Re: [ccp4bb] Why the name aimless

2013-05-03 Thread Graeme Winter
Suspect most people would be looking for painless though I would guess that should be a program to tell you the right crystallization conditions... On 3 May 2013 00:15, Jacob Keller j-kell...@fsm.northwestern.edu wrote: Nevertheless? JPK On Thu, May 2, 2013 at 2:18 PM, Roger Rowlett

[ccp4bb] A small clarification

2013-05-03 Thread Kavyashree Manjunath
Dear users, I wanted a small clarification, I was solving a ligand data in H3 space group with a dimer as the asymmetric unit. Initially, I had solved and refined this without using the same Rfree reflections as that of native data. So I resolved and refined the same data by considering the

Re: [ccp4bb] A small clarification

2013-05-03 Thread Herman . Schreuder
Dear Kavya, There used to be a chaos with H3 and R3 settings so you first thing you might want to check that the same setting is used in both cases. Easiest would be to check the CRYST1 record in your pdb files to make sure that the same cell is used. If you did not start for the second data

Re: [ccp4bb] A small clarification

2013-05-03 Thread Kavyashree Manjunath
Sir, Ok. Thank you I was unaware of this alternative indexing. But I used the same processed data from mosflm for both. Only while scaling I chose the native Rfree set. Thank you Regards KAvya could be a case of alternative indexing - some spacegroups allow more than one indexing scheme and

Re: [ccp4bb] A small clarification

2013-05-03 Thread Kavyashree Manjunath
Dear Sir, There used to be a chaos with H3 and R3 settings so you first thing you might want to check that the same setting is used in both cases. Easiest would be to check the CRYST1 record in your pdb files to make sure that the same cell is used. I check it, the unit cell dimensions are

[ccp4bb] Fwd: [ccp4bb] Structural Biologist Central London_ DEADLINE VERY SOON

2013-05-03 Thread Nicholas Keep
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Re: [ccp4bb] A small clarification

2013-05-03 Thread Eleanor Dodson
You knowe there are alternative indexing for H3 - you couldnt have solved one as h k l and the other as k h -l? And alternate origins - H3 is a polar spacegroup so if you redid the molecular replacement you may finish up anywhere along the c axis.. Easiest is to do a superpose of both sets of

Re: [ccp4bb] A small clarification

2013-05-03 Thread Kavyashree Manjunath
Respected Mam, The molecule is not along the C axis. I opened both these molecules along with the pseudo-translation peak generated by patterson function, it could be observed that the origin of the one of the dimer corresponded to the 2nd peak (pseudo translation) peak. So I guess this is due