a one line solution is needed...
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and also
void change()
{
// Code here
int x = 1;
int*p= &x;
while(*p != 5) p++;
*p = 10;
}
On Wed, Feb 16, 2011 at 8:02 AM, Balaji S wrote:
>
> The solution is..
>
>_AX = 10;
>
>
> can anyone explain??
>
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The solution is..
_AX = 10;
can anyone explain??
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nice solution
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void change()
{
#define i i=10,n
}
this will do..
On Tue, Feb 15, 2011 at 11:33 PM, Rel Guzman Apaza wrote:
> Nothing... 10 in base 5 = 5 in base 10.
>
> void change(){
> printf(""); //...?
> }
>
> 2011/2/15 Don
>
> A semicolon is valid in the middle of a line in C or C++.
>>
>> For i
Nothing... 10 in base 5 = 5 in base 10.
void change(){
printf(""); //...?
}
2011/2/15 Don
> A semicolon is valid in the middle of a line in C or C++.
>
> For instance, no one says that
>
> for(i = 0; i < 10; ++i)
>
> is three lines of code.
>
> Don
>
> On Feb 15, 11:31 am, jalaj jaiswal
after termination of semicolon , that will be considered a separate line i
guess
On Tue, Feb 15, 2011 at 10:59 PM, Don wrote:
> void change()
> {
> printf("10"); while(1) {}
> }
>
> On Feb 15, 10:17 am, Balaji S wrote:
> > Insert only one line in the function change() so that the output of the
