Thanks guys... it worked. I did exactly what both of you said. thanks
a lot.
On Oct 13, 5:16 am, qwanta [EMAIL PROTECTED] wrote:
Also, don't forget to restart apache after making the httpd.conf
changes.
On Oct 12, 2:16 pm, imran k [EMAIL PROTECTED] wrote:
Hi everyone! I am Imran k and
Upgraded to 1.2 and everything is ok now...
Thx everybody.
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Upgraded to v1.2 and
everything is ok now.
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You want to call a view from a mysql stored procedure?
You could probably make a request to a controller. Without a
controller you wouldn't have much in your view!!
On Oct 17, 6:31 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
i want to convert my whole system in store procedure, so that
As far as I know, you can invalidate in controller just by calling
$this-YourModel-invalidate(...)
Does that help?
On Oct 16, 11:38 pm, cem [EMAIL PROTECTED] wrote:
Hi ;
I am trying to build a freelancer script with cakephp . I made
categories and projects. One project can have more than
The application has to be installed on a existing shared linux
webhosting the client is using. So Windows like functions is no option
in this case. Furthermore would we like to incorporate these functions
in future apps and 90% of the the time servers hosting our apps are of
the type Linux.
On
what is the proper way to pass data between pages? Let's say I want to
display a message that a database save is successful, or failed. Right now,
I am passing the information as a parameter in the URL (
localhost/blah?success=1 ). Is there a better way to do it? I've thought
about using a
If you want to pass on the message maybe setFlash is the best option
(possibly with a custom key):
http://book.cakephp.org/view/568/flash
Although I don't see anything wrong with using your own session keys.
Either way, I'd stay away from URL parameters as they can be faked by
the end users,
Well, I have a question.
If I understand the testAction with fixturize = true correctly, it
copies the tables from the default connection and then calls the
specified URL. So it doesn't use the fixtures I have written in my
test directory. Is this correct ?
I would prefer if all the tests
Being new to cake (became the owner of 2 cakephp applications), I dont
think I am getting something simple. First, I have three tables,
customers (PK ID int), services (PK ID int) and then
customers_services (customer_id int, service_id int). I then have the
2 models below. I am in the process
Hi everybody,
I try to follow the sitemap tutorial, but have problems with the layout.
If I call http://localhost/myapp/sitemap.xml it tries to use the default.ctp in
the layouts root, which results in a complete mess.
If I add
function index (){
Try to put the RequestHandler into the components property. It
detects which content type is requested and sets the layout path
according to that.
If you want to set the layout and layoutPath manually do it this way:
class PostsController ...
function index() {
I am not aware of a way to rendering an element without actually
bringing all of Cake to life.
A few ideas that may be more of less suitable to you.
The quick and hacky way:
$_GET['url'] = '/controller/action/param';
require_once('path/to/cake/app/webroot/index.php');
This is an old way to get
First error fixed, but still stuck with the rest:
Correct syntax is of course 8 or at least not obviously wrong):
$this-layoutPath = 'xml/';
$this-layout = 'default';
-Ursprüngliche Nachricht-
Von: cake-php@googlegroups.com [mailto:[EMAIL PROTECTED] Im
If it's just basic blogging functionality, you might be better off
sticking with the various blogs that have been built using CakePHP
and/or building your own.
[EMAIL PROTECTED] wrote:
I am not aware of a way to rendering an element without actually
bringing all of Cake to life.
A few ideas
Except the routing it works now:
Wow... I am really amazed by myself :cD
A hint for another poor soul trying this:
1. set the debug level to the usual 1 or 2, but not 0 as long as you are not
sure that your output is correct.
2. validate the expected output in an online validator like
Cake handles the join table naming convention based off the tables
used, rename your join table to customers_scheduler_services
On Oct 17, 8:22 am, MDB [EMAIL PROTECTED] wrote:
Being new to cake (became the owner of 2 cakephp applications), I dont
think I am getting something simple. First, I
Thank you, that fixed the error however now the services are not
showing for the customer. Is there something else that I am missing?
On Oct 17, 9:14 am, scs [EMAIL PROTECTED] wrote:
Cake handles the join table naming convention based off the tables
used, rename your join table to
I've been using the firecake.php helper to aid in my debugging. I primarily
use it to drill into the values held in those big nested arrays that result
from running recursive find() on models. Was working great, but now I'm
getting unterminated string literal errors on the fbout['Variables']
The (not existing but still logged in) user should not have any access
at all!
I solved it by putting this into the AppController's beforeFilter:
if($checkuser = $this-Session-read('Auth.User.id'))
{
if( !$this-Auth-identify($checkuser) )
{
$this-Auth-logout();
Just to clarify... What I really like about firecake.php and the FireBug
output is that the arrays are expandable/collapsible. That's the
functionality I'd like to find in another debugging solution.
