Jeremy Burns
Hello again :)
Code in the model of my port-table:
(the $hasOne association from my origionally question was updated to
the association below:)
[code]
public $hasMany = array(
'Port' = array(
'className' = 'Port',
'foreignKey' = 'uplink_id'
)
);
[/code]
I
Can you show me your entire $hasMany and $belongsTo declarations, and your find
statement?
Jeremy Burns
jeremybu...@me.com
On 26 Mar 2010, at 06:24, sebb86 wrote:
Jeremy Burns
Hello again :)
Code in the model of my port-table:
(the $hasOne association from my origionally question was
sure! :-)
[code of model port]
public $belongsTo = array(
'HardwareUnit' = array(
'className' = 'HardwareUnit'
),
'Vlan' = array(
'className' = 'Vlan'
),
'PortEmploymentGroup' = array(
'className' = 'PortEmploymentGroup'
The problem is (I think) that you are creating a self join but calling the
joined model 'Port', which is the name of the current model.
Try changing to this (I've used ParentPort and ChildPort but you can rename at
will):
public $belongsTo = array(
'HardwareUnit' = array(
By default a find with recursive will only fetch the data from the
model and it's directly associated models. Therefore when running
User-find() you will get User and Project but not Library as library
has no direct link to User.
To include the extra level of associations increase User-recursive
Does anyone have an example of how to create an Ajax form from start
to end using the Js helper in 1.3? Which components/helpers to
include, how to set up the view and the controller, how to get the
right layout etc? The information is all out there somewhere, but in
bits. I'd love to see a simple
Jeremy
It works with a little modification :) great!!!
The modification is to change ChildPort to ParentPort in the
following code:
[code]
var $paginate = array(
'fields' = array('*'),
'recursive' = 2,
'limit' = 50,
'order' =
Thank you Jeremy.
I'll go through the reference links you provided.
I like the philosophy of CakePHP more and more as I explore it. I'll
send you a link for my question once I develop the page.
Regards,
Alper
On Mar 26, 7:22 am, Jeremy Burns jeremybu...@me.com wrote:
I'd recommend that you read
Hi all,
I'm going over the QuickWall example in CakePHP Application
Development book by Ahsanul Bari and Anupom Syam.
In the example, there is a line where the questions are produced:
?php e($html-link($question['Question']['question'].'?',
array('action' = 'show', $question['Question']['id'])));
Something looks wrong with your implementation; I'd expect to see
http://localhost/quickwall/questions/show/1 (assuming you've set this up in the
quickwall folder).
It's a personal thing, but I'm not a fan of that book. Some of the code samples
are wrong and it doesn't stick to conventions
Hi all, I've searched the google group and unfortunately cant find any
info on this (or anywhere for that matter)..
I'm trying to send PHP variables over an ajax dropRemote request but
the action thats meant to be recieving the parameters is not picking
it up.
Basically I am trying to drag
Thank you again Jeremy for the warning.
There are not many books available about CakePHP and I borrowed this one
from a friend.
I guess I'll stick with the online examples.
Alper
On Fri, Mar 26, 2010 at 12:07 PM, Jeremy Burns jeremybu...@me.com wrote:
Something looks wrong with your
Hi Jeremy,
What about the Beginning CakePHP: From Novice to Professional book by David
Golding?
Did you have any chance to review it?
Alper
On Fri, Mar 26, 2010 at 1:35 PM, Alper K. Tunç alpe...@gmail.com wrote:
Thank you again Jeremy for the warning.
There are not many books available about
Hello.
i have 2 models (Item and Order) joined together by a HABTM
relationship.
since i need some additional fields (quantity) in the join table i
splitted the HABTM in 2x hasMany.
after that i coded a Order add form wich gives me this data array
Array
(
[Order] = Array
(
Hi euromark,
I have tried now FALSE as well but it does the same... those quotes
still brakes the html..
Thanks
Tomas
On 25 bře, 13:13, euromark dereurom...@googlemail.com wrote:
escape should not be true but FALSE in this case
On 25 Mrz., 08:41, toka...@gmail.com toka...@gmail.com wrote:
I have found this book to be by far the best. It covers all of the bases and
does what it says on the tin.
