There is not a sure way to do that in C or C++ without putting an
additional requirement on the caller.
Don
On Jan 28, 5:14 am, Anil Sharma anilsharmau...@gmail.com wrote:
How to calculate the size/lenght of an int array which is passed as an ONLY
argument to a function???
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You
null is a macro defined in stdio.h which is equal to 0 . so sizeof(0) is 4
:)
On Wed, Sep 7, 2011 at 2:44 AM, UTKARSH SRIVASTAV
usrivastav...@gmail.comwrote:
and why sizeof(NULL) is giving 4 any ans?
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B-Tech 3rd Year
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*UTKARSH
and why sizeof(NULL) is giving 4 any ans?
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*UTKARSH SRIVASTAV
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B-Tech 3rd Year
@MNNIT ALLAHABAD*
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@MNNIT ALLAHABAD*
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Okay.
I was a bit wrongactually the thing is that
The exact number of bytes allocated for various C data types depends on *both
the machine and the compiler.**
*so it may be the that the compiler u are using is 32 bit..
one thing that u can try out is that on ubuntu install 64 bit
@aditya..the answer may vary, because c is machine dependent
language..in few machines int is of 2 bytes and char is of 1 byte..u
can't say..it varies with diff machines
On 7/26/11, aditya kumar aditya.kumar130...@gmail.com wrote:
char *s[5] is a array of pointers of type char . but the thing is
for compiler giving 8 bit for pointers, shouldn't int also be of 8 bits??
On Thu, Jul 28, 2011 at 12:26 PM, Jnana Sagar supremeofki...@gmail.comwrote:
@aditya..the answer may vary, because c is machine dependent
language..in few machines int is of 2 bytes and char is of 1 byte..u
can't
@sunny : what you means by machine dependent means 64 bit: you means by
compiler / operating system /computer architecture ?
because i never get size of pointer 8 byte. if your statement true then tell
me which compiler / operating system /computer architecture i should have
get this output 8.
computer architecture !!!
64 bit machine has word size of 8 bytes so pointers are of 8 bytes
you never got size as 8 byte because u might be working on a 32 bit machine
!!
On Wed, Jul 27, 2011 at 2:18 PM, hary rathor harry.rat...@gmail.com wrote:
@sunny : what you means by machine dependent
On Wed, Jul 27, 2011 at 2:18 PM, hary rathor harry.rat...@gmail.com wrote:
@sunny : what you means by machine dependent means 64 bit: you means by
compiler / operating system /computer architecture ?
because i never get size of pointer 8 byte. if your statement true then
tell me which
@ sunny ; i am working on 64 bit windows 7 with dev and also in gcc + ubuntu
64 bit ... am using i3 processor that is 64 bit... what should do to get
size 8 byte ?
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A reasonable guess would be 28 bytes. But the size of a structure is
implementation dependent, and therefore, some other result could be
correct as well.
Don
On Jul 26, 7:40 am, Puneet Gautam puneet.nsi...@gmail.com wrote:
#includestdio.h
#includestddef.h
struct node{
int a;
@everyone:
I have this mind strangling doubt..!!!
Why is char *s[5] of 20 bytes...?
yes the output is 28...
On 7/26/11, Don dondod...@gmail.com wrote:
A reasonable guess would be 28 bytes. But the size of a structure is
implementation dependent, and therefore, some other result could be
char *s[5] is an array of 5 char pointers. A pointer is an int, of size 4
bytes. So, 5*4 = 20 bytes
On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam puneet.nsi...@gmail.comwrote:
@everyone:
I have this mind strangling doubt..!!!
Why is char *s[5] of 20 bytes...?
yes the output is 28...
On
char *s[5] is a array of pointers of type char . but the thing is size of
pointers is 4byte irrespective of its type . coz address is always an
unsigned int which is of 4byte.
On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam puneet.nsi...@gmail.comwrote:
@everyone:
I have this mind strangling
ok...!
#includestdio.h
#includestddef.h
struct node{
int a;
char b[5];
struct node *link;
};
main()
{
int a;
a=sizeof(struct node);
printf(%d,a);
getchar();
return 0;
}
why is its output : 16?
Sudnt it be 4(int a) +5(char b[5]
Its Cos that is pointer and all pointers is 4 bytes address..
On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam puneet.nsi...@gmail.comwrote:
@everyone:
I have this mind strangling doubt..!!!
Why is char *s[5] of 20 bytes...?
yes the output is 28...
On 7/26/11, Don dondod...@gmail.com
for the above mentioned code, in previous post,: shudnt the output be 4+5+4=13?
On 7/26/11, Prem Krishna Chettri hprem...@gmail.com wrote:
Its Cos that is pointer and all pointers is 4 bytes address..
On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam
puneet.nsi...@gmail.comwrote:
@everyone:
I
padding..
4 byes int + 3 padding bytes + 5 char bytes + 4 bytes pointer =16
On Tue, Jul 26, 2011 at 7:22 PM, Puneet Gautam puneet.nsi...@gmail.comwrote:
for the above mentioned code, in previous post,: shudnt the output be
4+5+4=13?
On 7/26/11, Prem Krishna Chettri hprem...@gmail.com wrote:
the link ll not occupy any m/y here...so its output ll be 14(int -4
bytes,ptr-2 bytes);;if i'm wrong jst crct it...
On 7/26/11, Prem Krishna Chettri hprem...@gmail.com wrote:
Its Cos that is pointer and all pointers is 4 bytes address..
On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam
@kavitha, what is m/y?
On Tue, Jul 26, 2011 at 7:27 PM, kavitha nk kavithan...@gmail.com wrote:
the link ll not occupy any m/y here...so its output ll be 14(int -4
bytes,ptr-2 bytes);;if i'm wrong jst crct it...
On 7/26/11, Prem Krishna Chettri hprem...@gmail.com wrote:
Its Cos that is
sry memory...
On 7/26/11, Akshata Sharma akshatasharm...@gmail.com wrote:
@kavitha, what is m/y?
On Tue, Jul 26, 2011 at 7:27 PM, kavitha nk kavithan...@gmail.com wrote:
the link ll not occupy any m/y here...so its output ll be 14(int -4
bytes,ptr-2 bytes);;if i'm wrong jst crct it...
It is not 28 ?
4 sizeof(int) + 20 + 4 (ptr). And no padding, cos' all is mutiple of 4.
On Jul 26, 7:40 am, Puneet Gautam puneet.nsi...@gmail.com wrote:
#includestdio.h
#includestddef.h
struct node{
int a;
char *b[5];
struct node *link;
};
main()
{
On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam
puneet.nsi...@gmail.comwrote:
@everyone:
I have this mind strangling doubt..!!!
Why is char *s[5] of 20 bytes...?
5 x sizeof (*s). do you see ?
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sry frendzma above posts were wrongans is 28 if ptr takes 4 bytes...
//BE COOL// kavi
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will there be any difference in size on 32 machine and on 64 bit machine ?
how and what ?
On Tue, Jul 26, 2011 at 7:58 PM, kavitha nk kavithan...@gmail.com wrote:
sry frendzma above posts were wrongans is 28 if ptr takes 4
bytes...
//BE COOL// kavi
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yes
on a 64 bit machine ans will be 4+5*8+8 = 52 bytes
pointers take 8 byte on 64 bit machine
On Tue, Jul 26, 2011 at 8:00 PM, vaibhav shukla vaibhav200...@gmail.comwrote:
will there be any difference in size on 32 machine and on 64 bit machine ?
how and what ?
On Tue, Jul 26, 2011 at 7:58
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