In one of the .htaccess files, you'll find, which might cause trouble related
to your intention.
IfModule mod_rewrite.c
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php?url=$1 [QSA,L]
/IfModule
please also
You can have several behaviors at the same time. And they may
conflict. Try to change their order in $actsAs, maybe it can help.
On Feb 8, 8:41 pm, Foroct forrestfraz...@gmail.com wrote:
I'm still having this same issue. Can I call two behaviors in the
$actAs declaration? If so am I doing it
Sounds an interesting idea and I would love to see a demo too. I'm
assuming there are no databases involved here that you are using ajax
calls to build the source code for a HTML web form that the user can
then copy/paste to use in their own site? Could this be developed to
work with a database
mike karthauser gave the correct solution.
The for loop should be built to handle any numbers of rows, as it
already does, and then you should do conditional checks within the
loop to know if there are 1, 2 or 3 values in each row, presumably
echoing some alternative content/code for empty
mike karthauser gave the correct solution.
The foreach loop should be built to handle any numbers of rows, as it
already does, and then you should do conditional checks within the
loop to know if there are 1, 2 or 3 values in each row, presumably
echoing some alternative content/code for empty
It sounds like you need to read the book on how to use Model::find().
http://book.cakephp.org/view/449/find
http://book.cakephp.org/view/453/field
If you are still stuck then you will need to provide more details on
the models, fields, conditions involved.
HTH
Paul
Check out the new CakePHP
Hi prasanth
You can easily clear your bug through this ?php echo
$html-link('$day_num',array('onmouseover'='function
calling()','onmouseout'='function calling()')); ?
--
Thanks with Regards,
M.Karthik MCA
Check out the new CakePHP Questions site http://cakeqs.org and help others with
If the model is Post, you can do the following:
$post = $this-Post-find('first', array(
'conditions' = array( ),
'fields' = array('Post.id')
));
Your ID will be in: $post['Post']['id']
On Tue, Feb 9, 2010 at 8:57 PM, WebbedIT p...@webbedit.co.uk wrote:
It sounds like you need to
No it's certainly not impossible, but you need to truly understand
what it is you're trying to achieve. Once you know that the answers
can be found in the cookbook.
I would imagine that any Menu can have any Recipe and as such you are
looking at a HABTM association that requires a menus_recipes
Any chance of a link so we can see it ourselves? Is the site on the
same server as others which are functioning correctly?
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their CakePHP related questions.
You received this message because you are subscribed to
On most of my sites pagination across the site is styled in exactly
the same way so I add the HTML/PHP into an element meaning any future
changes to pagination are made in one place.
At the top of my element I include the following which adds any passed
arguments into the paginator's options.
if
I think you are mixing up two thinks.
Don't let users access adm area' = ACL - accessing resources
nor other users area = Not classic ACL it's more permissions issue -
accessing data.
for example:
The annual report is a resource that can be watched by managers but not by
regular employee.
You
ok i have the answer and i want to share it the trick reside in
Inflector::underscore($plugin) the correct code is like this :
$controllers = Configure::listObjects('controller');
$plugins = Configure::listObjects('plugin');
if (!empty($plugins)) {
foreach ($plugins as $plugin) {
Thankyou Paul for your suggestions.
Creating a webform markup generating UI was an initial requirement
that has now changed into this - everything gets saved into our db.
I have so far being using my own markup rendering methods to generate
the html that is sent asynchronously to the UI. I have
If you are looking to call one controller from another, it's not a
good practice measure but sometimes it's just unavoidable. I use
this mainly for The Easy API - http://theeasyapi.com when I am
connecting a lot of API's together I will often times have to call one
function from a different
Hello, im kinda new in Cake, i've always been developing Flash sites
and now im using Cake for the backends (or CMS) for this sites. But im
having problems with the paths configurations, webroot folder, etc.
This is the setup i want to acomplish:
Cake core:
/cake
Webroot:
/public_html/
App dir:
Well,
I have a project like yours.
I have to build a survey-builder.
My client wants to login the system, and be able to create as many pools
(big pools) as he wants.
And his employees need to login the system and have access to fill this
forms up and save them to his db.
The project is in the
You could put your flash front in in the root (www.mydomain.com) and
then install cake at www.mydomain.com/intranet
On Feb 9, 1:20 pm, VitillO vj.nu...@gmail.com wrote:
Hello, im kinda new in Cake, i've always been developing Flash sites
and now im using Cake for the backends (or CMS) for this
I think you can place your flash app in your default page.
