Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Paul Werner
Just as a clarification to what you wrote and the terminology that you used, how exactly are you defining a Supernet, particularly on this network? v/r, Paul Werner I could be wrong here, but I would imagine the reason this works is that you have a supernet there, with the mask of

Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Thomas Larus
Great point. It's not a supernet of anything. Not with the first octet being 24. Thomas Larus - Original Message - From: Paul Werner To: ; [EMAIL PROTECTED] Sent: Saturday, October 27, 2001 4:02 PM Subject: Re: Subject: Re: quick response (help) please [7:24238] Just

Re: Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Paul Werner
Subject: Re: Subject: Re: quick response (help) please [7:24238] Just as a clarification to what you wrote and the terminology that you used, how exactly are you defining a Supernet, particularly on this network? v/r, Paul Werner I could be wrong here, but I would imagine

RE: Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Chuck Larrieu
Subject: Re: Subject: Re: quick response (help) please [7:24238] Just as a clarification to what you wrote and the terminology that you used, how exactly are you defining a Supernet, particularly on this network? v/r, Paul Werner I could be wrong here, but I would imagine the reason

Re: Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Wojtek Zlobicki
27, 2001 5:31 PM To: [EMAIL PROTECTED] Subject: Re: Re: Subject: Re: quick response (help) please [7:24238] Agreed. While it is possible to supernet class A addresses, it is generally impractical for the most part, unless the ISP/AS that is summarizing two Class A addresses owns both address

RE: Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Ken Diliberto
It says 09/12/2001 as the last update. Chuck Larrieu 10/27/01 08:02PM [snip] BTW, looking over the allocation table at: http://www.iana.org/assignments/ipv4-address-space interesting. anyone know how up to date this is? Chuck [snip] Message Posted at:

RE: Re: Subject: Re: quick response (help) please [7:24238]

2001-10-27 Thread Paul Werner
] Sent: Saturday, October 27, 2001 4:02 PM Subject: Re: Subject: Re: quick response (help) please [7:24238] Just as a clarification to what you wrote and the terminology that you used, how exactly are you defining a Supernet, particularly on this network? v/r, Paul Werner

quick response (help) please [7:24238]

2001-10-26 Thread John Green
the IP address alloted by the dhcp server to my home computer (via cable ie cable modem connection) is IP address 24.15.125.255 subnet mask 255.255.248.0 def gw 24.15.125.1 ok look ar the last quad it is 255 !!! i can't believe this. do you how this is possible ? 0 and 255 are

Re: quick response (help) please [7:24238]

2001-10-26 Thread James Haynes
This is a valid address for the subnet mask given. IP address 24.15.125.255 subnet mask 255.255.248.0 Network address = 24.15.120.0 Broadcast address = 24.15.127.255 -- James Haynes Network Architect Cendant IT A+,MCSE,CCNA,CCDA,CCNP,CCDP, CQS-SNA/IPSS John Green wrote in message [EMAIL

Re: quick response (help) please [7:24238]

2001-10-26 Thread Allen May
then yes you would be correct. If it still doesn't make sense try http://www.learntosubnet.com Allen - Original Message - From: John Green To: Sent: Friday, October 26, 2001 8:22 AM Subject: quick response (help) please [7:24238] the IP address alloted by the dhcp server to my home

Re: quick response (help) please [7:24238]

2001-10-26 Thread Thomas Larus
I could be wrong here, but I would imagine the reason this works is that you have a supernet there, with the mask of 255.255.248.0, so the hosts address is not all-ones, so is not treated as a broadcast address. The host address includes 3 binary digits from the third octet (125), so it works

Re: quick response (help) please [7:24238]

2001-10-26 Thread Allen May
Grignore the IP range. I can't even read my own writing. You get the point tho24.15.112.0 subnet 255.255.248.0. - Original Message - From: Allen May To: Sent: Friday, October 26, 2001 9:00 AM Subject: Re: quick response (help) please [7:24238] Look at the subnet

Re: quick response (help) please [7:24238]

2001-10-26 Thread John Green
oops... i got it. thank you all for correting me. --- James Haynes wrote: This is a valid address for the subnet mask given. IP address 24.15.125.255 subnet mask 255.255.248.0 Network address = 24.15.120.0 Broadcast address = 24.15.127.255 -- James Haynes Network

Re: quick response (help) please [7:24238]

2001-10-26 Thread Ken Diliberto
Hello, John. If you break the address and the subnet mask down into binary, it may make a little more sense. The 0-255's make it easier for us humans to understand. The equipment only sees a long string of 0's and 1's. That 255 only makes a difference when using a classful mask. Here is how

Re: quick response (help) please [7:24238]

2001-10-26 Thread Brian Whalen
0 and 255 are network and subnet octets for a 255.255.255.0 or /24 subnetted network. Your example is not that. Brian Sonic Whalen Success = Preparation + Opportunity On Fri, 26 Oct 2001, John Green wrote: the IP address alloted by the dhcp server to my home computer (via cable ie cable