arr and char arr[]

2011-06-25 Thread Anantha Krishnan
When we declare *char *str=hello;* this hello will be stored in the read-only memory i.e *TEXT Segment*. so when we try to write the read-only memory by **str='w';* it will throw *Segmentation fault*. Obviously we must allocate some memory in heap to modify it like: *char *str=(char

Re: [algogeeks] Re: char *arr and char arr[]

2011-06-25 Thread oppilas .
Thanks all :). On 6/25/11, Anantha Krishnan ananthakrishnan@gmail.com wrote: When we declare *char *str=hello;* this hello will be stored in the read-only memory i.e *TEXT Segment*. so when we try to write the read-only memory by **str='w';* it will throw *Segmentation fault*.