If you didnt change the default route, this should work.
create the /app/views/pages/home.ctp
and into it, you put your flash there.
and in the /app/config/routes.php, you change your route back to the default
route:
Router::connect('/',
@Richard: Thats the setup i was using in previous projects, but what i
want is the webroot files from Cake (images, docs, etc) to be outside
intranet directory, its just a matter of organization, its seems
cleaner to me this way, because Flash will be accessing this files
too.
@Renato: I could
Unless you really know what you are doing, you should avoid storing
canonical data in serialized strings.
Though it has been done with very great results off the cakephp world.
See how it is done at FriendFeeder:
http://bret.appspot.com/entry/how-friendfeed-uses-mysql
Serialized data used as a
Hi, I am trying to set a custom layout for Auth flash message.
setFlast() support that but it seems to be hardcoded in the core for
case of auth messages.
any idea how to set my own layout wrapper around this message ...
Login failed. Invalid username or password.???
thanks
help
Sure, it's a Dutch webshop in porselain, china and other table-stuff:
http://www.serviesjesenmeer.nl/
Since it's pretty intermittent I cannot tell you how to reproduce it
exactly, but clicking around enough should give you an indication
(Especially on the left side which shows categories of
Oh, and concerning the different server, a Dutch hosting-company hosts
my sites, so I cannot really tell if they are on actual different
servers... But since it's from the same company I kinda expect the
same standard for all hosting, so it's poobably not that.
Thanks!
On 9 feb, 11:13, WebbedIT
Try something along these lines:
$this-Session-setFlash
(__
('Message.', true),
true,
array('class' = 'flashError')
);
Jeremy Burns
jeremybu...@me.com
On 9 Feb 2010, at 14:32, toka...@gmail.com wrote:
Hi, I am trying to set a
I;m not really sure about the exact mechanics you'd like, but you can
probably set the view so that it changes according to the date:
?php
if (date(Y-m-d) date(2010-12-27) ) {
//Display Christmas inforamtion
} elseif (//Whatever) {
//Display other timedependant views
}
Perhaps you can use
Thanks, I will not use serialized data for this. All of my current
contact models use the BelongsTo - HasMany approach and this project
will also. I had just finished coding a metadata interactor and used
serialized data with great success but I see it does not fit for this
type of relationship.
Not sure but is there a chance that the username is an empty string
like or has a stray space perhaps? And therefore not considered
empty?
If not... Beats me! :D
On 8 feb, 17:31, Tomek Mazur tmazu...@gmail.com wrote:
Hi,
I have this weird problem. I set up validation rules but cake seems
Can you tell what exactly goes wrong? Can you see anything or is it
just a blank screen?
If you set debug on 2 on your app/config/core.php, does it display any
errormessage when you use the application?
On 8 feb, 08:41, Sitthykun ly.sitthy...@gmail.com wrote:
Hi all,
for now I using cakePHP
Hi, I thought I'd see if any user or contributor to the MongoDB
datasource can answer this question.
The datasource is this one by ichikaway:
http://github.com/ichikaway/mongoDB-Datasource
The datasource strangely requires each model to define $_schema in the
class definition. I say strangely
I've just released my 1.2 version (beta) Facebook Plugin for
CakePHP1.3
http://www.webtechnick.com/blogs/view/229/CakePHP_Facebook_Plugin_Auth_Facebook_and_more
A quick rundown of features:
- Full featured authentication via Facebook. Facebook Authentication
will work with or without a user
if you are using the AuthComponent, you should change the auth message
via:
$controller-AuthComponent-loginError = __('whatever you want',
true);
this is the best way (DRY)
On Feb 9, 3:32 pm, toka...@gmail.com toka...@gmail.com wrote:
Hi, I am trying to set a custom layout for Auth flash
Nope. I tried this with other rules: minLength, maxLength and it
always validates. It seems like the rules are simply ignored. It
occours only in this one specific model. Don't know what's behind
this...
On 9 Lut, 15:49, Céryl c.a.h.wilt...@student.tue.nl wrote:
Not sure but is there a chance
Seems my server seems to be down. While I look into it, you can view
and download the plugin from the svn here:
http://www.xp-dev.com/sc/browse/70786/%2Ftrunk
Hope to have the site up and running soon,
Nick
On Feb 9, 8:15 am, nurvzy nur...@gmail.com wrote:
I've just released my 1.2 version
great thanks for the info guys. that helps a lot
On Feb 8, 11:18 pm, Miles J mileswjohn...@gmail.com wrote:
Yes, anything to do with model/database logic should be placed in the
model.
The controller is used to pass the data from the model into the
correct view.
On Feb 8, 6:56 pm, dtirer
So I have a site where there is a formal registration form, whereafter
the user gets logged in automatically via the Auth-login() method.