RyOnLife wrote:
I've been using the firecake.php helper to aid in my debugging. I
Anyone got any ideas?
Cheers
Alex
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Okay, here is what I have now and I am no longer getting any error but
the services for the cusomer are no longer showing.
table customers is now scheduler_customers
table services is now scheduler_customers
table customers_services is now scheduler_customers_sheduler_services.
My customer
I finally figured it out. I changed the table name
(scheduler_customers_sheduler_services) but I didn't change the column
names to scheduler_customer_id and scheduler_service_id. Once I did
that it started working again. Thanks again for your help.
On Oct 17, 10:00 am, MDB [EMAIL PROTECTED]
You could check out Krumo : http://krumo.sourceforge.net/
It's a php debugging solution; makes expandable variables and stuff.
I've used it in the past with good results.
hth
grigri
On Oct 17, 3:05 pm, RyOnLife [EMAIL PROTECTED] wrote:
Just to clarify... What I really like about firecake.php
Sweet! Just what I was looking for. Thanks.
grigri wrote:
You could check out Krumo : http://krumo.sourceforge.net/
It's a php debugging solution; makes expandable variables and stuff.
I've used it in the past with good results.
hth
grigri
On Oct 17, 3:05 pm, RyOnLife [EMAIL
I think there's a bakery article on it...
yep, here it is:
http://bakery.cakephp.org/articles/view/nicer-print_r-with-krumo
I couldn't get the skin images to work with that, but it was a long
time ago - cake has got better since.
Let us know how you get on, if it works well I might start
Having trouble getting it to work. I just dropped the class into my
include_path, required it, then tried both krumo($var) (call to undefined
function) and krumo::krumo($var) (class not found) with no luck. What's the
best way to make it work with Cake? Do I have to turn it into a helper?
Took less than 5 minutes for me to give it a crack, but the Bakery article
seems to be a bit outdated: I'm getting a fatal error because the krumo
class cannot be found. I changed from vendor() to App::import in the helper,
but couldn't find anything else. I'm thinking I'm missing another change
look at Model::query() You can run arbitrary SQL through that.
-Mark
On Oct 17, 1:31 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
i want to convert my whole system in store procedure, so that place
guide me how can i call store procedure, how can i call view from
mysql.
I want to add some scripts from views, elements, helpers to the
header. Header is in layout of course. What is the proper way to do
that?
Two examples:
- css - I want to include some css files only when I use Elements or
helpers they are used by. Is it any way to do this in cakephp? Or have
I
What is the proper cake-way of doing this?
I think You don't need views for inquiries, only elements. Views are
for separate pages, to render inquires on customer page use elements
or even some kind of helper... anyway thats the way I do it. :)
Robert
Hi,
I have applied Acl and Auth as instructed in the example tutorial of
the book. The first user I created is a member of user_group = 1
which has access to all controllers using:
$group-id = 1;
$this-Acl-allow($group, 'controllers');
But when I login and try to access anything I keep
More info for someone, could still do with some help though.
After a nights rest I was more capable of reading the notice properly
and debug where the problem was occurring. It seems that my user
model is failing to read the primary key of the user_group model.
When accessed by the following
What bugs me is that they are conceptually different views of a model,
not reusable web page elements -- i.e. they are not menus, sidebars,
headers, footers... With that kind of architecture, I'd end up with
customer controller retrieving and passing inquiry data to
customer view, which then
[resolved]
A night of sleep gave me a fresh pair of eyes that alerted me to where
the problem was and I quickly worked out that I was not requesting the
id field when specifying fields to be fetched during model
association. Thought they came through by default, but I was wrong,
they have to be
Hi,
I am using jquery for ajax in my application.. and was getting very
good results using it.
But when I was working on a registration page then this jquery is not
providing me seamless effect.
There is two select box - drop down
1 State
2 City
when ever a user select a state correspondingly
This is a security issue, and not an identity authentication issue.
The Auth component is designed to make it easy to confirm someone's
identity, but not to manage security or permissions for a website. You
could use ACL or do it yourself.
Anytime a user does something that requires a level of
Both of the methods are the same only you use controller.
On 10/17/2008, Mathew [EMAIL PROTECTED] wrote:
This is a security issue, and not an identity authentication issue.
The Auth component is designed to make it easy to confirm someone's
identity, but not to manage security or
Ok is this for the user Block?
On 10/17/2008, WebbedIT [EMAIL PROTECTED] wrote:
Hi,
I have applied Acl and Auth as instructed in the example tutorial of
the book. The first user I created is a member of user_group = 1
which has access to all controllers using:
$group-id = 1;
You may want to post this in the AJAX groups also!
