On Jul 16, 1:50 pm, rchavik wrote:
> huh? i think the data is already in the controller.. it's should be in
> $this->data array.
>
> Do a debug in your BeersController->view_beer method.
let me rephrase:
Do a debug($this->data) in your BeersController->view_beer method, eg:
class BeersContro
On Jul 16, 1:50 pm, rchavik wrote:
> huh? i think the data is already in the controller.. it's should be in
> $this->data array.
>
> Do a debug in your BeersController->view_beer method.
let me rephrase:
Do a debug($this->data) in your BeersController->view_beer method, eg:
class BeersContro
huh? i think the data is already in the controller.. it's should be in
$this->data array.
Do a debug in your BeersController->view_beer method.
Get firebug, and inspect the response from the webserver.
On Jul 16, 11:53 am, jeremy wrote:
> hai can anyone tell me how can i get the posted values
hai can anyone tell me how can i get the posted values from jquery to
a controller
so far this problem has not been solved..
my jquery alerts correctly as shown in the above disucssion
now its the only problem of how to get this values to a controoler in
cakephp
any refrence or examples o
=>i mean is there any way to get the value from jquery to a controller
function
=> and if so how ..
=> or could u give me any tutorials regarding this issue
=> it could be veryhelpful
=>thankz again
On Tue, Jul 14, 2009 at 2:02 PM, jeff wrot
Thanx for the reply
Dr. Loboto
but could u tell me how to do that
i mean requesting view_beer action by jQuery code
i may sound stupid ...but the truth is i dont know how to do it
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If you request your view_beer action by browser address bar, you'll
see empty data as it is not AJAX and no parameters passed. When you
request your view_beer action by that jQuery code you see filled data
as it is AJAX and you passed data.
On Jul 14, 1:28 pm, jeff wrote:
> sorry
> Dr. Loboto
> w
sorry
Dr. Loboto
what i mean to say is that
when i alert the data through javascript
it gives me the foll
Data submitted: Array
(
[pass] => Array
(
)
[named] => Array
(
)
[controller] => beers
[
You finally see your controller output and data you submitted is
there. Your initial post was exactly about achieving this result.
On Jul 14, 11:48 am, jeremy wrote:
> hai guys am waiting didnt get any response so far...
>
> please help me as i need to get this working..
hai guys am waiting didnt get any response so far...
please help me as i need to get this working..
my javascript file is as shown below
$(document).ready(function() {
>
> var value = $('.add-beer-link').attr('id');
>
> alert(va
Thanz again
Dr. Lobotoso now i understood what u was referring to
and now i changed my javascript files as follows
===
$(document).ready(function() {
var value = $('.add-beer-link').attr('id');
alert(value);
$('#some-beer-name').click( funct
$('.add-beer-link').click( function () {
$.post('http://localhost/jeffery/cake_1.2.3.8166/beers/
view_beer',
{name: "John" , id: value },function(RESPONSE, textStatus)
{
alert(RESPONSE);
});
});
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Thanks for replying
Dr. Lobotobut i just cant understand what response u r talking about...
moreover exactly i dont know how to do it???
so if u can help me with a code sample or example i could figure it out...
i read the link ,but cant follow what u r refering to please forgive me
for
And again. You just NOT output your response anywhere.
Read jQuery manual first: http://docs.jquery.com/Ajax/jQuery.post
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Hello,
You can try to debug AJAX requests using firebug firefox extension
Amit
http://amitrb.wordpress.com/
http://coppermine-gallery.net/
http://cheesecake-photoblog.org/
http://www.sanisoft.com/blog/author/amitbadkas
On Thu, Jul 9, 2009 at 11:13 AM, jeff wrote:
> Thanks for replying guys..
Thanks for replying guys..
I never use IE7,
Am currently using Firefox 3.5
so this is what i did then, i changed my javascript a little
beers_view_beer.js
===
$(document).ready(function() {
var value = $('.add-beer-link').attr('id');
al
Are you doing your testing in IE7? There are reports that IE sucks:
https://trac.cakephp.org/ticket/1935
http://www.google.com/search?q=internet+explorer+sucks
Or maybe following in the footsteps of a tried-and-true approach:
http://marcgrabanski.com/article/cakephp-ajax-quick-save-jq
I do not see your AJAX response display.
Read this too: http://docs.jquery.com/Ajax/jQuery.post
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thanx for the reply marcelo
so i think i need to reconsider a better understanding of cakephp
therefore i now turned into a much simple program in cakephp
using all its feature
but still am not able to get the value from jquery to a controller in
cakephp
heres what i did
i create
On Tue, Jul 7, 2009 at 4:46 AM, jeremy wrote:
>
> my controller file is simple and is given below...
>
> users_controller.php
> ==
>
> class UsersController extends AppController
> {
> var $name = "Users";
> var $uses = null; //if no DB connection is re
Start working from a simple base. Add FormHelper to your application
then try the following:
create('User');
echo $form->input('username');
echo $form->input('password');
echo $form->end('Login');
?>
You will need to rework your jQuery so the IDs match the generat
thanks for the reply
i changed the namefield value to data[User][username] and
data[User][password]
but there isnt any result
should i completely rewrite the login view page using the helpers...
if so can u tell me how to include the values for id, name for each field
ie for the (form,
First, the obvious: build your forms using FormHelper. FormHelper will
help with form integration with CakePHP.
The main problem with your form is the naming of the fields. When
using Cake "username" just doesn't cut it, because the framework is
expecting a specific data structure. Try renaming y
hai guys am new to this cakephp stuff and is having problem using
cakephp with jquery...
my problem is that am not able to get the values posted from jquery to
a controller in php...
my controller file is simple and is given below...
users_controller.php
==
params['form'])
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