Second place goes to Practical CakePHP Projects.
But you're right - CakePHP books are thin on the ground.
Jeremy Burns
jeremybu...@me.com
On 26 Mar 2010, at 11:44, Alper K. Tunç wrote:
I'll update the thread with some findings after rooting through the
code a bit.
Looking at the source I found out that -f does not force 'generate'
to create a new schema.. It is used To force generation of all
tables into the schema... but not only that.
It can also be used to force update to
I am almost there with the Schema Shell. Now just one thing remains.
Being able to do run update -f without answering y or n to the
questions.
Is there a non-interactive mode for the Schema Shell? I can't see any
option to do it.
/Martin
Check out the new CakePHP Questions site
Found a shell-based way to automatically answer the question.
http://www.unix.com/shell-programming-scripting/30246-how-give-variable-command-shell-script.html
On Mar 26, 3:41 pm, Martin Westin martin.westin...@gmail.com wrote:
I am almost there with the Schema Shell. Now just one thing
I'm using AJAX to update part of a page. On occasion, however, the
user may make a change that necessitates reloading the entire page,
not just the elements that are used with the AJAX call.
If I do a redirect in the controller, it reloads the entire page into
the ajax element. Is there a way in
There's no way to controller the reload of the current page or a only a part
from the controller. You should send an special reponse to the javascript
(ie:a simple reload string could work), and at the client side do
something like document.location=youurl
Regards,
Pablo Viojo
pvi...@gmail.com |
Thank you, Pablo. I'll give that a try.
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Thanks Jeremy
Turns out all I needed to do was modify the main .htaccess. I had done
this previously but had errors and wasn't aware of the errors. Fixed
the errors and it is working.
On Mar 25, 10:33 pm, Jeremy Burns jeremybu...@me.com wrote:
Try installing it in /app/webroot/xxx, where xxx
Hello everybody.
I need to create few radio options, each one separated by different
portions of html code.
E.g.:
input type='radio' id='data[User][Title]' value='1'Mr/input
brinput type='select'... ...something... br
input type='radio' id='data[User][Title]' value='2'Mrs/input
p some other
Check validation errors. If ItemsOrders items are validated after
Order and fail transaction should be rolled back. Data stays added
as you have non-InnoDB table orders that do not support
transactions.
On Mar 26, 6:28 pm, Ernesto e.fanz...@gmail.com wrote:
Hello.
i have 2 models (Item and
Hi again.
I've found a solution to my problem.
I ended up creating the input-radios one at the time, and inserting
the html I need between them.
What I was actually mistaking was not setting the
attributes['value'].
echo $form-
Looking here:
http://book.cakephp.org/view/78/Associations-Linking-Models-Together
I'm certain my issue is due to a personal lack of understanding.
I'm trying to homebrew a simple app to keep track of my guitar
practice.
I have the following models:
PracticeItem: a specific exercise to be
On Mar 26, 4:51 am, sebb86 kahlc...@googlemail.com wrote:
in addition: in my view i retrieve this data in a foreach loop with
this code:
[view code]
td style=text-align:left?php if ($port['Port']['uplink_id'] !=
NULL) { ? ?php echo - port id ; echo $port['Port']['uplink_id'];
echo (-
Hello everybody,
In the app I am building I have these three radios:
echo $form-input('RuleRecurrence.weekdayconditions', array(
'type' = 'radio',
'options' = array('always' = 'Sempre'),
'checked' = ($WeekdayCondition == 'always' ? true :
I am building a form with a set of radio buttons and am failing to get
any kind of error message when they don't pass the validation.
Here is the model code I have for validation..
var $validate = array(
'name' = array(
'rule' = 'notEmpty',
Hello Johnny,
class PracticeItem extends AppModel {
}
class PracticeInstance extends AppModel {
var $belongsTo = 'PracticeItem';
}
class PracticeSession extends AppModel {
var $hasMany = 'PracticeInstance';
}
tblPracticeInstances
* id
* practiceitem_id
* practicesession_id
*
Once again, silly me.