On 10/17/2008, bookme [EMAIL PROTECTED] wrote:
Hi,
I am using jquery for ajax in my application.. and was getting very
good results using it.
But when I was working on a registration page then this jquery is not
providing me seamless
I have the following models:
Users (id, name, ...)
Preferences (id, user_id, ...)
With the relationships User hasOne Preference and Preferences
belongsTo User set in each model.
I created a form with all fields for either users and preferences.
$form-create('User',Array('action' =
Hi All,
Intending to build a small CMS for my own site.I have heard of
WildFlower CMS. Can anyone reccommend it or others?
Im new to using CakePHP and a CMS that is simple and easy to use would
be great.
many thanks
gemmes
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- css - I want to include some css files only when I use Elements or
helpers they are used by. Is it any way to do this in cakephp? Or have
I include all css files into all pages?
I prefer to include all css scripts in the head. It has tow
advantages:
- The includes are made in one place in
see this
http://snook.ca/archives/cakephp/elemental_conditional_content_with_cakephp/
2008/10/17 Robert [EMAIL PROTECTED]
I want to add some scripts from views, elements, helpers to the
header. Header is in layout of course. What is the proper way to do
that?
Two examples:
- css - I want
Could you use a setTimeout() to get what you want?
On Oct 17, 12:17 pm, Arak Tai'Roth [EMAIL PROTECTED] wrote:
Okay, so I've been going back and forth now for awhile. The guys in
the scriptaculous group are able to help but not in a fashion that is
overly helpful using CakePHP. So I'm
Hi all,
I've this problem. I've a username and password login to enter my
application. When I test it on localhost everything works fine. The
problem is that if I put a link to a blank page, the session falls on
the original page and in the new blank one. Why it happens only on my
extarnal server
Set the name attribute into the CommandParser class (If your are
using PHP 4 the name attribute is mandatory as it is in models and
controllers).
class CommandParserComponent extends Object {
var $name = CommandParser;
//the rest of the code.
}
Okay, so I've been going back and forth now for awhile. The guys in
the scriptaculous group are able to help but not in a fashion that is
overly helpful using CakePHP. So I'm wondering yet again, if anyone
else on here has run into this problem and has a solution. I can't
imagine that I am the
When a user is removed from the Users table, remove them from ACL.
That way when (or if) they try and do something, ACL will deny them.
It doesn't matter that they are still logged in since they are logged
in as a user that can't do anything. Mark Story has a GREAT 3 part ACL
tutorial and there
Thanks Xavieruni!!
Here problem is not in AJAX logic because everything is working fine
in webroot folder if I don't use concept of controller.
I think problem is in cake.
because Cake is not generating XML correctly .. I read some manual for
cake XML also..but still in problem.
Please help
Bookme,
You really should go back to jQuery. Thousands of man hours have been
put into making that cross platform (its not an easy task.) This task
can be accomplished by jQuery without much strain. Go look through the
jQuery documentation. This is a case of you asking someone to give you
fish,
Hi guys,
Thanks for the help. Bernhard, I took your advice and changed the rss
controller to a feeds controller which works now. I pointed /rss to /
feeds in routes so now either one works.
Here's my new problem: We want to have multiple feeds. Press
releases, video, etc. So I was planning
Nevermind my last question! I looked up the syntax and I'm using
this:
$Route-connect('/rss/:action', array('controller' = 'feeds',
'action' = 'index'));
which works fine.
-Max
On Oct 16, 9:03 pm, Adam Royle [EMAIL PROTECTED] wrote:
What I would do is add a feed() action into your Articles
Thanks, Robert. What happens when you introduce ajax into the
equation, and now you want to dynamically reload one of these elements
(for example, customer had 5 inquiries, you're showing one at a time
through ajax). Do you now have to create an action/view for each of
these elements anyway so
Hari,
I have an existing cake 1.1 based app. I would like to add a new multi
user feature.
There would be a database and in the database there would be the
tables prefixed by usernames, like user1_maintable,
user1_optionstable, user2_maintable, user2_optionstable, etc
I just want to give an
I think it hits the external sever first and the the local.
On 10/17/2008, mcphisto [EMAIL PROTECTED] wrote:
Hi all,
I've this problem. I've a username and password login to enter my
application. When I test it on localhost everything works fine. The
problem is that if I put a link to a
Try going back to the JQUERY also instead of xml try rss.
On 10/17/2008, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Bookme,
You really should go back to jQuery. Thousands of man hours have been
put into making that cross platform (its not an easy task.) This task
can be accomplished by
That has already been said!
On 10/17/2008, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
When a user is removed from the Users table, remove them from ACL.
That way when (or if) they try and do something, ACL will deny them.
