Haakon Claassen (hclaasse)
> Sent: Sunday, September 29, 2002 1:28 PM
> To: [EMAIL PROTECTED]
> Subject: RE: Filter odd routes via wildcard bits - How?? [7:54496]
>
>
> Hi
>
> Just do the binary calculus
>
> 0.0.254.255 is . . 1110 .
>
, September 29, 2002 1:28 PM
To: [EMAIL PROTECTED]
Subject: RE: Filter odd routes via wildcard bits - How?? [7:54496]
Hi
Just do the binary calculus
0.0.254.255 is . . 1110 .
apply that to your prefix 172.168.1.0
the first two bytes (172 and 168) will have to match
ailto:[EMAIL PROTECTED]]
Sent: zondag 29 september 2002 20:59
To: [EMAIL PROTECTED]
Subject: Filter odd routes via wildcard bits - How?? [7:54496]
Hello,
I am trying to understand how a wildcard mask of 0.0.254.255 filters odd
routes so that only even routes get across the router.
Ex. If you
ah, the old "odd - even" question.
in all of mathematics, if a number is evenly divisible by "2" ( with no
remainder" then it is an even number. by definition.
in binary, the extension of this principal is that if the right most bit is
"0" then the number is even. you could count it out on your
Hello,
I am trying to understand how a wildcard mask of 0.0.254.255 filters odd
routes so that only even routes get across the router.
Ex. If you have routes for 172.168.1.0/24, 2.0/24, 3.0/24, 4.0/24, 5.0/24,
6.0/24 and you have an access-list of:
#access-list 11 deny 172.168.1.0 0.0.254.255
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