The several value are setting each time the value for the radio.
So when the first one is created, value = 'always' and it is checked.
When Cake parses the second input and creates it, it sets the value to
'exact', and the second one is checked.
So I was finding always the
It's a little difficult to wrap my head around, but I think I see
what's going on.
belongsTo is a many to one relation, so many PracticeInstance belong
to 1 PracticeItem
That defies my intuition, because it's more natural for me to think of
a PracticeItem as belonging to a PracticeSession. The
In AppController, I have:
$this-authorize = 'controller';
I have several types of Users, each with a 'model' field set. I'd like
to bar certain types of Users from accessing the forum. In
ForumSectionsController, I have:
function isAuthorized()
{
return $this-Auth-user('admin') ||
Hello together
Array
(
[Model1] = Array
(
[id] = 1
[title] =titletext
[description] = description
)
[Model2] = Array
(
[0] = Array
(
[id] = 2
[model1_id] = 1
I have to correct it because in the that have to be an other value
$this-set('variable', $this-Model1-find('first',array(
'conditions' = array('Model1.id' = $id),
'recursive' = 1,
'fields' =
Why are you using ?var1=$hiddenFieldId? Why not just use:
'url' = '/purchases/addGuestToTable/'.
$hiddenFieldId.'/'.draggedid.element.id
Then in your purchases controller:
function addGuestToTable($hiddenFieldId, $draggedId){
//Do what you want.
}
Hope that helps,
Nick
On Mar 26, 5:08 am,
try
'recursive' = -1
On 03/26/2010 05:23 PM, amarradi wrote:
I have to correct it because in the that have to be an other value
$this-set('variable', $this-Model1-find('first',array(
'conditions' = array('Model1.id' = $id),
'recursive' =1,
isAuthorized() is only called if the action is not already allowed
$this-Auth-allow('action_name'). In the controller you want to lock
down do you have something along the lines of $this-Auth-allow('*')
in your beforeFilter?
Hope that helps,
Nick
On Mar 26, 1:45 pm, cricket
Thanks for the tip but i get this sql error
Unknown column Model2.id' in 'field list'
Because there is an array in Model2.
[0]
[1]
I dont know how do i get an coorect dataset
On 26 Mrz., 21:31, Martin Radosta martinrado...@gmail.com wrote:
try
'recursive' = -1
On 03/26/2010 05:23
The Question is how do i get the information from an/the associated
model
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
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CakePHP group.
To post to this
Thanks again, Pablo. That worked.
For a brief moment, it displays my response message, and then reloads
the page. I suspect maybe I need to tweak the jQuery to get that to go
faster. I'm using ajaxForm from the jQuery form library.
Check out the new CakePHP Questions site http://cakeqs.org and
I didn't, but I just realised the problem. In AppController, I had
$this-authorize = 'controller' instead of $this-Auth-authorize =
'controller'. It works fine now.
Thanks for responding, though.
On Mar 26, 4:45 pm, nurvzy nur...@gmail.com wrote:
isAuthorized() is only called if the action is
Which fields from Model2 do you want? Do you want anything from
Model2?
On Mar 26, 4:57 pm, amarradi radis...@googlemail.com wrote:
The Question is how do i get the information from an/the associated
model
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their
Hello together,
i have two models, hasOne(Model2) hasMany(Model1) connection
now i try to search over an id in model1 the data in model2.
i try it in this way
$this-set('var1',$this-Model1-find('first', array(
'conditions' = array('Model1.id' = $id),
'recursive'
I want the title description and in the first version
reservation_status
i try it over contains or recursive 2 But no change
On 27 Mrz., 00:39, cricket zijn.digi...@gmail.com wrote:
Which fields from Model2 do you want? Do you want anything from
Model2?
On Mar 26, 4:57 pm, amarradi
I have to go to bed good night
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I have this for my find all ;
$count = 10;
$params = array(
'conditions' = array(
'Entry.featured' = 1),
'fields' = array(
'Entry.id',
'Entry.title'),
'limit' = $count,
'order' = 'rand()',
'contain' = false);
return $this-find('all', $params);
So I have 100 dummy
Yes, I did try that. There is a field for confirm password as well and that
is all that is being presented to the controller.