It doesn't matter that they are still logged in since they are logged
I am not sure, I have never seen that function or know its use. I will
look into it though.
On Oct 17, 10:40 am, scs [EMAIL PROTECTED] wrote:
Could you use a setTimeout() to get what you want?
On Oct 17, 12:17 pm, Arak Tai'Roth [EMAIL PROTECTED] wrote:
Okay, so I've been going back and
For a pure javascript/ajax template, go here http://ajaxphp.packtpub.com/
and download the sample chapter http://ajaxphp.packtpub.com/1825_01_Final.pdf
This should give you a basic working xmlhttprequest that should be
easy to modify to do what you need.
On Oct 17, 11:57 am, bookme [EMAIL
Doh! Putting the form tag inside the table instead of wrapping it is a
no no.
On Oct 7, 9:39 am, nightfallvt [EMAIL PROTECTED] wrote:
My index tables have aformbelow the heading to allow users to filter
data. When using ajax pagination theformdisappears after the first
request. Normal
Hey,
I have 2 Tables:
pictures
ratings
every rating belongs to a picture and every picture has many ratings.
(just a normal rating DB)
i want to make a list of every picture with it's average rating in the
picture view. Therefor i had made a avgRating function (gets the id of
the picture and
Hy,
I have something to work with schemas and PostgreSQL. I would like to
make join between tables of different schemas, but from the same
database.
Someone can work this way?
Anderson
Brazil.
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You received this message because you are
Hy,
I have something to work with schemas and PostgreSQL. I would like to
make join between tables of different schemas, but from the same
database.
Someone can work this way?
Anderson
Brazil.
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You received this message because you are
Hi everyone,
I have been working on this problem for many weeks and I have not
solved it yet: I have 3 divs in a layout and I want the three of them
to update when I submit an ajax form I put into one of them, but when
I send the form (even if I just use a bare ajax link) the resultant
layout
Both $html-css() and $javascript-link() have an $inline parameter,
and if you set that to false they will not be displayed inline, but
added to a $scripts_for_layout variable. Then, you just need ?php
echo $scripts_for_layout; ? in your head, and you're good to go.
I think that's what you're
Hi,
Cannot post comment to Bakery, http://bakery.cakephp.org/comments/add/360,
it says the title field cannot be left blank but I have completed
it:(
Thanks.
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CakePHP
Sounds like a browser problem.
On 10/17/2008, ilozka [EMAIL PROTECTED] wrote:
Hi,
Cannot post comment to Bakery, http://bakery.cakephp.org/comments/add/360,
it says the title field cannot be left blank but I have completed
it:(
Thanks.
--
Xavier A. Mathews
If you have the relationship setup correctly, you don't have to use
the ratings model. You can do this in your controller:
$this-set('ratings', $this-Picture-Rating-avgRating($id));
That's all off the top of my head, but it should work.
HTH,
hydra12
On Oct 17, 4:22 pm, nomex [EMAIL
thanks for your help, but this gives me a Mysql error.
my avgRatings function looks like this:
function getRating($id=null) {
if ($id) {
$avg_rating = $this-query(select avg(rating) from
ratings where picture_id = '.$id.');
$avg_rating1 =
I'm trying to modify model data before it gets sent to the controller
by using the afterFind callback.
I am able to modify the data in the model whose find method has been
called however any associated models do no have their afterFind
called.
For example I has a Post with some Comments, I ask
Hello!
I'm using Cake for several days now, I'm still under big impression of its
capabilities.
Nevertheless, I have faced a problem, to which solution, which I have found,
feels not logical in the Cake ways of doing things. First, let me show you
my table structure: (btw, I'm using
You shouldn't break conventions when naming your primary keys.
Cake will expect your primary key to be named 'id'... So Design.id and
Status.id.
Of course you can override those by setting a $prmaryKey = 'myOwnKey';
in the model, but why make your life more difficult?
On Oct 17, 8:17 pm,
As I work on my CakePHP based projects, I find that my views/elements
directory gets more and more filled. I really like putting view logic
in elements even in cases where I am not actually re-using the
element. I find I am treating elements almost like functions, so that
when I have a fairly
Hi,
I have problem with ORM (m-n) to relationship.
http://farm4.static.flickr.com/3171/2950137747_b098638c67.jpg?v=0 ERD
image
The table categories is related to itself using m-n relationship. To
make this possible I created a new mapping table called as
categories_categories.
This is the
Yes Stan, thats exactly what I've been looking for :)
Thanks a lot.
Elemental is also nice, I forgot about it.
Thank You all!
On 17 Paź, 23:31, Stan [EMAIL PROTECTED] wrote:
Both $html-css() and $javascript-link() have an $inline parameter,
and if you set that to false they will not be
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