ya guys m sorry actually swap code within the function is working ryt and
swap code wasnt working ryt.. i did misunderstood sumthing..
@sandeep sir: thanku sir :)
On Thu, Jul 14, 2011 at 11:26 AM, Sandeep Jain sandeep6...@gmail.comwrote:
Your swap function is not correct. You are swapping p q
ya i too think de same...
//BE COOL// kavi
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ya i have posted na just nw i m sorry tht i misunderstood it.. swap code
within the func is working ryt n swap func itself is working wrong..
On Thu, Jul 14, 2011 at 4:20 PM, kavitha nk kavithan...@gmail.com wrote:
ya i too think de same...
//BE COOL// kavi
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You received this
can some body tell me that:
void swap(node *p,node *q)
{
node *t;
t=p;
p=q;
q=t;
}
void mirror(node *p)
{
if (p==NULL)
return;
else
{mirror(p-r);
mirror(p-l);
swap(p-r,p-l);
}
}
in this the swapping is occuring but if i do :
void
u need a pointer to a pointer to swap the pointers...
On Thu, Jul 14, 2011 at 1:21 AM, Anika Jain anika.jai...@gmail.com wrote:
can some body tell me that:
void swap(node *p,node *q)
{
node *t;
t=p;
p=q;
q=t;
}
void mirror(node *p)
{
if (p==NULL)
Its working I guess in both the cases...
On 7/14/11, Anika Jain anika.jai...@gmail.com wrote:
can some body tell me that:
void swap(node *p,node *q)
{
node *t;
t=p;
p=q;
q=t;
}
void mirror(node *p)
{
if (p==NULL)
return;
else
{mirror(p-r);
by using swap function is pointer to a pointer used then??
On Thu, Jul 14, 2011 at 1:36 AM, Piyush Kapoor pkjee2...@gmail.com wrote:
u need a pointer to a pointer to swap the pointers...
On Thu, Jul 14, 2011 at 1:21 AM, Anika Jain anika.jai...@gmail.comwrote:
can some body tell me that:
n sorry i have wriiten it in c++ not c..
On Thu, Jul 14, 2011 at 1:44 AM, Anika Jain anika.jai...@gmail.com wrote:
by using swap function is pointer to a pointer used then??
On Thu, Jul 14, 2011 at 1:36 AM, Piyush Kapoor pkjee2...@gmail.comwrote:
u need a pointer to a pointer to swap the
Your swap function is not correct. You are swapping p q locally. Since you
are using c++, make the following changes.
void swap*(node* p,node* q)*
{
node *t;
t=p;
p=q;
q=t;
}
Regards,
Sandeep Jain
On Thu, Jul 14, 2011 at 1:45 AM, Anika Jain anika.jai...@gmail.com wrote:
n