It stores data automatically from $this-data in the Session.
However, I have another part of the site that deals with new users
searching for something via an
Hi all. I have created an element that will interact with an external
webservice. The webservice presents weather forecast data in XML and
I am using my element code to parse the XML and render it on my site.
The weather forecast service never updates their data more frequently
than 1 hour, so I
hmm, I would advise you that instead of registering a user 'on the
fly', first showed him a registration form if his email does not exist
in the bd and then redirect him to wherever he were once logged in.
Anyway, for login you only must send to users controller a post data
in the conventional
Hi,
I'm new with CakePHP and I have a question ( only one at this
moment :P ). I want to integrate CakePHP with another web applications
I've developed before. How to integrate CakePHP functions into them?
I've read something about dispatcher function but it only works for
internal controllers
Here' my two Models:
User:
id
email
password
Request:
id
user_id
item
If I have a function in my UsersController, and I HAVE User.id, and I
want to RETRIEVE User.email and Request.item, how do I do that with a
find()?
Check out the new CakePHP Questions site http://cakeqs.org and help others
Hm I see. I read that you can manually insert session data as
parameters into the Auth-login() function.
But maybe I'll try directing through the UsersController-register(),
and then putting the user on their way after that
On Feb 9, 1:19 pm, anler anle...@gmail.com wrote:
hmm, I would advise
Oh and:
User hasMany Request
Request belongsTo User
Also, even after the query works, I'm always confused about how to
reference the data ($variable['User']['Request']['item'], ?? etc)
On Feb 9, 2:44 pm, dtirer dti...@gmail.com wrote:
Here' my two Models:
User:
id
email
password
that is something I would not do, anyway if you still wants to, I would
recommend you to use only the data layer of cakephp because is into this
layer(models) where the business logic of the application should be, with
models you can create for yourself a 'mini api' and integrate it wherever
you
you should think that, User *hasMany* Requests, therefore when you query
the User model, the related requests comes in as a *collection*, so
$var['User']['Request']['item'] will not work because ['Request'] is a
collection, an array of rows 'item'
array(
'User' = array(...),
'Request' =
I forgot, if a user can have only want request, you should use hasOne in
order to do what you told above
anl
On Tue, Feb 9, 2010 at 10:24 PM, anl hp anle...@gmail.com wrote:
you should think that, User *hasMany* Requests, therefore when you query
the User model, the related requests comes
Are you using CakePHP 1.3.0-beta? Then you should check out the latest
source code from github.
Cheers,
Jan
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their CakePHP related questions.
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Check there are no blank spaces after the php close tags in your models
On 9 February 2010 10:21, Céryl c.a.h.wilt...@student.tue.nl wrote:
Can you tell what exactly goes wrong? Can you see anything or is it
just a blank screen?
If you set debug on 2 on your app/config/core.php, does it
if you only see a blank screen verifies in php.ini that display_errors
= on
On 8 feb, 08:41, Sitthykun ly.sitthy...@gmail.com wrote:
Hi all,
for now I using cakePHP 1.2.6 on window vista with apache 2.2.x
I would like to test with blog sample, but it does not work.
I have thought it maybe
Hi there!
I need some information about how to use CakePHP with DB2... Anybody
has exprience with that?
I need to use:
- Debian.
- Apache.
- CakePHP.
- DB2.
If anybody did a project link this, please help me with a how-to or
any idea about the implementation...
Thanks a lot!
Check out the
With some help... I figured out the problem. I was using the file
cache option and although the /tmp/cache directory was writable I was
missing a necessary directory. Since I was trying to cache an element
the /tmp/cache/element directory needs to exist and it must be
writeable. My problem was
I have the following problem:
- user model [id, firstname, lastname, email]
- review model [id, author_id, target_id, comment]
Each user can review other users. Both review.author_id and
review.target_id should be linked to user.id.
What is the relation between those models? Each review
Review Belongs To User, thats all, since Review.author_id references a
single user User
On 9 February 2010 22:00, NickPick dickreu...@yahoo.com wrote:
I have the following problem:
- user model [id, firstname, lastname, email]
- review model [id, author_id, target_id, comment]
Each user
Check this model filename. Should be post_comment.php. This model may
be not loaded at all if you named it wrong. In this case $this-
PostComment in controller will be of class AppModel and won't have
your validation rules, of course.
On Feb 9, 9:54 pm, Tomek Mazur tmazu...@gmail.com wrote:
I have a form with an 'Item' and 'email' field. It submits to an
Items Controller.
I want to validate both fields, however, the 'email' is technically
part of a User model.
So what happens is, when the form is submitted, it's supposed to
search for the Item in the form. it also check if the
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