On Fri, Mar 26, 2010 at 1:29 AM, Jeremy Burns jeremybu...@me.com wrote:
Have you debugged the data that is being presented to the controller
function? Set debug to 2
I'm not sure why but I'm relatively sure that it's not recognizing the form
fields for username and password.
On Fri, Mar 26, 2010 at 10:38 PM, Ed Propsner crotchf...@gmail.com wrote:
Yes, I did try that. There is a field for confirm password as well and that
is all that is being presented to
I am trying to figure out how to use containable properly.
These are the model relationship:
Client has many Account
Account has many Bills
Bills have many BillResources
ResourceType hasMany BillResource
BillResources belong to bill
Bills belong to Account
Account belongs to Client
I am trying
Maybe your database table engine does not support transactions.
What engine are you using?
Lucca Mordente
On 26 mar, 09:28, Ernesto e.fanz...@gmail.com wrote:
Hello.
i have 2 models (Item and Order) joined together by a HABTM
relationship.
since i need some additional fields (quantity) in
Hi Forum
I've a problem with my cake application.
i've 2 tables (sites and articles). The relations in the model:
sites belong to sites (self join)
sites has many sites
sites has many article
articles belongs to sites
I added the translation behavior to my model and put the db-fields in
the
The reason I recommended that you examine the data array is that sometimes (and
I often get confused with this myself) you need to double check exactly where
the item you are looking for sits in the array. So if you can see the field you
want, build the path to it by walking back up from it. If
The only thing showing in the array is the field for 'confirm_password',
[code]
Array
(
[User] = Array
(
[confirm_password] = test
)
)
[/code]
I'm having the same issue with the the username field. It's acting
like the field doesn't exist.
On Sat, Mar 27,
So all you can get is $this-data['User']['confirm_password']...
Are you expecting more fields to be in the array? Are the fields you want
inside the form in the view?
Jeremy Burns
jeremybu...@me.com
On 27 Mar 2010, at 05:00, Ed Propsner wrote:
The only thing showing in the array is the
|Your question is not clear, I guess you need this:
$this-Model1-Behaviors-attach('Containable');
|
$this-Model1-find('first',
array(
'conditions' = array('Model1.id' = $id),
'contain' = array('Model2' = array('fields' =
array('Model2.title',
Yes, I'm expecting to see $this-data['User'][''password'] as well. Both
fields exist and are displayed in the view.
On Sat, Mar 27, 2010 at 1:09 AM, Jeremy Burns jeremybu...@me.com wrote:
So all you can get is $this-data['User']['confirm_password']...
Are you expecting more fields to be in
But are they inside the form in the view?
Jeremy Burns
jeremybu...@me.com
On 27 Mar 2010, at 05:15, Ed Propsner wrote:
Yes, I'm expecting to see $this-data['User'][''password'] as well. Both
fields exist and are displayed in the view.
On Sat, Mar 27, 2010 at 1:09 AM, Jeremy Burns
Yup, I double checked to make sure I didn't somehow inadvertently end the
form early but it's all good. The field before 'password' is 'username' and
i'm using $ajax-observeField to display changes to the 'username' field but
it's not doing anything and I'm guessing that it's' not seeing the field
Use $form-input() instead of $form-radio() or use $form-error()
together with $form-radio()
On Mar 27, 1:05 am, aapljack brianmiddle...@gmail.com wrote:
I am building a form with a set of radio buttons and am failing to get
any kind of error message when they don't pass the validation.
Here
You say they are being recognised OK, but they weren't in the $this-data array?
Have you checked the actual page source to examine the form in the view? Only
yesterday I debugged a similar problem where the browser was ending the form
for me (I had embedded it incorrectly into a table).
Jeremy
Sorry, I'm new to Cake and was a bit confused. I was echoing the debug
inside the controller that the ajax call uses. The only two fields that are
being used in that controller are 'password' and 'confirm_password' ... only
'confirm_password' is displayed with the debug.
Up until now I never
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