@aditi : I Think the output depends on whether it is row major or column
major representation in memory .
Does he row amjor or column
On Sun, Aug 7, 2011 at 12:19 AM, aditi garg wrote:
> oh @ akshay y ru doing 10x4??? 10 is the no of rows not the columns so it
> shud be 15x3+4...and
oh @ akshay y ru doing 10x4??? 10 is the no of rows not the columns so it
shud be 15x3+4...and by multiplying by 4(in 10x4) ur taking it to the 5th
row ie A[4][4] its only A[3][4]...
i hope its clear now
On Sun, Aug 7, 2011 at 12:14 AM, akshay khatri wrote:
>
>
> On 6 August 2011 23:56, adit
On 6 August 2011 23:56, aditi garg wrote:
> @akshay: what i meant ws suppose the array strted from in decimal...so
> A[3][4] wud be at 0049 and B[3][4] will be at 0196
> convert dese 2 values to hex it gives 31 and C4 respectively...now base
> address is 1000 and 2000 instead if so add
@akshay: what i meant ws suppose the array strted from in decimal...so
A[3][4] wud be at 0049 and B[3][4] will be at 0196
convert dese 2 values to hex it gives 31 and C4 respectively...now base
address is 1000 and 2000 instead if so add the base address and u get
the ans 1031 and 20C4...i
On 6 August 2011 23:40, aditi garg wrote:
> A[3][4] wud be in the 4th row...so strtung address of 4th row wud be
> 46..and thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows
> + 16 fr the 4th elemnet so 196
>
How does it start from 46 and 180 ?
as per my knowledge, 0x1000 = 409
A[3][4] wud be in the 4th row...so strtung address of 4th row wud be 46..and
thn 4th element wud be at 49...similarly fr B 180 fr the frst 3 rows + 16 fr
the 4th elemnet so 196
On Sat, Aug 6, 2011 at 11:37 PM, akshay khatri wrote:
> how is that 49 bytes and 196 bytes
> shouldn't it be 44 and 176
how is that 49 bytes and 196 bytes
shouldn't it be 44 and 176 bytes respectively
On 6 August 2011 23:26, Ram Chauhan wrote:
> 1049 and 1098
>
> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>
>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>> IF A
1049 and 1098
On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
> CHAR A[10][15] AND INT B[10][15] IS DEFINED
> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Ge
@ankit ur ans is fine bt u missed a point that dey are calculating in hex so
convert ur ans to hex and it will be the same as the one i posted...
@siddharth...A[3][4] will be 49 bytes ahead of the base address...and 49 in
hex is 31 so ans will be 1031
and int (assuming 4 bytes) the value B[3][4] wi
@aditi: explain ur answer.. How u got it ?
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
On 6 August 2011 23:15, aditi garg wrote:
> No the ans is 1031 and 20C4...
> i got it btw...thanx :)
>
explain ?
>
>
> On Sat, Aug 6, 2011 at 11:13 PM, Aditya Virmani
> wrote:
>
>> 1033,2066?
>>
>>
>> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>>
>>> CHAR A[10][15] AND INT B[10][15] IS
A[3][4]= 1049
B[3][4]= 2196
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more optio
No the ans is 1031 and 20C4...
i got it btw...thanx :)
On Sat, Aug 6, 2011 at 11:13 PM, Aditya Virmani wrote:
> 1033,2066?
>
>
> On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
>
>> CHAR A[10][15] AND INT B[10][15] IS DEFINED
>> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
>> IF ADDRESS OF A IS O
1033,2066?
On Sat, Aug 6, 2011 at 11:09 PM, aditi garg wrote:
> CHAR A[10][15] AND INT B[10][15] IS DEFINED
> WHAT'S THE ADDRESS OF A[3][4] AND B[3][4]
> IF ADDRESS OF A IS OX1000 AND B IS 0X2000
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks
14 matches
Mail list logo
