On Nov 6, Dan Anderson said:
>
>> Dan> So: foo->bar qw(foo bar); is equivalent to foo->bar("foo","bar"); ?
>>
>> Only in recent Perls.
>
>Do you know exactly how recent? Are we talking 5 or better or 3 or
>better?
Without check perldeltas, I'd say 5.6.
--
Jeff "japhy" Pinyan [EMAIL PROTEC
> Dan> So: foo->bar qw(foo bar); is equivalent to foo->bar("foo","bar"); ?
>
> Only in recent Perls.
Do you know exactly how recent? Are we talking 5 or better or 3 or
better?
Thanks in advance,
-Dan
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> "Dan" == Dan Anderson <[EMAIL PROTECTED]> writes:
Dan> So: foo->bar qw(foo bar); is equivalent to foo->bar("foo","bar"); ?
Only in recent Perls. The mapping of qw(...) to a (...) list at compile
time is a modern addition. Older Perls replaced it with a runtime
split on the string, and pro
[sorry about that first post, I got ^X-happy]
On Nov 5, Dan Anderson said:
>use Data::Dump qw(dump);
>foo->bar qw(foo bar);
>Am I correct in assuming that if I have a subroutine foo (or method if
>called with a package name), and I use qw() it takes all words seperated
>by spaces, and passes the
On Nov 5, Dan Anderson said:
>I've noticed that in code examples something like the following will be
>used:
>
>use Data::Dump qw(dump);
>foo->bar qw(foo bar);
>
>(Syntax may not be 100% correct).
>
>Am I correct in assuming that if I have a subroutine foo (or method if
>called with a package name
Dan Anderson wrote:
> I've noticed that in code examples something like the following will be
> used:
>
> use Data::Dump qw(dump);
> foo->bar qw(foo bar);
>
> (Syntax may not be 100% correct).
>
> Am I correct in assuming that if I have a subroutine foo (or method if
> called with a package name),
I've noticed that in code examples something like the following will be
used:
use Data::Dump qw(dump);
foo->bar qw(foo bar);
(Syntax may not be 100% correct).
Am I correct in assuming that if I have a subroutine foo (or method if
called with a package name), and I use qw() it takes all words sep
